108° 4x+8° O alternate interior corresponding vertical linear pair same-side Interior alternate exterior degrees
Alternate Interior angles
x = 25
Explanations:By careful observation of the diagram, we would see that both angles are at the opposite sides of the transversal. At the same time, they are at the interior of the two parallel lines.
This means that <108 and <4x + 8 are alternate interior angles.
Since the two lines intersecting the transversal are parallel, the alternate interior angles are equal
That is,
4x + 8 = 108
4x = 108 - 8
4x = 100
x = 100/4
x = 25
Find the ordered pair that solves this by the elimination method. 1/5x +y = 6/5 and 1/10x + 1/3 y = 7/10
We already know that the solution is (9, -3/5), let's show that
\(\frac{1}{10}x+\frac{1}{3}y=\frac{7}{10}\)Let's plug our solution into the equation
\(\begin{gathered} \frac{1}{10}\cdot9+\frac{1}{3}\cdot(-\frac{3}{5})=\frac{7}{10} \\ \\ \frac{9}{10}-\frac{3}{15}=\frac{7}{10} \\ \\ \frac{9\cdot15-3\cdot10}{10\cdot15}=\frac{7}{10} \\ \\ \frac{135-30}{150}=\frac{7}{10} \\ \\ \frac{105}{150}=\frac{7}{10} \\ \\ \frac{21}{30}=\frac{7}{10} \\ \\ \boxed{\dfrac{7}{10} =\dfrac{7}{10} } \end{gathered}\)The second equation is true!
X-15<-6=9 what is the answer pls
The solution set of the inequality x-15≤6/9 is x≤47/3.
What is Inequality?a relationship between two expressions or values that are not equal to each other is called 'inequality.
The given inequality is x-15≤6/9
x minus fifteen lesser than or equal to six by nine.
x is the variable and minus is the operator,
x-15≤6/9
On the right side the numerator and denominator is divided by 3
x-15≤2/3
Add 15 on both sides
x≤2/3+15
x less than or equal to two by three plus fifteen.
x≤2+3(15)/3
When three is multiplied with fifteen we get 45.
x≤45+2/3
So when forty five and two are added we get 47.
x≤47/3
Hence, the solution set of the inequality x-15≤6/9 is x≤47/3.
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Complete quesstion,
Find the solution set of the inequality x-15≤6/9
Please help me with question 4!
Answer:
I think that there might be some complex differential equation
stuff going on here if this were in the real world, but for the sake of this problem... may I suggest that the tank is filling up at a rate of
1/8 of a tank per hour...
it is evaporating at a rate of 1/12 tank per hour
you can subtract the rates
1/8 - 1/12 = 12/96- 8/96 = 3/96 = 1/32 tank/hr
so to fill the tank it should take 32 hours...
I think the logic and math work... lets see if someone else will verify this analysis?
Step-by-step explanation:
a theater charges $8 for main floor seats and $5 for balcony seats. for a full house, the ticket income is $4,200. at one show, only 25% of the main floor seats and 40% of the balcony seats were sold for a total of $1,200. how many main floor tickets and how many balcony tickets were sold for this show?
By solving a system of equations we can see that there are 400 main-floor seats and 200 balcony seats.
Let x = number of seats on the main-floor
y = number of balcony seats
We know that if all the seats are sold, then the total income is $4,200, we can write the equation:
x*8 + y*5 = $4,200
And if 25% of the main-floor and 40% of the balcony seats are sold, then we get an income of $1200, then we can write:
0.25*x*8 + 0.4*y*5 = $1,200
x*2 + y*2 = $1,200
2(x + y) = $1200
x + y = $600
x = 600 - y
putting the value of x in equation1)
8(600-y) + 5y = 4200
4800 - 8y + 5y = 4200
3y = 600
y = 200
and x = 600 - 200 = 400
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if cosØ=1/6 what are the values of sinØ and tanØ?
Answer:
Step-by-step explanation:
cos theta = (adjacent side) / (hypotenuse) = 1/6. The adjacent side has length 1 and the hypotenuse length 6. The opposite side has length
√(6^2 - 1^2) = ÷√35
and so sin theta = (opp side) / (hypotenuse) = (√35) / 6
and tan theta = [(√35) / 6] / (1/6), or √35
Find the output, h, when the input,
is -18.
h = 17+ 6
h=?
When the input x is -18, the output h is 14. The answer is obtained using substitution method.
What is substitution method?
One of the algebraic techniques for solving simultaneous linear equations is the substitution approach. It entails changing any variable's value from one equation to the other by substituting it in. In this manner, a pair of linear equations are combined into a single, simple linear equation with just one variable.
Now, we are given h = 17+x/6
So, when the input x is -18, using substitution method,
h=17+(-18/6)
=17+(-3)
=17-3
=14
Hence, when the input x is -18, the output h is 14.
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help please sorry again
Answer:
C. 2 and 6
Step-by-step explanation:
2 and 6 are the zeros because they are both on X
Y equals 135.2 3X -245, 121.9
The value of y at x = 121.9 for the expression y = 3x - 245 will be 120.7.
What is an expression?Expression in maths is defined as the relation of numbers variables and functions by using mathematical signs like addition, subtraction, multiplication and division.
Given that the expression is y = 3x - 245. The value of x is 121.9.
The solution for the value of y will be calculated as:-
y = 3x - 245
y = ( 3 x 121.9 ) - 245
y = 365.7 - 245
y = 120.7
Therefore, the value of y for the given expression will be 120.7.
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The complete question is given below.
Find the value of y for the expression y = 3x - 245 at x = 121.9.
Solve the following Linear Programming Problem by Graphical Method:
Max z = 15x1 + 20 xz x₁ + 4x₂ ≥ 12 x₁ + x₂ ≤ 6 s.t., and x₁, x₂ ≥ 0
The solution to the linear programming problem is:
Maximum value of z = 120
x₁ = 0, x₂ = 6
To solve the given linear programming problem using the graphical method, we first need to plot the feasible region determined by the constraints and then identify the optimal solution.
The constraints are:
x₁ + x₂ ≥ 12
x₁ + x₂ ≤ 6
x₁, x₂ ≥ 0
Let's plot these constraints on a graph:
The line x₁ + x₂ = 12:
Plotting this line on the graph, we find that it passes through the points (12, 0) and (0, 12). Shade the region above this line.
The line x₁ + x₂ = 6:
Plotting this line on the graph, we find that it passes through the points (6, 0) and (0, 6). Shade the region below this line.
The x-axis (x₁ ≥ 0) and y-axis (x₂ ≥ 0):
Shade the region in the first quadrant of the graph.
The feasible region is the overlapping shaded region determined by all the constraints.
Next, we need to find the corner points of the feasible region by finding the intersection points of the lines. In this case, the corner points are (6, 0), (4, 2), (0, 6), and (0, 0).
Now, we evaluate the objective function z = 15x₁ + 20x₂ at each corner point:
For (6, 0): z = 15(6) + 20(0) = 90
For (4, 2): z = 15(4) + 20(2) = 100
For (0, 6): z = 15(0) + 20(6) = 120
For (0, 0): z = 15(0) + 20(0) = 0
From the evaluations, we can see that the maximum value of z is 120, which occurs at the corner point (0, 6).
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A particular fortune cookie lists four two-digit positive integers as your lucky numbers. The first three are 57, 13, and 72, but you got sauce on the last one and can't read it. If the sum of the digits of all four numbers equals $\frac{1}{5}$ of the sum of all four numbers, what is the smallest possibility for the fourth lucky number
Answer:
38
Step-by-step explanation:
Let the missing number be 10x + y, where x is the tens digit, and y is the ones digit.
5 + 7 + 1 + 3 + 7 + 2 + x + y = (1/5)(57 + 13 + 72 + 10x + y)
25 + x + y = (1/5)(142 + 10x + y)
125 + 5x + 5y = 142 + 10x + y
4y = 5x + 17
y = (5/4)x + 17/4
y = 1.25x + 4.25
x must be 1 less than a multiple of 4.
Try x = 3.
y = 1.25 × 3 + 4.25
y = 8
The number is 3(10) + 8 = 38
Check:
5 + 7 + 1 + 3 + 7 + 2 + 3 + 8 = 36
57 + 13 + 72 + 38 = 180
36 = (1/5)(180)
36 = 36
38 is correct.
Solve for
y in terms of x. (Isolate y)
x-y=6
anthony can run at the rate (in meters per minute) shown in the graph below) which of the following best describes anthony’s rate of speed
Step-by-step explanation:
no this is a test I cant hlep i will tell ms.jules you are searching for the answers
q(m + p); use m = 3, p = 1, and q = 4
Answer:
16
Step-by-step explanation:
Q(M + P)
4(3 + 1)
4(4)
16
There are two types of improper integrals. Write two improper integrals, one of each type, and state why each is improper.
Write, but do not evaluate, the partial fractions decomposition of (9x^2 – 4)/ (x−9)^2(x^2−9)(x2+9)
Improper integrals: Improper integrals are integrals with an infinite region of integration or integrands that have an infinite discontinuity within their limits.
Improper integrals are classified into two types: Type I and Type II.
Let's see both of them below:
Type I Improper Integrals:
If the limit, as b approaches a from the right-hand side, of the integral of f(x) from a to b does not exist, then the Type I improper integral is represented by ∫a to ∞ f(x)dx, or∫−∞ to a f(x)dx.
Because the integral of f(x) from a to b has no limit as b approaches a from the right-hand side, this occurs.
Type II Improper Integrals: If f(x) has an infinite discontinuity in the interval (a,b) or at b, then the Type II improper integral is represented by∫a to b f(x)dx = lim h→b- ∫a to h f(x)dx or ∫b to ∞ f(x)dx = lim n→∞ ∫b to n f(x)dx. This occurs since the interval of integration contains an infinite discontinuity.
In other words, if f(x) has an infinite discontinuity in (a,b) or at b, the integral of f(x) from a to b, or from b to infinity, does not converge.
Partial fractions decomposition of (9x²-4)/[(x-9)²(x²-9)(x²+9)] can be given as shown below:
For a given rational function whose denominator is a product of quadratic factors, partial fractions are a method of reducing it to a sum of simpler fractions. In order to locate the coefficients A, B, C, D, E, and F in partial fraction decomposition of the given rational function, follow the steps below.
The denominators of partial fraction can be shown as follows;
\($$\frac{9{x}^{2}-4}{\left(x-9\right)^{2}\left(x^{2}-9\right)\left(x^{2}+9\right)}=\frac{A}{x-9}+\frac{B}{\left(x-9\right)^{2}}+\frac{C}{x+3}+\frac{D}{x-3}+\frac{E}{x^{2}+9}+\frac{F}{x+3}$$\)
Multiply both sides of the equation by the common denominator, which is; (x - 9)²(x + 3)(x - 3)(x² + 9)
\($$9{x}^{2}-4=A\left(x-9\right)\left(x+3\right)\left(x-3\right)\left(x^{2}+9\right)+B\left(x+3\right)\left(x-3\right)\left(x^{2}+9\right)\)+\($$C\left(x-9\right)\left(x-3\right)\left(x^{2}+9\right)+D\left(x-9\right)\left(x+3\right)\left(x^{2}+9\right)+E\left(x-9\right)\left(x+3\right)\left(x-3\right)+F\left(x-9\right)^{2}\left(x+3\right)$$\)
Substitute the value of x=-3 to get the value of C.
\($$9(-3)^{2}-4=C(-3-9)(-3-3)(-3^{2}+9)+\cdots$$\)
\($$=C(-12)(-6)(-18)=C(12)(6)(18)$$\)
Therefore, C = \($ \frac{- 1}{27}$\)
Substitute the value of x=3 to get the value of D.
\($$9(3)^{2}-4=D(3-9)(3+3)(3^{2}+9)+\cdots$$\)
\($$=D(-6)(6)(18)=D(6)(-6)(18)$$\)
Therefore, D = \($ \frac{1}{27}$\)
Let \($x^{2}+9=y$\)
Substitute the values of A, B, E, and F to get the value of C.
\($$9{x}^{2}-4=A(x-9)(x+3)(x-3)(x^{2}+9)+\cdots$$\)
\($$+B(x+3)(x-3)(x^{2}+9)+C(x-9)(x-3)(x^{2}+9)+D(x-9)(x+3)(x^{2}+9)+\cdots$$\)
\($$+E(x-9)(x+3)(x-3)+F(x-9)^{2}(x+3)$$\)
\($$9{x}^{2}-4=\left[A(x-9)(x+3)(x-3)+\cdots\right]+\left[B(x+3)(x-3)(x^{2}+9)+\cdots\right]$$\)
\($$+\left[\frac{-1}{27}(x-9)(x-3)(x^{2}+9)+\cdots\right]+\left[\frac{1}{27}(x-9)(x+3)(x^{2}+9)+\cdots\right]+\left[E(x-9)(x+3)(x-3)\)\($$+\cdots\right]+\left[\frac{F}{(x-9)}(x-9)^{2}(x+3)+\cdots\right]$$\)
\($$=\frac{1}{y-9}\left(\frac{A}{x-9}+\frac{B}{(x-9)^{2}}+\frac{C}{x+3}+\frac{D}{x-3}\right)+\frac{E}{y}+\frac{F}{y-9}$$\)
Multiply both sides by \($x^{2}-9$\) to get rid of the y variable.
\($$9{x}^{2}-4=\frac{A(x+3)(x-3)(y-9)}{y-9}+\frac{B(x-9)(y-9)}{(x-9)^{2}}+\frac{C(x-9)(x+3)(y-9)}{x+3}$$\)
\($$+\frac{D(x-9)(x+3)(y-9)}{x-3}+\frac{E(x+3)(x-3)}{y}+\frac{F(x-9)(y-9)}{y-9}$$\)
\($$=A(x+3)(x-3)+B(x-9)+C(x-9)(x+3)+D(x-9)(x+3)+E(x+3)(x-3)(x^{2}+9)+F(x-9)^{2}(x+3)$$\)
Let's solve the above equation.
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persevere of all the students at north high school, 25% are enrolled in algebra and 20% are enrolled in algebra and health. a. if a student is enrolled in algebra, find the probability that the student is enrolled in health as well. p(algebra)
The probability that a student enrolled in algebra is also enrolled in health is 0.8.
Let's denote the event of a student being enrolled in algebra as A and the event of a student being enrolled in health as H. We are given that 25% of the students are enrolled in algebra (P(A) = 0.25) and 20% of the students are enrolled in both algebra and health (P(A ∩ H) = 0.20).
We want to find P(H|A), the probability that a student is enrolled in health given that the student is enrolled in algebra.
Using the conditional probability formula:
P(H|A) = P(A ∩ H) / P(A)
We substitute the given values:
P(H|A) = 0.20 / 0.25
Simplifying this expression:
P(H|A) = 0.80
Therefore, the probability that a student enrolled in algebra is also enrolled in health is 0.80, or 80%.
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The length of a planet's orbit around a star is approximately 18,950,000 km.
It takes the planet about 940 Earth days to complete a full orbit.
What is the planet's average speed in kmh-1 to 3sf?
Answer:
The planet's speed is 18,950,000 km per 940 days
which equals
20,159.5744680851 kilometers per day
Dividing that by 24 gives us the planetary speed in km / hour which is
839.982269503546 kilometers per hour.
I have no idea what 3sf means so I can't answer that.
Step-by-step explanation:
Write the equation of a parabola with focus (-2,5) y = 3. Show your work, including a sketch.
The equation of the parabola with focus (-2, 5) and directrix y = 3 is y = \((1/4)x^2 + x + 5.\)
To write the equation of a parabola with focus (-2, 5) and directrix y = 3, we can use the standard form of the equation of a parabola:
\((x - h)^2 = 4p(y - k)\)
Where (h, k) is the vertex of the parabola and p is the distance from the vertex to the focus or directrix.
First, let's determine the vertex of the parabola. The vertex lies halfway between the focus and the directrix, so its y-coordinate is the average of the y-coordinates of the focus and the directrix:
Vertex y-coordinate = (5 + 3) / 2 = 8 / 2 = 4
Since the directrix is a horizontal line, the vertex has the same y-coordinate as the directrix. Therefore, the vertex is (h, k) = (-2, 4).
Next, let's determine the value of p. The distance from the vertex to the focus (or directrix) is p. In this case, the focus is (-2, 5), so the distance from the vertex to the focus is:
p = 5 - 4 = 1
Now we can write the equation of the parabola using the vertex and the value of p:
\((x - (-2))^2 = 4(1)(y - 4)\)
\((x + 2)^2 = 4(y - 4)\)
Expanding the square on the left side:
(x + 2)(x + 2) = 4(y - 4)
(x^2 + 4x + 4) = 4y - 16
Simplifying the equation:
\(x^2 + 4x + 4 = 4y - 16\)
x^2 + 4x + 20 = 4y
Rearranging the terms:
4y = x^2 + 4x + 20
Finally, dividing both sides by 4 to isolate y, we get the equation of the parabola:
\(y = (1/4)x^2 + x + 5\)
So, the equation of the parabola with focus (-2, 5) and directrix y = 3 is y = \((1/4)x^2 + x + 5.\)
To sketch the parabola, plot the focus (-2, 5) and the directrix y = 3 on a graph. The vertex is also located at (-2, 4). The parabola opens upwards because the coefficient of x^2 is positive. Use the equation to plot additional points and sketch the curve symmetrically around the vertex.
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Jessica and Laura are shopping for new clothes at a store that is going out of business. The different brands of shirts are all the same price, and the same goes for pants. At the store, Jessica purchases 3 shirts and 4 pairs of pants for a total of $90. Laura purchases 4 shirts and 2 pairs of pants for a total of $70.
Given Jessica and Laura's expenditure on shirts and pants, the equation to solve for the price of each shirts and pants is:
3s + 4p = 90
4s + 2p = 70
Let
Cost of each shirts = s
Cost of each pants = p
Jessica:
3s + 4p = 90 (1)
Laura:
4s + 2p = 70 (2)
Multiply (2) by 2
8s + 4p = 140 (3)
8s + 4p = 140 (3)3s + 4p = 90 (1)
Subtract (1) from (3) to eliminate p
8s - 3s = 140 - 90
5s = 50
s = 50/5
s = $10
substitute s = 10 into (1)
3s + 4p = 90 (1)
3(10) + 4p = 90
30 + 4p = 90
4p = 90 - 30
4p = 60
p = 60/4
p = $15
Therefore, the cost of each shirts is $10 and the cost of each pants is $15
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How to solve -6v - 5 > 13
Answer:
you use division then add then you get the answer
Step-by-step explanation:
Each month, a phone company charges $20 for 500 minutes of talk time plus $0.45 for each additional minute. Unlimited texting costs $30 more. Choose an expression to show the cost of a talk-and-texting plan for one month, given x minutes over 500.
Answer:
50+45x
Step-by-step explanation:
if p=(3,1) and Q=(-3,-7), find the equation of the circle that has segment PQ as the diameter (x-{?})^2+(y-{?})^2={?}
Answer:
x² + (y + 3)² = 25
Step-by-step explanation:
the centre (C) of the circle is at the midpoint of the diameter.
using the midpoint formula
midpoint = ( \(\frac{x_{1}+x_{2} }{2}\) , \(\frac{y_{1}+y_{2} }{2}\) )
with (x₁, y₁ ) = P (3, 1 ) and (x₂, y₂ ) = Q (- 3, - 7 )
C = ( \(\frac{3-3}{2}\) , \(\frac{1-7}{2}\) ) = ( \(\frac{0}{2}\) , \(\frac{-6}{2}\) ) = (0, - 3 )
the radius r is the distance from the centre to either P or Q
using the distance formula
r = \(\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }\)
with (x₁, y₁ ) = C (0, - 3 ) and (x₂, y₂ ) = P (3, 1 )
r = \(\sqrt{(3-0)^2+(1-(-3)^2}\)
= \(\sqrt{3^2+(1+3)^2}\)
= \(\sqrt{3^2+4^2}\)
= \(\sqrt{9+16}\)
= \(\sqrt{25}\)
= 5
the equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k ) are the coordinates of the centre and r is the radius
here (h, k ) = (0, - 3 ) and r = 5 , then
(x - 0 )² + (y - (- 3) )² = 5² , that is
x² + (y + 3)² = 25
A blueprint of a house shows a wall that is 5 inches long. If the blueprint is drawn to a scale of 1:60, what is the actual length of the wall in the house?
a
25 feet
b
5/60 feet
c
36 feet
d
12 feet
Answer:
12 feet
Step-by-step explanation:
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3. It costs Margo a processing fee of $3 to rent a storage unit, plus $17 per month to keep her belongings in the unit. Her friend Carissa wants to store a box of her belongings in Margo's storage unit and tells her that she will pay her $1 toward the processing fee and $3 for every month that she keeps the box in storage. Write an expression that represents how much Margo will have to pay for the storage unit if Carissa contributes. Then, determine how much Margo will pay if she uses the storage unit for 6 months.
The Expression that represents how much Margo will have to pay for the storage unit if Carissa contributes is 14m + 2 while Margo will pay $86 if she uses the storage unit for 6 months.
What is a Word Problem?A word problem is a mathematical exercise where significant background information on the problem is presented in ordinary language rather than in mathematical notation.
Let m represent amount of monthly payments
Margo's payment = 17m + 3
Carissa's payment = 3m + 1
The payment will be = 17m + 3 - (3m + 1)
Total payment = 14m + 2
For 6 months, m = 6
Substituting in the equation 14m + 2
Payment for 6 months = 14(6) + 2
Payment = $86
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I don’t know how to solve for p.
Answer:
p=12
Step-by-step explanation:
DBC = 180
ABE = 180
ABC + DBA = 180
ABC = (5p -28)
DBA + (12p -4)
CBD = ABC + DBA = 180
-------------------------------------------------
180 = (5p - 28) + (12p + 4)
180 = 17p - 24
204 = 17p
12 = p
p = 12
------------------------------------------------------
180 = (5(12) - 28) + (12(12) +4)
180 = 60 - 28 + 144 +4
180 = 180
find the value of the variable
Answer:
x=5
Step-by-step explanation:
6:5
x:4, so x =5
The side also looks a little bigger than 4.
Hope it Helps
Alice gets a job selling boots, and is given the option of wages plus commission, or commission only. In the first option, she would earn $33 in wages for each day of work, plus $2.50 for every pair of boots sold. Under the commission only option, she would earn no wages, and $3.25 for every pair of boots sold. How many pairs of boots would Alice have to sell in one day to make the two options equal?
Answer:
44 pairs of boots
Step-by-step explanation:
As per two options given to Alice,
1). Wages of $33 for each day work + commission of $2.5 for every pair sold.
If Alice sells x pairs of boots in a day, then total amount earned by Alice,
= (33 + 2.5x)
2). Commission of $3.25 for every boot sold.
If Alice sold x pairs of boots, total earnings of the day = 3.25x
If earning of Alice is equal in both the plans,
(33 + 2.5x) = 3.25x
3.25x - 2.5x = 33
0.75x = 33
x = 44
Therefore, for the sales of 44 pairs of the boots Alice will earn equal by both the plans.
Help me please I will give brainliest!
Answer:
the answer is 1 1/4
Step-by-step explanation:
1/4 multiple 5= 5/4 or 1 1/4
i need help (links will be reported and wrong answers)
Answer:
40 cm^3
5 x 8 x 1
hope this helps
have a good day :)
Step-by-step explanation:
y=3x y=18 solve for x
Answer:
6=x
Step-by-step explanation:
y= 18; y= 3x
18=3x
18/3 = 3x/3
6=x
Hope this helps!