If the speed of a car with a turbo engine can be modeled as a function of time using the parabolic equation s(t) = 2t, how many seconds will it take the car to exceed the 65 mph?

Answer: 240.8 m/s & 8.669x10^8 km/hr

Explanation: a) V= \(\frac{602m}{2.50s}=240.8 m/s\) or 2.408x10^2 m/s (when you divide, final units just become the top unit over the bottom unit)

b) V=    \(\frac{602m}{2.50s}X\frac{3600s}{1hr}X\frac{1000km}{1m}=8.669X10^8\)

(each unit cancels so the first seconds cancel and turn into hours and then the meters cancel and turn into km)

The number of waves present in the picture is one wave

The wavelength of the wave is 5 cm

The frequency of the wave is the number of waves per second.

The period of the wave is the time taken for one complete wave oscillation.

The speed of the wave is the distance covered per second

The properties of a wave are the characteristics that are used to identify waves.

The properties of waves include:

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A sugar water solution does not conduct electricity because it does not have free ions that can carry electric charge.

When sugar dissolves in water, it does not dissociate into ions, which are necessary for the flow of electricity through a solution.Electricity conduction requires the presence of free-moving ions to carry the electric charge. In a sugar water solution, there are no free-moving ions, and therefore, it cannot conduct electricity. Therefore, a sugar water solution does not conduct electricity and is considered to be a non-electrolyte.

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Answer:

C.

Explanation:

Apex says so

For an object sliding at velocity v with a force of friction \(F\) and a normal force \(Fn\) , an equation that can be used to calculate the coefficient of kinetic friction \(\mu_k\)  is

\(\mu_k=\dfrac{F}{Fn}\)

It is a type of resistive force which comes to play when two contacting surfaces have relative motion with respect to each other.

in general, the coefficient of kinetic friction (\(\mu_k\)) is slightly less than the coefficient of static friction(\(\mu_s\)).

The coefficient of kinetic friction is calculated by the mathematical expression

\(\mu_k=\dfrac{F}{Fn}\)

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The sound pressure level produced within the roof void as a result of the plant room noise is calculated to be 48 dB.

To determine the sound pressure level in the roof void, we utilize the sound reduction index of the plant room wall and the sound pressure level in the plant room. The formula used for this calculation is L2 = L1 - R, where L2 represents the sound pressure level in the roof void, L1 denotes the sound pressure level in the plant room, and R signifies the sound reduction index of the plant room wall adjoining the roof void. Given that the sound pressure level in the plant room is 61 dB and the sound reduction index of the plant room wall is 13 dB, we substitute these values into the formula to find the sound pressure level in the roof void:

L2 = 61 dB - 13 dB

L2 = 48 dB

Hence, the sound pressure level produced within the roof void as a result of the plant room noise is determined to be 48 dB. To further reduce the sound pressure level from the plant room to the adjacent rooms, there are several recommended strategies. One approach is to improve the sound insulation of the common wall between the plant room and the adjacent rooms. This can involve increasing the sound reduction index of the wall by adding sound-absorbing materials or panels, or enhancing the sealing of any gaps or openings to minimize sound leakage.

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During the Tau Tauri phase of a protostar's evolution, the brightness decreases ( D )

Option A is incorrect because the forms long before the Tau Tauri phase. Option B is incorrect because the decreasing of surface area does not stop until nuclear ignition. Option C is incorrect because the brightness increases before and after the Tau Tauri phase and not during the Tau Tauri phase. Option E is incorrect because the nuclear burning ends the Tau Tauri phase.

Since the brightness increases before and after the Tau Tauri phase, during the Tau Tauri phase the brightness actually decreases. When the surrounding envelope has cleared in the third phase is called the Tau Tauri phase.

Therefore, during the Tau Tauri phase of a protostar's evolution, the brightness decreases ( D )

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A. It takes about 4 seconds for the stone to hit the bottom of the cliff. B. The horizontal distance the stone strike the ground is 20 m. C. The horizontal and vertical components of velocity of the stone as it hits the ground is 5.0 m/s, and -39.24 m/s (downward) respectively.

A. The time it takes a stone to hit the bottom of the cliff can be determined using the kinematic equation for displacement:

`Δy = viyt + 1/2at²`,

where Δy is the vertical displacement, viy is the initial vertical velocity, a is the acceleration due to gravity, and t is time.The initial vertical velocity of the stone is zero since it was thrown horizontally. Therefore, we have:

Δy = 78.4 m and a = -9.81 m/s² (downward).

Substituting these values, we get:

78.4 m = 0 + 1/2(-9.81 m/s²)t²

t ≈ 4 seconds.

B. The horizontal distance traveled by the stone is given by the formula:

`d = vixt`,

where d is the horizontal distance, vix is the initial horizontal velocity, and t is time.

Since there is no horizontal acceleration acting on the stone, vix remains constant at 5.0 m/s.

Thus, we have: d = 5.0 m/s × 4 s = 20 m.

Therefore, the stone strikes the ground 20 meters from the base of the cliff.

C. The horizontal component of velocity remains constant at 5.0 m/s since there is no horizontal acceleration acting on the stone. The vertical component of velocity can be found using the kinematic equation:

`vf = vi + at`,

where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is time.

When the stone hits the ground, its final vertical velocity is -vfy (downward), and its initial vertical velocity is zero.

Substituting these values, we get:

-vfy = 0 + (-9.81 m/s²) × 4 s

vfy ≈ -39.24 m/s (downward).

Therefore, the horizontal component of velocity is 5.0 m/s, and the vertical component of velocity is -39.24 m/s (downward).

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Answer:

Explanation:

2. a

3. c

Answer:

A  it is still at the same passe and it is going back down

Explanation:

Answer:

The correct answer to your question is A. The object is moving at a constant, negative, velocity. It is negative because it is moving back towards the origin.

Explanation:

The magnetic flux through a loop can be calculated using the formula:

Φ = B * A * cos(θ)

Where:

- Φ is the magnetic flux.

- B is the magnetic field strength.

- A is the area of the loop.

- θ is the angle between the magnetic field direction and the normal to the loop.

Given the values:

- A = 0.27 m² (area of the loop).

- B = 0.37 T (magnetic field strength).

- θ = 43° (angle between the magnetic field and the normal to the loop).

We can substitute these values into the formula to calculate the magnetic flux:

Φ = (0.37 T) * (0.27 m²) * cos(43°)

Using a calculator or trigonometric table, we find:

Φ ≈ 0.108 T·m²

Therefore, the magnetic flux through the loop is approximately 0.108 T·m².

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\(\\ \sf\longmapsto m1v1+m2v2=(m1+m2)v3\)

\(\\ \sf\longmapsto 95(4.1)+85(5.5)=(95+85)v3\)

\(\\ \sf\longmapsto 389.5+467.5=180v3\)

\(\\ \sf\longmapsto 857=180v3\)

\(\\ \sf\longmapsto v3=857/180\)

\(\\ \sf\longmapsto v3=4.76m/s\)

Queremos crear un diagrama general para calcular el área de un triangulo.

Este será algo como:

Como naturalmente habra algunas variaciones segun el programa que utilicemos, lo voy a escribir de forma bastante general.

Primero definamos nuestras variables:

Por ejemple, en fortran usariamos algo como:

real:: B, H, A

Donde B será la variable que usaremos para la base, H para la altura, y A para el área.

Luego tenemos que escribir en pantalla algo que le diga al usario que debe introducir la base y el area.

Luego el programa debe ser capaz de leer ese input.

con algo de la forma:

B = read*input 1

H = read*input 2

Una vez tenemos definidas las variables, simplemente calculamos el área del triangulo:

A = H*B/2

Finalmente la podemos mostrar en pantalla con algo como:

print(A).

Lo que nos mostraría el valor del área.

Concluyendo, el diagrama en general sería:

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Answer:

51.2 m/

Explanation:

The headwind will slow down the airplane and make it move slower relative to the ground     98.7 - 47.5 = 51.2 m/ relative to ground

Answer:

The extension is directly proportional to the force applied.

ex: if the force is doubled, the extension doubles. This works until the limit of proportionality is exceeded.

Hope this helped~

Explanation:

Answer:

the extension will also double, unless the spring has reached its limit of proportionality because of Hooke's law: The extension of a spring is directly proportional to the force applied, provided that the limit of proportionality is not exceeded.

The common velocity of clay 1 and clay 2 is 15 m/s. Option C

We know that a collision can be said to be inelastic when the momentum and the kinetic energy are not conserved. This implies that rather than having the objects move out in different directions, the objects would rather stick together and just move in the same direction.

In this case we would also need the law of the conservation of linear momentum. Recall that according to this law, the momentum before collision  would just be the same as the momentum after Collison.

Thus;

Momentum before collision = momentum after Collison

(2100 * 20) + (2500 * 0) = (2100 + 2500)v

Where v is the common velocity

v = 42000/4600

v =  15 m/s

Thus they would have the common velocity of 15 m/s

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Answer:

Velocity is the rate of change of displacement. Acceleration is the rate of change of velocity. Velocity is a vector quantity because it consists of both magnitude and direction. Acceleration is also a vector quantity as it is just the rate of change of velocity.

Condensed water droplets collect other water droplets to form the collector drop until they fall from the clouds as rain. In this way rain is formed in the tropics where the air is warmer.

A significant volume of water evaporates and is released into the atmosphere when water bodies are heated during the day. Evaporation is the term for this. Water vapour is carried upward by the hot air as it rises. The air cools and expands as it rises. Condensation is the term for this occurrence. Clouds are created as a result of water vapour condensation. With the assistance of the wind, these clouds are transported away, and when they become heavy, they drop to the ground as rain.

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Answer:

I believe it would be Pennsylvania and New Jersey they both border Maryland. Didn't see any other states that border Maryland with West Virginia and Virginia being exempt from the question.

Explanation:

Answer:  the correct answer is Maryland and Virginia

Explanation:  

Answer:

is called matter :)

Explanation:

If a ball is given a push so that it has an initial velocity of 2 m/s down a certain inclined plane, then the distance it has rolled after t seconds is s = 2t + t². Then it takes 11 seconds for the velocity to reach 24 m/s. The correct option is D.

To find the time it takes for the velocity of the ball to reach 24 m/s, we need to solve for the time when the velocity function equals 24 m/s.

The velocity function is the derivative of the distance function, so we'll first find the derivative of the distance function s = 2t + t² with respect to time t:

ds/dt = d/dt(2t + t²)

ds/dt = 2 + 2t

Now we can set the velocity function equal to 24 m/s and solve for t:

2 + 2t = 24

Subtracting 2 from both sides:

2t = 22

Dividing both sides by 2:

t = 11

Therefore, it takes 11 seconds for the velocity to reach 24 m/s.

The correct answer is (d) 11 seconds.

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The mathematical model and parameters that define and fix a coordinate system assigned to a reference frame of physical monuments is Geodetic Datum.

A geodetic datum is a coordinate system used to locate points on the Earth's surface. It defines a reference frame of physical monuments or reference points, which are related to the center of the Earth by a datum transformation. This transformation provides a connection between a global Cartesian coordinate system (such as WGS84) and the local geodetic coordinate system of the region of interest. This connection is specified by a set of parameters that define the position and orientation of the reference frame relative to the global Cartesian coordinate system.

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The motion represented by a horizontal line on a distance is object at rest which means its distance is not changing with time.

We begin our investigation of motion by looking at objects that are extremely little in proportion to the scale of their journey through space. So that humans can deal with only an object in just this manner, we call it a particle. This chapter looks at the case at which a particle moves in such a straight path.

The coordinate of the particle, given by x or y, specifies its location. The particle's coordinate varies with time, t, as it moves. The displacement x is just the shift in position of the particle from x1 to x2, with x = x2 -X1.

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Answer:

The answer is "Y → X → Z".

Explanation:

In this question, the chart is missing and the question is not complete that's why we search this question and only give its correct answer that's is defined above, and please find the complete question in the attached file.

Answer:

Explanation:

Using the formula : E = mc²

Where m = mass = 6.8 × 10^-6 kg

c = speed of light = 3 ×10^8 m/s

The amount of joules of energy that would be produced equals :

Plugging in our values :

E = mc²

E = (6.8 × 10^-6) kg × (3 ×10^8)²m/s

E = (6.8 × 10^-6) kg × 9 × 10^16 m/s

E = 61.2 × 10^(-6 + 16)

E = 61.2 × 10^10 J

Answer:

E = 6.12 × 1011 kg × m2/s2

Explanation:

The largest repulsive force is when the charges are equal and have the same magnitude, given that the charges are stationary and separated by a distance r.

Coulomb's law states that the electrical force between two charged objects is directly proportional to the product of the quantity of charge on the objects and inversely proportional to the distance between them. The formula for

Coulomb's Law is: F = k(q1q2 / r^2)where F is the force between the charges, q1, and q2 are the magnitudes of the charges, r is the distance between the charges, and k is Coulomb's constant. Coulomb's constant, k, is equal to 9 x 10^9 Nm^2/C^2.

To calculate the force, we have to multiply Coulomb's constant, k, by the product of the charges, q1 and q2, and divide the result by the square of the distance between the charges, r^2.

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