Answer:
Below
Step-by-step explanation:
Square area = s^2
ds/dt = 3
Area = s^2 Find the derivative with respect to t of both sides
area/dt = 2s ds/dt
= 2 (10)(3) = 60 in^2 per sec
For each question below, determine True or False: If a simple random sample is chosen with replacement, each individual has
the same chance of selection on every draw.
The statement If a simple random sample is chosen with replacement, each individual has the same chance of selection on every draw is True.
If a simple random sample is chosen with replacement, it means that after each selection, the chosen individual is placed back into the population before the next selection is made. In this case, each individual in the population has the same chance of being selected for every draw.
The process of replacing the selected individual ensures that the selection probabilities remain constant throughout the sampling process. As a result, each individual has an equal probability of being chosen on each draw, making the statement true.
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1
The graph shows an image of a dilation about the origin with a scale factor of 2.
-10-8-6-4-
2
40
1
What are the coordinates of the pre-image of A', point A?
(-8,-12)
01
8 10 X
As a result, the answer to the provided coordinate plane problem is only choice C), which is the right answer.
What is a coordinate plane?The term "coordinate plane" refers to a two-dimensional region that consists of two number lines. It emerges when the X-axis & Y-axis intersect at a location known as the origin. Using the numbers on a coordinate grid, one can locate points.
Here,
Since, If there is a coordinate plane with both parallel lines, go with option A.
Therefore, there is no cure.
There are hence a finite number of solutions that could be found.
If two lines cross, there is only one potential result for Option B. Consequently, the quantity of potential solutions is.
According to Option C, there must be an endless number of solutions to the system because there are two coinciding lines that provide us an infinite number of junction sites.
The difference between Option D) and Option B) is noted.
Only choice C) is hence the proper one.
Therefore , the solution to the given problem of coordinate plane comes out to be Only choice C) is hence the correct one.
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the hypotenuse of a right triangle measures 12 centimeters and its shorter leg measures 4 centimeters. what is the measure of the larger acute angle of the triangle? round your answer to the nearest tenth of a degree.
The measure of the larger acute angle of the right triangle is 73.7°. This can be calculated using trigonometry and the Pythagorean theorem.
The larger acute angle of the triangle can be found using trigonometry. First, we can find the length of the other leg using the Pythagorean theorem: a² + b² = c², where c is the hypotenuse and a and b are the legs. Plugging in the values we get: 4² + b² = 12², solving for b we get b = √(12² - 4²) = 8√3. Now we can use inverse tangent to find the larger acute angle: tan⁻¹(opposite/adjacent) = tan¹⁽⁸√³/⁴⁾ ≈ 73.7°. So, the measure of the larger acute angle is 73.7°.
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HOTS Question:
Solve: 2xy /x+y = 3/2, x+y≠0 and xy / 2x-y = -3 / 10, 2x-y≠0
\(x = \frac{1}{2}\) and \(y = - \frac{3}{2} \)
Step-by-step explanation:
\( \frac{2x}{x + y} = \frac{3}{2} \)
\( = > \frac{x + y}{xy} = \frac{4}{3} \)
\( = > \frac{1}{x} + \frac{1}{y} = \frac{4}{3} \)---- Eq. 1
Then,
\( \frac{xy}{2x - y} = - \frac{3}{10} \)
\( = > \frac{2x - y}{xy} = - \frac{10}{3} \)
\( = > - \frac{1}{x} + \frac{2}{y} = - \frac{10}{3} \)-- Eq. 2
Let
\( \frac{1}{x} = u\)and
\( \frac{1}{y} = v\).
Then, from Eq. 1 & 2, we get:
\(u + v = \frac{4}{3}\) and
\( - u + 2v = - \frac{10}{3} \)
\( = > 3u + 3v = 4\)and
\( - 3u + 6v= - 10\)
By adding, we get,
\(9v = - 6\)
\( = > v = \frac{ - 6}{9} \)
\( = > v = - \frac{2}{3} \)
Substituting "y" got above in Eq.1, we get,
\( \frac{1}{x} - \frac{2}{3} = \frac{4}{3} \)
\( = > \frac{1}{x} = \frac{6}{3} = 2\)
\( = > x = 2\)
Hence,
\(x = \frac{1}{2} \)
\( = > y = - \frac{3}{2} \)
The value of x in the given expression is ²/₃ and y is -6.
Simplification of the linear equationThe given linear equation can be simplified by equating the variables to the equivalent values as shown below;
\(\frac{2xy}{x + y} = \frac{3}{2} \\\\4xy = 3x + 3y\ \ ---(1) \\\\\)
Equation (2) is obtained as follows;
\(\frac{xy}{2x - y} = \frac{-3}{10} \\\\10xy = -6x + 3y \ ---(2)\)
Multiple equation (1) by 2
8xy = 6x + 6y
Add equation (1) and (2) together
8xy = 6x + 6y
10xy = -6x + 6y
---------------------------
18xy = 12y
divide both sides by "y"
18x = 12
x = 12/18
x = ²/₃
Solve for y
8y x (²/₃) = 6(²/₃) + 6y
16y/3 = 12/3 + 6y
Multiply through by 3
16y = 12 + 18y
-2y = 12
y = -6
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Select the correct answer. Which point lies on the circle represented by the equation (x − 3)2 + (y + 4)2 = 62?
The point that lies on the circle is represented by the equation (x−3)² + (y+4)² = 6² is (-3,-4).
What is an equation of a circle?A circle can be characterized by its center's location and its radius's length.
Let the center of the considered circle be at (h, k) coordinate. Let the radius of the circle be 'r' units.
Then, the equation of that circle would be:
(x-h)² + (y-k)² = r²
The sole point that lies on the circle when a circle is graphed with the equation on the graph and all the specified points are graphed is (-3,-4).
Consequently, the equation (x-3)² + (y+4)² = 6² represents the point on the circle (-3,-4).
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2. Jill makes a blend of brownies for the bake sale. The double-chocolate brownies are $5.50 per plate, and the chocolate-mint brownies are $4.00 per plate. Jill sells more than 11 plates total. Jill also sells less than $66.50 worth of brownies. Using this information, choose the solution set that would be found in the overlapping areas of a graph of Jill's sales. 2. Jill makes a blend of brownies for the bake sale . The double - chocolate brownies are $ 5.50 per plate , and the chocolate - mint brownies are $ 4.00 per plate . Jill sells more than 11 plates total . Jill also sells less than $ 66.50 worth of brownies . Using this information , choose the solution set that would be found in the overlapping areas of a graph of Jill's sales .
By using a graphing calculator, the solution set that would be found in the overlapping areas of a graph of Jill's sales is (15, -4).
How to determine the solution set?First of all, we would assign variables to the blend of brownies that were made by Jill for the bake sale as follows:
Let x be the double-chocolate brownies.Let y be the chocolate-mint brownies.Since Jill sold more than 11 plates in total, we have:
x + y > 11.
Also, Jill sold less than $66.50 worth of brownies:
5.50x + 4.00y < 66.50.
By using a graphing calculator, the solution set that would be found in the overlapping areas of a graph of Jill's sales is (15, -4).
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Use the confidence interval to find the margin of error and the sample mean:
(0.256,0.380)
a.The margin of error is: _____
b.The sample mea is: _____
The confidence interval to find the margin of error and the sample mean:
(0.256,0.380) The sample mean is the average value obtained from the sample data.
To find the margin of error and the sample mean, we need more information.
The confidence interval (0.256, 0.380) provides the range of possible values for the true population mean.
However, without knowing the sample size or the level of confidence associated with the interval, we cannot calculate the margin of error or the sample mean.
The margin of error is typically calculated by multiplying the standard error by the appropriate critical value, based on the desired level of confidence. The sample mean is the average value obtained from the sample data.
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Show that the equation
x4+4y 4= z2 x # 0, y # 0, z #0
has no solutions. It may be helpful to reduce this to the case that x > 0 y > 0, z > 0, (x,y) = 1, and then by dividing by 4 (if necessary) to further reduce this to where x is odd.
There are no solutions to the equation x4 + 4y4 = z2 with x > 0, y > 0, z > 0, (x,y) = 1, and x odd since, we have a4 + b4 = z/2, which contradicts the assumption that (x,y,z) is a solution with (x,y) = 1.
First, we need to show that if there is a solution to the equation above, then there must exist a solution with x > 0, y > 0, z > 0, (x,y) = 1. To see why this is true, suppose there is a solution (x,y,z) to the equation such that x ≤ 0, y ≤ 0, or z ≤ 0. Then, we can negate any negative variable to get a solution with all positive variables. If (x,y) ≠ 1, we can divide out the gcd of x and y to obtain a solution (x',y',z) with (x',y') = 1.
We can repeat this process until we obtain a solution with x > 0, y > 0, z > 0, (x,y) = 1.Next, we need to show that if there is a solution to the equation above with x > 0, y > 0, z > 0, (x,y) = 1, then there must exist a solution with x odd. To see why this is true, suppose there is a solution (x,y,z) to the equation such that x is even. Then, we can divide both sides of the equation by 4 to obtain the equation (x/2)4 + y4 = (z/2)2, which contradicts the assumption that (x,y,z) is a solution with (x,y) = 1. Thus, if there is a solution with (x,y,z) as described above, then x must be odd. Now, we will use Fermat's method of infinite descent to show that there are no solutions with x odd.
Suppose there is a solution (x,y,z) to the equation x4 + 4y4 = z2 with x odd. Then, we can write the equation as z2 - x4 = 4y4, or equivalently,(z - x2)(z + x2) = 4y4.Since (z - x2) and (z + x2) are both even (since x is odd), we can write them as 2u and 2v for some u and v. Then, we have uv = y4 and u + v = z/2. Since (x,y,z) is a solution with (x,y) = 1, we must have (u,v) = 1. Thus, both u and v must be perfect fourth powers, say u = a4 and v = b4. Then, we have a4 + b4 = z/2, which contradicts the assumption that (x,y,z) is a solution with (x,y) = 1. Therefore, there are no solutions to the equation x4 + 4y4 = z2 with x > 0, y > 0, z > 0, (x,y) = 1, and x odd.
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Consider a random variable X with the Student-t distribution with 16df. Find P(−1.2
We need to find the probability P(−1.2 < X < 1.2), where X is a random variable with the Student-t distribution with 16 df. The probability density function of the Student-t distribution is given by:f(x) = Γ((v+1)/2) / {√(vπ)Γ(v/2)(1+x²/v)^(v+1)/2)}, where Γ() denotes the gamma function, v is the degrees of freedom, and x is the argument of the function.
Using the definition of the probability density function, we can integrate this function over the given interval to find the required probability. However, this integration involves the gamma function, which cannot be easily calculated by hand. Therefore, we use software or statistical tables to calculate this probability. Using a statistical table for the Student-t distribution with 16 df, we can find that P(−1.2 < X < 1.2) is approximately 0.741. Thus, the probability that X takes a value between -1.2 and 1.2 is 0.741. Given X is a random variable with the Student-t distribution with 16df. To find the probability P(−1.2 < X < 1.2), we need to use the probability density function of the Student-t distribution.
The probability density function of the Student-t distribution is: f(x) = Γ((v+1)/2) / {√(vπ)Γ(v/2)(1+x²/v)^(v+1)/2)}, where Γ() denotes the gamma function, v is the degrees of freedom, and x is the argument of the function. Using the definition of the probability density function, we can integrate this function over the given interval to find the required probability. However, this integration involves the gamma function, which cannot be easily calculated by hand. Therefore, we use software or statistical tables to calculate this probability. For the given value of 16 df, we can use a statistical table for the Student-t distribution to find the probability P(−1.2 < X < 1.2). From this table, we get that the probability P(−1.2 < X < 1.2) is approximately 0.741. Thus, the probability that X takes a value between -1.2 and 1.2 is 0.741.
The probability P(−1.2 < X < 1.2), where X is a random variable with the Student-t distribution with 16 df, is approximately 0.741.
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Help pleasee
Qn is attached belowww
PLEASE HELPP
Answer:
QR = 65.4 m
Step-by-step explanation:
a. Apply Law of Cosines to find QR:
p² = q² + r² - 2qr × Cos P
p = QR = ?
q = PR = 150 m
r = PQ = 120 m
P = 25°
Plug in the values
p² = 150² + 120² - (2)(150)(120) × Cos(25°)
p² = 22,500 + 14,400 - 36,000 × 0.9063
p² = 36,900 - 32,626.8
p² = 4,273.2
p = √4,273.2
p ≈ 65.4 m (nearest tenth)
QR = 65.4 m
Which of the following functions would be represented by a dashed line passing through the origin and (3,2) shaded above the line
Answer:
Explanation:
Generally, the slope-intercept form of the equation of a line is given as;
\(y=mx+b\)where m = the slope of the line
b = y-intercept of the line
From the question, we're told that the required line will pass through the origin and (3, 2), so we can find our slope(m) of the line using the given coordinates x1 = 0, y1 = 0, x2 = 3, and y2 = 2;
\(m=\frac{y_2-y_1}{x_2-x_1}=\frac{2-0}{3-0}=\frac{2}{3}\)So the slope(m) of the line is 2/3.
Since we're told that the line will pass through the origin, it means that the y-intercept (b) = 0.
Since the gragh will be shaded above the dashed line, it means that the inequality will have a greater than sign(>).
We're told that the line will be dashed, it means that the function have only the greater than sign(>) without the equal to sign(=).
Combining all the information above, the function for the line can be
-3|x-4|=21 solve and show work
Answer: If you are solving for x, then thee is no solution
Step-by-step explanation:
LOLOLOLOL PLS HELP THO
ASAP
WIlLL MARK BRAINLIEST MY GUY LOLOL
Answer:
bruh whats with the LOLOLOO AHHAA
Does anyone know how to solve these types of triangles?
Answer:
x= 101
Step-by-step explanation:
Exterior angle of triangle states that the exterior angle of a triangle is the sum of the 2 opposite interior angles. This is abbreviated as 'ext. ∠ of ∆'. Thus using the exterior angle theorem,
x°= 64° +37° (ext. ∠ of ∆)
x°= 101°
x= 101
_____
Alternative method:
Let the third angle in the triangle be y°.
Since the sum of the angles in a triangle is 180°,
y° +64° +37°= 180° (∠ sum of ∆)
Simplify:
y° +101°= 180°
y°= 180° -101°
y°= 79°
The sum of the angles on a straight line is 180°.
x° +y°= 180° (adj. ∠s on a str. line)
Substitute y°= 79°:
x° +79°= 180°
x°= 180° -79°
x°= 101°
x= 101
Is (5, 1) a solution to the equation y = x
Answer:
Yes
Step-by-step explanation:
Answer:
No, because the coordinates that the slope 1x would make don`t include (5, 1)
Note: A 'solution' implies a coordinate that the slope intersects with
Each time you flip a certain coin, heads appears with probability p. Suppose that you flip the
coin a random number N of times, where N has the Poisson distribution with parameter λ and
is independent of the outcomes of the flips. Find the distributions of the numbers X and Y of
resulting heads and tails, respectively, and show that X and Y are independent.
The distributions of the numbers X and Y of resulting heads and tails [(pλ)^k / k! e^(-pλ)] [(1-p)^λ / (1-p+ p/k+1)] and [(pλ)^m / m! e^(-pλ)] [(1-p)^λ / (1-p+ p/m+1)]. Here, X and Y are independent.
Let X be the number of heads and Y be the number of tails. Then we have:
X + Y = N
We want to find the distributions of X and Y. Let's start with X:
P(X = k) = P(X = k | N = n)P(N = n)
where P(X = k | N = n) is the probability of getting k heads given that the number of flips is n. This is simply a binomial distribution with parameters n and p:
P(X = k | N = n) = (n choose k) p^k (1-p)^(n-k)
where (n choose k) is the binomial coefficient.
The probability of N being equal to n is given by the Poisson distribution:
P(N = n) = e^(-λ) λ^n / n!
Therefore, we have:
P(X = k) = ∑ P(X = k | N = n)P(N = n)
= ∑ (n choose k) p^k (1-p)^(n-k) e^(-λ) λ^n / n!
= e^(-λ) / k! ∑ (n choose k) p^k (1-p)^(n-k) λ^n
= e^(-λ) / k! (pλ + (1-p)λ)^k ∑ ((pλ + (1-p)λ)/λ)^n / (k+1)^n
= e^(-λ) / k! (pλ + (1-p)λ)^k e^(pλ+(1-p)λ) / (k+1)
= [(pλ)^k / k! e^(-pλ)] [(1-p)^λ / (1-p+ p/k+1)]
The first factor in the last expression is the Poisson distribution with parameter pλ, which means that X has a Poisson distribution with parameter pλ.
Similarly, Y has a Poisson distribution with parameter (1-p)λ is [(pλ)^m / m! e^(-pλ)] [(1-p)^λ / (1-p+ p/m+1)]
Now we need to show that X and Y are independent. To do this, we need to show that for any values k and m:
P(X = k and Y = m) = P(X = k) P(Y = m)
Using the expressions we found earlier for P(X = k) and P(Y = m), we have:
P(X = k and Y = m) = e^(-λ) / k! [(pλ)^k e^(-pλ)] [(1-p)^m λ^m e^(-(1-p)λ)]
P(X = k) P(Y = m) = e^(-λ) / k! [(pλ)^k e^(-pλ)] [(1-p)^λ / (1-p+ p/m+1)] e^(-λ) / m! [(1-pλ)^m e^(pλ)]
Notice that the two expressions are the product of two factors, one depending on k only, and the other depending on m only. Therefore, the joint distribution of X and Y factorizes into the product of their marginal distributions, which means that X and Y are independent.
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Aidan has $2,600 currently saved for a speed boat. If he saves $205 per month and his account earns a 1.7% interest rate, how many years will it take before he can buy the $29,000 boat? Enter your answer to two decimal places.
7.95
6.89
9.70
6.69
It will take Aidan approximately 9.70 years to save enough to buy the $29,000 speed boat.
To calculate the time it will take for Aidan to save enough for the speed boat, we can use the formula for compound interest. The formula is given by:
\(Future Value = Present Value * (1 + interest rate)^{(number of periods)}\)
In this case, Aidan currently has $2,600 saved, and he saves an additional $205 per month. The future value (FV) is $29,000, and the interest rate (r) is 1.7% per year. We need to find the number of periods (t) in years. Rearranging the formula, we get:
t = log(FV / PV) / log(1 + r)
Plugging in the values, we have:
t = log((29000 - 2600) / 205) / log(1 + 0.017)
≈ 9.70 years
Therefore, it will take Aidan approximately 9.70 years to save enough to buy the $29,000 speed boat.
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Determine the equation of the line that is parallel to y=2/3x+4 and passes through the point (3,7)
Step-by-step explanation:
If the line is parallel to y=2/3x+4 then,
m=m
slope of eqn y=2/3x+4
m=2/3(On comparing with y= mx + c)
the passing point is (3,7) then,
y-y1 = m(x-x1)
y-7=2/3(x-3)
y-7=2/3x -2
y-7= -4x/3
3y-7= -4x
4x + 3y - 7=0
So, The reqd eqn is 4x + 3y - 7 = 0
PLZZZZZZZZZZZZ PLZZZZZZZZZZZZ PLZZZZZZZZZZZZ PLZZZZZZZZZZZZ help
Answer:
a. option is the correct answer
Question Content Area
Net Present Value
A project has estimated annual net cash flows of $15,000 for ten
years and is estimated to cost $47,500. Assume a minimum acceptable
rate of return of 20%. Use
The required rate of return (or minimum acceptable rate of return) is 20 percent. If the net cash flows are $15,000 per year for ten years, the total cash flow is $150,000. The project's cost is $47,500. We can now apply the net present value formula to determine whether or not the project is feasible.
Net Present Value (NPV) = Cash flow / (1 + r)^n - Cost Where, r is the discount rate, n is the number of years, and Cost is the initial outlay.
Net Present Value = 150000 / (1 + 0.20)^10 - 47500
Net Present Value = $67,482.22
Since the NPV is positive, the project is feasible. When calculating net present value, it's important to remember that a positive NPV implies that the project is expected to generate a return that exceeds the cost of capital, whereas a negative NPV indicates that the project is expected to generate a return that is less than the cost of capital, and as a result, it should be avoided.
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do you think, in ur own opinion? do you think all lives matter or only blm?
I would say alm and blm but I want to hear from you! :)
Answer: when a black person heard u say all lives matter they would absolutely hurt you don’t ever say that infront of a colored one
Step-by-step explanation:
Answer:
i thnik all lives matter
Step-by-step explanation:
help please i dont understand this chile-
Answer:
37.5%
60%
75% and .75
Step-by-step explanation:
1- Which of the following has had the greatest success treating major depression? Select one
A) MAO inhibitors
B) Lithium
C) tricyclic
D) SSRIs
2- Believing that you are being singled out for attention is a (an) Select one
A) delusion of persecution
B) delusion of reference
C) delusion of orientation
D) delusion of grandeur
1. The option D) SSRIs, The greatest success in treating major depression has been observed with the use of selective serotonin reuptake inhibitors (SSRIs).
These drugs are a type of antidepressant that work by increasing the levels of serotonin in the brain. SSRIs are considered to be the most effective medication for the treatment of depression, particularly in the long-term.
2. the option B) delusion of reference ,A belief that an individual is being singled out for attention is known as delusion of reference. Delusions are a common symptom of schizophrenia and other psychotic disorders.
A delusion of reference is characterized by the belief that everyday events or objects have a special meaning that is directed specifically towards the individual. For example, an individual with this delusion may believe that the radio is broadcasting a message meant for them or that strangers on the street are staring at them because they are part of a conspiracy.
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Which statement is true?
Answer:
The answer is B cause all the rest is lower and negatives make the other one wrong so the answer is B hope this helps :)
Answer:
-1.2<6.9 is the statement that's true.
Explanation: - 1.2 is smaller than 6.9
It rain 3.75 inches in 15 hours at the rate how much will it rain in 3.5 hours
Answer:
0.87 inches (or if it meant after 3.5 more hours, 4.37 inches)
Step-by-step explanation:
15/3.5 is 4.29(rounded to the nearest hundredth)
3.75/4.29= 0.87 inches
(or if it meant after 3.5 more hours)
3.5+0.87= 4.37
Let R be region in the fourth quadrant enclosed by the x-axis and the curve y=x^(2)-2kx, where k is a constant. If the area of the region R is 36 , then the value of k is
Therefore, the value of k is 3 if the area of the region R is 36.
To find the value of k, we need to find the bounds of the integral that will give us the area of region R. Since R is in the fourth quadrant and is enclosed by the x-axis and the curve y=x^(2)-2kx, we need to find the x-intercepts of the curve:
x^(2)-2kx=0
x(x-2k)=0
x=0 or x=2k
Since R is in the fourth quadrant, we only need to consider the x-intercept x=2k. Therefore, the bounds of the integral are from x=0 to x=2k.
The area of region R can be found using the following integral:
A = ∫[0, 2k] (x^2 - 2kx) dx
= [x^3/3 - kx^2] from 0 to 2k
= (8k^3)/3 - 4k^3
= (4k^3)/3
Since we are given that the area of region R is 36, we can set up the following equation:
(4k^3)/3 = 36
Simplifying, we get:
k^3 = 27
Taking the cube root of both sides, we get:
k = 3
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Solve for y.
y - 12 = -10
y = 2
y = -22
y = 22
y = -2
Answer:
y = 2
because when you transpose -12 it changes the sign it become positive
How many 1 \5 are in 9?
Answer:
45/5 or 45
Step-by-step explanation:
5x9=45 45/9=9
so therefore there are 45 , 1/5 in 9
The number of times a fraction number 1/5 is present in the integer number 9 will be 45 times.
What is Algebra?Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.
The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.
The number of times a fraction number 1/5 is present in the integer number 9 is calculated by the division of the number 9 by the fraction number 1/5. Then we have
⇒ 9 / (1/5)
⇒ 9 x 5
⇒ 45
The number of times a fraction number 1/5 is present in the integer number 9 will be 45 times.
More about the Algebra link is given below.
https://brainly.com/question/953809
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A sphere with a radius of 3 cm has the same volume as a cone with a radius of 6 cm. What is the height of the cone A) 2 cm B) 3 cm C)4 cm D) 5 cm
Answer:
I belive it would be b. But don't take my word for it
Step-by-step explanation:
Olivia's family drove to Disneyland for spring break. Her mom and dad shared driving duties for a total of 14 hours. Her mom drove 65 miles per hour and her dad drove 60 miles per hour. They drove a total of 895 miles. How many hours did each person drive.
Answer: Dad = 3 hours
Mom = 11 hours
Step-by-step explanation:
Let the number of hours driven by her mum be m.
Let the number of hours driven by her dad be d.
We can form equation from the question as:
d + m = 14 ........... i
60d + 65m = 895.......... ii
Since d + m = 14, d = 14 - m
Substitute 14 - m into d in equation ii
60d + 65m = 895
60(14 - m) + 65m = 895
840 - 60m + 65m = 895
840 + 5m = 895
5m = 895 - 840
5m = 55
m = 11
The mother drove for 11 hours
Since d + m = 14
d + 11 = 14
d = 14 - 11
d = 3
The father drive for 3 hours