If the seventh number is 21 and the ninth number is 55, what’s the tenth number?

Answer:

Area=78m^2

Step-by-step explanation:

4*12=48m^2 <-- The area of a rectangle LxW

12*5=60 60/2=30 <-- The area of a triangle (HxB)/2

30+48=78m^2 Add them together to get the total area

Answer:

Parallel

Step-by-step explanation:

First ecuation

\(y=\frac{1}{3} x+9\)   slope = 1/3

Second equation:

\(x-3y=3\)

\(-3y=-x+3\)  

\(y=\frac{-x+3}{-3}\)

\(y=\frac{1}{3} x-1\)  slope = 1/3

Both equations represent parallel lines because they have the same slope

Hope this helps

Answer:

15

Step-by-step explanation:

Angle 2 is 2x+10

angle 4 is 4x+80

and from the figure we can understand that when we add these 2 equations

We get

6x+ 90= 180

6x = 180 - 90= 90

6x= 90

x = 90 ÷ 6 = 15

answer = 15

Step-by-step explanation:

the final score is just the sum of the individual rounds:

-2 + -3 + -6 + -1 = -2 - 3 - 6 - 1 = -12

Answer:

Answer:

What fair

Step-by-step explanation:

To graph a piecewise function, plot the different parts of the function separately based on the specified conditions or intervals, and ensure continuity at the endpoints.

Here's a step-by-step guide on how to graph a piecewise function:

1. Identify the different conditions or intervals: A piecewise function is defined by different equations or expressions for specific intervals or conditions. Identify these conditions or intervals and the corresponding equations for each interval.

2. Plot the intervals on the x-axis: Identify the range of values for the x-axis based on the given intervals. Mark the intervals on the x-axis accordingly.

3. Graph each part of the function: For each interval, graph the corresponding equation or expression. Treat each part as a separate function within its defined interval.

4. Consider the endpoints of each interval: Pay attention to the endpoints of each interval and determine whether they are included or excluded from the graph. Use open or closed circles to represent the endpoints, depending on whether they are included or excluded.

5. Ensure continuity: Check if the function is continuous across the intervals. Make sure there are no gaps or jumps in the graph where the intervals meet.

6. Label the axes and add any necessary annotations: Label the x-axis and y-axis, and add any necessary annotations such as the function name, equation, or any important points or features.

7. Review and refine: Step back and review the graph to ensure accuracy and clarity. Make any necessary adjustments to the graph to improve its presentation.

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Answer:

6.67lbs

Step-by-step explanation:

let's write cookies as C.

we know dozen means 12 so we multiply 5 by 12 to know how many cookies that the bakery uses 2lbs of butter for.

That would be; 2lbs= 5×12 C

2lbs=60C.

now we can find how much butter is used for a single cookie(C) by dividing both sides by 60;

lbs=C;

C= lbs

since we know what C is, we can use that in finding how much butter will be needed for 200 cookies(C)

200C=200(lbs)

200C= lbs

200C= 6lbs or 6.67lbs

Mary can water an area of approximately 78.5 square feet with the sprinkler.

To find the area that Mary can water with the sprinkler, we need to calculate the area of the circle. The formula for the area of a circle is:

Area = πr^2

Given that the diameter of the circle is 10 ft, we can calculate the radius (r) by dividing the diameter by 2:

r = 10 ft / 2 = 5 ft

Now we can substitute the radius into the formula to find the area:

Area = π(5 ft)^2

Using an approximation of π as 3.14, we can calculate:

Area = 3.14 × (5 ft)^2

Area = 3.14 × 25 ft^2

Area = 78.5 ft^2

Therefore, Mary can water an area of approximately 78.5 square feet with the sprinkler.

Your question is incomplete but most probably your full question attached below

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The median and quartiles fall in the middle age classes.

The median is the middle value in a set of data, meaning that half of the data falls below the median and half falls above it. The quartiles divide the data into four equal parts, with the first quartile (Q1) being the 25th percentile, the second quartile (Q2) being the median or 50th percentile, and the third quartile (Q3) being the 75th percentile.

In terms of age classes, the median and quartiles would fall in the middle age classes. For example, if the age classes were 0-10, 11-20, 21-30, 31-40, 41-50, 51-60, 61-70, 71-80, and 81-90, the median and quartiles would fall in the 21-30, 31-40, and 41-50 age classes.

It is important to note that the specific age classes that the median and quartiles fall in will depend on the distribution of the data. However, they will always fall in the middle age classes, as they represent the middle values of the data set.

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To minimize the mean squared error (mse) in estimating X4, the linear estimator Ẋ4 = a3X3 + a2X2 + aX1 is used. The values of aj, i = 1, 2, 3, and the resulting minimum mse are determined.


To find the values of aj in the linear estimator Ẋ4 = a3X3 + a2X2 + aX1 that minimize the mean squared error (mse), we need to calculate the conditional expectations and covariance. Given that Wi and Xi are mutually independent standard normal random variables, we have X1 = W1, X2 = W2 + 0.9X1, X3 = W3 + 0.9X2 + 0.7X1, and X4 = W4 + (1/2)W3 + (1/4)W2 + (1/8)W1.

By calculating the conditional expectations E[X3|X1, X2] and E[X2|X1], we can determine the values of a3 and a2 that minimize the mse. Once we have these values, we substitute them into the expression for Ẋ4. The resulting expression gives us the estimated value of X4 based on Xi, i = 1, 2, 3, and also provides the minimum mse E[(X4 - Ẋ4)^2].

The detailed calculations for determining the values of aj and the minimum mse require further computation and cannot be provided within the given word limit.

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If d is unknown, the polar equation remains r = (6d) / (1 ± 6*cos(θ)).

To write a polar equation of a conic with the focus at the origin and the given data, we will use the general polar equation for a conic:

r = (ed) / (1 ± e*cos(θ))

where r is the polar distance, e is the eccentricity, d is the distance from the focus to the directrix, and θ is the polar angle.

Since we are given a hyperbola, eccentricity e = 6, and the directrix is represented by r, we can substitute these values into the equation:

r = (6d) / (1 ± 6*cos(θ))

However, we are not given the distance from the focus to the directrix (d). If you have a specific value for d, you can substitute it into the equation to get the final polar equation of the conic.

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Carson Kelly is expected to hit approximately 31 home runs in 2024.

To find how many home runs Carson Kelly is expected to hit in 2024, we can use the formula for compound interest, where the initial amount is the number of home runs he hit in 2019, and the interest rate is the expected growth rate of his home run hitting ability, which is 12 percent or 0.12 as a decimal.

Let H be the number of home runs hit in 2019, and H(n) be the number of home runs hit in year n, then we can write:

H(n) = H * (1 + r)^n

Where r is the growth rate, and n is the number of years into the future.

If we plug in the given values, we can find the number of home runs Carson Kelly is expected to hit in 2024, which is 5 years after 2019.

H = 18 (number of home runs in 2019)

r = 0.12 (growth rate)

n = 5 (number of years into the future)

H(5) = 18 * (1 + 0.12)^5

H(5) = 18 * 1.7623

H(5) = 31.9214

It's important to note that this is simply an estimate based on the given growth rate, and the actual number of home runs he hits in 2024 may vary based on many factors, including injuries, team support, and the skill of opposing pitchers, among others.

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The standard error for the distribution of sample means for a population with a mean of 100 and a standard deviation of 15 and a sample size of 25 is:

3

The standard error for the distribution of sample means can be calculated using the formula:

SE = (standard deviation) / sqrt(sample size)

In this case, the standard deviation is 15 and the sample size is 25. Plugging these values into the formula, we get:

SE = (15) / sqrt(25)

SE = (15) / 5

SE = 3

Therefore, the standard error for the distribution of sample means is 3. This means that the distribution of sample means will have a standard deviation of 3, which is smaller than the standard deviation of the population (15). This is because the larger the sample size, the smaller the standard error, and the more accurately the sample means will represent the population mean.

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7: Graph A

8: Graph B

9: Graph C

therefore: Graph A has infinitely MANY solutions; Graph B has ONE solution; Graph C has NO solution

also!! khan academy has a lesson that talks about this and is super helpful: https://www.khanacademy.org/math/algebra/x2f8bb11595b61c86:systems-of-equations/x2f8bb11595b61c86:number-of-solutions-to-systems-of-equations/a/number-of-solutions-to-system-of-equations-review

funny they were already in order :) also could you please give me brainliest? all my brainliest answers disappeared :/

Step-by-step explanation:

d = a  -  - a   = a + a = 2a

Answer:

D(-4, -3), E(-7, 4), and F(-7, -3).

Step-by-step explanation:

The current coordinates are A(4, 2), B(7, 9), and C(7, 2).

If you reflect the coordinates over the y-axis, the y-values will not be changing, but the signs of the x-values will flip. So, you will have A'(-4, 2), B'(-7, 9), and C'(-7, 2).

When you translate the resulting triangle down 5 units, the y-values will decrease by 5 units. So, the coordinates of triangle DEF will be D(-4, -3), E(-7, 4), and F(-7, -3).

Hope this helps!

Answer:

D (-4, -3)

E (-7, 4)

F (-7,-3)

Step-by-step explanation:

Well triangle ABC reflected over the y-axis to make triangle DEF looks like the image below. ↓

Then we have to translate triangle DEF 5 units down.

With the coordinates D, E, F,

D (-4,2)

E (-7,9)

F (-7,2)

To translate it 5 units down we just subtract the y coordinates by 5.

D (-4, -3)

E (-7, 4)

F (-7,-3)

Thus,

the coordinates for triangle DEF are (-4, -3) , (-7, 4) , (-7,-3).

Hope this helps :)

On solving the provided question, An expression that finds the sum of x and y => X + Y

a collection of numbers, symbols, and operators (like + and ) that represent a value. Examples -  2 + 3 is a formula and there is also the statement 3 x/2. The equals symbol does not appear in expressions. Actually, none of these = ≠ < > ≤ ≥

We frequently have to understand a written phrase in order to write an expression. For instance, the notation x + 6 can be used to represent the phrase "6 added to some number," where x stands for the unknown value.

An expression that finds the sum of x and y -

=> X + Y

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Image is missing, so i have attached it

Answer:

21.07 mm²

Step-by-step explanation:

We will use the Formulas:

Area of semicircle = πr²/2

Area_rectangle = Length x width = Lw

We are given:

Length of rectangle = 14 mm

From the attached image, the diameter of the semicircle is equal to the length of the rectangle.

Thus;

diameter of semicircle = length of rectangle

Therefore,

diameter of semicircle = 14 mm

Also, from the attached image, the radius of the semicircle is equal to the width of the rectangle.

Thus;

diameter of semicircle/2 = radius of semicircle

Hence;

radius of semicircle = 14/2 = 7mm = width of rectangle

Thus;

Area of rectangle = L*w = 14 × 7 = 98 mm²

Area of semicircle = πr²/2 = π×7²/2 = 76.93 mm²

To get the area of the shaded region, we will subtract area of the semi-circle from the area of the rectangle.

Area of shaded region = Area_rectangle - Area_semicircle = 98 - 76.93 = 21.07 mm²

Answer:d*6=t

Step-by-step explanation:

Step-by-step explanation:

The total of the number of computers he sold in 2015 is 67.

The total of the number of computers he sold in 2016 is 61.

The total of the number of computers he sold in 2017 is 71.

He sold 35 computers in Quarter 1, 24 in Quarter 2, 61 in Quarter 3, and 79 in Quarter 4.

He sold the most computers in 2017 and the least in Quarter 2.

Therefore, to find the total number of computers he sold all time, we add 67, 61, and 71 together to get 199.

Hope this helped!

Answer with Step-by-step explanation:

From the given table

(a)

In quarter 1

Computer sold in 2015=12

Computer sold in 2016=15

Computer sold in 2017=8

Total computer sold in quarter 1=12+15+8=35

In quarter 2

Computer sold in 2015=9

Computer sold in 2016=10

Computer sold in 2017=5

Total computer sold in quarter 2=9+10+5=24

In quarter 3

Computer sold in 2015=21

Computer sold in 2016=17

Computer sold in 2017=23

Total computer sold in quarter 3=21+17+23=61

In quarter 4

Computer sold in 2015=25

Computer sold in 2016=19

Computer sold in 2017=35

Total computer sold in quarter 4=25+19+35=79

In 2015

Total number of computer sold=12+9+21+25=67

In 2016

Total number of computer sold=15+10+17+19=61

In 2017

Total number of computer sold=8+5+23+35=71

(b)He sold the most computers in 2017

(c) He sold the least computers in quarter 2.

The coordinates of A'', B'' and C'' are (-1, 4), (-4, 3) and (-1, 2) respectively.

Transformation of geometrical figures or points is the manipulation of a given figure to some other way.

Different types of transformations are Rotation, Reflection, Glide reflection, Translation and Dilation.

Given triangle has coordinates,

A(2, -2), B(5, -3) and C(2, -4).

First the triangle is translated by the rule (x, y) → (x - 1, y + 6)

A(2, -2) becomes A'(2 - 1, -2 + 6) = A'(1, 4).

B(5, -3) becomes B'(5 - 1, -3 + 6) = B'(4, 3)

C(2, -4) becomes C'(2 - 1, -4 + 6) = C'(1, 2)

Then the translated triangle is reflected across the Y axis.

When reflected a point (x, y) across the Y axis, y coordinate remains same and x coordinate flips.

A'(1, 4) becomes A''(-1, 4)

B'(4, 3) becomes B''(-4, 3)

C'(1, 2) becomes C''(-1, 2)

Hence the vertices of the triangle after undergoes translation and reflection becomes A''(-1, 4), B''(-4, 3) and C''(-1, 2).

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Answer : value of x and y in the matrix equation is:

x = -3

y = +4, -4

Step-by-step explanation :

The matrix expression is:

\(\left[\begin{array}{ccc}x+4\\y^2+1\end{array}\right]+\left[\begin{array}{ccc}-9x\\-17\end{array}\right]=\left[\begin{array}{ccc}28\\0\end{array}\right]\)

First we have to add left hand side matrix.

\(\left[\begin{array}{ccc}(x+4)+(-9x)\\(y^2+1)+(-17)\end{array}\right]=\left[\begin{array}{ccc}28\\0\end{array}\right]\)

Now we have to add left hand side terms.

\(\left[\begin{array}{ccc}x+4-9x\\y^2+1-17\end{array}\right]=\left[\begin{array}{ccc}28\\0\end{array}\right]\)

\(\left[\begin{array}{ccc}4-8x\\y^2-16\end{array}\right]=\left[\begin{array}{ccc}28\\0\end{array}\right]\)

Now we have to equating left hand side matrix to right hand matrix, we get:

\(\Rightarrow 4-8x=28\text{ and }y^2-16=0\\\\\Rightarrow 8x=4-28\text{ and }y^2=16\\\\\Rightarrow x=-3\text{ and }y=\pm 4\)

Therefore, the value of x and y in the matrix equation is -3 and +4, -4 respectively.

Answer:

D is wrong. The correct answer choice is C ( x=-3 and y= +4, -4)

Step-by-step explanation:

Math unit test review

Answer:

no

Step-by-step explanation:

becdxhjkc

Answer:

X = -14

All you have to do is type in 2(x+5)=(x-4) in to a algebra calculator and you will get -14

The equilibrium point for the supply and demand equations p² + 4q = 253 and 183p² + 6q = 0 is (q, p) = (3, 10).

To find the equilibrium point, we need to solve the system of equations formed by the supply and demand equations. By substituting the value of q = 3 into the first equation, we get p² + 4(3) = 253, which simplifies to p² + 12 = 253.

Solving this equation gives us p = 10. Substituting the values of q = 3 and p = 10 into the second equation, we get 183(10)² + 6(3) = 0, which simplifies to 18300 + 18 = 0.

Since this equation holds true, we have found the equilibrium point to be (q, p) = (3, 10), where the equilibrium quantity is q = 3 and the equilibrium price is p = 10.

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Main Answer: The value of ∂z/∂s = (e^(s/t))/t - 2t/(s^3)  and ∂z/∂t = -(e^(s/t)) × s/(t^3) + 2/(s^2)

Supporting Question and Answer:

How do you differentiate the function z = ex + 2y with respect to s and t using the chain rule when x = s/t and y = t/s?

To differentiate z with respect to s and t using the chain rule, we substitute the expressions for x and y in terms of s and t, and then differentiate each term separately.

Body of the Solution: To find ∂z/∂s and ∂z/∂t using the chain rule, we'll express z in terms of s and t and then differentiate with respect to each variable separately.

Given: z = e^x + 2y

x = s/t

y = t/s

First, let's express z in terms of s and t by substituting the expressions for x and y:

z = e^(s/t) + 2(t/s)

Now, we'll differentiate z with respect to s using the chain rule:

∂z/∂s = (e^(s/t)) × (1/t) + 2 × (1/s) × (-t/s^2)

Simplifying, we get:

∂z/∂s = (e^(s/t))/t - 2t/(s^3)

Next, we'll differentiate z with respect to t using the chain rule:

∂z/∂t = (e^(s/t)) × (-s/t^2) + 2 × (1/s) × (1/s)

Simplifying, we get:

∂z/∂t = -(e^(s/t)) ×s/(t^3) + 2/(s^2)

Final Answer: Therefore, the partial derivatives are:

∂z/∂s = (e^(s/t))/t - 2t/(s^3)

∂z/∂t = -(e^(s/t)) × s/(t^3) + 2/(s^2)

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The value of function ∂z/∂s = (e^(s/t))/t - 2t/(s^3)  and ∂z/∂t = -(e^(s/t)) × s/(t^3) + 2/(s^2)

How do you differentiate the function z = ex + 2y with respect to s and t using the chain rule when x = s/t and y = t/s?

To differentiate z with respect to s and t using the chain rule, we substitute the expressions for x and y in terms of s and t, and then differentiate each term separately.

find ∂z/∂s and ∂z/∂t using the chain rule, we'll express z in terms of s and t and then differentiate with respect to each variable separately.

Given: z = e^x + 2y

x = s/t

y = t/s

First, let's express z in terms of s and t by substituting the expressions for x and y:

z = e^(s/t) + 2(t/s)

Now, we'll differentiate z with respect to s using the chain rule:

∂z/∂s = (e^(s/t)) × (1/t) + 2 × (1/s) × (-t/s^2)

Simplifying, we get:

∂z/∂s = (e^(s/t))/t - 2t/(s^3)

Next, we'll differentiate z with respect to t using the chain rule:

∂z/∂t = (e^(s/t)) × (-s/t^2) + 2 × (1/s) × (1/s)

Simplifying, we get:

∂z/∂t = -(e^(s/t)) ×s/(t^3) + 2/(s^2)

Final Answer: Therefore, the partial derivatives are:

∂z/∂s = (e^(s/t))/t - 2t/(s^3)

∂z/∂t = -(e^(s/t)) × s/(t^3) + 2/(s^2)

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In order to get the two points which the trend line should go through to best represent the data given in the scatter plot, we have to analyze the graph first. By observing the scatter plot and the given data, it is clear that the plant growth is not a linear relationship, but a curve.

The scatter plot does not show a linear relationship. Hence, to draw the best trend line, we need to connect the points that best fit the curve of the data given. Option D: 6, 2 and 10, 1.75 shows the two points which the trend line should go through to best represent the data given in the scatter plot.

The trend line should be drawn so that it fits the curve of the data, connecting the two points: (6, 2) and (10, 1.75) and represents the most common trend of the data given.

The other points in the scatter plot are not in line with the curve of the data, hence, connecting those points to draw a trend line would not represent the data given properly.

Therefore, the two points that the trend line should go through to best represent the data given in the scatter plot are 6,2 and 10,1.75.

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