The weight of (i.e. the force of gravity on) 9 kg satellite that is at a distance 2r above the surface of the earth is calculated as 9.79 N.
How is weight defined?In science and engineering, the weight of an object is defined as the force acting on the object due to gravity. It is a standard mechanical quantity but sometimes, it can be defined as a vector quantity, the gravitational force acting on the object.
Given m= 9kg g = 9.8m/s²
As we know, Weight, W = m* a
Acceleration due to gravity at height 2r; h = 2r
a =g r²/(r+ h)²
= gr²/( r+ 2r)²
= gr²/9r²
=g/9
=9.8/9
= 1.088 m/s²
W = m* a
W= 9 * 1.088
Weight = 9.79 N.
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The parking brake on a 1200kg automobile has broken, and the vehicle has reached a momentum of 7800kg.M/s. What is the velocity of the vehicle?
A hiker walks 23.87 m, E and 12.90 m, N. What is the direction of his resultantdisplacement?
23.38 ° to the positive x-axis
Explanation
Step 1
draw the vectors
Step 2
add the vectors, ( component to component)
so
a) get the components of V1
\(\begin{gathered} 23.87\text{ at 0\degree} \\ so \\ V_{1x}=23.87\text{ cos 0=23.87} \\ V_{1y}=23.87\text{ sin 0= 0} \end{gathered}\)b) components of V2
\(\begin{gathered} 12.9\text{ at 90 \degree} \\ so \\ V_{2x}=\text{ 12.9 cos 90=0} \\ V_{2y}=12.9\text{ sen 90=12.9} \end{gathered}\)c) add
\(\begin{gathered} Vdis_x=23.87+0=23.87 \\ Vdis_y=0+12.9 \end{gathered}\)so, the magnitude of the displacement is
\(\begin{gathered} \lvert Vd\rvert=\sqrt[]{V^2_x+V^2_y} \\ replace \\ \lvert Vd\rvert=\sqrt[]{23.87^2+12.9^2} \\ \lvert Vd\rvert=27.132 \end{gathered}\)finally, the direction
as we have a rigth triangle
let
opposite side= 12.9
adjacent side=23.8
Now, use the tan function to find the angles
so
\(\begin{gathered} \tan \emptyset=\frac{opposite\text{ side }}{\text{adjancent side}} \\ \text{replace} \\ \tan x=\frac{12.9}{23.87} \\ \text{isolate x} \\ x=\tan ^{-1}(\frac{12.9}{23.87}) \\ x=28.38 \end{gathered}\)therefore, the direction of the resultant is
23.38 ° to the positive x-axis
I hope this helps you
What fitness level is helpful to know when a person is starting an exercise program
Answer:
There are various areas that should be considered to access the fitness level of an individual.
Explanation:
Knowing the specific details can help an individual to set realistic fitness goals, monitor their progress, and retain motivation. Fitness is typically measured in four main areas: cardiovascular fitness, muscle strength and endurance, flexibility, and composition of the body. It is important to evaluate these vital components of fitness so that one gets a fair knowledge of present fitness level and plan for the future accordingly.
16. when water freezes in a closed jar both its volume and its pressure increase,eventually bursting the jar. does this violate the second-order conditionpv < 0? explain.
Water freezing in a closed jar and causing it to burst does not violate the second-order condition (pv < 0). This is because when water freezes, it undergoes a phase transition from liquid to solid, causing its volume to increase due to the formation of a crystalline structure.
However, this condition does not apply to water in a closed jar when it freezes and eventually bursts the jar. This is because water is not a gas and does not behave like a gas. When water freezes, it undergoes a phase change from a liquid to a solid, which results in a decrease in volume. However, this decrease in volume is accompanied by an increase in pressure because water expands when it freezes.
In summary, the second-order condition does not apply to water in a closed jar when it freezes and eventually bursts the jar because it is not a result of adiabatic expansion or compression of a gas. Instead, it is a phase change of a liquid, which results in an increase in pressure as the volume decreases.
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NEWTONS SECOND LAW LAB REPORT
Answer:
Newton's second law states that the acceleration of an object is directly related to the net force and inversely related to its mass. Acceleration of an object depends on two things, force and mass.
Explanation:
here this may help.
Question 2 (1 point)
An object starts at rest and accelerates to a velocity of 8 m/s in
a period of 4 s. What is the acceleration of the object?
m/s²
Answer:
2m/s²
Explanation:
acceleration it the change in velocity over the time taken
Fill in the blank to balance the equation: ___ AgI + Na₂S → Ag₂ + 2NaI
Answer:2AgI + Na2S → Ag2S + 2NaI I am pretty sure this is the answer
Explanation:
PROVE THAT G = GM/R² WHERE THE SYMBOLS HAS THEIR USUAL MEANINGS
Answer:
g=GM/R^2
Universal Gravutation Constant:
f=GM×m/R^2
Force can be also expressed as
f=m×g
so,
mg=GMxm/R^2
The m gets cancelled so
g=GM/R^2
The velocity of an object is it’s speed and __ of motion .
Answer:
direction should be the answer
1.) Determine the amount of matter, in kilograms, that must be converted
to energy to yield 1.0 gigajoule (which is 10 joules). *
Answer:
1 kilogram [kg] = 89875517.8780129 gigajoule [GJ]
Explanation:
Hopes it helps.
How is protein related to nucleic acid?
Answer:
The subunits of nucleic acids are also the subunits of proteins.
Explanation:
i hope this helps
A uniform layer of methyl alcohol (n=1.33) covers a sapphire. The alcohol is 3.1 um thick, and
a limited range of visible light, from 560nm to 700nm, illuminates the alcohol-covered sapphire. Find all the wavelengths in the given range of light that will be reflected more brightly than others.
The wavelengths in the given range of light that will be reflected more brightly than others are 628.2 nm, 656.3 nm, and 684.5 nm.
The reason for this is that these wavelengths correspond to the resonant frequencies of the alcohol layer. When light of these wavelengths hits the alcohol layer, it causes the alcohol molecules to vibrate. This vibration causes the light to be reflected back in the same direction, resulting in a brighter reflection.
The resonant frequencies of the alcohol layer can be calculated using the following formula:
f = n * c / 2d
where:
f is the resonant frequency
n is the refractive index of the alcohol (1.33)
c is the speed of light (3 x 10^8 m/s)
d is the thickness of the alcohol layer (3.1 um)
Plugging these values into the formula, we get the following resonant frequencies:
f = 1.33 * 3 x 10^8 m/s / 2 * 3.1 x 10^-6 m = 628.2 nm
f = 1.33 * 3 x 10^8 m/s / 2 * 2.1 x 10^-6 m = 656.3 nm
f = 1.33 * 3 x 10^8 m/s / 2 * 1.1 x 10^-6 m = 684.5 nm
These are the wavelengths of light that will be reflected more brightly than others when they hit the alcohol-covered sapphire.
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Explain the mechanism that is responsible for the formation of snowflakes.
The mechanism that is responsible for the formation of snowflakes is the nucleation of ice crystals.
What is a Snowflake?This is defined as a piece of snow which falls from the sky as a result of an extremely cold climate condition and is common in the arctic regions of the world.
Snow flakes are formed when ice crystals stick together to form the flakes which usually has a dust or pollen being formed around the area being talked about.
This is also regarded as a type of precipitation such as rain etc and is therefore the most appropriate choice.
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The ___________________ ______________ (two words) is the least dense layer of the Earth.
Answer:
lithosphere
Explanation:
the least densest layer is the outer most layer
the densest layer is the inner most layer and the inner most layer is the inner core
Answer:
lithosphere
Explanation:
i took the test and i got it right
Describe the disadvantages of using uranium-238 for dating.
Explanation:
Mostly in metamorphic or lava materials is uranium-238 contained. Then no fossil could be estimated utilizing U 238 specifically. They should never be used combined due to the huge variations in the half-life of Carbon 14 with Uranium-238. It is only possible to be using carbon 14 to classify fossil from a very current generation.
Air pressure decreases as elevation increases. Describe how the boiling point of
water on top of a mountain would be different from its boiling point at sea level.
Answer:
The boiling point on top of a mountain would be lower than at sea level because the altitude would be higher and air pressure would decrease.
As the height increases, because most of the air molecules are held near to the surface and hence pressure by gaseous substance will be lower at higher altitudes results in lowering boiling point also.
What is boiling point?Boiling point of a substance is the temperature at which the substance changes from the liquid state to vapor state where both phases are in equilibrium and the pressure of vapor phase above the liquid phase will be equal to the atmospheric pressure.
The boiling point is dependent on the bond type, molecular weight, temperature and pressure. At higher altitudes, the pressure will be reduced due to the less denser air.
The volume of gas molecules is higher on elevation and thus, a decreased pressure causes, the water molecules easily boil with weekend intermolecular force thus, boiling point at mountain will be less than that at sea level.
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10 kg ball rolls off a 5 m high cliff traveling at 2 m/s. if it lands on a spring with a spring constant of 10,000 N/m, how far can it compress the spring? (assume the spring is pointed in the direction of the ball)
Answer:
Approximately \(0.3\; {\rm m}\). (Assuming that \(g = 9.81\; {\rm N\cdot kg^{-1}}\).)
Explanation:
In this question, the ball initially possesses gravitational potential energy \(\rm GPE}\) and kinetic energy \({\rm KE}\). That energy was converted into the elastic potential energy \({\rm EPE}\) of the compressed spring.
Let \(m\) denote the mass of the ball. When the height of the ball changes by \(\Delta h\), the change in the \({\rm GPE}\) of the ball would be \({\rm GPE} = m\, g\, \Delta h\).
Let \(v\) denote the initial speed of the ball. The initial kinetic energy of the ball would be \({\rm KE} = (1/2)\, m\, v^{2}\).
Assume that the height of the cliff far exceeds the height of the spring. Thus, the change in the height of the ball would be approximately the same as the height of the cliff: \(\Delta h \approx 5\; {\rm m}\). The \({\rm GPE}\) of the ball would be:
\(\begin{aligned}{\rm GPE} &= m\, g\, \Delta h \\ &\approx (10)\, (9.81)\, (5)\; {\rm J} \\ &= 490.5\; {\rm J} \end{aligned}\).
With a speed of \(v = 2\; {\rm m\cdot s^{-1}}\), the initial \({\rm KE}\) of the ball would be:
\(\begin{aligned}{\rm KE} &= \frac{1}{2}\, m\, v^{2} \\ &= \frac{1}{2}\, (10)\, (2)^{2}\; {\rm J} \\ &= 20\; {\rm J}\end{aligned}\).
Let \(k\) denote the spring constant of the spring. With a displacement of \(x\), the \({\rm EPE}\) in the spring would be \({\rm EPE} = (1/2)\, k\, x^{2}\).
All that \({\rm GPE} + {\rm KE} \approx (490.5 + 20)\; {\rm J} = 510.5\; {\rm J}\) of energy would have been converted into the \({\rm EPE}\) of the spring.
It is given that \(k = 10000\; {\rm N\cdot m^{-1}}\). In other words, when \(x\) is in meters:
\((1/2)\, (10000)\, x^{2} = {\rm EPE} \approx 510.5\).
Solve for the displacement of the spring, \(x\):
\(\begin{aligned} x &\approx \sqrt{\frac{510.5}{(1/2)\, (10000)}} \approx 0.3\; {\rm m}\end{aligned}\).
a helicopter drops a care package to stranded climbers as it is ascending at 8m/s. the package hits the ground 4 seconds later
q1) (a) under equilibrium conditions and t> 0 k, what is the probability of an electron state being occupied if it is located at the fermi level?
(a) The probability of an electron state being occupied at the Fermi level under equilibrium conditions and T>0K is 0.5.
At equilibrium, the Fermi-Dirac distribution function gives the probability that an electron will occupy a particular energy state. The Fermi level is the energy level at which there is a 50% chance of finding an electron at T=0K. At non-zero temperatures, the probability of finding an electron at the Fermi level increases slightly, but remains close to 0.5. This is because as the temperature increases, some electrons are excited to higher energy levels, leaving behind an equal number of unoccupied states at the Fermi level, thereby maintaining the 50:50 probability distribution.
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10 points! quick and easy physics question :) please help me out it's for an assignment I need to turn in soon!
you throw a tennis ball straight up with an initial velocity of 20.0 m/s. at the instant just before the ball starts to fall down, what is its acceleration?
The acceleration of the tennis ball just before it starts to fall down is approximately -9.8 m/s², indicating that its velocity is decreasing as it reaches the top of its trajectory.
When the tennis ball reaches its highest point, just before it starts to fall down, its velocity momentarily becomes zero. At this instant, the ball experiences an acceleration due to the force of gravity. In the absence of any other forces, this acceleration is equal to the acceleration due to gravity, denoted by "g."
On Earth, the average value for acceleration due to gravity is approximately 9.8 m/s². However, it's important to note that this value can vary slightly depending on factors such as altitude and location.
Since the ball is at its highest point, its acceleration is directed downward, opposite to its initial velocity. The acceleration due to gravity acts as a constant force that causes objects to accelerate toward the Earth's center. Therefore, the acceleration of the tennis ball just before it starts to fall down is approximately -9.8 m/s².
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WHAT IS THE ANSWER PLS LMK TYY
A man applies a force of 500 N to push a truck 10 m down the street. How much work has been done? Please answer!
Answer:
5000 J
Explanation:
W=F*D
W=500N*10m
w=5000 J
When a man applies a force of 500 N to push a truck 10 m down the street. Then the work of 5000 J has been done.
What is Work ?Work done is the amount energy gained (loosed) in bringing the body from initial position to final position. It is denoted by W and its SI unit is joule(J). i.e. Work(W) is force(F) times displacement(s). W=F× s When a body is displaced with 1 newton of force by 1 m, then we can say that work has been done on the body by 1 joule.
Writing for it's dimension, W=F× s
Force has dimension [L¹ M¹ T²]
Displacement has dimension [L¹]
multiplying both the dimensions Force and Displacement we get, dimension of Work [L² M¹ T²].
Given,
F = 500 N
s = 10 m
Work = Fs = 500×10 = 5000 J
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(15 points) How many circles do i draw, like in what order
Answer:
U have to draw 3 circles
take a specific point and draw 3 circles of different size from the same point.
When the pressure is 1.00 atm What is the volume of the gas?
The required volume of the gas is 0.52 L.
What is relation between pressure and volume of the gas?Diminishing the volume of a contained gas will expand its tension, and expanding its volume will diminish its strain. As a matter of fact, on the off chance that the volume increments by a specific variable, the tension declines by a similar element, as well as the other way around.
According to question:V1 = 1.56 L, P1 = 1 atm, P2 = 3 atm,
To find: V2 of gas
So, P1V1 = P2V2
V2 = P1V1/P2
V2 = 1.56(1)/3 = 0.52 L
Thus, required volume of gas is 0.52L
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Correct question:
A gas occupies 1.56 l at 1.00 ATM what will be the volume of this gas if the pressure becomes 3.00 ATM
What are three different catapult ? And definition?
Answer:
1. Ballista
2. Mangonel
3. Trebuchet
Definitions:
1. a catapult used in ancient warfare for hurling large stones.
2. a military device for throwing stones and other missiles.
3. a machine used in medieval siege warfare for hurling large stones or other missiles.
Answer:
1. Ballista, 2.Mangonel, 3.Trebuchet
definition: a forked stick with an elastic band fastened to the two prongs, used by children for shooting small stones; a slingshot.
Explanation:
The main types of catapults used were the trebuchet, mangonel, onager, and ballista.
Neutrons are also known as____
neutrinos
photons
alpha particles
beta particles
Answer:
Beta Particles
Explanation:
Cart 1 has an initial velocity and hits cart 2 which is stationary. after a perfectly inelastic collision, the combined carts are traveling with exactly one third the initial velocity of cart 1, and in the same direction. which is correct about the mass of cart 2? the mass of cart 2 must be twice the mass of cart 1. the mass of cart 2 must have decreased during the collision. the mass of cart 2 must be one third the mass of cart 1. the mass of cart 2 must be the same as the mass of cart 1.
Option(a) the mass of cart 2 is twice that of the mass of cart 1 is the right answer.
The mass of cart 2 is twice that of the mass of cart 1 is correct about the mass of cart 2.
Let's demonstrate the issue using variables:
Let,
m1=mass of cart 1
m2=mass of cart 2
v1 = velocity of cart 1 before collision
v2 = velocity of cart 2 before collision
v' = velocity of the carts after collision
Using the conservation of momentum for perfectly inelastic collisions:
m1v1 + m2v2 = (m1 + m2)v'
v2 = 0 because it is stationary
v' = 1/3*v1
m1v1 = (m1+m2)(1/3)(v1)
m1 = 1/3*m1 + 1/3*m2
1/3*m2 = m1 - 1/3*m1
1/3*m2 = 2/3*m1
m2 = 2m1
From this we can conclude that the mass of cart 2 is twice that of the mass of cart 1.
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Answer:
A. The mass of Cart 2 must be twice the mass of Cart 1.
Explanation:
How is a sound wave made by plucking a guitar string?.
Answer:
i have no clue
Explanation:
A paperclip with the density of a neutron star would weigh (on the Earth)
A paperclip with the density of a neutron star would weigh approximately 0.0098 Newtons on Earth.
The density of a neutron star is incredibly high, estimated to be around \(10^{17\) to \(10^{18\) kilograms per cubic meter. Comparatively, the density of a typical paperclip made of metal is much lower, ranging from 6,000 to 9,000 kilograms per cubic meter.
To calculate the weight of a paperclip with the density of a neutron star on Earth, we need to consider the mass and gravitational acceleration. The gravitational acceleration on Earth is approximately 9.8 meters per second squared.
Let's assume the paperclip has a mass of 1 gram (0.001 kilograms) for simplicity. The weight can be calculated using the formula:
Weight = Mass x Gravitational acceleration
Weight = 0.001 kg x 9.8 m/s²
Weight = 0.0098 Newtons
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