Answers
Answer: true
Explanation: idek
Related Questions
On an aircraft carrier a 20,608kg plane can be launched from 0m/s to 78m/s in 2seconds in order for the plane to take off in a relatively small space and time. What is the impulse experienced on this plane during launch?
Answers
To determine the impulse we use the fact that the impulse is equal to the change in momentum:
\(I=p_2-p_1\)Where:
\(\begin{gathered} I=\text{ impulse} \\ p_2=\text{ final momentum} \\ p_1=\text{ initial momentum} \end{gathered}\)The momentum is the product of the mass and the velocity, therefore, we have:
\(\begin{gathered} I=m_v_2-m_v_1 \\ \end{gathered}\)Since the initial velocity is zero, we have:
\(\begin{gathered} I=m_2v_2-m_(0) \\ I=m(v_2) \end{gathered}\)Now, we substitute the values:
\(I=(20608kg)(78\frac{m}{s})\)Solving the operation:
\(I=1607424kg\frac{m}{s}\)Therefore, the momentum is 1607424 kgm/s
Charges A and B are separated by a distance. If the distance is reduced to ½ the original value, what effect will it have on the electrostatic force?
Answers
ANSWER:
B. Quadrupled.
STEP-BY-STEP EXPLANATION:
By means of Coulomb's law we have the following:
\(F=k\cdot\frac{q_1\cdot q_2}{r^2}\)Now, if the distance is halved (r' = 1/2 r), we substitute:
\(\begin{gathered} F^{\prime}=k\cdot\frac{q_1\cdot q_2}{(\frac{1}{2}r)^2} \\ \\ F^{\prime}=k\frac{q_1q_2}{\frac{1}{4}r^2} \\ \\ F^{\prime}=4\cdot k\cdot\frac{q_1\cdot q_2}{r^2} \\ \\ F^{\prime}=4F \end{gathered}\)Which means that the force is quadrupled.
The correct answer is B. Quadrupled.
A 50kg boy stands on rough horizontal ground. The coefficient
of static friction, us, is 0.68. The maximum static friction
between the boy and the ground is __N.
Answers
Given :
A 50 kg boy stands on rough horizontal ground. The coefficient of static friction, us, is 0.68.
To Find :
The maximum static friction between the boy and the ground is _ N.
Solution :
We know maximum static friction is given by :
\(F = \mu mg \\\\F= 0.68\times 50\times 9.8\\\\F = 333.2\ N\)
Therefore, maximum static friction is 333.2 N.
Hence, this is the required solution.
Consider a 2.75 W electric clock. What is the yearly cost, in dollars, of operating such aclock if the cost of electricity is $0.075 per kW⋅h?
Answers
1 year= 365 days
1 day = 24 hours
1 kw = 1000w
2.75 x 1/1000 = 0.00275 kw
0.00275 kw * 24 * 365 = 24.09 kw*h
Cost = $0.075 per kwh
Cost = 0.075 x 24.09 = $1.80
When a skater pulls her arms in, it
reduces her moment of inertia from
2.12 kg m² to 0.699 kg-m². If she was
initially spinning 3.25 rad/s, what is
her final angular velocity?
Answers
The skater's final angular velocity is approximately 9.86 rad/s.
The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:
L = Iω
where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.
Initially, the skater has an angular momentum of:
L_initial = I_initial * ω_initial
Substituting the given values:
L_initial = 2.12 kg m² * 3.25 rad/s
The skater's final angular momentum remains the same, as angular momentum is conserved:
L_final = L_initial
The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:
L_final = I_final * ω_final
0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s
Solving for ω_final:
ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²
Hence, the skater's final angular velocity is approximately 9.86 rad/s.
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A cannonball (20kg) is fired at an angle --its initial speed upon leaving is 100m/s and the ball reaches a height of 180 meters. Assume no friction and g=10m/s2. What is the initial kinetic energy when the ball leaves the cannon?
Answers
Explanation:
Kinetic energy = 1/2 m v^2
= 1/2 ( 20 kg) * (100 m/s)^2 = 100 000 J
What is the answer to this question?
Answers
Answer:
c
Explanation:
Answer:
b
Explanation:
100 g of water at 25 °C is poured into an insulating cup. 50 g of ice at 0 °C is added to the water. The water is stirred until the temperature of the water has fallen to 0 °C. 18 g of ice remains unmelted. The specific heat capacity of water is 4.2 J / g °C. Which value does this experiment give for the specific latent heat of fusion of ice?
Answers
The specific latent heat of fusion of ice obtained from this experiment is approximately 583.33 J/g.
To determine the specific latent heat of fusion of ice using the given experiment, we need to consider the energy transferred during the process.First, we need to calculate the energy lost by the water to cool down from 25 °C to 0 °C. The energy lost is given by:
Q1 = m1 * c * ΔT1
Where:
m1 = mass of water = 100 g
c = specific heat capacity of water = 4.2 J/g °C
ΔT1 = change in temperature = (0 °C - 25 °C) = -25 °C
Q1 = 100 g * 4.2 J/g °C * (-25 °C) = -10,500 J
Next, we calculate the energy released by the water to freeze and cool the remaining ice. The energy released is given by:
Q2 = m2 * Lf
Where:
m2 = mass of ice = 18 g
Lf = specific latent heat of fusion of ice (to be determined)
Q2 = 18 g * Lf
Since energy is conserved in the system, the energy lost by the water (Q1) is equal to the energy released by the water (Q2):
-10,500 J = 18 g * Lf
Solving for Lf:
Lf = -10,500 J / 18 g = -583.33 J/g
The negative sign indicates that energy is being released during the process of freezing.
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The kinetic energy k of an object in joules is given by the formula k= 1 over 2mv^2 where m is the object’s mass in kilograms and v is it’s velocity in meters per second. An object’s velocity in meters per second, and it’s kinetic energy is 48,000 joules..If it speeds up to 40 meters per second, what is its new kinetic energy
Answers
Answer:
Ek = 192000 [J]
Explanation:
Originally missing speed data to solve this problem, we must assume that the original speed is 20 [m/s]. In this way, we can calculate the mass of the object.
48000 = (1/2)*m*(20)^2
m = 240 [kg]
The mass is conserved since it does not change only changes the speed of the body so we can calculate a new kinetic energy.
Ek = (1/2)*240*(40)^2
Ek = 192000 [J]
What is buoyancy? How is it related to the force of gravity?
Answers
Answer:
buoyancy is the ability to float on water or other liquids. this relates to the force of gravity because the stronger that force, the more likely it is to sink.
Explanation:
HELP URGENT- will give brainliest if correct
Answers
Answer:
6 km is the right answer
hope it helps you
Explanation:
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If a captain wants to take her boat (speed in still water: 5.0m/s) directly across a river with a current of 3.5m/s, what upstream angle should she head at?
Answers
Let's make a diagram to visualize the problem.
To find the angle, we have to use the tangent trigonometric reason, which is the ratio between the opposite leg and the adjacent leg.
\(\tan \alpha=\frac{3.5}{5}\to\alpha=\tan ^{-1}(\frac{3.5}{5})\to\alpha\approx35\)Therefore, the angle sould be 35 degrees.Lien is pushing a box across a table. She used a force of 100 N to get the box moving. Which force did she overcome
to get the box moving?
O the downward force of gravity on the box
O the upward force of the table on the box
the reaction force on the box
O the push force on the box
Answers
Answer:
the reaction force on the box
Explanation:
In order to push or pull an object, an external force is needed to overcome the weight of that object. This force is called ACTION FORCE. However, according to 3rd law of Newton, which states that for every action, there is an equal and opposite reaction, an opposite force counters the object in an opposite direction. This force is called REACTION FORCE.
According to this question, Lien is pushing a box across a table. She used a force of 100 N to get the box moving. This means that she had to overcome an opposite force called REACTION FORCE, with an ACTION FORCE of 100N
Answer:
C. the reaction force on the box
Explanation:
i literally just finished the quiz
Which of the following solar phenomena is likely to have the most negative impact on Earth?
A solar flare as it may cause brief radio blackouts
An aurora as it may damage communication networks
An aurora as it may cause worldwide transmission problems
A solar flare as it may harm satellites and aircrafts flying near poles
Answers
Answer:
A solar flare as it may harm satellites and aircrafts flying near poles
Explanation:
Since solar flare is electro magnetic waves going to Earth the waves will mostly get absorbed by the north and south poles resulting in the aurora borealis, but if the solar flare is strong enough it may stop communications and engines in satellites and aircrafts and in result harming them
Answer:
A solar flare as it may harm satellites and aircrafts flying near poles
Explanation:
what kind of energy does a cell have
Answers
Answer:
The only form of energy a cell can use is a molecule called adenosine triphosphate (ATP). Chemical energy is stored in the bonds that hold the molecule together.
Explanation:
hope it helps
Some dragonflies splash down onto the surface of a lake to clean themselves. After this dunking, the dragonflies gain altitude, and then spin rapidly at about 1100 rpm to spray the water off their bodies. When the dragonflies do this "spin-dry," they tuck themselves into a "ball" with a moment of inertia of 2.0×10−7kg⋅m2 . How much energy must the dragonfly generate to spin itself at this rate?
Answers
The dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.
Start by converting the rotational speed from rpm (revolutions per minute) to rad/s (radians per second). Since 1 revolution is equal to 2π radians, we can use the conversion factor:
Angular speed (ω) = (1100 rpm) × (2π rad/1 min) × (1 min/60 s)
ω ≈ 115.28 rad/s
The moment of inertia (I) is given as 2.0 × 10^-7 kg⋅m².
Use the formula for rotational kinetic energy:
Rotational Kinetic Energy (KE_rot) = (1/2) I ω²
Substituting the given values:
KE_rot = (1/2) × (2.0 × 10^-7 kg⋅m²) × (115.28 rad/s)²
Calculate the value inside the parentheses:
KE_rot ≈ (1/2) × (2.0 × 10^-7 kg⋅m²) × (13274.28 rad²/s²)
KE_rot ≈ 1.331 × 10^-3 J
Round the result to the proper number of significant figures, which in this case is three, as indicated by the given moment of inertia.
KE_rot ≈ 4.8 × 10^-4 J
Therefore, the dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.
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describe how the wavelength of a wave changes if the wave slows down but its frequency does not change
Answers
If the wave slows down with no change in frequency, the wavelength decreases.
What is a wave?A wave is defined as the disturbance that has the ability to transfer energy from one point to another in a medium.
The properties of a wave include the following:
Wavelength: This is defined as the distance that is observed between adjacent points in an identical cycle of a waveform.Frequency: This is the number of cycles of a wave that can occur per minute time.Time period: This is the time it takes for a complete cycle of wave to occur.Speed: Wave speed is the distance a wave travels in a given amount of time.Amplitude: This is defined as the distance from the centre line (or the still position) to the top of a crest or to the bottom of a trough.When there is a change in the speed of the wave with no change in frequency, the length of the wave would decrease.
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Which hypothesis cannot be tested experimentally?
Question 13 options:
The average speed of air molecules increases with temperature.
Ghosts are the souls of people who have died.
The structure of any part of the broccoli is similar to the whole structure of the broccoli.
A vegetarian is less likely to be affected by night blindness.
Answers
Ghosts are the souls of people who have died cannot be tested experimentally.
An experiment is a technique used in science to create a discovery, test a theory, or show a known truth. because owing to a lack of technology, we might not be able to analyze souls.Any procedure where measurements are taken and tests are run to support or disprove a hypothesis is referred to as a scientific experiment.The scientific experiment is a component of the scientific method as a whole. This process is a series of sequential processes used to learn new information about any subject.The steps are: making a discovery. posing a query and developing a theory. scientific tests to validate the theory and gather data Analyzing the findings and making judgments presenting the findingsTo know more about experiment visit : https://brainly.com/question/9199868
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what statement is true according to newton’s first law of motion?
a. in the absence of unbalanced force an object at rest will stay at rest and an object in motion will come to a stop.
b. in the absence of an unbalanced force, an object will start moving and an object in motion will come to a stop.
c. in the absence of an unbalanced force, an object at rest will stay at rest and an object in motion will stay in motion.
d. in the absence of an unbalanced force, an object will start moving and an object in motion will stay in motion.
Answers
Answer:
c. in the absence of an unbalanced force, an object at rest will stay at rest and an object in motion will stay in motion.
Explanation:
First law: things keep doing what they are doing, unless force is applied.
You can’t pool the wool over my eyes!
Alliteration
Allusion
Assonance
Hyperbole
Metaphor
Onomatopoeia
Oxymoron
Personification
Simile
Answers
Answer:
Assonance
Hope this helps :)
Hope this helps :)Explanation below.
Explanation:
The oo sound is repeated many times, and oo is a vowel sound. So assonance would make the most sense.
a bar of gold measures .113m *.0254m*.0106m. how many gallons of water have the same mass as this bar?
Answers
The volume (in gallon) of water that have the same mass as the bar of gold is 0.153 gallon
How do I determine the volume (in gallon) of water?We'll begin by obtaining the mass of the gold bar. This is given below:
Volume of gold bar = 0.113 m × 0.0254 m × 0.0106 m = 0.00003 m³Density of gold = 19300 kg/m³Mass of gold bar =?Density = mass / volume
Cross multiply
Mass = Density × Volume
Mass of gold bar = 19300 × 0.00003
Mass of gold bar = 0.579 Kg
Finally, we shall determine the volume of water having the same mass as 0.579 Kg of the gold bar. Details below:
Mass of gold bar = 0.579 KgMass of water = Mass of gold bar = 0.579 KgDensity of water = 1000 Kg/m³ Volume of water = ?Volume = mass / density
Volume of water = 0.579 / 1000
Volume of water = 0.000579 m³
Multiply by 264.172 to express in gallon
Volume of water = 0.000579 × 264.172
Volume of water = 0.153 gallon
Thus, we can conclude that the volume of the water is 0.153 gallon
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A stone whirled at the end of a rope 30cm long makes 5revs. Find the linear speed?
Answers
The stone moves at a linear speed of 9.42 m/s.
How is linear velocity determined?Where v stands for speed, d for distance, and t for time, the equation for linear velocity is v = d/t. The SI unit for linear velocity is the metre per second, abbreviated as m/s (ms-1).
The circumference of the circle the stone traces and the distance the stone travels in one revolution are equal.
C = 2πr
where r is the rope's length. If we substitute r = 30 cm, we obtain:
C = 2π(30 cm) ≈ 188.5 cm
As a result, one revolution of the stone moves it approximately 188.5 cm.
The stone moves a total of five times, covering the following distance:
d = 5(188.5 cm) = 942.5 cm
v = d/t
Let's say the stone makes 5 revolutions in t seconds. The linear speed is then:
v = d/t = 942.5 cm/t
To obtain the answer in milliseconds, we can convert the quantities to metres and seconds:
v = 9.425 m/t
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in the diagram, r1= 40 ohm, r= 25.4 ohms, and r3= 70.8 ohms. what is the equivalent resistance of the group?
Answers
R2 and R3 in parallel are equivalent to a single resistor of 18.69 ohms.
In series with R1, that makes 58.69 ohms for all three uvum as a group.
4.0
What are the issue and challenges that students faced during covid19?
Answers
COVID-19 had both pros and cons for students. Challenges and issues are subjective to every other student.
On one hand, some students were thrilled because they can just take classes online without them even needing to get out of bed but it was also ruining the very aspect of being disciplined as a student.
Moreover, many students were studying abroad far from home. They couldn't even manage to deal with the panic Covid-19 brought with itself. They felt so helpless not knowing what to do next as they couldn't even manage to get home safely. While the students studying from home were getting lethargic.
Besides, not everyone had access to the internet because they also had to manage other finances. Families were worried about survival during the first few months of the pandemic. It was beyond stressful for the student to cope with their studies.
Nevertheless, supportive communities and authorities were there as well. Apparently, we went through it quite well.
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A ball is held at rest at some height above a hard, horizontal surface. Once the ball is released it falls, hits the surface, and starts bouncing vertically up and down. Suppose that with each bounce the ball loses a fixed fraction p (with 1>p>0) of its energy. This loss could be due to a number of reasons (inelasticity, drag, etc) that are left unspecified.How many times will the ball bounce before coming to rest (if at all)? Provide a detailed explanation of your reasoning, not simply a one-line answer.How long will it take for the ball to come to rest (if at all)? Give your answer as a formula that contains as variables only p and the time T1 from the moment that the ball was released to the first contact with the horizontal surface.
Answers
It can never theoretically become 0. After n bounces, it may be closer to 0 or extremely tiny, depending on the precise values of p and T1.
Briefing:initial height dropped =h = gT12/2
T1 - time from the moment that the ball was released to the first contact with the horizontal surface.
initial energy T = mgh
after first bounce energy loss = mghp
height it will raise after first bounce mgh1 = mgh(1-p)
after each bounce its energy is reduced by p
after n bounces it will raise to a height
mghn=mgh(1-p)n
hn= h(1-p)n = gT12/2 *(1-p)n
gT₁² (1-p)n/2
Theoritically hn can never become 0. It can be closer to 0 or can be negligibly small after n bounces, depending on the actual values of p and T1 .
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Your heart pumps about 70 mL of blood per beat and beats an average of 80 Times per minute how many gallons of blood does your heart pump every hour
Answers
Answer:
88.761
Explanation:
A flat sheet of paper of area 0.450 m2 is oriented so that the normal to the sheet is at an angle of 600 to a uniform electric field of magnitude 18 N C-1. What is the magnitude of the electric flux through the sheet? A. 3.22 N m2 C-1 B. 21.42 N m2 C-1 C. 5.04 N m2 C-1 D. 11.72 N m2 C-1 E. 4.05 N m2 C
Answers
The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).
The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.
In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²
(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:
Electric flux = Electric field strength × Area
Electric flux = 18 N C⁻¹ × 0.450 m²
Electric flux = 8.1 N m² C⁻¹
In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.
The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).
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An object is attached to a trolley with a 0.80 kg mass, which is then pushed into an identical trolley at a speed of 1.1 m / s. The two trolleys couple together and move at a speed of 0.70 m / s after the collision. Calculate the mass of the object.
Answers
The mass of the object is approximately 0.457 kg.
The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.
Using the momentum equation, the mass of the object can be calculated as follows:
Total momentum before collision = Total momentum after collision
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
Solving for the mass of the object, we get:
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object
0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object
0.32 kg = 0.70 kg * mass of the object
Dividing both sides by 0.70 kg, we find:
mass of the object = 0.32 kg / 0.70 kg = 0.457 kg
The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.
The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.
After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.
In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.
Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.
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Stella's respiratory system is not working well why is this a problem for her ability to exercise
Answers
Explanation:
Her cells will not work well when they have low levels of oxygen.
A 18.0 kg block slides down an inclined plane (angle of inclination is 36 degrees). If the coefficient of kinematic friction is 0.55, what is the acceleration of the block? Consider g = 9.8 m/s². Express your answer correct to 2 decimal places. Add the appropriate unit(s).
Answers
Answer:
Explanation:
The force of gravity acting on the block can be resolved into two components, one parallel to the incline and one perpendicular to the incline. The perpendicular component is balanced by the normal force of the incline, and the parallel component is opposed by the force of friction. The force of friction is given by:
F_friction = coefficient_of_friction * F_norm
where F_norm is the normal force of the incline. The normal force is equal in magnitude and opposite in direction to the perpendicular component of the force of gravity, which is:
F_perpendicular = m * g * cos(theta)
where m is the mass of the block, g is the acceleration due to gravity, and theta is the angle of inclination.
The parallel component of the force of gravity is:
F_parallel = m * g * sin(theta)
The net force acting on the block is:
F_net = F_parallel - F_friction
Using Newton's second law, F = m * a, we can solve for the acceleration of the block:
a = F_net / m
Substituting the expressions for F_parallel and F_friction, we get:
a = [m * g * sin(theta) - coefficient_of_friction * m * g * cos(theta)] / m
Simplifying, we get:
a = g * [sin(theta) - coefficient_of_friction * cos(theta)]
Substituting the given values, we get:
a = 9.8 m/s^2 * [sin(36°) - 0.55 * cos(36°)] = 6.43 m/s^2
Therefore, the acceleration of the block is 6.43 m/s^2.