The Activation Energy, Ea, is approximately 51.2 kJ/mol, rounded to three significant figures.
To determine the activation energy, Ea, from the given information, we will use the Arrhenius equation. The equation is represented as follows:
k = Ae^(-Ea/RT)
Where k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant (8.314 J/mol·K), and T is the temperature in Kelvin.
Taking the natural logarithm of both sides, we get:
ln(k) = ln(A) - (Ea/RT)
Now, plotting ln(k) vs. 1/T, we get a linear equation with a slope equal to -Ea/R. Given that the slope is -6,158 k, we can set up the equation:
-6,158 = -Ea / 8.314
To solve for Ea, we multiply both sides by -8.314:
Ea = 6,158 * 8.314
Ea ≈ 51,217 J/mol
Since we want the activation energy in kilojoules per mole (kJ/mol), we need to convert Joules to kilojoules:
Ea = 51,217 J/mol * (1 kJ / 1,000 J)
Ea ≈ 51.2 kJ/mol
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How many squares are in this 2×2 grid (Figure 1)? Note that the figure link lets you know that a figure goes along with this part. This figure is available to the left.
The number of squares in this figure is 5 squares.
How to identify the number of squares in the figure?To identify the number of squares in the figure we must take into account that a square is a geometric figure that has 4 sides of the same length.
Based on the information above, we can infer that there are 5 squares, four small squares, and 1 large square that spans the entire area of the figure. So, we can say that this figure has 5 squares.
Note: This question is incomplete because the image is missing. Here is the image:
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How many single covalent bonds can carbon form?
o A. 1
O B. 2
O C.3
O D. 4
Carbon contains four electrons in its outer shell
The value of ΔH° for the reaction below is -790 kJ. The enthalpy change accompanying the reaction of 0.95 g of S is __________ kJ.
23 2S (s) + 3O (g) 2SO (g
The enthalpy change accompanying the reaction of 0.95 g of S is -11.85 kJ
Further explanationGiven
ΔH° for the reaction is -790 kJ
Required
The enthalpy change
Solution
Reaction
2S (s) + 3O₂(g) = 2SO₃ (g)
mol of S(MW=32 g/mol) :
\(\tt mol=\dfrac{0.95}{32}=0.03\)
For 2 mol S, the entalphy = -790kJ
The enthalpy change for 0.03 mol :
\(\tt \dfrac{0.03}{2}\times -790~kJ=-11.85~kJ\)
The enthalpy change accompanying the reaction will be "-11.85 kJ".
Given:
Value of ΔH°,
-790 kJAccording to the question,
→ \(2S(s) +3O_2(g) =2SO_3(g)\)
Mol of S will be:
= \(\frac{0.95}{32}\)
= \(0.03\)
hence,
The enthalpy change for 0.03 mol will be:
= \(\frac{0.03}{2}\times -790\)
= \(-11.85 \ kJ\)
Thus the answer above is correct.
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How many milliliters of 0.100M NaOH are required to neutralize the following solution 5.00mL of.0500M HCI
1) Set the chemical equation
\(\text{NaOH + HCl = NaCl + H}_2O\)2) Find out how many moles of HCl react in the solution.
\(\text{moles of HCl = }\frac{0.0500\text{ M}}{\square}\cdot\frac{5.00\text{ mL}}{\square}\cdot\frac{1\text{ L}}{1000\text{ mL}}=\text{ 0.00025 moles of HCl}\)3) Find out how many moles of NaOH reacted with HCl
\(\text{moles of NaOH = }\frac{0.00025\text{ moles of HCl}}{\square}\cdot\frac{1\text{ mole of NaOH}}{1\text{ mole of HCl}}=\text{ 0.00025 moles of NaOH}\)4) Find out the milliliters of NaOH
\(mL\text{ of NaOH = }\frac{0.00025\text{ moles of NaOH}}{0.100\text{ M}}\cdot\frac{1000\text{ mL}}{1\text{ L}}\text{= 2.50 mL}\)Please help thank you
To draw the skeletal structure from a Lewis structure, you need to identify the central atom and its bonded atoms.
How do you draw the skeletal structure from the Lewis structure?To draw the skeletal structure from a Lewis structure, you need to identify the central atom and its bonded atoms. The central atom is usually the least electronegative atom in the molecule, and it is surrounded by the other atoms that are bonded to it.
Here are the steps to draw the skeletal structure from a Lewis structure:
Identify the central atom: In the Lewis structure, the central atom is usually the atom that has the most connections to other atoms.
Count the total number of atoms: Count the total number of atoms in the molecule or ion.
Replace the bonding electrons with dashes: Replace the bonding pairs of electrons between the atoms with dashes (-).
Arrange the atoms: Arrange the atoms in a way that makes sense based on their connectivity in the Lewis structure. The atoms should be positioned in a way that minimizes the number of intersections between the dashes.
Add lone pairs: If there are any lone pairs of electrons on the central atom, add them to the skeletal structure as dots.
Check for consistency: Make sure the skeletal structure you have drawn is consistent with the Lewis structure in terms of the number of electrons, the types of atoms, and the bonding pattern.
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How might a fact be disproved? Are there some facts that will never be disproved
Can anyone help me with this question please
I NEED THIS RIGHT NOW!! Daria had some sand from the beach. The mass of the sand was 72 grams. She used the graduated cylinder below to measure the volume.
What is the volume of the sand found in the graduated cylinder? _____ mL
Daria had some beach sand with her. The sand has a 72 gramme mass. She calculated the volume using the graduated cylinder below. The graduated cylinder contains 15 mL of sand.
The volume of the sand is calculated using the graduated cylinder below. The sand's bulk is specified as 72 grammes.
We can use the water displacement method to calculate the volume of the sand. Following is a description of how to estimate the amount of sand using the water displacement method:
The graduated cylinder of water should first be measured for volume.
The graduated cylinder's water volume should then be measured after adding the sand to it. The volume of water increases by the same amount.
Let's use the provided problem to implement this approach.
In the beginning, there is 10 mL of water in the graduated cylinder. The graduated cylinder contains 25 mL of water once the sand has been added.
The amount of sand is therefore equal to the difference between the two volumes, which is: Sand volume equals final water volume minus initial water volume (25 - 10 = 15 mL).
As a result, there are 15 mL of sand in the graduated cylinder.
Answer : 15
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how could you engineer a device that produces beneficial friction and heat?
A device that produces beneficial friction and heat can be engineered by ensuring that frictional factors that result in deformation and wear are reduced to a great extent.
Friction is the force that resists the relative motion of two bodies that are in contact with each other. The rubbing of an object against another produces heat. Heat is a form of energy known as thermal energy. Every form of friction tends to produce heat as it causes an increase in the movement of molecules on the contact surfaces thus converting kinetic energy into thermal energy (heat).
The resultant frictional forces including the thermal energy produced can be harnessed by engineered devices into products that are beneficial. Examples of such devices that have been engineered for this purpose include:
Friction weldersHousehold heating devices etc.Therefore, work done due to frictional forces and heat produced therein can be adapted to devices efficiently if detrimental effects due to these forms of energy are reduced acceptable levels.
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2KI (aq) + Cl₂(g) → 2KCl(aq) + 1₂(g)
What volume of 12 gas forms when
21 L Cl2 react at STP?
[?] L 12
The volume of 12 gas forms when 21 L Cl2 react at STP is 21 L.
To determine the volume of 12 gas (I assume you mean I2 gas) formed when 21 L of Cl2 reacts at STP (standard temperature and pressure), we need to use the ideal gas law equation.
The ideal gas law equation is given by:
PV = nRT
Where:
P = pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature
At STP, the pressure is 1 atm, and the temperature is 273.15 K.
From the balanced equation, we can see that the molar ratio between Cl2 and I2 is 1:1. So, if 21 L of Cl2 reacts, it will produce an equal volume of I2 gas.
Given that the volume of Cl2 is 21 L, we can assume the volume of I2 gas formed will also be 21 L.
Therefore, the volume of I2 gas formed is 21 L.
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when an impurity is added to pure water what happens to the boiling point of the mixture?
Boiling point of water is 100 degree Celsius at mean sea level. Boiling point is related to the vapour pressure of the solution. On adding an impurity, the vapor pressure of solution decreases. With an increase in concentration of solute, vapour pressure decreases, hence boiling point increases
1. How many molecules are in 96.1 g of carbon dioxide?2. How many oxygen atoms are in 96.1 g of CO2?3. How many grams would 1.0 x 10^25 particles of copper(II) sulfate weigh?4. How many liters of H2 gas are equal to 4374.4 grams of H2 gas?
To calculate the number of molecules we can apply the Avogadro equation, which relates the moles of a compound to the number of molecules. The Avogadro number tells us that in one mole of any substance there are 6.022x10^23 molecules.
\(1mo_{}l=6.022\times10^{23}molecules\)Now we must calculate the number of moles in the mass we are given. For this, we use the molar mass.
The molar mass of CO2 is 44.01 g/mol, so the moles of CO2 in 96.1 g will be:
\(\begin{gathered} Mo_{}lCO_2=\frac{\text{Mass of CO}_2}{Molar\text{ mass}} \\ Mo_{}lCO_2=\frac{96.1g}{44.01\frac{g}{mol}} \\ Mo_{}lCO_2=2.18\text{mol} \end{gathered}\)Now we will apply Avogadro to know the number of molecules present in 2.18 moles of CO2.
\(\begin{gathered} \text{Number of molecules=2.18mol}\times\frac{6.022\times10^{23}molecules}{1mol} \\ \text{Number of molecules}=1.31\times10^{24}molecules \end{gathered}\)So, in 96.1 g of carbon dioxide, there are 1.31x10^24 molecules
EASY CHEM, WILL GIVE BRAINLIEST!!
Hi there!
\(\large\boxed{4.04g}\)
To solve, we can use dimensional analysis to convert from molecules to grams.
We must use Avogadro's number (6.02 × 10²³) in converting from molecules to moles.
After converting, multiply by the atomic mass, or grams per mole.
\(1.204 * 10^{24} moles *\frac{1 mol}{6.02*10^{23}moles}* \frac{2.02g}{1mol }= 4.04g\)
How many atoms of lead are in 3.5 moles of lead?
Answer:
2.1 × 10²⁴ atoms Pb
Explanation:
Avogadro's number: 6.022 × 10²³
Step 1: Find conversions
1 mol Pb = 6.022 × 10²³ atoms Pb
Step 2: Use Dimensional Analysis
\(3.5 \hspace{3} mol \hspace{3} Pb(\frac{6.022(10)^{23} \hspace{3} atoms \hspace{3} Pb}{1 \hspace{3} mol \hspace{3} Pb} )\) = 2.107 × 10²⁴ atoms Pb
Step 3: Simplify
We have 2 sig figs.
2.107 × 10²⁴ atoms Pb ≈ 2.1 × 10²⁴ atoms Pb
How many electrons are in the nucleus of an atom with an atomic number of 7?!!
]All organic compounds contain the element carbon but, not all compounds containing the element “carbon”are organic .Justify this statement.
The statement "All organic compounds contain the element carbon, but not all compounds containing the element 'carbon' are organic" can be justified based on the definition and characteristics of organic compounds.
Organic compounds are compounds primarily composed of carbon and hydrogen atoms, often with other elements like oxygen, nitrogen, sulfur, and phosphorus. These compounds are typically associated with living organisms and are known for their unique properties and behavior, including the ability to form complex structures, exhibit covalent bonding, and undergo organic reactions.
On the other hand, there are compounds that contain carbon but are not classified as organic. One notable example is carbon dioxide (\(CO_{2}\)), which is a simple inorganic compound composed of carbon and oxygen. Carbon dioxide does not possess the characteristic properties of organic compounds, such as the ability to form long chains or undergo organic reactions.
Additionally, there are inorganic compounds like carbonates (such as calcium carbonate) and carbides (such as calcium carbide) that contain carbon but are not considered organic. These compounds have distinct chemical and physical properties different from those of organic compounds.
In summary, while all organic compounds contain carbon, not all compounds containing carbon are organic. The classification of a compound as organic or inorganic depends on its overall molecular structure, bonding, and characteristic properties.
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How can the affect of radiation on healthy cells can be reduced when treating cancer?
The affect of radiation on healthy cells can be reduced when treating cancer by focusing the radiation on the cancerous cells.
How can the effect of radiation on healthy cells can be reduced when treating cancer?These side effects are also known as late side effects, which causes the human healthy cells after some time. The Doctors try to protect the healthy human cells by lowering the power of the radiations as possible. The radiation dose is balanced between being high enough to kill cancer cells, yet low enough to limit damage to healthy cells. If we use the advancement of technology of dose conformity such as IMRT, SBRT, and IGRT, then we can get rid of such dangerous radiations.
So we can conclude that the affect of radiation on healthy cells can be reduced when treating cancer by focusing the radiation on the cancerous cells.
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What is the freezing point of a solution prepared from 45.0 g ethylene glycol (C2H6O2) and 85.0 g H2O? Kf of water is 1.86°C/m.
Answer:
\(T_{sol}=-15.9\°C\)
Explanation:
Hello,
In this case, we can analyze the colligative property of solutions - freezing point depression - for the formed solution when ethylene glycol mixes with water. Thus, since water freezes at 0 °C, we can compute the freezing point of the solution as shown below:
\(T_{sol}=T_{water}-i*m*Kf\)
Whereas the van't Hoff factor for this solute is 1 as it is nonionizing and the molality is:
\(m=\frac{mol_{solute}}{kg\ of\ water}=\frac{45.0g*\frac{1mol}{62g} }{85.0g*\frac{1kg}{1000g} } =8.54m\)
Thus, we obtain:
\(T_{sol}=0\°C+(-8.54m*1.86\frac{\°C}{m} )\\\\T_{sol}=-15.9\°C\)
Best regards.
The freezing point of a solution prepared from 45.0 g ethylene glycol and 85.0 g of water is -15.9 °C.
What is freezing point depression?Freezing point depression is a drop in the temperature at which a substance freezes, caused when a smaller amount of another, non-volatile substance is added.
Step 1: Calculate the molality of the solution.We will use the definition of molality.
b = mass of solute / molar mass of solute × kg of solvent
b = 45.0 g / 62.07 g/mol × 0.0850 kg = 8.53 m
Step 2: Calculate the freezing point depression (ΔT).We will use the following expression, where Kf is the cryoscopic constant of water.
ΔT = Kf × b = 1.86 °C/m × 8.53 m = 15.9 °C
Step 3: Calculate the freezing point of the solution.The freezing point of pure water is 0°C.
T = 0°C - 15.9 °C = -15.9 °C
The freezing point of a solution prepared from 45.0 g ethylene glycol and 85.0 g of water is -15.9 °C.
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When converting from moles into atoms, what number should you put on the top of the conversation factor?
The number of the atoms that should be the numerator is 6.02 * 10^23 atoms.
What is the conversion factor?We have to note that the conversion factor is the factor that can be used in the conversion of one unit to the other. We have to note that if we are able to change the unit then we can be able to make the conversion.
We have to note that the Avogadro's number is the number of atoms that we can find in one mole of a substance and it has a value of about 6.02 * 10^23 atoms in the atom of magnesium.
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Atoms of which two elements will form an ionic bond?
a. N and O
b. Mg and Cl
c. Fe and Co
d. Rb and Al
Given the reaction below which of the following best describes the energy changes in this reaction?
Cu + Cl2 + energy —> CuCl2
Answer:
first choice
Explanation:
energy is written on the left side is its absorbed
2 elements came together so bonds are formed.
In the combustion of hydrogen gas, hydrogen reacts with oxygen from the air to form water vapor. hydrogen+oxygen⟶water
If you burn 46.2g of hydrogen and produce 413g of water, how much oxygen reacted?
mass of oxygen:
Answer:
ok, here is your answer
Explanation:
AI-generated answer
To find the mass of oxygen that reacted, we need to use the Law of Conservation of Mass, which states that in a chemical reaction, the mass of the reactants equals the mass of the products.
First, we need to find the number of moles of hydrogen that reacted:
Molar mass of hydrogen (H₂) = 2.016 g/mol
Number of moles of H₂ = mass/molar mass = 46.2 g/2.016 g/mol = 22.92 mol
Next, we need to use the balanced chemical equation to find the number of moles of water produced:
hydrogen + oxygen → water
2H₂ + O₂ → 2H₂O
From the equation, we can see that for every 2 moles of H₂, 1 mole of O₂ is required to produce 2 moles of H₂O. Therefore, the number of moles of O₂ required to produce 22.92 moles of H₂O is:
Number of moles of O₂ = 1/2 x 22.92 mol = 11.46 mol
Finally, we can find the mass of oxygen that reacted by using its molar mass:
Molar mass of oxygen (O₂) = 32.00 g/mol
Mass of oxygen = number of moles x molar mass = 11.46 mol x 32.00 g/mol = 366.72 g
Therefore, the mass of oxygen that reacted is 366.72 g.
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Match each element with the correct chemical symbol.
1. oxygen
Na
2. nitrogen
N
3. carbon
K
4. iron
Fe
5. potassium
O
6. sodium
C
7. copper
Cu
Answer:
Oxygen - O
Nitrogen - N
Carbon - C
Iron - Fe
Potassium - K
Sodium - Na
Copper - Cu
Explanation:
I know trust me
Hope this helps :)
In a single replacement reaction, the chloride ion in NaCl can be replaced
by
a. potassium
b. carbon
c.fluorine
d.neon
Answer:
c. fluorine
Explanation:
A single replacement reaction is defined as the chemical reaction in which a strong molecule replaces the weak molecule from a compound.
In a single replacement reaction, the chloride ion in NaCl can be replaced by fluorine and gives Sodium fluoride as fluorine (F) is stronger than chlorine (Cl) and from other given molecules also. So the single replacement reaction between NaCl and F will be:
NaCl + F2 => NaF + Cl2
Hence, the correct answer is "c. fluorine".
Which of the following is/are true?
A in each period the atomic numbers increase from
left to right
b The periods are numbered 1 through 7 on the left-
hand side of the periodic table
C Elements in the same period have chemical
properties which are not all similar
d All of the above
Answer:
Answer is D. All of the above
5. The distribution constant (partitioning coefficient) for X between n-hexane and water is 8.9. Calculate the concentration of X remaining in the aqueous phase after 50.0 mL of 0.200 M X is treated by extraction with the following quantities of n-hexane: (a) one 40.0-mL portion. (b) two 20.0-mL portions. (c) four 10.0-mL portions. (d) eight 5.00-mL portions.
Answer:
a.is the correct answer
How many grams of lithium nitrate will be needed to make 200.0 grams of lithium sulfate, assuming that you have an adequate amount of lead (IV) sulfate to do the reaction? [a] How much lead (IV) sulfate will you actually need? [b]Pb(SO4)2 + 4 LiNO3 --> Pb(NO3)4 + 2 Li2SO4
[a] In the reaction, you can see that 4 moles of lithium nitrate (LiNO3) produce 2 moles of lithium sulfate (Li2SO4). The first thing that we need to do, is found the moles of lithium sulfate based on its mass (200.0 grams) and then, find the number of moles of lithium nitrate produced (remember that the molar mass of Li2SO4 is 110 g/mol).
\(200.0gLi_sSO_4\cdot\frac{1molLi_2SO_4}{110gLi_2SO_4}=1.82molesLi_2SO_4\)Now, doing a rule of three to find the number of moles of LiNO3, that would be:
\(\begin{gathered} 4molesLiNO_3\to2molesLi_2SO_4 \\ \text{?molesLiNO}_3\to1.82molesLi_2SO_4. \end{gathered}\)The calculation to find the number of moles of LiNO3 would be:
\(1.82\text{ moles}Li_2SO_4\cdot\frac{4molesLiNO_3}{2\text{ moles }Li_2SO_4}=3.64molesLiNO_3.\)Using this value and the molar mass of LiNO3 which is 69 g/mol, we're going to obtain the mass in grams of LiNO3, like this:
\(3.64molesLiNO_3\cdot\frac{69gLiNO_3}{1molLiNO_3}=251.16gLiNO_3.\)We will need 251.16 grams of lithium nitrate to make 200.0 grams of lithium sulfate.
[b] You can see that we're producing 3.64 moles of LiNO3. In the reaction, 4 moles of LiNO3 are reacting with 1 mole of Pb(SO4)2 and we will take into account this information because LiNO3 is the reactant that runs out first; the calculation to find the number of moles of lead (VI) sulfate would be:
\(3.64molesLiNO_3\cdot\frac{1molPb(SO_4)_2}{4molesLiNO_3}=0.91molesPb(SO_4)_2.\)Using this value and the molar mass of Pb(SO4)2 which is 399.1 g/mol, we're going to obtain the mass of Pb(SO4)2:
\(0.91molesPb(SO_4)_2\cdot\frac{399.1\text{ g }Pb(SO_4)_2}{1\text{ mol }Pb(SO_4)_2}=363.18\text{ g }Pb(SO_4)_2.\)We will need 363.18 grams of lead (IV) sulfate.
What is the molarity of solution if 42.1 grams of KOH is dissolved in 3.0 L of solution?
Answer:
the molarity of the solution is 0.25 M.
Explanation:
To calculate the molarity of a solution, we need to know the amount of solute in moles and the volume of the solution in liters.
The first step is to calculate the amount of KOH in moles using its molar mass. The molar mass of KOH is the sum of the atomic weights of potassium (39.1 g/mol), oxygen (16.0 g/mol), and hydrogen (1.0 g/mol):
Molar mass of KOH = 39.1 g/mol + 16.0 g/mol + 1.0 g/mol = 56.1 g/mol
The amount of KOH in moles is:
moles of KOH = mass of KOH / molar mass of KOH
moles of KOH = 42.1 g / 56.1 g/mol
moles of KOH = 0.750 moles
Now that we know the amount of KOH in moles, we can calculate the molarity of the solution:
Molarity = moles of solute / liters of solution
Molarity = 0.750 moles / 3.0 L
Molarity = 0.25 M
Therefore, the molarity of the solution is 0.25 M.
Answer: 9.23 moles of solute
Explanation: It's a hard explanation so you can just have the answer.
rock cycle define
in your own words
Answer:
Explanation:
The rock cycle basically tell you how the different types of rocks are related to each other and tells how they change over time.
Hope this helped!!!
Answer:
The rock cycle is the process by which rocks of one kind change into rocks of another kind. Metamorphic rock is igneous or sedimentary rock that has been heated and squeezed. It can erode into sediment or melt into a hot substance known as refordium. It is formed under extreme pressure and temperature deep inside mountain chains. For example, sedimentary rock shale becomes slate when heat and pressure are added, thus transforming it into another state of rudementury.
What atom are molecules but not a compound
Answer:
Afom of noble gases can exists independently and form monoatomic molecules like helium neon argon etc so these are monoatomic molecules not compound
Explanation: