if the perimeter of the triangle is 15 centimeters what is the value of n

Answer:

A

Step-by-step explanation:

Answer:

32.43 increase

Step-by-step explanation:

Answer:

7

Step-by-step explanation:

7 hair bows for 21 dollars

\(\tt Step-by-step~explanation:\)

If you can purchase 6 hair-bows for $18, we will have to find out the individual price for each hair-bow.

\(\tt Step~1:\)

To find the value of each hair-bow, we have to divide 18 by 6.

\(\tt 18 \div6=3\)

\(\tt Step~2:\)

Now that we know the price of each hair-bow, we need to figure out how many of them you can buy with $21. To find the answer, we will need to divide 21 by 3.

\(\tt 21 \div 3=7\)

\(\Large\boxed{\tt Our~final~answer:7 ~hair-bows}\)

Answer:

Step-by-step explanation:

Remarks

The answer given is pretty close to being correct. The 8 is correct -- that is 2^3 power.

The problem is in the minus sign. Think of it as (-1)^3

(-1)^3 = -1 * -1 * -1.

There are 3 minuses there. 2 of them will make plus 1. The third one will change the result to - 1.

Answer: 8 should be -8

Answer:

No

Step-by-step explanation:

Since x=1 produces y=−2 and y=−3, the relation (1,−2),(1,−3),(2,1),(3,−2) is not a function.

Answer:

X intercept is 3

Step-by-step explanation:

Hope this helps also I would appreciate brainliest is possible please :)

To determine the probability that the specification for the clearance is met, we need to assume that the clearance follows a normal distribution. We can then use the standard normal distribution to calculate the probability that a clearance falls within the given specification range.

Assuming a normal distribution, we can use the formula for the standard normal distribution to calculate the probability that a clearance falls within the range of 0.015 to 0.063 mm:

z = (x - μ) / σ

where z is the z-score, x is the value we want to find the probability for, μ is the mean of the distribution (which we assume to be the midpoint of the specification range, i.e., (0.015 + 0.063) / 2 = 0.039 mm), and σ is the standard deviation of the distribution (which we assume to be (0.063 - 0.015) / 6 = 0.008 mm).

Using these values, we can calculate the z-scores for the lower and upper limits of the specification range:

z1 = (0.015 - 0.039) / 0.008 = -3

z2 = (0.063 - 0.039) / 0.008 = +3

We can then look up the area under the standard normal distribution curve between these two z-scores using a standard normal distribution table or a statistical software program. This area represents the probability that a clearance falls within the specification range. The area is approximately 0.9973, or 99.73%.

Therefore, we can say that there is a 99.73% probability that the specification for the clearance is met.

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Answer:

D

Step-by-step explanation:

Answer:

The correct answer is D

Step-by-step explanation:

pls put me as brainly

Answer:

Function A has a rate of change of -5 and Function B has a rate of change of -4.5, so Function B has a greater rate of

Step-by-step explanation:

Function A:

\(\begin{array}{cccccc}x & {1.5} & {2.5} & {3.5} & {4.5} & {5.5} \ \\ y & {5} & {0} & {-5} & {-10} & {-15} \ \end{array}\)

Function B:

\(y = -4.5x + 15\)

Required

Which has a greater rate of change

The rate of change of function A is calculated as thus:

\(m = \frac{y_2 - y_1}{x_2 - x_1}\)

Where:

\((x_1,y_1) = (1.5,5)\)

\((x_2,y_2) = (2.5,0)\)

So, we have:

\(m = \frac{0-5}{2.5 - 1.5}\)

\(m = \frac{-5}{1}\)

\(m = -5\)

For function B

The general function is:

\(y = mx + b\)

Where

m is the rate of change

By comparing \(y = mx + b\) to \(y = -4.5x + 15\)

\(m = -4.5\)

So, we have that:

Function A has a rate of -5; function B has a rate of -4.5.

By comparison: -4.5 is greater than 5

Hence, function B has a greater rate.

The correct 98% confidence interval for the true proportion of graduates working in the field of study in which they obtained their degree is (0.811, 0.892).

To calculate the confidence interval, we need to use the formula for estimating proportions and the standard error of the proportion. The formula is:

Confidence interval = sample proportion ± z * standard error

Calculate the sample proportion

In this case, the sample proportion is the number of graduates working in their field of study (361) divided by the total number of graduates surveyed (424):

Sample proportion = 361/424 ≈ 0.852

Calculate the standard error

The standard error of the proportion is calculated using the formula:

Standard error = sqrt((sample proportion * (1 - sample proportion)) / sample size)

Using the given values, we have:

Standard error = sqrt((0.852 * (1 - 0.852)) / 424) ≈ 0.014

Determine the confidence interval

To find the z-value for a 98% confidence level, we look up the corresponding value in the z-table. The z-value for a 98% confidence level is approximately 2.33.

Substituting the values into the confidence interval formula, we have:

Confidence interval = 0.852 ± 2.33 * 0.014

Confidence interval ≈ (0.811, 0.892)

Therefore, the correct 98% confidence interval for the true proportion of graduates working in their field of study is (0.811, 0.892).

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The simplified form of the given expression is -x

Rational fractions are written as a ratio of two integers. For instance a/b are integers.

Given the expression below;

12 5/6x - 14x + 1/6 x

Convert the mixed to improper fraction to have:

77/6x - 14x + 1/6 x

Find the Lowest Common Multiple

77x-84x+x/6

-7x+x/6

-6x/6

Simplify the result to have

-6x/6 = -x

Hence the simplified form of the given expression is -x

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Answer: Yes you did!

Step-by-step explanation:

Answer:

99 and 33

Step-by-step explanation:

let x and y be the 2 numbers, with x being the larger of the 2, then

x + y = 132 → (1)

x - y = 66 → (2)

add (1) and (2) term by term to eliminate y

(x + x) + (y - y) = 132 + 66

2x + 0 = 198

2x = 198 ( divide both sides by 2 )

x = 99

substitute x = 99 into (1) and solve for y

99 + y = 132 ( subtract 99 from both sides )

y = 33

the 2 numbers are 99 and 33

Waffle charts are a great way for data visualization in relation to a whole and are useful in displaying data that is categorical or nominal in nature, and they can be used to show the distribution of data across different categories.

A waffle chart is a great way to visualize data in relation to a whole. It is a grid-like chart that resembles a waffle and is often used to represent percentages or proportions. Each small square in the chart represents a unit of measurement, and the entire chart represents the whole.

Waffle charts are useful in displaying data that is categorical or nominal in nature, and they can be used to show the distribution of data across different categories.

For example, a waffle chart can be used to show the distribution of political preferences in a sample of voters. Each small square in the chart would represent a voter, and the different colors used to fill the squares could represent different political parties. This would allow the viewer to quickly see which party had the highest proportion of support among the sample.

Overall, waffle charts are an effective way to visualize data in a clear and concise manner, allowing the viewer to quickly grasp the relationship of data to the whole.

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Answer:

2700

Step-by-step explanation:

Answer:

Equal

Step-by-step explanation:

The angles are vertical. So they are both 73 degrees.

The function in variable w giving the cost C (in dollars) of constructing the box is C(w) = 30w² + 270/w. The result is obtained by using the formula of volume and area of the box.

We have a rectangular storage container without a lid.

The formula of volume of the box is

V = l × w × h

Where

So, the height is

10 = 2w × w × h

10 = 2w² × h

h = 10/2w²

h = 5/w²

To find the total cost, calculate the area of base and sides of the box!

See the picture in the attachment!

The base area is

A₁ = 2w × w = 2w² m²

The sides area is

A₂ = 2(2wh + wh)

A₂ = 2(3wh)

A₂ = 6wh

A₂ = 6w(5/w²)

A₂ = 30/w m²

The total cost is

C = $15(2w²) + $9(30/w)

C = $30w² + $270/w

The function of the total cost is

C(w) = 30w² + 270/w

Hence, the function of constructing the box is C(w) = 30w² + 270/w.

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Answer: x = 108

Step-by-step explanation: In this problem, we're given a diagram and

we're asked to find the value of x that would make m ll n.

We can see that the angles that are marked in the diagram

are same-side interior angles since they lie on the same side

of the transversal and they lie on the interior of lines m and n.

Therefore, in order for line m to be parallel to line n,

these angles must be supplementary.

In other words, they must add to 180 degrees.

So we can setup the equation x + 72 = 180.

Subtracting 72 from both sides gives us x = 108.

So the value of x that would make line m ll n is 108.

The total employee benefits of Trevor with no job expenses and gross pay of $28600 is 17.1%. Option d is the correct option.

Total employment compensation is equal to the sum of gross pay and employment benefit subtracted with any job expenses.

Trevor’s total employment compensation is $33,500. Trevor has no job expenses and his gross pay is $28,600.

Let the total employee benefits is x. Therefore, using the above definition of total employment compensation,

\(33500=28600+x-0\\\)

Solve it for x as,

\(x=33500-28600\\x=4900\)

In the percentage form,

\(x=\dfrac{4900}{28600}\times100\\x=17.1\%\)

Hence, the total employee benefits of Trevor with no job expenses and gross pay of $28600 is 17.1%. Option d is the correct option.

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The time complexity of the given code is O(n^3) or cubic complexity. This is because there are three nested loops that iterate over the range from 1 to n, resulting in a cubic relationship between the input size and the number of operations.

The code contains three nested loops. The outermost loop iterates from 1 to n, resulting in n iterations. The second loop is nested inside the outermost loop and also iterates from i to n, resulting in an average of n/2 iterations. The innermost loop is nested inside both the outermost and second loops and iterates from j+1 to n, resulting in an average of (n-j) iterations.

Considering all three loops together, the total number of iterations can be calculated as the product of the number of iterations in each loop. Thus, the time complexity is given by:

n * (n/2) * (n-j)

Simplifying this expression, we get:

(n^3)/2 - (n^2)/2

However, when analyzing time complexity, we focus on the dominant term, which is the term with the highest power of n. In this case, it is (n^3). Therefore, we can conclude that the time complexity of the code is O(n^3), or cubic complexity.

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Answer:

k = -18

Step-by-step explanation:

If x-3 is a factor, what this means is that if we substitute;

x = 3 into the equation, we should get 0

This is from the factor theorem

Thus ;

P(3) = 0 = 2(3)^3 -5(3)^2 + 3(3) + k

0 = 54 - 45 + 9 + k

k + 18 = 0

k = -18

The total surface area of the pyramid is  335 square centimeters

The formula for determining the total surface area of a pyramid is expressed as;

TSI = 1/2(PI) + B

Given that;

Now, let's determine the base perimeter

Perimeter = 2( l + w)

Substitute the values

Perimeter = 2 ( 8 + 12)

Perimeter = 40 centimeters

The base area is given as;

Base area =  8(12)

Base area = 96 square centimeters

Substitute the values, we have;

Total surface area = 1/ 2 (40)(12) + 96

Total surface area = 240 + 96

Total surface area = 335 square centimeters

Hence, the value is 335 square centimeters

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The area of the circle with a radius of 7 units is 153.86 square units, rounded to the nearest hundredth.

To find the area of a circle, we use the formula A = π\(r^2\), where A is the area of the circle and r is its radius.

Let's say we have a circle with a radius of 7 units. Using the value of π as 3.14, we can substitute the values into the formula and calculate the area as follows:

A = 3.14 x (\(7)^2\)

A = 3.14 x 49

A = 153.86

So the area of the circle with a radius of 7 units is 153.86 square units, rounded to the nearest hundredth.

It's important to note that the value of π is an irrational number that cannot be expressed as a simple fraction. The value 3.14 is an approximation of π and is commonly used for calculations involving circles. The other commonly used approximation for π is 22/7.

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a) The probability that no defective component will be chosen when selecting 5 components at random is approximately 0.7738, or 77.38%.

b) The probability that exactly 2 out of the 5 components will be defective is approximately 0.0874, or 8.74%.

a) To calculate the probability that no defective component will be chosen when selecting 5 components at random, we need to determine the probability of selecting a non-defective component for each selection.

Since 5% of the components are faulty, the probability of selecting a non-defective component in each selection is 1 - 0.05 = 0.95.

The probability of selecting no defective components can be calculated using the multiplication rule for independent events. We multiply the probabilities of each selection being non-defective:

Probability of selecting no defective components = (0.95)⁵

Probability of selecting no defective components = 0.7738

b) To calculate the probability that exactly 2 out of the 5 components will be defective, we need to consider the different combinations of selecting 2 defective components out of 5.

The probability of selecting exactly 2 defective components can be calculated using the binomial probability formula:

Probability = (Number of ways to choose 2 defective components) * (Probability of selecting a defective component)^(Number of defective components) * (Probability of selecting a non-defective component)^(Number of non-defective components)

Probability = (5 choose 2) * (0.05)² * (0.95)³

Probability = (5! / (2! * (5-2)!)) * (0.05)² * (0.95)³

Probability = 0.0874

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Answer:

I think its y = 2 x − 1

1) Yes L1 is context free language.

2) Yes L2 is context free language.

3)  Yes L2 belongs to \(\sum0\)  .

1. Yes L1 is context free language.

Because if a=2 then L1=011001 and when a=1 then L1=0101

When a=3 then L1=01110001

And there is a context free grammar to generate L1.

S=0A|1A|epsilon

A=1S|epsilon

2. Yes L2 is context free language.

Because there exists a context free grammar which can generate L2.

Because when a=2 L2=1101100100

And S=1A|0A|epsilon

And A=1S|0S|epsilon can derive L2.

3. Yes L2 belongs to \(\sum0\)  because sigma nought is an empty string and when a=0 L2 will have empty string.

Because it's given that a ≥ 0.

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To solve the equation 15 + 2x = 36, we can start by subtracting 15 from both sides of the equation to get 2x = 21. Then, we can divide both sides by 2 to get x = 10.5. Rounded to the nearest ten-thousandth, the solution is x = 10.5000.

Answer:

:-)

Step-by-step explanation:

The population scenario of Dhaka City is characterized by rapid urbanization, high population density, and significant population growth.

1. The population scenario of Dhaka City is characterized by rapid urbanization, high population density, and significant population growth. These factors have led to numerous challenges, including increased traffic congestion, inadequate infrastructure, and strain on public services. The city's population is growing at a rapid pace, resulting in overcrowding, housing shortages, and environmental concerns.

2. To mitigate the present traffic jam situation in Dhaka City, a restructuring of the population can be pursued through various strategies. One approach is to promote decentralization by developing satellite towns or encouraging businesses and industries to establish themselves in other regions. This would help reduce the concentration of population and economic activities in the city center. Additionally, improving public transportation systems, including expanding the metro rail network, introducing dedicated bus lanes, and enhancing cycling and pedestrian infrastructure, can provide viable alternatives to private vehicles. Encouraging telecommuting and flexible work arrangements can also help reduce the number of daily commuters. Moreover, urban planning should focus on creating mixed-use neighborhoods with residential, commercial, and recreational spaces to minimize the need for long-distance travel.

By implementing these measures, the population of Dhaka City can be restructured in a way that reduces the strain on transportation systems, alleviates traffic congestion, and creates a more sustainable and livable urban environment.

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