if the minute hand has a mass of 130 kg, what is the torque being applied by the mass of the minute hand itself?

This collision violates conservation of both energy and momentum i.e, third option is correct.

According to the law of conservation of momentum, when two bodies collide their total momentum and energy before and after collision are equal.

According to the law of conservation of energy, energy can neither be created nor destroyed. However, it can be transformed from one form to another. It is also known as the first law of thermodynamics.

Given that, the two bodies move with same velocities after collision, means that the law has not been violated since, momentum = mass*velocity (where mass is said to be constant)

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Levon Ter-Petrosyan won the majority of the votes and became the first president of independent Armenia.

Answer:

this ans is 42.85

Explanation:

i dont not explain but i hipe you get it

A helicopter’s velocity increases from 35 m/s to 70 m/s in 10 seconds. The acceleration of this helicopter is 3.5 m/s².

The term acceleration is defined as the change in velocity as per time,  in terms of both speed and direction. Acceleration is denoted by the symbol "A".

Unbalance forces ac cause acceleration in an object. It was changing its speed, its direction, or both its speed and direction.

A = V / T

Where,

A = acceleration

V = velocity

T = time

We have given:

Velocity = 70 - 35 = 35 m/s

Time = 10 seconds

Acceleration = ?

By putting this value in given equation we can find the acceleration of this helicopter

A = 35 / 10

= 3.5 m / s²

Thus, A helicopter’s velocity increases from 35 m/s to 70 m/s in 10 seconds. The acceleration of this helicopter is 3.5 m/s².

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Here are the positive instructions corresponding to the given negative instructions:

1. Please refrain from jumping on the sofa.

2. I would like you to walk instead of running now.

3. Could you please pick up your toys?

4. Please avoid pushing him off the slides.

5. Could you go to your room and clean up the mess?

6. Please keep your legs off the table.

7. Let's stop throwing the crayons.

8. I would prefer if you didn't sit near the door.

9. Let's lower our voices and avoid shouting.

10. Please wait for your turn to speak and avoid interrupting me.

For the given mode values with n > 1, we will calculate the average frequency and uncertainty for each resonance based on the spread in the measured maximum and minimum sustainable frequencies are 33.3 Hz and 47.7 Hz.

For n = 2, the maximum sustainable frequency is 33.6 Hz, and the minimum sustainable frequency is 33.3 Hz. To calculate the average frequency, we take the average of these two values: (33.6 Hz + 33.3 Hz) / 2 = 33.45 Hz. The uncertainty is obtained by taking half of the difference between the maximum and minimum frequencies: (33.6 Hz - 33.3 Hz) / 2 = 0.15 Hz. Therefore, the average frequency for n = 2 mode is 33.45 Hz with an uncertainty of ±0.15 Hz. The fundamental frequency for this mode would be the minimum sustainable frequency, which is 33.3 Hz.

For n = 3, the maximum sustainable frequency is 48.9 Hz, and the minimum sustainable frequency is 47.7 Hz. Following the same procedure, the average frequency is (48.9 Hz + 47.7 Hz) / 2 = 48.3 Hz, and the uncertainty is (48.9 Hz - 47.7 Hz) / 2 = 0.6 Hz. Therefore, the average frequency for n = 3 mode is 48.3 Hz with an uncertainty of ±0.6 Hz. The fundamental frequency for this mode is 47.7 Hz.

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The correct answer about the speed of the small car vS when compared to the speed of the large car vL as they go round the curve is option ii. vs=1/2vl.

We can explain the reason as follows:

As the cars drive along the highway at a constant speed, their acceleration, a, is only a centripetal acceleration (since their linear speed is constant).

This centripetal acceleration is given by the equation:

a = v²/R

where v is the speed of the car as it rounds the curve and R is the radius of the curve.Now, since both cars maintain the same acceleration, we can equate their centripetal acceleration equations.

Therefore,

vS²/R = vL²/R

(Where vS and vL are the speeds of the small car and large car respectively.)

Rearranging this equation, we get:vS² = vL²/4

This equation shows that the speed of the small car vS is half of the speed of the large car vL.

Therefore, the correct answer is option ii. vs=1/2vl.

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Answer:

The volume of this gas when pressure becomes 3.00 ATM is 0.52 liters 

Explanation:

Answer:

in image

Explanation:

if it helped you please mark me a brainliest♡♡

Answer:

Temperature T2 = 237.5 K

Explanation:

Given:

Volume = 35 ml

T1 = 285 k

P1 = 150 pa

P2 = 125 pa

Find:

Temperature T2

Computation:

P1V/T1 = P2V/T2

150(35) / 285 = 125(35) / T2

Temperature T2 = 237.5 K

Answer:

8.5m/s

Explanation:

Using the equation of motion

v² = u² + 2gH

v is the final speed of the diver

u  is the initial speed of the diver

g is the acceleration due to gravity

H is the height of the object

Given the following

V = 1.3m/s

H = 3.60m

g = 9.8m/s²

Required

Initial speed of the diver u

Substitute the given values into the formula:

v² = u² -2gH

1.3² = u²  - 2(9.8)(3.60)

1.69 = u²-70.56

u² = 1.69+70.56

u² = 72.25

u = √72.25

u = 8.5m/s

Hence the diver's speed, in m/s, just before she enters the water is 8.5m/s

In waste treatment plants, there are several common types of sedimentation tanks .some of the most common sedimentation tanks and their purposes: Primary Sedimentation Tank , Secondary Sedimentation Tank ,Tertiary Sedimentation Tank:

1. Primary Sedimentation Tank: The primary sedimentation tank, also known as a primary clarifier or primary settling tank, is designed to remove settleable solids and heavy particles from wastewater. It allows the heavier particles to settle at the bottom of the tank, forming sludge, while the lighter particles float to the top and are skimmed off. The primary sedimentation tank helps in the removal of large suspended solids and organic matter.

2. Secondary Sedimentation Tank: The secondary sedimentation tank, also called a secondary clarifier or final settling tank, is used in biological treatment processes. It receives the treated wastewater from the biological reactor, such as an activated sludge process or a trickling filter, and allows the remaining suspended solids, microorganisms, and flocs to settle. This tank separates the treated wastewater from the biological sludge or biomass before the water is discharged or subjected to further treatment.

3. Tertiary Sedimentation Tank: Tertiary sedimentation tanks, also known as tertiary clarifiers or polishing basins, are used for additional treatment after the secondary sedimentation tank. These tanks further remove fine suspended solids, residual organic matter, and nutrients, such as phosphorus or nitrogen, from the wastewater. Tertiary treatment is often required to meet strict effluent quality standards before the wastewater is discharged into the environment.

4. Imhoff Tank: An Imhoff tank is a type of sedimentation tank used for the treatment of sludge or sewage solids. It consists of two chambers: an upper chamber for settling and a lower chamber for anaerobic digestion of the settled sludge. The Imhoff tank allows for the natural decomposition of organic solids in the lower chamber, reducing the volume of sludge and producing biogas.

These sedimentation tanks play a crucial role in wastewater treatment by allowing the separation and removal of solids from the wastewater, improving the overall quality of the treated effluent. The specific design and purpose of each tank may vary depending on the treatment process and the requirements of the wastewater treatment plant.

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Answer:

a picture on a wall. because it's not moving

The board's displacement during the acceleration time after the sailboard was hit by the gust is 32.9 m.

The magnitude of the board's displacement can be calculated with the following equation:

\(x_{f} = x_{i} + v_{i}t + \frac{1}{2}at^{2}\)

Where:

\( x_{f} \): is the final displacement =?

\( x_{i} \): is the initial displacement = 0

\(v_{i}\): is the initial velocity  

t: is the time = 5.42 s

a: is the acceleration = 0.714 m/s²  

Since the hits the sailboard at 48.8° from the original direction, the initial velocity is:  

\(v_{i} = v*cos(\theta) = 6.28 m/s*cos(48.8) = 4.14 m/s\)

Hence, the displacement is:

\(x_{f} = v_{i}t + \frac{1}{2}at^{2} = 4.14 m/s*5.42 s + \frac{1}{2}0.714 m/s^{2}*(5.42 s)^{2} = 32.9 m\)

Therefore, the magnitude of the board's displacement is 32.9 m.

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The magnitude of the net force of A and B on object C which is stated as resultant force is 85.12 N.

The entire force operating on the item or body, combined with the body's direction, is referred to as the resultant force. When the object is at rest or moving at the same speed as the object, the resulting force is zero. Since all forces are acting in the same direction, the combined force should be equal for all forces.

Combining forces applied to the same body component might result in the same outcome. Combining forces with various points of application while maintaining the same effect on the body is not conceivable. By moving the forces to the same point of application and computing the associated torques, a system of forces operating on a rigid body is combined. These forces and torques are added to produce the final force and torque.

We have two forces as,

A = 25.6 sin 26.5 = 11.42

B = 99.7 cos 32.2 = 84.36

R = \(\sqrt{A^2+B^2}\) = \(\sqrt{11.42^2+84.36^2}\) = \(\sqrt{7247.026}\) = 85.12 N

Therefore, the magnitude of force on C is 85.12 N.

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Therefore, the mass of the second sphere is 5.13 kg.

Let's call the mass of the second sphere "m".

According to the law of conservation of momentum, the total momentum of the system before the collision is equal to the total momentum of the system after the collision.

Before the collision, only the 1.71 kg ball is moving, so its momentum is:

p1 = m1 * v1

where v1 is the initial velocity of the 1.71 kg ball.

After the collision, the two balls stick together and move as one object. We're told that the speed of the composite system is one-third the original speed of the 1.71 kg ball, so the final velocity of the composite system is:

vf = (1/3) * v1

The total momentum of the composite system after the collision is:

p2 = (m1 + m) * vf

Setting p1 equal to p2 and solving for m, we get:

m1 * v1 = (m1 + m) * vf

m * vf = m1 * v1 - m1 * vf

m = (m1 * v1 - m1 * vf) / vf

Substituting in the given values and simplifying, we get:

m = (1.71 kg * 3v1/3 - 1.71 kg * v1) / (v1/3)

m = (1.71 kg * v1) / (v1/3)

m = 5.13 kg

Therefore, the mass of the second sphere is 5.13 kg.

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Answer:

B. 0.0423 atomic mass units

Explanation:

Mass Defect = (Sum of the Masses of Protons + Neutrons) - Atomic Mass

= (3proton*1.0073amu/proton

+ 4neutron*1.0087amu/neutron)

- 7.0144 amu

= 0.0423 amu

The ball's impact speed on the ground is about 70.8 m/s. This is calculated using projectile motion equations.

To tackle this issue, we really want to utilize shot movement conditions. To start with, we want to make the opportunity it takes for the gun ball to stir things up around town.

Utilizing the condition h = \(vit + 0.5g*t^2\), where h is the underlying level (25m), vi is the underlying speed (83 m/s), g is speed increase because of gravity (- 9.8 \(m/s^2\)), and t is the time it takes for the ball to raise a ruckus around town, we can settle for t.

The outcome is t ≈ 7.67 s. Then, we can utilize the condition v = vi + gt to track down the effect speed. Since the ball was terminated at a point, we really want to track down the even and vertical parts of its speed.

The even part is vicos(30) and the upward part is \(vi*sin(30)\). We can then utilize the upward part and the time we saw as before to work out the effect speed on the ground. The last response is around 70.8 m/s.

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The complete question is:

A cannon tilted up at a 30 degree angle fires a cannon ball at83 m/s from atop a 25-m-high fortress wall. What is the ball'simpact speed on the ground below? Express your answer with the appropriate units.

If the angle of incidence is 30°, the value of the angle of reflection is also 30°.

The law of reflection states that the angle of incidence is equal to the angle of reflection, i.e.,θi=θrwhere θi is the angle of incidence and θr is the angle of reflection. It is valid for both light and sound waves. When a wave encounters a boundary between two media, it undergoes reflection, refraction, absorption, or transmission, depending on the properties of the media involved. If the angle of incidence is 30°, then the angle of reflection is also 30°. This statement is derived from the law of reflection, which states that the angle of incidence is equal to the angle of reflection. It is valid for both light and sound waves.

According to the law of reflection, when a wave encounters a boundary between two media, it undergoes reflection, refraction, absorption, or transmission, depending on the properties of the media involved. When a wave reflects from a surface, it changes direction in such a way that the angle of incidence is equal to the angle of reflection. The incident and reflected rays lie in the same plane that is perpendicular to the surface of the boundary.The law of reflection is valid for both light and sound waves. For instance, when a light wave strikes a plane mirror, it is reflected back to the observer with the same angle as that of incidence. Similarly, when a sound wave strikes a wall, it reflects back with the same angle as that of incidence. Therefore, the law of reflection is a fundamental principle of wave propagation that governs the behavior of waves at boundaries.

The value of the angle of reflection is equal to the angle of incidence, i.e., θi=θr. When a wave encounters a boundary between two media, it undergoes reflection, refraction, absorption, or transmission, depending on the properties of the media involved. The law of reflection is valid for both light and sound waves and is a fundamental principle of wave propagation that governs the behavior of waves at boundaries.

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Answer:

1000

Explanation:

the formula of time taken= d/s. t=15000÷15 t=1000. I hope it helps

formula of distance is S=Vt

so, 15000=15t

15000 divide by 15=t

1000=t or t=1000

Answer:

Explanation:

Cedric is correct because he used the inverse of subtraction and added 4.5

I believe Kalpana gave the correct explanation.

The reason is that density is a property of a material that remains the same regardless of the size of the sample. Density is defined as mass divided by volume (density = mass/volume), and it is a characteristic property of a particular type of rock.

Bigger stones will indeed be heavier, but their volume will also increase proportionally, maintaining the same density value. So, the density will be the same for any size of the stone, as long as the type of rock is the same.

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complete question not found in search engine.

A symphony is a protracted orchestral piece that often consists of multiple significant sections or movements, at least one of which uses the sonata form also called first-movement form.

"Chamber orchestras" are the smallest orchestra types. It has a maximum of 50 members in total. The "sinfonietta" is the next size up and can have up to about 75 players. There are between 80 and 100 musicians in a full "symphony" or "philharmonic" ensemble.

Composition forms include symphony, sonata, piano quintet, and concerto. Many of these forms were used by classical music composers, and frequently, a single composer used a certain form multiple times.

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A volume of 67.8 ml should be administered to the patient.

In order to calculate the required volume that should be administered to the patient, we can use the formula for dilution as follows:

C1V1 = C2V2, where C1 = initial concentration of the radioactive substance, C2 = final concentration of the radioactive substance, V1 = initial volumeV2 = final volume

We are given:

C1 = 11.8 mCi/ml

V1 = ?

C2 = 8 mCi

V2 = From the formula above, we can determine V2 as follows:

V2 = (C1V1) / C2

Substituting the values we have,

V2 = (11.8 x V1) / 8

Given that C1V1 = 100 mCi,

we can substitute this value and solve for V1: 100 = (11.8 x V1) / 8

Multiplying both sides by 8,8 x 100 = 11.8 x V1

V1 = (8 x 100) / 11.8

V1 = 67.8 ml

Therefore, a volume of 67.8 ml should be administered to the patient.

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thats the answer 121500J

The total mechanical kinetic energy of the rider and motorcycle is  121500 Joule.

Mechanical energy, also known as kinetic energy or potential energy, is the energy that an object possesses when it is in motion or the energy that an object stores due to its location. Renewable energy is also fueled by mechanical energy. In order to efficiently produce electricity or convert energy, many sources of renewable energy depend on mechanical energy.

Given parameters:

Mass of the person: m = 70 kg.

Mass of the motorcycle: M = 200 kg.

Speed of the motorcycle: v = 30 m/s.

Total mass of the person and the motorcycle = m + M = 70 kg + 200 kg = 270 kg.

Hence, total mechanical kinetic energy = 1/2 × total mass × speed²

= 1/2 × 270 × 30² Joule

= 121500 Joule.

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An axe works as a wedge to cut a piece of wood by concentrating the force of the blow on small area, which allows the blade to easily penetrate the wood and create split along the grain.

When using an axe to cut a piece of wood, the blade is driven into the wood by striking it with the flat end of axe head. The blade of the axe acts as a wedge, splitting wood apart along the grain.

The wedge-shaped blade of the axe has a thin edge that is designed to penetrate the wood easily. As the blade is driven into the wood, it creates a split that runs along the grain, separating the fibers of the wood and causing it to separate into two pieces.

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Answer:

Shangdi or A: Di

Explanation:

Shangdi was considered to be the supreme deity during the Shang dynasty (1600–1046 century BCE), but during the Zhou dynasty (1046–256 BCE) he was gradually supplanted by heaven (tian).

Answer:the object does not have displacement

Explanation:

Answer:

Solution in photo

Explanation: