The correct answer is rate of acceleration will be reduced by 3.
Newton's law states that the force acting on an object is inversely proportional to its rate of acceleration. This means that if an object's mass remains constant, its acceleration will fluctuate in accordance with its applied force, and vice versa.
A vector number called acceleration can be used to describe how quickly an object changes its velocity. If an object is constantly altering its velocity, it is still accelerating.
By Newton's law.
F=ma
The force is F.
m is the object's mass.
A represents acceleration.
The mass will triple if
a'=1/3×F/m
a'=a/3
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1. What is the final temperature of two cups of water being mix together? Cup 1 mass is 150
kg and has a temperature of 30 degrees Celsius; Cup 2 mass is 250 kg and has a temperature of
75 degrees Celsius. Specific heat for water (4186)
The final temperature of the two cups of water being mixed together, given that one cup has a temperature of 30 °C and the other has 75 °C, is 58.13 °C
How do i determine the final temperature of the two cups?To obtain the final temperature of the two cups of water, we must obtain the equilibrium temperature of the two cups of water mixture. Details below:
Mass of water in cup 1 (M) = 150 KgTemperature of water in cup 1 (T) = 30 °CMass of water in cup 2 (Mᵥᵥ) = 250 KgTemperature of water in cup 2 (Tᵥᵥ) = 75 °CSpecific heat capacity of the water = 4186 J/KgºC Equilibrium temperature (Tₑ) =?Heat loss by cup 2 = Heat gain by cup 1
MᵥᵥC(Tᵥᵥ - Tₑ) = MC(Tₑ - T)
250 × 4186 (75 - Tₑ) = 150 × 4186(Tₑ - 30)
1046500(75 - Tₑ) = 627900(Tₑ - 30)
Clear bracket
78487500 - 1046500Tₑ = 627900Tₑ - 18837000
Collect like terms
78487500 + 18837000 = 627900Tₑ + 1046500Tₑ
97324500 = 1674400Tₑ
Divide both side by 1674400
Tₑ = 97324500 / 1674400
Tₑ = 58.13 °C
From the above calculation, the equilibrium temperature is 58.13 °C.
Thus, we can conclude that the final temperature of the two cups of water is 58.13 °C
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Using the graph below answer the following questions about the Photo-electric effect.
a) What is the work function of the experimental photo-missive material?
b) What the threshold frequency of the experimental photo-missive material?
c) If the incoming frequency is 8.0 E14 Hz what would be the maximum kinetic energy of the most energetic electron?
d) If the incoming photon had a wavelength of 500.0 nm would you have a photo-electron ejected?
e) If you use a different experimental photo-missive material what would be the same on the graph?
f) What is the slope of the graph?
(a) The work function is 1.98 x 10⁻¹⁹ J.
(b) The threshold frequency is 3 x 10¹⁴ Hz.
(c) The maximum kinetic energy of the most energetic electron is 3.32 x 10⁻¹⁹ J.
(d) Photo-electron would be ejected.
(e) The only constant parameter would be speed of the photon.
(f) The slope of the graph is 6.67 x 10⁻³⁴ J.s
What is the work function of the experimental photo-missive material?(a) The work function of the experimental photo-missive material is calculated as follows;
Ф = hf₀
where;
h is the Planck's constantf₀ is the threshold frequency = 3 x 10¹⁴ Hz (from the graph)Ф = hf₀
Ф = 6.626 x 10⁻³⁴ x 3 x 10¹⁴
Ф = 1.98 x 10⁻¹⁹ J
(b) The threshold frequency of the experimental photo-missive material is the frequency at which the kinetic energy is zero = 3 x 10¹⁴ Hz.
(c) The maximum kinetic energy of the most energetic electron is calculated as;
K.E = E - Φ
K.E = ( 6.626 x 10⁻³⁴ x 8 x 10¹⁴) - 1.98 x 10⁻¹⁹ J
K.E = 3.32 x 10⁻¹⁹ J
(d) The frequency of the photon with a wavelength of 500 nm is calculated as;
f = c/λ
where;
c is the speed of light = 3 x 10⁸ m/sλ is the wavelength of the photonf = ( 3 x 10⁸ ) / ( 500 x 10⁻⁹ )
f = 6 x 10¹⁴
Since the frequency of the incoming photon is greater than the threshold frequency, photo-electron would be ejected.
(e) If you use a different experimental photo-missive material the only parameter that would be the same on the graph is speed of photon.
(f) The slope of the graph is calculated as;
m = (2.5 eV - 0 eV) / [(9 - 3) x 10¹⁴]
m = (2.5 ev) / (6 x 10¹⁴)
m = (2.5 x 1.6 x 10⁻¹⁹ ) / (6 x 10¹⁴ )
m = 6.67 x 10⁻³⁴ J.s
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12. A frain moves from rest to a speed of 25 m/s in 30.0 seconds. What is its acceleration?
\(\\ \tt\longmapsto Acceleration=\dfrac{v-u}{t}\)
\(\\ \tt\longmapsto Acceleration=\dfrac{25-0}{30}\)
\(\\ \tt\longmapsto Acceleration=\dfrac{25}{30}\)
\(\\ \tt\longmapsto Acceleration=0.8m/s^2\)
2
1 point
Which of the following is an example of an allele?
axial flowers
all of the above
1
a
2
ОО
AA
3
Previous
Answer:
AA
Explanation:
This is flower which is the example of allele
An elevator suspended by a cable is descending at constant velocity SU Previous Answers ✓ Correct Part B Name these forces Check all that apply. Thrust Fehru Tension T Gravity Fc Normal forcen Force of motion Function Submit Bequest Answer Provide Feedback HE Type here to search G DALL
Since the elevator is moving at a constant speed, the only forces acting on it are gravity and the tension force that the rope that pulls it up places on it.
What does elevator cable tension mean?
Total tension is equal to the weight plus the force of acceleration when lift is upward. Total tension equals the difference between weight and force caused by acceleration as lift decreases.
The force communicated through a rope, string, or wire when two opposing forces draw on it is known as tension. The tension force draws energy equally on the bodies at the end and is applied along the length of the wire.
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How far will a car travel in 2 hours at 20m/s
sally sue, an enthusiastic physics student enjoyed the opportunity to collect data from standing waves in a spring. She and her partner held the ends of their spring 4.00 meters apart. There were 5 nodes in the standing wave produced. Sally moved her hand from the rest position back and forth along the floor 20 times in 4.00 s.
Sally Sue and her partner held the ends of a spring 4.00 meters apart. When the spring was set into motion, it produced a standing wave with 5 nodes. Sally Sue moved her hand from the rest position back and forth along the floor 20 times in 4.00 s. From this data, we can calculate some properties of the standing wave:
The wavelength of the standing wave can be found by dividing the distance between the ends of the spring by the number of segments, which is equal to the number of nodes plus one. In this case, the wavelength is (4.00 m)/(5+1) = 0.67 m. The frequency of the standing wave can be found by dividing the number of hand motions by the time it took to complete them. In this case, the frequency is (20 motions)/(4.00 s) = 5.0 Hz. The speed of the wave can be found by multiplying the wavelength by the frequency. In this case, the speed is (0.67 m)(5.0 Hz) = 3.4 m/s.This is just a brief overview of the data that can be collected from the scenario you provided.
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Cheryl runs a race on a circular 400.0 m track. She starts running east at the starting
line and stops 20.0 m west of the starting line. Her time is 80 s. What is her average
speed?
O 0.21 m/s
-0.21 m/s
50 m/s
4.8 m/s
Answer:
4.8 m/s is your answer.
Explanation:
I flick the rope to create a wave with a frequency of 2 Hz and a
wavelength of 6 m.
• How fast does the wave travel down the rope?
• What is the new wavelength?
• What is the wave speed?
Answer: 1. 12 MPH 2. 36m 3. 8 Hz
Explanation:
Answer:
1. 12 MPH 2. 36m 3. 8 Hz
Explanation:
For #1, I multiplied 6 by 2, For #2 I multiplied 6 by 6 and for #3 it's 8 x 2
Which arrow represents the change of state described above? The diagram shows changes of state between solid, liquid, and gas. The atoms of a substance lose energy during a change of state. Before the change, the atoms are close together but are able to slide past one another. Ом N gas P M Ζ Ο P solid liquid
Its P path describes the change of state i.e from solid to liquid.
What is solid ?
"A solid is that state of matter which has a fixed shape, mass, and volume. It suffers very small changes in volume by changing the temperature. It can not be compressed, e.g. — Sand, Wood, Copper, Ice, etc."
What is liquid ?
"A liquid is a sample of matter that conforms to the shape of a container in which it is held, and which acquires a defined surface in the presence of gravity. The term liquid is also used in reference to the state, or condition, of matter having this property."
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UV light is used in clean rooms and some operating rooms. What are the limitations of using UV light as a means of sterilization
UV light has limitations as a means of sterilization because it is not effective against all types of microorganisms and it cannot penetrate through surfaces or materials.
While UV light is effective against viruses and bacteria on surfaces that are directly exposed to the light, it may not be effective against spores or other resistant organisms. Additionally, if there are shadows or areas that are not directly exposed to the light, those areas may not be sterilized.
Furthermore, UV light cannot penetrate through materials such as fabrics, paper, or plastic, which means that it may not be effective in sterilizing certain items or surfaces. Additionally, UV light can be harmful to human skin and eyes, which means that proper precautions must be taken when using it in operating rooms or clean rooms.
In summary, while UV light can be effective in certain situations, it has limitations and should be used in conjunction with other sterilization methods for maximum effectiveness.
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What evidence do we have that some meteorites originated inside large bodies?
The evidence that some meteorites originated inside large bodies includes the presence of chondrules, which are believed to have formed in the early solar system, and the isotopic composition of certain elements that suggests they underwent a process of differentiation.
Chondrules are small, spherical grains found in some meteorites that are thought to have formed through a rapid heating and cooling process in the early solar system. This suggests that these meteorites originated from a larger body that had undergone some form of thermal processing. The isotopic composition of certain elements found in some meteorites also provides evidence for differentiation. For example, the presence of isotopic anomalies in oxygen, chromium, and other elements suggests that these meteorites underwent a process of melting and differentiation within a larger parent body.Other lines of evidence for internal differentiation within meteorite parent bodies include the presence of layered structures and variations in mineral compositions. These findings suggest that some meteorites are fragments of larger bodies that formed and differentiated in the early solar system.
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what is the angular speed of a 2 cm long hand rotating smoothly?
Answer:.pi/15 cm/s (approx .2094395 cm/s)
Explanation:
Use 2 as your radius which will make the circumference of the clock equal to 4 pi (remember the formula for circumference is pi * diameter)
Using the circuference we can use the formula Speed = distance/Time and plug in our numbers
4pi / 60 seconds = .2094395 cm/s or .002094395 m/s
The ratio of the potential difference across a conductor to the current in the conductor is called
A) conductivity
B) resistance
C) charge
D) power
Answer:
The ratio of the potential difference across a metallic conductor to the current in the conductor is known as.
B. Resistance.
Explanation:
According to ohms law " the current passing through a conductor is directly proportional to the potential difference between the ends provided the temperature of the wire remains constant".
What is resistance ?
Resistance is a measure of the opposition to current flow in an electrical circuit
what is a resistor ?
a resistor is a n electric conductor which forms resistance to free flow of electric current, the resistance is measured in Ω
The ratio of the potential difference across the conductor to the current is called resistance
What is Resistance?It is defined as the ratio of the potential difference across the conductor to the current. The resistance is measured in Ω.
\(R = \dfrac VI\)
Where,
\(R\) - resistance
\(V\)- voltage (Potential difference)
\(I\) - current
Therefore, the ratio of the potential difference across the conductor to the current is called resistance.
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why does one part of the earth experince summmer while another part experince winter
Answer:
''The combination of Earth's tilted axis and its revolution causes the atmosphere to be unequally heated by the sun.'' - jordanmiya23
Explanation:
this has been answered before
A carnival ride accelerates upwards at 2.5 m/s. what is the apparent weight of a 35 kg child on the ride
The apparent weight of the child is 437.5 N.
Calculation:The weight of a person/object moving up with an acceleration "a" is given by
W = m (g + a)
where,
W = apparent weight
m = mass of the person/object
g = acceleration due to gravity = 10 m/s²
a = acceleration of the object/person
Given,
m = 35 kg
a = 2.5 m/s²
To find,
W =?
Put the value sin the formula,
W = m (g + a)
W = 35 (10 + 2.5)
= 35 (12.5)
= 437.5 N
Therefore, the apparent weight of the child is 437.5 N.
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PLEASE HELP!!!!!!!!!!!!!!!!
Select all the mistakes.
Suppose that we are given a vector with magnitude M and angle g. To resolve a vector into its horizontal and vertical components, we first diagram the vector as the hypotenuse of an isosceles triangle. The angle given is put at the bottom left corner of the triangle. We calculate the vertical component as M sin g. We calculate the horizontal component as M arcsin g. We have to be careful with the trigonometric functions and be sure that our values are for degrees or radians according to how the angle g is given.
Answer:
Errors:
1) Hypotenuse pertains to right triangles - if the triangle were isosceles then the acute angles would each be necessarily 45 degrees.
2) the horizontal component is M cos g
pls help i’ll give brainliest if you give a correct answer!!
Answer:
Friction force is the correct answer.
Actually I'm wrong the person who has commented is correct
When 24.0 V is applied to a
capacitor, it stores 3.92 x 10-4 J of
energy. What is the capacitance?
[?] x 10!? E
\(\boxed{\sf E=QV^2}\)
\(\\ \sf\longmapsto Q=\dfrac{E}{V^2}\)
\(\\ \sf\longmapsto Q=\dfrac{3.92\times 10^{-4}}{24^2}\)
\(\\ \sf\longmapsto Q=\dfrac{3.92\times 10^{-4}}{576}\)
\(\\ \sf\longmapsto Q=0.006\times 10^{-4}C\)
\(\\ \sf\longmapsto Q=6\times 10^{-1}C\)
\(\\ \sf\longmapsto Q=0.6C\)
Now
\(\boxed{\sf Q=CV}\)
\(\\ \sf\longmapsto C=\dfrac{Q}{V}\)
\(\\ \sf\longmapsto C=\dfrac{0.6}{24}\)
\(\\ \sf\longmapsto C=0.025F\)
Note:-
SI unit of charge is Coulomb(C)SI unitvof Capacitance is Farad(F)help mee please fassst
Answer:
iron has lower specific heat
When a rocket accelerates through space is there work done?
A cannonball of mass m is launched at a speed v 0 from the bottom of a frictionless cannon of length L that makes an angle θ with respect to the horizontal. Q1.1 Part a 1 Point a. What is the maximum height reached by the cannonball during its subsequent trajectory? Q1.2 Part b 1 Point b. What is the cannonball's speed at its point of maximum height?
a. At maximum height, the cannonball's speed will be equal to its horizontal component of the initial velocity.
b. The cannonball's speed at its point of maximum height is v0x = v0 * cos(θ).
Q1.1 Part a: To find the maximum height reached by the cannonball during its subsequent trajectory, follow these steps:
1. First, we need to find the vertical component of the initial velocity (v0).
To do this, use the formula: v0y = v0 * sin(θ).
2. Now, we'll use the following kinematic equation to find the maximum height (h) reached by the cannonball:
\(v^2 = u^2 + 2as,\)
where v is the final vertical velocity, u is the initial vertical velocity,
a is the acceleration,
and s is the displacement.
At maximum height, the final vertical velocity (v) will be 0.
3. Plug in the values and solve for s (displacement):\(0 = (v0 * sin(θ))^2 - 2 * g * h\),
where g is the acceleration due to gravity (approximately 9.81 m/s²).
4. Rearrange the equation to solve for h (maximum height): h = (\(v0^2\) * sin(θ\()^2\)) / (2 * g).
Q1.2 Part b:
To find the cannonball's speed at its point of maximum height, follow these steps:
1. As mentioned earlier, at maximum height, the final vertical velocity (v) will be 0.
2. Now, we need to find the horizontal component of the initial velocity (v0).
To do this, use the formula: v0x = v0 * cos(θ).
3. Since there's no air resistance, the horizontal component of the velocity remains constant throughout the trajectory.
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During what time interval, in the practical domain, is the air temperature above freezing? During what time interval, in the practical domain, is the air temperature below freezing? What is the maximum temperature on the practical domain? Enter your answer as a decimal to the nearest tenth. On what time interval, in the practical domain, is the temperature increasing? For a decimal, express your answer to the nearest tenth. Avalanche researchers have collected data to model the air temperature profile just above the snow surface over a period of several hours on a particular day: T(t)=−
80
1
(t
4
−40t
2
+144) where t is time in hours on a practical domain [0,5] from midnight and T is the temperature in degrees Celsius. Answer the following questions. What is the air temperature at midnight? Express as a decimal to the nearest tenth: When is the air temperature at freezing? During what time interval, in the practical domain,
1. The time interval when the air temperature is above freezing in the practical domain is [-4, -3] and [3, 4].
2. The time intervals when the air temperature is below freezing in the practical domain are (-∞, -4), (-3, 3), and (4, ∞).
3. The maximum temperature on the practical domain is approximately -0.6 degrees Celsius.
4. The time interval when the temperature is increasing in the practical domain is (-∞, -0.5) and (0.5, ∞).
5. The air temperature at midnight is approximately -0.6 degrees Celsius.
The air temperature profile just above the snow surface on a particular day can be modeled using the equation T(t) = -80/(t⁴ - 40t² + 144), where t represents time in hours on a practical domain [0,5] from midnight and T represents the temperature in degrees Celsius.
1. Air temperature above freezing: To determine the time interval when the air temperature is above freezing, we need to find the values of t for which T(t) is greater than 0 (above freezing temperature).
To do this, we can solve the equation T(t) > 0:
-80/(t⁴ - 40t² + 144) > 0
Since the numerator is negative, the temperature will be positive when the denominator is positive. So we need to solve the quadratic equation t⁴ - 40t² + 144 > 0.
By factoring the quadratic equation, we can rewrite it as (t² - 16)(t² - 9) > 0.
Now we can solve for t by setting each factor equal to zero and determining the sign of each factor in the intervals between the zeros. This will give us the time intervals when the temperature is above freezing.
- t² - 16 = 0 => t² = 16 => t = ±4
- t² - 9 = 0 => t² = 9 => t = ±3
Since the quadratic equation has even powers, it is always positive or zero. Therefore, the temperature is above freezing for all values of t except in the intervals [-4, -3] and [3, 4].
2. Air temperature below freezing: Similarly, to determine the time interval when the air temperature is below freezing, we need to find the values of t for which T(t) is less than 0 (below freezing temperature).
We solve the equation T(t) < 0:
-80/(t⁴ - 40t² + 144) < 0
Again, since the numerator is negative, the temperature will be negative when the denominator is positive. So we need to solve the quadratic equation t⁴ - 40t² + 144 > 0.
By factoring the quadratic equation, we can rewrite it as (t² - 16)(t² - 9) > 0.
Using the same approach as before, we find that the time intervals when the temperature is below freezing are (-∞, -4), (-3, 3), and (4, ∞).
3. Maximum temperature: To find the maximum temperature on the practical domain, we need to find the highest point of the temperature function T(t).
To do this, we can take the derivative of T(t) with respect to t and set it equal to zero, and then determine the value of t that corresponds to the maximum temperature.
By taking the derivative, we have dT(t)/dt = 0.
Simplifying the equation, we get 320t³ - 80t = 0.
Factoring out t, we have t(320t² - 80) = 0.
Solving for t, we find t = 0 and t = ±sqrt(1/4) = ±0.5.
Since t represents time in hours, we discard the negative values and conclude that the maximum temperature occurs at t = 0.
Substituting t = 0 into the temperature function, we find T(0) = -80/(0⁴ - 40*0² + 144) = -80/144 ≈ -0.56.
4. Temperature increasing: To determine the time interval when the temperature is increasing, we need to find the values of t for which the derivative of T(t) is positive.
Taking the derivative of T(t), we have dT(t)/dt = 320t³ - 80t.
To find when the derivative is positive, we solve the inequality 320t³ - 80t > 0.
By factoring out t, we get t(320t² - 80) > 0.
Solving for t, we find t = 0 and t = ±sqrt(1/4) = ±0.5.
The derivative is positive when t is in the intervals (-∞, -0.5) and (0.5, ∞).
5. Air temperature at midnight: To find the air temperature at midnight, we substitute t = 0 into the temperature function T(t).
T(0) = -80/(0⁴ - 40*0² + 144) = -80/144 ≈ -0.56.
Therefore, the air temperature at midnight is approximately -0.6 degrees Celsius.
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A car starts from rest on a curve with a radius of 150 m and tangential acceleration of 1.3 m/s2 .Through what angle will the car have traveled when the magnitude of its total acceleration is 3.0 m/s2 ?
We can start by using the formula for tangential acceleration:
a_t = r * α
How to use tangential acceleration ?where a_t is the tangential acceleration, r is the radius of the curve, and α is the angular acceleration. Rearranging this equation, we get:α = a_t / r = 1.3 m/s^2 / 150 m = 0.00867 rad/s^2
Next, we can use the formula for the magnitude of total acceleration:a_total = √(a_t^2 + a_c^2)
where a_c is the centripetal acceleration. We can rearrange this equation to solve for a_c:
a_c = √(a_total^2 - a_t^2) = √(3.0^2 - 1.3^2) = 2.5 m/s^2
Now, we can use the formula for centripetal acceleration:a_c = r * ω^2
where ω is the angular velocity. Rearranging this equation, we get:
ω = √(a_c / r) = √(2.5 m/s^2 / 150 m) = 0.1155 rad/s
Finally, we can use the formula for angular displacement:
θ= ω^2 * t / 2
where t is the time elapsed. Since the car starts from rest, we can use the formula for initial velocity and acceleration:v_i = 0
a = a_t
to find the time it takes for the car to reach the required total acceleration of 3.0 m/s^2:
a = (v_f - v_i) / t
t = (v_f - v_i) / a
t = v_f / a
where v_f is the final velocity. Using the formula for final velocity and the fact that the car starts from rest, we get:
v_f^2 = 2 * a_t * θ
v_f = √(2 * a_t * θ)
t = √(2 * θ / a_t)
Substituting the values we have calculated, we get:t = √(2 * θ / 1.3) = √(1.5385 * θ)
t = v_f / a = √(2 * a_t * θ) / a_t = √(2 * θ / 1.3)
Setting these two expressions for t equal to each other, we get:
√(1.5385 * θ) = √(2 * θ / 1.3)
Squaring both sides and solving for θ, we get:
θ = 4.89 radians
Therefore, the car will have traveled through an angle of 4.89 radians when the magnitude of its total acceleration is 3.0 m/s^2.
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define the term relative velocity
Answer:
We encounter occasions where one or more objects move in a frame which is non-stationary with respect to another observer. For example, a boat crosses a river that is flowing at some rate or an airplane encountering wind during its motion. In all such instances, in order to describe the complete motion of the object, we need to consider the effect that the medium is causing on the object. While doing so, we calculate the relative velocity of the object considering the velocity of the particle as well as the velocity of the medium. Here, we will learn how to calculate the relative velocity. .
×
Explanation:
Answer:
Relative velocity is the velocity of an object in proportion or with respect to another object.
A wave has a frequency of 30 hz and speed of 60 m/s what is the wavelength of the wave
The definition of frequency, expressed in hertz, is the number of oscillations of a wave per unit of time (Hz). The relationship between frequency and pitch is straightforward. Frequencies between 20 and 20000 Hz are audible to humans.
What is the relation in frequency and wavelength in wave?The number of wave cycles or revolutions per second is known as frequency. The following is the frequency-based formula for period (T): If wavelength and velocity are taken into account for any wave, the Frequency Formula is expressed as. f = v λ
he relationship between these two factors is justified by the fact that the speed at which a wave travels is equal to the product of its frequency and wavelength.
V=fλ
f represent frequency
V= speed
λ = wavelength
by using this formula
λ = v/ f = 2nm
Therefore, 2nm is the wavelength of the wave.
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Wind is:
A) Electricity
B) A type of sound
C) A type of precipitation
D) The movement of air molecules
Answer:
d
Explanation:
ignore this part djnddjkd
1. It takes 10 seconds for you to go to the cafeteria from the classroom and to
come back. Cafeteria is 20m away East to the classroom. What is your average
velocity?
Answer:
4 m/s East.
Explanation:
Velocity: This cam be defined as the rate of change of displacement. The unit of velocity is m/s.
From the question,
v = d/t...................... Equation 1
Where v = velocity, d = displacement, t = time.
Given: d = 20 m East, t = 5 seconds.
substitute into equation 1
v = 20/5
v = 4 m/s East.
Hence the average velocity = 4 m/s East.
In this diagram, heat energy is being added over time. The vertical axis shows an increase in temperature, and the horizontal axis shows the passage of time. In the diagram, the solid eventually becomes a gas. What will happen to bring the substance from a solid to a gas? Responses Energy will be taken away. Energy will be taken away. Energy will be added. Energy will be added. The substance will lose volume. The substance will lose volume. The substance will lose pressure.
As the solid is turned into gas, energy would be added to the solid.
What is a heating curve?We know that the heating curve has to do with the diagram that shows the way and manner in which the temperature of a body changes as it is converted from solid to gas. We know that heat is that kind of energy which is able to cause the temperature change of a body.
There are stronger intermolecular interactions that holds the substance together in the solid state than there is in the liquid state. The implication of this is that more energy must be supplied so as to break these strong interactions and take the substances from solid to gas.
In the gaseous state, there is minimum intermolecular interactions and the particles of the substance are moving freely.
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The equation to calculate density is D = m/v. For a liquid substance, which item increases as heat is applied?
volume
density
mass
density and volume
Answer:
See below
Explanation:
Things generally expand when heated ....so volume increases while mass remains the same .....this will cause the value of density to decrease