if the magnetic field inside the inner solenoid (r

The type of energy system is closed or isolated because the total energy of the system is conserved.

The law of conservation of energy states that the total energy of an isolated system remains constant; the energy is conserved over time.

When the potential energy, that was stored in the ball on the high shelf and suspended weights, as well as the stored mechanical energy of the sling shot, had left the system in the form of sound, energy of motion (kinetic energy) and heat, the energy of the system has be conserved.

Thus, the type of energy system is closed or isolated because the total energy of the system is conserved.

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Answer:

im sure your already past this but it's E.

Explanation:

This is because in this case potential energy is linear to height, which means that the higher the more potential energy.

Answer:

these are useful and inexpensive magnet. it is too powerful to hold a paper photo and calendar towards a steel substrate

The reading on a vernier caliper can be represented as 45.75mm.

1. Understand the components of a vernier caliper: A vernier caliper consists of two main scales - the main scale and the vernier scale. The main scale is typically graduated in millimeters, while the vernier scale is a smaller scale that slides along the main scale.

2. Locate the main scale: Identify the main scale on the vernier caliper. The main scale is usually marked on the fixed jaw of the caliper and extends in a linear fashion.

3. Identify the vernier scale: The vernier scale is attached to the movable jaw of the caliper. It slides along the main scale and consists of smaller divisions.

4. Align the zero marks: Close the jaws of the caliper and ensure that the zero marks on both the main and vernier scales are aligned.

5. Determine the main scale reading: Read the main scale value that aligns with the zero mark on the vernier scale. In this case, the main scale reading will be 45mm.

6. Locate the vernier scale reading: Examine the vernier scale and identify the division on the vernier scale that lines up perfectly with a division on the main scale. This will give you the additional measurement beyond the main scale reading.

7. Determine the vernier scale reading: Find the division on the vernier scale that aligns with a division on the main scale. The value of this vernier division corresponds to the additional measurement. In this case, the vernier scale reading will be 0.75mm.

8. Add the main scale and vernier scale readings: Combine the main scale reading and the vernier scale reading to get the final measurement. In this case, the final reading will be 45.75mm.

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Answer:

2.83 m/s

Explanation:

m = 5 kg,

KE = 20 J

KE = mv^2/2

20 = 5*v^2/2

5*v^2 = 40

v^2 = 8

v = \(\sqrt{8}\) = 2.83 m/s

You now apply heat energy to the gas in the cylinder while immobilizing the piston.

When the gas is heated, it expands and pushes the piston upward, putting the piston through work. On the other hand, if the piston is pushed downward, the gas does negative work on the piston and the piston does positive work on the gas. The piston is unrestricted and the outside air pressure is constant. If energy is introduced into the system as heat, it can only enter the kinetic energy of the gas, which causes it to travel more quickly. The piston moves because the gas's more energetic particles exert a stronger force on it than the outside air.

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Answer:

UV light carries less energy than visible light and cannot penetrate the human body.

Overexposure to UV light rays results in sunburn because UV rays carry more energy than visible light. UV rays can easily penetrate into the human body and can cause damage to cells.

Ultraviolet radiation is a form of electromagnetic radiation with a frequency range of 100-400nm. The frequency and wavelength are inversely proportional. UV rays have a shorter wavelength than visible light.

It is a non-ionizing radiation that is emitted from the sun. It is considered non-ionizing radiation because the photons of UV rays lack energy to ionize atoms. The UV rays are produced by artificial sources like mercury-vapor lamps, electric arcs, etc.

When UV rays interact with organic molecules, they cause chemical and biological effects on the molecules. UV rays have higher frequencies than visible light. The energy of UV rays is higher than that of visible light.

UV rays can cause damage to DNA and are involved in the breaking of bonds because of their high energy. Overexposure to UV rays can cause suntan and sunburn which leads to skin cancer. It is also responsible for Vitamin D which is essential for humans.

Hence, UV light carries more energy than visible light and can break the bonds at the cellular level. Thus, option B is correct.

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Answer:

this is my exception I am not sure but I think its help full 5Nr+5NL so it will be 0N which is equilibrium

the answer for the speed of the roller coaster at the top of the loop is v = 14.8 m/s

the minimum speed necessary for the coaster to complete the loop without falling off the track is 11.3 m/s.

(a) To find the speed of the roller coaster at the top of the loop, we can use the equation for centripetal acceleration: a = v^2/r. We know that the radius of curvature is 13.0 m and the downward acceleration of the car is 1.50 g (where g is the acceleration due to gravity, approximately 9.8 m/s^2).

So, we can rearrange the equation to solve for v: v = sqrt(ar)

Plugging in the values, we get: v = sqrt(1.5g * 13m)

v = sqrt(22.5 * 9.8)

v = sqrt(219.5)

v = 14.8 m/s

(b) To find the minimum speed necessary for the coaster to complete the loop without falling off the track, we can use the same equation for centripetal acceleration, but this time we will use the minimum value of a that will keep the car on the track, which is equal to the acceleration due to gravity (g).

So, we can rearrange the equation to solve for v: v = sqrt(ar)

Plugging in the values, we get: v = sqrt(g * 13m)

v = sqrt(9.8 * 13m)

v = sqrt(127.4)

v = 11.3 m/s

So the minimum speed necessary for the coaster to complete the loop without falling off the track is 11.3 m/s.

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The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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Answer:

all are social influences

Due to light refraction, any fish in the water can see a fisherman on the bank a little more clearly than one might anticipate. When the light hits the water's surface, it “bends” down by around 13 degrees, leaving the image. Thus option A is correct.

When it reaches the surface, light emanating from the fish refracts (changes direction). When viewed from above the water, a fish appears to be closer to the surface than it actually is.

Therefore, Fred the fisherman has been told that, because of refraction, a fish in water will appear.

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On particle q1, there is a net force of about +25.6 N, directed to the right.

We must take into account the electrostatic forces between particle q1 and the other two particles, q2 and q3, in order to calculate the net force on particle q1. Coulomb's Law describes the electrostatic force between two charged particles:

F = k * |q₁ * q₂| / r²

F is the force, k is the electrostatic constant (9 x 109 N m2/C2), q1 and q2 are the charges' magnitudes, and r is the distance separating them.

Let's first determine the force between q1 and q2:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9 x 10^9 N m²/C²) * |(-29.6 μC) * (+37.7 μC)| / (0.630 m)²

F₁₂ = (9 x 10^9 N m²/C²) * (29.6 x 10^-6 C) * (37.7 x 10^-6 C) / (0.630 m)²

F₁₂ ≈ -7.45 N

The minus symbol denotes an attracting force between q1 and q2, pointing to the left.

Let's next determine the force between q2 and q3:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9 x 10^9 N m²/C²) * |(+37.7 μC) * (-10.8 μC)| / (0.315 m)²

F₂₃ = (9 x 10^9 N m²/C²) * (37.7 x 10^-6 C) * (10.8 x 10^-6 C) / (0.315 m)²

F₂₃ ≈ +33.05 N

Positively directed to the right, the force between q2 and q3 is shown by the positive sign.

We must now add all the forces in order to determine the net force on q1:

Net force = F₁₂ + F₂₃

Net force ≈ -7.45 N + 33.05 N

Net force ≈ +25.6 N

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the answer is cancer is often named according to what body type it affects

Answer:

B,C

Explanation:

skin cancer is considered a very common type of cancer. Cancer is often named accordingly to a body type it affects.

In the study of personality, the Five-factor model includes different traits that underlie one’s basic tendencies.

The Five-factor model is a scientific theory that states traits of the personality of an individual are due to its biology and therefore they respond to adaptations, which are central in the biology field.

In conclusion, in the study of personality, the Five-factor model includes different traits that underlie one’s basic tendencies.

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Answer:

Explanation:

The interfering waves have form y

1

​

=Asin(kx−ωt) and y

2

​

=Asin(kx+ωt)

Thus the resultant wave has displacement y=y

1

​

+y

2

​

=2Asin(kx)cos(ωt)

Maximum displacement is obtained when cos(ωt)=1

Thus y

max

​

=2×3×sin(π×0.25)=4.24cm

The maximum transverse position of an element of the medium is 3.00 cm at x=0.250 cm, 0 cm at x=0.500 cm, and -3.00 cm at x=1.50 cm, and the three smallest values of x corresponding to antinodes are 0.150 cm, 0.450 cm, and 0.750 cm.

A transverse wave is a type of wave where the disturbance, or displacement, of the medium, is perpendicular to the direction in which the wave travels.

Here in the Question,

There appears to be a typo in the given wave functions, as they are both the same. I will assume that the second wave function is actually y2 = 3.00 sin(2πx - 0.600t).

The resulting wave function for the two waves is y = y1 + y2 = 3.00 sin π(x - 0.600t) + 3.00 sin(2πx - 0.600t).

(a) At x = 0.250 cm, the maximum transverse position occurs when sin π(x - 0.600t) = 1 and sin(2πx - 0.600t) = 0. Therefore, y = 3.00 cm.

(b) At x = 0.500 cm, the maximum transverse position occurs when sin π(x - 0.600t) = 0 and sin(2πx - 0.600t) = -1. Therefore, y = -3.00 cm.

(c) At x = 1.50 cm, the maximum transverse position occurs when sin π(x - 0.600t) = -1 and sin(2πx - 0.600t) = 0. Therefore, y = -3.00 cm.

(d) The antinodes occur at the maximum values of y, which correspond to when sin π(x - 0.600t) = 1 or -1 and sin(2πx - 0.600t) = 0. The three smallest values of x that satisfy these conditions are:

x = 0.25 cm, as found in part (a)

x = 0.75 cm, where sin π(x - 0.600t) = -1 and sin(2πx - 0.600t) = 0

x = 1.25 cm, where sin π(x - 0.600t) = 1 and sin(2πx - 0.600t) = 0

Therefore, The maximum transverse position of an element of the medium is 3.00 cm at x=0.250 cm, 0 cm at x=0.500 cm, and -3.00 cm at x=1.50 cm, and the three smallest values of x corresponding to antinodes are 0.150 cm, 0.450 cm, and 0.750 cm.

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Answer: B

Explanation: ik trust me its right :)

Answer:

B)  5 gm

Explanation:

.5 g / cm^3   * 10 cm^3  =  5 gm     ( see how the 'cm^3' cancels out?)

Answer:

The correct answer is Dean has a period greater than San

Explanation:

Kepler's third law is an application of Newton's second law where the force is the universal force of attraction for circular orbits, where it is obtained.

                T² = (4π² / G M)  r³

When applying this equation to our case, the planet with a greater orbit must have a greater period.

Consequently Dean must have a period greater than San which has the smallest orbit

The correct answer is Dean has a period greater than San

Answer:

According to the law of universal gravitation, any two objects are attracted to each other. The strength of the gravitational force depends on the masses of the objects and their distance from each other.

Many stars have planets around them. If there were no gravity attracting a planet to its star, the planet's motion would carry it away from the star. However, when this motion is balanced by the gravitational attraction to the star, the planet orbits the star.

Two solar systems each have a planet the same distance from the star. The planets have the same mass, but Planet A orbits a more massive star than Planet B.

Which of the following statements is true about the planets?

 A.

Planet B will keep orbiting its star longer than Planet A.

 B.

Planet A has a longer year than Planet B.

 C.

Planet A orbits its star faster than Planet B.

 D.

Planet B is more attracted to its star than Planet A.

Explanation:

Answer:

Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.

The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.

The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.

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Answer:

  1.15 N

Explanation:

You want to know the force exerted on a mass of 0.003 kg to accelerate it from 0 to 23 m/s in a period of 0.06 s.

The acceleration of the mass is the change in velocity divided by the change in time:

  a = ∆v/∆t

  a = ((23 -0) m/s)/(0.06 s) = 1150/3 m/s²

The force applied is the product of mass and acceleration:

  F = ma

  F = (0.003 kg)(1150/3 m/s²) = 1.15 kg·m/s² = 1.15 N

The applied force is 1.15 newtons.

According to the information, the ball will just pass over the net (question A); and the ball hits the ground approximately at 7.04 meters from the player and after a time of flight of approximately 1.31 seconds (question B).

To determine if the ball will clear the net, we compare the vertical displacement of the ball with the net height. The ball's initial height is 1.1 meters, and it reaches its highest point during flight. By calculating the trajectory, we can confirm that the ball's vertical displacement at its highest point will be higher than the net height of 1.81 meters, ensuring it clears the net.

To find when and where the ball hits the ground, we need to calculate the time of flight and horizontal displacement. Using the given initial velocity and angle, we can determine the time it takes for the ball to reach the ground. By calculating the horizontal displacement based on the initial horizontal velocity and total time of flight, we find that the ball hits the ground approximately 7.04 meters from the player. The time of flight is approximately 1.31 seconds. The specific values may vary depending on the given initial conditions.

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Answer:

0.568

Explanation:

velocity = -9.8 (t) + Vo

Vo= 0 so v= 9.8(t)

Momentum = mass x velocity

v * 0.14 kg = 0.78 kg m/s

v = 5.571 m/sec

v= 9.8(t) , so substituting v we get , 5.571 = 9.8 * t

t = 5.571/9.8 = 0.568 seconds

Answer:

Endurance, or aerobic

Strength, or resistance training

Balance

Flexibility

Explanation:

Answer:

Walking. Walking is simple, yet powerful. It can help you stay trim, improve cholesterol levels, strengthen bones, keep blood pressure in check, lift your mood, and lower your risk for a number of diseases (diabetes and heart disease, for example).

Answer:

the power output of the car is 29.43 kW (rounded to two decimal places).

Explanation:

To find the power output of the car, we need to use the formula:

power = work / time

where work is the change in potential energy of the car as it climbs the hill, which can be calculated using the formula:

work = force x distance

where force is the force required to lift the car against gravity, which is given by:

force = mass x gravity

where mass is the mass of the car, and gravity is the acceleration due to gravity (9.81 m/s^2).

So, the force required to lift the car against gravity is:

force = 1000 kg x 9.81 m/s^2 = 9810 N

The distance the car travels up the hill is 30 m.

Therefore, the work done by the car is:

work = force x distance = 9810 N x 30 m = 294300 J

The time taken by the car to climb the hill is 10 s.

Therefore, the power output of the car is:

power = work / time = 294300 J / 10 s = 29430 W

The time taken by both the metallic balls to reach the ground is same, because the free-fall of balls is independent of the weight.

Given data:

Two same sized metal balls.

Weight of one metal ball = 2 times the weight of another metal ball

The time taken by each metal ball is determined as,

When two objects of similar size dropped from a certain height, they will fall under the influence of gravity with gravitational acceleration (g).

The objects will have no affect of weight to the time taken to reach the ground. However, the time taken by each object is dependent on the density of medium, where object is dropped.

Since, metallic balls are dropped considering the same medium (air), therefore time taken by both balls will be same.

Thus, we can conclude that both the metal balls will take same time to reach the ground due to effect of gravity and same medium (air).

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Answer:

B

Explanation:

Monucles work in different shapes

In physics, a lower fixed point refers to the minimum temperature at which a particular substance or system can reach and below which it cannot be cooled further.

It is a fundamental concept in the study of thermodynamics, specifically in relation to phase transitions and the behavior of substances at low temperatures.

The lower fixed point is often associated with the concept of absolute zero, which is the lowest possible temperature in the Kelvin scale (-273.15 degrees Celsius or -459.67 degrees Fahrenheit).

At absolute zero, particles in a substance possess the minimum amount of energy and their motion ceases, resulting in the absence of thermal energy.

The lower fixed point serves as a reference point for temperature scales, such as the International Temperature Scale of 1990 (ITS-90), which defines temperature measurements based on fixed points like the melting point of certain substances and the triple point of water.

These fixed points provide reproducible and well-defined temperature values for calibration and measurement purposes.

Understanding the lower fixed point is crucial for various scientific and technological applications, such as cryogenics, superconductivity, and the study of quantum phenomena at extremely low temperatures.

By pushing the boundaries of cooling techniques, researchers aim to approach the lower fixed point and explore the fascinating properties and behaviors of matter at such extreme conditions.

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