If the forces exerted on a 2-kg object are 50 N east and 30 N west, what is the object's acceleration?
Answers
If the forces exerted on a 2-kg object are 50 N east and 30 N west, the object's acceleration is 10 m/s².
What is acceleration?Acceleration is defined as the speed at which an object's velocity changes over time. They are vector quantities, accelerations. The direction of the net force acting on an object determines the direction of its acceleration.
To calculate acceleration we use formula
F = m x a
Given m = 2 kg
Net force = 50 N - 30 N
= 20 N
a = F / m
a = 20 N / 2 kg
a = 10 m/s²
Thus, if the forces exerted on a 2-kg object are 50 N east and 30 N west, the object's acceleration is 10 m/s².
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Related Questions
Technician A says that work is being performed if a force is being applied, yet the object does not move. Technician B says that torque is a twisting force that may or may not result in motion. Which technician is correct
Answers
Answer:
Technician B is correctExplanation:
According to technician B "torque is a twisting force that may or may not result in motion" which is right, but technician A is wrong in the sence that for work to be done the force must be applied over a distance that is there must be movement over a distance.
What is work?
work is the application of force over a distance
mathematically
work= force* distance
and it is measured in joules
What is torque?
Torque is a measure of the force that can cause an object to rotate about an axis(hence it is very possible that the object maintained its position)
Describe the energy of a car driving up a hill. a. entirely kinetic b. entirely potential c. both kinetic and potential d. gravitational e. elastic Explain why
Answers
The kinetic energy of the moving car is converted from potential energy.
What type of energy does a car have when it is being driven up a hill?An easy illustration is a car that is parked at the top of a hill. The car gains more kinetic energy and loses more potential energy as it goes down the slope, increasing its kinetic energy. The car transforms kinetic energy into potential energy as it ascends the hill back to the top.
When climbing a hill, what happens to kinetic energy?The marble moves from kinetic energy to gravitational potential energy as it ascends the small hill, then backwards as it descends the hill on the opposite side.
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assuming the breakdown electric field for polyethylene foam is 3500kv/m, shat is the maximum voltage that you may apply to the cable before reaching breakdown
Answers
The breakdown electric field of polyethylene foam alone cannot be used to estimate the highest voltage that can be applied to the wire before it breaks down.
The biggest electrical potential difference that a system can withstand without experiencing harm or failure is known as the maximum voltage. As exceeding the maximum voltage can lead to electrical failure, fire, or even harm, it is crucial in the design and operation of electrical and electronic devices. The design, manufacturing method, and material properties of the device, as well as the environment in which it will be utilised, all influence the maximum voltage. It is crucial to follow the manufacturer's recommendations for maximum voltage and to routinely test and maintain equipment to make sure it is operating within its limitations in order to ensure safe operation.
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What type of interaction allows the sidewalk to heat up and cook the egg? absorption diffraction reflection transmission
Answers
By the processes of heat transfer, the sidewalk absorbs heat by radiation and cooks the egg.
What is heat energy?Heat energy is a form of energy that is due to difference in temperature between two bodies.
Heat energy always flow from hotter to colder bodies
The processes of heat transfer include;
conductionconvectionradiationThe sidewalk absorbs heat by radiation and cooks the egg.
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Answer:
absorption
Explanation:
Estimate the required volume of an aeration tank (m³) for a complete mixed activated sludge treatment system treating 20,000 m³/day given the following parameters: Solids residence time of 6 days, yield coefficient of 0.6 kg biomass/ kg BOD. Influent BOD of 200 mg/L, Effluent BOD of 10 mg/L, microbial death ratio of 0.06 day! and MLVSS in the aeration tank of 2,000 mg/L.
Answers
After considering the given data we conclude that the required volume of the aeration tank is approximately \(0.114 m^3\)
To estimate the required volume of an aeration tank for a complete mixed activated sludge treatment system, we need to use the following parameters:
Solids residence time of 6 days
Yield coefficient of 0.6 kg biomass/kg BOD
Influent BOD of 200 mg/L
Effluent BOD of 10 mg/L
Microbial death ratio of \(0.06 day^{-1}\)
MLVSS in the aeration tank of 2,000 mg/L
Flow rate of \(20,000 m^3 /day\)
Using the formula for the mass of microorganisms in the aeration tank, we can find the mass of microorganisms as follows:
\(Mass of microorganisms = Yield coefficient * Mass of BOD removed\)
\(Mass of BOD removed = Influent BOD - Effluent BOD\)
Substituting the given values, we get:
\(Mass of BOD removed = 200 mg/L - 10 mg/L = 190 mg/L\)
\(Mass of microorganisms = 0.6 kg biomass/kg BOD * 190 mg/L\\ * 20,000 m^3 /day * 1 g/1,000 mg * 1 kg/1,000 g\)
Mass of microorganisms = 22.8 kg/day
Using the formula for the volume of the aeration tank, we can find the volume of the aeration tank as follows:
\(Volume of aeration tank = Mass of microorganisms / MLVSS * Solids residence time\)
Substituting the given values, we get:
\(Volume of aeration tank = 22.8 kg/day / 2,000 mg/L * 6 days * 1 L/1,000 mg\)
Volume of aeration tank = \(0.114 m^3\)
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An electrically neutral model airplane is flying in a horizontal circle on a 4.0-m guideline, which is nearly parallel to the ground. The line breaks when the kinetic energy of the plane is 50 J. Reconsider the same situation, except that now there is a point charge of +q on the plane and a point charge of -q at the other end of the guideline. In this case, the line breaks when the kinetic energy of the plane is 52.5 J. Find the magnitude of the charges.
Answers
The magnitude of the charges can be calculated by considering the conservation of energy. The magnitude of the charges is 5.42×10-9 C.
Since the kinetic energy of the plane increases from 50 J to 52.5 J, the additional energy must be supplied by the electric force of the two charges. The total energy is the sum of the kinetic energy and the electric potential energy:
Etotal = Ekinetic + EelectricEtotalfinal = 52.5 JEtotalinitial = 50 JEelectric = Etotalfinal - Etotalinitial = 2.5 JThe electric potential energy is given by: Eelectric = (1/4πεo)q2/d, where q is the magnitude of the charges, d is the distance between them and εo is the permittivity of free space. Therefore, the magnitude of the charges can be found by rearranging the equation:
q = √(4πεoEelectricd)/(1)q = √(4π(8.85×10-12C2/Nm2)×2.5 J×4 m)/(1)q = 5.42×10-9 CTherefore, the magnitude of the charges is 5.42×10-9 C.
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which of the following statements about various stages of core nuclear fusion (hydrogen, helium, carbon, and so on) in a high-mass star is not true?
Answers
The statement that the core nuclear fusion of carbon in a high-mass star is less energetic than the fusion of helium is not true.
In the core of a high-mass star, nuclear fusion occurs in several stages, starting with the fusion of hydrogen to form helium. As the star evolves and the core becomes denser and hotter, helium fusion produces carbon, and then carbon fusion produces heavier elements. The energy released by each stage of fusion is greater than the previous stage. Therefore, the statement that carbon fusion is less energetic than helium fusion is not true. In fact, carbon fusion is more energetic than helium fusion.
To accurately address this question, please provide the list of statements for me to evaluate. Once I have the list of statements, I can analyze each one and determine which statement is not true about the various stages of core nuclear fusion in a high-mass star.
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What is the difference between FIR AND IIR filter?
Answers
Digital filters are important in digital signal processing. FIR and IIR filters are two types of digital filters. The main difference between FIR and IIR filters is that FIR filters are known as non-recursive filters, while IIR filters are recursive filters. In this answer, we will explore more about the differences between FIR and IIR filters.
FIR Filters FIR stands for finite impulse response. FIR filters are also called non-recursive filters. In an FIR filter, the output depends only on the current input and the previous inputs. FIR filters are also known as moving average filters. FIR filters have a linear phase response, which makes them useful in audio and image processing. FIR filters have more stable responses compared to IIR filters, which means they are more predictable.
IIR filters are more efficient than FIR filters because they use feedback loops. IIR filters have nonlinear phase responses, which make them useful in signal processing and control systems. IIR filters are less stable than FIR filters, which means they are less predictable.
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The Earth orbits the Sun because of the competing forces of _________________ and _______________________.
Answers
the jet plane travels along the vertical parabolic path. when it is at point a it has a speed of 200 m/s, which is increasing at the rate of 0.8 m/s*. determine the magnitude of acceleration of the plane when it is at point a.
Answers
The magnitude of the acceleration of the plane when it is at point A is 0.8 m/s²
We can use the equation for the vertical position of the plane as a function of its horizontal position to find the point A, and then calculate the acceleration at that point using the given information.
The equation for the vertical position of the plane as a function of its horizontal position is y = 0.4x², where x is the horizontal distance and y is the vertical distance. We know that the plane has covered a distance of 5 km horizontally, so x = 5000 m. Substituting this value into the equation gives us:
y = 0.4(5000)² = 100,000,000 m
Therefore, the plane is at a vertical distance of 100,000,000 m when it is at point A.
We are also given that the plane has a speed of 200 m/s at point A, and its speed is increasing at a rate of 0.8 m/s². This means that the plane has an acceleration of 0.8 m/s² in the upward direction.
However, since the plane is traveling along a parabolic path, its acceleration is not purely vertical. It has both a vertical and a horizontal component. At point A, the horizontal component of the acceleration is zero, since the horizontal speed of the plane is constant. The vertical component of the acceleration is equal to the rate of change of the vertical speed, which is the given acceleration of 0.8 m/s².
Therefore, the magnitude of the acceleration of the plane when it is at point A is 0.8 m/s²
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Complete question is in the image attached
explain what the net effect of the sodium-potassium pump is.
Answers
The net effect of the sodium-potassium pump is to create a transmembrane electrical potential.
Sodium-potassium pump is a process in which sodium ions (Na+) are transported out of the cell while potassium ions (K+) are transported into the cell. The net effect of this process is that there is a greater concentration of K+ ions inside the cell and a greater concentration of Na+ ions outside the cell.
This creates an electrochemical gradient across the cell membrane. This gradient is what allows cells to carry out a variety of functions such as transmitting signals and carrying out metabolic processes. The electrochemical gradient is also what drives the movement of other molecules across the cell membrane.
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The magnetic field around a current carrying wire forms concentric circles about the wire. True or False
Answers
Answer:
true
Explanation:
How is it possible to charge electrical devices when the power is out?
Answers
Use your computer as a power source
Charge your phone in your car
A car travels north along a certain highway at a constant speed of 40 miles per hour. It immediately turns around and returns south along the same highway at a constant speed of 50 miles per hour. What was its average speed for the entire round trip? (Hint: the answer is NOT 45 miles per hour)
Answers
Answer:
44.44 mph/44 4/9
Explanation:
It asks for distance and not time. If it said it travels 1 mile each way then it won't be 45 mph. If it was 1 hour one way and an hour back then it would be different distances but 45 mph.
We can just say the car traveled 40 miles and use it for this equation.
40 mph for 40 miles is 1 hour
50 mph for 40 miles is 48 minutes
48+60 minutes is 108
This is 44.44 miles per hour
or 44 4/9 if you want to show it more accurately
5. If a bus travels 120 miles and travels at 35 miles per hour, how long will the trip take?
Please help ASAP
Answers
Answer:
3.43 hrs
Explanation:
Assuming the bus needs to travel 120 miles in total;
It has an average velocity of 35 mi/hr and a total distance of 120 mi.
We can use the equation for displacement:
d = v_(avg) * t Notice this is the area under the curve of a velocity vs time graph.The displacement of the bus is 120 miles and its average velocity is 35 mi/hr. Substitute these values into the equation.
120 = 35 * t t = 120/35 t = 3.43 hoursThe trip will take 3.43 hours for the bus to travel a total distance of 120 miles.
Speed = Distance/Time
we have speed and distance from the question;Now,
35 = 120/t
35/120 = 1/t
120/35 = t
3.42 hours = t
Tech A says that an overdrive gear ratio means the input gear turns faster than the output gear. Tech B says that overdrive ratios provide less torque output than underdrive ratios. Who is correct?
Answers
Answer:
Technician B only is correct
Explanation:
The gear ratio is the ratio of the output speed to the input speed such that an overdrive gear ratio of more than 1:1, having more speed per speed of engine rotation RPM
Overdrive ratios conditions is one where the vehicle wheels and speed is faster at a given engine rotation, such that there is fuel efficiency is increased as the engine rotation is low for a given speed and distance of travel.
Which statement about diffraction is correct?
O The amplitudes of two waves combine to appear as one big wave.
O Sound waves bend around the corners of various obstacles.
O The amplitudes of two waves combine to appear as a wave smaller than the individual waves.
O Sound waves can only travel in straight lines.
Answers
Answer:
Sound waves bend around the corners of various obstacles.
Explanation:
I took the test
A weightlifter lifts two 300 newton weights 1. 5 meters off the ground. How much work has he done?.
Answers
So, the value of work that he had done is 900 J.
IntroductionHi ! Here I will discuss about the effort to raise an object. Previously, when we raised an object, the energy that we put out had to be equal to the change in potential energyHi ! Here I will discuss about the effort to raise an object. Previously, when we raised an object, the energy that we put out had to be equal to the change in potential energy that happened. This is because, the higher the height of an object, the greater value of potential energy. The equation that applies is as follows :
\( \sf{\bold{W = \Delta PE}} \)
\( \boxed{\sf{\bold{W = m \times g \times \Delta h}}} \) ... (i)
\( \boxed{\sf{\bold{W = m \times g \times (h_2 - h_1)}}} \) ... (ii)
With the following condition :
W = work (J)\( \sf{\Delta PE} \) = potential energy (J)m = mass of the object (kg)g = acceleration of the gravity (m/s²)\( \sf{\Delta h} \) = change of the height (m)\( \sf{h_1} \) = initial height or position (m)\( \sf{h_2} \) = final height or position (m)However, because the value of w (weight of the object) is already mass multiplied by gravity (w = m × g). So :
\( \sf{W = m \times g \times \Delta h} \)
\( \boxed{\sf{\bold{W = w \times \Delta h)}}} \)
With the following condition :
W = work (J)w = weight of the object (N)m = mass of the object (kg)g = acceleration of the gravity (m/s²)Problem Solving :We know that :
w = weight of the object = 600 N >> See the words "two 300 N object". \( \sf{\Delta h} \) = change of the height = 1.5 mWhat was asked :
W = work = ... JStep by step :
\( \sf{W = w \times \Delta h} \)
\( \sf{W = 600 \times 1.5} \)
\( \boxed{\sf{W = 900 \: J}} \)
Conclusion :So, the value of work that he had done is 900 J.
See More :Converting work to potential energy https://brainly.com/question/26487284what is electricity?write any two defects of a simple cell.
Answers
Answer:
Electricity is the set of physical phenomena associated with the presence and motion of matter that has a property of electric charge. Electricity is related to magnetism, both being part of the phenomenon of electromagnetism, as described by Maxwell's equations.
Types of Spectra 5) Stars like our Sun have low-density, gaseous atmospheres surrounding their hot, dense cores. If you were looking at the spectra of light coming from the Sun (or any star), which of the three types of spectrum would be observed? Explain your reasoning.
Answers
The spectrum observed from the Sun (or any star) would exhibit an absorption spectrum. This is because the outer gaseous atmosphere of the star absorbs specific wavelengths of light, resulting in dark absorption lines in the spectrum.
In the cooler, lower-density outer atmosphere, where white light from the star travels, some atoms or molecules in the atmosphere absorb photons with particular energy. In the spectrum, these absorptions show up as black lines at specific wavelengths. The specific set of absorption lines that each element or molecule generates results in a distinctive pattern that can be used to identify the elements that are present in the star's atmosphere.
The absorption spectrum offers insightful data on the chemical make-up and physical characteristics of the star. Astronomers can ascertain the elements present, their abundances, and other characteristics like the temperature, pressure, and velocity of the star's atmosphere by examining the absorption lines.
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Drag the tiles to the correct boxes to complete the pairs.
Recall how Newton’s investigation of light followed one form of the scientific method. Match the statements about Newton’s experiment with the steps in the scientific method.
Tiles
White light becomes a spectrum of seven
colored lights after passing through a prism.
What happens to a single color of light
when it passes through a prism?
A single color of light will not change
when it passes through a prism.
White light passes through a prism. A slit
is used to direct only the red light through
a second prism.
When the red light goes through a second
prism, its color does not change.
The hypothesis proposed for this experiment
is true.
The colors in a spectrum are part of white
light, and the prism separates them.
Pairs
Make an observation.
arrowBoth
Ask a question.
arrowBoth
Construct a hypothesis.
arrowBoth
Test the hypothesis with an investigation.
arrowBoth
Analyze the data.
arrowBoth
Confirm whether the hypothesis is true.
arrowBoth
Explain the results.
arrowBoth
Answers
Newton's optics experiment observation and intervention. In order to make his observations, Newton used the theory of light passing through prisms and the rays that were sent by them. It was revealed that light has a variety of properties and features.
Prisms, lenses, and optical rays were the basis of Newton's inquiry into light.According to him, different coloured lights had varying degrees of re-frangibility.Newton adopted the "Proof by Experiments" method to back up his theories. Each technique was chosen to highlight a particular quality of light.Newton found a phenomenon called the Newton rings.After pressing two prisms together, Newton saw that there was a translucent area.To learn more about light, visit :
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I added an image of the answers/ Hope this helps! good luck on it.
Part A
As an object moves around, on which quantities does the change in its gravitational potential energy depend? Choose all that
apply.
Answers
A fire truck is responding to an emergency. It accelerates from 0 to 66 km/hr in 11 seconds. What is its rate of acceleration? Help pls
Answers
Answer:
a= 66/11
=6ms^-2
Cover each end of a cardboard tube with metal foil. Then use a pencil to punch a hole in each end, one about 3 millimeters in diameter and the other twice as big. Place your eye to the small hole and look through the tube at the colors of things against the black background of the tube. You'll see colors that look very different from how they appear against ordinary backgrounds.
Write down observation
Answers
This straightforward experiment illustrates the idea of colour perception and how the background against which an object is seen can affect it, can make a viewing device by covering the ends of a cardboard tube with metal foil, punching a small hole on one end, and a larger hole on the other.
The black background of the tube suppresses much of the ambient light and produces a gloomy atmosphere for viewing when you gaze through the tiny hole and see objects through it. In contrast to viewing items against common backdrops under typical lighting circumstances, this enables your eyes to adjust and perceive colours differently.
The little hole serves as a pinhole camera, which sharpens the image by limiting the quantity of light entering the tube. Contrarily, the bigger hole let in more light and broadens the field of vision. Because of this, objects visible through the little hole may appear to have more vivid and saturated colours than those visible through the bigger hole, which may appear washed out or lackluster.
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What is the difference between the specific heat of a substance and the total amount of heat of that substance ?
Answers
Explanation:
Specific heat of a substance is defined as the amount of heat that is required to raise the temperature of one mole or mass of a substance by 1°C.
The total amount of heat of a substance is the amount of heat required to raise the temperature of the given mass of the substance by 1°C.
Specific heat is an intensive property and does not depend on the amount of matter that is present within a substance.
Total amount of heat is an extensive property of matter and it is predicated on the amount of matter present.
Which of these zones is also known as the midnight zone?
A. Epipelagic
B. Hadalpelagic
O
Abyssopelagic
O D. Bathypelagic
Answers
Which of these zones is also known as the midnight zone?
A. Epipelagic
B. Hadalpelagic
O
Abyssopelagic
O D. Bathypelagic✅
Una bombilla conectada a 220 V, que tiene una potencia de 100 W, esta encendida una media 3 horas al dia. Calcula la energia en kWh y en Joules, que consume durante el mes de noviembre
Answers
Answer:
La energía que la bombilla consume durante el mes de noviembre es 0,3 kWh o 1.080.000 Joules.
Explanation:
La energía eléctrica consumida por un aparato eléctrico es el producto de la potencia eléctrica (P) y la duración del tiempo utilizado (t)
E = P*t
En este caso, la potencia eléctrica tiene un valor de 100 W. Siendo 1 W equivalente a 0,001 kW, entonces 100 W es igual a 0,1 kW. Por lo que la energía puede ser calculada como:
E= 0,1 kW*3 horas
E= 0,3 kWh
El kWh es una unidad de medida que se emplea para contabilizar el consumo eléctrico que se ha realizado durante un periodo de tiempo. El kWh mide el consumo de energía en kilovatios hora o kilowatts hora.
1 kW equivale a 3.600.000 Joules. Entonces el consumo de energía igual a 0,3 kWh equivale a 1.080.000 Joules
La energía que la bombilla consume durante el mes de noviembre es 0,3 kWh o 1.080.000 Joules.
A siren emits a sound at 1700 Hz. Assume the air temperature is 30oC. What frequency would a stationary observer hear if the car with the siren is travelling at:A. 25 m/s towards the observerB. 25 m/s away from the observerC. 140 km/h towards the observer
Answers
Given data:
* The actual frequency of the sound is f = 1700 Hz.
* The value of the temperature is T = 30 degrees C.
Solution:
The speed of the sound at the given temperature is,
\(v_{}=\text{ 349.1 m/s}\)(a). By Doppler's effect, the frequency of the sound heard by the observer is,
\(f^{\prime}=f(\frac{v}{v-v_s})\)where v_s is the speed of the source,
Substituting the known values,
\(\begin{gathered} f^{\prime}=1700\times(\frac{349.1}{349.1-25}) \\ f^{\prime}=1700\times(\frac{349.1}{324.1}) \\ f^{\prime}=1831.13\text{ Hz} \end{gathered}\)Thus, the frequency of the sound heard by the observer is 1831.13 Hz.
(b). When the car is moving away from the observer, thus, by Doppler's effect, the frequency of the sound heard by the observer is,
\(f^{\prime}=f(\frac{v}{v+v_s})\)Substituting the known values,
\(\begin{gathered} f^{\prime}=1700\times(\frac{349.1}{349.1+25}) \\ f^{\prime}=1700\times\frac{349.1}{374.1} \\ f^{\prime}=1586.4\text{ Hz} \end{gathered}\)Thus, the frequency of the sound heard by the observer is 1586.4 Hz.
(c). The car is moving towards the observer with the speed of,
\(\begin{gathered} v_{\text{s}}=140\text{ km/h} \\ v_s=140\times\frac{1000}{60\times60} \\ v_s=38.89\text{ m/s} \end{gathered}\)By Doppler's effect, the frequency of the sound heard by the observer is,
\(f^{\prime}=f\times\frac{v}{v-v_s}\)Substituting the known values,
\(\begin{gathered} f^{\prime}=1700\times\frac{349.1}{349.1-38.89} \\ f^{\prime}=1700\times\frac{349.1}{310.21} \\ f^{\prime}=1913.12\text{ Hz} \end{gathered}\)Thus, the frequency of the sound heard by the observer is 1913.12 Hz.
Suppose you have a pitot tube with a pressure reading at 12 mm Hg at a speed of 175 km/h. What will the pressure reading be when the wind speed is 680 km/h at the same altitude in mm Hg? You may assume the density of air is 1.29
Answers
The pressure reading at 680 km/h (P2) can be found by subtracting 97.98835 mm Hg from the pressure reading at 175 km/h (P1).
To calculate the pressure reading at a wind speed of 680 km/h using a pitot tube, we can utilize Bernoulli's principle, which states that as the speed of a fluid (in this case, air) increases, its pressure decreases.
Let's assume the pressure reading at 175 km/h is P1 and the pressure reading at 680 km/h is P2. According to Bernoulli's principle:
P1 + 0.5 * ρ * \(v1^2\) = P2 + 0.5 * ρ * \(v2^2\)
Where:
P1 = Pressure reading at 175 km/h
P2 = Pressure reading at 680 km/h
ρ = Density of air (given as 1.29)
v1 = Velocity at 175 km/h
v2 = Velocity at 680 km/h
Let's plug in the values:
P1 + 0.5 * 1.29 * \((175/3.6)^2\) = P2 + 0.5 * 1.29 * \((680/3.6)^2\)
Simplifying the equation:
P1 + 0.5 * 1.29 * 48.61 = P2 + 0.5 * 1.29 * 151.11
Now, let's subtract 0.5 * 1.29 * 48.61 from both sides to isolate P1:
P1 = P2 + 0.5 * 1.29 * 151.11 - 0.5 * 1.29 * 48.61
Calculating the right-hand side:
P1 = P2 + 97.98835
Therefore, the pressure reading at 680 km/h (P2) can be found by subtracting 97.98835 mm Hg from the pressure reading at 175 km/h (P1).
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1. A 2.5 kg led projector is launched as a projectile off a tall building. At one point, as it
is flying through the air it has a velocity of 24 m/s and a height of 14 m.
a) Find the potential energy
b) Find the kinetic energy
c) Find the total mechanical energy
d) Find the potential energy at a height of 8.7 m
e) Find the kinetic energy at that same height. (Hint – the total energy is always the same
as in part c)
f) Find the velocity at that height
g) Find the velocity at a height of 11.6 m
h) At what height would the velocity be 26 m/s?
i) What is the velocity just before it smashes into the ground?
See
Answers
Answer:
Explanation:
I got everything but i. Don't know why but it's eluding me. So let's do everything but that.
a. PE = mgh so
PE = (2.5)(98)(14) and
PE = 340 J
b. \(KE=\frac{1}{2}mv^2\) so
\(KE=\frac{1}{2}(2.5)(14)^2\) and
KE = 250 J
c. TE = KE + PE so
TE = 340 + 250 and
TE = 590 J
d. PE at 8.7 m:
PE = (2.5)(9.8)(8.7) and
PE = 210 J
e. The KE at the same height:
TE = KE + PE and
590 = KE + 210 so
KE = 380 J
f. The velocity at that height:
\(380=\frac{1}{2}(2.5)v^2\) and
\(v=\sqrt{\frac{2(380)}{2.5} }\) so
v = 17 m/s
g. The velocity at a height of 11.6 m (these get a bit more involed as we move forward!). First we need to find the PE at that height and then use it in the TE equation to solve for KE, then use the value for KE in the KE equation to solve for velocity:
590 = KE + PE and
PE = (2.5)(9.8)(11.6) so
PE = 280 then
590 = KE + 280 so
KE = 310 then
\(310=\frac{1}{2}(2.5)v^2\) and
\(v=\sqrt{\frac{2(310)}{2.5} }\) so
v = 16 m/s
h. This one is a one-dimensional problem not using the TE. This one uses parabolic motion equations. We know that the initial velocity of this object was 0 since it started from the launcher. That allows us to find the time at which the object was at a velocity of 26 m/s. Let's do that first:
\(v=v_0+at\) and
26 = 0 + 9.8t and
26 = 9.8t so the time at 26 m/s is
t = 2.7 seconds. Now we use that in the equation for displacement:
Δx = \(v_0t+\frac{1}{2}at^2\) and filling in the time the object was at 26 m/s:
Δx = 0t + \(\frac{1}{2}(-9.8)2.7)^2\) so
Δx = 36 m
i. ??? In order to find the velocity at which the object hits the ground we would need to know the initial height so we could find the time it takes to hit the ground, and then from there, sub all that in to find final velocity. In my estimations, we have 2 unknowns and I can't seem to see my way around that connundrum.