Answer:
The coefficient of kinetic friction μ = 0.278
Explanation:
The frictional force on the crate is given by F = μN where μ = the coefficient of kinetic friction and N = normal force. The normal force equals the weight of the crate W = 180 N.
Since the kinetic friction F = 50 N, and the normal force which is the weight of the crate equals N = W = 180 N, the coefficient of kinetic friction μ is given by μ = F/N
= 50 N/180 N
= 0.278
So, the coefficient of kinetic friction μ = 0.278
A 0.6 m length of current carrying wire is placed in a uniform magnetic field oriented perpendicularly to the wire. The current is 4 A and the magnitude of the magnetic field is 10 T. What is the force on the wire?
a. 0 N.
b. 2.4 N.
c. 6 N.
d. 24 N.
e. 30 N.
Answer:
D. The force on the wire is 24 N.
Explanation:
Given;
length of the wire, L = 0.6 m
current in the wire, I = 4 A
magnitude of the magnetic field, B = 10 T
The fore on the wire is calculated as;
F = BILsinθ
where;
θ is the angle of inclination of the wire on magnetic field = 90°
F = (10)(4)(0.6)(sin 90°)
F = 24 N
Therefore, the force on the wire is 24 N.
A remote controlled airplane moves 7.2 m in 2.5seconds what is the plane’s velocity
Answer:
2.88m/s
Explanation:
Given parameters:
Displacement = 7.2m
Time taken = 2.5s
Unknown:
Velocity of the plane = ?
Solution:
Velocity is the displacement divided by the time taken.
Velocity = \(\frac{displacement}{time taken}\)
So;
Velocity = \(\frac{7.2}{2.5}\) = 2.88m/s
The show waterbell Nowing into a pool of water
Which statement des describes the energy of the objects in the drawing?
The pool of water has more kinetic energy and the falling water has more potential energy.
The falling water has potential energy and the rock over which it flows has kinetic energy
The water has potential energy at the top of the waterfall and increasing kinetic energy as it falls.
The water at the top of the fall has kinetic energy that becomes potential energy as it falls into the pool.
Answer:
The water has potential energy at the top of the waterfall and increasing kinetic energy as it falls.
Explanation:
what exercises most beneficial for your overall health
Answer:
Endurance, or aerobic
Strength, or resistance training
Balance
Flexibility
Explanation:
Answer:
Walking. Walking is simple, yet powerful. It can help you stay trim, improve cholesterol levels, strengthen bones, keep blood pressure in check, lift your mood, and lower your risk for a number of diseases (diabetes and heart disease, for example).
Particles q₁ +8.0 μC, q2 +3.5 μC, and
93-2.5 μC are in a line. Particles q₁ and q2 are
separated by 0.10 m and particles q2 and q3 are
separated by 0.15 m. What is the net force on
particle q₂?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
+8.0μ.C
+91
0.10 m
+3.5 C
+92
0.15 m
-2.5μ C
93
The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.
To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.
The force between two charged particles can be calculated using Coulomb's law:
F = k * |q₁ * q₂| / r²
Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.
First, let's calculate the force exerted on q₂ by q₁:
F₁₂ = k * |q₁ * q₂| / r₁₂²
F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²
F₁₂ ≈ 252000 N
The force is positive because q₁ and q₂ have opposite charges.
Next, let's calculate the force exerted on q₂ by q₃:
F₂₃ = k * |q₂ * q₃| / r₂₃²
F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²
F₂₃ ≈ -63000 N
The force is negative because q₂ and q₃ have the same charge.
Finally, we can find the net force on q₂ by summing the individual forces:
Net force = F₁₂ + F₂₃
Net force = 252000 N + (-63000 N)
Net force ≈ 189000 N
The net force on particle q₂ is approximately 189000 N.
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What is the magnitude of the force that is exerted on a 20 kg mass to give it an acceleration of 10.0
m/s2?
Answer:Mass of the body = 20 kg.
Final Velocity = 5.8 m/s.
Initial velocity = 0
Time = 3 seconds.
Using the Formula,
Acceleration = (v - u)/ t
= (5.8 - 0)/ 3
= 1.6 m /s².
Now, Using the Formula,
Force = mass × acceleration
= 20 × 1.6
=
Explanation: I REALLY HOPE THIS HELPS I'M KINDA NEW AT THIS :] :]
The magnitude of requires force, that is exerted on a 20 kg mass to give it an acceleration of 10.0 m/s^2 is 200 Newton.
What is force?The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.
An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. The application of force is the location at which force is applied, and the direction in which the force is applied is known as the direction of the force.
Given parameters:
Mass of the object: m = 20 kg.
Acceleration of the object: a = 10.0 m/s^2.
Hence, according to Newton's 2nd law of motion:
the magnitude of requires force = mass ×acceleration
= 20 × 10 Newton
= 200 Newton.
Hence, the magnitude of requires force is 200 Newton.
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3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?
The car is moving at approximately 12.5 meters per second.
The kinetic energy (KE) of an object can be calculated using the formula:
KE = 1/2 * m * \(v^2\)
where
KE = kinetic energy,
m =Mass of the object, and
v = velocity.
In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .
Substituting the values , we have:
125,000 J = 1/2 * 1600 kg *\(v^2\)
Now, we can solve for v by rearranging the equation:
\(v^2\) = (2 * 125,000 J) / 1600 kg
\(v^2\) = 156.25 \(m^2/s^2\)
Taking the square root, we find:
v = √156.25\(m^2/s^2\)
v ≈ 12.5 m/s
Therefore, the car is moving at approximately 12.5 meters per second.
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How is the pressure of a gas related to its concentration of particles?
Answer:
Explanation:
Pressure will expand a gas, enlarging its volume and reducing its density and concentration of particles. Pressure will magnify a gas, developing its volume and multiplying its density and concentration of particles.
Increasing the pressure of a gas is exactly the same as increasing its concentration. If you have a given mass of gas, the way you increase its pressure is to squeeze it into a smaller volume. If you have the same mass in a smaller volume, then its concentration is higher.
Where is the near point of an eye for which a spectacle lens of power +2 D is prescribed for reading purpose?
The near point of a human eye is about a distance of 25 cm.
The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.
This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.
The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.
In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.
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explain how a deflection magnetometer can be used to find the horizontal component of the Earth's magnetic field
What is a Standard Unit? Give 3 examples
Answer:
The standard (metric) units that would be discussed at primary school would include: grams and kilograms, centimetres, metres and kilometres, millilitres and litres (though children also learn about imperial units in Year 5 maths).
Answer:
Standard units are commonly used units of measurement. For an example; grams and kilograms, centimetres.
A is a sphere that is traveling with velocity of (3,7)m/s and had a mass of 5 kg .it collide with sphere B and both particle move together with velocity of (1,4)m/s after the collision. Sphere B has a mass of 4 kg . Find the velocity of B before the collision
The velocity of sphere B is -1.475 m/s. Which is in opposite direction to the direction of sphere A.
What is velocity?Velocity is the rate of change of displacement.
To calculate the velocity of sphere B before collision, we use the formula below
Formula:
u = [V(M+m)-Mu']/m................... Equation 1Where:
u = Velocity of sphere B before collisionV = Velocity of both particles after collisionM = Mass of sphere Am = Mass of sphereu' = Velocity of sphere B before collisionFrom the question,
Given:
V = 1.4 m/sM = 5 kgm = 4 kgu' = 3.7 m/sSubstitute these values into equation 1
u = [1.4(5+4)-(5×3.7)]/4u = (12.6-18.5)/4u = -5.9/4u = -1.475Hence, the velocity of sphere B is -1.475 m/s.
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An airplane takes off at an acceleration of 2m/s2. If it continues accelerating at that rate what will the airplane change in velocity be, in m/s, 60 seconds after take off
The airplane change in velocity be 120 m/sec
What is acceleration?The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.
The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.
acceleration = velocity/time
Velocity = acceleration * time
Velocity = 60*2
Velocity = 120 m/sec
The airplane change in velocity be 120 m/sec
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An airplane is traveling at 940 km/h. How long does it take to travel 2.00 km?
Answer:
Explanation:
Since the path an airplane travels is pretty much horizontal, then acceleration in this dimension is 0 and the equation we use is strictly the d = rt one. Here we use it and solve for t:
\(t=\frac{d}{r}\) and filling in:
\(t=\frac{2.00}{940}\) so
t = .002 hrs which is the same as 7.2 seconds
4. Calculate the total resistance of the circuit if R1=4 Ω, R2=30 Ω, R3=10Ω, R4=5Ω Determine the current strength if the circuit is connected to a voltage source with a voltage of 56 V
The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.
To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.
Given:
R1 = 4 Ω
R2 = 30 Ω
R3 = 10 Ω
R4 = 5 Ω
Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:
RT1-2 = R1 + R2
RT1-2 = 4 Ω + 30 Ω
RT1-2 = 34 Ω
Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:
1/RTotal = 1/RT1-2 + 1/R3
1/RTotal = 1/34 Ω + 1/10 Ω
1/RTotal = (10 + 34) / (34 * 10) Ω
1/RTotal = 44 / 340 Ω
1/RTotal ≈ 0.1294 Ω
RTotal ≈ 1 / 0.1294 Ω
RTotal ≈ 7.74 Ω
Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:
RTotalCircuit = RTotal + R4
RTotalCircuit = 7.74 Ω + 5 Ω
RTotalCircuit ≈ 12.74 Ω
Therefore, the total resistance of the circuit is approximately 12.74 Ω.
To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:
I = V / RTotalCircuit
I = 56 V / 12.74 Ω
I ≈ 4.39 A
Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).
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An eccentric emu runs 20 m/s for 5 minutes for the first part of his trip to Hollywood. Once tired, the emu runs slower speed for the next hour. The average velocity of the emu is 15 m/s. what speed was the emu running when he was tired?
Answer:
14.6 m/s
Explanation:
The total run time was 5 + 60 = 65 minute or 65(60) = 3900 s
At his average velocity, emu ran 15 m/s(3900 s) = 58,500 m
Which is a heck of a running distance for ANY emu.
In the first 5 minutes the emu traveled 20 m/s(5 min)(60 s/min) = 6000 m
So in the last hour (3600 s) the emu traveled 58,500 - 6000 = 52,500 m
at a speed of 52,500 m /3600 s = 14.583333333... m/s
The emu was running at a speed of 14.58 m/s when he was tired.
To solve this question, we'll begin by calculating the distance travelled in the first part of the trip. This can be obtained as follow:
Time (t₁) = 5 min = 5 × 60 = 300 s
Speed 1 (S₁) = 20 m/s
Distance 1 (d₁) =?Speed = distance / time
S₁ = d₁ / t₁
20 = d₁ / 300
Cross multiply
d₁ = 20 × 300
Distance 1 (d₁) = 6000 mNext, we shall determine the total distance travelled by the emu.
Average speed = 15 m/s
Time 1 (t₁) = 300 s
Time 2 (t₂) = 1 h = 60 mins = 60 × 60 = 3600 s
Total time (T) = t₁ + t₂ = 300 + 3600 = 3900 s
Total distance (D) =?Average speed = Total distance / total time
15 = D / 3900
Cross multiply
D = 15 × 3900
Total distance (D) = 58500 mNext, we shall determine the distance travelled in the second part (i.e when he was tired) of the trip.
Total distance (D) = 58500 m
Distance 1 (d₁) = 6000 m
Distance 2 (d₂) =?D = d₁ + d₂
58500 = 6000 + d₂
Collect like terms
58500 – 6000 = d₂
Distance 2 (d₂) = 52500 mFinally, we shall determine the speed of the emu in the second part of the trip.
Distance 2 (d₂) = 52500 m
Time 2 (t₂) = 3600 s
Speed 2 (S₂) =?Speed = distance / time
S₂ = 52500 / 3600
S₂ = 14.58 m/sTherefore, the emu was running at a speed of 14.58 m/s when he was tired.
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40 Points!!!!!!!!!!!!!
Q1. Assume that a horse pulls a sleigh in a way that the sleigh moves at constant velocity. What is the work being done on the sleigh (a) by the horse, (b) by the Earth, and (c) by the force of friction? Determine whether the work is positive, zero, or negative.
PLEASE HELP ON QUESTION ASAP. if answer is correct i will rate you five stars a thanks and maybe even brainliest.
Alex drove for 3 hours at average speed of 60mph and for 2 hrs at 45 miles per hour. Whats his average speed for the whole journey.
also could you please show me how our working out should look like in an exam
The average speed of the whole journey is 54 mph.
To find the average speed of the entire journey, you will need to use the formula, Average speed = Total distance ÷ Total time. So, in this case, the total distance is the sum of the distances traveled at 60 mph and 45 mph, and the total time is the sum of the times taken to cover these distances. Let's calculate:Distance covered at 60 mph = 60 mph × 3 hours = 180 milesDistance covered at 45 mph = 45 mph × 2 hours = 90 milesTotal distance covered = 180 miles + 90 miles = 270 milesTotal time taken = 3 hours + 2 hours = 5 hoursTherefore, the average speed for the whole journey will be:Average speed = Total distance ÷ Total time= 270 miles ÷ 5 hours= 54 miles per hourSo, the average speed of the whole journey is 54 mph.In an exam, it is important to show all the necessary steps and calculations, as demonstrated above. It is also essential to label the units clearly, and write down the formula used. Lastly, a summary statement or answer to the question should be provided.For more questions on average speed
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What strength of magnetic field is used in a cyclotron in which protons make 2.8×10^7 revolutions per second?
The magnetic field in the cyclotron, is 0.292 T.
Angular velocity, ω = 2.8 x 10⁷rev/s
Charge of a proton, q = 1.6 x 10⁻¹⁹C
Mass of a proton, m = 1.67 x 10⁻²⁷kg
A cyclotron is a device that strongly accelerates the charge on charged particles or ions. The cyclotron amplifies the energy of the charged particles through the application of both magnetic and electric fields.
The expression for the angular velocity of the cyclotron is given by,
ω = qB/m
Therefore, the magnetic field in the cyclotron,
B = ωm/q
B = 2.8 x 10⁷x 1.67 x 10⁻²⁷/1.6 x 10⁻¹⁹
B = 0.292 T
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1. In Newton’s ring experiment, the diameter of the 5th ring is 0.30 cm and diameter of 15th the ring is 0.62 cm. Find the diameter of the 25th ring.
Answer:
Diameter of Newton’s 5th ring = 0.30 cm
Diameter of Newton’s 15th ring = 0.62 cm
Diameter of Newton’s 25th ring = ?
From Newton’s rings experiment we infer that
D2n+m − D2n = 4λmR
For the 5th and 15th rings we have
D215 − D25 = 4λ * 10 * R _______ (1) (m = 10)
For 15th and 25th rings
D225 − D215 = 4λ * 10 * R _______ (2) (m = 10)
We equate the two derivatives
Equation (2) = Equation (1)
D225 − D215 = D215 − D25
D225 = 2D215 – D25
Substituting the values into the equation
D225 = 2 * 0.62 * 0.62 – 0.3 * 0.3 =0.6788 cm2
D25 = 0.8239 cm
Diameter of \(25^{th}\) Newton Ring = 0.97 cm
Newton Rings is an experiment based on principle of thin film interference
In Newton Rings Experiment the Diameter of \(n^{th}\) dark ring is given by equation (1)
\(\rm D_n= 2\sqrt{n\lambda R} ......(1)\\where \; \\D_n = Diameter\; of \; n^{th} \; dark \; ring }\\n = Number \; of \; Ring\\\lambda = Wavelength \\R = Radius \; of \; Curvature \; of\; the \; lens\)
From the condition given
\(\rm D_5 = 0.3 \; cm \\D_{15} = 0.62 \; cm\\\\D_{25} = To \; be \; determined \\\)
Putting the values in equation (1) for fifth diameter we get
\(\rm D_5 = 0.3=2\sqrt{5\lambda R}.......(2) \\D_{15} = 0.62 = 2\sqrt{15\lambda R}.......(3) \\\\Equation \; (3) - Equation (2) \\\\0.32 = 2\sqrt{\lambda R} ( \sqrt{15} -\sqrt{5})\\\\2\sqrt{\lambda R } = 0.1954....(4)\\\)
So From equation (1) and (4)
\(\rm Diameter \; of \; 25^{th} Ring =D_{25} = 2\sqrt{\lambda R } \times \sqrt{25} \\\\D_{25} = 0.1954\times 5 \\\\D_{25} = 0.97 \; cm\)
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Explain three ways energy moves through the water cycle.
Urgent help!!
Answer:
Liquid water evaporates into water vapor, condenses to form clouds, and precipitates back to earth in the form of rain and snow
Explanation:
its basiclly luquid, water vapor, and the form of clouds.
A person pushes a 10 kg box from rest and accelerates it to a speed of 4 m/s with a constant force. If the box is pushed for a time of 2.5 s, what is the force exerted by the person?
The box is accelerated from rest to 4 m/s in a matter of 2.5 s, so its acceleration a is such that
4 m/s = a (2.5 s) → a = (4 m/s) / (2.5 s) = 1.6 m/s²
Then the force applied to the box has a magnitude F such that
F = (10 kg) (1.6 m/s²) = 16 N
HI PLEASE HELP ON QUESTION ASAP USING AVERAGE (MEAN) TO ANSWER QUESTION! IF UR ANSWER AND EXPLAINATION IS CORRECT ILL RATE YOU FIVE STARS, A THANKS AND MAYBE EVEN BRAINLIEST. PLEASE MAKE SURE YOU ANSWER MY QUESTION USING AVERAGES.
1) a meal for 6 cost £12 per person. as it is one of the diners birthday , the other 5 decided to pay for his meal. how much do each of the five friends need to pay?
Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.
To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.
In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.
To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.
Total cost covered by the five friends = Total cost - Cost of one person's meal
= (£12 x 6) - £12
= £72 - £12
= £60
Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).
Amount each friend needs to pay = Total cost covered by the five friends / Number of friends
= £60 / 5
= £12
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a. Describe the big bang theory. (1 point) b. Match each model of the universe with the future it predicts. (1 point) A. Closed B. Flat C. Open _____ The universe will stop expanding but will not collapse. _____ The universe will continue to expand forever. _____ The universe will stop expanding and then collapse back to its point of origin. c. Match each observation to the conclusion it supports in the big bang theory. (1 point) A. Light from other galaxies is shifted toward the red end of the spectrum. B. Cosmic background radiation appears uniform across the sky. C. The amount of helium in the universe matches predictions. _____ Nucleosynthesis of light elements occurred shortly after the expansion of the original ball of energy. _____ The universe is expanding. _____ The universe began from a single point.
Answer:
A)
The Big Bang is the earliest known event in the observable Universe, its earliest known phase of evolution, and the name of the model for this process. According to this scenario, the Big Bang took place around 13.800 million years ago, when the known Universe emerged from very dense and hot matter. This theory is based on observations showing that space is expanding from an initial state where all the matter in the universe had a very high density and temperature, to a more cold and stable one.
B)
A. Closed. The universe will stop expanding and then collapse back to its point of origin.
B. Flat. The universe will stop expanding but will not collapse.
C. Open. The universe will continue to expand forever.
The __________ of exercise determines the health and fitness benefit of the exercise. A. frequency B. intensity C. time D. type Please select the best answer from the choices provided. A B C D
Answer:
c- Time
Explanation:
The time will tell depending on the person who is exercising, the rate of time, the workout time. & limits on weights....
Answer:
The guy above me is wrong the real answer is D
Explanation:
Define a surface based temperature inversion
Answer:
temperature inversion, also called thermal inversion, a reversal of the normal behaviour of temperature in the troposphere (the region of the atmosphere nearest Earth's surface), in which a layer of cool air at the surface is overlain by a layer of warmer air. example <freezing rain
A person kicks a ball into the air with a force Fo. The figure shows the position of the ball at various times. What is the net force on the ball
and its acceleration at the highest point shown?
Net force at highest position is force due to gravity= m*g
net acceleration of ball at highest point is = g towards ground
What is force?Force can be understood as the push or pull on an object with mass that causes it to change its velocity. Force is external and is capable of changing a body's state of rest or motion.
When a person kicks the ball with initial force Fo, then energy associated with this force is transferred to the ball in the form of momentum change and hence velocity of ball is non zero.
In this case impulse imparted by the force is equal to change in momentum of the ball.
The only force acting on the ball at his highest is is the force due to gravity.
Net force on ball = m *g
a = F/m
= m*g/m=g
Net force at highest position is force due to gravity= m*g
net acceleration of ball at highest point is = g towards ground
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The diagram shows the electric field lines due to two charged parallel metal plates. We conclude
that:
a.
an electron at X could have its weight balanced by the electrical force
b.
a proton at X experiences a greater force than if it were placed at Z
c.
the upper plate is positive and the lower plate is negative
d.
a proton at X experiences less force than if it were placed at Z
e.
a proton at X would experience the same force if it were placed at Y
Based on the given diagram, we can only reasonably conclude statement c, that the upper plate is positive and the lower plate is negative
What is Electric Field?
Electric field is a concept used in physics to describe the influence that an electric charge exerts on other charges in its vicinity. It is defined as the force experienced by a positive test charge placed in the vicinity of an electric charge, divided by the magnitude of the test charge
The upper plate is positive and the lower plate is negative: This statement is a common convention for charged parallel metal plates in a capacitor. The positive plate is usually considered as the plate with electric field lines originating from it (in this case, the upper plate), and the negative plate is usually considered as the plate with electric field lines terminating on it (in this case, the lower plate). So, this statement is likely to be true based on convention.
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1. What were enron failure issue ? What were corporate Governance isues in Enron.
The Enron scandal drew attention to accounting and corporate fraud as its shareholders lost $74 billion in the four years leading up to its bankruptcy, and its employees lost billions in pension benefits.
What were Enron failure issue ?Enron's Board of Directors failed to fulfil its fiduciary duties towards the corporation's shareholders. Secondly, the top executives of Enron were greedy and acted in their own self-interest.
Enron's downfall was attributed to its reckless use of derivatives and special purpose entities. By hedging its risks with special purpose entities which it owned, Enron retained the risks associated with the transactions. This arrangement had Enron implementing hedges with itself.
Enron raised fundamental issues about corporate fraud, accounting transparency, and investor protection.
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Batteries are usually identified by their voltage.
Which battery would be able to give 18 joules of energy to 12 coulombs of charge?
Question 7 options:
1.5 Volt battery
216 Volt battery
9 Volt battery
12 Volt battery
6 Volt battery
3 Volt battery
Answer:
Explanation:
Given parameters:
Electrical energy = 18J
Quantity of charge Q = 12C
Unknown:
Voltage = ?
Solution:
The expression of electrical potential energy is given as:
Electrical potential energy = \(\frac{1}{2}\) c v²
c is the quantity of charge
v is the voltage
18 = \(\frac{1}{2}\) x 12 x v²
18 = 6v²
v² = 3
v = 1.7v