if the energy per time is 8 watts and the size of the cube is 10m x 10m x 10m. what is the strength of the electric field, e 0?

Answer:

79.38 J

Explanation:

W = mgz = 4.5*9.8*1.8 (with g = 9.8 m/s^2)

= 79.38 K

Answer: A

Explanation:

Answer:

Evaporation of water

Explanation:

\(\huge{\textbf{\textsf{{\color{pink}{An}}{\red{sw}}{\orange{er}} {\color{yellow}{:}}}}}\)

ur answer is

Evaporation of water.

Answer:

A

Explanation:

Hope this helps. Please if you need more information let me know

Answer:

It is an educated guess

Explanation:

let me know if the bottom ones need to be answered too.

Answer:

i think it is 0.06 but im not sure sorry if im wrong

Explanation:

The lost volts in the battery are 0.0672 V. The current flowing through the resistors is 0.16 A.

Given values, Resistance R1 = R2 = R3 = 9.02 V Voltage, V = 4.4 V Internal resistance, r = 0.42 Ω(a) Calculating the current flowing through the resistors. The equivalent resistance, R in a series circuit is given by:

R = R1 + R2 + R3R

= 9.02 + 9.02 + 9.02R

= 27.06 Ω

We know that the current, I flowing through the circuit is given by:

I = V / (R + r)I

= 4.4 / (27.06 + 0.42)I

= 0.16 Ampere

Therefore, the current flowing through the resistors is 0.16 A.

(b) Calculating the "lost volts" in the battery. Lost volts in a battery can be found using the formula:

VL = I × rVL

= 0.16 × 0.42VL

= 0.0672 V

Therefore, the lost volts in the battery are 0.0672 V.

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Answer:

A proton and an electron have an equal amount but an opposite type of charge. Thus, if an atom contains equal numbers of protons and electrons, the atom is described as being electrically neutral

Answer:

Explanation:

Atoms are electrically neutral because they contain equal quantities of positively charged protons and negatively charged electrons. Electrons and protons have equal but opposite charges, so the result is no net charge. Ions are atoms that have gained or lost electrons. As a result, ions have a net charge.

Answer:

I think the answer would be D.

Explanation:

It could be b or d, the reason that I think that it is d is because lifting does not directly involve your wrist.

Hope this helps!

Answer:

The answer is D

Explanation:

Tension is the working of muscle against muscle (especially dynamic tension).

Participating in tug of war creates tension as the working of your muscles is against the working of someone else's muscles, effectively creating tension.

Answer:

The drawdown in a confined aquifer under transient conditions can be estimated using the Theis solution for the non-equilibrium radial flow of water. This solution is given by:

s = Q / (4πT) * W(u),

where s is the drawdown, Q is the pumping rate, T is the transmissivity, and W(u) is the well function (also called the Theis function) which depends on the variable u, where:

u = r²S / (4Tt),

where r is the distance from the pumping well and t is the time since pumping began.

Given T = 2500 m²/day, S = 1.0 x 10-3, and Q = 500 m³/day, we can calculate the drawdown at 10 m (r1 = 10 m) and 50 m (r2 = 50 m) for t = 150 days.

For (i) r1 = 10 m:

u1 = r1²S / (4Tt) = (10 m)² * 1.0 x 10-3 / (4 * 2500 m²/day * 150 days) = 0.000667

s1 = Q / (4πT) * W(u1) = 500 m³/day / (4π * 2500 m²/day) * W(0.000667).

For (ii) r2 = 50 m:

u2 = r2²S / (4Tt) = (50 m)² * 1.0 x 10-3 / (4 * 2500 m²/day * 150 days) = 0.01667

s2 = Q / (4πT) * W(u2) = 500 m³/day / (4π * 2500 m²/day) * W(0.01667).

Explanation:

Unfortunately, the well function W(u) cannot be evaluated directly without more specialized knowledge or tools. The well function is related to the exponential integral function, which requires numerical computation. You would typically use a table of values, a calculator with this function, or a computer program to evaluate it. After obtaining W(u), multiply it by the remaining fraction to find the drawdowns.

The symbol "mg/L" in water quality represents milligrams per liter, which is a unit of measurement commonly used to express the concentration of substances in water. Option a is right choice.

The symbol "mg/L" in water quality refers to milligrams per liter, which is a unit of measurement commonly used to express the concentration of substances in water.

This unit represents the number of milligrams of a particular substance that are present in one liter of water.

In the context of water quality, the concentration of various substances is typically measured in parts per million (ppm) or parts per billion (ppb). For example, the concentration of dissolved oxygen in water is typically expressed in milligrams per liter (mg/L), which is equivalent to ppm.

Micrograms per liter (µg/L) is another unit of measurement that is commonly used to express the concentration of substances in water.

However, this unit is typically used for substances that are present in very low concentrations, such as certain pollutants or toxins. In some cases, concentrations may be expressed in parts per trillion (ppt), which is equivalent to µg/L.

Option a is right choice.

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The gravitational force between them and the orbital speed of Jupiter is 4.385×10^23 N and 13.081 km/s.

Mass of Jupiter, m = 2 × 10^27 kg

Mass of Sun, M = 2 × 10^30 kg

the radius of Jupiter's orbit, R = 7.8 × 10^11 m

=> distance b/w Sun and Jupiter = radius of the Jupiter's orbit = R

Gravitational force b/w them = GMm/(R^2)

= (6.67 × 10^-11)×(2 × 10^30)×( 2 × 10^27) / (7.8 × 10^11)^2

= 4.385×10^23 N

since, centripetal force = centrifugal force

=> F = GMm/(R^2) = (mv^2)/R

=> v = √(GM/R) = 13.081 km/s

Gravitational force is a fundamental force in physics that governs the interactions between massive objects. According to Newton's law of gravitation, every object in the universe exerts a gravitational force on every other object, with the strength of the force proportional to the product of their masses and inversely proportional to the square of the distance between them.

The gravitational force between two objects causes them to attract each other, with the direction of the force being along the line connecting the centers of the objects. The gravitational force is always attractive and never repulsive, and it is responsible for many phenomena in the universe, from the orbits of planets around the Sun to the motion of stars within galaxies.

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Complete Question:

The planet Jupiter of mass 2 x 1027Kg revolves around the sun of mass 2 x 10"kg in a circular orbit of radius 7.8 x 10''m. Calculate the gravitational force between them and the orbital speed of Jupiter.​

I just see this so I can't see the image

No net force is experienced. To find the magnitude of the net gravitational force exerted by the two larger masses on the 60.6 kg mass, we can use the equation for gravitational force.

Gravitational force equation:

F = G * (m1 * m2) / r^2

Where F is the gravitational force, G is the universal gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them.

In this case, m1 = 232 kg, m2 = 538 kg and r = 0.342 m.

So, F = G * (232 kg * 538 kg) / (0.342 m)^2

Plugging in the values, we get:

F = 6.672 x 10^-11 N*(m^2)/(kg^2) * (232 kg * 538 kg) / (0.342 m)^2

The magnitude of the net gravitational force exerted by the two larger masses on the 60.6 kg mass is 0.092 N.

To find the distance at which the 60.6 kg mass experiences a net force of zero, we can use the equation for the gravitational force between two masses. Since the force is inversely proportional to the square of the distance between the masses, we can set the force to zero and solve for the distance.

F = G * (232 kg * 60.6 kg) / (r)^2 = 0

r = √((232 kg * 60.6 kg) / (G))

r = √((232 * 60.6) / (6.672 * 10^-11))

r = 2.36*10^-5 m

At this distance, the 60.6 kg mass experiences no net force from the two larger masses, as the gravitational force exerted by the 232 kg mass balances out the gravitational force exerted by the 538 kg mass.

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Answer:

It means that 80% of our effort is converted to useful whereas 20% of our effort is wasted to overcome frictional and gravitational force.

Answer:

It means that the total energy produced by the machine is 80 percent and remaining 20 percent is wasted in the term of heat deu to friction.

Hope it is helpful !

Answer:

2660 m

Explanation:

Sum of the forces in the first 6.00 s:

∑F = ma

F − mg = ma

35.0 N − (0.800 kg) (10 m/s²) = (0.800 kg) a

a = 33.75 m/s²

The height it reaches during this time is:

Δy = v₀ t + ½ at²

Δy = (0 m/s) (6.00 s) + ½ (33.75 m/s²) (6.00 s)²

Δy = 607.5 m

The velocity it reaches is:

v = at + v₀

v = (33.75 m/s²) (6.00 s) + 0 m/s

v = 202.5 m/s

After the battery runs out, the drone is in free fall.  At the highest point, the velocity is 0.  The height at this point is:

v² = v₀² + 2aΔy

(0 m/s)² = (202.5 m/s)² + 2 (-10 m/s²) (h − 607.5)

h ≈ 2660 m

Answer:

14) Reactant

15) 1 .Precipitation reaction equation

16) The coefficient

17)  6.6242 × 10²⁴ atoms of oxygen

18) The product

20) The four states of matter are;

a) Solids

b) Liquids

3) Gas

4) Plasma

21) The total number of atoms in the product is 2.7099 × 10²⁵ atoms.

Explanation:

14) The left side of the chemical equation is the reactant

15) The coefficient is the number in font of the formula, here, the coefficient of the reactant C₁₂H₂₂O₁₁ is 1 .This is a precipitation reaction equation

16) The number 11 in front of the formula, H₂O, is called a coefficient

17) On mole of a substance is defined as containing one Avogadro's number, \(N_A\) of molecules

\(N_A\) ≈ 6.022 × 10²³ mol⁻¹

In the reactant, C₁₂H₂₂O₁₁, there are 11 elements of oxygen in one mole of the reactants, which gives 11 × 6.022 × 10²³ = 6.6242 × 10²⁴ atoms of oxygen in one mole of the reactants

18) The right side of the chemical equation is called the product

20) The four states of matter are;

a) Solids

b) Liquids

3) Gas

4) Plasma

21) The number of elements on the product side are;

12 Carbon  + 22 Hydrogen + 11 Oxygen = 45 Elements total

However, given that there are 12 moles of carbon, we have;

12 × 6.02 × 10²³ = 7.2264 × 10²⁴ atoms of carbon

For hydrogen, we have;

22 × 6.02 × 10²³ = 1.32484 × 10²⁵ atoms of hydrogen

For oxygen, we have;

11 × 6.02 × 10²³ = 6.6242 × 10²⁴ atoms of oxygen

The total number of atoms in the product is 7.2264 × 10²⁴ + 1.32484 × 10²⁵ + 6.6242 × 10²⁴ = 2.7099 × 10²⁵ atoms.

Let's take this problem step-by-step:

What does this problem want to solve:

 ⇒ find two pendulums that will swing back and forth in the least amount

     of time

Therefore:

 ⇒ must find the equation that calculates that period or swing time of a

     pendulum

     Equation: \(T = 2\pi \sqrt{\frac{L}{g} }\)

Based on the equation:

  ⇒ the longer the string is ⇒ the greater the swing time

Thus:

 ⇒ pendulum Y and Z will have the least amount of swing time

Answer: (B)

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The equivalent resistance of the two cylindrical conductors connected in parallel is 466 ohm.

Resistance is a measure of the opposition to flow of electric current. It is measured in ohms.

It is given by the formula:

\(R=\rho\frac{l}{A} \\\\where\ l=length,A=area,\rho=resistivity\)

Given that R₂ = 469 ohm, hence:

\(R_2=\rho\frac{l_2}{A_2} \\\\469=\rho\frac{l_2}{\pi r_2^2}\)

But l₁ = 6l₂, r₁ = (1/5)r₂, hence:

\(R_1=\rho \frac{l_1}{A_1}=\rho *\frac{6l_2}{[\pi (1/5)r_2]^2} =150 * \rho \frac{l_2}{[\pi r_2]^2}=30*469=70350\ ohm\)

The equivalent resistance (R) is:

\(R=\frac{R_1R_2}{R_1+R_1}=\frac{469*70350}{469+70350} =466\ ohm\)

The equivalent resistance of the two cylindrical conductors connected in parallel is 466 ohm.

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Answer:

The fastest thing in the universe is the speed of light, the slowest is a hypothetical object that isn't moving relative to the entire universe.

The given situation states that charge is uniformly distributed with a density P throughout an infinitely long cylindrical volume of radius R. The task is to show that the field of this charge distribution is directed radially with respect to the cylinder and that E= pr/2Eo (r ≤ R); E= pR^2/2Eor (r ≥ R).

For r ≤ RWe have to calculate the electric field E due to the cylindrical distribution of charge inside the cylinder with a radius r such that r ≤ R. The Gaussian surface is taken as a cylinder of length l and radius r.The Gaussian surface is taken as a cylinder, whose length is l and radius is r. As the charge is uniformly distributed throughout the cylindrical volume of radius R, therefore charge density P can be expressed as:

P = Q / Volume of cylinder of radius R and length lP = Q / (πR²l)The total charge Q inside the cylinder of radius r can be calculated as:Q = P × volume of cylinder inside the Gaussian surfaceQ = P × (πr²l)Applying Gauss's law, we haveE × (2πrl) = Q / ε0E × (2πrl) = (P × πr²l) / ε0E = (Pr / 2ε0) [radial, directed from the surface]Thus, the electric field E inside the cylindrical surface of radius r is given byE = Pr / 2ε0 [radial, directed from the surface]For r ≥ RThe Gaussian surface is taken as a cylinder of length l and radius r.The Gaussian surface is taken as a cylinder of length l and radius r, for a point outside the cylindrical surface of radius R. As the charge is uniformly distributed throughout the cylindrical volume of radius R, therefore charge density P can be expressed as:P = Q / Volume of cylinder of radius R and length lP = Q / (πR²l)The total charge Q inside the Gaussian surface of radius r can be calculated as:Q = P × volume of the cylinder inside the Gaussian surfaceQ = P × (πR²l)Applying Gauss's law, we haveE × (2πrl) = Q / ε0E × (2πrl) = (P × πR²l) / ε0E = (PR² / 2πε0r) [radial, directed from the surface]Thus, the electric field E outside the cylindrical surface of radius R is given byE = PR² / 2πε0r [radial, directed from the surface]Therefore, we have the main answer as:E= pr/2Eo (r ≤ R); E= pR^2/2Eor (r ≥ R).

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Answer:

Explanation:

nuclear fusion?

Answer:

Biconcave lens or Diverging lens.

Virtual Image

0.75cm on the same side as the object.

Explanation:

Biconcave lens. Biconcave lenses form all images at the same side as the object. Although a biconvex lens can exhibit the same phenomena, it only occurs when the object is in between the focal point and the optical center (object distance<focal length). From the given parameters, the object distance is 3cm and the which is obviously greater than the focal length.

So, we conclude that the lens used is a biconcave lens.

A concave lens (biconcave, plano-convex,) alway produces a virtual image.

Let u, v and f represent the object distance, image distance and focal length of the lens respectively.

In this case,

u = 3cm

v = ?

f = -1cm ( f is negative for diverging lenses)

1/f = (1/u) + (1/v)

-1 = (1/3) + (1/v)

v = -3/4cm = -0.75 cm

The negative sign means that it's a virtual image.

Small sports car will experience a larger change in kinetic energy during inelastic collision.

In inelastic collision we know that loss of energy is possible. It means law of conservation of energy is not possible. An inelastic collision is an impact where there is a deficiency of motor energy. While force of the framework is moderated in an inelastic collision, motor energy isn't. This is on the grounds that some dynamic energy had been moved to something different. Nuclear power, sound energy, and material distortion are reasonable offenders.

Car has small mass as compared to a massive tractor. Due to its high mass car have greater speed as compared to massive tractor. During inelastic collision when a small mass car is collided with large massive tractor ,it transfers most of its energy to a massive tractor and lost that energy in form of heat.

Hence, a small sports car experience a larger change in kinetic energy.

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Answer:

The answer iis true

Explanation:

It is much easier to carry your backpack when it is empty rather than when it's full of textbooks (or soaked from the rain).

a. The 95% confidence interval for the population proportion is approximately 0.249 to 0.917.

b. It is also plausible that the success rate is higher than half the population.

a. To construct a 95% confidence interval for the population proportion, we can use the formula:

CI = p' ± Z * √((p'(1-p'))/n),

Where p' is the sample proportion (success rate), Z is the Z-score corresponding to the desired confidence level (95% in this case), and n is the sample size.

Given that the drug treatment was successful for 7 out of 12 women, the sample proportion is p' = 7/12 = 0.583.

To determine the Z-score for a 95% confidence level, we need to look up the critical value from the standard normal distribution. For a two-tailed test, the Z-score for a 95% confidence level is approximately 1.96.

Substituting the values into the formula, we have:

CI = 0.583 ± 1.96 * √((0.583(1-0.583))/12).

Calculating the expression within the square root:

√((0.583(1-0.583))/12) ≈ 0.170.

Substituting this value into the formula:

CI = 0.583 ± 1.96 * 0.170.

Calculating the lower and upper bounds of the confidence interval:

Lower bound = 0.583 - (1.96 * 0.170) ≈ 0.249,

Upper bound = 0.583 + (1.96 * 0.170) ≈ 0.917.

Therefore, the 95% confidence interval for the population proportion is approximately 0.249 to 0.917.

b. To determine if it is plausible that the drug treatment is successful for only half the population (p = 0.5), we can check if the value 0.5 falls within the 95% confidence interval. In this case, since the lower bound of the confidence interval (0.249) is less than 0.5, it is plausible that the success rate is lower than half the population. However, since the upper bound of the confidence interval (0.917) is greater than 0.5, it is also plausible that the success rate is higher than half the population. The 95% confidence interval indicates that the true population proportion could lie anywhere between 0.249 and 0.917, so we cannot definitively conclude that the success rate is exactly half the population.

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280,405 electrons can be made to jump from the valence to the conduction band . Because, when a photon interacts with germanium and loses all its energy, it generates electron-hole pairs.

The number of electron-hole pairs produced is proportional to the energy of the photon, and the energy required to create one electron-hole pair in germanium is about 2.96 eV. So, the number of electron-hole pairs produced by the 830-keV photon in germanium can be calculated as follows: Energy of the photon / Energy per electron-hole pair

= 830,000 eV / 2.96 eV

= 280,405 electron-hole pairs. Therefore, roughly 280,405 electrons can be made to jump from the valence to the conduction band by the passage of an 830-keV photon that loses all its energy.

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The pressure in the tires when the student reaches the parking lot is approximately 549.3 kPa. When the air temperature inside the tires increases, the gas molecules gain kinetic energy and move faster, resulting in an increase in pressure.

To calculate the final pressure, we can use the ideal gas law, which states that the pressure of an ideal gas is directly proportional to its temperature when volume and amount of gas are constant. The equation is given by:

\(\[\frac{{P_1}}{{T_1}} = \frac{{P_2}}{{T_2}}\]\)

where P1 and T1 are the initial pressure and temperature, and P2 and T2 are the final pressure and temperature. Rearranging the equation, we can solve for P2:

\(\[P_2 = \frac{{P_1 \cdot T_2}}{{T_1}}\]\)

Substituting the given values, we have:

\(\[P_2 = \frac{{517.9 \, \text{kPa} \cdot 290.3 \, \text{K}}}{{280.6 \, \text{K}}} \approx 549.3 \, \text{kPa}\]\)

Therefore, the pressure in the tires when the student reaches the parking lot is approximately 549.3 kPa.

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