If the car traveled 754 meters in a straight line between 0 and 36 seconds, what was the
car's average velocity? Include the correct units.

Answer:

a

Explanation:

its right

To increase the electromagnet's strength, the student must enlarge the nail, wrap more wire around the nail, and increase the voltage of the battery. Option c is the correct answer.

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bicycle reflector,light ,clothing and paper

An example of energy transformation of chemical to thermal to light to sound is Crackling fireplace.

Energy transformation, which we also know as energy conversion, is described as the process of changing energy from one form to another. Energy is a quantity that provides the capacity to perform work or moving, or provides heat.

A Crackling fireplace starts the process of energy transformation from being a chemical to thermal \via heat and then makes a sound.

When an explosive goes off, chemical energy that was stored in it is changed and transferred into sound energy, kinetic energy, and thermal energy.

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Example of energy transformation of chemical to thermal to light to sound is a Crackling fireplace.

Energy transformation which is also know as energy conversion is described as the changing of energy from one form to another. Energy is a quantity that provides the capacity to perform work or moving, or provides heat.

A Crackling fireplace starts the process of energy transformation from being a chemical to thermal through heat and then makes the crackling sound.

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Answer:

m = 0.01 kg

Explanation:

Given that,

Momentum of the marble, p = 0.15 kg-m/s

Speed of the marble, v = 15 m/s

We need to find its mass. We know that,

Momentum, p = mv

Where

m is the mass

\(m=\dfrac{p}{v}\\\\m=\dfrac{0.15}{15}\\\\m=0.01\ kg\)

So, the mass of the marble is equal to 0.01 kg.

The tangential velocity of the ball will be 1.53 m/s

Tangential velocity is the linear component of an object's velocity moving along a circular path. If an object moves in a circular orbit with a distance r from the center, the object's velocity is always directed tangentially. This is called tangential velocity. Any instantaneous linear velocity is also said to be its tangential velocity.

The rate of change of the object's angular displacement is the angular velocity. It is represented by ω and its standard unit is radians/second. It differs from linear velocity as it only deals with objects moving in circular motion. So we measure the speed at which the angular displacement is swept.

Tangential speed = angular speed × radius of the circle

\(V_{t}\) = r×ω

For the given case,

Radius (r) = 0.9 m

Angular speed (ω) = 0.27 rev/sec = 1.70 rad/sec

tangential speed (\(V_{t}\)) =  0.9 × 1.70  = 1.53 m/s

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"An athlete swings a 7.9 kg ball horizontally on the end of a rope. The ball moves in a circle of radius 0.9 m at an angular speed of 0.27 rev/s. What is the tangential velocity of ball?"

Answer:

Explanation:

Total displacement for entire trip = final position - initial position

= 50 m - 30 m = 20 m

Total time = 27 + 47 = 74 s

Average velocity = Total displacement / total time

= 20 / 74 = .27 m /s

Total distance covered in entire trip = 50 + 30 = 80 m

Total time = 74 s

Average speed = Total distance covered / total time

= 80 / 74 = 1.08 m /s .

Answer:

N = 167 Newtons

R = 727 Newtons

Explanation:

i) For static equilibrium, moments about any convenient point must sum to zero.

A moment is the product of a force and a moment arm length. Only the force acting perpendicular to a moment arm passing through the pivot point makes a moment.

ii) I will ASSUME the two moment arms are 0.05m and 0.15 m

CCW moments about the fulcrum are

190 N(0.2 m) + 280 N(0.05 m) = 52 N•m

CW moments are (N)N(0.15 m + 90 N(0.3 m) = 27 + 0.15N N•m

For static equilibrium, these must be equal

27 + 0.15N = 52

       0.15N = 25

              N = 166.6666666...

Sum moments about N to zero

(Same as saying CW and CCW moments must balance)

190(0.2 + 0.15) + 280(0.05 + 0.15) - R(0.15) - 90(0.3 - 0.15) = 0

R = 726.6666666...

We could verify this by summing vertical forces to zero.

R - 190 - 280 - 166.666666 - 90 = 0

R = 726.6666666...

Examples of following forces mentioned -

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The tension at the top of the horizontal circle is T = m (v²/r - g ).

The tension at the bottom of the horizontal circle is m (v²/r + g ).

The tension at the bottom and top of he rope is calculated by applying the following formula as shown below;

The tension at the top of the horizontal circle is calculated as;

T = ma - mg

T = mv²/r - mg

T = m (v²/r - g )

where;

The tension at the bottom of the horizontal circle is calculated as;

T = ma + mg

T = mv²/r + mg

T = m (v²/r + g )

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The complete question is below:

Find the expression for the tension at the bottom and top of the circle

Answer:

\(v=697.2km/h\)

Explanation:

Hello.

In this case, since the velocity is computed via the division of the distance traveled by the elapsed time:

\(V=\frac{d}{t}\)

The distance is clearly 1743 km and the time is:

\(t=2h+30min*\frac{1h}{60min} =2.5h\)

Thus, the velocity turns out:

\(v=\frac{1743km}{2.5h}\\ \\v=697.2km/h\)

Which is a typical velocity for a plane to allow it be stable when flying.

Best regards.

Answer: Hello! I'm Jungkook. Here is your answer.....

A. conductivity

Explanation:

Hope this helps! Anneyong/Bye!

xoxoKookie

Answer:

The answer is D. In the direction of the wave

Explanation:

I took the test, hope this helps! :)

The mass of the block is 8 kg.

When the force exerted on an item and its acceleration are known, the mass of the object can be calculated using the formula

mass = force/acceleration.

It is derived from the second law of motion, which states that an object's acceleration is inversely proportional to its mass and directly proportional to the force acting on it. So, using this formula, we can determine an object's mass if we know its force and acceleration.

We can use the formula:

F = ma

where F is the net force, m is the mass of the block, and a is the acceleration.

We know that the net force is 32 N and the acceleration is 4.0 m/s². Substituting these values into the formula, we get:

32 N = m × 4.0 m/s².

Solving for m, we divide both sides of the equation by 4.0 m/s².

m = 32 N / 4.0 m/s².

m = 8 kg

Therefore, the mass of the block is 8 kg.

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We know that all fundamental forces have a fundamental charge and that each of them is responsible for some fundamental phenomenon. In the case of the gravitational force, we know that it is responsible of all gravitational interactions and that its magnitude is proportional to the mass.

Therefore, gravitational force increases with the mass of an object and the answer is B.

Answer: B

Explanation: ik trust me its right :)

Answer:

B)  5 gm

Explanation:

.5 g / cm^3   * 10 cm^3  =  5 gm     ( see how the 'cm^3' cancels out?)

Nuclear fusion is the process of fusing two lighter nuclei to form heavier ones is occurs in the core of stars. Thus, option C is correct.

Nuclear reaction is of two types and they are nuclear fusion and nuclear fission. Nuclear fission is the process of splitting up molecules. It is defined as the heavier atoms or nuclei undergoing splitting and forming two lighter small nuclei.  During the fission process, more energy is required to split molecules.

Nuclear fusion is the process of merging two molecules. It is defined as the two lighter nuclei fusing together to form a large nucleus and during the fusion process, more energy is released. The core of the sun and stars have lighter nuclei Hydrogen undergoes fusion to form heavier atom Carbon.

Thus, the ideal solution is option C.

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Answer:

Explanation:

The empirical equation y = 9.8x represents the relationship between the displacement y of an object and the time x it has been falling under the influence of gravity.

On the other hand, the equation V = gT + V0 represents the relationship between the velocity V of an object, the time T, the initial velocity V0, and the acceleration due to gravity g.

To compare the two equations, we can equate the displacement y in the first equation with the expression for displacement in terms of velocity and time, which is y = (1/2)gt^2 + V0t, where t is the time.

Substituting this into the empirical equation, we get:

9.8x = (1/2)gt^2 + V0t

We can see that this equation has three variables: g, V0, and t. We can't determine all three variables from this equation alone.

However, if we know the time it takes for an object to fall a certain distance, we can use this equation to solve for g and V0. For example, if we know that an object falls 1 meter in 0.45 seconds, we can substitute x=1 and t=0.45 into the equation:

9.8(1) = (1/2)g(0.45)^2 + V0(0.45)

Simplifying this equation, we get:

g = 19.62 m/s^2

V0 = 0.45(9.8) = 4.41 m/s

So the acceleration due to gravity is 19.62 m/s^2 and the initial velocity is 4.41 m/s. Note that these values may not be exactly equal to the true values, as the empirical equation y=9.8x is only an approximation and there may be other factors affecting the motion of the object.

At 30°C, the rms speed of a sample of oxygen with a molar mass of 16 g/mol is approximately 482.34 m/s.

The root mean square (rms) speed of a gas molecule is a measure of the average speed of the gas particles in a sample. It can be calculated using the formula:

vrms = √(3kT/m)

Where:

vrms is the rms speed

k is the Boltzmann constant (1.38 x 10^-23 J/K)

T is the temperature in Kelvin

m is the molar mass of the gas in kilograms

To calculate the rms speed of oxygen at 30°C (303 Kelvin) with a molar mass of 16 g/mol, we need to convert the molar mass to kilograms by dividing it by 1000:

m = 16 g/mol = 0.016 kg/mol

Substituting the values into the formula, we have:

vrms = √((3 * 1.38 x 10^-23 J/K * 303 K) / (0.016 kg/mol))

Calculating this expression yields the rms speed of the oxygen sample:

vrms ≈ 482.34 m/s

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Answer:

Explanation:

yes

The relative kinetic energy of molecules in the soda is least energy and above the soda in the glass is greatest energy.

The relative kinetic energy of gas molecules increases with increase in the mean distance between the gas molecules.

Also, relative kinetic energy of gas molecules increases with in the temperature of the gas molecules and decreases with a decrease in the temperature of the of the gas molecules;

ΔK.E ∝ T

The ice in the soda lowers the temperature of the gas molecules, thereby reducing their average speed which in turn reduces the average kinetic energy of the gas molecules in the soda.

Above the soda in the glass, the concentration of the gas molecules is less and their mean distance is greatest when compared to inside the soda. This results to an increase in the speed of the gas molecules which increases their average kinetic energy.

Thus,  the relative kinetic energy of molecules in the soda is least energy and above the soda in the glass is greatest energy.

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(a) The smallest vertical magnetic field B that would cause the rod to

slide is 0.145 Tesla for given  The coefficient of static friction

between the rod and rails is μs= 0.60

A magnetic field is a vector field that describes the magnetic influence on moving charges, currents, and magnetic materials. A moving charge in a magnetic field is subjected to a force that is perpendicular to both its own velocity and the magnetic field.

(a) using formula

 μs × m × g = I × L × B

μs= 0.60

M= 1.2 kg

I = current =  55.0 A

L = Length = 0.9 m

magnetic field (B) =  0.145 Tesla

(b) expression

force (f) = I × L × B × sinФ

(c)  given B = 0.145 Tesla

 μs × m × g= I × L × B × sinФ

Ф = 90°

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Explanation:

here, force applied (N) = 345 N

or, mass of scooter (m) = 70 kg

now, acceleration (a) = ?

we know, force = mass × acceleration

or, 345 = 70 × acceleration

or, acceleration = 345/70

therefore, acceleration = 4.9 m/s2 (meter/second square)

Answer:

The acceleration is

Explanation:

Acceleration = final velocity - initial velocity
                        ---------------------------------------
                                speed
Initial velocity = 10m/s
final velocity = 22m/s
speed = 2 secs
acceleration = 22 - 10
                       -----------
                           2
                    = 12/2
                     6 m/s^2

With a 9.0 voltage battery connected with two resistors, one is 10 ohms and the other resistor is at 20 ohms the voltage drop across the battery 1 volt. Thus, option A is correct.

Given data

voltage supplied Vs= 1.5 volts

resistance R1= 1000 ohms

resistance R2= 500 ohms

The total resistance is

Rt= 1000+ 500

Rt= 1500 ohms

In series connection the current is the same for all components while the voltage divides across all components,the voltages consumed by each individual resistance is equal to the source voltage.

Therefore, With a 9.0 voltage battery connected with two resistors, one is 10 ohms and the other resistor is at 20 ohms the voltage drop across the battery 1 volt. Thus, option A is correct.

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Answer:

Speed of the spacecraft right before the collision: \(\displaystyle \sqrt{\frac{2\, G\cdot M_\text{e}}{R\text{e}}}\).

Assumption: the earth is exactly spherical with a uniform density.

Explanation:

This question could be solved using the conservation of energy.

The mechanical energy of this spacecraft is the sum of:

Let \(m\) denote the mass of this spacecraft. At a distance of \(R\) from the center of the earth (with mass \(M_\text{e}\)), the gravitational potential energy (\(\mathrm{GPE}\)) of this spacecraft would be:

\(\displaystyle \text{GPE} = -\frac{G \cdot M_\text{e}\cdot m}{R}\).

Initially, \(R\) (the denominator of this fraction) is infinitely large. Therefore, the initial value of \(\mathrm{GPE}\) will be infinitely close to zero.

On the other hand, the question states that the initial kinetic energy (\(\rm KE\)) of this spacecraft is also zero. Therefore, the initial mechanical energy of this spacecraft would be zero.

Right before the collision, the spacecraft would be very close to the surface of the earth. The distance \(R\) between the spacecraft and the center of the earth would be approximately equal to \(R_\text{e}\), the radius of the earth.

The \(\mathrm{GPE}\) of the spacecraft at that moment would be:

\(\displaystyle \text{GPE} = -\frac{G \cdot M_\text{e}\cdot m}{R_\text{e}}\).

Subtract this value from zero to find the loss in the \(\rm GPE\) of this spacecraft:

\(\begin{aligned}\text{GPE change} &= \text{Initial GPE} - \text{Final GPE} \\ &= 0 - \left(-\frac{G \cdot M_\text{e}\cdot m}{R_\text{e}}\right) = \frac{G \cdot M_\text{e}\cdot m}{R_\text{e}} \end{aligned}\)

Assume that gravitational pull is the only force on the spacecraft. The size of the loss in the \(\rm GPE\) of this spacecraft would be equal to the size of the gain in its \(\rm KE\).

Therefore, right before collision, the \(\rm KE\) of this spacecraft would be:

\(\begin{aligned}& \text{Initial KE} + \text{KE change} \\ &= \text{Initial KE} + (-\text{GPE change}) \\ &= 0 + \frac{G \cdot M_\text{e}\cdot m}{R_\text{e}} \\ &= \frac{G \cdot M_\text{e}\cdot m}{R_\text{e}}\end{aligned}\).

On the other hand, let \(v\) denote the speed of this spacecraft. The following equation that relates \(v\!\) and \(m\) to \(\rm KE\):

\(\displaystyle \text{KE} = \frac{1}{2}\, m \cdot v^2\).

Rearrange this equation to find an equation for \(v\):

\(\displaystyle v = \sqrt{\frac{2\, \text{KE}}{m}}\).

It is already found that right before the collision, \(\displaystyle \text{KE} = \frac{G \cdot M_\text{e}\cdot m}{R_\text{e}}\). Make use of this equation to find \(v\) at that moment:

\(\begin{aligned}v &= \sqrt{\frac{2\, \text{KE}}{m}} \\ &= \sqrt{\frac{2\, G\cdot M_\text{e} \cdot m}{R_\text{e}\cdot m}} = \sqrt{\frac{2\, G\cdot M_\text{e}}{R_\text{e}}}\end{aligned}\).

Answer:

The correct answer is A    

Explanation:

In this exercise we are given a graph of temperature versus time.

In calorimeter processes there are two types

* one that when giving thermal energy to the system its temperature increases, this fundamentally due to the greater kinetic energy of the molecular ones, this process observes in the graphs as a straight line of constant slope

* A process donates all the thermal energy that is introduced is cracked in breaking the molecular bonds, taking matter from one thermodynamic state to another, for example: liquid to gas.

This process in curves as a horizontal line, that is, there is no temperature change,

When analyzing the graph shown, parts C and D are the one that show a change in temperature with thermal energy. The correct answer is A

Answer:

C and D

Explanation:

Just took the quiz