if the amount of energy calculated in part a is stored in an inductor in which the current is 80.0 a , what is the inductance?

the total charge passing a given point in the conductor \(12000\pi C\)

What is charge ?

In physics, rate, additionally called electric powered rate, electric rate, or electrostatic rate and symbolized q, is a feature of a unit of count number that expresses the quantity to which it has greater or fewer electrons than protons. In atoms, the electron incorporates a poor fundamental or unit rate; the proton incorporates a fine rate. The varieties of rate are identical and opposite.

Given

I = \(100sin (120 \pi t )\)

t = 0 to t = 1/240s

d Q = I dT = \(100sin (120 \pi t ) dt\)

Q = \(100*120\pi\)

Q = \(12000\pi C\)

the total charge passing a given point in the conductor \(12000\pi C\)

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The statement is True.

For 1D flow in a pipe, the shear stress varies linearly from 0 at the wall (where the fluid velocity is zero) to a maximum at the centerline (where the velocity is maximum).

This is because the fluid velocity profile is parabolic for laminar flow, and the shear stress is directly proportional to the velocity gradient. In the center of the pipe, the velocity gradient is zero, and hence the shear stress is at its maximum value.

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Answer:

84.83 ft/s^2 or 85 ft/s^2

Explanation:

A = Δ v Δ t

Acceleration is the rate of change of an objects speed; in other words, it's how fast velocity changes. According to Newton's second law, acceleration is directly proportional to the summation of all forces that act on an object and inversely proportional to its mass. It's all common sense - if several different forces are pushing an object, you need to work out what they add up to (they may be working in different directions), and then divide the resulting net force by your object's mass.

This acceleration definition says that acceleration and force are, in fact, the same thing. When the force changes, acceleration changes too, but the magnitude of its change depends on the mass of an object. This is not true in a situation when the mass also changes, e.g., in rocket thrust, where burnt propellants exit from the rocket's nozzle.

In the 17th century, Sir Isaac Newton, one of the most influential scientists of all time, published his famous book Principia. In it, he formulated the law of universal gravitation which states that any two objects with mass will attract each other with a force exponentially dependent on distance between these objects (specifically, it is inversely proportional to the distance squared). The heavier the objects are, the greater is gravitational force. It explains, for example, why planets orbit around the very dense Sun.

In Principia, Newton also includes three laws of motion which are central to understanding the physics of our world. The acceleration calculator is based on three various acceleration equations, where the third is derived from Newton's work:

a = (v_f - v_i) / Δt,

a = 2 * (Δd - v_i * Δt) / Δt²,

a = F / m,

where:

a is the acceleration,

v_i and v_f are respectively the initial and final velocities,

Δt is the acceleration time,

Δd is the distance traveled during acceleration,

F is the net force acting on an object that accelerates,

m is the mass of this object.

If you already know how to calculate acceleration let's focus on the units of acceleration. You can derive them from the equations we listed above. All you need to know is that speed is expressed in feet per second (imperial/US system) or in meters per second (SI system) and time in seconds. Therefore, if you divide speed by time (as we do in the first acceleration formula), you'll get acceleration unit ft/s² or m/s² depending on which system you use.

Alternatively, you can use the third equation. In this case, you need to divide force (poundals in US and newtons in SI) by mass (pounds in US and kilograms in SI) obtaining pdl/lb or N/kg. They both represent the same thing, as poundal is pdl = lb * ft/s² and the newton is N = kg * m/s². When you substitute it and reduce the units, you'll get (lb * ft/s²) / lb = ft/s² or (kg * m/s²) / kg = m/s².

There is also a third option that is, in fact, widely used. You can express acceleration by standard acceleration, due to gravity near the surface of the Earth which is defined as g = 31.17405 ft/s² = 9.80665 m/s². For example, if you say that an elevator is moving upwards with the acceleration of 0.2g, it means that it accelerates with about 6.2 ft/s² or 2 m/s² (i.e., 0.2*g).

If two identical rubber pads (having h x b rectangular cross sections) transmit a load P applied to a rigid plate to a fixed support.Then the average shear stress on the pads on the top/bottom surfaces of the pad resulting from the applied load P is 0.0278 MPa

To solve this problem, we can use the equations for shear stress and shear strain:

Shear stress = Load / Area

Shear strain = Shear stress / Shear modulus

a) To determine the average shear stress on the top/bottom surfaces of the pads resulting from the applied load P, we need to calculate the area of the pads in contact with the rigid plate:

Area = b x t = 60 mm x 150 mm = 9000 mm²

Then we can use the equation for shear stress:

Shear stress = P / Area

Substituting the given values, we get:

Shear stress = 500 N / 9000 mm² = 0.0556 MPa

Since the two pads are identical and carry the same load, the average shear stress on both top and bottom surfaces of each pad is the same, which is:

Average shear stress = 0.0556 / 2 = 0.0278 MPa

b) To determine the average shear strain in the rubber material, we need to use the equation for shear strain:

Shear strain = Shear stress / Shear modulus

Substituting the given values, we get:

Shear strain = 0.0278 MPa / 0.3 MPa = 0.0926

Therefore, the average shear strain in the rubber material is 0.0926 or 9.26%.

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Answer: 0.308

Explanation:

acellus

Answer:

The answer is "26.208 km"

Explanation:

Given value:

\(\to S= 2.6 \ \frac{m}{s}\\\\\to t= 2.8 \ hours\)

Formula:

\(d= st\\\\d= 2.6 \times 2.8 \times \frac{60 \times 60}{1000}\\\\d= 26.208\ km\)

Chlorine has two naturally occurring isotopes, \(^{35}Cl\) and \(^{37}Cl\).

What is the mass number,  number of  protons, neutrons, and electrons are present in \(^{35}Cl\)?

The mass number of \(^{35}Cl\) is 35.

The number of protons present in \(^{35}Cl\) is 17.

The number of neutrons present in \(^{35}Cl\) is 18.

The number of electrons present in \(^{35}Cl\) is 17.

What is the mass number,  number of  protons, neutrons, and electrons are present in \(^{37}Cl\)?

The mass number of \(^{37}Cl\) is 37.

The number of protons present in \(^{37}Cl\) is 17.

The number of neutrons present in \(^{37}Cl\) is 20.

The number of electrons present in \(^{37}Cl\) is 17.

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Answer:

A DAY IN THE LIFE OF METIS JOURNAL, I WROTE IT HOPE U LIKE IT ;))) XD

We, who live in the west, were Nomadic. So we always moved from place to place to hunt buffalo and other fur-bearing animals. And now again we have to shift everything we collected , like, all the essential needs we collected. It’s really hard to shift stuff, But when you move to a new place you get to see new beautiful places. They are just so satisfying to see! It’s like all my work(like the shifting work) is paid off. I love it! We always meet the Hudson’s bay company employees, and give them furs which we took from the bissons and other furry animals we hunted. And in exchange they give us their (Hudson’s Bay company) goods. Which is good! Because then we or I won't be able to enjoy that delicious pemmican!

 The one reason that makes me proud of my parents is that because of them I am like a translator for both sides in the fur trade! Anyways coming back to the present. As I said before, we were moving today to another place, But on the way some people along with my father will ride the famous York boats carrying supplies to fur posts. I begged my father to take me with him! And as usual he gave me some silly reason for me to stay. And now since I don’t have anything to do I will-..Nevermind, My mom’s calling me. Okay after helping my mom keep the fur posts into the York boats me , my mom, and the others are just relaxing and enjoying nature just to take a break. Since, I am so obsessed with my Journal notebook today I’m just going to sit here and right what comes to my mind. I’m not like the others who always seem to be talking with someone. I like my own space! 

I kind of miss my dad already, but he and his fellow members need to travel the waterways from the red river further west and north to hudson bay. These red river carts also travel the trek back and forth over land to St. Paul, Minnesota and to posts in saskatchewan.  Speaking about the red river, the only large settlement in the region is the red colony. About 12000 people lived in this colony around Fort Garry. Some were the original Selkirk settlers or their descendents. They had come from Scotland with lord Selkirk when he established the colony in 1811. Many of these original settlers were poor farmers who had been displaced  from their lands in scotland. They had endured many hardships in the early years of settlement, including foods, hunger, and sickness. I love studying about other colonies, cultures , history etc.

Explanation:

write this as your answer you will get extra marks

Answer:

Using V= IR

I= 0.2307 Ampere

Answer:

735 J

Explanation:

Total height reached(displaced)=10x15 cm

= 10 x 15/100 m

= 1.5 m

Workdone = F.S (force x displacement)

Here, the boy is traveling against the gravitation force(=mg) , and traveled a height of 1.5m

Hence,

Workdone = 50 x 9.8 x 1.5 J

= 735 J

Answer:

750J

Explanation:

Solution;

M=50kg, g=10m/s

Distance=15×10÷100

=1.5m

W=M×g×h

=50×10×1.5

=750J

The child will take  6.52 seconds to complete 15 dribbles.

Frequency means number of cycles completed in one second.

Here we are provided with the dribbling frequency as 2.30 hz, which means the child can dribble a basketball 2.30 times in one sec.

I.e.     f = 1/T =2.30 hz

So , the time period for one dribble  is

T = 1/f

T = 1/ 2.3

T = 0.434 sec

So we have the time period for one dribble as 0.434 sec

Now, similarly we can calculate the time period for 15 dribbles , by multiplying the time of one dribble with the number of times the ball is dribbled.

I.e. time for 15 dribbles = T x 15

  = 0.434 x 15

  = 6.52 seconds

And this is the time for 15 dribbles.

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The dog MUST be SEEN by a vet.

Not on the phone, not from your description. Not a web search, and not asking for advice online.

A qualified veterinarian has to have his hands on the animal, examine the dog, and make some suggestions. It might cost some money.

There's something missing here. A qualified real vet will never just say "I don't know, good bye!".

Answer:

9s

Explanation:

v=u+at

36=0+4t

t=36-0/4

t=9s

Answer:

Uniform Speed: A body is said to be moving with uniform speed, if it covers equal distances in equal intervals of time. Variable Speed: A body is said to be moving with variable speed if it covers unequal distances in equal intervals of time.

Explanation:

I got it from google

Answer:

Speed is a measure of how fast an object is moving at a given instant of time. It is a scalar quantity. Its unit is m/s. For a body covering equal distances in equal time intervals, the speed is called uniform speed.

Explanation:

Answer:

its the third one

Explanation:

There is 6.4 kg of water in the kettle.

We can use the formula for calculating the heat energy required to heat a substance:

Q = mcΔT

where Q is the heat energy in joules, m is the mass of the substance in kilograms, c is the specific heat capacity of the substance, and ΔT is the change in temperature in degrees Celsius.

In this case, we know that the kettle uses 160 kJ of energy to heat the water from 25°C to 100°C. We also know that the specific heat capacity of water is 4.18 J/g°C.

Converting kJ to J and plugging in the values:

160000 J = m × 4.18 J/g°C × (100°C - 25°C)

Simplifying:

160000 J = m × 4.18 J/g°C × 75°C

Dividing both sides by 4.18 J/g°C × 75°C:

m = 160000 J ÷ (4.18 J/g°C × 75°C)

m = 6400 g = 6.4 kg

Therefore, there is 6.4 kg of water in the kettle.

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The reason you have to keep running your engine when your car is moving at a constant velocity on the highway is to overcome frictional forces.

So, the correct answer is C.

When your car is moving along the highway at a constant velocity, the net force acting on it is zero. However, you still need to keep running your engine to overcome the frictional forces acting on your car.

Frictional forces such as air resistance, rolling resistance, and the resistance caused by the engine and transmission of your car all act against the motion of your car.

Therefore, your engine needs to continue to produce power to counteract these forces and maintain your car's speed.

Additionally, keeping your engine running is important to power essential features of your car, such as your radio and air conditioning, and to prepare for sudden acceleration needs, such as when merging onto a highway or passing another vehicle.

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The statement "All galvanic cells have the same cell potential because they are all referenced to the standard hydrogen electrode (SHE)" is false.

While it is true that the standard hydrogen electrode (SHE) is used as a reference to measure cell potentials of galvanic cells, it does not mean that all galvanic cells have the same cell potential. The cell potential, also known as electromotive force (EMF) or cell voltage, is determined by the difference in reduction potentials between the two half-cells in a galvanic cell.

The SHE is assigned a potential of 0 volts, and other half-cell potentials are measured relative to this reference. The cell potential of a galvanic cell is calculated by taking the difference between the reduction potential of the cathode (where reduction occurs) and the reduction potential of the anode (where oxidation occurs).

Different galvanic cells consist of different redox couples, resulting in varying reduction potentials. Consequently, these cells will have different cell potentials. It is important to note that the cell potential depends on the specific redox reactions taking place in the galvanic cell, as well as factors such as temperature and concentration of the involved species.

In summary, although the standard hydrogen electrode is used as a reference for measuring cell potentials, it does not lead to all galvanic cells having the same cell potential.

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Based on the graph, it appears that the species most likely to be affected if the water temperature increases from 74°F to 80°F would be the rainbow trout.

It is because the graph shows that rainbow trout have a much narrower range of temperature tolerance compared to the other species listed, such as bass and catfish. While bass and catfish can tolerate temperatures up to 90°F, rainbow trout can only tolerate temperatures up to around 68°F.

As the water temperature increases beyond 68°F, the health and survival of rainbow trout are likely to be negatively impacted, making them more vulnerable to the effects of increasing water temperature. Therefore, if the water temperature were to increase from 74°F to 80°F, it would be expected to have a significant impact on the population of rainbow trout in the ecosystem.

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The direction of the electric field at the position indicated by the dot in the figure can be specified as an angle above the horizontal line. The angle is determined by the direction of the electric field vector at that point, which can be determined using the right-hand rule.

The direction of the electric field is determined by the sign of the charge, which is responsible for creating the field. Positive charges create an electric field that extends outward from them, while negative charges create an electric field that extends inward towards them. Additionally, the direction of the electric field is the same as the direction of the force it would exert on a positive test charge.

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Answer:

Concentrating solar power (CSP) plants use mirrors to concentrate the sun's energy to drive traditional steam turbines or engines that create electricity.

Explanation:

The following set of quantum numbers (ordered n , ℓ , mℓ , ms ) are possible for an electron in an atom are 3, 2, -3, 1/2; 3, 2, 2, -1/2; 5, 3, 4, 1/2; 2, 2, 2, 1/2".

The set of quantum numbers (ordered n, ℓ, mℓ, ms) are possible for an electron in an atom are as follows:3, 2, -3, 1/23, 2, 2, -1/25, 3, 4, 1/22, 2, 2, 1/2

The quantum numbers are a set of numbers that can be used to identify an electron's location.

In atoms, the principal quantum number (n), the angular momentum quantum number (l), the magnetic quantum number (ml), and the electron spin quantum number (ms) are all used.

Principal Quantum Number(n) - It specifies the energy level of an electron in an atom.

Angular Momentum Quantum Number (l) - It specifies the shape of the orbital in which the electron is present.

Magnetic Quantum Number (ml) - It specifies the orientation of the orbital in which the electron is present.

Electron Spin Quantum Number (ms) - It specifies the spin of an electron in the orbital.

In the given options, 4 sets of quantum numbers are possible for an electron in an atom.

They are 3, 2, -3, 1/2; 3, 2, 2, -1/2; 5, 3, 4, 1/2; 2, 2, 2, 1/2, and hence the correct answer is "DETAIL ANS: 3, 2, -3, 1/2; 3, 2, 2, -1/2; 5, 3, 4, 1/2; 2, 2, 2, 1/2".

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okay, so what i have learned from my experiences with doing school on e.d.g.e.n.u.i.t.y (they won't let me say the website name on here lol) is that after you write an extended response, they show you a sample response as well as these checkboxes which show things they wanted you to have included in your answer. ideally they want you to select all of them, meaning that all of those elements were included in your answer. it's not a matter or right or wrong; none of those checkboxes contain a wrong answer. you just select the ones that apply to your answer, and you won't get penalized if you don't select all of the checkboxes. you don't even have to select any of them. there's been times where my answer has been not at all what it should've been and i just click done without checking any of those boxes because i did not include any of those elements in my response. as long as the box that you wrote your answer in is outlined in green (which yours is, and that means that the computer likes your answer), you will be fine.

i hope this makes sense! it's sort of hard to explain. if you have any questions, just comment and i'll try my best to explain better lol. have a great rest of your day! <3

You have a cart that has a mass of 400 kg and a KE of 500 J, you remove some of the things on the cart to make it lighter. If it is moving at the same speed as before, and the KE is now 125 J, what is the new mass?

kinetic energy : the energy which a body possesses by the virtue of motion

velocity : it is the rate at which a body covers displacement.

The mass of the cart given initially is : 400kg

The kinetic energy given initially is : 500J

now we know the kinetic energy formula : KE = \(\frac{1}{2}mv^{2}\)

in the first case lets apply this formula and get the velocity first.

500 = (1/2)x(400)x\(v^{2}\)

500x2 = 400x\(v^{2}\)

\(v^{2}\) = 1000/400

\(v^{2}\) = 10/4

therefore \(v^{2}\) = 10/4 \(m^{2}/s^{2}\)

now that we found the velocity of the body, lets use this to find the new mass.

now in the second case, we have
new kinetic energy : 125J

let the new mass be m.

lets substitute the given info in the formula , we get

125 = (1/2)x(m)x\(v^{2}\)

but we know \(v^{2}\) = 10/4

so we have,

125 = (1/2)x(m)x(10/4)

125x2 = (10m/4)

150x4 = 10m

60=m

therefore the new mass of the body is 60kg

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Answer:

9.81 J

Explanation:

The 10 kg block shown in the figure is in contact with the spring that has a natural length of 25 cm. When the block is released, it compresses the spring, remaining static 15 cm from the floor. Calculate the change in elastic potential energy of the spring in Joules

The given parameters are;

The mass of the block in contact with the spring = 10 kg

The natural length of the spring = 25 cm

The final height of the block after being released = 15 cm

Therefore;

The potential energy of the block = m·g·h

The initial potential energy of the block = 10 kg × 9.81 m/s² × 0.25 m = 24.252 J

The final potential energy of the block = 10 kg × 9.81 m/s² × 0.15 m = 14.715 J

By energy conservation principle

The change in potential energy of the block = The change in elastic potential energy of the spring = (1/2)·k·x² = 24.252 J - 14.715 J = 9.81 J

a. The centripetal acceleration of the car is 0.5 m/s².

b. The centripetal force on the car is 600 N.

c. The coefficient of static friction between tires and the road is 0.051.

d. The car's speed is doubled, we need a coefficient of static friction of 0.204 to prevent the car from sliding.

a. The formula for the centripetal acceleration of the car is given as below:

ac = v²/r

where ac is the centripetal acceleration,

v is the speed, and

r is the radius of curvature of the circular path.

Substituting the values given in the problem, we get:

ac = (20 m/s)²/800 m = 0.5 m/s²

b. The formula for the centripetal force of the car is given as below:

F = mac

where F is the centripetal force,

m is the mass of the car, and

ac is the centripetal acceleration.

Substituting the values given in the problem, we get:

F = (1200 kg)(0.5 m/s²) = 600 N

c. The formula for the maximum static frictional force is given as below:

\(f_{max}\) = μsN

where \(f_{max}\) is the maximum static frictional force,

μs is the coefficient of static friction, and

N is the normal force acting on the car.

For a car moving in a circular path, the normal force is equal to the weight of the car, which is given by:

N = mg

where m is the mass of the car and g is the acceleration due to gravity (9.8 m/s²).

Substituting the above equations and solving for μs, we get:

\(f_{max}\) = μsN

⇒ μs = \(f_{max}\) / N

Substituting the values given in the problem, we get:

\(f_{max}\) = mac = (1200 kg)(0.5 m/s²) = 600 N and

N = mg = (1200 kg)(9.8 m/s²) = 11760 N

Therefore,μs = 600 N/11760 N = 0.051

d. Doubling the speed of the car will cause the centripetal acceleration to double as well.

The formula for centripetal acceleration is given as:

ac = v²/r,

where ac is the centripetal acceleration,

v is the speed, and

r is the radius of curvature of the circular path.

Substituting the new speed (40 m/s) into this formula, we get:

ac = (40 m/s)²/800 m = 2 m/s²

Therefore, the new centripetal acceleration is 2 m/s².

Using the same formula as in part (c), we can find the new coefficient of static friction.

The maximum static frictional force is still equal to the centripetal force, which is given by:

F = mac = (1200 kg)(2 m/s²) = 2400 N

Therefore,

μs = \(f_{max}\)/N = 2400 N/11760 N = 0.204

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The special theory of relativity predicts that fast-moving objects will appear to be shorter along the direction of motion than when they are seen at rest. Option B is the correct answer.

According to Einstein's theory, an item contracts more in the direction of motion the quicker it moves. This effect is not perceptible in our ordinary experiences since it is only perceptible at speeds that are a considerable fraction of the speed of light. Option B is the correct answer.

A fundamental theory of physics known as the special theory of relativity describes how the rules of physics apply to things moving quickly. The most well-known prediction of the theory is that no matter how quickly the observer is travelling in relation to the light source, the speed of light stays constant in all reference frames. Numerous tests have verified this prediction, which is now regarded as one of the foundations of contemporary science.

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The complete question is, "The special theory of relativity predicts that fast-moving objects will appear to be ______than when they are seen at rest:

a. fatter

b. shorter along the direction of motion

c. stretched out along the direction of motion

d. older

e. less massive"