if secondary productivity is determined by the amount of tissue produced by grass and shrubs in a given year, this is an example of top down control detritus food chain mineralization bottom up control

Answers

Answer 1

If secondary productivity is determined by the amount of tissue produced by grass and shrubs in a given year, this is an example of bottom- up control.

The bottom-up control is driven by the presence or absence of the producers in the ecosystem. Changes in their population will affect the population of all the species in the food web, and thus, the ecosystem. This approach is also called the resource-controlled (or food-limited) food web of an ecosystem.

An example of bottom-up control would be nutrient driven changes to seagrass ecosystems. In the northern Gulf of Mexico increases in nutrient levels to seagrass meadows from land runoff can cause increased growth of the epiphytes that grow on seagrass blades.

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Related Questions

How much force is required to accelerate a 795 kilogram Lawrence sir speedy by 15 Meters per second squared

Answers

ANSWER:

11925 N

STEP-BY-STEP EXPLANATION:

To calculate the value of the force, we must use the following equation:

\(F=m\cdot a\)

In this case, we know that the mass and also the acceleration, we replace and we would have:

\(\begin{gathered} F=795\text{ kg}\cdot15\frac{m}{s^2} \\ F=11925\text{ }\frac{\operatorname{kg}\cdot m}{s^2}\text{ or N} \end{gathered}\)

Q17: The coefficient of linear expansion of steel is a = 11 x 10-6 / °C. A steel
ball has a volume of exactly 100 cm3 at 0°C. When heated to 100°C, its
volume becomes in (cm3):
A
B
D
E
100.33
100.11
100.0011
100.0033
None of them

Answers

Solution:

The coefficient of volume expansion

p = ΔV/V1Δt

3a = V2-V1/V1Δt

Given

a = = 11 x 10-6 / °C

V2 is the final volume

V1 is the initial volume = 100cm³

Δt = 100-0 = 100°C

Substitute

3(11 x 10-6) = V2-100/100(100)

33*10^-6 * 10000 = V2-100

33*10^-2 = V2-100

V2 = 100 + 0.33

V2 = 100.33

Hence the new volume is 100.33cm³

Tectonic processes are fueled by heat from __________, while atmospheric convection is fueled by heat from ___________.
A. the core, the sun
B. asteroid impacts, radiation
C. the sun, the core
D. radiation, asteroid impacts

Answers

Tectonic processes are fueled by heat from the core, while atmospheric convection is fueled by heat from the sun. That is option A.

What are tectonic processes?

The tectonic processes is defined as the process catalysed by heat from the earth core that results to the structuring and properties of the earth crust. This results to the following:

convergent, where plates move into one another;

divergent, where plates move apart; and

transform, where plates move sideways in relation to each other.

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The following graph of velocity versus time represents that of an automobile that travels in a straight line. From this graph, one can conclude that:

The following graph of velocity versus time represents that of an automobile that travels in a straight

Answers

The true statement is that the acceleration in the first two seconds is 6 m/s^2.

What is acceleration?

The term acceleration is defined as the rate of change of velocity with time. The graph as shown is a velocity time graph. The graph shows the changes that occur in the velocity over a given time interval.

Now  we have;

Initial velocity = 0 m/s

Final velocity = 12 m/s

Time taken = 2s

Acceleration = 12 - 0/2

= 6 m/s^2

Thus the true statement is that the acceleration in the first two seconds is 6 m/s^2.

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One stone has a mass of 16 kg and a kinetic energy of 26 J. A second stone has mass and nine times the kinetic energy. Compare their speeds.

Answers

The velocity in the first and the second case will be 1.8028 and 5.408 m/sec.

What is kinetic energy?

The energy of the body by the virtue of its motion is known as the kinetic energy of the body. It is defined as the product of half of mass and square of the velocity.

Given data:

Kinetic energy, KE=26 J

Mass,m=16 kg

The velocity is obtained as;

\(\rm KE= \frac{1}{2}mv^2 \\\\ v=\sqrt{\frac{2KE}{m} } \\\\ v=\sqrt{\frac{2 \times 26}{16} } \\\\v=1.8028 \ m/sec\)

The second stone has mass and nine times the kinetic energy:

\(\rm KE= \frac{1}{2}mv^2 \\\\ v'=\sqrt{\frac{9\times 2KE}{m} } \\\\ v=\sqrt{9 \times \frac{2 \times 26}{16} } \\\\v=5.408 \ m/sec\)

Hence the velocity in the first and the second case will be 1.8028 and 5.408 m/sec.

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How to explain third law when a boat is moving away from a paddock when a women’s feet is on the paddock and the boat

How to explain third law when a boat is moving away from a paddock when a womens feet is on the paddock

Answers

Answer:

According to Newton's third law of motion, for every action, there is an equal and opposite reaction. When the man jumps from a boat, he applies force on the boat due to which boat moves backward. An equal force is exerted by the boat on the man which helps the man to jump out of the boat.

Which of the following is an example of a free-trade agreement?

Answers

Answer:

Austrailia

Explanation:

5. [6.67/10 Points] DETAILS
MY NOTES
ASK YOUR TEACHER
N/C
(a) Determine the electric field strength at a point 1.00 cm to the left of the middle charge shown in the figure below. (Enter the
magnitude of the electric field only.)
6.00 μC
1.50 μC -2.00 μC
3.00 cm
Submit Answer
PREVIOUS ANSWERS
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Need Help? Read It
(b) If a charge of -6.13 µC is placed at this point, what are the magnitude and direction of the force on it?
magnitude
N
direction
SERCP11 15.3.P.018. 2/5 Submissions Used
2.00 cm →

Answers

As the charge is negative, the force, which has a magnitude of 33.05 N, is directed to the left, against the electric field.

What is the electric field's intensity at a specific distance from the point charge E?

E is a symbol for the magnitude of the electric field at a specific distance from a point charge. At twice the distance from the point charge, what is the electric field's strength? The field's strength is E/2 at twice the distance. The field's strength is still equal to E at a distance that is twice as great.

E = k*q/r²

r1 = 2.00 cm

r2 = 1.00 cm + 3.00 cm = 4.00 cm

r3 = 1.00 cm

Using these distances, we can calculate the electric field due to each charge:

E1 = kq1/r1² = (9.0 x 10⁹ Nm²/C²) * (1.50 x 10⁻⁶ C) / (0.02 m)² = 168.75 N/C (to the right)

E2 = kq2/r2² = (9.0 x 10⁹ Nm²/C²) * (-2.00 x 10^⁻⁶ C) / (0.04 m)² = -112.50 N/C (to the left)

E3 = kq3/r3² = (9.0 x 10⁹ Nm²/C²) * (6.00 x 10⁻⁶ C) / (0.01 m)² = 5.40 x 10⁶ N/C (to the right)

E = E1 + E2 + E3 = 168.75 N/C - 112.50 N/C + 5.40 x 10⁶ N/C = 5.39 x 10⁶ N/C (to the right)

F = q*E

F = (-6.13 x 10 C) * (5.39 x 10⁶ N/C) = -33.05 N

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Please help me in questions 4_5_6

Please help me in questions 4_5_6

Answers

Yes, the force of the engine does work on the car as it accelerates the car forward. Work is defined as the transfer of energy that occurs when a force is applied over a distance, and in this case, the force of the engine is causing the car to move, so it is doing work.

How to explain the force

As the car gains speed, its kinetic energy increases, which means it has more energy of motion. Kinetic energy is defined as one-half of the mass of an object times its velocity squared, so as the car's speed increases, so does its kinetic energy.

The gravitational potential energy of the car will remain constant as long as it stays on a horizontal road, assuming there is no change in elevation. Gravitational potential energy is the energy an object possesses due to its position in a gravitational field, and since the car's position relative to the ground is not changing, its gravitational potential energy will remain constant.

The tractive force of the engine may change depending on the speed of the car and the resistance to motion that the car is encountering. As the car speeds up, the air resistance acting on the car will increase, which will require more force from the engine to maintain the same acceleration. Additionally, if the road surface is rough or there are inclines, the tractive force required to maintain the same speed or acceleration will also increase.

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what is the value of pi(8.104)^2 written with correct significant numbers

Answers

Answer:206.3

Explanation:

An aluminum wing on a passenger jet is 30 m long when its temperature is 27 C. At what temperature would the wing be 0.03 shorter?

Answers

Answer:2000

Explanation:

Image shows question, please help

Image shows question, please help

Answers

Jonathan needs to maintain a separation of 0.543 mm between the plates to get the desired charge, and a dielectric constant of 92.6 to achieve a separation of 5 mm with a dielectric.

(a) Using the equation Q = CV, where Q is the charge, C is the capacitance, and V is the voltage, we can solve for the capacitance: C = Q/V =\((8.15 x 10^-9 C) / (50 V) = 1.63 x 10^-10 F.\)

Then, using the formula for capacitance of parallel plate capacitors: C = ε0A/d, where ε0 is the permittivity of free space, A is the area of the plates, and d is the separation distance, we can solve for the separation distance: d =\(_{3}OA/C = (8.85 x 10^-12 F/m) x (0.01 m^2) / (1.63 x 10^-10 F) = 0.543 mm.\)

(b) To find the dielectric constant, we can use the formula for capacitance of a parallel plate capacitor with a dielectric: C = εrε0A/d, where εr is the relative permittivity or dielectric constant of the material. Solving for εr, we get: εr = Cd / ε0A = \((1.63 x 10^-10 F)\) x (0.005 m) / \((8.85 x 10^-12 F/m)\) x \((0.01 m^2)\) = 92.6.

Therefore, Jonathan should use a dielectric with a relative permittivity of 92.6 to achieve a separation of 5 mm.

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The rate at which goods and services can be produced is called
a)capital investment.
b)productivity.
c)producer price output.
d)human capital.

Answers

Answer:

productivity

Explanation:

it's the efficiency of production of goods or services

Answer:

Explanation:

The rate at which goods and services can be produced is called

b) productivity.

What can we say about
machines and engines?
A. Friction increases fuel
#efficiency.
B. Friction is unlikely.
C. There is no friction.
D. The process of overcoming
friction uses valuable fuels.

Answers

Machine efficiency is decreases by friction. It produces heat and energy loss.

Does friction make the machine more effective?

Because friction opposes the motion of two surfaces when they slide past one another and because friction must always be overcome in real machinery, it reduces efficiency.

What results from reducing machine friction?

Reduced heat between machine parts and increased efficiency are the results of minimizing friction in a machine. Heat is generated between parts that interact with one another as machines operate. If unchecked, such heat can accumulate to a point where it harms machine parts.

Are engines and machinery subject to friction?

There are many moving parts in an internal combustion engine today. These components can rub against one another, causing a great deal of friction that not only reduces the engine's performance but also increases the risk of damage. When molecules come into close contact with one another, friction is produced and drag is induced by the characteristics of the molecules.

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So can some take some time to answer number 3 for me?

So can some take some time to answer number 3 for me?

Answers

Answer:

Positive and negative

Explanation:

In order to attract to form the ionic compound, those charges are needed

E.g

Na+ (sodium)

Cl- (chloride)

Which ultimately forms NaCl (sodium chloride) which is a ionic compound

to jump, you exert 1400N of force on the ground. (it exerts 1400N back on you) you applied this force over a distance of 0.3 m as your extend your legs. how much work have you done? how high will you ride into the air if your mass is 70 kg?​

Answers

Answer:

Explanation:

Work done is expressed as;

Work done = Force × distance

Given

Force = 1400N

Distance = 0.3m

Workdone = 1400×0.3

Work done = 420joules

Given mass = 70kg

Weight = 700N

To know how high you will ride into the air

420 = 700×d

d = 420/700

d = 0.6m

You ride 0.6m into the air

A child sits on a merry-go-round, 1.5 meters from the center. The merry-go-round is turning at a constant rate, and the child is observed to have a radial acceleration of 2.3 m/s2. How long does it take for the merry-go-round to make one revolution

Answers

Answer:

5 .07 s .

Explanation:

The child will move on a circle of radius r

r = 1.5 m

Let the velocity of rotation = v

radial acceleration = v² / r

v² / r = 2.3

v² = 2.3 r = 2.3 x 1.5

= 3.45

v = 1.857 m /s

Time of revolution = 2π r / v

= 2 x 3.14 x 1.5 / 1.857

= 5 .07 s .

The merry-go round will take 5.07 s to complete one complete revolution.

Given data:

The distance of child from the center is, r = 1.5 m.

The magnitude of radial acceleration is, \(a = 2.3 \;\rm m/s^{2}\).

Since, the child is on merry-go round, which is undergoing a rotational motion. And radial acceleration means that it is under the acceleration, whose value is given as,

\(a=\dfrac{v^{2}}{r}\\\\v=\sqrt{a \times r}\)

Here, v is the linear velocity.

Solving as,

\(v=\sqrt{2.3 \times 1.5} \\\\v=1.857 \;\rm m/s\)

Now, we to obtain the time taken by merry-go round to complete one revolution. Then the expression for the time taken to complete one revolution is,

\(T=\dfrac{2 \pi r}{v}\\\\T=\dfrac{2 \pi \times 1.5}{1.857}\\\\T = 5.07 \;\rm s\)

Thus, we can conclude that the merry-go round will take 5.07 s to complete one revolution.

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What is generally TRUE about diagnosing psychological disorders?

A.
High levels of neurotransmitters have been linked to depression.

B.
Diagnoses are not based on opinion or personal assessment.

C.
Doctors agree about what behaviors make up each disorder.

D.
Psychological disorders can be very difficult to diagnose.

Answers

The statement that says "Psychological disorders can be very difficult to diagnose" is true about diagnosing psychological disorders.

What are psychological disorders?

Psychological disorders are those mental, behavioral, emotional and thinking conditions that interfere with the normal performance of the individual in society.

Mental disorders are psychiatric conditions that are expressed in a syndrome, verifiable from different diagnostic criteria.

The steps to obtain a diagnosis include a medical history, physical examination, and possibly laboratory tests and a psychological evaluation.

Therefore, we can conclude that a psychological disorder is an alteration in the mental balance of a person that requires specialized attention adapted to the characteristics of the dysfunction.

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In which of the following situations would it NOT be wise to estimate?
a.
the number of miles per gallon an automobile can provide
b.
the time it would take to walk to the grocery store from home
c.
the amount of food to prepare for twelve people
d.
the amount of medicine to give a patient

Answers

Medicine to a patient. That should be calculated based on weight, strength/dosage and possibly other factors

A horizontal 645 N merry-go-round of radius
1.7 m is started from rest by a constant hori-
zontal force of 61.8 N applied tangentially to
the merry-go-round.
Find the kinetic energy of the merry-go-
round after 3.59 s. The acceleration of gravity
is 9.8 m/s². Assume the merry-go-round is a
solid cylinder.
2
Answer in units of J.

Answers

The kinetic energy of the merry-go-round after about 3.59 seconds will be 847.72 J.

What is Kinetic energy?

Kinetic energy is the energy an object because of its motion. If we want to accelerate an object, then we must apply force of some magnitude. Applying a force which requires us to do work. After work has been done on that object, energy has been transferred to the object, and the object will be moving with a new constant speed. Kinetic energy is a vector quantity due to the presence of both magnitude and direction.

Fg = 645 N, F = 61.8 N, r = 1.7m and t = 3.59 sec

Now, Mass of disc, m= Fg/g =645/ 9.8 = 65.81kg

Moment of Inertia is given by,

I = 1/2 mr²

I = 1/2 (65.81) (1.7)²

I = 1/2 (65.81) (2.89)

I = 1/2 (190.19)

I = 95.09 kg m²

Now, T= Fh r = 65.81 × 1.7 = 111.87Nm

Therefore, α = τ/ I = 111.87/ 95.09 = 1.1764 rad/ sec²

Angular velocity, ω = αt = 1.1764 × 3.59

ω = 4.223 rad/sec

Therefore, Kinetic Energy = 1/2Iω²

KE = 1/2 (95.09)(4.223)²

KE = 1/2 (95.09) (17.83)

KE = 1/2(1695.45)

KE = 847.72 J

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Describe what the motion of the rigid system will be if:
a. The first condition for equilibrium is not satisfied.
b. The second condition for equilibrium is not satisfied.
c. Neither condition for equilibrium is satisfied.

Answers

The motion of the rigid system will be (a) linear (b) rotational (c) both linear and rotational

The first condition for equilibrium states that the body must have a net force of zero. This means that when the net force acting on a body is not zero the body will continue to move in a straight path and the motion of the rigid body will be linear.

The second condition for equilibrium states that the body must have zero net torque acting on the body for achieving equilibrium. torque is the rotational equivalent of force. Therefore, when the net torque is not zero, the rigid body keeps rotating which leads to a rotational motion.

When both the conditions of equilibrium are not satisfied the rigid body does not achieve the static equilibrium.

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An object has a constant velocity of 20 m/s to the north, and there are two
forces acting on it. What is this situation called?
O A. Force equilibrium
B. Inertia equilibrium
C. Dynamic equilibrium
D. Static equilibrium

Answers

Answer:

It's Dynamic Equilibirum

Explanation

Compare the table of information with the bar graph shown. What makes verifying that the bar graph has the same information as the table especially challenging? own answer
Answer:The table uses metric tons as its numerical scale unit, whereas the bar graph uses pounds. This use of differing units means the reader must convert units of measurement before verifying that the information in the table matches the information in the bar graph.

Answers

When displaying sections of data, bar charts is used. As long as the number of categories to compare, vertical bar charts can be useful for comparing several category discrete data, like ages, classes, schools.

Why are graphs more illuminating than tables?

Charts and graphs are useful visual aids because they make information accessible and quick to understand. So, it is not unexpected that both print and digital media frequently use graphs. When data is displayed as a graph rather than a table, it can often be easier to understand because the graph might show a pattern or comparison.

What do the tables, graphs, and data represent?

Visual representations of data, such as tables and graphs, are used to arrange information and reveal patterns and correlations. To present the results of their research, scientists and researchers frequently employ tables and graphs.

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a car travel 3 km due north than 5 km East resalt despelcement​

Answers

Answer:

resultant displacement is 5.8km

a car travel 3 km due north than 5 km East resalt despelcement

describe the energy changes in a mass spring system that is oscillating horizontally explain how this changes of the system is vibrating vertically​

Answers

Answer:

Below

Explanation:

In a mass-spring system that is oscillating horizontally, the energy changes between potential energy and kinetic energy. When the mass is at its maximum displacement from the equilibrium position, it has maximum potential energy and zero kinetic energy. As the mass starts to move towards the equilibrium position, its potential energy decreases while its kinetic energy increases. At the equilibrium position, the mass has zero potential energy and maximum kinetic energy. As the mass moves away from the equilibrium position, its kinetic energy decreases while its potential energy increases. This cycle repeats as long as the system is oscillating.

Now, if the support of the system is vibrating vertically, the energy changes that occur during horizontal oscillations cause the mass to move vertically as well. As the mass moves to its maximum displacement from the equilibrium position horizontally, it also moves upwards, gaining potential energy due to its increased height from the ground. As the mass moves towards the equilibrium position horizontally, it also moves downwards, losing potential energy and gaining kinetic energy due to its increased speed towards the ground. At the equilibrium position, the mass has zero potential energy but maximum kinetic energy, which is all in the vertical direction. As the mass moves away from the equilibrium position horizontally, it also moves upwards, gaining potential energy again. The cycle repeats, causing the mass to oscillate vertically as well.

Therefore, the energy changes that occur during horizontal oscillations in a mass-spring system can cause the system to vibrate vertically if the support is vibrating vertically.

Explain the advantages and disadvantages of having a racecar with a small mass in reference to Newton’s 1st law of motion. Use the term inertia in your answer.

Answers

Answer:

Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. This tendency to resist changes in a state of motion is inertia.

Explanation:

help on this asap please

help on this asap please

Answers

Answer:

I think A is correct.

Explanation:

If it's not I'm sorry probably my fault but I hope this helps:)

Calculate the net force on the particle q1.

Calculate the net force on the particle q1.

Answers

Answer:

-12.1

Explanation:

i’m almost sure this is it, i’m checking my old answers

if not let me know and i’ll give you some more answers

At what speed does a 2000 kg compact car have the same kinetic energy as a 18000 kg truck going 21 km/hr?

Answers

Answer:

v = 17.5 m/s = 63 km/h

Explanation:

The general expression for the kinetic energy of one moving object is as follows:

       \(K = \frac{1}{2}*m *v^{2} (1)\)

       where m = mass of the object, v= speed of the object.

In order to get the value of the kinetic energy of the truck in Joules, we need to convert km/hr to m/s first, as follows:

       \(21 km/hr * \frac{1 hr}{3600s}*\frac{1000m}{1 km} = 5.83 m/seg (2)\)

Now, replacing (2) and m = 18000 kg in (1), we get:

       \(K = \frac{1}{2}*18000 kg *(5.83m/s)^{2} = 306250 J (3)\)

This value must be the same for the 2000 kg compact car, so we can write:

       \(K = 306250 J = \frac{1}{2}*2000 kg *v^{2} (4)\)

Solving for v, we get:

       \(v = \sqrt{\frac{306250}{1000} (m/s)2} = 17. 5 m/s = 63 km/h (5)\)

Part A
Shown is a 10 by 10 grid, with coordinate axes x and y
(Figure 1).
The grid runs from -5 to 5 on both axes. Drawn on this
grid are four vectors, labeled A through D. This problem
will ask you various questions about these vectors. All
answers should be in decimal notation, unless otherwise
specified.
What is the x component of A?
Express your answer to the nearest integer.

Part AShown is a 10 by 10 grid, with coordinate axes x and y(Figure 1).The grid runs from -5 to 5 on

Answers

Based on the grid shown, the x component of the vector A is 3.

What is the x component of the vector A?

The given grid is a 10 by 10 grid, this means that every box in the grid has a length of 1 unit on all sides.

Thus, the x and y components of the vectors can be determined.

The x and y components of vector A is 3 and 3 respectively.

Therefore, based on the grid shown, the x component of the vector A is 3.

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