If Phosphorus, P, gained 3 electrons, the net ion charge would be

+5
-5
+3
-3

Answer:

A

Explanation:

I just know it because i am smart, trust me I know this is correct.

a i think if i am wrong i am truly sorry but i dont think i am wrong

Answer:

hshssytdtctdyeheb

Explanation:

yye6d66d6d6dududyydydydyehwj2

Seria 5.498 millas

Solo se debe dividir el valor de longitud entre 5280

Inter-conversion of glucose and fructose occurs with an equilibrium constant of 1.0. Glucose isomerase catalyzes this reaction. The final concentration of fructose at equilibrium from 40mM glucose is a. 40 mM.

Using this formula to find the  final concentration of fructose

Final concentration of fructose  =Equilibrium from glucose/ Equilibrium constant

Where:

Equilibrium constant = 1.0

Equilibrium from glucose = 40 mM

Let plug in the formula

Final concentration of fructose  = 40mM / 1.0

Final concentration of fructose  =  40mM

Therefore we can conclude that the correct option is A.

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The complete question is:

Inter-conversion of glucose and fructose occurs with an equilibrium constant of 1.0. Glucose isomerase catalyzes this reaction. The final concentration of fructose at equilibrium from 40mM glucose is

a. 40 mM

b. 20 mM

c. 10 mM

d. 0 mM​

Structure A represents the arrangement of atoms in pure copper because  copper is a solid and only made of one type of atom.

The chemical element copper has the atomic number 29 and the symbol Cu. Copper, a transition metal, is a solid at ambient temperature.

Pure copper has a low hardness, is exceedingly ductile, and is malleable. For electrical applications, a number of reasonably pure Cu grades are produced, with small variances in deoxidation.

Solid copper is defined as a face-centered-cubic (fcc) arrangement of copper atoms.

Thus, structure A correctly represents the arrangement of atoms in pure copper.

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Answer:

a. 167 mL b. 39.27 %

Explanation:

a. From the chemical equation. 2 mole of Al reacts with 3 mole H₂SO₄ to produce 1 mol  Al₂(SO₄)₃.

Now, we calculate the number of moles of Al in 45.0 g Al.

We know number of moles, n = m/M where m = mass of Al = 45.0 g and M = molar mass of Al = 26.98 g/mol.

So n = 45.0 g/26.98 g/mol = 1.668 mol

Since 2 mole of Al reacts with 3 mole H₂SO₄, then 1.668 mole of Al reacts with x mole H₂SO₄. So, x = 3 × 1.668/2 mol = 2.5 mol

So, we have 2.5 mol H₂SO₄.

Now number of moles of H₂SO₄, n = CV where C = concentration of H₂SO₄ = 15.0 M = 15.0 mol/L and V = volume of H₂SO₄.

V = n/C

= 2.5 mol/15.0 mol/L

= 0.167 L

= 167 mL of 15.0 M H₂SO₄ reacts with 45.0 g Al to produce aluminum sulfate.

b. From the chemical reaction, 2 mol Al produces 1 mol Al₂(SO₄)₃

Therefore 1.668 mol Al will produce x mol  Al₂(SO₄)₃. So, x = 1 mol × 1.668 mol/2 mol = 0.834 mol

So, we need to find the mass of 0.834 mol  Al₂(SO₄)₃. Now molar mass  Al₂(SO₄)₃ = 2 × 26.98 g/mol + 3 × 32 g/mol + 4 × 3 × 16 g/mol = 53.96 g/mol + 96 g/mol + 192 g/mol = 341.96 g/mol.

Also number of moles of  Al₂(SO₄)₃, n = mass of  Al₂(SO₄)₃,m/molar mass  Al₂(SO₄)₃, M

n =m/M

So, m = nM = 0.834 mol × 341.96 g/mol = 285.2 g

% yield = Actual yield/theoretical yield × 100 %

Actual yield = 112 g, /theoretical yield = 285.2 g

So, % yield = 112 g/285.2 g × 100 %

= 0.3927 × 100 %

=  39.27 %

The volume (mL) of 15.0 M sulfuric acid needed to react with 45.0 g of aluminum is 166mL and % yield of the reaction is 39.46%.

Moles of any substance will be calculated by using the below formula as:
n = W/M, where

W = given mass

M = molar mass

Given chemical reaction is :

2Al(s) + 3H₂SO₄(aq) → Al₂(SO₄)₃(aq) + 3H₂(g)

Moles of 45g of Al will be calculated as:

n = 45g / 27g/mol = 1.66 mole

From the stoichiometry of the reaction, it is clear that:

1.66 moles of Al = react with 3/2×1.66=2.49 moles of H₂SO₄

By using the formula of molarity we can calculate the volume of H₂SO₄ as:

M = n/V

V = (2.49) / (15) = 0.166L = 166mL

Again from the stoichiometry it is clear that:
1.66 moles of Al = produces 1/2×1.66= 0.83 moles of Al₂(SO₄)₃

Mass of 0.83 moles of Al₂(SO₄)₃ = (0.83mol)(341.96g/mol) = 283.82 g

Given actual yield of Al₂(SO₄)₃ = 112g

% yield will be calculated as:

Percent yield = (Actual yield/Theoretical yield) × 100

% yield = (112/283.82) × 100 = 39.46%

Hence required values are discussed above.

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Answer:

D-negative ion

Explanation:

Hope this helps!

Answer: crystal lattice

At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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An exothermic reaction releases 325 kJ. 1359.8 kJ energy is this in calories.

An exothermic reaction is a chemical reaction that releases heat energy into the surroundings. During an exothermic reaction, the products of the reaction have less potential energy than the reactants, and the excess energy is released in the form of heat.

One calorie is defined as the amount of energy required to raise the temperature of one gram of water by one degree Celsius.

One joule is defined as the amount of energy required to apply a force of one newton over a distance of one meter.

1 cal = 4.184 J

1 cal = 0.004184 kJ

325000 cal = x kJ

0.004184/ 1 = x / 325000

x = 1359.8 kJ

Thus, 1359.8 kJ energy is this in calories.

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Answer:

589 torr or mmHg.

Explanation:

We know that 1 atmospheric pressure is equal to 760 torr or 760 mmHg so calculate 0.775 atm pressure in term of mmHg and torr. We perform the following steps which is

1 atm -------- 760 torr or mmHg

0.775 atm ------- X

By cross multiplication we get

X = 760 x 0.775

X = 589 torr or mmHg

So we can conclude that if 0.775 atm is equals to 589 torr.

The reaction order and specific reaction rate constant can be determined by performing the kinetics experiment on irreversible polymerization A. Kinetic experiments can be used to investigate the rate and mechanism of chemical reactions. Chemical kinetics is the study of chemical reactions' speed and pathway.

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The image having the complete question is attached to this answer.

Answer:

Ga

Explanation:

In order to answer this question well, we must have a good enough knowledge of the periodic table.

We know that the elements in group 3A or group 13 of the periodic table have three valence electrons in their outermost shell.

We just have to look out among the options to notice if there is any member of group 3A or 13.

Gallium is a member of this group. Hence the answer above.

The balanced redox reaction of metallic zinc with ammonium ion in acidic medium can be written as follows:

\(\rm 4 Zn^{2+} + 2NH_{4}^{+} + 6 H_{2}O \rightarrow \rm 4 Zn + 2NO_{3}^{-} + 20 H^{+}\).

Thus the coefficients of Zn and H+ are 4 and 20.

A redox reaction is the reaction in which a species reduces to its lower oxidation state by reacting with hydrogen or by accepting one or more electrons.

In the given reaction, the Zn²⁺ ions reduces to Zn metal by accepting two electrons. In the acidic medium this reaction proceeds with water and H+ ions.

The coefficients of the reactants and products in the given redox reaction is given in the balanced equation given written below:

\(\rm 4 Zn^{2+} + 2NH_{4}^{+} + 6 H_{2}O \rightarrow \rm 4 Zn + 2NO_{3}^{-} + 20 H^{+}\).

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Answer:

its is wrong to do that

Explanation:

the smell of the meat will mix with that of the fruits

Answer:

weather- rain, hail, snow, sunny, dry, etc.

climate- warm, cold, humid, dry, etc.

Explanation:

The difference if weather and climate is that climate is the way the temperature is,  whether it's warm, cold, humid, dry. While weather is the state of the atmosphere at a place and time as regards heat, dryness, sunshine, wind, rain, etc.

The buffering capacity increases when  the concentrations of both acetic acid and acetate are doubled.

A buffer is a solution that mitigates against changes in acidity and alkalinity. A buffer is usually made up a weak acid and its conjugate base or a weak base and its conjugate acid.

The buffering capacity of a buffer increases as the concentration of the concentration of the acid/base as well as its conjugate base/acid increases. Therefore, the buffering capacity increases when  the concentrations of both acetic acid and acetate are doubled.

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The question is incomplete. Here is the complete question.

When 2.10 g of a certain molecular compound X are dissolved in 65.0 g of benzene (C₆H₆), the freezing point of the solution is measured to be 3.5°C. Calculate the molar mass of X. If you need any additional information on benzene, use only what you find in the ALEKS Data resource. Also, be sure your answer has a unit symbol, and is rounded to 2 significant digits.

Answer: MM = 47.30 g/mol.

Explanation: There is a relationship between freezing point depression and molality. With this last one, is possible to calculate molar mass or molar weight of a compound.

Freezing Point Depression occurs when a solute is added to a solvent: the freezing point of the solvent decreases when a non-volatile solute is incremented.

Molality or molal concentration is a quantity of solute dissolved in a certain mass, in kg, of solvent. Its symbol is m and it's defined as

\(m=\frac{moles(solute)}{kg(solvent)}\)

Freezing point depression and molal are related as the following:

\(\Delta T_{f}=K_{f}.m\)

where

\(\Delta T_{f}\) is freezing point depression of solution

\(K_{f}\) is molal freezing point depression constant

m is molality

Now, to determine molar mass, first, find molality of the mixture:

\(\Delta T_{f}=K_{f}.m\)

\(m=\frac{\Delta T_{f}}{K_{f}}\)

For benzene, constant is 5.12°C/molal. Then

\(m=\frac{3.5}{5.12}\)

m = 0.683 molal

Second, knowing the relationship between molal and moles of solute, determine the last one:

\(m=\frac{moles(solute)}{kg(solvent)}\)

\(mol(solute)=m.kg(solvent)\)

mol(solute) = 0.683(0.065)

mol(solute) = 0.044 mol

The definition for Molar mass is the mass in grams of 1 mol of substance:

\(n(moles)=\frac{m(g)}{MM(g/mol)}\)

\(MM=\frac{m}{n}\)

In the mixture, there are 0.044 moles of X, so its molecular mass is

\(MM=\frac{2.1}{0.044}\)

MM = 47.30 g/mol

The molecular compound X has molecular mass of 47.30 g/mol.

Explanation: The rate law for a chemical reaction is an equation that relates the rate of the reaction to the concentrations of the reactants. To determine the rate law for a reaction, experiments are typically conducted with different initial concentrations of the reactants and the initial rate of the reaction is measured.

From the data provided, it appears that the reaction is of the form X + Y → C. And the concentration of X and Y are varied in three trials and the corresponding Initial rate is measured.

In the first trial, [X] = 0.01 M and [Y] = 0.015 M, and the initial rate of the reaction is 7.83x10-5 M/s.

In the second trial, [X] = 0.01 M and [Y] = 0.03 M, and the initial rate of the reaction is 3.13x104 M/s.

In the third trial, [X] = 0.02 M and [Y] = 0.015 M, and the initial rate of the reaction is 1.57x10 M/s.

Given the data, the rate law for this reaction is OR = KX²M. This is because when the concentration of X is doubled, the rate of the reaction is quadrupled, which is consistent with a rate law of the form OR = k[X]^2.

Answer: yes

Explanation:

Answer:

before

Explanation:

Answer:

Does evaporation happen before of after condensation?

Explanation:

Condensation, the opposite of evaporation, occurs when saturated air is cooled below the dew point (the temperature to which air must be cooled at a constant pressure for it to become fully saturated with water), such as on the outside of a glass of ice water.

Or

Heat (energy) is necessary for evaporation to occur. Condensation, the opposite of evaporation, occurs when saturated air is cooled below the dew point (the temperature to which air must be cooled at a constant pressure for it to become fully saturated with water), such as on the outside of a glass of ice water.

you need to add 1.79 mL of 3.0 M HCl to react with 0.45 g of NaHCO3 and produce the most NaCl.

To determine how much 3.0 M HCl is needed to react with 0.45 g of sodium hydrogen carbonate (NaHCO3) and get the most NaCl, you need to first calculate the number of moles of NaHCO3 that you have:

molar mass of NaHCO3 = 84.01 g/mol

moles of NaHCO3 = mass / molar mass = 0.45 g / 84.01 g/mol = 0.00536 mol

Next, you need to determine the stoichiometry of the reaction between NaHCO3 and HCl. The balanced chemical equation for this reaction is:

NaHCO3 + HCl → NaCl + H2O + CO2

From this equation, you can see that one mole of NaHCO3 reacts with one mole of HCl to produce one mole of NaCl. Therefore, you need 0.00536 moles of HCl to react with 0.00536 moles of NaHCO3.

To calculate the volume of 3.0 M HCl needed to provide 0.00536 moles of HCl, you can use the following equation:

moles of solute = concentration x volume of solution (in liters)

Rearranging this equation to solve for the volume of solution gives:

the volume of solution = moles of solute/concentration

Plugging in the values gives:

volume of solution = 0.00536 mol / 3.0 mol/L = 0.00179 L or 1.79 mL

Therefore, you need to add 1.79 mL of 3.0 M HCl to react with 0.45 g of NaHCO3 and produce the most NaCl.

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Answer:

A

Explanation:

The person would gain weight because the undigested food would sit in the person's body. The person would not lose or gain weight, but it would take longer for the body to use the food that was eaten.