if one of the charge's magnitude is increased by a factor of 4 and the distance between the charges is increased by a factor of 7 what will be the new magnitude of the force exerted

Answer: I think it's 8,900

Explanation:because since you need to estimate it to the nearest thousand so 6,521 would be 7,000 and then 1,063 would be 1,000 and then 901would turn into 900 so then you add them all up and ur answer will be 8,900.

But I'm sorry if this was not the answer u were looking for

Answer:

It is easier to stop the bicycle moving at a lower velocity because it will require a smaller force to stop it when compared to a bicycle with a higher velocity that needs a bigger force.

Explanation:

The question above is related to "Newton's Law of Motion." According to the Third Law of Motion, whenever an object exerts a force on another object (action force), an equal force is exerted against it. This force is of the same magnitude but opposite direction.

When it comes to moving bicycles, the force that stops their movement is called "friction." Applying the law of motion, the higher the speed, the higher the force that is needed to stop it while the lower the speed, the lower the force that is needed to stop it.

Answer:

C. The forces are balanced.

Explanation:

Every answer other than C means the object moved.

Given 16 kg of a radioactive sample with a certain half-life of 15 years:

To determine how much of the 16 kg radioactive sample is left after 60 years with a half-life of 15 years, we will use the following steps:

1. Calculate the number of half-lives that have passed: 60 years / 15 years per half-life = 4 half-lives
2. Calculate the remaining sample amount using the formula: remaining amount = initial amount * (1/2)^number of half-lives
3. Apply the formula: remaining amount = 16 kg * (1/2)^4 = 16 kg * 1/16 = 1 kg

After 60 years, 1 kg of the radioactive sample is left. The correct answer is D. 1kg.

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I don't know I can't read that sorry I mean don't understand

True, heat transfer into a system from the surroundings is considered a positive transfer of energy. This is because the system is gaining energy from its surroundings, causing its internal energy to increase. This can be represented by a positive value for heat transfer (Q) in the equation for the change in internal energy of a system: ΔU = Q - W, where W is the work done by the system. If heat is transferred out of the system and into the surroundings, it would be considered a negative transfer of energy and represented by a negative value for Q.

Answer:

They rearrange themselves and join together differently to make new substances called products. The number of atoms of each type is the same before and after a reaction. This means that the total mass of the products is the same as the total mass of the starting substances. In other words, mass is conserved.

Answer:

true

Explanation:

I just had a test on this

Answer:

true

Explanation:

cause it is

The net force on a rock that has a force of 4.9N down and 2.8N up applied to it is 2.1N down.

Define force.

A force is an effect that can alter an object's motion according to physics. An mass-laden object can change its velocity, or accelerate, as a function of a force. An obvious method of describing force is as a push or a pull. A force is a vector quantity because it possesses both magnitude and direction.

Thrust, which increases an object's velocity; drag, which decreases an object's velocity; and torque, which causes changes in an object's rotational speed, are all concepts connected to force. Each part of an extended body often exerts stresses on the sections that are nearby.

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A long bone increases in length until epiphyseal closure occurs.

Long bones, such as those found in the arms and legs, have the ability to increase in length through a process called longitudinal growth. This growth occurs at the specialized areas called growth plates or epiphyseal plates located near the ends of the bone.

The growth plates consist of cartilage that actively divides and is gradually replaced by bone tissue. As long as the growth plates are open, the bone can continue to lengthen.

However, once epiphyseal closure occurs, the growth plates fuse and harden into solid bone, indicating the end of longitudinal growth. This closure typically happens during adolescence when the bones reach their final length and maturity.

After epiphyseal closure, bones can no longer grow in length, but they can still increase in thickness through a process called appositional growth.

Therefore, the correct answer is: epiphyseal closure occurs.

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Sunrise at A occurs during the winter solstice, sunrise at B occurs during the vernal equinox, and sunrise at C occurs during the summer solstice.

The eastern horizon is where the sun rises, and the position of sunrise changes throughout the year due to the tilt of the Earth's axis.

In this case, the diagram shows three different positions of sunrise, A, B, and C.

Here's the correct pairing of the location of sunrise to the time of the year:

A - Winter Solstice (December)
B - Equinoxes (March and September)
C - Summer Solstice (June)

During the Winter Solstice (A), the sun rises at its southernmost point on the horizon. During the Equinoxes (B), the sun rises due east, and during the Summer Solstice (C), the sun rises at its northernmost point on the horizon.

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During a trial, the sequence of events typically begins with the plaintiff's attorney's direct examination of the first witness. This marks the start of the presentation of evidence and allows the plaintiff's attorney to establish their case and elicit testimony from their witness.

The purpose of direct examination is for the plaintiff's attorney to ask questions that allow the witness to provide relevant information and support the plaintiff's claims. The attorney may ask open-ended questions, seek factual details, and allow the witness to explain their perspective or experiences related to the case. The questions are usually designed to guide the witness in presenting their testimony in a clear and organized manner.

Through direct examination, the plaintiff's attorney aims to establish key facts, introduce evidence, and present a coherent narrative that supports the plaintiff's legal arguments. The attorney may also use leading questions, which suggest the desired answer, in order to elicit specific information from the witness.

After the direct examination, the defendant's attorney has the opportunity to cross-examine the witness. During cross-examination, the defendant's attorney asks questions to challenge or clarify the witness's testimony and potentially undermine the plaintiff's case.

Overall, the plaintiff's attorney's direct examination of the first witness is a crucial step in presenting their case and providing the court with evidence and testimony to support their claims. It sets the tone for the trial and establishes the initial foundation for the plaintiff's arguments.

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The sample size with some specified width error by reducing the confidence level to 80% is 3 times the original sample size and the width error which have been scaled in size compared to the original width error is by a factor of 10.

When reducing the confidence level to 80% and the original width (error) E by a third, the new sample size will be 3 times the original size. To calculate this, use the formula n = (zα/2 / E)² × σ2.

If the original confidence level was 95%, then the original zα/2 = 1.96. If the new confidence level is 80%, then the new zα/2 = 1.282.

The original error was E, and the new error is 1/3 E. By substituting these values into the formula, we get n = (1.282 / (1/3 E))² × σ2. This simplifies to n = 3 × (1.96 / E)² × σ2, which is 3 times the original sample size.

If the original confidence level was 95%, then the original zα/2 = 1.96.

If the new confidence level is 85%, then the new zα/2 = 1.44.

The original error was E, and the new error is 10E.

By substituting these values into the formula, we get n = (1.44 / (10E))² × σ2.

This simplifies to n = (1.96 / E)² × σ2, which is 10 times the original sample size.

Therefore, the width (error) will have scaled in size by a factor of 10 compared to the original width (error) E.

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6% is the maximum grade the tractor could ascend.

To calculate the maximum grade the crawler tractor could ascend, we need to find the maximum tractive force the tractor can exert and then relate that to the grade resistance.

Step 1: Convert the tractor's weight to tons.
1 ton = 2000 lb
Tractor's weight in tons = 68,000 lb / 2000 lb/ton = 34 tons

Step 2: Calculate the rolling resistance force.
Rolling resistance force = Rolling resistance factor * Tractor's weight in tons
Rolling resistance force = 120 lb/ton * 34 tons = 4,080 lb

Step 3: Calculate the maximum tractive force.
The maximum tractive force equals the rolling resistance force because, on the steepest grade possible, all of the tractor's available traction will be used to overcome the rolling resistance.
Maximum tractive force = 4,080 lb

Step 4: Calculate the grade resistance force.
Grade resistance force = Tractor's weight * sin(slope angle)

Step 5: Set the maximum tractive force equal to the grade resistance force.
4,080 lb = 68,000 lb * sin(slope angle)

Step 6: Solve for the slope angle.
sin(slope angle) = 4,080 lb / 68,000 lb
sin(slope angle) ≈ 0.06

slope angle ≈ arcsin(0.06)
slope angle ≈ 3.44°

Step 7: Convert the slope angle to a grade percentage.
grade percentage = (tan(slope angle)) * 100%
grade percentage ≈ (tan(3.44°)) * 100%
grade percentage ≈ 6%

The maximum grade the crawler tractor could ascend on wet earth with a rolling resistance factor of 120 lb/ton is approximately 6%.

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Answer:

w=f×d

=120×5

=600 j...........

1. The force experienced by the 5μC charge is 0.45 N.

2. The force on the 20μC charge is -0.45 N.

3. The electric field strength located at 15cm from the 20μC charge is 12 N/C.

4. The electric field lines will point away from the 20μC charge, radially outward.

1. To calculate the force experienced by the 5μC charge, we can use Coulomb's law. Coulomb's law states that the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Mathematically, the formula is given by:

\(F = k * (q1 * q2) / r^2\)

Where F is the force, k is the electrostatic constant (9 x 10^9 Nm²/C²), q1 and q2 are the charges, and r is the distance between them.

Plugging in the values:

\(F = (9 x 10^9 Nm^2/C^2) * ((5 x 10^-6 C) * (20 x 10^-6 C)) / (0.1 m)^2\)

= 0.45 N

Therefore, the force experienced by the 5μC charge is 0.45 N.

2. By Newton's third law of motion, the force on the 20μC charge is equal in magnitude but opposite in direction to the force experienced by the 5μC charge. Hence, the force on the 20μC charge is -0.45 N.

3. To calculate the electric field strength at a point, we can use the formula:

\(E = k * (q / r^2)\)

Where E is the electric field strength, k is the electrostatic constant, q is the charge, and r is the distance from the charge.

Plugging in the values:

\(E = (9 x 10^9 Nm^2/C^2) * (20 x 10^-6 C) / (0.15 m)^2\)

= 12 N/C

Therefore, the electric field strength located at 15cm from the 20μC charge is 12 N/C.

4. Electric field lines depict the direction of the electric field. Since the charge is positive (20μC), the electric field lines will point away from it, radially outward. Hence, at the 15cm mark from the 20μC charge, the electric field lines will extend outward from the charge in all directions.

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Answer:

When we can get the Kinetic energy from this formula KE= 1/2 M V^2and we can get the potential energy from this formula PE =  M g H

we can set that the kinetic energy at the bottom of the fall equals the potential energy at the top so, KE = PE

1/2 MV^2 = M g H

1/2 V^2 = g H

when V is the velocity, g is an acceleration of gravitational force (9.8 m^2/s) and H is the height of the fall (8 m).

∴ v^2 = 2 * 9.8 * 8 = 156.8

∴ v= √156.8 = 12.5 m/s

Spraying an asphalt road with water will make it easier to walk across and bare feet on a hot sunny day because it has a high specific heat capacity.

This is referred to as the amount of heat which is required to raise the temperature of the unit mass of a given substance by a given amount.

Water as a compound has a very high specific heat capacity which means that it needs a high amount of heat for the temperature to change. This therefore means that when the water is sprayed on the surface, the road doesn't become too hot and can be walked on with the barefoot which makes it the correct reason.

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The image height on the detector will change by a factor of 2 if you change from a 50-mm-focal-length lens to a 100-mm-focal-length lens and refocus.

The magnification of a lens is given by the ratio of the image height to the object height. Since the object height remains the same, the change in magnification is solely determined by the change in focal length.

The magnification of a lens is given by the formula:

Magnification = - (image distance / object distance).

Since we are only interested in the ratio of image heights, we can ignore the negative sign.

For the 50-mm lens, the magnification is:

Magnification1 = 50 mm / object distance.

For the 100-mm lens, the magnification is:

Magnification2 = 100 mm / object distance.

Taking the ratio of the two magnifications:

Magnification2 / Magnification1 = (100 mm / object distance) / (50 mm / object distance) = 100 mm / 50 mm = 2.

Therefore, the image height on the detector changes by a factor of 2 when switching from a 50-mm-focal-length lens to a 100-mm-focal-length lens and refocusing.

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The major concern of exposure to extremely low-frequency (ELF) radiation has been a. Childhood leukemia and brain cancers.

Studies and research have suggested a possible link between ELF radiation and an increased risk of certain health effects, particularly childhood leukemia and brain cancers. These concerns primarily arise from long-term exposure to ELF electromagnetic fields, such as those emitted by power lines, electrical appliances, and electrical substations.

However, it is important to note that scientific consensus on the health effects of ELF radiation is still evolving, and further research is needed to fully understand the potential risks associated with prolonged exposure. Other health concerns such as non-malignant skin cancer, cataracts, and malignant melanoma have not been identified as major concerns specifically related to exposure to ELF radiation.

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The rate constant k is typically increased by:

1. Increasing the temperature of the reaction: The rate constant is directly proportional to the temperature of the reaction as described by the Arrhenius equation. An increase in temperature usually results in an increase in the rate constant.

2. Increasing the concentration of reactants: A higher concentration of reactants typically leads to a higher frequency of collisions, which can result in a higher reaction rate and an increase in the rate constant.

3. Adding a catalyst: A catalyst can provide an alternative reaction pathway with lower activation energy, which can increase the rate of the reaction and therefore the rate constant.

Answer:

Higher Temperature

Explanation:

Rate constant k in itself is affected by 2 terms: temperature and activation energy. Higher temperature will cause a bigger rate constant k hence rate increases. Lower activation energy (via the use of catalyst) will cause a bigger k hence rate increases...

Answer:

Originally :  Level = log I / I0

Currently: Level = 10 log I / I0

Level = 10 log 600 = 10 * 2.78 = 27.8

Note the term 1 bel = 10 decibels

✴ A train is uniformly slowed down from 35m/s to 21m/s over a distance of 350m. Calculate the acceleration and the time taken to come to rest from the 35m/s.

✒ The acceleration is - 1.12 ms-² and the time taken to come to rest from the 35m/s is 31.3 seconds .

Given :-

A train is uniformly slowed down from 35m/s to 21m/s over a distance of 350m.

To Find :-

Calculate the acceleration and the time taken to come to rest from the 35m/s.

Calculation :-

According to the question,

Initial velocity ( u ) = 35 m/s

Final velocity ( v ) = 21 m/s

Displacement ( s ) = 350 meters

♠ A train is uniformly slowed down from 35m/s to 21m/s over a distance of 350m.

From the equation of motion ,

↗ v² - u² = 2as

➡ ( 21 )² - ( 35 )² = 2 x a x 350

➡ 441 - 1225 = 2 x a x 350

➡ - 784 = 700 x a

➡ - 784 = 700a

➡ 700a = - 784

➡ a = -784/700

➡ a = - 1.12 ms-²

So, The Acceleration of the train is - 1.12 ms-².

Initial velocity ( u ) = 35 m/s

Acceleration ( a ) = - 1.12 m/s²

Final velocity ( v ) = 0 m/s

From, the equation of motion ;

↗ v = u + at

➡ 0 = 35 + ( - 1.12 x t )

➡ 0 = 35 + ( - 1.12t )

➡ 0 - 35 = - 1.12t

➡ - 35 = - 1.12t

➡ t = 35/1.12

➡ t = 3500/112

➡ t = 31.3 seconds

The time taken to come to rest from the 35m/sis 31.3seconds.

Answer:

B

Explanation:

YOUR MUM NOOB SORRY MY MAD THE ANSWER WILL BE B BECAUSE B IS THE BEST YAY.

In Rutherford's famous set of experiments, the fact that some alpha particles were deflected at large angles indicated that the atom contains a dense, positively charged nucleus.

Rutherford conducted experiments where he bombarded a thin gold foil with alpha particles. According to the prevailing model at the time, the Thomson model, it was believed that the positive charge in an atom was spread uniformly throughout the atom, much like plum pudding.

However, Rutherford's observations revealed that some alpha particles experienced significant deflections and even bounced back at large angles. This unexpected result could not be explained by the Thomson model.

Rutherford proposed a new atomic model known as the nuclear model, suggesting that the atom consists of a tiny, dense, positively charged nucleus at the center and the majority of the atom is empty space. This explained the deflection of alpha particles, as they were repelled or deflected by the positive charge concentrated in the nucleus.

The deflection of alpha particles at large angles indicated the presence of a compact and positively charged nucleus within the atom, leading to a fundamental revision of the understanding of atomic structure.

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At 30 degrees Celsius, a saturated solution of KClO3 will contain approximately 24 grams.

Solution: Plagiarism is the act of taking someone else's work or ideas and passing them off as your own. It is an unethical practice and is considered an academic offense. To avoid plagiarism, it is important to properly cite any sources that are used, including quotes, facts, images, and any other type of borrowed material. Additionally, it is important to give credit to the original authors of any ideas or works that are used. It is also recommended to paraphrase or re-word any material that is borrowed, so that it is not presented in the same exact form as the original. By following these steps, you can ensure that your work is completely plagiarism-free.

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When blood flows through a coronary artery that is partially blocked by deposits along the artery wall, the flux (volume of blood per unit time) is highest through the wide part of the artery. Therefore, the correct option is B.

The flux is a measurement of the flow of fluid per unit area over time. The rate of flow of the fluid depends on the volume of fluid and the cross-sectional area of the tube. Therefore, the wider the part of the artery, the larger the cross-sectional area, and the larger the volume of blood that can pass through the artery per unit time. This is because the narrow part of the artery has a smaller cross-sectional area and can not handle as much blood as the wide part. Hence, the flux is largest through the wide part of the artery.  Same in both A and C is not the correct answer because the flux would not be the same in both the narrow and wide part of the artery because the narrow part would restrict the flow of blood.

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