If liquid water at 30 c is flowing in a pipe and the pressure drops to the vapor pressure, what happens in the water?

A Lord Kelvin generator cannot produce an electron liquid with accelerated water hitting a charged plate.

A Lord Kelvin generator, also known as a Kelvin water dropper or electrostatic generator, is a device that generates high voltage electrostatic charge through the separation of charges by the falling water droplets. The process involves water flowing through two nozzles, falling onto oppositely charged metal buckets. The water droplets carry the charge to the buckets, which accumulate an increasing electrostatic charge until they discharge in the form of a spark.

An electron liquid is a theoretical concept referring to a state of matter where the electrons in a material behave as a fluid. This state can be achieved under certain conditions like extremely low temperatures, but not by a Lord Kelvin generator. The generator's function is to produce high voltage electrostatic charges, not to create new states of matter or manipulate electrons to form electron liquids.

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The speed of the car at the bottom of the driveway is approximately 4.71 m/s.

To find the speed of the car at the bottom, first, calculate the parallel component of gravity (Fg_parallel = m * g * sin(theta)), which is 2603 kg * 9.8 m/s² * sin(35°) ≈ 14724 N.

Then, find the net force acting on the car (F_net = Fg_parallel - frictional force), which is 14724 N - 3651 N = 11073 N. Next, determine the acceleration (a = F_net / m) as 11073 N / 2603 kg ≈ 4.26 m/s².

Finally, use the kinematic equation (v² = u² + 2as) to calculate the final speed (v = √(0² + 2 * 4.26 m/s² * 5 m)) ≈ 4.71 m/s.

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The power dissipated in the light bulb if it carries a current of 3i is 9p.

The power dissipated by a light bulb is given by the equation P = I²R, where I is the current flowing through the bulb and R is its resistance. Since the same light bulb is being used, its resistance remains constant.

When the current flowing through the bulb is increased to 3i, the power dissipated is given by P' = (3i)²R = 9i²R = 9P,

where P is the power dissipated when the current was i.

Therefore, the power dissipated in the light bulb is multiplied by a factor of 9 when the current is increased to 3i.

Assuming the resistance of the light bulb remains constant, we can use Ohm's law to find the new current when the current is tripled. Ohm's law states that the current flowing through a conductor is directly proportional to the voltage applied across it and inversely proportional to its resistance. Therefore, when the current is tripled, the voltage across the bulb will also triple since the resistance remains constant.

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The graph shown in the first option nicely plots the lion's and gazelle's velocities as a function of time, so option A is the correct answer.

Velocity is the rate of change of displacement over time.

As mentioned in the problem of running at a constant speed towards a gazelle with a standing lion as shown above.

So option A is correct.

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Answer:

friction, conduction and induction

Explanation:

Had it in class I had it correct hope this helps.

The rank of the galaxies based on the speed with which each should be moving away from earth due to the expansion of the universe, from fastest to slowest are:

Galaxies are separating from one another in static space. As space enlarges, galaxies are relocating away from one another.

We may learn a lot about the nature of the cosmos from Hubble's law, which states essentially that a galaxy's velocity (or, as it is commonly displayed, its redshift) is precisely proportionate to its distance. The relationship between distance and velocity should not exist if the cosmos is constant and unchanging. According to Hubble's law, a galaxy gets larger the farthest it is from Earth.

Therefore, Hubble-Lemaître law, commonly referred to as Hubble's law, is the finding in physical cosmology that galaxies are eloping from Earth at rates proportionate to their separation. In other words, they are traveling away from Earth more quickly the more away they are.

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See full question below

The following figures give the approximate distances of five galaxies from Earth. Rank the galaxies based on the speed with which each should be moving away from Earth due to the expansion of the universe, from fastest to slowest.

- 800 million ly

- 2 billion ly

- 70 million ly

- 230 million ly

- 5 billion ly

Answer:

the density of gold is 19.3 g/cc

Answer:

Gold has density of 19.3 g/cc.

Explanation:

The density of an element is the amount of mass it has per unit volume.

Answer:

Magnetization is the density of magnetic dipole moments that are induced in a magnetic material when it is placed near a magnet. ... Magnetization is also known as magnet polarization.

Answer:

Acceleration

Explanation:

For example, if the acceleration is zero, then the velocity-time graph is a horizontal line (i.e., the slope is zero). If the acceleration is positive, then the line is an upward sloping line (i.e., the slope is positive).

Answer:

D

Explanation: Given that a student leaves their history classroom and walks 20 meters north to a drinking fountain. Then the student turns and walks 50 meters south to their art classroom.

The distance is a scalar quantity.

The distance = 50 + 20

distance = 70 metres

Therefore, the magnitude of the total distance traveled by the student is 70 metres. Which is option D

Answer:

LOL Diagrams

a way to represent how the energy is stored in the chosen system during various snapshots and to represent any changes in total energy for the system. Each “L” represents how the energy is stored during a particular snapshot (instant). The “O” shows the objects inside and outside the system.

The frequency observed by the observer on the left (fL) is higher than the frequency observed by the observer on the right (fR). Here option A is the correct answer.

The observed frequency, fL, of the sound heard by the observer on the left is higher than the observed frequency, fR, heard by the observer on the right. This phenomenon is known as the Doppler effect.

When a source of sound is moving towards an observer, the sound waves are compressed, resulting in a higher frequency. Conversely, when the source of sound is moving away from an observer, the sound waves are stretched, leading to a lower frequency.

In this case, as the police car is moving towards the observer on the left, the sound waves are compressed, causing an increase in frequency. Therefore, the observer on the left hears a higher frequency, fL. On the other hand, the observer on the right experiences the sound waves stretching due to the car moving away, resulting in a lower frequency, fR. Thus, the correct answer is A. fL > fR.

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Explanation: Research highlights the individuals with ASDS are nutritionally vulnerable because they exhibit a selective or pick eating pattern and sensory sensitivity that predisposes them to restricted intakes.

I hope this helps!

The vertical height of the marble when it comes to a stop before rolling back is 20 centimeters.

As per the Law of conservation of energy,

If there is no external force acting on the system, the energy will always remains the same at every point of the motion.

As, we can see, there is no external force on the marble,

Energy of the marble at start will be equal to energy of the marble at the vertical height

We can write,

Energy while rolling = Energy at the highest point

1/2MV² = MgH

Where,

M is the mass of the marble,

V is the velocity of the marble,

g is the acceleration due to gravity and,

H is vertical height of the marble.

So,

1/2MV² = MgH

1/2V² = gh

Putting all the values,

1/2(2)² = 10H

H = 4/20

H = 0.2 meters.

So, the vertical height of the marble is 20 cm.

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By applying net force formula, the acceleration of the box is 1.8 m/s²

Acceleration is the velocity change per time taken. It is a vector quantity and it is measured in m/s²

Given that Marco pulls the box away from his brother, applying a force of 38 N to the left. His sister helps him by applying an additional force of 36 N to the left. Their brother applies a force of 35 N to pull the box in the opposite direction. The box weighs 22 kg.

F = ma

Where

To determine the acceleration of the box, substitute all the parameters into the formula

(38 + 36) - 35 = 22 a

74 - 35 = 22a

39 = 22a

a = 39/22

a = 1.77 m/s²

Therefore, the acceleration of the box is 1.8 m/s² approximately.

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When a car's velocity is positive and its acceleration is also positive, the car's overall motion is speeding up in a forward direction.

Velocity is the measure of an object's speed in a specific direction, while acceleration is the measure of how quickly an object's velocity changes over time. So, if both the velocity and acceleration are positive, the car's speed is increasing in the forward direction. This means that the car is moving faster and faster in a forward direction.

Likewise, it can be said that the automobile develops an accelerated movement.

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Answer:

The correct option is;

(B) \(\underset{P}{\rightarrow}\) is conserved, K Not conserved

Explanation:

From the diagram related to the question and from the question, we have;

m₁ = m₂ = 2 kg

v₁ = 4 m/s, v₂ = -2 m/s, v₃ = 1 m/s, therefore, we have;

The total initial momentum of the system = m₁ × v₁ + m₂ × v₂

m₁ (v₁ + v₂) = 2×(4 - 2) = 4 kg·m/s

The total final momentum of the system = m₁ × v₃ + m₂ × v₃ = 2 ×1 +2 ×1  = 4 kg·m/s

Given that the total initial momentum = The total final momentum, we have that the momentum, p, is conserved

The kinetic energy of the system before collision  = 1/2×m₁×v₁² + 1/2×m₂×v₂²

∴ The kinetic energy of the system before collision  = 1/2*2*(4)² + 1/2*2*(-2)² = 20 J

∴ The kinetic energy of the system after collision  = 1/2×m₁×v₃² + 1/2×m₂×v₃²

1/2*2*(1)² + 1/2*2*(1)² = 2 J

The kinetic energy of the system before collision ≠ The kinetic energy of the system after collision

Therefore, the kinetic energy of the system is not conserved.

If the velocities of object X and object Y after collision is the same (inelastic collision), then only momentum is conserved but if the velocities of both objects after collision are different (elastic collision), then both momentum and kinetic energy are conserved.

According to principle of conservation of linear momentum, the total momentum before and after collision is conserved.

For inelastic collision, only momentum is conserved while kinetic energy is not conserved.

\(m_1u_1 \ + \ m_2u_2 = v(m_1 + m_2)\)

\(\frac{1}{2} m_1u_1^2 \ + \frac{1}{2} m_2u_2^2 = \frac{1}{2}v^2(m_1+m_2)\)

For elastic collision, both momentum and kinetic energy are conserved;

\(m_1u_1 \ + \ m_2u_2 =m_1v_1 \ + \ m_2v_2\)

\(\frac{1}{2} m_1u_1^2 \ + \frac{1}{2} m_2u_2^2 = \frac{1}{2}m_1v_1^2 \ +\ \frac{1}{2}m_2v_2^2\)

Thus, we can conclude that, if the velocities of object X and object Y after collision is the same (inelastic collision), then only momentum is conserved but if the velocities of both objects after collision are different (elastic collision), then both momentum and kinetic energy are conserved.

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Answer:

0.0013 m/s

Explanation:

Speed in inches per minute = 3 inches per minute

Speed in m/s =?

Next, we shall convert 3 inches per minute (3 in/min) to metre per minute.(m/min)

39 in/min = 1 m/min

Therefore,

3 in/min = 3 in/min × 1 m/min / 39 in/min

3 in/min = 1/13 m/min

Finally, we shall convert 1/13 m/min to m/s. This can be obtained as follow:

1 m/min = 1/60 m/s

Therefore,

1/13 m/min = 1/13 m/min × 1/60 m/s / 1 m/min

1/13 m/min = 1/780 m/s

1/13 m/min = 0.0013 m/s

Thus, 3 in/min is equivalent to 0.0013 m/s.

Therefore the speed of the snail in m/s is 0.0013 m/s

Answer:

This rapid growth increase was mainly caused by a decreasing death rate (more rapidly than birth rate), and particularly an increase in average human age. By 2000 the population counted 6 billion heads, however, population growth (doubling time) started to decline after 1965 because of decreasing birth rates.

Explanation:

The main cause of human population growth is increased well-being.

Well-being is a term to refer to the state of satisfaction of economic, social, labor, psychological, biological needs, among others of the human.

Therefore, when civilizations and societies became more complex, many issues such as health, food, hygiene, education, government, among others, improved, giving more well-being to their inhabitants.

Well-being has evolved with society and today people have access to many things, services, and goods that give them well-being, improving their quality and life expectancy. Therefore, the correct answer is well-being.

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Terminal speed of a wooden ball (density 0.830g/cm³) falling through the air, if the radius is 8.50 cm and the drag coefficient is 0.500 = 1.860 m/s

The object in free fall would reach this speed if there were no air resistance at that height = 176 m

We have,

ρ = 0.830 g/cm³ = 830 kg/m³

r = 8.50 cm = 0.08 m

c = 0.500

ρ air = 1.2 kg/m³

Determine mass of the wooden sphere:

m = ρV

= 0.830 { \(\frac{4}{3}\) \(\pi\) (8.5)³}

= 2.13 kg

So, the terminal speed of a wooden sphere:

v = √(2mg/D(ρ air)(A)

= \(\sqrt{\frac{2(2.13)(9.8)}{(0.500)(1.20)(0.0201)} }\)

= 1.860 m/s

The height:

h = v²/2g

= (1.860)² / 2(9.8)

= 176 m

The question is incomplete, it should be:

a. Estimate the terminal speed of a wooden sphere (density 0.830 g/cm³) falling through air, if its radius is 8.50 cm and its drag coefficient is 0.500. (the density of air is 1.20 kg/m³)? b. From what height would a freely falling object reach this speed in the absence of air resistance?

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Answer:

hello! Jaesuk~Sakai here!

Explanation:

The four group 3 elements are scandium, yttrium, lanthanum and actinium. “lanthanide” refers to the elements between lanthanum and lutetium. That term does not encompass scandium and yttrium. Scandium and yttrium act pretty much identically to lanthanides.

happy to help!!

Remember to always stay happy no matter what happens! ^^

Calculate the buoyant force acting on the block, which is equal to the weight of water displaced, using Archimedes' principle. The block's weight less the buoyant force equals the tension in the string.

To calculate the buoyant force, we need to determine the volume of water displaced by the block. The volume of the block is equal to its mass divided by its density, so we have: Volume of block = mass / density = 653 g / 0.73 g/cm3 = 894.5 cm3 Since the block is completely submerged, the volume of water displaced is also 894.5 cm3. The weight of this volume of water is: Weight of water = density of water x volume of water x acceleration due to gravity

= 1 g/cm3 x 894.5 cm3 x 9.81 m/s2

= 8,756.75 g ,Thus, the buoyant force acting on the block is 8,756.75 g or 8.75675 N. Since the block is trying to float to the surface, the buoyant force acts upwards and the tension in the string acts downwards. Therefore, the tension in the string is: Tension in string = weight of block - buoyant force

= 653 g x 9.81 m/s2 - 8.75675 N

= 6,263.63 N - 8.75675 N

= 6,254.87 N , Therefore, the tension in the string is approximately.

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The required lim t → ∝ v(t) when an object is dropped from rest is calculated to be mg/c.

Given that,

An object with mass m is dropped from rest and taking air resistance into account.

The velocity as a function of time is,

v(t) = (m g)/c [ 1 - e^-(ct/m)]

v(t) = (m g)/c [ 1 - 1/e^(ct/m)]

lim t → ∝ v(t) = (m g)/c [ 1 - 1/∝]

lim t → ∝ v(t) = (m g)/c ( 1 - 0)

lim t → ∝ v(t) = (m g)/c

Thus, the required lim t → ∝ v(t) when an object is dropped from rest is calculated to be mg/c.

The question is incomplete. The complete question is 'v = mg c (1 − e−ct/m) where g is the acceleration due to gravity and c is a positive constant describing air resistance. (a) Calculate lim t→∞ v.'

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To solve a line cut by a transversal, use the properties of parallel lines, such as corresponding angles and alternate interior angles, to find the unknown angle measurements.

When a line is cut by a transversal, a number of simultaneous equations can be formed by using the properties of parallel lines. For example, the corresponding angles of the lines will always be equal, the alternate interior angles will be equal, and the consecutive interior angles will add up to 180 degrees. Using these properties, you can identify the unknown angle measurements. For example, if the measure of one of the corresponding angles is known, the measure of the other corresponding angle can be determined simply by using the fact that they are equal. Similarly, if one of the alternate interior angles is known, the other can be determined using the fact that they are equal. By forming these equations, you can solve for the unknown angle measurements.

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Answer:

11×10⁵ J

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 1000 kg

Height (h) = 110 m

Acceleration due to gravity (g) = 10 m/s²

Potential energy (PE) =?

The potential energy of the roller coaster can be obtained as follow:

PE = mgh

PE = 1000 × 10 × 110

PE = 11×10⁵ J

Therefore, potential energy of the roller coaster is 11×10⁵ J

The inductive reactance is 1578.34 Ω.

We need to know about inductive reactance to solve this problem. The inductive reactance is the internal resistance in the inductor caused by changing current. It can be described as

XL = ω . L

where XL is inductive reactance, ω is angular speed and L is inductance.

The angular speed can be determined by

ω = 2π . f

where f is frequency.

From the question above, we know that

f = 81 Hz

L = 3.1

By substituting the given parameters, we get

XL = ω . L

XL = 2π . f . L

XL = 2π . 81 . 3.1

XL = 1578.34 Ω

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According to the given statement F = -12716 N is the average force exerted on the ball by the bat.

The average force is the force applied by an object traveling over a specific period of time at a given rate of speed, or velocity. This velocity is not immediate or precisely calculated, even as word "average" implies.

m = 220 g = 0.22 kg

v\(_1\) = 32.20m/s

v\(_2\) = -54.50 m.s

t = 1.5 ms = 1.5 * 10⁻³

To find the average force exerted on the ball.

If we use the impulse-momentum theorem,

F = mv\(_2\) - mv\(_1\)/t

Now, we have to substitute values in equation 11:

\($F=\frac{0.22 \mathrm{~kg} \cdot\left(-54.5 \frac{\mathrm{m}}{\mathrm{s}}\right)-0.22 \mathrm{~kg} \cdot\left(32.2 \frac{\mathrm{m}}{\mathrm{s}}\right)}{1.5 \cdot 10^{-3} \mathrm{~s}}$\)

F = -12716 N

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If you're standing, you need friction between your feet and the ground; otherwise, you will slip or slide.

\(\huge{\mathcal{\colorbox{black}{\textcolor{lime}{\textsf{I hope this helps !}}}}}\)

♥️ \(\large{\textcolor{red}{\underline{\texttt{SUMIT ROY (:}}}}\)

Answer:

Wavelength - b

Amplitude - c

Wave period - e

Trough - a

Crest - d

Explanation:

:)

False. someone with the characteristics of an autotelic personality does not prefer medium-skill, high-challenge situations to stimulate growth.

Contrary to the statement,  In fact, individuals with an autotelic personality are more inclined towards high-skill, high-challenge situations. The term "autotelic" refers to a person's ability to find intrinsic satisfaction and enjoyment in activities for their own sake, rather than relying on external rewards or motivations. These individuals actively seek out tasks and endeavors that require their full engagement and offer opportunities for personal growth, learning, and mastery.

Autotelic individuals thrive when their existing skills are matched with challenging situations that push their limits. By immersing themselves in demanding activities, they enter a state of flow, where they feel completely absorbed and in the zone. This optimal state of engagement leads to a sense of fulfillment and enhances their overall well-being. It is through these high-skill, high-challenge tasks that individuals with an autotelic personality experience the most growth and development.

In summary, an autotelic personality is characterized by a preference for high-skill, high-challenge situations rather than medium-skill, high-challenge situations. They actively seek out opportunities to stimulate their personal growth and find intrinsic satisfaction in pushing themselves beyond their current abilities.

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