If it takes 37.5 minutes for a 1.75 L sample of gaseous chlorine to effuse through the pores of a container, how long will it take an equal amount of fluorine to effuse from the same container at the same temperature and pressure?

Answer:

h = –xy + r

Step-by-step explanation:

Given the equation, \(x = \frac{r-h}{y}\):

To solve for h:

Multiply both sides of the equation by y to cancel the fraction on the right-hand side:

\(x (y) = (\frac{r-h}{y}) (y)\)

\(xy = r - h\)

Next, subtract r from both sides:

xy – r = r – r – h

xy – r = – h

Next, divide both sides by -1  to solve for h:

\(\frac{xy - r}{-1} = \frac{-h}{-1}\)

Therefore, the equation for h is:

h = –xy + r

Answer:

The correct end behavior are;

As x approaches positive infinity, y approaches positive infinity (D)

As x approaches negative infinity, y approaches positive infinity (B)

Step-by-step explanation:

Here, we want to get the end behavior of the graph

Kindly note that the upward arrow represents a movement toward infinity

Thus, we have it as follows;

As the value of x increases (towards the right); the value of y tends toward positive infinity

secondly: as the value of x decreases, tends toward the left, the value of y also tends toward positive infinity

Answer:

x = 1/4

Step-by-step explanation:

\(log_{x}\) 16 = 2 can be written as \(16^{x}\) = 2

(\(2^{4}\))^x = 2^1

if bases are the same we can create this equation:  4x = 1

                                                                                      x = 1/4

\(\displaystyle\ \Large\boldsymbol p^q=16 \ \ then \\\\ 1) p=2 \ ; \ q=4 \Longrightarrow q^{pq}=4^{2\cdot 4}= 4^{8}=65536 \\\\\\2) p=4 \ ; \ q=2\Longrightarrow q^{pq}=2^{4\cdot2} =256\)

Answer:

is the 9 seven for five 1233

Answer:

56

Step-by-step explanation:

Top line:

100% - 80% = 20%

20% of 60 = 0.2 × 60 = 12

Small piece on top is 12.

Second line:

Small piece is 12.

100% - 60% = 40%

Small piece is also 40%.

40% of x = 12

0.4x = 12

x = 12/0.4

x = 30

The entire second line is 30.

60% of 30 = 0.6 × 30 = 18

60% of second line is 18.

Third line:

30% of third line = 18

100% - 30% = 70%

30/18 = 70/x

30x = 18 × 70

x = 42

Larger part of third line is 42.

Fourth line:

75% of 4th line is 42.

100/x = 75/42

75x = 100 × 42

x = 56

Answer: 56

this is

the equation on the math

The coefficient of determination (R^2) in a simple linear regression model, which predicts home price based on the number of bedrooms, quantifies the goodness of fit of the model. It is calculated as the square of the correlation coefficient (r) between the number of bedrooms and the home price.

What is a simple linear regression model? A simple linear regression model is a statistical model that attempts to find the relationship between two quantitative variables. It is based on the idea that a dependent variable may depend on a single independent variable. As a result, a linear function is used to represent the relationship between the two variables.

A regression line, which is a straight line, is used to make predictions based on this relationship. It's important to note that the regression line can be used to make predictions only within the range of the data. Outside this range, the relationship between the two variables is unknown.

What is the coefficient of determination? The coefficient of determination, denoted as r-squared, is a statistic that indicates how well the regression line fits the data. The coefficient of determination is calculated as the ratio of the explained variation to the total variation. It ranges from 0 to 1, with 1 indicating a perfect fit between the regression line and the data and 0 indicating no relationship between the two variables.

Therefore, in a simple linear regression model that predicts home price based on the number of bedrooms, the coefficient of determination is a statistic that provides the measure of how well the model fits the data.

The coefficient of determination, denoted as R^2, represents the proportion of the variance in the dependent variable (home price) that can be explained by the independent variable (number of bedrooms) in a simple linear regression model.

In other words, R^2 measures the goodness-of-fit of the regression model. It indicates the percentage of the total variation in the home price that is accounted for by the variation in the number of bedrooms.

The coefficient of determination, R^2, can range from 0 to 1, where:

R^2 = 0 implies that the independent variable (number of bedrooms) does not explain any of the variations in the home price.

R^2 = 1 implies that the independent variable (number of bedrooms) explains all of the variations in the home price.

Therefore, the coefficient of determination (R^2) in a simple linear regression model that predicts home price based on the number of bedrooms is the square of the correlation coefficient (r) between the two variables. It represents the proportion of the variance in the home price that can be explained by the number of bedrooms.

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Answer:

Here is the answer

Step-by-step explanation:

Apples in 1 baskets=100

Apples in 64 baskets=100*64-6400

apples (before adding 30 apples in each

basket).... ..(1)

Some apples left unpacked

So he added 30 apples to each

Total apples added by him- 30*64(in each basket*no of baskets)

= 1920 apples

.(2)

So total no apples eq(1)+eq(2)

= 6400 apples + 1920 apples

=8320 apples packed in total

Therefore the total no. of apples packed were 8320 apples.

Hope this helps

Thanks

Answer: D

Step-by-step explanation:

Fill in the x's with -2 for the first time to get one answer then go back and fill in 4 for the second answer.

g(-2)= 10

g(4)=-8

Proving g(-2) is greater than g(4).

To answer your question, let's consider the set U = {2, 4, 5, 6, 7, 3, 5}, and let W be the set of all x in R³ such that U * x = 0. The theorem in Chapter 4 that can be used to show that W is a subspace of R³ is the "Subspace Theorem."

The Subspace Theorem states that a subset W of a vector space V is a subspace if it satisfies the following three conditions:
1. The zero vector of V is in W.
2. If u and v are in W, then their sum (u+v) is in W.
3. If u is in W and c is a scalar, then the product (cu) is in W.

To describe W in geometric language, W would be a plane or a line that passes through the origin in R³, which is orthogonal (perpendicular) to the given vector U. This is because all the vectors x in W have a dot product of 0 with U, indicating that they are orthogonal to U.

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The percentage of the total distance is 73%.

In mathematics, the percentage of a number is a ratio expressed as a fraction of 100. The that we use to represent the percentage is the sign “%”. The calculate the percentage of a number we use the following formula.

Percentage% = [ value of number ]/ [Total value ] × 100

Here we have

Olivia fell asleep after they had traveled 243 miles.

The total length of the trip was 900 miles.

The distance that traveled when Olivia fell asleep

= 900 miles - 243 miles

= 657 miles

The percentage of the total trip they traveled when Olivia fell asleep  

= (657/900) × 100 = 73%  

Therefore,

The percentage of the total distance is 73%.

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According to the charts, 50% was the percent increase in Factory 2's monthly production of chairs from 2009 to 2010.

Monthly production is the total amount of goods or services that a company produces within a given month. It is calculated by dividing the total production for a given period of time by the number of months in that period.

This is calculated by taking the difference in the number of chairs produced between 2009 and 2010 that is

(360-240 = 120)

and dividing it by the number of chairs produced in 2009 (240).

120/240

= 0.5

= 50%

Overall, Factory 2's monthly production of chairs increased by 50% from 2009 to 2010.

This means that the number of chairs produced in 2010 was 50% greater than the number of chairs produced in 2009.

Factory 2 increased its monthly production of chairs from 240 in 2009 to 360 in 2010.

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Answer:

z > - \(\frac{11}{9}\)

Step-by-step explanation:

7z + 7 > - 2z - 4

9z + 7 > - 4

9z > -11

z > - \(\frac{11}{9}\)

Answer: Just turn it into an equation! Replace the > with a =.

Step-by-step explanation:

Subtract 7 from both sides (bc you’re doing the opposite of +7) So 7z +7-7 cancels out so you just have 7z. 7z = -2z -4 -7, so 7z = -2z -11

Add 2z to both sides (bc your doing the opposite again) to get 9z = -11

Divide both sides by the number of the of the term with both a number and variable, in this case 9z, the number is 9. So 9z/9= -11/9 so simplified, z= -11/9

Final answer = -11/9

Hope this helps :D

Answer:

D.

Step-by-step explanation:

x = number of glasses of iced tea

y = number of glasses of lemonade

The total number of glasses is

x + y

The total number of glasses is 44

x + y = 44

This is not a choice, but the answer must be equivalent to this equation.

Solve for x by subtracting y from both sides.

x = 44 - y

Answer: D.

Answer: x is greater than or equal to 18

Step-by-step explanation:

Answer:

x ≤ - 2

Step-by-step explanation:

- x/6 ≤ 3

- x/2 ≤ 1

- x ≤ 2

x ≤ - 2

Answer:

Step-by-step explanation: Exponential depreciation formula :-

y = A(1 - r)^t, where y is the value of good after t years , r is rate of depreciation and A is the initial value.

Given : A= $20800  ; r=10.75%=0.1075  

The equation models this situation:

Then, the value of car after t=13 years :-

Hence, the value of car after 13 years = $4742.10

A sample size of at least 1068 to obtain a 95% confidence interval for the proportion of fat in meat that is within 3% of the true value.

To calculate the sample size needed for a 95% confidence interval for the proportion of fat in meat that is within 3% of the true value, we can use the following formula:

\(n = (Z^2 \times p \times (1-p)) / E^2\)

where:

n is the sample size

Z is the Z-score for the desired confidence level (1.96 for a 95% confidence interval)

p is the estimated proportion of fat in the population (we can use 0.5 as a conservative estimate)

E is the maximum allowable margin of error (0.03 in this case)

Substituting the values, we get:

\(n = (1.96^2 \times 0.5 \times (1-0.5)) / 0.03^2\)

n = 1067.11

Rounding up to the nearest whole number, we get a sample size of 1068. Therefore, we need a sample size of at least 1068 to obtain a 95% confidence interval for the proportion of fat in meat that is within 3% of the true value.

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The surface area of the rectangular prism is 88 square inches.

Given that:

Length, L = 6 inches

Width, W = 2 inches

Height, H = 4 inches

Let the prism with a length of L, a width of W, and a height of H. Then the surface area of the prism is given as

SA = 2(LW + WH + HL)

SA = 2(6 x 2 + 2 x 4 + 4 x 6)

SA = 2 (12 + 8 + 24)

SA = 2 x 44

SA = 88 square inches

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Answer:

Here:

Step-by-step explanation:

x is how much she spends, y is how much she saves.

for c, you can write:

y = 300, x = 0

y = 200, x = 100

y = 100, x = 200

y = 50, x = 250

y = 1, x = 299

x and y are variables because they can vary depending on one or the other.

The formula is just a relation between x and y. For example, another way can be that I give you $10 and you buy me 5 bottles of water. But if I give you $20, you will buy 10. The amount I give you and the number of bottles you buy me are both dependent and they have a relationship no matter what value they are. And the relationship is described by the function in the question.

The calculation (3.4876)/(4.11+1.2) should be reported with three significant figures: 0.657.

To determine the number of significant figures in the answer to the calculation (3.4876)/(4.11+1.2), we need to consider the number of significant figures in the given values and apply the rules for significant figures in mathematical operations.

First, let's analyze the number of significant figures in the given values:

- 3.4876 has five significant figures.

- 4.11 has three significant figures.

- 1.2 has two significant figures.

To perform the calculation, we divide 3.4876 by the sum of 4.11 and 1.2. Let's evaluate the sum:

4.11 + 1.2 = 5.31

Now, we divide 3.4876 by 5.31:

3.4876 / 5.31 = 0.6567037...

Now, let's determine the number of significant figures in the result.

Since division and multiplication retain the least number of significant figures from the original values, the result should be reported with the same number of significant figures as the value with the fewest significant figures involved in the calculation.

In this case, the value with the fewest significant figures is 5.31, which has three significant figures.

Therefore, the answer to the calculation (3.4876)/(4.11+1.2) should be reported with three significant figures: 0.657.

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Answer:

x=7

Step-by-step explanation:

since the ray bisects we know <CAT and <TAR are equal

so we can set up the equation like this: <CAT + <CAT = <CAR

(5x)+(5x)=(9x+7)

calculate equation and you'll get x=7

Answer:

The value of x is 3 or 2.

Step-by-step explanation:

Given equation is 2^(x-2) + 2^(3-x) = 3

On applying exponents rule a^(x-y) = a^x÷a^y

Where, a = 2, x = x and y = -2

So, using this, we get

⇛{(2^x/2²) + (2³/2^x)} = 3

⇛{(2^x/2*2) + {(2*2*2)/2^x}] = 3

⇛[(2^x)/4} + {(4*2)/2^x}] = 3

⇛[(2^x)/4} + {8/(2^x)}] = 3

Let assume that 2^x = y

So, above equation can be rewritten as

⇛{(y/4) + (8/y)} = 3

⇛{(y²+32)/4y} = 3

⇛{(y²+32)/4y} = (3/1)

On applying cross multiplication then

⇛1(y²+32) = 3(4y)

Multipy the number outside of the brackets with numbers and variables on the brackets on both LHS and RHS.

⇛y²+32 = 12y

⇛y²-12y + 32 = 0

By splitting the middle term, we get

⇛y² - 8y - 4y + 32 = 0

⇛y(y-8) - 4(y-8) = 0

⇛(y-8)(y-4) = 0

➝ y = 8 or y = 4

➝ 2^x = 8 or 2^x = 4

➝ 2^x = 2³ or 2^x = 2²

Therefore, x = 3 or x = 2

Answer: The value of x is 3 or 2.

VERIFICATION:

•If x = 3 the equation is

2^(x-2) + 2^(3-x) = 3

Substitute the value of x = 3 in equation

⇛2^(3-2) + 2^(3-3) = 3

⇛2¹ + 2⁰ = 3

⇛2 + 1 = 3

⇛3 = 3

LHS = RHS

•If x = 2 then the equation is

2^(x-2) + 2^(3-x) = 3

Substitute the value of x = 2 in equation

⇛2^(2-2) + 2^(3-2) = 3

⇛2^0 + 2^1 = 3

⇛1 + 2 = 3

⇛3 = 3

LHS = RHS

Hence, verified.

Please let me know if you have any other questions.

Answer:

$5.89 each

3.73 + 3× = 21.40

Step-by-step explanation:

subtract the total cost from the milk

21.40 - 3.73 = 17.67

divide that cost by 3 (to get the answer for just one bag)

17.67 ÷ 3 = 5.89

The p-value for study B is 0.98.

With the same set of data, two studies were conducted.

Study A was a two-sided test while study B was a one-sided test.

The p-value of the test in study A is 0.040.

If the test statistic from your sample has a negative value, the p-value for a two-sided test is equal to twice the p-value for the lower-tailed p-value. If the test statistic from your sample has a positive value, the p-value is two times that of the upper-tailed p-value.

So, in conclusion:

The one-tail p-value equals one minus half the two-tailed value.

The two-tail p-value is twice the one-tail p-value.

As study A is a two-sided test with p-value = 0.04.

The p-value of study B will be:

p = 1 - ( 1/2 ) × 0.04

p = 1 - 0.02

p = 0.98

The p-value for study B is 0.8.

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Answer:

it would be 100, 10, 90, 9

Step-by-step explanation:

If you start off with 100

you will add 10 which

will equal 110 then you add

90 to it and it would equal 200 then

add 9 and it equals 209

and 19x11 equals 209

The area of a two-dimensional cross-section depends on the shape it represents, such as a square, rectangle, triangle, circle, or any other polygon. Each shape has its own formula for calculating its area.

In order to determine the area of the cross-section, we need additional information such as the shape of the cross-section, its dimensions, or any other relevant details. Without this information, it is not possible to calculate the area. Please provide more details or a specific shape or scenario so that an accurate answer can be generated. Once the shape is specified, the appropriate formula can be applied to calculate the area.

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a) Since E is closed, its complement F\ E is contained in F, so the intersection of {U_i1, U_i2, ..., U_in} with E is still a finite subcover of E. Thus, E is compact.

b) The union of all these finite subcovers is a finite subcover of {U_i} that covers K, showing that K is compact.

(a) To show that E is compact, we need to show that any open cover of E has a finite subcover. Let {U_i} be an open cover of E. Since E is closed in F, its complement F\E is open in F. Thus, {U_i} and F\ E together form an open cover of F. Since F is compact, there exists a finite subcover {U_i1, U_i2, ..., U_in, F\ E}. Since E is closed, its complement F\ E is contained in F, so the intersection of {U_i1, U_i2, ..., U_in} with E is still a finite subcover of E. Thus, E is compact.

(b) Let K1, K2, ..., Kn be a finite collection of compact subsets of S. Let {U_i} be an open cover of their union K= K1∪ K2 ∪ ... ∪ Kn. Then each Ki is contained in K, so {U_i} is also an open cover of each Ki. Since each Ki is compact, there exists a finite subcover {U_i1, U_i2, ..., U_ik_i} of {U_i} for each Ki. Thus, we have a finite collection of sets {U_i1, U_i2, ..., U_ik_1}, {U_i1, U_i2, ..., U_ik_2}, ..., {U_i1, U_i2, ..., U_ik_n} that covers K1, K2, ..., Kn respectively. The union of all these finite subcovers is a finite subcover of {U_i} that covers K, showing that K is compact.

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Answer:

135

Step-by-step explanation:

bc its the right answer

Answer:

the answer is 138.57 so ur answer would be 135

Step-by-step explanation:

The z-values for the given situations are approximate:

a. The area to the left of z is 0.1827. z = -0.90

b. The area between −z and z is 0.9830. z = 2.17

c. The area between −z and z is 0.2148. z = 0.85

d. The area to the left of z is 0.9997. z = 3.49

e. The area to the right of z is 0.6847. z= -0.48

a. For an area of 0.1827 to the left of z, the corresponding z-value can be found using a standard normal distribution table or a statistical calculator. The z-value is approximately -0.90.

b. To find the z-value for an area between -z and z equal to 0.9830, we need to find the value that corresponds to (1 - 0.9830)/2 = 0.0085 in the upper tail of the standard normal distribution. Using the table or calculator, the z-value is approximately 2.17.

c. Similarly, for an area between -z and z equal to 0.2148, we find the value that corresponds to (1 - 0.2148)/2 = 0.3926 in the upper tail. The z-value is approximately 0.85.

d. For an area of 0.9997 to the left of z, we find the value that corresponds to 0.9997 in the upper tail. The z-value is approximately 3.49.

e. To find the z-value for an area to the right of z equal to 0.6847, we find the value that corresponds to 1 - 0.6847 = 0.3153 in the upper tail. The z-value is approximately -0.48.

In summary, the z-values for the given situations are approximate:

a. -0.90

b. 2.17

c. 0.85

d. 3.49

e. -0.48

These values can be used to determine the corresponding percentiles or probabilities for the standard normal distribution. The values are typically found using standard normal distribution tables or statistical calculators that provide the cumulative probability distribution function (CDF) for the standard normal distribution.

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