if it requires energy u to accelerate a rocket fro rest to 1/2c the energy needed to acclerate a rocket from 1/2 c to c would be
Answers
The energy needed to accelerate a rocket from 1/2 c to c would be 3 times of U if it require U to accelerate from rest to 1/2c.
Now,we know that kinetic energy of rocket is given by =(1/2)mv² where m is the mass of the rocket and v is the velocity of rocket.
According to work-energy theorem,we know that work done=change in kinetic energy of the body.
Here,we have initial velocity of rocket is =0,and final velocity of rocket =1/2c
So,Work done=(1/2) ×m×(1/2)c² - 0²
=>U=(1 / 4) ×(1/2)×m×c²-------(eq1)
Now,we need to find the required amount of kinetic to accelerate it from 1/2c to c
So, required kinetic energy is Work done=(1/2)mc² - (1/2)×m×(1/2)c²
=>Required kinetic energy=(1/2×m×c²) × (1-1/4)
=>Required kinetic energy=(3/4)×(1/2×m×c²)
=>Required kinetic energy=(3)×((1 / 4) ×(1/2)×m×c²)
=>Required kinetic energy=3 ×times of U(from eq1)
Hence,kinetic energy required is 3 times of U.
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Related Questions
xf - (40cm) = (1.0 m/s) (1.8 s) + 1/2 (2.2 m/s^2) (1.8 s)^2
Answers
Answer:
easy stuff
Explanation:
Two resistors, R1 and R2, are
connected in parallel. R2 = 221.0
ohms, and the equivalent resistance
of the combination is 120.7 ohms.
What is the value of R1?
(Unit = ohm)
Answers
The reciprocal of the total resistance is equal to the sum of the reciprocals of the component resistances:
1/(120.7 Ω) = 1/R₁ + 1/(221.0 Ω)
1/R₁ = 1/(120.7 Ω) - 1/(221.0 Ω)
R₁ = 1 / (1/(120.7 Ω) - 1/(221.0 Ω)) ≈ 265.9 Ω
The value of R1 is approximately 266.35 ohms
When resistors are connected in parallel, the reciprocal of the equivalent resistance is equal to the sum of the reciprocals of the individual resistances.
Mathematically, it can be expressed as:
1 / Req = 1 / R1 + 1 / R2
Where:
Req is the equivalent resistance of the combination.
R1 is the resistance of the first resistor.
R2 is the resistance of the second resistor.
Given the values:
R2 = 221.0 ohms
Req = 120.7 ohms
Let's find R1:
1 / Req = 1 / R1 + 1 / R2
1 / 120.7 = 1 / R1 + 1 / 221.0
Now, let's solve for R1:
1 / R1 = 1 / 120.7 - 1 / 221.0
1 / R1 = 0.008281 - 0.004524
1 / R1 = 0.003757
R1 = 1 / 0.003757
R1 ≈ 266.35 ohms
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A balance of forces is demonstrated by an object which is slowing to a stop true or false
Answers
Answer:
its true since i already did this last year, if i am wrong i apologize
Explanation:
describe the energy transformations on a pendulum (kinetic and potential)
Answers
Answer:
Explanation:
As a pendulum swings, its potential energy converts to kinetic and back to potential. ... During the course of a swing from left to right, potential energy is converted into kinetic energy and back.
Answer:
Once the weighted end of the pendulum is released, it will become active as gravity pulls it downwards. Potential Energy Is Converted To Kinetic Energy. which is the energy exerted by a moving object. An active pendulum has the most kinetic energy at the lowest point of it's swing when the weight is movin.
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In moving out of a dormitory at the end of the semester, a student does 2.00 104 J of work. In the process, his internal energy decreases by 3.80 104 J. Determine each of the following variables (including the algebraic sign).
(a) W = J
(b) U = J
(c) Q = J
Answers
(a) The student's work is 2.00 x 104 J.
(b) The student's internal energy drops by 3.80 x 104 J.
(c) The First Law of Thermodynamics is applied to calculate Q: U = Q - W.
(a) The work done by the student is 2.00 x 10^4 J. The algebraic sign is positive because the student is doing work on the surroundings by moving out of the dormitory.
(b) The internal energy of the student decreases by 3.80 x 10^4 J. The algebraic sign is negative because the energy is leaving the system.
(c) To determine Q, we use the First Law of Thermodynamics: ΔU = Q - W. Rearranging this equation, we get Q = ΔU + W. Plugging in the values, we get Q = (3.80 x 10^4 J) + (2.00 x 10^4 J) = 5.80 x 10^4 J. The algebraic sign is positive because the heat flows into the system from the surroundings.
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Please help!! Thank you<3 This isn't Physics its Sciene please help me :(
Answers
Answer:
The strong - arm team would win because they can excert more thrust on the rope.Explanation:
In this case, gravity is pulling down on them ( both teams ), the strong - arm team is excerting thrust by trying to pull the rope, and you've got the drag of the other team pulling back.
During an all-night cram session, a student heats up a 0.858 liter (0.858 x10 −3
m 3
) glass (Pyrex) beaker of cold coffee. Initially, the temperature is 18.2 ∘
C, and the beaker is filled to the brim. A short time later when the student returns, the temperature has risen to 90.6 ∘
C. The coefficient of volume expansion of coffee is the same as that of water. How much coffee (in cubic meters) has spilled out of the beaker?
Answers
approximately 2.093 x 10^(-6) cubic meters (or 2.093 milliliters) of coffee has spilled out of the beaker.To calculate the volume of coffee that has spilled out of the beaker, we can use the concept of thermal expansion. The change in volume is given by the formula ΔV = βVΔT, where β is the coefficient of volume expansion, V is the initial volume, and ΔT is the change in temperature.
First, let's convert the initial volume to cubic meters: V = 0.858 x 10^(-3) m^3.
Next, we calculate the change in temperature: ΔT = 90.6 - 18.2 = 72.4 °C.
The coefficient of volume expansion for water (and coffee) is approximately β = 3.4 x 10^(-4) °C^(-1).
Plugging in these values into the formula, we get:
ΔV = (3.4 x 10^(-4) °C^(-1)) * (0.858 x 10^(-3) m^3) * (72.4 °C) = 2.093 x 10^(-6) m^3.
Therefore, approximately 2.093 x 10^(-6) cubic meters (or 2.093 milliliters) of coffee has spilled out of the beaker.
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A water jet that leaves a nozzle at 55.47 m/s at a flow rate of 118.25 kg/s is to be used to generate power by striking the buckets located on the perimeter of a wheel. Determine the power generation (kW) potential of this water jet.
Answers
Step 1: The power generation potential of the water jet is approximately X kW.
Step 2:
To determine the power generation potential of the water jet, we need to calculate the kinetic energy of the jet and then convert it to power. The kinetic energy (KE) of an object can be calculated using the formula \(KE = 0.5 * m * v^2\), where m is the mass of the object and v is its velocity.
Given that the flow rate of the water jet is 118.25 kg/s and the velocity is 55.47 m/s, we can calculate the mass of the water jet using the formula m = flow rate / velocity. Substituting the given values, we get \(m = 118.25 kg/s / 55.47 m/s ≈ 2.13 kg.\)
Now, we can calculate the kinetic energy of the water jet using the formula\(KE = 0.5 * 2.13 kg * (55.47 m/s)^2 ≈ 3250.7 J.\)
To convert this kinetic energy into power, we divide it by the time it takes for the jet to strike the buckets on the wheel. Since the time is not given, we cannot provide an exact power value. However, assuming a reasonable time interval, let's say 1 second, we can convert the kinetic energy to power by dividing it by the time interval. Thus, the power generation potential would be approximately \(3250.7 J / 1 s = 3250.7 W ≈ 3.25 kW.\)
Therefore, the power generation potential of the water jet is approximately 3.25 kW.
The power generation potential of the water jet depends on its kinetic energy, which is determined by its mass and velocity. By calculating the mass of the water jet using the flow rate and velocity, we can then calculate its kinetic energy. Finally, by dividing the kinetic energy by the time interval, we can determine the power generation potential in kilowatts.
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Sally is visiting Lake Tahoe at ~6,000 feet and loves being among the conifer trees. They smell so good! It's a bright sunny day and many people are driving around the scenic lake loop. Sally notices a beautiful blue haze filling the valleys.
Answers
The blue haze filling the valleys is likely caused by the release of volatile organic compounds (VOCs) from the conifer trees, combined with the warm, sunny weather. These VOCs can irritate the airways, causing an asthma attack in people with sensitivity, such as Sally.
The blue haze that Sally observed in the valleys around Lake Tahoe is likely the result of a phenomenon known as photochemical smog. This occurs when volatile organic compounds (VOCs) released from conifer trees combine with nitrogen oxides (NOx) from vehicle emissions and sunlight to form a toxic mixture of air pollutants. This mixture can be harmful to people with respiratory issues like asthma, as it can irritate the airways and trigger an asthma attack. The bright, sunny day and the increased number of vehicles driving around the scenic lake loop likely contributed to the formation of this smog. In general, high altitudes and areas with limited air movement can trap pollutants, leading to higher concentrations in the air and worsening air quality. People with respiratory issues should be cautious and take steps to protect their health when visiting these areas.
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What does the term conserved mean?
Answers
1 : to keep in a safe or sound state He conserved his inheritance. especially : to avoid wasteful or destructive use of conserve natural resources conserve our wildlife. 2 : to preserve with sugar. 3 : to maintain (a quantity) constant during a process of chemical, physical, or evolutionary change conserved DNA ...
A. It Implies That M Is Finitely Generated. B. It Implies That M Has Nonzero Elements Of Nonzero Order. C. When Every Non-Null Element Has Null . D. In The Case That The Ring R Is A Body. E. None Of The Above Alternatives Gives A
Which of the following alternatives give a true statement. Justify your answer.
A modulus M over a ring R has a finite basis:
a. It implies that M is finitely generated.
b. It implies that M has nonzero elements of nonzero order.
C. When every non-null element has null .
d. in the case that the ring R is a body.
e. None of the above alternatives gives a true statement.
Which of the following statements are true?
a. If a subset of a module generates that whole module, then the subset cannot be
empty.
b. Every submodule S of a module M verifies the inequality C. Two different subsets of M have to generate two different submodules of M.
d. If S generates a submodule N of the module M, then contains S.
e. Neither statement is true.
Answers
The correct answer is e. None of the above alternatives gives a true statement. None of the statements in options a, b, c, and d are true when it comes to a modulus M over a ring R having a finite basis.
When a modulus M can be formed entirely from a finite set of elements, the modulus M is said to be finitely generated. M's finite basis does not, however, automatically imply that M is finitely generated. A basis is a set of linearly independent elements, and it might not be enough to produce all of the components of the modulus.
According to the assertion in option b, M must include nonzero items of nonzero order if it has a finite basis. This is untrue, though. The smallest positive number k, such that the element raised to the power of k equals the identity element, is referred to as the order of an element.
According to option c, every non-null element in a modulus with a finite basis has a null. Nevertheless, this claim is likewise untrue. It is possible for a modulus with a finite basis to have non-null elements without a null element.
According to option d, a ring R is a body, or a field, and only then can a modulus have a finite basis. However, this assertion is also untrue. Even though the ring R is not a field, a modulus can nonetheless have a finite basis. None of the given alternatives provides a true statement about a modulus M over a ring R having a finite basis.
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2. A force of 20N acts on a particle of mass 2 Kg and displaces it by 5m at an angle 30°. What is the work done? a) 40J ) b) 50 J c) 100J
Answers
Mass is not required
Force=F=20NAngle=30°Displacement=s=5m\(\\ \rm\longmapsto W=Fscos\Theta\)
\(\\ \rm\longmapsto W=20(5)cos30\)
\(\\ \rm\longmapsto W=100\times \dfrac{\sqrt{3}}{2}\)
\(\\ \rm\longmapsto W=50\sqrt{3}J\)
Answer:
\(we \: have \\ w = fs \cos( \alpha ) \\ f = 20n \\ m = 2kg \\ s = 5m \\ \alpha = 30 \\ \\ then \: w = 20 \times 5 \times \cos(30) \\ 100 \cos(30) \\ = 100 \frac{ \sqrt{3} }{2} \\ = 50 \sqrt{3} \\ = 86.6 \: joule\\ thank \: yo\)
a horizontal spring with stiffness 0.5 n/m has a relaxed length of 15 cm. a mass of 20 g is attached and you stretch the spring to a total length of 25 cm. the mass is then released from rest and moves with little friction. what is the speed of the mass at the moment when the spring returns to its relaxed length of 15 cm?
Answers
The speed of the mass when the spring returns to its relaxed length of 15 cm is 0.632 m/s.
1. First, we need to find the spring constant (k) and the mass (m). We are given k = 0.5 N/m and m = 20 g (which we need to convert to kg): m = 20/1000 = 0.02 kg.
2. Next, we need to determine the elongation (x) of the spring. We are given the initial length (25 cm) and the relaxed length (15 cm):
x = 25 cm - 15 cm = 10 cm (which we need to convert to meters):
x = 10/100 = 0.1 m.
3. Now, we can calculate the potential energy (PE) stored in the spring when it's stretched: PE = (1/2) * k * x^2 = (1/2) * 0.5 N/m * (0.1 m)^2 = 0.0025 J.
4. When the spring returns to its relaxed length, the potential energy will be converted into kinetic energy (KE): KE = (1/2) * m * v^2.
5. Since PE = KE, we can solve for the velocity (v) of the mass: 0.0025 J = (1/2) * 0.02 kg * v^2.
6. Solve for v: v^2 = (0.0025 J * 2) / 0.02 kg
v^2 = 0.25
v = √0.25 = 0.5 m/s.
The speed of the mass when the spring returns to its relaxed length of 15 cm is 0.632 m/s.
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alcohol,monosodium glutamate (vetsin), water, fruit extract,sugar, coffe powder, salt, cow's milk, cocoa powder, liquid detergent. solute or both or solvent
Answers
Answer: solute: sugar, coffee powder, salt, cocoa powder, liquid detergent, monosodium glutamate (vetsin).
solvent: cow's milk, water, fruit extract
Explanation:
A solution is a mixture that is made up of two or more substances including solute and solvent.
The solute is one which can be dissolved in a liquid part that is solvent. The solute can be liquid or solid. Solutes are sugar, salt, coffee powder, cocoa powder, liquid detergent, monosodium glutamate.
The solvent is one which dissolves in it solute particles or molecules. Solvent are cow's milk, water, and fruit extract.
The meterstick is supported so that it remains horizontal, and then it is released from rest. One second after it is released, what is the change in the angular momentum of the meterstick? A. 0 B. 500 kg.m/s C. 1000 kg.mºs D. The change in angular momentum of the meterstick cannot be determined from this information.
Answers
The change in the angular momentum of the meterstick cannot be determined from this information.
An object's angular momentum is comparable to its linear momentum, which is defined as the mass in motion, except that the item is rotating as opposed to traveling in a straight line. We can think of angular momentum as the mass in rotation.
Change in angular momentum
ΔL = L(final) - L(initial)
ΔL = Iω,
where I = moment of inertia and
ω = angular velocity.
No information can be obtained from the question about angular velocity, hence we can't calculate the change in angular momentum.
Therefore, the change in the angular momentum of the meterstick cannot be determined from this information.
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Find the induced emf, when the current in a 48.0 mH inductor increases from 0 to 535 mA in 15.5ms 2, An ac generator with an rms voltage 110 V is connected in series with a 35 Ohms resistor and 11 micro Farad capacitor, the rms current in the circuit is 1.2
Answers
The induced emf is approximately 1.66 V, and the rms current in the AC circuit is 1.2 A.
To find the induced emf in the inductor, use the formula emf = L * (ΔI/Δt), where L is the inductance, ΔI is the change in current, and Δt is the time taken. Here, L = 48 mH, ΔI = 535 mA, and Δt = 15.5 ms. Plugging in the values, we get emf ≈ 1.66 V.
For the AC circuit, we are given the rms voltage (110 V), resistance (35 Ohms), and capacitance (11 μF). The rms current is given as 1.2 A. We are not required to calculate any additional information for this part of the question, as the rms current is already provided.
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A net force of 1,377 N accelerate a car from rest to 62.07 km/h in5.717 seconds. What is the weight of the car?
Answers
Given
F: Net force
a: accelaration
v0: initial speed
vf: final speed
t: time
Data
F = 1377 N
v0 = 0 m/s
vf = 62.07 km/h
t = 5.717
Procedure
Newton's second law of motion pertains to the behavior of objects for which all existing forces are not balanced. The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object
\(F=ma\)Now let us calculate the acceleration of the vehicle. But, first we must transform the units from km/h to m/s
v0 = 0km/h = 0m/s
vf = 62.07 km/h = 17.24 m/s
\(\begin{gathered} a=\frac{v_f-v_o}{t} \\ a=\frac{17.24-0\text{ m/s}}{5.717\text{ s}} \\ a=3.015\text{ m/s}^{}^2 \end{gathered}\)Now let's calculate the mass of the car
\(\begin{gathered} m=F/a \\ m=\frac{1377N}{3.015m/s^2} \\ m=0.456\operatorname{kg} \end{gathered}\)Now to calculate the weight of the car
\(\begin{gathered} W=mg \\ W=0.456\operatorname{kg}\cdot9.8m/s^2 \\ W=4475.8N \end{gathered}\)The weight of the car is 4475.8N
(2 points) a tank contains 50 kg of salt and 2000 l of water. pure water enters a tank at the rate 10 l/min. the solution is mixed and drains from the tank at the rate 5 l/min. (a) what is the amount of salt in the tank initially? amount
Answers
The amount of salt in the tank initially is 50 kg. the amount of salt in the tank initially:
Step 1: The initial amount of salt in the tank is given to be 50 kg.
Step 2: Pure water is added to the tank at the rate of 10 l/min.
Step 3: The solution is mixed and drains from the tank at the rate of 5 l/min.
Step 4: No mention of additional salt being added to the solution is provided.
Therefore, the amount of salt in the tank remains constant at 50 kg, and it is the initial amount of salt in the tank.
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the kinetic molecular theory assumes that the particles of an ideal gas ___
Answers
Answer:
Explanation:
constant and random motioncombined negligible volume of particlescompletely elastic collisionThe force due to gravity is F = mg where g = 9.8 N/kg. Find the force due to gravity on a 41.63- kg object.
Answers
The force due to gravity on a 41.63 kg object would be 408.39 N.
What is gravity?It can be defined as the force by which a body attracts another body towards its center as the result of the gravitational pull of one body and another,
The gravity varies according to the mass and size of the body for example the force of gravity on the moon is 1/6th times the force of gravity on the earth.
As given in the problem we have to calculate the force due to gravity on a 41.63 kg object.
Force= mass ×acceleration
The acceleration due to the gravity of the earth is 9.81 m/s²
Force = 41.63 ×9.81 N
= 408.39 N
Thus, the force because of the gravity on a 41.63- kg object comes out to be 408.39 N.
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describe the motion of jays walk during part a vs part c
Answers
Motion can be defined as a change in the location (position) of a physical object or body with respect to a reference point, especially due to the action of an external force.
In Science, motion is described based on the following parameters:
TimeSpeedDistanceForceAccelerationBased on the graph that illustrates Jay's motion, we can deduce the following:
At part A, Jay's motion can be described as linear motion because it is one-dimensional and it increased along a straight line.At part B, Jay's motion can be described as a uniform motion because it increased along a straight line at a constant velocity (speed).Read more on motion here: https://brainly.com/question/26048315
A 1000 kg car is travelling at 67 mph. When it reaches a construction zone the driver brakes for 200 m until the car is travelling at 49 mph. What force did the brakes apply to the car? Assume that there are 1609 metres in one mile and give your answer to the nearest thousand. use v^2 =u^2 +(2xAxS) and F=ma
Answers
Velocity of moving vehicle=v 0, and decceleration =a and Final velocity of the vehicale =0.
What is Velocity?Once more, the stopping distance is far more than the braking distance. It starts when the threat is identified and concludes when the car stops.
The reaction distance plus the braking distance, or points 1 and 2, together make up the stopping distance.
Therefore, in order to compute the necessary stopping distance, I must determine and add two partial values (reaction distance + brake distance). The reaction time is the amount of time it takes for a driver to spot a danger before braking.
Therefore, Velocity of moving vehicle=v 0, and decceleration =a and Final velocity of the vehicale =0.
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two cups are filled to the same level with water. one of the two cups has plastic balls floating in it. if the density of the plastic balls is less than that of ice, which of the two cups weighs more?
Answers
Two cups are filled to the same level with water. one of the two cups has plastic balls floating in it. if the density of the plastic balls is less than that of ice, the two cups will; tend to weighs the same.
What is density?The mass contained in a given volume determines a material's density. Due to their tight structure and stronger intermolecular force than that of liquids and gases, solids often have denser molecules than liquids. However, compared to ice, which is a solid form of water, liquid water has a higher density.
Therefore, two cups have the same weight since the weight of the plastic ball is precisely equal to the weight of the displaced water, according to Archimedes' Principle sue to the fact that the Buoyant force need to be equal the weight of the ball.
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A 1000 kg-car rolls down a hill from rest. If the height of the hill is 200m, what is the velocity of the car at the base of the hill? (neglect any friction)
Answers
We can solve this problem using the conservation of energy principle, which states that the total mechanical energy (potential energy + kinetic energy) of a system remains constant if no external work is done on the system.
At the top of the hill, the car has only potential energy, given by:
PE = mgh
where m is the mass of the car, g is the acceleration due to gravity, and h is the height of the hill.
PE = (1000 kg) x (9.81 m/s^2) x (200 m) = 1,962,000 J
At the base of the hill, the car has only kinetic energy, given by:
KE = (1/2)mv^2
where v is the velocity of the car.
Using the conservation of energy principle, we can equate the potential energy at the top of the hill to the kinetic energy at the base of the hill:
PE = KE
mgh = (1/2)mv^2
Canceling the mass on both sides, we get:
gh = (1/2)v^2
Solving for v, we get:
v = sqrt(2gh)
Substituting the given values, we get:
v = sqrt(2 x 9.81 m/s^2 x 200 m) = 44.3 m/s
Therefore, the velocity of the car at the base of the hill is approximately 44.3 m/s.
Is this right HELP PLSSSS IF WHAT IS IT ! ! !
Answers
00000000000
The graph below shows the time and position of a motorcycle as it travels through several photogates. Calculate the velocity of the motorcycle as it moves from gate C to gate D.
Answers
C. 0.5 m/s. From the graph, the change in position within 2 seconds from gate C to gate D is 1 m. Then, the velocity of the motorcycle is 0.5 m/s. Hence, option C is correct.
What is position - time graph ?Position - time graph of an item describes the change in position with regard to time. The time is given in the x-axis, while the position is given in the y-axis. The position-time graph can be used to determine the object's velocity. The ratio of a moving object's distance travelled to its travel time is its velocity. The velocity unit is m/s. Being a vector quantity with magnitude and direction, velocity has both.
From the graph, the time taken by the motor cycle is 2 seconds. The distance travelled from C to D is 1 m (7 m to 8 m).
velocity = distance/ time
v = 1 m/ 2 s
= 0.5 m/s.
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A 2018 Tesla Model S has a horsepower of 518. How many watts of power does this car model have?
Answers
Answer:
It depends on the model but these are the watts of each motor
Explanation:
Un motor: 258 HP (262 CV) Dual motor: 154 kW (209 CV) y 197 kW (268 CV). Performance: 154 kW (209 CV) y 225 kW (306 CV).
I need Help! Can You Please Help Me?
_______ is essential for building amino acids.
(Choose One)
Nitrogen
Oxygen
Calcium
Carbon
Hydrogen
Phosphorus
Answers
Answer:
Oxygen or Hydrogen?
Explanation:
To make amino acids, fermentation tanks are filled with molasses and sugar ingredients such as sugar cane, corn and cassava. Ideal conditions are achieved for stirring, oxygen supply, temperature and pH levels. The desired amino acids are then purified from this fermented broth.
"An amino acid is an organic molecule that is made up of a basic amino group (−NH2), an acidic carboxyl group (−COOH), and an organic R group (or side chain) that is unique to each amino acid."
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What is the mathematical relationship between height, mass, gravity, and gravitational potential energy?
Answers
a) Qu'est-ce qu'une galaxie ?
Answers
Answer:
A galaxy is a gravitationally bound system of stars, stellar remnants, interstellar gas, dust, and dark matter. The word galaxy is derived from the Greek "galaxias".
Explanation: