If f(x) = |x-21, then find
ƒ(-3).

Answer:

True

Step-by-step explanation:

To determine when the total cost of each health club will be the same, we can set up an equation and solve for the number of months.

Let's assume the number of months is represented by 'x'.

For Club A, the total cost is given by:

Total cost of Club A = $13 (one-time fee) + $28x (monthly fee)

For Club B, the total cost is given by:

Total cost of Club B = $19 (one-time fee) + $27x (monthly fee)

To find the number of months when the total cost is the same, we set the two equations equal to each other:

$13 + $28x = $19 + $27x

Simplifying the equation, we get:

$28x - $27x = $19 - $13

$x = 6

Therefore, after 6 months, the total cost of each health club will be the same.

To find the total cost for each club after 6 months, we substitute the value of 'x' back into the equations:

Total cost of Club A after 6 months = $13 + $28(6) = $13 + $168 = $181

Total cost of Club B after 6 months = $19 + $27(6) = $19 + $162 = $181

So, the total cost for both Club A and Club B will be $181 after 6 months.

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The incorrect statement is:

B. The three-part inequality - 5x < 15x^2 < 3 is equivalent to - 6 ≤ 5 - x < 6.

In the given statement, there is an error in the inequality. The correct statement should be:

The three-part inequality - 5x < 15x^2 < 3 is equivalent to - 6 ≤ 5 - x and 5 - x < 6.

When solving the three-part inequality - 5x < 15x^2 < 3, we need to split it into two separate inequalities. The correct splitting should be:

- 5x < 15x^2 and 15x^2 < 3

Simplifying the first inequality:

- 5x < 15x^2

Dividing by x (assuming x ≠ 0), we need to reverse the inequality sign:

- 5 < 15x

Simplifying the second inequality:

15x^2 < 3

Dividing by 15, we get:

x^2 < 1/5

Taking the square root (assuming x ≥ 0), we have two cases:

x < 1/√5 and -x < 1/√5

Combining these inequalities, we get:

- 5 < 15x and x < 1/√5 and -x < 1/√5

Therefore, the correct statement is that the three-part inequality - 5x < 15x^2 < 3 is equivalent to - 6 ≤ 5 - x and 5 - x < 6, not - 6 ≤ 5 - x < 6 as stated in option B.

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Answer:

Yes

Step-by-step explanation:

To know if a table is a function or not, we have to see if 1 input only has 1 output.

Looking at the table each input only has 1 output, so it is a function.

Answer:

453936

que tenga un lindo día

Answer:

453936

Step-by-step explanation:

Hope this helps!

The only solution for the equation 8 tan^2 θ = 3 cos^2 θ in the given Range is θ ≈ 19.47 degrees.

a) We are given the equation 8 tan θ = 3 cos θ.

Dividing both sides of the equation by cos θ, we have:

8 tan θ / cos θ = 3

Using the identity tan θ = sin θ / cos θ, we can substitute it into the equation:

8 (sin θ / cos θ) / cos θ = 3

Simplifying further, we get:

8 sin θ / cos^2 θ = 3

Now, multiplying both sides of the equation by cos^2 θ, we have:

8 sin θ = 3 cos^2 θ

Using the identity cos^2 θ = 1 - sin^2 θ, we can substitute it into the equation:

8 sin θ = 3(1 - sin^2 θ)

Expanding the equation, we get:

8 sin θ = 3 - 3 sin^2 θ

Rearranging the terms, we have:

3 sin^2 θ + 8 sin θ - 3 = 0

Therefore, we have successfully shown that the equation can be rewritten in the form 3 sin^2 θ + 8 sin θ - 3 = 0.

b) Now, let's solve the equation 3 sin^2 θ + 8 sin θ - 3 = 0.

To solve the quadratic equation, we can use factoring, quadratic formula, or other appropriate methods.

In this case, the equation factors as:

(3 sin θ - 1)(sin θ + 3) = 0

Setting each factor equal to zero, we have two equations:

3 sin θ - 1 = 0    or    sin θ + 3 = 0

For the first equation, solving for sin θ, we get:

3 sin θ = 1

sin θ = 1/3

Taking the inverse sine (sin^-1) of both sides, we find:

θ = sin^-1(1/3) ≈ 19.47 degrees (to 2 decimal places)

For the second equation, solving for sin θ, we have:

sin θ = -3

Since the range of sine is between -1 and 1, there are no solutions for this equation in the given range (0 ≤ θ ≤ 90 degrees).

Therefore, the only solution for the equation 8 tan^2 θ = 3 cos^2 θ in the given range is θ ≈ 19.47 degrees.

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Answer:

1) 30 pounds is the weight of the bag all together

2) science book is the heaviest book

Step-by-step explanation:

bag=4 pounds

library book=2 pounds

maths book=2×4=8 pounds

science book=8×2=16 pounds

4+2+8+16=30 pounds all together

heaviest book= science book (16 pounds)

Answer:

See below.

Step-by-step explanation:

Problem 3.

1. <3, <4

Given

2. <1, <2

Given

3. KG

Congruence of segments is reflexive.

4. HKG, LKG

ASA

Problem 4.

1. MR, OR

Given

2. PR, NR

Given

3. <2

Vertical angles are congruent.

4. MPR, ONR

SAS

Answer: (5 , 1)

Step-by-Step explanation:

hihi your problem is a system of question y = x-4 and  y = -x+6 okay so  graph them both normally and then find the point where they intersect which is gonna be a coordinate point, and that's your solution !!

y = x-4
the y intersect is going to be 4
the slope is a positive 1 , going up to the right, through the positive quadrant, line is facing to the right

y = -x+6
the y intersect is going to be -6
the slope is going to be a -1 , following up the opposite way the line is going to face the left

once you graph them both you'll see the point of intersection, the solution
make sure you drew your lines very clearly !!!!

the solution is  x = 5 and y = 1 which is also (5 , 1)

hopefully this was helpful !

The slope of the lined graph is 5 / 3

The formula for determining the slope of a line is expressed as;

Slope = y2 - y1/ x2 - x1

From the graph shown;

Now, let's substitute the values

Slope, m = 4 - (-1) / 3 - 0

Find the differences

Slope, m = 4 + 1/ 3

Slope, m = 5 / 3

Thus, the slope of the lined graph is 5 / 3

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ANSWER:

The circumference is 198 cm

STEP-BY-STEP EXPLANATION:

We have the formula to calculate the circumference of the circle is the following:

we replace the value of pi and the radius:

9514 1404 393

Answer:

  e.  7x -y = -5

Step-by-step explanation:

Rearranging the first equation to general form, we have ...

  7x -2 = 0 . . . . subtract 5 from both sides

Rearranging the second equation to general form, we have ...

  y -7 = 0 . . . . . subtract 6 from both sides

Now, we can equate these expressions for 0:

  7x -2 = y -7

Subtracting y gives ...

  7x -y -2 = -7

and adding 2 gives the standard form equation ...

  7x -y = -5 . . . . matches choice E

_____

Comment on the question

Mathematically, there is no good reason to do this. It seems to be simply an exercise in manipulating equations.

Here, we subtracted the y-equation from the x-equation to get the final result. There are many other ways an expression for "0" can be used to combine these equations.

Answer:

y = 30 + 3.25c

(where y is the total cost in dollars, and c is the number of balloon bouquets)

Step-by-step explanation:

Let y = total cost (in dollars)

Let c = number of balloon bouquets

Given:

⇒ y = 30 + 3.25c

Y inetercept:-

Rate of change=3.25

So

Cost be Y

The size of the angle between AH and the plane ABCD is approximately 74.4°, rounded to one decimal place.

To find the size of the angle between AH and the plane ABCD in the given cuboid, we can use the concept of three-dimensional geometry.

First, let's consider the right triangle BCA. The given angle BCA is 48°, and we know that the length of AB is 7.3 cm. Using trigonometric functions, we can find the length of BC:

BC = AB * sin(BCA)

BC = 7.3 * sin(48°)

BC ≈ 5.429 cm

Now, let's look at the right triangle BAH. The length of AH is given as 8.1 cm. We can find the length of BH by subtracting BC from AB:

BH = AB - BC

BH ≈ 7.3 - 5.429

BH ≈ 1.871 cm

Next, let's consider the right triangle ABH. We want to find the angle BAH, which is the complement of the angle between AH and the plane ABCD. We can use the cosine function to find the angle BAH:

cos(BAH) = BH / AH

cos(BAH) ≈ 1.871 / 8.1

BAH ≈ arccos(1.871 / 8.1)

BAH ≈ 74.4°

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Answer:

sin I = \(\frac{80}{89}\)

Step-by-step explanation:

sin I = \(\frac{opposite}{hypotenuse}\) = \(\frac{KJ}{JI}\) = \(\frac{80}{89}\)

Answer:

A

Step-by-step explanation:

3 4 5 6

The sample mean weight, from this random sample of 135 pigs, fall within the confidence interval. (Option A: yes)

Suppose that we have:

Then the confidence interval is obtained as

\(\overline{x} \pm Z_{\alpha /2}\dfrac{\sigma}{\sqrt{n}}\)

\(\overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}\)

For this case, we work with sample standard deviation(you can choose even population standard deviation, it won't matter as both are not given here).

We're provided that:

Since the formula for limits of confidence interval is:

\(\overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}} = \overline{x} \pm 1.645\dfrac{s}{\sqrt{135}}\)

That has:

\(\text{Lower limit} = 75 = \overline{x} - 1.645\dfrac{s}{\sqrt{135}}\\\\\text{Upper limit} = 90 = \overline{x} +1.645\dfrac{s}{\sqrt{135}}\\\\\)

Thus, we get:

Adding both the equations, we get:

\(165 = 2\overline{x}\\\\\overline{x} = 82.5 \: \rm pounds\)

That is between 75 and 90 pounds.

Thus, the sample mean weight, from this random sample of 135 pigs, fall within the confidence interval. (Option A: yes)

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Answer:

see below

Step-by-step explanation:

Clerk is wrong at step two. It should be...

To calculate the sales tax take 9.5% and divide by 100 which is 0.095. The tax is 0.095(39.90) = 3.79

Cost of items + Tax = Total cost

Cost of items + .095(cost of items) = Total cost

39.90 + 3.79 = 43.69

Answer:

19cm

Step-by-step explanation:

(chose one way)

1. way using commutativity

(3cm+4cm)+(10cm+2cm)=7cm+12cm=19cm

2. way just writing

3cm+4cm+10cm+2cm=19cm

at x = 1 we have one tangent line and at x = 5 we have just another tangent line.

\(f(x)=3x^2-15x\implies \left. \cfrac{df}{dx}=6x-15 \right|_{x=1}\implies \stackrel{\stackrel{m}{\downarrow }}{-9}~\hfill \left. 6x-15\cfrac{}{} \right|_{x=5}\implies \stackrel{\stackrel{m}{\downarrow }}{15}\)

so we have the slopes, but what about the coordinates?

well, for the first one we know x = 1 and we also know f(x), let's use f(1) to get "y", and likewise we'll do the for the second one.

\(\stackrel{x=1}{f(1)}=3(1)^2-15(1)\implies f(1)=-12\qquad \qquad (\stackrel{x_1}{1}~~,~~\stackrel{y_1}{-12}) \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-12)}=\stackrel{m}{-9}(x-\stackrel{x_1}{1}) \\\\\\ y+12=-9x+9\implies y=-9x-3 \\\\[-0.35em] ~\dotfill\)

\(\stackrel{x=5}{f(5)}=3(5)^2-15(5)\implies f(5)=0\qquad (\stackrel{x_1}{5}~~,~~\stackrel{y_1}{0}) \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{15}(x-\stackrel{x_1}{5})\implies y=15x-75\)

Answer:

p = 18

Step-by-step explanation:

Let's solve your equation step-by-step.

−2(8p+2)−3(2−7p)=2(4+2p)

Step 1: Simplify both sides of the equation.

−2(8p+2)−3(2−7p)=2(4+2p)

(−2)(8p)+(−2)(2)+(−3)(2)+(−3)(−7p)=(2)(4)+(2)(2p)(Distribute)

−16p+−4+−6+21p=8+4p

(−16p+21p)+(−4+−6)=4p+8(Combine Like Terms)

5p+−10=4p+8

5p−10=4p+8

Step 2: Subtract 4p from both sides.

5p−10−4p=4p+8−4p

p−10=8

Step 3: Add 10 to both sides.

p−10+10=8+10

p=18

Therefore, the final answer is 18, I hope this helps :D

Answer:

p=18

Step-by-step explanation:

See image below:)

Answer:

f ( x+2) – f(2) = x² + x

Step-by-step explanation:

f(x) = x² – 3x+4

f(x+2) = (x+2)² – 3 (x+2) +4

= ( x²+ 4x + 4) – 3x – 6 +4

= x² + 4x +4 – 3x – 6 + 4

= x² + x +2

f(x) = x² – 3x+4

f(2) = 2² – 3(2) +4 = 4 – 6 + 4 = 2

f ( x+2) – f(2) = (x² +x +2 ) – (2)

= x² + x +2 – 2

= x² + x

I hope I helped you^_^

Answer:

LxWxH

Step-by-step explanation:

The linear function that gives the monthly cost E for x > 300 is given by:

E(x) = 44 + 0.04x.

A linear function is modeled by:

y = mx + b

In which:

When x > 300, we have that:

Hence the intercept is given by:

b = 8 + 0.12 x 300 = 44.

The slope is the cost per kWh of 4 cents, hence the function is:

E(x) = 44 + 0.04x.

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Answer:

(-5,-2)

Step-by-step explanation:

To find the mid-point the formula is;

\((x_1+x_2)/2 ,(y_1+y_2)/2\)

In this case point A (3,-8) , mid-point (-1,-5), point B (x,y)

Thus (3+x)/2 = -1  

        3+x=-2

            x= -2-3 = -5

And

      ( -8+y)/2 = -5

      -8 + y = -5*2

       -8 +y = -10

             y= -10 +8 = -2

Hence point B coordinates are: (-5, -2)

Answer:

a) 0.8088 = 80.88% probability that there are at most 2 typos on a page.

b) 0.0858 = 8.58% probability that there are exactly 10 typos in a 5-page paper.

c) 0.001 = 0.1% probability that there are exactly 2 typos on each page in a 5-page paper.

d) 0.717 = 71.7% probability that there is at least one page with no typos in a 5-page paper.

e) 0.2334 = 23.34% probability that there are exactly two pages with no typos in a 5-page paper.

Step-by-step explanation:

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

\(P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}\)

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\(\mu\) is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)

In which \(C_{n,x}\) is the number of different combinations of x objects from a set of n elements, given by the following formula.

\(C_{n,x} = \frac{n!}{x!(n-x)!}\)

And p is the probability of X happening.

The number of typos made by a student follows Poisson distribution with the rate of 1.5 typos per page.

This means that \(\mu = 1.5n\), in which n is the number of pages.

(a) Find the probability that there are at most 2 typos on a page.

One page, which means that \(\mu = 1.5\)

This is

\(P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)\)

In which

\(P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}\)

\(P(X = 0) = \frac{e^{-1.5}*(1.5)^{0}}{(0)!} = 0.2231\)

\(P(X = 1) = \frac{e^{-1.5}*(1.5)^{1}}{(1)!} = 0.3347\)

\(P(X = 2) = \frac{e^{-1.5}*(1.5)^{2}}{(2)!} = 0.2510\)

\(P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2231 + 0.3347 + 0.2510 = 0.8088\)

0.8088 = 80.88% probability that there are at most 2 typos on a page.

(b) Find the probability that there are exactly 10 typos in a 5-page paper.

5 pages, which means that \(n = 5, \mu = 5(1.5) = 7.5\).

This is P(X = 10). So

\(P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}\)

\(P(X = 10) = \frac{e^{-7.5}*(7.5)^{10}}{(10)!} = 0.0858\)

0.0858 = 8.58% probability that there are exactly 10 typos in a 5-page paper.

(c) Find the probability that there are exactly 2 typos on each page in a 5-page paper.

Two typos on a page: 0.2510 probability.

Two typos on each of the 5 pages: (0.251)^5 = 0.001

0.001 = 0.1% probability that there are exactly 2 typos on each page in a 5-page paper.

(d) Find the probability that there is at least one page with no typos in a 5-page paper.

0.2231 probability that a page has no typo, so 1 - 0.2231 = 0.7769 probability that there is at least one typo in a page.

(0.7769)^5 = 0.283 probability that every page has at least one typo.

1 - 0.283 = 0.717 probability that there is at least one page with no typos in a 5-page paper.

(e) Find the probability that there are exactly two pages with no typos in a 5-page paper.

Here, we use the binomial distribution.

0.2231 probability that a page has no typo, so \(p = 0.02231\)

5 pages, so \(n = 5\)

We want P(X = 2). So

\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)

\(P(X = 2) = C_{5,2}.(0.2231)^{2}.(0.7769)^{3} = 0.2334\)

0.2334 = 23.34% probability that there are exactly two pages with no typos in a 5-page paper.

Answer:

4 hours

Step-by-step explanation:

f the circumference of the circular garden =63 yards

Circumference of a Circle =2πr=πd (d=diameter)

Therefore:

πd= 63

diameter of the circular garden =63/3.14=20 yards

If he digs at a rate of 5 yards per hour, the time required to dig across the garden will be:

20 yards/5 yard per hours = 4 hours

It will take him 4 hours to dig across the circular garden.