If equal masses of O2 and N2 are placed in separate containers of equal volume at the same temperature, which of the following statements is true? If false, explain why it is false.
(a) The pressure in the flask containing N2 is greater than that in the flask containing O2
(b) There are more molecules in the flask containing O2 than in the flask containing N2

I believe it is to speed up chemical reactions

Answer:

My basis in choosing situation to make your work done is when theres a force applied to an object to make it done, once you move a one thing and you should apply a force , it will called work ,,

Explanation:

The grams of iburofen does such a tablet contain 800 mg =   0.8g Ibuprofen

1 g = 10^-3g = .001g

Ibuprofen has  800 mg doses in over-the-counter analgesic

800g = 800 × .001

        = 0.8g

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There are various kind of elements that are present in periodic table. Some elements are harmful, some are radioactive, some are noble gases. Therefore, Strontium belongs to group 2, alkaline earth metal family of the periodic table.

Periodic table is a table in which we find elements with properties like metals, non metals, metalloids and radioactive element arranges in increasing atomic number.

Periodic table help a scientist to know what are the different types of elements are present in periodic table so that they can discover the new elements that are not being discovered yet.

Strontium is the element having 38 protons and 50 neutrons.

mass number= proton number + neutron number

                      =38+ 50

                     =88

Group number of this element is group 2. Strontium belongs to akaline earth metal family.

Therefore, Strontium belongs to group 2, alkaline earth metal family of the periodic table.

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Answer:

The answer is a

The value of ΔG at 25 °C for the given reaction is: ΔG = -370.4 kJ/mol + 0 = -370.4 kJ/mol So, the correct answer is -370.4 kJ/mol

To determine the value of ΔG (Gibbs free energy) at 25 °C for the given reaction:

25 (s, rhombic) + 3/2 \(O_2\)(g) → \(2SO_3\)(g)

We can use the equation:

ΔG = ΔG° + RT ln(Q)

where:

ΔG is the standard Gibbs free energy change

ΔG° is the standard Gibbs free energy change under standard conditions

R is the gas constant (8.314 J/(mol·K) or 0.008314 kJ/(mol·K))

T is the temperature in Kelvin (25 °C = 298 K)

Q is the reaction quotient, which is the ratio of the concentrations of the products to the concentrations of the reactants at a given point during the reaction.

Given that ΔG° is -370.4 kJ/mol, we can plug the values into the equation:

ΔG = -370.4 kJ/mol + (0.008314 kJ/(mol·K) * 298 K) * ln(Q)

Now, we need to determine the value of Q. Since all reactants and products are in their standard states, Q = 1, as their concentrations are taken to be 1.

ΔG = -370.4 kJ/mol + (0.008314 kJ/(mol·K) * 298 K) * ln(1)

Since ln(1) = 0, the term (0.008314 kJ/(mol·K) * 298 K) * ln(1) becomes 0.

Therefore, the value of ΔG at 25 °C for the given reaction is:

ΔG = -370.4 kJ/mol + 0 = -370.4 kJ/mol

So, the correct answer is -370.4 kJ/mol.

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The vessel's internal pressure is atm, is  \(6.66*10^{-6} atm\)

A vacuum pump is a machine that expels air or gas from a sealed space in order to create a partial vacuum and a difference in pressure. Based on the pressure needs and the application it serves, vacuum pumps are designed using a range of technologies.Fatal accidents have happened in the history of pressure vessel invention and use, proving that pressure vessels can be harmful.A container designed to carry gases or liquids at a pressure much higher than atmospheric pressure is known as a pressure vessel.

The pressure in the vessel in atm is \(6.66 * 10^{-6} atm\).

To calculate this, we first convert \(5.0 * 10^{-3} mmHg\) to atm.

1 mmHg = 0.001315789 atm

Here, \(5.0 * 10^{-3} mmHg = 6.66 * 10^{-6} atm.\)

Therefore, the pressure in the vessel in atm is \(6.66*10^{-6} atm\)

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Answer:

So trees in temperate don't lose their leaves because the weather events aren't harsh enough.

Trees in tropical rainforest don't lose their leaves because they are a different type of tree known as evergreens that are green all year round.

Explanation:

Ok so first we'll define some things

Deciduous Trees=  Trees that lose all of their leaves for part of the year.

Trees shed their leaves trees to try and survive harsh weather events.

Temperate deciduous trees lose their leaves in fall to better survive the winter conditions of extreme cold and reduced daylight.

Temperate rainforests = An area that doesn't experience extremely cold or extremely hot temperatures or what we would call harsh weather events.

Broad-leaved trees in tropical rainforests are known evergreen, they are known as this as they are green all year round.

Thus, the total pressure is 0.184 atm.

What is Pressure?

The amount of pressure exerted (thrust) on a floor in line with unit place is described as ‘pressure’. It can also be defined as the ratio of the force to the place (over which the pressure is performing).

The force applied perpendicular to the surface of an object in step with unit vicinity over which that force is sent.

PV=nRT is the ideal gas equation.

Where P denotes pressure, V denotes volume, n is the number of moles, R denotes the gas constant, and T denotes temperature.

As a result, the temperature of the  sample will only be doubled, with the same volume and number of moles. Because temperature and pressure are inextricably linked, if one rises, the other must rise as well, resulting in a pressure of 0.092 atm.

The following are the steps in the breakdown process: Decomposition reaction:  ⇄  +

As a result, 1 mole of   produces 2 moles of products (1 of each), and n doubles. The pressure will double to 0.184 atm since the volume and temperature are now constants, and the pressure is directly proportional to the number of moles.

Thus, the total pressure is 0.184 atm.

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The temperature increase from 20 °C to 46 °C indicates that the reaction between zinc and copper sulfate solution is exothermic, with heat being released into the surroundings.

In the given reaction between zinc and copper sulfate solution, the temperature change can provide insights into the type of heat change occurring during the reaction. Based on the provided information, the initial temperature of the copper sulfate solution was 20 °C, and the final temperature of the mixture after the reaction was 46 °C.

The temperature increase observed in this reaction indicates an exothermic heat change. An exothermic reaction releases heat energy into the surroundings, resulting in a temperature rise. In this case, the reaction between zinc and copper sulfate solution is exothermic because the final temperature is higher than the initial temperature.

During the reaction, zinc displaces copper from copper sulfate to form zinc sulfate and copper metal. This displacement reaction is known as a single displacement or redox reaction. Zinc is more reactive than copper and therefore replaces copper in the compound.

The formation of new chemical bonds during the reaction releases energy in the form of heat. This energy is transferred to the surroundings, leading to an increase in temperature. The heat released is greater than the heat absorbed, resulting in a net increase in temperature.

The exothermic nature of this reaction can be explained by the difference in bond energies between the reactants and products. The breaking of bonds in the reactants requires energy input, while the formation of new bonds in the products releases energy.

In this case, the energy released during the formation of zinc sulfate and copper metal is greater than the energy required to break the bonds in copper sulfate and zinc.

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Systematic name : 5-chloro-2-pentanol (or 5-chloropentan-2-ol)

Systematic name : 1,2-difluoro-3-heptanol   (or 1,2-difluoroheptan-3-ol).

The active site of numerous reactions is the hydroxyl group (OH). Pentyl butyrate, which has an apricot-like aroma, is the ester that results from the reaction of 1-pentanol and butyric acid. Amyl acetate, also known as pentyl acetate, is the ester that is created when 1-pentanol and acetic acid are combined.

A research evaluating the efficacy of diesel fuel blends with different amounts of pentanol as an additive was done in 2014. Higher pentanol concentrations resulted in higher gaseous emissions at the expense of lower particulate emissions.

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We can see here that the catalytic cycle for the hydrogenation of alkenes using Wilkinson's catalyst involves several steps.

Here's an overview of the catalytic cycle, including the necessary details:

i. Chemical structure of the catalyst:

Wilkinson's catalyst, also known as chloridotris(triphenylphosphine)rhodium(I), has the following chemical structure: [RhCl(PPh3)3]

ii. Molecular geometry of the catalyst:

The Wilkinson's catalyst has a trigonal bipyramidal geometry around the rhodium center. The three triphenylphosphine (PPh3) ligands occupy equatorial positions, while the chloride (Cl) ligand occupies an axial position.

iii. Type of reactions involved:

The catalytic cycle involves several reactions, including:

iv. Starting material, reagent, and solvent:

The starting material is an alkene, and the reagent is Wilkinson's catalyst ([RhCl(PPh3)3]). The reaction is typically carried out in a suitable solvent, such as dichloromethane (CH2Cl2) or tetrahydrofuran (THF).

v. Major and minor end-products:

The major end-product of the hydrogenation reaction is the fully saturated alkane, resulting from the addition of hydrogen across the double bond. The minor end-product may include cis- or trans-configured alkanes if the original alkene substrate possesses geometric isomers.

vi. Intermediates:

The intermediates in the catalytic cycle include:

These intermediates play a crucial role in facilitating the hydrogenation reaction and enabling the catalytic cycle to proceed.

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Answer:

A heterotroph is an organism that eats other plants or animals for energy and nutrients. The term stems from the Greek words hetero for “other” and trophe for “nourishment.”

Answer:

If the forward reaction is endothermic,

The equilibrium position will shift right, and the equilibrium constant Kc will increase.

Increasing the temperature (heating) for a reaction will increase the rates of both the forward and backward reactions, but it will increase the rate of endothermic reaction to a greater extent.

Since the forward reaction is endothermic, heating will cause the rate of forward reaction higher than that of the backward reaction, meaning more CO2 will be formed. The equilibrium position thus shifts right.

As more CO2 is formed, its concentration increases. Hence, the equilibrium constant also increases.

Answer:

\(\boxed {\boxed {\sf Almost \ all \ phosphates \ are \ insoluble}}\)

Explanation:

For magnesium phosphate to make an aqueous solution, it must be soluble in water.

Let's check the solubility rules. There are many different lists and versions, but it should mention a rule about phosphates.

Magnesium phosphate is included in "all phosphates" so it is insoluble and can't become an aqueous solution.

Magnesium Phosphate (Mg₃(PO₄)₂) would not make an aqueous solution because it is insoluble in water.

A solution is a homogeneous mixture of one or more solutes dissolved in a solvent.

According to the solubility rule, all phosphates are insoluble in water except sodium and potassium phosphates and thus magnesium phosphate does not form an aqueous.

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Answer:

Theoretical Yield of SF₆ = 2.01 moles

Explanation: If you understand and can apply the methodology below, you will find it applies to ALL chemical reaction stoichiometry problems based on the balanced standard equation; i.e., balanced to smallest whole number coefficients.

Solution 1:

Rule => Convert given mass values to moles, solve problem using coefficient ratios. Finish by converting moles to the objective dimensions.

Given      S₈            +          24F₂            =>    8SF₆

             425g                    229g                      ?

= 425g/256g/mol.      = 226g/38g/mol.

= 1.66 moles S₈          = 6.03 moles F₂ <= Limiting Reactant

Determining Limiting Reactant => Divide moles each reactant by their respective coefficient; the smaller value will always be the limiting reactant.

S₈ = 1.66/1 = 1.66

F₂ = 6.03/24 = 0.25 => F₂ is the limiting reactant

Determining Theoretical Yield:

Note: When working problem do not use the division ratio results for determining limiting reactant. Use the moles F₂ calculated from 229 grams F₂ => 6.03 moles F₂. The division procedure to define the smaller value and limiting reactant is just a quick way to find which reactant controls the extent of reaction.  

Given      S₈            +          24F₂            =>    8SF₆

             425g                    229g                      ?

   = 425g/256g/mol. = 226g/38g/mol.

= 1.66 moles S₈          = 6.03 moles F₂ <= Limiting Reactant

Max #moles SF₆ produced from 6.03 moles F₂ and an excess S₈

Since coefficient values represent moles, the reaction ratio for the above reaction is 24 moles F₂ to 8 moles SF₆. Such implies that the moles of SF₆ (theoretical) calculated from 6.03 moles of F₂ must be a number less than the 6.03 moles F₂ given. This can be calculated by using a ratio of equation coefficients between 24F₂ and 8SF₆  to make the outcome smaller than 6.03. That is,

moles SF₆ = 8/24 x 6.03 moles = 2.01 moles SF₆ (=> theoretical yield)  

S₈ + 24F₂ => 8SF₆

moles SF₆ = 8/24(6.03) moles = 2.01 moles

You would NOT want to use 24/8(6.03) = 18.1 moles which is a value >> 6.03.        

This analysis works for all reaction stoichiometry problems.

Convert to moles => divide by coefficients for LR => solve by mole mole ratios from balanced reaction and moles of given.    

____________________

Here's another example just for grins ...

             C₂H₆O   +   3O₂     =>     2CO₂    + 3H₂O

Given:    253g          307g               ?               ?

a. Determine Limiting Reactant

b. Determine mass in grams of CO₂ & H₂O produced        

Limiting Reactant

moles  C₂H₆O = 253g/46g/mol = 5.5 moles  => 5.5/1 = 5.5

moles  O₂ = 307g/32g/mol = 9.6 moles         =>  9.6/24 = 0.4 ∴ O₂ is L.R.

But the problem is worked using the mole values; NOT the number results used to ID the limiting reactant.  

 C₂H₆O   +       3O₂          =>     2CO₂    + 3H₂O

------------ 9.6 mole (L.R.)              ?               ?

mole yield CO₂ = 2/3(9.6)mole = 6.4 mole  (CO₂ coefficient < O₂ coefficient)

mole yield H₂O = 9.6mole  = 9.6mole (coefficients O₂ & CO₂ are same.)

mole used C₂H₆O = 1/3(9.6)mole = 3.2 mole (coefficient  C₂H₆O < coefficient O₂)

For grams => moles x formula weight (g/mole)

Answer:

The answer is

Plant also use cellular respiration

Answer:

B - Plants also use cellular respiration.

Explanation:

Did the test.

Answer: 11.1 L.

Explanation: A balloon filled with helium gas at 1.00 atm occupies 11.1 L.

Consider the gas is taken at STP. Thus at standard temperature and pressure of 1 atm where one mole of any gas contains 22.41 L. Thus helium gas at 1 atm pressure contains 22.414 L/mol

Helium is 2nd element in periodic table. It is a noble gas ncluded in the 18th group. Helium is the second most abundant element in the universe. Stars including sun is made of helium gas and hydrogen gas.

The condition at which the temperature is 298 K and pressure of 1 atm is called standard temperature and pressure or STP condition. At STP one mole pf every substance contains 22.414 liter of the gas.This is called molar volume.

Therefore, the volume of helium gas at 1 atm pressure by considering the condition of STP and the gas if taken is one moles will be 22.414 liter. This is the volume of one mole of all gas at stp.

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These substances have dispersed particles that are large enough to scatter light, making the beam visible. Therefore, out of the options provided, a mixture that scatters light is an example of a colloid. Option B)

A colloid is a type of mixture in which particles are dispersed throughout a medium, creating a homogeneous appearance. Unlike solutions, where the particles are completely dissolved, and suspensions, where the particles settle out, colloids have particles that are larger than those in solutions but smaller than those in suspensions. One characteristic of colloids is that they can scatter light due to the size of the particles. This scattering of light is known as the Tyndall effect. Examples of colloids include milk, fog, and aerosol sprays. These substances have dispersed particles that are large enough to scatter light, making the beam visible. Therefore, out of the options provided, a mixture that scatters light is an example of a colloid. Therefore option B) is correct

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Note Complete Question

which is an example of a colloid?

a mixture that settles out,

b mixture that scatters light,

c mixture that is separated by filtration,  

d salt and water mixture?

Answer: A) Cold ice makes the liquid condense

On the flip side, warm temperatures make the liquid expand. Since there is only one direction to go, the liquid expands upward until it reaches a certain marker on the thermometer, to indicate the temperature.

Answer:

Condensation reaction/ direct synthesis reaction

Explanation:

Combines simple molecules to form complex molecules producing water

Word equation: sulfuric acid + sulfur -> sulfur dioxide + water

Chemical equation: H2SO4 + S -> SO2 + H2O

Answer:

Word equation: Sulfuric acid + Sulfur → Sulfur Dioxide + Water

Chemical equation: H2SO4 + S → SO2 + H2O

Explanation:

The mass concentration of sand in the ethanol solution is 0.299 g/dm³.

To find the concentration in grams per cubic decimeter (g/dm³), we first need to convert the volume from liters to cubic decimeters (dm³). Since 1 liter is equal to 1 cubic decimeter, we can directly convert the volume.

Given:

Mass of sand = 0.2 g

Volume of ethanol = two-thirds liter

Converting volume to dm³:

1 liter = 1 cubic decimeter

two-thirds liter = (2/3) cubic decimeter = 0.67 dm³ (rounded to two decimal places)

Now we can calculate the concentration in g/dm³ by dividing the mass of sand by the volume in dm³:

Concentration = Mass / Volume

Concentration = 0.2 g / 0.67 dm³

Concentration ≈ 0.299 g/dm³ (rounded to three decimal places)

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The correct option is 2.

A 88

B 94

C 100

To solve this problem, we need to use our knowledge of how streams flow and how velocity changes in different parts of the stream.

Typically, streams flow fastest in the center of the channel and slowest along the edges, due to friction with the banks and bottom of the stream.

Given that it lies in the middle of the stream's two extreme velocities, option 2, which equals 94, is probably the right response. The velocity near the channel's middle is probably closer to 100 because the stream runs there the quickest.

On the other hand, it is likely that the velocity near the edges is closer to 88 since the stream runs more slowly along the edges due to friction with the banks and streambed. Consequently, a velocity of 94 is the most logical choice because it is within the range that is  predicted by the velocity distribution of a stream.

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An impact of the specific heat of the water on the planet is that islands and coastal places have moderately pleasant climates. Therefore, option A is correct.

The specific heat of water is relatively high compared to other substances. This means that water requires a significant amount of heat energy to increase its temperature. As a result, water has a stabilizing effect on the climate of coastal and island regions.

The high specific heat of the water helps to moderate temperature changes, resulting in milder and more pleasant climates in these areas.

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Answer:

Molar mass of MgCl2 is 95 g/mol

Mg = 24 g/mol and Cl = 35.5 ×2 = 71 g/mol

moles = mass given/ molar mass

= 2.7/95 = 0.028 mol

volume = 250/1000 = 0.25 dm3 (ml is the same as dm3)

molarity of MgCl2 = moles/volume

= 0.028/0.25

= 0.112 mol/dm3

Answer:

167.217g/mol

Explanation:

Formula mass is defined as the mass in grams that a mole of a molecule weighs. To solve the formula mass of ZrF₄ we require the molar mass of Zr and of F (Molar mass Zr: 91.225g/mol; F: 18.998g/mol)

In this molecule, there is 1 mole of Zr and 4 moles of F. The formula mass is:

Zr = 1*91.225g/mol = 91.225g/mol

F = 4*18.998g/mol = 75.992g/mol

Formula mass: 91.225g/mol + 75.992g/mol

\(= 5 * 10^{13} * 0.056169 = 0.2808 * 10^{13}\)The ratio of  [Ag+] to [Ag(S₂O₃)₂³⁻] in a bath to which [S₂O₃²⁻] = 0.0237 M is 3.56 x 10⁻¹³.

In processing black and white photographic film, excess silver(I) halides are removed with sodium thiosulfate.

The reaction for this treatment based on complexation is:

Ag+(aq) + 2S₂O₃²⁻(aq) ⇒ Ag(S₂O₃)₂³⁻(aq)

For this reaction:

\(K_{f} = \frac{[Ag(S_{2}O_{3})_{2}^{3-}]}{[Ag^{+}] [S_{2}O_{3}^{2-}]^{2}}\) = \(5 * 10^{13}\)

Given that, [S₂O₃²⁻] = 0.237 M

We can deduce that:

\(K_{f} = \frac{[Ag(S_{2}O_{3})_{2}^{3-}]}{[Ag^{+}] [0.237]^{2}}\) = \(5 * 10^{13}\)

Therefore

\(\frac{[Ag(S_{2}O_{3})_{2}^{3-}]}{[Ag^{+}]}\)  \(= 5 * 10^{13} * 0.056169 = 0.2808 * 10^{13}\)

The equation becomes:

\(\frac{[Ag^{+}]}{[Ag(S_{2}O_{3})_{2}^{3-}]}\) = \(\frac{1}{0.2808 * 10^{13} }\) = \(3.56 * 10^{-13}\)

The ratio for [Ag+] to [Ag(S₂O₃)₂³⁻] is 3.56 x 10⁻¹³

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