The maximum weight possible for the flowerpot that the cords can support can be calculated by adding the maximum tension that each cord can hold before it fails. Since each cord can hold no more than 50 N in tension before it fails, the maximum weight possible for the flowerpot that the cords can support is:
Maximum weight = 50 N + 50 N + 50 N + 50 N = 200 N
Therefore, the maximum weight possible for the flowerpot that the cords can support is 200 N.
It is important to note that the maximum weight possible for the flowerpot is dependent on the number of cords that are used to support it. If there are more cords, the maximum weight possible for the flowerpot will be greater. Conversely, if there are fewer cords, the maximum weight possible for the flowerpot will be less.
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Each external force acts on the system for 10 seconds. Rank the change in momentum of each of the cart-cart systems from largest to smallest. (The label of “m” or “2 m” desginates the relative mass of each cart.)
It is possible to have some of the categories below BLANK since you may have items that are EQUAL to each other.
Put the largest as far up as you can, and the smallest as far down as you can
Answer:
thanks me later
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If a force is exerted on an object, which statement is true?
A. A large force always produces a large change in the object’s momentum.
B. A large force produces a large change in the object’s momentum only if the force is applied over a very short time interval
C. A small force applied over a long-time interval can produce a large change in the object’s momentum
D. A small force produces a large change in an object’s momentum.
Answer:
B. A large force produces a large change in the object’s momentum only if the force is applied over a very short time interval.
Explanation:
This statement aligns with Newton's second law of motion, which states that the change in momentum of an object is directly proportional to the force applied and occurs in the direction of the force, and is inversely proportional to the time over which the force is applied. Therefore, a large force applied over a very short time interval can result in a large change in the object's momentum, while a small force applied over a long time interval may not produce a significant change in the object's momentum.
47. explain why the abundances of heavy elements in stars correlate with their positions in the galaxy.
The presence of heavy elements in stars correlates with their positions because these elements show which star formed first, and a star's brightness and spectral type show where it is in the galaxy.
Heavy elements are present in population I stars. It is concentrated in the discs of spiral galaxies and typically contains the sun. It is also hot, youthful, and brilliant. The majority of them are found in spiral arms. In globular clusters and the outer galactic halo, where the concentration of heavy elements is relatively low, population II stars are born. The important information to compare the locations of the stars is therefore their abundances of heavy metals. Energy must be added in order for elements heavier than iron and nickel to develop.
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A box of mass 20 kg has a base of area 4 m2
. Calculate the pressure exerted by it on the ground. (Use 1
kg-f = 10 N)
\(\huge \bf༆ Answer ༄\)
First, find the force exerted by the box.
\( \sf \: F = ma \)
The required terms are :
m = mass = 20 kga = Acceleration due to gravity = 10 m/s²Calculate the force : -
\( \sf \: F = 20 \times 10 \)\( \sf \: F = 200 \: N\)_____________________________________
Pressure can be calculated using this formula : -
\( \sf \: P = \dfrac {F }{A }\)The stated terms are :
P = pressure F = force = 200 NA = Area = 4 m²Calculate the Pressure now : -
\( \sf \: P = \dfrac{200}{4} \)\( \sf \: P = 50 \: pascals\)\(꧁ \: \large \frak{Eternal \: Being } \: ꧂\)
a spherical cavity is hollowed out of the interior of a neutral conducting sphere. at the center of the cavity is a point charge, of positive charge q.
Only the charge present inside the cavity can explain the electric field that exists there. The electric field inside the hollow would remain unchanged as a result.
Each point in space has an electric field associated with it when there is charge present in any form. E, often known as electric field strength, electric field intensity, or just the electric field, is a mathematical constant that expresses the strength and direction of an electric field. To predict what would happen to electric charges nearby a specific point, one only needs to be aware of the value of the electric field there, without having any precise knowledge of what generated the field.
When one charge is thought of as the generator of an electric field that spreads outward into the surrounding space, the electric force is not thought of as a direct interaction of two electric charges that are separated from one another.
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marble roller coaster lab report
A lab report on a scientific experiment in which students construct a roller coaster lab report for a tiny marble is called a "Marble Roller Coaster."
The experiment's goal is to comprehend physics concepts like potential and kinetic energy, friction, and gravity. The goal of the lab report, materials utilised, steps taken, data gathered, and findings achieved are often covered in parts of the report. A lab report on a scientific experiment in which students construct a roller coaster for a tiny marble is called a "Marble Roller Coaster." The discussion of the findings, in which the students analyse the information and make inferences about the experiment, is also included in the report. The study could potentially include suggestions for enhancing the roller coaster's design in the future.
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what is marble roller coaster lab report?
If a member of the LGBTQ community wears pink clothing and displays triangles and images of a rainbow, they are exemplifying what communication practice?
Answer:
The correct answer is - separation.
Explanation:
Communication practice is the ability to the explaining or showing emotions in various ways such as reading, talking, expressing, performing, writing, and witnessing or showing signs.
Separation is an example of communication practice with that in this case LGBTQ community showing their expression that they exist and different from others by displaying rainbows and wearing pink clothing.
Thus, the correct answer is - separation.
A thin nonconducting rod with a uniform distribution of positive charge Q is bent into a circle of radius R. The central perpendicular axis through the ring is a z-axis, with the origin at the center of the ring.
(a) What is the magnitude of the electric field due to the rod at z = 0? N/C
(b) What is the magnitude of the electric field due to the rod at z = infinity? N/C
(c) In terms of R, at what positive value of z is that magnitude maximum? R
(d) If R = 4.00 cm and Q = 9.00 �C, what is the maximum magnitude?N/C
Answer:
a) E_{z} = 0, b) E_{z} = 0, c) z = 1.73 [1 + \(\sqrt{1 - \frac{4R^2}{3} }\)], d) \(E_{max}\)Emax = 9.7 10¹⁰ N / C
Explanation:
For this exercise we use the expression
E = k ∫ dq / r²
By applying this expression to our problem of a ring of radius R, with a perpendicular axis in the z direction, we can calculate the electric field for a small charge element
dE = k dq / r²
In the attachment we can see a diagram of the electric field, it is observed that the fields perpendicular to the z axis cancel and the field remains in the direction of the axis
d\(E_{z}\)= dE cos φ
we substitute
E_{z} = k∫ \(\frac{dq}{r^2}\) cos φ
let's write the expressions
r² = R² + z²
cos φ = z / r
we substitute in the integral, where we see that the load differential does not depend on the distance and the value of the total load is + Q
E_{z} = k \(\frac{1}{ (R^2 +z^2) } \ \frac{z}{ (R^2 + z^2)^{1/2} }\) ∫ dq
E_{z} = k Q \(\frac{z}{ (R2+z^2)^{3/2} }\)
This is the expression for the electric field in the axis perpendicular to the ring, we analyze this expression to answer the questions
a) the magnitude of the field at z = 0
E_{z} = 0
b) the magnitude of the field for z = inf
when z »R the expression remains
E_{z} = k \(\frac{z}{z^{3} }\) Q
E_{z} = k Q \(\frac{1}{z^2}\)
therefore when the value of z = int the field goes to E_{z} = 0
c) In value of z for which the field is maximum.
We have an extreme point when the first derivative is equal to zero
\(\frac{dE_z}{dz } = k Q [ (R^2 +z^2)^{3/2} - z \ 3 \frac{z}{ (R^2 +z^2)^{1/2} } = 0\)
we solve
(R² + z²)^{ 3/2} = 3 z² /(R² +z²) ^{1/2}
(R² + z²)² = 3z²
r² + z² = √3 z
z² –1.732 z + R² = 0
we solve the quadratic equation
z = [1.732 ± \(\sqrt{3 - 4R^2}\)]/ 2 = [1.73 ± 1.73 \(\sqrt{ 1 - \frac{4 R^2}{3} }\) ] / 2
z = 0.865 [1 ± \(\sqrt{1 - \frac{4R^2}{3} }\)]
Therefore there are two points where the field has an extreme point one, one is a maximum and the other a minimum, as we have already determined a minimum at z = 0 the maximum point must be
z = 0.865 [1 + \(\sqrt{1 - \frac{4R^2}{3} }\)]
d) the value of Emax
z₁ = 0.865 [1+\(\sqrt{1 - \frac{4 \ 0.04^2}{3} }\)) = 1.73 [1 + √0.99786]
z₁ = 1.729 m
z₂ = 0.865 [1 - √0.99786 ]
z₂ = 0.0011 m≈ 0
for which the field has a maximum value substituting in equation 1
\(E_{max} = 9 10^9 \ 9 \ \frac{1.729}{(0.04^2 + 1.729^{3/2})}\)
\(E_{max}\) = 81 10⁹ \(\frac{1.729}{1.4408}\)
\(E_{max}\)Emax = 9.7 10¹⁰ N / C
what is the total flux through the surface of the sba consider a charge of 3 nc inside a sphere is radius 3m what is the total flux through the surface of the sphere
The total flux through the surface of the sphere is 338.98 Nm²/C.
How to solve for the total fluxIn this case, we are given that there is a charge of 3 nC (nano-coulombs) inside a sphere of radius 3 m. Since the sphere is a closed surface, the total flux through the surface of the sphere will be equal to the electric flux due to the charge enclosed by the sphere.
Using the electric flux formula, we can calculate the total flux through the surface of the sphere as:
Φ = Q / ε₀ = (3 x 10^-9 C) / (8.85 x 10^-12 F/m)
Φ = 338.98 Nm²/C
Therefore, the total flux through the surface of the sphere is 338.98 Nm²/C.
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On the court in the picture below, the X's represent the defense (team that does not have the birdie) and the O's represent the offense (team that does
have the birdie). What type of shot should the offense make to try to score? Hint: Look at the position of the X players. What part of the court is open? O Drop Shot
O Serve
O Clear
The offense should aim for an Drop Shot to try to score.
What is a drop shot?A drop shot is a soft shot that lands just over the net and falls quickly, making it difficult for the defense to reach and return. In this situation, the drop shot can be effective because it would require the X players to quickly move forward from the backcourt, putting them out of position and giving the offense an opportunity to score.
Based on the position of the X players, it looks like the back of the court is more crowded compared to the front. Therefore, the offense should aim for an Drop Shot to try to score.
Thus, the part of the court that is open is drop shot.
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Description on Slider Mechanism concept on a wheelchair. (200
words)
A slider mechanism is a concept used in wheelchairs to allow for smooth and efficient movement of the seat. It involves a sliding mechanism that enables the user to adjust the position of the seat along the wheelchair frame, providing flexibility and comfort.
The slider mechanism concept in wheelchairs revolves around the idea of a sliding seat that can be adjusted forward or backward along the frame of the wheelchair. This mechanism allows the user to modify their seating position to achieve optimal comfort, balance, and posture.
Typically, the slider mechanism consists of a set of rails or tracks installed on the wheelchair frame, with the seat attached to a carriage that slides along these tracks. The sliding mechanism can be manual, where the user manually pushes or pulls the seat to adjust its position, or it can be powered, using electric motors or hydraulics for easier adjustment.
The benefits of the slider mechanism are numerous. It allows wheelchair users to modify their seating position to accommodate specific activities or preferences, such as reaching a table or desk, transferring in and out of the wheelchair, or adjusting weight distribution for better balance. The sliding mechanism also helps in preventing pressure sores and discomfort by allowing users to periodically change their seating position and relieve pressure points.
Overall, the slider mechanism concept on a wheelchair enhances the user's mobility and comfort by providing an adjustable seating position. It offers flexibility, adaptability, and improved ergonomics, enabling wheelchair users to customize their experience based on their individual needs and preferences.
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Vector has a horizontal component dx = 15. 0 m and makes an angle 0= 38. 0 with respect to the positive
x direction. What is the magnitude of ay, the vertical component of vector?
The required vertical component of the vector when the angle made by it with the x-axis is given along with the horizontal component is calculated to be 11.72 m.
The angle made with the positive x-axis is given as 38°.
The horizontal component dx is given as 15 m.
The inverse tangent function gives the angle made with the positive x-axis.
Mathematically, it is,
θ = tan⁻¹(dy/dx)
tan θ = dy/dx
tan 38° = dy/15
dy = 0.78 × 15 = 11.72 m
Thus, the required vertical component of the vector when the angle made by it with the x-axis is given along with the horizontal component is calculated to be 11.72 m.
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How can you determine if a circuit is a series circuit or parallel circuit
Answer: A circuit is said to be a parallel circuit if the electrical components are connected in a parallel configuration or their end are connected to a common point. It forms multiple loops or pathways for the current to flow. A circuit is said to be a series circuit if the components are connected in a series configuration or cascaded formation in a single line. A series circuit forms a pathway that has only one loop, therefore, the current flowing through components is the same and the voltage divides depending on the resistance of each component.
Explanation:
Add an E-W force and a N-S force so the object is at equilibrium.
Add a Force
re
Given: 64.0 N. 128.7°CCW
Tap to learn about CCW
The addition of vectors allows to find the vector that the equilibrium is
F = (40.02 i ^ - 49.95 j ^) N
Parameters given
Vector value A = 64.0 N and tea = 128.7ºTo find
The vector that allows equilibrium
The force is a vector magnitude so the sum of the force must be done using the methods to add vectors.
One of the easiest methods to perform the addition of vectors is the analytical method where each vector is decomposed in a Cartesian system and the components added using algebraic summation and then the resulting vector is constructed.
We decompose the vector
cos θ = \(\frac{A_x}{A}\)Ax / A
sin θ = \(\frac{A_y}{A}\)
Aₓ = A cos θ
\(A_y\)= A sin θ
Aₓ = 64 cos 128.7
\(A_y\) = 64 sin 128.7
Aₓ = -40.02 N
\(A_y\) = 49.95 N
To find the vector that allows equilibrium, we work each axis independently
X axis
Aₓ + Fₓ = 0
Fₓ = - Aₓ
Fₓ = 40.02 N
Y axis
\(A_y + F_y =0 \\F_y = - A_y\\F_y = - 49.95 N\)
We can write the resulting vector in two ways
1) F = (40.02 i ^ - 49.95 j ^) N
2) in the form of module and angle
Let's find the module with the Pythagoras' Theorem
F =\(\sqrt{F_x} ^2 + F_y^2)\\F = \sqrt{40.02^2 + 49.95^2 }\)
F = 64 N
Angles
tan θ = \(\frac{F_y}{F_x}\)
θ = tan⁻¹ \(\frac{F_y}{F_x}\)
θ = tan⁻¹ \(\frac{-49.95}{40.02}\)
θ = -51.3º
This angle is measured clockwise from the positive side of the x-axis
In conclusion using the sum of vectors we can find the vector that allows the equilibrium is
F = (40.02 i^ - 49.95 j^ ) N
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1. How much energy must be removed from a 200 g block of ice to cool it from 0 degrees C to -20 degrees C? The specific heat of ice is 2090 (J / kg⋅k)
Express your answer to two significant figures and include the appropriate units.
Two forces acting on an object in the same direction. One is 25N West and the other is 15 N West. What is the net force?
Answer: 40 N
Explanation: 25N + 15N
An 80kg dog initially running at a velocity 2 m/s accelerates to a velocity of 3 m/s. What is the impulse on the dog
Impulse is equal to the change in momentum of an object. The momentum of an object is equal to its mass times its velocity.
The initial momentum of the dog is 80kg * 2m/s = 160kg*m/s.
The final momentum of the dog is 80kg * 3m/s = 240kg*m/s.
The change in momentum of the dog is 240kgm/s - 160kgm/s = 80kg*m/s.
Therefore, the impulse on the dog is 80kg*m/s.
Please help, thanks!
\( \huge \boxed {\mathfrak{ \color{gold}Answer ࿐ }}\)
The wave having the lowest frequency is :
=》A. (a)
The greatest hurdle that must be overcome to fully embrace nuclear power to generate electricity is
A) safe storage of radioactive waste.
B) monitoring low-level radiation continuously being released into the surrounding region.
C) filtering the release of CO2 contributing to greenhouse gasses.
D) deactivating radioactive water flushed from cooling towers.
E) increased safety measures to decrease the potential for nuclear explosion releasing radiation into the atmosphere.
The most significant barrier to fully embracing nuclear technology to produce energy is the safe storage of radioactive waste.
Nuclear power is the only large-scale energy-producing technology that completely accepts responsibility for all waste and prices it into the product. Nuclear power generates extremely less waste in comparison to other thermal energy-producing sources. Used nuclear fuel may be used as either a resource or as waste. Nuclear waste is not exceptionally dangerous nor difficult to control in comparison to other toxic industrial waste. Technically established safe techniques for the ultimate disposal of high-level radioactive waste exist; the worldwide agreement is that geological disposal is the best choice.
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What is the minimum speed the block must have at the top of the loop to make it around the loop-the-loop without leaving the track?.
the minimum speed the block must have at the top of the loop to make it around the loop-the-loop without leaving the track is `sqrt(gr)`.
It is given as
`v=sqrt(gr)`
where v is the velocity of the block at the top of the loop, g is the acceleration due to gravity, and r is the radius of the loop.
However, the minimum speed is the one that makes the net force acting on the block to be equal to the centripetal force. At the top of the loop, the gravitational force on the block is acting downwards while the normal force on the block is acting upwards.
So the net force on the block is the difference between the two forces. This is given by:
Net force = gravitational force - normal force
`F_net = m*g - m*(v^2)/r
`Since the block is moving in a circle, the net force must be equal to the centripetal force.
That is,
`F_net = m*a_c
`where `a_c` is the centripetal acceleration. The centripetal acceleration is given by:
`a_c = v^2/r
`So we can substitute this expression for `a_c` into the equation for
`F_net`: m*(v^2)/r
= m*g - m*(v^2)/r2m*(v^2)/r
= m*gm*(v^2)/r
= mgr(v^2)
= grv = sqrt(gr)
Therefore, the minimum speed the block must have at the top of the loop to make it around the loop-the-loop without leaving the track is `sqrt(gr)`.
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How Tyler mentally reacts toward himself when he swings and misses the ball, is called _____.
A) self-talk
B) feedback
C) solution focused
Answer:
A)Self-Talk
Explanation:
Not really sure
A. Self talk
he is mentally reacting to HIMSELF
Forces with magnitudes of v = 135 newtons and u = 280 newtons act on a hook (see figure). The angle between the two forces is 45°. Find the direction and magnitude of the resultant of these forces. (Hint: Write the vector representing each force in component form, then add the vectors. Round your answers to two decimal places.)
To find the resultant force we will first find the component force of the forces given, to do this, we need to remember that any vector can be express in component form by:
\(\begin{gathered} \vec{v}= \\ \text{ where } \\ v\text{ is the magnitude } \\ \theta\text{ is the angle of the vector with respect to the positive x-axis.} \end{gathered}\)For force u we notice that its magnitude is 280 N and its angle is zero, then we have:
\(\begin{gathered} \vec{u}=<280\cos0,280\sin0> \\ \vec{u}=<280,0> \end{gathered}\)For force v we know that its magnitude is 135 N and its angle is 45°, then we have:
\(\begin{gathered} \vec{v}=<135\cos45,135\sin45> \\ \vec{v}=<95.46,95.46> \end{gathered}\)Now that we have both vectors in component form we add them to get the resultant in component form:
\(\begin{gathered} \vec{F}=\vec{u}+\vec{v} \\ \vec{F}=<280,0>+<95.46,95.46> \\ \vec{F}=<375.46,95.46> \end{gathered}\)Once we have the resultant force in component form we can find its magnitude and direction if we remember that they are given by:
\(\begin{gathered} F=\sqrt{F_x+F_y} \\ \theta=\tan^{-1}(\frac{F_y}{F_x}) \end{gathered}\)Plugging the values we found for the components we have:
\(\begin{gathered} F=\sqrt{375.46^2+95.46^2} \\ F=387.41 \end{gathered}\)and
\(\begin{gathered} \theta=\tan^{-1}(\frac{95.46}{375.46}) \\ \theta=14.27 \end{gathered}\)Therefore, the magnitude of the resultant force is 387.41 N and the direction is 14.27°
4000 ml to kl plis help mee
En un recipiente de cobre de forma rectangular de aproximadamente 3.5 m largo por 4.5m ancho tiene una temperatura en temporada de invierno 4 ° C . Calcular su superficie cuando este en verano a una temperatura 40 ° C . ( Cobre 16.6 x 10 ( -6 )
Answer:
A_f= 15,769 m²
Explanation:
Este es un ejercicio de dilatación térmica,
ΔA = (2α) A₀ ΔT
el arrea de recipiente
A₀ = L A
A₀ = 3,5 4,5
A₀= 15,75 m²
el coeficiente de dilatación térmica es alfa = 16,6 10⁻⁶ C⁻¹
calculemos
ΔA = 2 16,6 10⁻⁶ 15,75 ( 40 -4)
ΔA = 522,9 (36) 10⁻⁶
A= 1,88 10⁻² m2
el cambio de volumen es
ΔA = A_f – A₀
A_f = A₀ + ΔA
A_f= 15,75 +1,88 10⁻²
A_f= 15,769 m²
ray has been having problems with his vision. when he is in a low-light environment, his eyes do not adjust properly to allow the maximum amount of light to strike his retina. similarly, when he walks out into sunlight, he is blinded by the bright rays and has to wear dark sunglasses while outside. which structure in ray's eyes is not working properly? group of answer choices iris cornea lens pupil
The structure in Ray's eyes that is not working properly is the iris.
The iris is the colored part of the eye that surrounds the pupil. It controls the size of the pupil, which regulates the amount of light entering the eye. In low-light environments, the iris should dilate, allowing more light to enter the eye and reach the retina. However, in Ray's case, his iris does not adjust properly, preventing the maximum amount of light from striking his retina and affecting his vision in low-light conditions.
Similarly, when Ray walks out into sunlight, his iris should constrict to limit the amount of light entering the eye and prevent overexposure. However, if his iris fails to constrict adequately, he would be blinded by the bright rays and require dark sunglasses to reduce the amount of light reaching his retina.
In summary, Ray's vision problems in both low-light and bright-light situations suggest that his iris is not functioning properly, affecting the regulation of light entering his eyes.
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A 0.50 kilogram ball is held at a height of 20 meters. What is the kinetic energy of the ball when it reaches halfway after being released?
A.
49 joules
B.
98 joules
C.
1.0 × 102 joules
D.
1.1 × 102 joules
Answer:
A
Explanation:
Use the conservation of energy formula to calculate the velocity of the ball when it reaches the halfway point (10m down). Then, use your calculated value to obtain the kinetic energy.
Answer:
A. 49 on Plato
Explanation:
Its the right one trust me .
Problem 10 A diffraction grating has 200 lines/mm. It is illuminated by two monochromatic sources with wavelengths ?1 400nm and ?2 :-525nm. i) Determine the separation of the second order maxima on a screen that is 2.5m from the diffraction grating. ii) Determine the highest order for which both maxima are present.
The separation of the second order maxima on the screen is 0.008 m and highest order for which both maxima are present is probably around 10.
We can use the formula for diffraction grating:
dsinθ = mλ
where d is the spacing between the grating lines, θ is the angle of diffraction, m is the order of the maximum, and λ is the wavelength of the light.
i) For the second order maximum, m = 2, and we have:
dsinθ = 2λ
The spacing between the second order maxima on the screen is given by:
y = L*tanθ
where L is the distance between the grating and the screen. Substituting sinθ = m*λ/d, we have:
y = L*(mλ)/(dcosθ)
Substituting the values given, we get:
d = 1/200 mm = \(510^-^6 m\)
λ1 = 400 nm = \(410^-^7 m\)
λ2 = -525 nm = \(-5.25*10^-^7 m\)
L = 2.5 m
m = 2
For the first wavelength, we have:
sinθ1 = mλ1/d = \(2410^-^7/(510^-^6)\) = 0.16
For the second wavelength, we have:
sinθ2 = mλ2/d =\(2(-5.2510^-^7)/(510^-^6\)) = -0.21
The separation between the second order maxima on the screen is given by:
y = Ltanθ = Lsinθ/cosθ = L*sin(θ1-θ2)/cos(θ1+θ2)
Substituting the values, we get:
y = 2.5*sin(0.16 - (-0.21))/cos(0.16 + (-0.21)) = 0.008 m
So the separation of the second order maxima on the screen is 0.008 m.
ii) The highest order for which both maxima are present occurs when the separation between adjacent maxima is less than the distance between the two wavelengths. In other words, we want to find the maximum value of m such that:
(m+1)λ1 - mλ2 > λ2 - λ1
Substituting the values, we get:
\((3410^-^7) - (2*(-5.2510^-^7)) > -52510^-^9 - 400*10^-^9\)
Simplifying, we get:
\(10^-7 > -92510^-^9^2^.^1^5\)
Since the inequality is satisfied, we can say that both maxima are present for the second order.
However, since the values of the wavelengths are relatively close, we can estimate that the highest order for which both maxima are present is probably around 10.
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How can we drop eggs the fewest amount of times without breaking it?
Answer:
drop in water
Explanation:
follow me m mm m
A 50 liter piton cylinder device contain oxygen at 50°C and 170 kpa now the oxygen i heated until the temperature reache 77°C. What i the amount of heat tranferred during thi proce?
The amount of heat transferred is proportional to the temperature difference between the objects and the heat capacity of the object.
Warmness is based totally on the authentic story of Neil McCauley, a calculating criminal and ex-Alcatraz inmate who was tracked down by way of Detective Chuck Adamson in 1964. In 1961, McCauley was transferred from Alcatraz to McNeil, as mentioned in the film.
Considering the fact that Michael Mann's warmness got here out, he's been citing the film as a concept for the paintings he did inside the Dark Knight. Connections have been drawn among the visuals, the interrogation scene, and even solid member William Fitchner, who's in each movie.
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An astronaut landed on the Moon. Would he
be able to jump higher, lower or to the same
height as compared to when he is on the Earth?
Why?
Answer:
jump higher
Explanation:
this is due to the Moon's surface gravity being weaker because it is far less massive than Earth. A body's surface gravity is proportional to its mass, but inversely proportional to the square of its radius.