A placekicker for a football team makes field goals 85% of the time when kicking from the 20-yard line. Assuming that field goal attempts can be considered random events, what is the probability that the placekicker will make 4 of his next 5 attempts from the 20-yard line?
Answer:
Step-by-step explanation:
answer should be 0.39
The probability that the placekicker will make 4 of his next 5 attempts from the 20-yard line is 0.39.
What is the probability?Probability in mathematics is the possibility of an event in time. In simple words how many times does that incident is happening in any given time interval?
Given:
A placekicker for a football team makes field goals 85% of the time when kicking from the 20-yard line.
Assuming that field goal attempts can be considered random events.
P = 0.85
n = 5
Standard deviation = √{5 x 0.85 x (1 - 0.85) = 0.79
The probability that the placekicker will make 4 of his next 5 attempts from the 20-yard line is,
= P (X ≥ 4)
= P (X ≥ 3.5)
= 1 - P(X < 3.5)
= 0.39
Therefore, the probability is 0.39.
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Write y - 4 = 1 ( x - 4) in slope intercept form.
Answer:
y=x
Step-by-step explanation:
First, distribute the 1 to the x and -4. Both of these when multiplied by one equal their original value, leaving you with y-4=x-4.
Then, to isolate the y, you add 4 to both sides. This leaves you with simply y=x.
Determine if the result of each product is a positive or negative integer
Answer:
1. -13x9= -117 Negative
2. 4x14= 65 Positive
3. -6x(-31)= 186 Positive
4. -18x(54)= 4374 Positive
5. 55x7= 385 Positive
Step-by-step explanation:
a production process produces 3% defective parts. a sample of five parts from the production process is selected. what is the probability that the sample contains exactly two defective parts?
The probability that a sample of five parts from a production process that produces 3% defective parts contains exactly two defective parts is approximately 0.2834.
To find this probability, we can use the binomial probability formula:
P(X = 2) = (5 choose 2) * 0.03^2 * (1 - 0.03)^3
Where "X" is the number of defective parts in the sample, "5 choose 2" represents the number of ways to choose 2 defective parts out of 5, and 0.03 and (1 - 0.03) represent the probabilities of selecting a defective and non-defective part, respectively.
Using a calculator, we can simplify and compute:
P(X = 2) = (5 choose 2) * 0.03^2 * 0.97^3
= 10 * 0.0009 * 0.9127
≈ 0.0081
Therefore, the probability is approximately 0.0081 or 0.81%.
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f (x) = 3/4x + 2
What is the value of f (24)
Answer: Find the Properties f (x)=x^2+2x-24. f (x) = x2 + 2x − 24 f ( x) = x 2 + 2 x - 24.
Step-by-step explanation:
Answer:
the value of f(24) = 20
Step-by-step explanation:
SOMEONE PLEASE HELP!!! HURRY
Answer:
Slope of the line DV = -1
Step-by-step explanation:
Let point D (-5, 1) be \((x_{1}, y_{1})\)
Let point V (-1, -3) be \((x_{2}, y_{2})\)
\(m=\frac{y_2-y_1}{x_2-x_1}\)
Plug in the appropriate values,
\(m = \frac{-3-1}{-1-(-5)} = \frac{-4}{4} = -1\)
slope equals -1
A softball backstop that is 10 feet high casts an 8-foot shadow at the same time a light pole casts a 20-foot shadow. The height of the flagpole is about how many feet??
I'm just getting points
Step-by-step explanation:
just getting points
Subtract 85 - 43. Simplify the answer and write as a mixed number?
Answer:
42
Step-by-step explanation:
Bobby has already ran 1 mile on his own, and he expects to run 1 mile during each track practice. How many track practices would it take for Bobby to run 33 miles?
Answer:
In order to have ran 33 miles, Bobby would have to attend 32 track practices.
Step-by-step explanation:
Solving this problem entails of uncovering the amount of track practices Bobby must attend in order to have ran 33 miles. Start by reading the problem carefully to break down the information provided.
You can see that Bobby has already ran one mile on his own. This is important to remember for later. The problem also states that he expects to run one mile at every track practice.
Setting up an equation will help us solve. Here is how we could set up the equation:
(amount of miles already ran = 1) + (number of track practices = x) = (total miles to run = 33)
1 + x = 33
The equation is now in place. You can solve this, or isolate 'x', by using the subtraction property of equality. This means we will subtract one from both sides of the equation, thus isolating the variable.
1 + x = 33
1 - 1 + x = 33 - 1
x = 32
The variable is the only term left on the left side of the equation. This means Bobby must attend track practice 32 times in order to have ran 33 miles.
Convert. If necessary, round to the nearest tenth.
_____ km ≈ 100 miles.
Answer:
160.9 km
Step-by-step explanation:
\(100mi\times \frac{5280 ft}{1mi}\times \frac{12in}{1ft}\times \frac{2.54 cm}{1in}\times \frac{1m}{100cm}\times \frac{1km}{1000m}= 160.9344km\)
Rounding to the nearest tenth you get 160.9 km
how do you find interquartile range
if c% of a number is (a+b) what is the number
Answer:(a+b)/c ×100
Step-by-step explanation:
Let the number be "x"
According to the question,
X×C% = a+b
>> X × C/100 = a+b
So, x =(a+b)/c × 100
0 is a COMPOSITE number.
Group of answer choices
True
False
Answer:
falseeeeeeeeeeeeeeeeeeee
Answer:
false ma g brainliest please?
Step-by-step explanation:
You may have noticed that the average is
approaching a specific value. What value is the
average approaching? (To convince yourself,
you may want to roll the number cube a little
more.)
Answer:
compensatory approach
The approach that the interviewer is taking with this candidate is known as a compensatory approach. This strategy uses techniques or modifications to our behavior or environment that are used to compensate for a deficit, weakness, injury, or perceived inadequacy in a specific area or skill. Which in this scenario is what the interviewer has done by using the candidates high score on the interview in order to compensate or overshadow the low personality score.
Step-by-step explanation:
Hope this helps:)
Answer:
3.5
Step-by-step explanation:
Here is some helpful words for you learning adventure
event: a word referring to one or more possible outcomes in an experiment
expected value: the “average” (or expected) result of an experiment after a large number of trials
experiment: a selection involving chance, with two or more possible outcomes
fair game: a game in which the expected value of the outcome is zero
independent events: the sequence of events in which the occurrence of one event does not affect the probability of following events
law of large numbers: the law stating that if an experiment is performed a large number of times, the average of the results will come closer and closer to the expected value as the number of trials increases
probability: a number of desired outcomes divided by the size of the sample space
sample space: a set that includes all possible outcomes of an experiment
Subject to the conditions 0≤x≤10,0≤y≤5 the minimum value of the function 4x−5y+10 is (1) 10 (2) 0 (3) −25 (4) −15
The minimum value occurs when x = 10 and y = 0, resulting in a minimum value of 10.
To find the minimum value of the function 4x - 5y + 10 subject to the conditions inequality 0 ≤ x ≤ 10 and 0 ≤ y ≤ 5, we evaluate the function at the boundaries of the given conditions.
At the upper bound of x, when x = 10, the function becomes 4(10) - 5y + 10 = 40 - 5y + 10 = -5y + 50. Since y has a lower bound of 0, the minimum value of -5y + 50 occurs when y = 0, resulting in a value of 50.
At the lower bound of y, when y = 0, the function becomes 4x - 5(0) + 10 = 4x + 10. Similarly, since x has an upper bound of 10, the minimum value of 4x + 10 occurs when x = 10, resulting in a value of 50.
Comparing the values obtained at the boundaries, we find that the minimum value of the function 4x - 5y + 10 is 10.
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In the following problem, which step should
you perform first?
(5 × 4) + 3² - 2
Answer:
The answer is 27
Step-by-step explanation:
First, expand the parentheses
Second, deciphering the foundations
Third, multiplying or dividing (starting with the present first)
Fourthly, addition or subtraction (it starts with the existing first)
Why does the test for homogeneity follow the same procedures as the test for independence?
Thus, the test for homogeneity follows the same procedures as the test for independence because the assumptions for performing the chi-square test for independence and chi-square test for homogeneity are the same.
The procedures for the chi-square test of homogeneity are the same as for the chi-square test of independence. The data is different for both tests. Tests of independence are used to determine whether there is a significant relationship between two categorical variables from the same population. One population is segmented based on the value of two variables. So there will be a column variable and a row variable.
The chi-square test of homogeneity of proportions can be used to compare population proportions from two or more independent samples, determining whether the frequency counts are distributed identically among different populations.
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Un coche inicia un viaje de 495 Km. a las ocho y media de la mañana con una velocidad
media de 90 Km/h ¿A qué hora llegará a su destino?
The time that you will arrive at your destination, given the distance of the trip and the average speed, is 2 pm
How to find the time of arrival?To find the time of arrival by using the car going at 90 km /h, you need to find the time that the whole trip would take.
The time the trip would take is found by the formula:
= Distance of trip / Average speed
= 495 / 90
= 5 . 5 hours
0.5 hours is 30 minutes so this is 5 hours 30 minutes.
The time you will arrive is therefore:
= 8 : 30 + 5 hours 30 minutes
= 2 pm
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I NEED HELP ASAP PLEASE
Which graph represents y=⌈x⌉over the domain 2≤x≤5 ?
1. A coordinate plane with a step function graphed with x axis increments of 1 increasing from negative 5 to 5 and with y axis in increments of 1 increasing from negative 5 to 5. A point at begin ordered pair 2 comma 2 end ordered pair. Another point at begin ordered pair 5 comma 5 end ordered pair. A line segment with open endpoint at begin ordered pair 2 comma 3 end ordered pair and closed endpoint at begin ordered pair 3 comma 3 end ordered pair. A second line segment with open endpoint at begin ordered pair 3 comma 4 end ordered pair and closed endpoint at begin ordered pair 4 comma 4 end ordered pair.
2. A coordinate plane with a step function graphed with x axis increments of 1 increasing from negative 5 to 5 and with y axis in increments of 1 increasing from negative 5 to 5. A point at begin ordered pair 5 comma 5 end ordered pair. A line segment with open endpoint at begin ordered pair 2 comma 3 end ordered pair and closed endpoint at begin ordered pair 3 comma 3 end ordered pair. A second line segment with open endpoint at begin ordered pair 3 comma 4 end ordered pair and closed endpoint at begin ordered pair 4 comma 4 end ordered pair.
3. A coordinate plane with a step function graphed with x axis increments of 1 increasing from negative 5 to 5 and with y axis in increments of 1 increasing from negative 5 to 5. A point at begin ordered pair 5 comma 5 end ordered pair. A line segment with open endpoint at begin ordered pair 1 comma 2 end ordered pair and closed endpoint at begin ordered pair 2 comma 2 end ordered pair. A second line segment with open endpoint at begin ordered pair 2 comma 3 end ordered pair and closed endpoint at begin ordered pair 3 comma 3 end ordered pair. A third line segment with open endpoint at begin ordered pair 3 comma 4 end ordered pair and closed endpoint at begin ordered pair 4 comma 4 end ordered pair.
4. A coordinate plane with a step function graphed with x axis increments of 1 increasing from negative 5 to 5 and with y axis in increments of 1 increasing from negative 5 to 5. A point at begin ordered pair 2 comma 2 end ordered pair. A line segment with open endpoint at begin ordered pair 2 comma 3 end ordered pair and closed endpoint at begin ordered pair 3 comma 3 end ordered pair. A second line segment with open endpoint at begin ordered pair 3 comma 4 end ordered pair and closed endpoint at begin ordered pair 4 comma 4 end ordered pair. A third line segment with open endpoint at begin ordered pair 4 comma 5 end ordered pair and closed endpoint at begin ordered pair 5 comma 5 end ordered pair.
A dinner set was marked $ 532 and a discount of 12% was offered on its marked price. Find the sale price of the dinner set.
Answer:
$468.16
Step-by-step explanation:
answer key
hank owns a fruit stall he sells 11 apple and 5 oranges for 2.71. one apple costs 16p how much does one orange cost?
Answer:
11*0.16=1.76
2.71-1.76=0.95
0.95/5=0.19
One orange costs 0.19
Step-by-step explanation:
i) [(2⁵)×7³] /(8³×7)
=8³ can be written as =(2×2×2)³
=(2³)³
we have,
=[(2⁵)²×7³) / [(2³)³×7)
=(2⁵×2×7³)/[(2³×3×7) ....(▪︎(Am)n=(amn)
=(2¹⁰×7³)/(2⁹×7)
=(2¹⁰×7³)/(2⁹×7)
=(2¹⁰-a×7³-¹)▪︎▪︎▪︎(▪︎am÷an=am-n)
=2×7²
=2×7×7
=97
-------
It's answer is correct and wrong
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Answer:
its 196
Step-by-step explanation:
x+3 if x >5
PLEASE HELP
Answer:
x>8
Step-by-step explanation:
If x>5, then adding 3 to it must mean the term is greater than 3+5 which is 8.
Find the cost of a pencil and eraser if two pencils and three erasers cost $140, and five
pencils and four erasers cost $280.
Answer:
1 pencil costs $40
1 eraser costs $20
an economist wants to estimate the mean per capita income (in thousands of dollars) for a major city in california. he believes that the mean income is $33.9 , and the standard deviation is known to be $9.2 . how large of a sample would be required in order to estimate the mean per capita income at the 80% level of confidence with an error of at most $0.55 ? round your answer up to the next integer.
The economist would need a sample size of at least 22 to estimate the mean per capita income with an 80% confidence level and an error of at most $0.55.
In order to determine the required sample size, we need to use the formula for sample size calculation in estimating the population mean. The formula is given by:
n = (Z * σ / E)^2
Where:
n = required sample size
Z = Z-score corresponding to the desired confidence level (80% confidence level corresponds to a Z-score of approximately 1.28)
σ = standard deviation of the population (known to be $9.2)
E = maximum allowable error ($0.55)
Substituting the given values into the formula:
n = (1.28 * 9.2 / 0.55)^2
n = (11.776 / 0.55)^2
n = 21.41^2
Since the sample size must be a whole number, we round up to the next integer:
n = 22
Therefore, the economist would need a sample size of at least 22 to estimate the mean per capita income with an 80% confidence level and an error of at most $0.55.
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y = x2 - 4
y = -(x + 5)
Answer:
what do u want to find I don't get it
1. If a basketball player makes 9 baskets in 12 tries, what is her ratio of baskets to tries, in lowest terms?
2. At the next game, the player has the same ratio of baskets to tries. If she tries 20 times, how many baskets should she make?
3. At the third game, she still has the same ratio of baskets to tries, This time she makes 12 baskets. How many times did she probably try?
Answer:
1. 3:4
Step-by-step explanation:
The ratio of baskets to tries is 3/4, 15 basket was made in 20 tries and 12 basket in 16 tries
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
1) . If a basketball player makes 9 baskets in 12 tries, hence:
Ratio of baskets to tries = 9/12 = 3/4
2) For 20 tries:
Number of basket = (3/4) * 20 = 15
3) For 12 basket:
Number of tries = 12 / (3/4) = 16
The ratio of baskets to tries is 3/4, 15 basket was made in 20 tries and 12 basket in 16 tries
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Need help on this one please
some one please help, lots of points granted !!!!!
Jenny works mowing lawns and babysitting. She earns $8.80 an hour for mowing and $7.70 an hour for babysitting. How
much will she earn for 1 hour of mowing and 3 hours of babysitting?
Answer:
$31.90
Step-by-step explanation:
Hope it helps :)
Have a good day/night
Brainliest pls?