If an octagon had half of its sides measure 5 in and the other half measure 12 inches what is the perimeter? Explain your answer? HELPP PLEASE

To determine the number of groups of three books that are possible, we can use the concept of combinations.

Since Pat has 10 books and she wants to select three of them, we can use the formula for combinations:

C(n, r) = n! / (r!(n - r)!)

Where n is the total number of items (books) and r is the number of items (books) to be selected.

In this case, n = 10 (total number of books) and r = 3 (number of books to be selected).

Plugging these values into the formula, we get:

C(10, 3) = 10! / (3!(10 - 3)!)

Simplifying further:

C(10, 3) = 10! / (3!7!)

Using the factorial notation:

C(10, 3) = 10 × 9 × 8 / (3 × 2 × 1)

C(10, 3) = 120

Therefore, there are 120 different groups of three books that Pat can select from her collection of 10 books.

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Answer:

1-9, 1929

Step-by-step explanation:

You do the arithmetic and then study the us government postal codes and then you do kid behavior with my names. So, you get 1929 basically, in a nutshell, forever incessantly. thank yopu  

The probability of Suzan grabbing at least one green marble when she randomly selects eight marbles from a bag containing 3 red marbles, 2 green marbles, 5 white marbles, and 2 purple marbles is 283/288.

To find the probability of Suzan grabbing at least one green marble when she randomly selects eight marbles from a bag, we need to consider the total number of favorable outcomes (marbles with at least one green) and the total number of possible outcomes (all marbles she could choose).

The bag contains a total of 3 red marbles, 2 green marbles, 5 white marbles, and 2 purple marbles. Suzan will randomly select 8 marbles from this bag.

To find the probability, we need to calculate the complement of the event "she has no green marbles."

To have no green marbles, Suzan must choose all marbles from the remaining colors, which are red, white, and purple.

The probability of selecting a red marble is 3/12 (3 red marbles out of 12 total).

The probability of selecting a white marble is 5/12 (5 white marbles out of 12 total).

The probability of selecting a purple marble is 2/12 (2 purple marbles out of 12 total).

Since the marbles are chosen randomly and independently, we multiply these probabilities together:

(3/12) * (5/12) * (2/12) = 30/1,728

This gives us the probability of Suzan having no green marbles.

To find the probability of Suzan having at least one green marble, we subtract this probability from 1:

1 - 30/1,728 = 1,698/1,728 = 283/288.

Therefore, the probability of Suzan having at least one green marble when she grabs eight marbles at random is 283/288.

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To multiply radical expressions with the same index, we use the product rule for radicals. \(\sqrt[n]{A}.\sqrt[n]{B} = \sqrt[n]{A.B}\)

To divide radical expressions with the same index, we use the quotient rule for radicals. \(\frac{\sqrt[n]{A} }{\sqrt[n]{B} } =\sqrt[n]{\frac{A}{B} }\)

Multiplying Radical Expressions :

Example,

given:  Multiply: \(\sqrt[3]{12} .\sqrt[3]{6}\)

Apply the product rule for radicals, and then simplify.

\(\sqrt[3]{12}.\sqrt[3]{6}=\sqrt[3]{12.6}\)

            \(=\sqrt[3]{72}\\=\sqrt[3]{2^{3} .3^{2} } \\=2\sqrt[3]{3^{2} } \\=2\sqrt[3]{9}\)

Dividing Radical Expressions

Example,

given: Divide: \(\frac{\sqrt[3]{96} }{\sqrt[3]{6} }\)

In this case, we can see that 6 and 96 have common factors. If we apply the quotient rule for radicals and write it as a single cube root, we will be able to reduce the fractional radicand.

\(\frac{\sqrt[3]{96} }{\sqrt[3]{6} } =\sqrt[3]{\frac{96}{6} }\)

      \(=\sqrt[3]{16} \\=\sqrt[3]{8.2} \\=2\sqrt[3]{2}\)

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Answer:The first one I think

Step-by-step explanation:

Answer:

The formula for the area of a trapezoid is the average of the bases multiplied by the altitude.

Step-by-step explanation:

Answer:

x=-4

Step-by-step explanation:

8x+4=-28

8x=-28-4

8x=-32

x=-4

cot(θ) = cos(θ)/sin(θ)

So if both cot(θ) and cos(θ) are negative, that means sin(θ) must be positive.

Recall that

cot²(θ) + 1 = csc²(θ) = 1/sin²(θ)

so that

sin²(θ) = 1/(cot²(θ) + 1)

sin(θ) = 1 / √(cot²(θ) + 1)

Plug in cot(θ) = -2 and solve for sin(θ) :

sin(θ) = 1 / √((-2)² + 1)

sin(θ) = 1/√(5)

Hence, point P's coordinates are (6, 3) as the midpoint of the line segment from R to Q, which is the precise halfway point between R and Q.

A point's location on a line or in space can be determined using a set of numbers called coordinates. An x-coordinate and a como, which denote the horizontal as well as vertical ranges from a bench mark known as the origin, are the two numbers that make up coordinates in two-dimensional space. Three numbers, the x, y, and z coordinates, which describe the distances from origin in the x, y, and g directions, respectively, might make up coordinates in three-dimensional space. Among other disciplines, coordinates are frequently employed in physics, arithmetic, and geometry.

given

The midpoint of the line segment from R to Q, which is the precise halfway point between R and Q, must be located in order to determine the coordinates of point P.

We can separately aver the x- and y-coordinates to get the middle.

The midpoint's x-coordinate is (4 + 8)/2, which equals 6.

(0 + 6)/2 = 3 is the midpoint's y-coordinate.

Hence, point P's coordinates are (6, 3) as the midpoint of the line segment from R to Q, which is the precise halfway point between R and Q.

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Answer:

(-3.5 , 2.3)

Step-by-step explanation:

I know

Therefore, approximately 1,491 Whos will be infected 10 days after the virus is first detected.

To approximate the number of Whos that will be infected 10 days after the virus is first detected, we can use the concept of exponential growth. We can use the formula for exponential growth:\(P(t) = P0 * (1 + r)^t,\) where P(t) is the population at time t, P0 is the initial population, r is the growth rate, and t is the time in days.

Let's calculate the growth rate (r) first:

r = (800 - 100) / 5

= 140 Whos per day

Now, we can calculate the approximate number of infected Whos 10 days later:

\(P(10) = 100 * (1 + 140/100)^{10\)

Using a calculator, we can compute this value:

\(P(10) ≈ 100 * (1.4)^{10\)

= 1491.03

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The statement "two proofs are required to establish the provable equivalence of two sentences of tfl" is false.

Only one proof is required to establish the provable equivalence of two sentences of TFL.

What is TFL? TFL (Truth-Functional Logic) is a form of propositional logic in which the only logical expressions are truth functions. Truth functions are built from a fixed set of truth-functional connectives or operators, each of which operates on one or more sentences to create a compound sentence. TFL's operators are all truth-functional; that is, the truth or falsity of a sentence depends solely on the truth or falsity of its atomic components and how they are combined by the operators.

Here are the five standard truth-functional operators in TFL:

Conjunction: AND (•)

Disjunction: OR (+)

Negation: NOT (~)

Conditional: IF...THEN (→)

Biconditional: IF AND ONLY IF (↔)

Proofs are used to demonstrate the validity of sentences in TFL. It is important to note that a sentence's validity is a property of the sentence itself, not the sentence's meaning. To demonstrate the validity of a sentence in TFL, proofs are created.In TFL, two sentences are provably equivalent if and only if they are logically equivalent. The provable equivalence of two sentences in TFL only requires one proof. Thus, the statement, "Two proofs are required to establish the provable equivalence of two sentences of TFL," is false.

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Answer:

x=8+4y

Step-by-step explanation:

Add 8y to both sides:

2x=16+8y

Divide both sides by 2:

x=8+4y

Answer:

$2.81

Step-by-step explanation:

if one meter of fabric costs $1.15 then,

The fabric cost = one meter fabric cost × fabric measurement

The fabric cost = 8 × $1.15

The fabric cost = 9.20 feet

The value of [1 ft = 0.305m], therefore,

The fabric cost = 9.20 × 0.305 m = $2.81

Hence, The fabric cost is $2.81.

Answer:

6inches to the 2nd power

Step-by-step explanation:

Volume is height multiplied by width and by height.

So 3 * 2 = 6

6 * 1 = 6

So your volume is 6 inches squared

Answer:

look it up on slader.com thats the sams problem that i have had before and it worked on slader.

Answer:

the answer is 76.8

Step-by-step explanation:

multiple of the number

The First step in adding and subtracting the rational expression is making the denominator equal .

The Rational Expression is defined as the expression that is written in the p/q form , where q ≠ 0 .

Let us understand adding and subtracting of the rational expression by an Example .

For Example : add the rational expressions 2/3 and 1/4 .

The First Step in adding them is to make the denominator equal ,

to make the denominator equal , we take LCM ,

the LCM of 3 and 4 is 12 ,

the rational expression become ⇒ 8/12 and 3/12 .

On adding , we get ; (8 + 3)/12 = 11/12 .

On subtracting , we get ; (8 - 3)/12 = 5/12 .

Therefore , making the denominator equal is the first step for adding and subtracting rational expressions .

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The simplified form of the expression 9²- (b + c)²/{c² - (a - b)²} is {81 - b² - c² - 2bc}/{c² - a² - b² + 2ab}.

A term is a single mathematical phrase. It might consist of only one variable—a letter—one number—positive or negative—or several variables multiplied but never added or subtracted. A number is placed in front of some nouns that have variables. Coefficients are numbers that come before phrases.

Given:

Two quadratic polynomials,

9²- (b + c)² and c² - (a - b)².

And the expression, according to the question,

9²- (b + c)²/{c² - (a - b)²}

In order to simplify the expression,

we have to expand the quadratic polynomial.

So,

(b + c)² = b² + c² + 2bc.

And (a - b)² = a² + b² -2ab.

Substituting the value of (b + c)² and (a - b)² to the expression,

we get,

9²- (b + c)²/{c² - (a - b)²}

= {81 - b² - c² - 2bc}/{c² - a² - b² + 2ab}

Therefore, the simplified expression is {81 - b² - c² - 2bc}/{c² - a² - b² + 2ab}

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\(\huge \boxed{\sf x < -3} \\\\\\ \displaystyle \sf 15 < -5x \\\\ Divide\ each\ side\ by\ -5\ and\ switch\ the\ symbol. \\\\ \frac{15}{-5} > \frac{-5x}{-5} \\\\-3 > x\)

Answer:

It would be 177.8 cm!!

Step-by-step explanation:

Answer:

177.8 CM

Step-by-step explanation:

70 x 2.54

= 177.8

For a pet shop to approximate 18 rabbits, it would take 6 weeks.

In the question, we have a formula that represents the number of rabbits available with them.

The amount of rabbits is dependent on another variable, Time.

The variables depend on each other, and the number of rabbits with the pet shop relies on the number of weeks.

R(t)= 2t(2/3) + 10

If the number of rabbits is 18, then the value of the equation would be equal to 18.    [R(t) = 18]

18= 2t(2/3) +10

18= 4t/3 + 10

8 X 3 = 4t

24/4 = t

6 = t

Therefore, 18 rabbits are approximated by the pet store in 6 weeks.

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Answer:

n

Step-by-step explanation:

2n - n ← factor out n from each term

= n(2 - 1)

= n × 1

= n

The price vectors a. p₁ = 3 and p₂ = 2, Mary will consume only good 1.

Here we have the Utility function as

U(x₁ , x₂) = 3x₁ + x₂

From the given utility function we can clearly see that these goods are substitutes for each other

Now,

δU/δx₁ = 3

δU/δx₂ = 1

Hence we get the Marginal Rate of Substitution or MRS

\(=- \frac{\delta U/ \delta x_1 }{\delta U/ \delta x_2}\)

= -3

The MRS signifies that for every additional unit of 1, Mary is willing to give up 3 units of good 2

|MRS| = 3

For Mary to only consume good 1, |MRS| > p₁/p₂

Hence here we get the p/p ratio for the 4 price vectors to be

a. 3/2 = 1.5

b. 10/3 = 3.33

c. 4

d. 15.4 = 3.75

Hence we can clearly say that for the price vectors p₁ = 3 and p₂ = 2, Mary will consume only good 1.

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The probability of Z being greater than 4 is nearly 0 (option D). Therefore, the answer is D.

Let's assume that the weight of a grapefruit follows a normal distribution with mean 0.9 pounds and standard deviation 0.1 pounds. Then, the weight of three grapefruits will follow a normal distribution with mean 2.7 pounds (3 x 0.9) and standard deviation 0.1732 pounds (sqrt(3) x 0.1).

Now, we need to find the probability that the total weight of three grapefruits is more than 3.4 pounds. We can standardize the distribution by subtracting the mean from 3.4 and dividing by the standard deviation:

Z = (3.4 - 2.7) / 0.1732 = 4

Using a standard normal distribution table or calculator, we can find that the probability of Z being greater than 4 is nearly 0 (option D). Therefore, the answer is D.

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Answer:It is given b the x2 of the anwserr fot the firghjt angle

Step-by-step explanation:

The correct answer is the statements for tangent line are (b) I and III only. I) f-1 (10) = 12 (II) (f-1)(12) = 1/7

The tangent line at x=10 is given by y = 7(x-10) + 12, which has a slope of 7. This means that the derivative of f(x) at x=10, f'(10), is equal to 7.

We can use the inverse function theorem to find the derivative of the inverse function f^(-1)(x) at x=12, denoted as (f^(-1))'(12). This is given by:

(f^(-1))'(12) = 1/f'(f^(-1)(12))

Since the tangent line at x=10 is given by y=7(x-10)+12, we know that f(10) = 12. Therefore, f^(-1)(12) = 10. Substituting this into the above equation, we get:

(f^(-1))'(12) = 1/f'(10) = 1/7

So, statement IV is false.

To check the other statements, we can use the fact that f(f^(-1)(x)) = x. Substituting x=10, we get:

f(f^(-1)(10)) = 10

Since f(10) = 12, this implies that f^(-1)(10) = 10/12 = 5/6. Therefore, statement I is true.

Similarly, substituting x=12, we get:

f(f^(-1)(12)) = 12

Since f(10) = 12, this implies that f^(-1)(12) = 10. Therefore, statement II is false, and statement III is true.

In summary, the correct statements are I and III only, so the answer is (b).

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In parametric models, "two-way association" refers to the relationship between two variables where each variable has an influence on the other. It implies that changes in one variable affect the other, and vice versa.

In parametric models, two-way association is characterized by a mutual dependency between the variables. This means that the values of both variables are determined by each other rather than being independent. The association can be described in terms of a mathematical equation or model that represents the relationship between the variables.

For example, in a regression model, if we have two variables X and Y, a two-way association implies that changes in X will cause corresponding changes in Y, and changes in Y will cause corresponding changes in X. This indicates a bidirectional relationship where both variables influence each other. Two-way associations are important in understanding and analyzing complex systems and can provide insights into causal relationships and interactions between variables.

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Answer:

here is it graphed

The proof of "if group G has exactly one subgroup H of order k, then H is normal in G" is explained below.

If a "group-G" has exactly one subgroup H of order k, we want to show that H is normal in G. This means that for any element g in G, when we conjugate H by g, we get H again.

To prove this, we consider the left cosets of H in G. A left coset of H is formed by taking an element g in G and multiplying it with each element of H. Since H is the only subgroup of order k, each left coset has k elements.

Now, we take any element-g from G. Since the left cosets partition G, g must be in one of these left cosets, which we can write as gH.

When we conjugate H by g, we get gHg⁻¹. This means we multiply each element of H by g and then multiply the result by g⁻¹, the inverse of g.

Since G is a group, this multiplication follows the group's properties.  When we multiply any element of H by g and then by g⁻¹, the result is still an element of H.

Because of this, we can conclude that for any element g in G, the conjugate of H by g (gHg⁻¹) is still a subset of H.

Therefore, H is normal in G.

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The given question is incomplete, the complete question is

If a group G has exactly one subgroup H of order k, prove that H is normal in G.

1) 2(-2x + 5)

→ -4x + 10 = 0

-4x = -10

x = -10/-4

x = 5/2

2) 6 - 3x

→ -3x + 6 = 0

-3x = -6

x = -6/-3

x = 2