If an object is between a concave mirror and its focal point, the image will be(A) real and smaller than the object.(B) real and larger than the object.(C) virtual and smaller than the object.(D) virtual and larger than the object.

The moment of inertia (I) will changes and net torque (Tnet) will also change, while the angular acceleration (a) remains constant.

The formula for net torque acting on an object is given as;

T(net) = Ia

where;

The  moment of inertia of an object is given as;

I ∝ MR²

where;

So mass, M changes, the moment of inertia (I) changes and net torque will also change, while the angular acceleration remains constant.

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Plasma lacks a precise form or volume, much like gas. It completes the empty space. Even though it is in the gaseous form, there is a difference because some of the particles are plasma-ionized.

High-energy particles are free to move around and fill the area they inhabit in the state of matter known as gas.

Neutral atoms or molecules often make up gaseous substances like air.

The ionised gas known as plasma, on the other hand, contains both positively and negatively charged particles.

It develops when a gas is subjected to an intense electric field or heated to incredibly high temperatures.

Plasma is a substance that may be found in stars, lightning, and fluorescent lights. It is also an essential component of many modern technology, like plasma TVs and fusion reactors.

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Answer:

Choice E.

Amplitude: \(20\; {\rm cm}\).

Frequency: \(2\; {\rm Hz}\).

Explanation:

The amplitude of a simple harmonic motion (SHM) is the maximum displacement from equilibrium.

In this question, the equilibrium is in the center of the two extremes. With one extreme at \(x = 10\; {\rm cm}\) and the other at \(x = 50\; {\rm cm}\), the center will be at \((1/2)\, (10 + 50)\; {\rm cm} = 30\; {\rm cm}\).

The maximum displacement will be \((50\; {\rm cm} - 30\; {\rm cm}) = 20\; {\rm cm}\) (or equivalently, \((30\; {\rm cm} - 10\; {\rm cm}) = 20\; {\rm cm}\).

Frequency measures the number of cycles completed in unit time (e.g., one second.) In one full cycle of an SHM, the oscillator will travel from one extreme to another and then back to the original extreme. In this question:

In other words, one full cycle of this SHM will take \(0.25\; {\rm s} + 0.25\; {\rm s} = 0.50\; {\rm s}\). The period of this SHM will be \(0.50\; {\rm s}\). Hence, the frequency of this SHM will be:

\(\begin{aligned} (\text{frequency}) &= \frac{1}{(\text{period})} \\ &= \frac{1}{0.50\; {\rm s}} \\ &= 2\; {\rm Hz}\end{aligned}\).

The reason why photons take about 170,000 years to reach the surface of the Sun while neutrinos take only approximately three minutes for the same trip lies in the interaction of these particles with matter.

Photons are electromagnetic radiation and they interact strongly with the charged particles present in the dense plasma of the Sun's core. These interactions cause frequent scattering and absorption, resulting in a random walk-like path for the photons. As a result, they experience numerous collisions and absorptions, which significantly slows down their journey to the Sun's surface. The process is often referred to as "radiative diffusion."

On the other hand, neutrinos are electrically neutral particles that interact only very weakly with matter. This weak interaction allows neutrinos to pass through the dense plasma of the Sun's core almost unimpeded. Neutrinos can traverse matter, including the Sun, without being significantly absorbed or scattered, making their journey from the core to the surface much faster than photons.

The differing interaction strengths of photons and neutrinos with matter explain why photons take much longer to reach the Sun's surface compared to neutrinos. This phenomenon highlights the unique properties and behavior of these fundamental particles in the realm of astrophysics and particle physics.

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Explanation:

as there is plastic covering around the wires because at the copper when we cover with like a insulators that can flow current are called insulators for when we when we touch the wire then we get current that's conductor orchid covering of fire so we can't be get a current

The magnitude of the displacement vector refers to the length or amount of the displacement vector. Displacement is the change in position of an object. Displacement is a vector quantity, which means it has both magnitude and direction. In this question, a figure skater is gliding along a circular path of radius 3.93 m.

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Answer:

Yes, air can indeed make shadows. A shadow occurs when an object in a light beam prevents some of the light from continuing on in the forward direction. When the light beam hits a wall or the ground, a darker shape is visible where less light is hitting the surface. Refraction is responsible.

Explanation:

Here is a clip of an example of air making a shadow

https://www.seeker.com/stories/air-shadows/

Answer:

It will move a distance of 4 * 3.5 = 4 cm in one cycle.

zero to max A, back to zero, zero to min A, back to zero (4 * A)

The gravitational force that the moon has on a person with a mass of 50 kg is approximately 1.15 N.

The gravitational force between two objects depends on their masses and the distance between them. This force is given by the formula:

F = (G × m₁ × m₂) / r² where F is the gravitational force, m₁ and m₂ are the masses of the two objects, r is the distance between them, and G is the gravitational constant, which has a value of 6.7 × 10⁻¹¹ N m²/kg².

Using this formula, we can find the gravitational force that the moon has on a person with a mass of 50 kg.

The mass of the moon is 7 × 10²² kg, and the distance between the moon and the person is 380,000,000 m.

Therefore, we have:

m₁ = 50 kg

m₂ = 7 × 10²² kg

r = 380,000,000 m

G = 6.7 × 10⁻¹¹ N m²/kg²

Substituting these values into the formula, we get:

F = (G × m₁ × m₂) / r²

F = (6.7 × 10⁻¹¹ × 50 kg × 7 × 10²² kg) / (380,000,000 m)²

F = 1.15 N

Therefore, the gravitational force that the moon has on a person with a mass of 50 kg is approximately 1.15 N.

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It as dangerous to be hit by the gun as by the bullet because of the following;

(A) The butt distributes the recoil force over an area much larger than that of the bullet.

(B) The rifle has a much lower speed than the bullet.

The principle of conservation of linear momentum states that in an isolated system, the total momentum of the system is conserved.

That is the sum of the initial momentum is equal to the sum of the final momentum.

momentum of the gun = momentum of the bullet

Mu = mU

where;

If the forward momentum of a bullet is the same as the backward momentum of the gun, the speed of the gun will be smaller than the speed of the bullet since the mass of the gun is bigger than mass of the bullet.

We cannot conclude on the kinetic energy, since it depends on both mass and velocity.

Finally, the butt distributes the recoil force over an area much larger than that of the bullet, since the butt has a larger surface area and will hit more surface area than the bullet.

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Answer:

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

PE = 30 × 10 × 15

We have the final answer as

Hope this helps you

At the level of an individual electron a short-circuit doesn't look much different than a normal current path, it will move because of the electric field.

At the level of an individual electron a short-circuit doesn't look much different than a normal current path, it will move because of the electric field.

Collaboration is critical to successful product design, and with Solid Edge, OEMs and suppliers can improve and manage collaboration across design teams, regardless of location. By reducing design revisions and communication delays, our customers enjoy quicker time-to-market and increased profitability.

The magnitude of the power dissipated in resistor R4 is approximately 10,028 watts.

To find the power dissipated in resistor R4, use the formula:

P = I² × R

where P = power, I = current flowing through the resistor, and R = resistance of the resistor.

The total resistance, Rt, can be calculated using the formula:

1/Rt = 1/R1 + 1/R2 + 1/R3

Substituting the given values:

1/Rt = 1/3 + 1/0.8 + 1/2

Simplifying the equation:

1/Rt ≈ 1.6667

Rt ≈ 0.6 Ω

Next, calculate the total voltage, Vt, by summing the individual voltage sources:

Vt = ε1 + ε2 + ε3

Substituting the given values:

Vt = 9 + 6 + 4

Vt = 19 V

Now calculate the current flowing through resistor R4 using Ohm's Law:

I = Vt / Rt

Substituting the calculated values:

I = 19 / 0.6

I ≈ 31.6667 A

Finally, calculate the power dissipated in resistor R4:

P = I² × R4

Substituting the calculated values:

P = (31.6667)² × 10

P ≈ 10,028 W

Therefore, the magnitude of the power dissipated in resistor R4 is approximately 10,028 watts.

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Answer and Explaination:

To solve this problem, we can analyze the forces acting on the mass as it travels up the inclined plane. We'll consider the gravitational force and the force exerted by the spring.

1. Gravitational force:

The force due to gravity can be broken down into two components: one perpendicular to the inclined plane (mg * cosθ) and one parallel to the inclined plane (mg * sinθ), where m is the mass and θ is the angle of the inclined plane.

2. Force exerted by the spring:

The force exerted by the spring can be calculated using Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position. The force can be written as F = -kx, where F is the force exerted by the spring, k is the spring constant, and x is the displacement from the equilibrium position.

Given:

Mass (m) = 5.0 kg

Compression of the spring (x) = 20.0 cm = 0.20 m

Angle of the inclined plane (θ) = 30°

First, let's find the force exerted by the spring (F_spring):

F_spring = -kx

To find k, we need the spring constant. Let's assume that the spring is ideal and obeys Hooke's Law linearly.

Next, let's calculate the gravitational force components:

Gravitational force parallel to the inclined plane (F_parallel) = mg * sinθ

Gravitational force perpendicular to the inclined plane (F_perpendicular) = mg * cosθ

Since the inclined plane is frictionless, the force parallel to the inclined plane (F_parallel) will be canceled out by the force exerted by the spring (F_spring) when the mass reaches its highest point.

At the highest point, the gravitational force perpendicular to the inclined plane (F_perpendicular) will be equal to the force exerted by the spring (F_spring).

Therefore, we have:

F_perpendicular = F_spring

mg * cosθ = -kx

Now, let's substitute the known values and solve for k:

(5.0 kg * 9.8 m/s^2) * cos(30°) = -k * 0.20 m

49.0 N * 0.866 = -k * 0.20 m

42.426 N = -0.20 k

k = -42.426 N / (-0.20 m)

k = 212.13 N/m

Now that we know the spring constant, we can calculate the maximum potential energy stored in the spring (PE_spring) when the mass reaches its highest point:

PE_spring = (1/2) * k * x^2

PE_spring = (1/2) * 212.13 N/m * (0.20 m)^2

PE_spring = 4.243 J

The maximum potential energy (PE_spring) is equal to the maximum kinetic energy (KE_max) at the highest point, which is also the energy the mass has gained from the spring.

KE_max = PE_spring = 4.243 J

Next, we can calculate the height (h) the mass reaches on the inclined plane:

KE_max = m * g * h

4.243 J = 5.0 kg * 9.8 m/s^2 * h

h = 4.243 J / (5.0 kg * 9.8 m/s^2)

h = 0.086 m

The height the mass reaches on the inclined plane is 0.086 m.

Now, we can calculate the distance traveled.

A 5.0 kg object compresses a spring by 0.20 m with a spring constant of 25 N/m. It climbs an incline, reaching a maximum height of 0.0102 m before coming back down, traveling a total distance of 0.0428 m.

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Explanation:

The momentum of the three objects are as follow :

11 kg-m/s, -65 kg-m/s and -100 kg-m/s

Before collision, the momentum of the system is :

\(P_i=11+(-65)+(-100)\\\\P_i=-154\ kg-m/s\)

After collison, they move together. It means it is a case of inelastic collision. In this type of collision, the momentum of the system remains conserved.

It would mean that, after collision, momentum of the system is equal to the initial momentum.

Hence, final momentum = -154 kg-m/s.

Answer:

My Answer is Answer

Explanation:

We can use Coulomb's equation, which states that the force between two point charges is imparted: due to the other two charges (\(\rm Q_1\) and \(\rm Q_2\)) to obtain a net force on the +5.0 nC charge (\(\rm Q_3\)).

\(\rm F = k * |Q_1 * Q_2| / r^2\)

where:

F = force between the charges

k = Coulomb's constant ≈ 9.0 x \(\rm 10^9 N.m^2/C^2\)

\(\rm Q_1\) and \(\rm Q_2\) = magnitudes of the charges

r = distance between the charges

Calculating the forces separately for each pair of charges and then find the net force:

Force between \(\rm Q_3\) and \(\rm Q_1\):

\(\rm Q_3\) = +5.0 nC = +5.0 x \(10^-^9\) C

\(\rm Q_1\) = +6.0 nC = +6.0 x \(10^-^9\) C

\(\rm r_1\) = distance between \(\rm Q_3\) and \(\rm Q_1\) = √[(0.00 m - 0.30 m\()^2\) + (0.00 m - 0.00 m\()^2\)] ≈ 0.30 m

\(\rm F_1\)= k * |\(\rm Q_3\) * \(\rm Q_1\)| / \(\rm r_1^2\)

\(\rm F_1\) = (9.0 x \(10^9\) N·\(\rm m^2/C^2\)) * |(5.0 x \(10^-^9\) C) * (6.0 x \(10^-^9\) C)| / (0.30 \(\rm m)^2\)

\(\rm F_1\)≈ 6.0 N (towards the left)

Force between \(\rm Q_3\) and \(\rm Q_2\):

\(\rm Q_3\) = +5.0 nC = +5.0 x \(10^-^9\) C

\(\rm Q_2\) = -1.0 nC = -1.0 x \(10^-^9\) C

r2 = distance between Q3 and Q2 = √[(0.00 m - 0.00 m)^2 + (0.00 m - 0.10 m)^2] ≈ 0.10 m

\(\rm F_2\) =\(\rm k * |Q_3 * Q_2| / r2^2\)

\(\rm F_2\) = (9.0 x \(\rm 10^9 N.m^2/C^2\)) * |(5.0 x \(10^-^9\) C) * (-1.0 x \(10^-^9\) C)| / (0.10 \(\rm m)^2\)

\(\rm F_2\) ≈ 45.0 N (towards the top)

Now we can sum the forces in the x and y directions to determine the net force:

Net force in the x-direction = \(\rm F_1\) = 6.0 N (to the left)

Net force in the y-direction = \(\rm F_2\) = 45.0 N (upwards)

The Pythagorean theorem can be used to determine the magnitude and direction of the net force.

Magnitude of net force = √(Net force in the x-direction\()^2\)+ (Net force in the y-direction\()^2\)

Magnitude of net force ≈ √(6.0 N\()^2\) + (45.0 N\()^2\)≈ √(36 \(\rm N^2\) + 2025 \(\rm N^2\)) ≈ √(2061 \(\rm N^2\)) ≈ 45.4 N

The direction of the net force is the angle θ:

θ = arctan(Net force in the y-direction / Net force in the x-direction)

θ = arctan(45.0 N / 6.0 N) ≈ arctan(7.5) ≈ 82.9°

As a result, the net force exerted by the other two charges on the +5.0 nC charge has a strength of about 45.4 N and is directed about 82.9° above the negative x-axis (in the upper left direction).

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Answer:

365 m/s

Explanation:

Mrs Finley

Answer:

it is double the temperature change of iron

A parallel circuit can be modelled by connecting the components parallel.

A parallel circuit is a form of electrical circuit in which the components are linked in parallel to one another, each having a separate channel for current flow and being directly connected to the power source. The circuit must first be schematically represented, with the power supply and each component linked in parallel. Next, the total resistance the total current in the circuit by using Ohm's Law must be calculated.

Additionally, it is necessary to confirm that the total current entering the circuit equals the total current leaving the circuit. In a parallel circuit, the total current passing through all of the components equals the current entering the circuit. The voltage drop between each component must then be once more computed using Ohm's Law.

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Answer:

A. Dependent variable

Explanation:

In a graph showing how temperature of a material changes over time, temperature is taken on y-axis and time is taken on x-axis. It shows how temerature altered as the time changes.

In temperature-time graph, temperature is directly dependent on time. With the increase in time, temperature rises, falls or remains constant. It implies that temperature is dependent variable that depend on time.

Hence, the correct option is (A).

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Answer:

a. 0.16240664737515434 moles

b. 67.5 degrees Celcius

Explanation:

a. Use Ideal Gas Equation

PV=nRT

Where P = pressure in pascals, V=Volume in cubic meters, n=number of moles, R is a constant=8.314 J/mol.K and T is temperature in Kelvin.

27C = 273+27=300Kelvin

volume 4L = 0.004m^3

Pressure = 1atm = 101325 Pascal

PV=nRT

101325Pa*0.004m^3=n*8.314J/mol.K*300K

Solving for n from the above you get n=0.16240664737515434 moles

b.Use combined gas law equation

P1*V1/T1=P2*V2/T2

P1= 1atm

V1=4L

T1=27C

P2= 4/16 L =0.25L

P=1*40 atm = 40atm

We do not know T2

USING THE FORMULA

(1atm*4L)/27C = (40atm*0.25L)/T2

(1*4)/27=(40*0.25)/T2

IF you simplify for T2, you get 67.5

Hence final temperature = 67.5 degrees Celcius

The potential energy changes indicated by C and B involve energy lost by the surroundings. Therefore, option B is correct.

Potential energy is the energy possessed by an object due to its position or condition. It is often associated with the potential for the object to do work or undergo a change. The concept of potential energy arises from the interactions between objects or within a system.

Potential energy is converted into other forms of energy, such as kinetic energy (energy of motion) when the object or system undergoes a change or is acted upon by external forces.

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Your question is incomplete, most probably the correct answer is this:

Based on the diagram, which statement explains how energy is conserved during this chemical reaction? (A) is also gained by the surroundings. B. The potential energy changes indicated by C and B involve energy lost by the surroundings. C. The potential energy lost by the reaction system (C) is also lost by the surroundings. D. The potential energy lost by the reaction system (B) is gained by the surrounding​

The magnitude of the total displacement is 20.28 m.

The angle of the total displacement with the x axis is 70.5⁰.

The total displacement of the player is calculated as follows.

Apply cosine rule as shown below;

d² = d₁² + d₂² - 2d₁d₂ cos(θ)

d² = (24.1)² + (7.9²) - (2 x 24.1 x 7.9) cos(52.5)

d² = 411.42

d = √411.42

d = 20.28 m

Apply sine rule as shown below;

d/sinD = d₂/sinD₂

20.28/sin(52.5) = 7.9/sinD₂

25.562 = 7.9/sinD₂

sinD₂ = 7.9/25.562

sinD₂ = 0.309

D₂ = sin⁻¹(0.309)

D₂ = 18⁰

angle with x axis =  18⁰ + θ

                            =  18⁰ +  52.5⁰

                            = 70.5⁰

Thus, the magnitude of the total displacement is 20.28 m.

The angle of the total displacement with the x axis is 70.5⁰.

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The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.

Given:

Object height (h) = 5 cm

Focal length of the convex lens (f) = 10 cm

Object distance (u) = 15 cm (positive since it's on the same side as the incident light)

To determine the nature, position, and size of the image, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values:

1/10 = 1/v - 1/15

To simplify the equation, we find the common denominator:

3v - 2v = 2v/3

Simplifying further:

v = 30 cm

The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.

To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -30 / 15 = -2

The magnification is -2, indicating that the image is inverted and twice the size of the object.

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Answer:

Spring High Tide

When the moon is full or new, the gravitational pull of the moon and sun are combined. At these times, the high tides are very high and the low tides are very low.

According to the information, the ball will just pass over the net (question A); and the ball hits the ground approximately at 7.04 meters from the player and after a time of flight of approximately 1.31 seconds (question B).

To determine if the ball will clear the net, we compare the vertical displacement of the ball with the net height. The ball's initial height is 1.1 meters, and it reaches its highest point during flight. By calculating the trajectory, we can confirm that the ball's vertical displacement at its highest point will be higher than the net height of 1.81 meters, ensuring it clears the net.

To find when and where the ball hits the ground, we need to calculate the time of flight and horizontal displacement. Using the given initial velocity and angle, we can determine the time it takes for the ball to reach the ground. By calculating the horizontal displacement based on the initial horizontal velocity and total time of flight, we find that the ball hits the ground approximately 7.04 meters from the player. The time of flight is approximately 1.31 seconds. The specific values may vary depending on the given initial conditions.

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Answer:

Explanation:

To determine the displacement of the jogger using a graphical method, we can create a vector diagram to represent the individual components of the jogger's motion. We can then find the resulting displacement by adding the vectors end to end.

Assuming that "50cm = 2km" is the scale, we can convert the distances to represent them on the diagram:

2.0 km due east = 100 cm

10 km at 45° north of east = 70.71 cm (using Pythagorean theorem)

0.5 km due north = 25 cm

Next, we can plot the vectors on a coordinate grid, with east as the x-axis and north as the y-axis.

The jogger's first move, 2 km due east, can be represented by a vector starting from the origin and extending 100 cm to the right.

The second move, 10 km at 45° north of east, can be represented by a vector starting from the end of the first vector and extending 70.71 cm up and to the right.

The third move, 0.5 km due north, can be represented by a vector starting from the end of the second vector and extending 25 cm straight up.

Finally, to find the displacement, we add the vectors end to end. The displacement is the vector that starts at the origin and extends to the endpoint of the final vector. The magnitude of the displacement can be found using the Pythagorean theorem.

Using this method, we can determine the displacement of the jogger using a graphical method and the given scale.