answer is 120 cubic meters/second
Briefing
if a river has an average width of 20 m,Width (W)= 20 m
width of 20 m,Depth (D)= 2 m
flowing with a velocity of 3 m/s, Velocity(V)= 3m/s
Discharge = V x D x W
Discharge = 20 × 2 × 3 =120 m3/s
Discharge is 120 cubic meters/second
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Which career professionals are part of the Architecture and Construction career cluster? Check all that apply.
Civil Engineers
Carpenters
Landscapers
Plumbers
Surveyors
Civil Drafters
Answer:
A,B,D,E,F
Explanation:
i took the test
Answer: A, B, D, and F all fit the description of professionals in the
Architecture and Construction career cluster
Explanation: Hope this helps!
the ostringstream member function ____ returns the contents of an ostringstream buffer as a string.
The ostringstream member function "str" returns the contents of an ostringstream buffer as a string. Here's how you can use it:
1. Create an ostringstream object:
ostringstream oss;
2. Write data to the ostringstream buffer using the insertion operator (<<):
oss << "Hello";
oss << " World";
3. Retrieve the contents of the buffer as a string using the "str" member function:
string result = oss.str();
The variable "result" will now contain the string "Hello World".
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Write code that inserts userItem into the output string stream itemsOSS https://brainly.com/question/14546794
An object has a mass of 5.20g. The mass of the object in kg is
Answer:
0.0520kg
Explanation:
divide by 1000
If velocity is Hositive, which would most likely yield a negative acceleration?
O A final velocity that is faster than an initial velocity.
O A time that is less than a half hour.
O An initial velocity that is faster than a final velocity.
O A time that is greater than a half hour.
Answer:
A final velocity that is faster than an initial velocity.
Explanation:
The acceleration of an object is given by :
\(a=\dfrac{v-u}{t}\)
Where
v is final velocity and u is initial velocity
t is time taken
If the final velocity is more than the initial velocity, the acceleration is positive. So, the correct option is (a).
arallel beam of light from a he-ne laser, with a wavelength 633 nm, falls on two very narrow slits 0.070 mm apart
When a parallel beam of light from a He-Ne laser with a wavelength of 633 nm falls on two very narrow slits that are 0.070 mm apart, an interference pattern is observed. This pattern is a result of the phenomenon known as double-slit interference.
In double-slit interference, light waves passing through the two slits interfere with each other, creating alternating regions of constructive and destructive interference. The interference pattern consists of bright fringes (where constructive interference occurs) and dark fringes (where destructive interference occurs).
To determine the position of the bright fringes, we can use the formula for the position of the bright fringe (m) on a screen placed at a distance (D) from the slits:
y = (mλD) / d
Where:
- y is the distance from the central maximum to the mth bright fringe
- λ is the wavelength of the light (633 nm in this case)
- D is the distance from the slits to the screen
- d is the distance between the two slits (0.070 mm in this case)
The interference pattern will have bright fringes spaced at regular intervals on the screen. By calculating the position of these fringes using the formula, you can determine the distance between them.
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the system shown above is released from rest. if friction is negligible, the acceleration of the 4.0 kg block sliding on the table shown above is most nearly
The acceleration of the first block (4 kg) is -9.8 m/s².
The given parameters:
Mass of the first block, m₁ = 4.0 kgMass of the second block, m₂ = 2.0 kgThe net force on the system of the two blocks is calculated as follows;
\(m_2 g - T = m_1 a\)
where;
T is the tension in the connecting string due weight of the first block\(m_2 g - m_1 g = m_1 a\\\\a = \frac{m_2 g - m_1g}{m_1} \\\\a = \frac{g(m_2 - m_1)}{m_1} \\\\a = \frac{9.8(2-4)}{2} \\\\a = -9.8 \ m/s^2\)
Thus, the acceleration of the first block (4 kg) is -9.8 m/s².
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What type of telescope is the hubble space telescope?
The Hubble space telescope is a reflecting telescope.
Mirrors are used by reflecting telescopes, also called reflectors, to collect and concentrate light. The HST features an eight-foot diameter primary mirror and a secondary mirror that focuses the light collected by the primary mirror onto the telescope's scientific equipment. The HST is a Cassegrain telescope, allowing for a compact design due to its concave primary mirror and convex secondary mirror.
Reflecting telescopes are frequently chosen over lens-based ones for space-based telescopes because lenses are more susceptible to distortion and poor image quality caused by thermal expansion and contraction than mirrors are. The HST was put into orbit in the year 1990 and has since been utilised to produce a number of ground-breaking astronomical discoveries.
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The equation for free fall at the surface of some planet (s in meters, t in seconds) is s=1.33t^(2). How long does it take a rock falling from rest to reach a velocity of 27.2(m)/(s) on this planet?
To increase the boiling temperature of 2051 g of water by 1.500 °C, approximately 3.431 grams of NaCl would need to be added.
Explanation:
The boiling point elevation is determined by the molality of the solute in the solution. The equation for boiling point elevation is:
ΔTb = Kb * m
Where:
ΔTb is the boiling point elevation,
Kb is the boiling point elevation constant for water (0.5100 °C/m),
m is the molality of the solute.
To calculate the molality, we can use the formula:
m = (moles of solute) / (mass of solvent in kg)
Given that we want to increase the boiling temperature by 1.500 °C, and the Kb value is 0.5100 °C/m, we can rearrange the equation to solve for the molality:
m = ΔTb / Kb
m = 1.500 °C / 0.5100 °C/m
m ≈ 2.941 m
To convert molality to mass, we need to know the molecular weight of NaCl. The molecular weight of NaCl is approximately 58.44 g/mol.
Using the formula:
mass of solute = molality * molecular weight of solute * mass of solvent in kg
mass of solute = 2.941 m * 58.44 g/mol * 2.051 kg
mass of solute ≈ 3.431 g
Therefore, approximately 3.431 grams of NaCl would need to be added to 2051 g of water to increase the boiling temperature of the solution by 1.500 °C.
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The equation for free fall at the surface of some planet (s in meters, t in seconds) is s=1.33t^(2), the long it take a rock falling from rest to reach a velocity of 27.2(m)/(s) on this planet is 1.414 seconds.
Free fall is a type of movement that an object undergoes when it falls freely under the effect of gravity. Gravity is a force that acts on every object and makes it move towards the center of the earth or any other celestial body. The acceleration due to gravity is expressed as g, and it is equal to 9.8 m/s² on earth. The time it takes a rock falling from rest to reach a velocity of 27.2 m/s on this planet can be calculated by equating the acceleration due to gravity with the given velocity.
The formula for velocity is given by V=U+at, where V is the final velocity, U is the initial velocity, a is the acceleration, and t is the time taken to reach the final velocity. Under free fall, the initial velocity is zero; therefore, the formula can be simplified to V = at.
Substituting the given values in the formula, we get 27.2=1.33t² × g or 27.2=1.33t² × 9.8.
We can simplify this equation to t² = (27.2)/(1.33 × 9.8) or t² = 2.
The square root of 2 is 1.414. Therefore, the time taken for the rock to reach a velocity of 27.2 m/s on this planet is 1.414 seconds.
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Which is one piece of information that astronomers use to calculate the age of the universe?
Answer:
the age of the oldest stars patterns of background radiation how fast distant galaxies are moving away from usExplanation:
According to the NASA, astronomers can estimate how old the universe is by comparing the age of the oldest stars and the rate of expansion of the universe. The rate of expansion of the universe is based on the Big Bang theory and it states that our universe is continuously expanding since it first developed. Astronomers measure Cosmic Microwave Background radiation resulting from the Big Bang.
Answer:
Patterns of background radiation
Explanation: well astronomy states that they are able to tell by the radiation gaps
i’m willing to give anybody extra points plus brainliest if anybody is willing to help me with this. please help!! this is due soon.
1. The box will move to the right with a force of 50 N when a 75 N force is applied to the left.
2. The box will not move if a 50 N force us applied to the left.
For Balanced, B or Unbalanced forces, U the correct option are:
B A person jogging at a constant speedU A car accelerating at a green light.U Pushing a lawnmower across the yardB A cookie sitting on a plate.U Slowing down to stop at a red light.U A bowling ball knocking over pins.B A book sitting on a shelf.U A linebacker tackling a running back.B A person sitting on a chair.B A plane flying at a constant speed.What are balanced and unbalanced?Balanced forces are forces that do not produce an acceleration of an object. Net force will be zero.
Unbalanced forces are forces that produce an acceleration of a body. Net force will be greater than zero.
Considering the boxes:
1. Net force = 50 N
Forces to the left = 25 N + x
Forces to the right = 50 N
Net force = Force to the left + force to the right
50 N = 25 N + x - 50
x = 75 N
2. Net force = 0 N
Forces to the left = 75 N + x
Forces to the right = 125 N
Net force = Force to the left + force to the right
0 N = 75 N + x -125
x = 50 N
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a body of mass 0.2kg is whirled round a horizontal circle by a string inclined at 30 degrees to the vertical calculate <br />a. tension in the string<br />b. speed of the body in the circle<br />
Answer:
a) T = 2.26 N, b) v = 1.68 m / s
Explanation:
We use Newton's second law
Let's set a reference system where the x-axis is radial and the y-axis is vertical, let's decompose the tension of the string
sin 30 = \(\frac{T_x}{T}\)
cos 30 = \(\frac{T_y}{T}\)
Tₓ = T sin 30
T_y = T cos 30
Y axis
T_y -W = 0
T cos 30 = mg (1)
X axis
Tₓ = m a
they relate it is centripetal
a = v² / r
we substitute
T sin 30 = m\(\frac{v^2}{r}\) (2)
a) we substitute in 1
T = \(\frac{mg }{cos 30}\)
T = \(\frac{ 0.2 \ 9.8}{cos \ 30}\)
T = 2.26 N
b) from equation 2
v² = \(\frac{T \ sin 30 \ r}{m}\)
If we know the length of the string
sin 30 = r / L
r = L sin 30
we substitute
v² = \(\frac{ T \ sin 30 \ L \ sin 30}{m}\)
v² = \(\frac{TL \ sin^2 30}{m}\)
For the problem let us take L = 1 m
let's calculate
v = \(\sqrt{ \frac{2.26 \ 1 \ sin^230}{0.2} }\)
v = 1.68 m / s
The coetticient of friction between a block and the surface it slides across is 0.360. The block has a mass of 150 kg
What force is required to accelerate the block 0.5 m/a^2.
The friction between the b;ock and surface is given by mass and accelerartion.
Force = mass * acceleration
Based on information from the graph above, what can be concluded about the relationship between the temperature of a solvent and the solubility of a solute?
A. No conclusions can be drawn.
B. For most solutes, as temperature increases, the solubility is unaffected.
C. For most solutes, as temperature increases, the solubility increases.
D. For most solutes, as temperature increases, the solubility decreases.
What is number 5?! I’m so confused.
Answer:
i think it's A
Explanation:
Answer:
The answer is A
Explanation:
The cable of a crane is lifting a 950 kg girder. The girder increases its speed from 0.25 m/s to 1.25 m/s in a distance of 2.7 m. Part A How much work is done by gravity? Express your answer with the appropriate units. WgValue Wor Units Submit Request Answer PartB How much work is done by tension? Express your answer with the appropriate units.
the work done by tension is Wt = KEf - KEi = 714.05 J (joules).
Part A: Gravity does not do any work in this scenario as it is a conservative force and the girder is not changing height. Therefore, Wg = 0 J (joules).
Part B: The work done by tension can be calculated using the work-energy principle. The change in kinetic energy of the girder is equal to the work done by tension.
The initial kinetic energy of the girder is KEi = (1/2)mv^2 = (1/2)(950 kg)(0.25 m/s)^2 = 29.7 J.
The final kinetic energy of the girder is KEf = (1/2)mv^2 = (1/2)(950 kg)(1.25 m/s)^2 = 743.75 J.
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If a bullet of mass 50 gm is moving with the velocity of 720 km/hr. Calculate its kinetic energy. Ans: here, mass (m)= 50 gm = 50/1000 kg = 0.05 kg velocity (v) = 720 km/hr= 720×1000/60×60=200m/s kinetic energy = ? We know, K.E.= 1/2 mv^2 = 1/2 × 0.05×(200)^2 = 0.05×40000/2 = 1000j ans. Is it correct???????
Answer:
yes 1000 j as I posted on the same Q elsewhere
Explanation:
most interstellar hydrogen atoms emit only radio waves at a wavelength of 21cm, but some hydrogen clouds emit profuse amounts of visible light. what causes this difference?
The difference in the emission of interstellar hydrogen atoms between radio waves at a wavelength of 21cm and visible light is due to the physical conditions of the hydrogen clouds.
Hydrogen atoms emit radio waves at a wavelength of 21cm when their electrons change their spin state from parallel to anti-parallel. This transition corresponds to a change in energy that is characteristic of hydrogen atoms in interstellar space, where the density of particles is low and the temperature is cold.
However, some hydrogen clouds can emit visible light when the conditions are right for the excitation of the hydrogen atoms. This can happen, for example, when the density of particles is high enough for collisions to excite the electrons of the hydrogen atoms to higher energy levels, and then they release that energy as visible light when they return to their ground state.
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A ball is released from the bottom of an elevator which is travelling upward with a velocity of 6 ft/s. If the ball strikes the bottom of the elevator shaft in 3 s. Determine the height of the elevator from the bottom of the shaft at the instant the ball is released
Explanation:
df = do + vot + 1/2 at ^2 do = what you are looking for df = ground = 0
0 = do + 6 (3 ) + 1/2 ( -9.81) (3^2)
do = 26.1 m
At a certain instant, a moving object comes to momentary rest. Is it accelerating at that moment?
No, the object is not accelerating at the moment it comes to rest. Acceleration is defined as the rate of change of velocity with respect to time. When an object comes to momentary rest, its velocity is zero. Therefore, there is no change in velocity over time, and as a result, the object has zero acceleration at that specific moment.
Acceleration can be positive, negative, or zero. Positive acceleration occurs when an object's velocity is increasing, negative acceleration (deceleration) occurs when an object's velocity is decreasing, and zero acceleration occurs when an object's velocity remains constant or when the object is at rest.
When an object comes to momentary rest, it means its velocity is changing from a non-zero value to zero. However, at that instant, the velocity is momentarily zero, and there is no further change in velocity. Therefore, the object has zero acceleration at that specific moment.
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show that the following units are equivalent: 1v × 1a = 1 j/s.
We can prove that 1 V × 1 A is equivalent to 1 J/s using the representation of Volts, Amperes, and Joules in Ohms law.
1 volt (V) is represented as the potential difference among two points in a circuit that holds one ampere (A) of current when a force of one watt (W) is scattered between those points.
1 ampere (A) is described as the continuous current that, if held in two consecutive similarity conductors of indefinite length, and positioned 1 meter asunder in a vacuum, would produce between these conductors a force similar to 2 × 10^-7 newton per meter of length.
1 joule (J) is represented as the quantity of work done when a force of one newton (N) is applied over a distance of one meter (m).
We can use the formula for power to relate the units of voltage and current to the unit of power:
Power (P) = Voltage (V) × Current (I)
P = (1 W) × (1 A) = 1 J/s
Therefore we can prove that 1 V × 1 A is equivalent to 1 J/s.
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An object moving with a speed of 35 m/a and has a kinetic energy of 1500j, what is the mass of the object
Explanation:
Speed or velocity (V) = 35 m/s
Kinetic energy (K. E) = 1500 Joule
mass (m) = ?
We know
K.E = 1/2 * m * v²
1500 = 1/2 * m * 35²
1500 * 2 = 1225m
m = 3000 / 1225
m = 2.45 kg
The mass of the object is 2.45 kg
Hope it will help :)
[04.04] Which best describes the current atomic theory?
Create a poem or a song explaining the principles of force and motion. Use at least 5 of these terms in your work: inertia, unbalanced force, balanced force, net force, gravity, speed, acceleration, velocity, Newton’s Laws.
Answer:
the laws of motion is what keeps everything going an back without gravity they couldn't been no us . let them say what they was but newton knows best if they want to come an say newtons discovery changed the world without him we couldn't rest
Does a neutral object contain no electric charge at all?
Bonjour à toi,
QUESTION)An electrically neutral object does not mean that it has no electrical charge. If today we find some elementary particles without electric charge (Higgs Boson, photon and gluon), the neutrality of the atom and molecules, or more globally of matter is due to various processes. An atom is electrically neutral because the electric charges that compose it compensate each other (as much negative charge, the electron, as positive, the proton). Ionic molecules arrange themselves so that the electric charges that compose them compensate each other.
a ______________ is a voltage, frequency, pulse, or phase change in an analog transmission.
Answer:
A modulation is a voltage, frequency, pulse, or phase change in an analog transmission.
Explanation:
A modulation is a voltage, frequency, pulse, or phase change in an analog transmission. It is a process by which a signal, such as an audio or video signal, is modified in order to be transmitted over a longer distance.
Some key points about modulation include:
- Modulation allows analog signals to be transmitted over long distances without degradation.
- There are several types of modulation, including amplitude modulation (AM), frequency modulation (FM), and phase modulation (PM).
- In AM, the amplitude of the signal is varied in order to carry information.
- In FM, the frequency of the signal is varied in order to carry information.
- In PM, the phase of the signal is varied in order to carry information.
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A modulation is a voltage, frequency, pulse, or phase change in an analog transmission.
Modulation is the process of changing a signal's characteristics to encode information for transmission. In analog transmissions, the signal is continuous and varies in amplitude, frequency, or phase.
Modulation techniques include, amplitude modulation (AM), frequency modulation (FM), and phase modulation (PM), among others. These techniques are used in radio, television, and telephone systems, among others.
The modulation process converts the analog signal into a format that can be transmitted over a channel, such as a wire or radio frequency, and then demodulated at the receiving end to recover the original signal.
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an astronaut travels to a distant star with a speed of .36c what is the distance covered on the return trip
An astronaut travels to a distant star with a speed of .36c. The distance covered on the return trip is 394.2 × 10⁸.
What is speed?A scalar quantity, speed is defined as the size of the change in an object's location over time or the size of the change in an object's position per unit of time. The instantaneous speed is the upper limit of the average speed as the duration of the time interval approaches zero. The average speed of an item in a period of time is equal to the distance traveled by the object divided by the duration of the period. Velocity and speed are not the same thing.
The parameters of speed are time divided by distance. The metre per second (m/s), the SI unit of speed, is more frequently used in everyday life than the kilometer per hour (km/h).
The distance covered on the return trip can be found using the equation: x = vt,
where x is the distance,
v is the velocity and
t is the time of travel.
Let's assume the astronomer was traveling for 1 year (or 365 days). Then the equation can be written as
x = (0.36)(365)(3 × 10⁸).
Solving for x, we get that the return trip covered x = 394.2 × 10⁸.
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An astronaut travels to a distant star at a speed of 0.36c (where c represents the speed of light). Assuming the distance to the star remains constant and the astronaut takes the same route back.
the distance covered on the return trip would be equal to the distance covered during the initial journey to the star. An astronaut is a person who is trained to travel and perform tasks in outer space. Astronauts are employed by space agencies, such as NASA in the United States or the European Space Agency, and typically have backgrounds in science or engineering. They undergo rigorous training in subjects such as space physiology, space medicine, and weightlessness, as well as in the operation of spacecraft, spacewalks, and scientific experiments. Astronauts have traveled to the moon, performed spacewalks, and conducted research on the International Space Station. They must be able to work effectively in confined and hazardous environments and possess excellent physical and mental health. Being an astronaut is a highly competitive and prestigious career, with a select few chosen for each space mission.
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how can we take advantage of waste materials
Answer:
we can incinerate waste materials and use the product as fuel rather than dumping them. It may produce carbon dioxide but we can create a machine that can convert carbon into energy.
how does a pendalum conserve energy
Glowing colors in the polar atmospheres are the result of
meteors entering the atmosphere
charged particles from the sun
dust from volcanic activity
Answer:
Charged Particles from the sun
Explanation:
A car starts from rest on a curve with a radius of 150 m and tangential acceleration of 1.3 m/s2 .Through what angle will the car have traveled when the magnitude of its total acceleration is 3.0 m/s2 ?
We can start by using the formula for tangential acceleration:
a_t = r * α
How to use tangential acceleration ?where a_t is the tangential acceleration, r is the radius of the curve, and α is the angular acceleration. Rearranging this equation, we get:α = a_t / r = 1.3 m/s^2 / 150 m = 0.00867 rad/s^2
Next, we can use the formula for the magnitude of total acceleration:a_total = √(a_t^2 + a_c^2)
where a_c is the centripetal acceleration. We can rearrange this equation to solve for a_c:
a_c = √(a_total^2 - a_t^2) = √(3.0^2 - 1.3^2) = 2.5 m/s^2
Now, we can use the formula for centripetal acceleration:a_c = r * ω^2
where ω is the angular velocity. Rearranging this equation, we get:
ω = √(a_c / r) = √(2.5 m/s^2 / 150 m) = 0.1155 rad/s
Finally, we can use the formula for angular displacement:
θ= ω^2 * t / 2
where t is the time elapsed. Since the car starts from rest, we can use the formula for initial velocity and acceleration:v_i = 0
a = a_t
to find the time it takes for the car to reach the required total acceleration of 3.0 m/s^2:
a = (v_f - v_i) / t
t = (v_f - v_i) / a
t = v_f / a
where v_f is the final velocity. Using the formula for final velocity and the fact that the car starts from rest, we get:
v_f^2 = 2 * a_t * θ
v_f = √(2 * a_t * θ)
t = √(2 * θ / a_t)
Substituting the values we have calculated, we get:t = √(2 * θ / 1.3) = √(1.5385 * θ)
t = v_f / a = √(2 * a_t * θ) / a_t = √(2 * θ / 1.3)
Setting these two expressions for t equal to each other, we get:
√(1.5385 * θ) = √(2 * θ / 1.3)
Squaring both sides and solving for θ, we get:
θ = 4.89 radians
Therefore, the car will have traveled through an angle of 4.89 radians when the magnitude of its total acceleration is 3.0 m/s^2.
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