if a radio is bought for rs 1000 is sold for rs 1500 find what is the profit percentage?
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Answer:

not 24 i got an 80 its not 24 though

Step-by-step explanation:

i dont know  how this helps but there you go

Answer:

To solve this problem, we can use algebra. Let x be the number of student tickets sold and y be the number of adult tickets sold. We know that:

x + y = 500 (the total number of tickets sold)

5x + 10y = 3000 (the total revenue from ticket sales)

We can use the first equation to solve for one of the variables in terms of the other. For example, we can use the first equation to solve for y in terms of x:

y = 500 - x

Now we can substitute this expression for y into the second equation:

5x + 10(500 - x) = 3000

5x + 5000 - 10x = 3000

-5x = -2000

x = 400

So, the number of student tickets sold is 400. The answer is d) 400

Total 400 students attended the play.

A function is a relation between a dependent and independent variable.

Mathematically, we can write → y = f(x) = ax + b.

Given is that student tickets cost $5 each and adult tickets cost $10 each. The total ticket sales were $3,000 for 500 tickets.

We can write the system of equations as -

5x + 10y = 3000

x + y = 500

Now -

x = 500 - y

So -

5(500 - y) + 10y = 3000

2500 - 5y + 10y = 3000

5y = 500

y = 100

x = 400

Therefore, total 400 students attended the play.

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Answer: y=3x-2

Step-by-step explanation:

Given a point and slope, all we need to do a find the y-intercept. What we do a to plug in (x,y).

-8=3(-2)+b       [multiply]

-8=-6+b           [add both sides by 6]
b=-2

This gives the final equation of y=3x-2.

Answer: total books = 8k

Step-by-step explanation:

k = books on each shelf

total books = bookcases * shelves per bookcase * books per shelf (k)

total books = 1 * 8 * k

total books = 8k

Answer:

8k

Step-by-step explanation:

To find the total number of books, take the number of shelves and multiply by the number of books on each shelf

8*k

The total number of books is 8k

Answer:

the value is 2.2721803393 x 1400

According to the information provided, statistics A seems to be an unbiased estimator of the population parameter.

Statistic A is the objective estimator of the population parameter, it should be emphasized. This is as a result of its 75 population parameter being its focal point. Statistic A would provide a more accurate estimate of the population parameter. This is due to the sample mean being 75, which is also the population mean. Given that statistic D is equal to the population means, it would serve as a more accurate estimate of the population parameter. The final point to make is that statistic C has no distribution shape.

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The general solution is given by: y = c1cos(5x) + c2sin(5x) + 1/25(- cos(ln(sec5x))) + 5xsin(5x)

The most general solution to the original nonhomogeneous differential equation can be found by adding the homogeneous solution and the particular solution together. That is,

y = y_h + y_p

= c1cos(5x) + c2sin(5x) + 1/25(- cos(ln(sec5x))) + 5xsin(5x)

This is the most general solution to the original nonhomogeneous differential equation. We can use the arbitrary constants c1 and c2 to find specific solutions for different initial conditions. The general solution is given by:

y = c1cos(5x) + c2sin(5x) + 1/25(- cos(ln(sec5x))) + 5xsin(5x)

This is the final answer. Note that we have used the terms "general solution" and "arbitrary constants" in our answer, as instructed.

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(a) If sn ≥ a for all but finitely many n, then lim sn ≥ a. (b) If sn ≤ b for all but finitely many n, then limit sn ≤ b. (c) If all but finitely many sn belong to [a, b], then lim sn belongs to [a, b].

Define limit ?

In mathematics, the limit of a sequence or function represents the value that the sequence or function approaches as its input or index approaches a certain value or goes to infinity.

(a) To prove that if sn ≥ a for all but finitely many n, then lim sn ≥ a, we can use the definition of convergence.

Assume that sn ≥ a for all but finitely many n. By the definition of convergence, lim sn = L exists if, for any ε > 0, there exists N such that |sn - L| < ε for all n ≥ N.

Let's consider the case where L < a. Since sn ≥ a for all but finitely many n, there exists a large enough N such that for n ≥ N, sn ≥ a. However, this contradicts the assumption that lim sn = L, as there are values of sn greater than or equal to a for n ≥ N. Therefore, we can conclude that L cannot be less than a.

Hence, if sn ≥ a for all but finitely many n, the limit lim sn must be greater than or equal to a, i.e., lim sn ≥ a.

(b) The proof for the second statement follows a similar approach.

Assume that sn ≤ b for all but finitely many n. By the definition of convergence, lim sn = L exists if, for any ε > 0, there exists N such that |sn - L| < ε for all n ≥ N.

Let's assume that L > b. Since sn ≤ b for all but finitely many n, there exists a large enough N such that for n ≥ N, sn ≤ b. However, this contradicts the assumption that lim sn = L, as there are values of sn less than or equal to b for n ≥ N. Therefore, L cannot be greater than b.

Hence, if sn ≤ b for all but finitely many n, the limit lim sn must be less than or equal to b, i.e., lim sn ≤ b.

(c) From parts (a) and (b), we have shown that if sn ≥ a for all but finitely many n, then lim sn ≥ a, and if sn ≤ b for all but finitely many n, then lim sn ≤ b.

Now, suppose that all but finitely many sn belong to the closed interval [a, b]. This implies that sn ≥ a for all but finitely many n (since they belong to [a, b]), and sn ≤ b for all but finitely many n (since they belong to [a, b]).

From parts (a) and (b), we can conclude that lim sn ≥ a and lim sn ≤ b. Therefore, the limit of sn belongs to the closed interval [a, b].

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Answer:

\(2nd \: term = - 9 + ( - 2) \\ = - 11 \\ 3rd \: term = - 11 +( - 2) \\ = - 13 \\ 4th \: term = - 13 + ( - 2) \\ = - 15 \\ \\ ..........\)

Answer:

D

Step-by-step explanation:

4C1*5C1*6C1*8C1

=960

Gurdip's total pay is (2x - 3)(x + 2) and Jumrang's total pay is x(2x + 3) in algebraic form.

Given that Gurdip is paid RM3 per hour less than twice Jumrang's pay, we can represent Gurdip's hourly pay as (2x - 3), where x is Jumrang's hourly pay.

Now, we are asked to find Gurdip's pay if he works (x + 2) hours and Jumrang's pay if he works (2x + 3) hours.

To calculate Gurdip's total pay, we multiply his hourly pay by the number of hours worked:

Gurdip's pay = (2x - 3)(x + 2)

Similarly, we can calculate Jumrang's total pay by multiplying his hourly pay by the number of hours worked:

Jumrang's pay = x(2x + 3)

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Answer:

52800

Step-by-step explanation:

Answer:

520800

Step-by-step explanation:

ive done this on.

Answer:

3cm

Step-by-step explanation:

those double hashes on those 5 sides mean they are equal. so essentially you have 5 sides that measure 3/10cm and one side that measures 1 1/2cm.

3/10 * 5 = 15/10 = 1 1/2cm

1 1/2cm + 1 1/2cm = 3cm

The independent variable for Scenario A is given as follows:

a. The employee benefits package.

In the case of a relation, we have that the independent and dependent variables are defined by the standard presented as follows:

In the context of this problem, we have that the input and the output of the relation are given as follows:

Hence the independent variable for Scenario A is given as follows:

a. The employee benefits package.

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Hey there! :)

Answer:

r ≈ 4.38 cm.

Step-by-step explanation:

Find the radius by working backwards using the equation A = πr²:

Given:

A = 60.24 cm²

π = 3.14

Plug these into the equation:

60.24 = 3.14r²

Divide both sides by 3.14:

19.185 = r²

Take the square root of both sides:

r ≈ 4.38 cm.

Answer:

20%

Step-by-step explanation:

20/25 = blue

This means 5/25 of the balls in the bag are NOT blue

(25-20 = 5)

We need to convert 5/25 to a percentage

\(\dfrac{5}{25} = \dfrac{5\times4}{25\times4}=\dfrac{20}{100}\)

% = per cent

"per" means "out of"

"cent" means "one hundred"

so

20/100 = 20%

Answer:

8

Step-by-step explanation:

Let x be the number added to both numerator and denominator.

Initial fraction=7/17

After adding x to both the numerator and the denominator

Then ,we get fraction=3/5

We have to find the value of x.

According to question

\(\frac{7+x}{17+x}=\frac{3}{5}\)

\(5(7+x)=3(17+x)\)

\(35+5x=51+3x\)

\(5x-3x=51-35\)

\(2x=16\)

\(x=\frac{16}{2}=8\)

The inequality expression given as |2x - 6 | < 0  has a solution of x > 3

From the question, the inequality is given as

|2x-6|<0

This gives

|2x - 6 | < 0

Remove the absolute bracket

So, we have the following representation

2x - 6 > 0

Add 6 to all sides of the inequality

So, we have

2x - 6 + 6 > 0 + 6

Evaluate the like terms

So, we have

2x > 6

Divide through by 2

x > 3

Hence, the solution to the expression is x > 3

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The number of cookies in the jar initially was 42

To find out how many cookies were in the jar initially, we can use algebra to represent the problem. Let x be the number of cookies in the jar initially. After Latoya took half of the cookies, Mark took 1/3 of the remaining cookies, Kandi took 1/4 of the remaining cookies, and Shannon took 1 cookie, there are 2 cookies left in the jar.

We can use this information to set up the equation:

x/2 - (x/2)/3 - (x/2)/4 - 1 - 2 = 0.

By solving this equation, we get x = 42. This means there were 42 cookies in the jar initially. To find out how many cookies were there before Latoya came, we just add the 2/3 of a cookie that was left over to the 2 whole cookies we know of.

So, 42+2/3 = 42.67 which means 42 cookies were there before Latoya came.

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To solve this pair of simultaneous equations using the method of substitution, we will solve one equation for one variable in terms of the other variable and then substitute that expression into the other equation.

Let's solve the first equation, x + 4y = -4, for x in terms of y:

x = -4 - 4y

Now we will substitute this expression for x into the second equation, 3y - 5x = -1:

3y - 5(-4 - 4y) = -1

Simplifying this equation, we get:

3y + 20 + 20y = -1

Combining like terms:

23y = -21

Dividing both sides by 23:

y = -21/23

Now we can substitute this value for y back into either of the original equations to solve for x. Let's use the first equation:

x + 4(-21/23) = -4

Multiplying both sides by 23:

23x - 84 = -92

Adding 84 to both sides:

23x = -8

Dividing both sides by 23:

x = -8/23

So the solution to the pair of simultaneous equations x + 4y = -4 and 3y - 5x = -1 is x = -8/23, y = -21/23.

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Answer:

Step-by-step explanation:

Option D is the correct answer

The next term is - 27

Answer:

she has rode 16 miles this week

Step-by-step explanation:

3 miles on monday 3 times that many on tuesday plus 4 miles one wensaday add them all up

3 times 3 is 9 plus 3 is 12 plus 4 is 16 there fore 16 miles in totale

sorry for my speling erros

She rode a total distance of 16 miles this week.

An expression in mathematics is a combination of terms both constant and variable. For example, we can write the expressions as -

2x + 3y + 5

2z + y

x + 3y

The distance rode by Lexi per day is mentioned below -

Monday - Lexi rode 3 miles on a bike.

Tuesday - Lexi rode 3 times more than she did Monday.

Wednesday - Lexi rode an additional 4 miles.

We can write the expression to find the total distance in miles covered by Lexi as -

d = d{M} + d{T} + d{W}

d = 3 + (3 + 3) + 4

d = 3 + 6 + 4

d = 13 miles

Therefore, she rode a total distance of 16 miles this week.

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Answer:

18 = 3y - 39

3y = -39+18 = -21

3y - 21

y = 21 - 3

y = 19

Under the consideration of collinearity of two line segments, the length of the line segment ST is equal to 13.

According to the statement seen in this question, the line segments RT and  ST are collinear to each other. Mathematically speaking, the length of the line segment ST can be found by using the following formula:

RT = RS + ST

ST = RT - RS

ST = 19 - 6

ST = 13

Under the consideration of collinearity of two line segments, the length of the line segment ST is equal to 13.

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Answer:

The volume of metal used in making 2.4 m long pipe is 1.58 cm³

Step-by-step explanation:

From the question,

The external radius is 11cm.

Also, the thickness of the pipe is 1cm, then we can determine the internal radius.

Internal radius = External radius - the thickness

Internal radius = 11cm - 1cm

Internal radius = 10cm

Now, to find the volume of metal used in making the long pipe,  

The volume of metal used in making the long pipe is the difference between the volume of the external cylinder and the volume of the internal cylinder.

Volume of a cylinder is given by the formula below

\(V = \pi r^{2}h\)

Where \(V\) is the volume of the cylinder

\(\pi\) is constant ( Take \(\pi\) = 3.14)

\(r\) is the radius

and \(h\) is the height

Let the radius of the external cylinder be R,

then, R = 11 cm = 0.11 m

and let the radius of the internal cylinder be r

then, r = 10 cm = 0.10 m

Then,

The volume of metal used in making the long pipe = \(\pi R^{2}h - \pi r^{2}h\)

= \(\pi (R^{2} - r^{2})h\)

= \(3.14\times(0.11^{2} - 0.10^{2})\times2.4\)

= \(3.14\times(0.0121 - 0.01)\times2.4\\\)

= \(3.14\times(0.0021 )\times2.4\\\)

= 0.0158 m³ or 1.58 cm³

Hence, the volume of metal used in making 2.4 m long pipe is 1.58 cm³

If there is a 0.41% chance that an American citizen will die from falling, then the probability  that you will not die from a fall is 99.59%

The chances of an American citizen will die from falling = 0.41%

The probability is the ratio of number of favorable outcomes to the total number of outcomes

The equation will be

The probability = Number of favorable outcomes / Total number of outcomes

The probability  that you will not die from a fall = 1 -  The chances of an American citizen will die from falling

Substitute the values in the equation

The probability  that you will not die from a fall = 1 - 0.41

= 99.59%

Therefore, the probability  that you will not die from a fall is 99.59%

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a) This is a valid recursive definition of a function f from the set of nonnegative integers to the set of integers. The formula for f(n) is f(n) = f(n-1) for n ≥ 1. To prove that this formula is valid, we can use mathematical induction.

Base case: f(0) = 1, which is true.

Inductive step: Assume that f(k) = f(k-1) for some k ≥ 1. Then f(k+1) = f(k) = f(k-1) = f(k+1-1), which is true.

Therefore, the formula is valid.

b) This is a valid recursive definition of a function f from the set of nonnegative integers to the set of integers. The formula for f(n) is f(n) = 2f(n-3) for n ≥ 3. To prove that this formula is valid, we can use mathematical induction.

Base case: f(0) = 1, f(1) = 0, f(2) = 2, which are all true.

Inductive step: Assume that f(k) = 2f(k-3) for some k ≥ 3. Then f(k+1) = 2f(k+1-3) = 2f(k-2) = 2(2f(k-3)) = 2f(k), which is true.

Therefore, the formula is valid.

c) This is not a valid recursive definition of a function f from the set of nonnegative integers to the set of integers because the recursive step does not define f(n) for all n ≥ 0.

d) This is a valid recursive definition of a function f from the set of nonnegative integers to the set of integers. The formula for f(n) is f(n) = 2f(n-1) for n ≥ 1. To prove that this formula is valid, we can use mathematical induction.

Base case: f(0) = 0, f(1) = 1, which are both true.

Inductive step: Assume that f(k) = 2f(k-1) for some k ≥ 1. Then f(k+1) = 2f(k+1-1) = 2f(k) = 2(2f(k-1)) = 2f(k+1-1), which is true.

Therefore, the formula is valid.

e) This is a valid recursive definition of a function f from the set of nonnegative integers to the set of integers. The formula for f(n) is f(n) = f(n-1) if n is odd and n ≥1 and f(n) = 2f(n-2) if n≥ 2. To prove that this formula is valid, we can use mathematical induction.

Base case: f(0) = 2, which is true.

Inductive step: Assume that f(k) = f(k-1) if k is odd and k ≥ 1 and f(k) = 2f(k-2) if k ≥ 2.

If k is odd, then f(k+1) = f(k) = f(k-1) = f(k+1-1), which is true.

If k is even, then f(k+1) = 2f(k+1-2) = 2f(k) = 2(2f(k-2)) = 2f(k+1-2), which is true.

Therefore, the formula is valid.

a) The formula for f(n) is (-1)ⁿ and b) The formula for f(n) is f(n) = 2k.

a) The proposed definition of function f is a valid recursive definition as it defines f(0) as 1 and then uses the previous value of f(n-1) to determine the value of f(n) for all n greater than or equal to 1. To find the formula for f(n), we can use induction. We can see that f(1) = -f(0) = -1, f(2) = -f(1) = 1, f(3) = -f(2) = -1, and so on. Thus, we can see that f(n) alternates between 1 and -1, depending on whether n is odd or even. Therefore, the formula for f(n) is (-1)ⁿ.

b) The proposed definition of function f is also a valid recursive definition as it defines f(0), f(1), and f(2), and then uses the previous value of f(n-3) to determine the value of f(n) for all n greater than or equal to 3. To find the formula for f(n), we can again use induction. We can see that f(3) = 2f(0) = 2, f(4) = 2f(1) = 0, f(5) = 2f(2) = 4, f(6) = 2f(3) = 4, f(7) = 2f(4) = 0, and so on.

Thus, we can see that f(n) alternates between 0 and 2, depending on whether n is congruent to 1 or 2 mod 3. Therefore, the formula for f(n) is f(n) = 2k, where k is the number of times n-3 can be divided by 3 before reaching a number less than or equal to 2. This formula is valid as it agrees with our observations and satisfies the recursive definition.

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The grade point average received by hector is 3.75.

Your grade point average (GPA) is calculated by dividing the total number of credits you have earned in high school by the sum of all of your course grades. The majority of colleges and secondary schools use a 4.0 scale to report grades. A perfect score, or an A, is a 4.0.

The unit value for each course in which a student obtains one of the grades mentioned above is multiplied by the grade point total for that grade to determine the GPA. Then, divide the sum of these products by the sum of the units. The cumulative GPA is calculated by dividing the total grade points by the total number of units.

3 a and one is B received by Hector.

The A = 4.0, B = 3.0, C = 2.0, D = 1.0 is given by college

We have GPA= A+A+A+B/4

GPA=4+4+4+3/4

GPA= 15/4

GPA=3.75

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Complete question

Hector Ramirez received three A's and one B in his college courses. What is his grade point average? Assume each course is three credits. A = 4.0, B = 3.0, C = 2.0, D = 1.0