if a planetary body (such as a rocky body bigger than about 400 km diameter) is big enough, it will be spherical. why is this:
Answers
The larger objects are rounded essentially comes down to gravity. The gravitational pull of an object will always be directed toward its mass centre. The more massive and gravitational attraction something has, the bigger it is.
The strength of the object itself opposes such force for solid objects. For instance, you are not drawn into the centre of the Earth by the downward force of gravity. The reason for this is that the ground is pushing back up at you; it is too strong to allow you to sink through it. The power of Earth has its limits, though. Imagine a massive mountain, like Mount Everest, becoming bigger and bigger as the planet's plates collide. Everest starts to sink as it gets taller due to its weight increasing. The mountain's height will be constrained as a result of the additional weight forcing it deeper into the Earth's mantle.
Hence, planets moves in fixed orbits.
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Related Questions
someon figure this out answer for me
Answers
Answer:
D. chemical control
Explanation:
The reason for using chemical control as last resort in IPM is:
1) Impact is very high
2) The response is immediate
write an expression for the magnitude of the force, f, exerted on the firefighter by the pole. answer in terms of the variables from the problem statement as well as g for the acceleration due to gravity.
Answers
The expression for the magnitude of the force exerted on the firefighter by the pole can be expressed as F = mg + ma.
Where m is the mass of the firefighter,
g is the acceleration due to gravity, and
a is the acceleration of the pole
In order to find an expression for the magnitude of the force, F, exerted on the firefighter by the pole, we need to consider the forces acting on the firefighter.
According to Newton's second law of motion, the force acting on an object is equal to its mass multiplied by its acceleration. In this case, the forces acting on the firefighter are the gravitational force, which is pulling the firefighter downwards with a force of mg, and the force exerted on the firefighter by the pole, which is pushing the firefighter upwards with a force of ma. Therefore, the total force acting on the firefighter is given by the sum of these two forces, which is: F = mg + ma
Thus, this expression gives us the magnitude of the force exerted on the firefighter by the pole. Here, m is the mass of the firefighter, g is the acceleration due to gravity, and a is the acceleration of the pole. if the pole is not accelerating (i.e., if a = 0), then the expression reduces to F = mg, which is the gravitational force acting on the firefighter.
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In the laboratory, a student determines the specific heat of a metal. She heats 18.6 grams of titanium to and then drops it into an insulated cup containing 80.5 grams of water at . When thermal equilibrium is reached, she measures the final temperature to be . Assuming that all of the heat is transferred to the water, she calculates the specific heat of titanium to be _____
Answers
Explanation:
To solve for the specific heat of titanium, we can use the formula:
Q = mcΔT
Where Q is the heat transferred, m is the mass of the substance, c is the specific heat, and ΔT is the change in temperature.
First, we need to calculate the amount of heat that is transferred from the titanium to the water:
Q = mTi * cTi * ΔTTi + mH2O * cH2O * ΔTH2O
Where mTi is the mass of titanium, cTi is the specific heat of titanium, mH2O is the mass of water, cH2O is the specific heat of water, ΔTTi is the change in temperature of the titanium, and ΔTH2O is the change in temperature of the water.
Since the experiment is carried out in an insulated cup, we can assume that there is no heat loss to the surroundings. Therefore, the amount of heat lost by the titanium is equal to the amount of heat gained by the water:
mTi * cTi * ΔTTi = - mH2O * cH2O * ΔTH2O
Note that we have placed a negative sign in front of the water's heat capacity because it is gaining heat, whereas the titanium is losing heat.
Now we can substitute the values given in the problem:
mTi = 18.6 g
cH2O = 4.18 J/g°C
mH2O = 80.5 g
ΔTH2O = 68.0°C - 22.4°C = 45.6°C
To find ΔTTi, we need to use the fact that the final temperature of the system is 30.5°C:
mTi * cTi * (30.5°C - 100°C) = - mH2O * cH2O * (30.5°C - 22.4°C)
Solving for cTi, we get:
cTi = [mH2O * cH2O * (30.5°C - 22.4°C)] / [mTi * (100°C - 30.5°C)]
cTi = [80.5 g * 4.18 J/g°C * 8.1°C] / [18.6 g * 69.5°C]
cTi = 0.522 J/g°C
Therefore, the specific heat of titanium is approximately 0.522 J/g°C.
TRUE/FALSE. the engine of an aircraft propeller delivers an amount of power 171 hphp to the propeller at a rotational velocity of 2410 rev/minrev/min.
Answers
The engine of an aircraft propeller delivers an amount of power 171 hp to the propeller at a rotational velocity of 2410 rev/min. This is a false statement.
What is power?
Power can be defined as the amount of work completed in a given amount of time. Watt (W), which is derived from joules per second (J/s), is the SI unit of power. Horsepower (hp), which is roughly equivalent to 745.7 watts, is a unit of measurement sometimes used to describe the power of motor vehicles and other devices.
With out knowing mass of the propeller, it can't be concluded about its rotational velocity - no mater how much power is applied on it.
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If bowling ball and golf ball drop from the same height, which will hit the ground first?
Answers
The bowling ball will likely hit the ground first.
If a bowling ball and a golf ball are dropped from the same height in a vacuum or an environment where air resistance is negligible, they will hit the ground at the same time. This is because in the absence of air resistance, the only force acting on the objects is gravity, and both objects experience the same acceleration due to gravity.
According to the theory of free fall, all objects near the surface of the Earth, regardless of their masses, accelerate at the same rate of approximately 9.8 meters per second squared (m/s²). This means that both the bowling ball and the golf ball would experience the same acceleration, causing them to fall with the same speed and hit the ground simultaneously.
However, in real-world scenarios where air resistance is present, the objects will experience different amounts of air resistance due to their different shapes and sizes. The bowling ball, being larger and heavier, will experience less air resistance relative to its weight compared to the golf ball. As a result, the bowling ball will tend to overcome air resistance more effectively and hit the ground slightly earlier than the golf ball.
So, in summary, if air resistance is negligible or not a factor, both balls will hit the ground simultaneously. If air resistance is significant, the bowling ball will likely hit the ground first.
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how much work is done by the moon's gravitational field as a 995 kg meteor comes in from outer space and impacts on the moon's surface?
Answers
The work done by the moon's gravitational field as the meteor impacts the moon's surface is zero
To calculate the work done by the moon's gravitational field as the meteor impacts its surface, we need to determine the change in potential energy.
The work done (W) is given by the formula W = ΔPE, where ΔPE represents the change in potential energy. The potential energy of an object in a gravitational field is given by PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height or distance from the reference point.
Since the meteor comes in from outer space, we can assume it starts at an infinite distance from the moon's surface, where the potential energy is zero. As it impacts the moon's surface, its distance from the moon's center decreases to zero.
Given:
Mass of the meteor (m) = 995 kg
Acceleration due to gravity on the moon (g) = 1.62 m/s² (approximate value)
The change in potential energy (ΔPE) can be calculated as follows:
ΔPE = PE_final - PE_initial
= mgh_final - mgh_initial
= mg(0) - mg(∞)
= 0 - 0
= 0
Therefore, the work done by the moon's gravitational field as the meteor impacts the moon's surface is zero. This indicates that the moon's gravitational field does not do any work on the meteor as it falls towards the surface.
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To celebrate a solid performanceon your second thermodynamics exam, you grab a 750mL bottle of champagne from the store (at room temp 25degrees). Being a connoisseur in such matters, you insist it be chilled to 8 degrees celsius in a bucket of ice at 0 degrees celsius. How much ice must melt before you pop the bubbly? (The subject is thermodynamics)
Answers
In order to chill a 750mL bottle of champagne using a bucket of ice at 0 degrees Celsius, approximately 249 grams of ice must melt. The specific heat capacity of ice is approximately 2.09 J/g°C.
To determine the amount of ice that needs to melt, we can use the principles of thermodynamics. First, we need to calculate the heat lost by the champagne and the heat gained by the melting ice. The heat lost by the champagne can be calculated using the equation Q = mcΔT, where Q is the heat lost, m is the mass of the champagne, c is the specific heat capacity of champagne, and ΔT is the change in temperature. Similarly, the heat gained by the ice can be calculated using the same equation, where m is the mass of the ice and c is the specific heat capacity of ice.
Given that the initial temperature of the champagne is 25 degrees Celsius and the final temperature is 8 degrees Celsius, ΔT for the champagne is 25 - 8 = 17 degrees Celsius. The specific heat capacity of champagne is approximately the same as water, which is 4.18 J/g°C. Therefore, the heat lost by the champagne is Q = (750g)(4.18 J/g°C)(17°C) = 53,595 J.
Since the ice is at 0 degrees Celsius, ΔT for the ice is 0 - (-8) = 8 degrees Celsius. The specific heat capacity of ice is approximately 2.09 J/g°C. Therefore, the heat gained by the ice is equal to the heat lost by the champagne, which is 53,595 J. Using the equation Q = mcΔT and solving for the mass of ice (m), we can rearrange the equation to m = Q / (cΔT). Plugging in the values, we get m = 53,595 J / (2.09 J/g°C * 8°C) ≈ 249 grams.
Therefore, approximately 249 grams of ice must melt in order to chill the champagne from 25 degrees Celsius to 8 degrees Celsius in a bucket of ice at 0 degrees Celsius.
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the tiny ripples in the background radiation cobe found are due to
Answers
The tiny ripples in the background radiation COBE found are due to the quantum fluctuations that occurred during cosmic inflation.
What is COBE?
The Cosmic Background Explorer (COBE) is a satellite that was launched in 1989 to study the cosmic microwave background radiation. It was the first satellite mission dedicated solely to cosmology, and it provided groundbreaking insights into the early universe.
What is the cosmic microwave background radiation?
The cosmic microwave background radiation is a faint glow of electromagnetic radiation that permeates the entire universe. It is thought to be the remnant of the Big Bang, and it has been detected in every direction of the sky.
What are quantum fluctuations?
Quantum fluctuations are tiny variations in the energy density of the early universe. They are a natural consequence of the uncertainty principle in quantum mechanics, and they played a crucial role in the formation of the large-scale structure of the universe.
What is cosmic inflation?
Cosmic inflation is a period of exponential expansion that occurred in the early universe. It is thought to have happened within the first 10^-32 seconds after the Big Bang, and it is responsible for the large-scale homogeneity and isotropy of the universe. Cosmic inflation was proposed in the early 1980s to solve some of the problems with the Big Bang model.
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When mixing 2 or more substances together, evidence that a chemical change occurred would NOT include? 20 POINTS
1.(producing a gas)
2.(change in color)
2.(change in shape)
3.(change in temperature)
Answers
Answer:
change in shape
Explanation:
because if you mix them together they are most likely going to be the same shape.....a liquid
Please help!
1. If a soldier lifts a 2-kg counterweight 0.5 meters, what is the gravitational force of the counterweight? (Include the equation and appropriate units.)
2. If a soldier lifts a 2-kg counterweight 0.5 meters, how much work is done? (Include the equation and appropriate units.)
please please please please help!!!
Answers
Answer:
the gravitational force of the counterweight is 19.6 Nthe work done is 9.8 JExplanation:
Question 1:
Given;
a counterweight of mass, m = 2-kg
distance moved by this weight, d = 0.5 meters
the gravitational force of the counterweight is calculated as;
F = mg
where;
F is gravitational force
m is the mass
g is acceleration due to gravity
F = 2 x 9.8 = 19.6 N
Thus, the gravitational force of the counterweight is 19.6 N
Question 2:
Given;
a counterweight of mass, m = 2-kg
height moved by this weight, h = 0.5 meters
the work done is calculated as;
Work done = Force x distance moved by this weight
Work done = 19.6 x 0.5 = 9.8 J
Thus, the work done is 9.8 J
A snowboarder is sliding back and forth on a half pipe at one point she leaves the top of the half pipe and slides to the other side choose when kinetic energy increases during the snowboarders ride
Answers
Answer:
he kinetic energy increases on the descent, being maximum at the lowest point of the trajectory.
Explanation:
In these semicircular sections the skaters slide from one side to the other, in the downward path their kinetic energy increases and their potential energy decreases; When it leaves the ramp and is in the air, the kinetic energy decreases rapidly, up to the point of maximum height where the kinetic energy is zero.
Consequently, the kinetic energy increases on the descent, being maximum at the lowest point of the trajectory.
Assume all temperatures to be exact.
The single glass pane in a window has dimensions of 1.80 m by 1.30 m and is 3.20 mm thick.
How much heat will flow through the glass in 1.50 h if there is a temperature difference of 7 ∘C between the inner and outer surfaces? (Consider conduction only.)
Express answer in J.
Answers
The heat flow through the glass in 1.50 h is 20512.5 J, assuming conduction only.
What is the heat flow through the glass?The amount of heat flow through a material is given by the formula: Q = kAΔTt/d, where Q is the heat flow, k is the thermal conductivity, A is the area, ΔT is the temperature difference, t is the time, and d is the thickness.
In this case, the thermal conductivity of glass is about 0.8 W/(m∙K), the area is 1.80 m × 1.30 m = 2.34 m², the temperature difference is 7 °C, the time is 1.50 h, and the thickness is 3.20 mm = 0.0032 m.
Substituting these values into the formula, we get:
Q = (0.8 W/(m∙K)) × (2.34 m²) × (7 °C) × (1.50 h) / (0.0032 m)
Q = 20512.5 J
Therefore, the heat flow through the glass in 1.50 h is 20512.5 J.
To summarize, the amount of heat flowing through a glass pane can be calculated using the formula Q = kAΔTt/d, where k is the thermal conductivity, A is the area, ΔT is the temperature difference, t is the time, and d is the thickness. In this case, the heat flow through the glass in 1.50 h is 20512.5 J, assuming conduction only.
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Which example possesses mechanical potential energy?
Answers
Answer:
you didnt show a picture i need to see the problem sorry
Answer:
The Correct answer is A a taut guitar string.
how does lightning interfere with radio wave communication?
Answers
Explanation:Lightning can affect radio waves in a number of ways. First, lightning can cause static interference on radio frequencies. This is because the electrical discharge from lightning can create electromagnetic fields that can disrupt radio signals. Second, lightning can also cause physical damage to radio equipment.
1. A block with a mass of 5.0 kg is pushed on a frictionless surface by applying a horizontal force of 80.0 N. The block starts from rest, and its final velocity is 12.6 m/s.
Answers
Answer:
397 j
Explanation:
Because 5.0kg yuh
The kinetic energy of the block with a mass of 5.0 kg is pushed on a frictionless surface by applying a horizontal force of 80.0 N. The block starts from rest, and its final velocity is 12.6 m/s is 396.9 J.
What is kinetic energy?A moving item or particle has a certain kind of power called kinetic energy. When an item exerts a net force to perform work, which involves the transfer of energy, the object accelerates and as a result, gains kinetic energy.
The amount of kinetic energy that a moving object or particle possesses is determined by both its mass and rate of motion. Any combination of vibration, axis rotation, translation (or movement along a path from one location to another), and translation are all possible motion types.
Given:
The mass of the block, m = 5 kg,
The horizontal force, F = 80 N,
The velocity of the block, v = 12.6 m / s,
Calculate the kinetic energy by the formula given below,
\(KE = 1/2mv^2\)
KE = 1 / 2 × 5 × 12.6²
KE = 1 / 2 × 5 × 158.6
KE = 396.9 J
Therefore, the kinetic energy of the block with a mass of 5.0 kg is pushed on a frictionless surface by applying a horizontal force of 80.0 N. The block starts from rest, and its final velocity is 12.6 m/s is 396.9 J.
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The complete question is A block with a mass of 5.0 kg is pushed on a frictionless surface by applying a horizontal force of 80.0 N. The block starts from rest, and its final velocity is 12.6 m/s. Find its kinetic energy?
What is the differece between force and motion?
Answers
Answer:
---
Explanation:
Force is like the amount of push
Motion is the result of Push
a 0.24 kg blob of clay is thrown at a wall with an initial velocity of if the clay comes to a stop in what is the average force experienced by the clay?
Answers
The - 60.6 N is the average force experienced by the clay.
Define average force.The force applied by a body moving at a constant velocity (rate of speed) over a fixed time period is known as the average force. The magnitude and direction of force are both vector quantities. The term 'average' denotes that this velocity was not precisely measured or was not 'instantaneous.' As a result, the average force over a given time period is equal to the body's mass multiplied by its average velocity. The magnitude and direction of the average force are both vector quantities.
Average acceleration = Δv/t
We know F = ma,
We have m = 0.24
Δv = Final velocity - Initial velocity
Δv = (0 - 23) m/s
Δv = -23 m/s
t = 91 ms or 0.91 s
As we know acceleration (a) = v/t
So, a = -23/0.91
a = - 25.27 m/s²
Put the above value in formula F = ma.
F = (0.24 kg) × (-25.27 m/s²)
F = - 60.6 N
Therefore, the average force experienced by the clay is - 60.6 N.
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The complete question is:
"A 0.24 kg blob of clay is thrown at a wall with an initial velocity of 23 m/s. the clay comes to a stop against the wall in 91 ms, what is the average force experienced by the clay"
7. If a graph is showing a positive slope, and the graph itself is a straight line, what must be the x and y axis if the straight
line is showing a constant acceleration?
Answers
An object has positive acceleration if it is accelerating and travelling in the right direction.
What does it signify if a position time graph has a straight line with a positive slope? A straight line with a positive slope will appear on the Position vs. Time graph of an item travelling forward at a constant speed. It shows that the object's velocity is constant and that it is travelling ahead.The y-axis of this sort of graph denotes position in relation to the starting point, while the x-axis denotes time. An object's distance from its beginning position at any given moment since it began moving is displayed on a position-time graph.In a distance-time graph, the object's speed is equal to the slope or gradient of the line. The line becomes steeper as the thing goes more quickly (and the greater the gradient).The starting point of the item is indicated by the y-intercept. An object's y-intercept is zero if it begins at the measuring instrument. Its y-intercept is 3 meters if it begins at a distance of 3 meters. When two items are in the same position, you may tell by where two lines intersect.To Learn more About Positive acceleration, Refer:
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A charge of 3.877 nC is moved from a position on the y axis of 8.856 cm to a position on the x axis of 1.619 cm while there is a charge 21.524 nC located at the origin. How much work in micro-Joules did it take to move the charge?
Answers
Answer:
sa64
Explanation:
2 What does how much, how
long and how
often have to do with exposure to chemicals?
Answers
Well how much, how long, and how often
For example how much is like how much a object is left in a small room with chemicals
How long is the time
how often is how much the same cycle is done repeatedly
The skater eventually comes to a stop.
What has happened to all of the skater's
original potential energy?
Answers
As you enter the lab, you find two bottles labeled "concentrated ammonium phosphate." In one paragraph, using your own words, describe the steps you could take to change one of the bottles into a diluted solution, and one of the bottles into a saturated solution.
Answers
Answer:
Butane is a four member carbon chain.
The properties of butane are as follows.
Butane is less denser than water.
In the presence of air, it readily burns to form water vapour and carbon dioxide. The reaction is as follows.
It has a boiling point of .
Butane has faint petroleum like odor.
Butane does not react with water.
Butane has weak dispersion force and water has strong hydrogen bonding. The weak dispersion force is unable to break the hydrogen bonding hence, butane does not dissolve in water.
Thus, we can conclude that the chemical properties butane burns readily in air and does not react with water are true out of the given list of options.
Explanation:
1. Find the electric field of a - 3.2 n C charge from a distance of 6 m.
2. Find the electric field of a + 3.2 n C charge from a distance of 6 m.
3. If two + 3.4μC experience a force of 0.01 C/m, how far are they from one another?
4. If two - 6μC experience a force of 0.03 C/m, how far are they from one another
Answers
Plugging in these values gives an electric field of -1.07 x 10-8 N/C.
What is electric field?Electric field is a physical phenomenon that occurs when an electric charge is present in a space.
The electric field of a -3.2 nC charge from a distance of 6 m can be calculated using the equation E = kQ/r2, where k is Coulomb's constant (8.99x109 Nm2/C2), Q is the charge of the particle (in this case, -3.2 nC), and r is the distance from the particle (6 m). Plugging in these values gives an electric field of -1.07 x 10-8 N/C.
2. The electric field of a +3.2 nC charge from a distance of 6 m can be calculated using the same equation as in #1, E = kQ/r2, where k is Coulomb's constant (8.99x109 Nm2/C2), Q is the charge of the particle (in this case, +3.2 nC), and r is the distance from the particle (6 m). Plugging in these values gives an electric field of +1.07 x 10-8 N/C.
3. To find the distance between two +3.4 μC particles that experience a force of 0.01 C/m, we can use the equation F = kQ1Q2/r2, where k is Coulomb's constant (8.99x109 Nm2/C2), Q1 and Q2 are the charges of the two particles (in this case, +3.4 μC each), and r is the distance between them. Plugging in these values gives a distance of 5.81 m.
4. To find the distance between two -6 μC particles that experience a force of 0.03 C/m, we can use the same equation as in #3, F = kQ1Q2/r2, where k is Coulomb's constant (8.99x109 Nm2/C2), Q1 and Q2 are the charges of the two particles (in this case, -6 μC each), and r is the distance between them. Plugging in these values gives a distance of 1.31 m.
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13) How much mechanical energy does a swinging bowling ball have if it has 250J of kinetic energy and
800J of potential energy?
A)
B)
C)
Answers
A. ME = PE + KE
ME = mechanical energy
PE = potential energy
KE = kinetic energy
B. ME = 800 + 250
C. 1050 J
The mechanisms by which thermal energy is generated in a solid include all of the following except A. Electric resistance heating B. Release of thermal energy stored in the solid C. Endothermic chemical reactions D. Absorption of neutrons E. Exothermic chemical reactions
Answers
Thermal energy is the energy associated with the movement of particles within a substance. The mechanisms by which thermal energy is generated in a solid are varied and include electric resistance heating, the release of thermal energy stored in the solid, endothermic chemical reactions, and exothermic chemical reactions.
However, one mechanism by which thermal energy is not generated in a solid is the absorption of neutrons.
Absorption of neutrons can lead to the formation of new isotopes, but it does not directly generate thermal energy. This is because neutrons do not carry an electric charge, and therefore cannot directly interact with the electrons in a solid to generate heat. Instead, the energy associated with the absorbed neutron is typically released through subsequent nuclear reactions, which can generate thermal energy indirectly.
In summary, while electric resistance heating, the release of thermal energy stored in the solid, endothermic chemical reactions, and exothermic chemical reactions are all mechanisms by which thermal energy can be generated in a solid, absorption of neutrons is not.
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A 0.1 kg toy contains a compressed spring. when the spring is released the toy fly 0.45 m upwards from ground level before falling back down to the ground. what is the speed of the toy when it hits the ground.
Answers
The speed of the toy when it hits the ground is 2.97 m/s.
The given parameters;
mass of the toy, m = 0.1 kgthe maximum height reached by the, h = 0.45 mThe speed of the toy before it hits the ground will be maximum. Apply the principle of conservation of mechanical energy to determine the maximum speed of the toy.
P.E = K.E
\(mgh_{max} = \frac{1}{2} mv_{max}^2\\\\gh_{max} = \frac{1}{2} v_{max}^2\\\\v_{max}^2= 2gh_{max}\\\\v_{max} = \sqrt{2gh_{max}}\)
Substitute the given values and solve the speed;
\(v_{max} = \sqrt{2\times 9.8 \times 0.45} \\\\v_{max} = 2.97 \ m/s\)
Thus, the speed of the toy when it hits the ground is 2.97 m/s.
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what is the difference between a meteor and a meteorite?
1. Meteors are larger than meteorites
2. Meteors come from the Kuiper belt and meteorites originate in the asteroid belt.
3. Meteors are more like comets than meteorites
4. a meteorite is a meteor that impacted the earth.
please help.
Answers
Answer:
meteorites, meteors are objects that enter Earth's atmosphere from space. But meteors—which are typically pieces of comet dust no larger than a grain of rice—burn up before reaching the ground. ... The term “meteorite” refers only to those bodies that survive the trip through the atmosphere and reach Earth's surface. I believe this is it
What is the medium for the waves in the photograph?
O A. Leaves
O B. Water
O C. Stones
O D. Air
Answers
During a demonstration of Newton's laws of motion, a student used the setup shown in Figure 1. The
student flicked the index card with a fingertip, and the coin fell straight down into a plastic cup as
shown in Figure 2.
ontage
werdana 10... 19
11162030
TAG Teste
Figure 1
Figure 2
Which of these best explains why the coin feil straight down into the cup instead of remaining on the
index card?
F. The coin was at rest until the card was removed, so it tended to remain in the same location.
Once the card was gone, the unbalanced force of gravity caused the coin to fall.
6. Moving the card applied an action force on the coin. Since the card was gone, gravity applied a
reaction force on the coin.
H. The card had less mass than the coin, so a smaller force of gravity acted on the card. The
larger force of gravity on the coin made it fall.
J. The acceleration of the coin falling into the cup was equal and opposite to the acceleration of
the card.
Answers
Answer:
The answer is f
Explanation:
I don't have one
d+x 8. A wire of 2 mm cross-sectional area and 10.3 cm long contains 2x1020 electrons. It has a 10 2 resistance. What is the drift velocity of the charges in the wire when 5 Volts battery is applied a
Answers
The drift velocity v will give us the answer.
\(v = (5 V) / ((2x10^20 electrons/m³) * (2x10^-6 m²) * (1.6x10^-19 C))\)
\(v = (5 V) / (4x10^-14 m³) * (1.6x10^-19 C)?\)To find the drift velocity of charges in the wire, we can use Ohm's Law, which states that the current flowing through a conductor is directly proportional to the applied voltage and inversely proportional to the resistance. The equation for Ohm's Law is:
I = V / R
Where:
I is the current flowing through the wire,
V is the applied voltage (in this case, 5 Volts),
R is the resistance of the wire (given as 10^2 Ohms).
Now, we need to calculate the current flowing through the wire using Ohm's Law. The current is the rate at which charges (electrons) move through the wire. The equation for current is:
I = n * A * v * q
Where:
n is the number of charges per unit volume (given as 2x10^20 electrons),
A is the cross-sectional area of the wire (given as 2 mm² or 2x10^-6 m²),
v is the drift velocity of the charges (what we need to find),
q is the charge of each electron (1.6x10^-19 C).
Rearranging the equation and solving for v, we have:
v = I / (n * A * q)
Substituting the given values:
v = (5 V) / ((2x10^20 electrons/m³) * (2x10^-6 m²) * (1.6x10^-19 C))
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