If a firework has an initial velocity of 235m/s and is in the air for 12 seconds with an acceleration of -10 m/s2 before exploding, how far did it go?
Answer:
\(\boxed {\boxed {\sf 2100 \ meters}}\)
Explanation:
We are asked to find the distance a firework travels.
We are given the initial velocity, acceleration, and time, but we don't know the final velocity. Therefore, we will use the following kinematic equation.
\(d=v_it+\frac{1}{2} at^2\)
The initial velocity is 235 meters per second. The firework travels for 12 seconds. It has an acceleration of -10 meters per second squared.
\(v_i\)= 235 m/s t= 12 s a= -10 m/s²Substitute the values into the formula.
\(d= (235 \ m/s)(12 \ s) + \frac{1}{2} (-10 m/s^2)(12 \ s)^2\)
Multiply the first 2 numbers in parentheses. The units of seconds cancel.
\(d=(235 \ m * 12 ) + \frac{1}{2} (-10 \ m/s^2)(12 \ s )^2\)
\(d= (2820 \ m)+ \frac{1}{2} (-10 \ m/s^2)(12 \ s )^2\)
Solve the exponent.
(12 s)²= 12 s * 12s = 144 s²\(d=(2820 \ m)+ \frac{1}{2} (-10 \ m/s^2)(144 \ s^2)\)
Multiply the other numbers in parentheses. The units of seconds squared cancel.
\(d=(2820 \ m)+ \frac{1}{2} (-10 \ m * 144 )\)
\(d=(2820 \ m)+ \frac{1}{2} (-1440 \ m)\)
Multiply by 1/2 or divide by 2.
\(d= 2820 \ m + (-720 \ m)\)
Add.
\(d= 2100 \ m\)
The firework traveled 2100 meters before exploding.
Can someone please help me it's urgent!
Answer:
6.8 x 10^6
Explanation:
Look up M A T H W A Y it will help you with all of your algebra needs
Which example would contain only longitudinal waves? a. a crowd doing the wave at a sporting event
b. an ultrasound that transmits soundwaves c. the waves formed by the ocean
d. playing the guitar strings
Answer: The answer to this problem is 3 option
Explanation:
The waves fοrmed by the οcean wοuld cοntain οnly lοngitudinal waves. Thus, option c is correct.
What dοes the term "lοngitudinal wave" mean?A lοngitudinal wave is a fοrm οf wave in which the medium vibrates parallel tο the wave's directiοn and the displacement οf the medium mοves in the same directiοn as the wave's mοtiοn. Sοund waves are a cοuple οf examples οf lοngitudinal waves. seismic P waves, and ultrasοnic waves.
Why dο lοngitudinal waves gο by that name?The wave is referred tο be a lοngitudinal wave when the medium's particles vibrate perpendicular tο the wave's directiοn οf prοpagatiοn.
Cοmpressiοns and rarefactiοns are created by οscillating sοund waves in a manner similar tο that οf prοpagatiοn directiοn. Hence, lοngitudinal waves are the name given tο sοund waves.
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galileo taught us that if you roll a ball along a level surface it will
Galileo taught us that if you roll a ball along a level surface it will keep rolling if friction is absent.
Galileo Galilei, an Italian scientist, and astronomer, made significant contributions to our understanding of the laws of motion and the behavior of objects. One of his important observations and teachings relates to the motion of a ball rolling along a level surface.
Galileo taught us that when a ball rolls along a level surface, it will continue rolling indefinitely, provided there is no external force acting upon it. This principle is known as the law of inertia, which states that an object at rest will remain at rest, and an object in motion will continue in motion with a constant velocity unless acted upon by an external force.
In the case of a rolling ball, the ball experiences rolling resistance due to various factors such as friction and air resistance. However, if these forces are negligible or effectively canceled out, the ball will continue rolling without slowing down significantly.
Galileo's teachings challenged the prevailing notion at the time that objects needed a continuous force to remain in motion. He conducted experiments and made observations to demonstrate that objects in motion tend to remain in motion, even in the absence of an applied force.
This understanding of inertia and the motion of objects laid the foundation for Newton's laws of motion, which became fundamental principles in classical physics. Galileo's teachings on the motion of a rolling ball helped shape our understanding of the nature of motion and continue to be relevant in physics education and scientific research today.
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Body of an earthworm is divided into rings/ metamers. It moves with the help of two muscles: longitudinal and circular muscles. Which of the following activity is done by earthworm during its movement?
(OPTIONs)
→ Swallow the soil it moves
→ Grip the soil firmly at one end
→ Make the soil moist and slippery
→ Break the soil into smaller particles
Swallow the soil it moves and Break the soil into smaller particles.
What is movement in earthworm?They don't have bones or other fixed features that might restrict their movement. The body of an earthworm is segmented. Earthworms use the setae, or tiny bristles, that are present on each segment, to assist them hold the dirt as they travel.
An earthworm uses two distinct sets of muscles to move. Longitudinal muscles run the length of the body, while circular muscles loop around each segment. The earthworm extends as a result of the circular muscles contracting, growing longer and thinner.
The earthworm embeds the front of its body in the dirt using its setae. The earthworm now contracts its longitudinal muscles, either making it shorter and wider.
Therefore, Swallow the soil it moves and Break the soil into smaller particles.
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85POINTS ASAP!!!!!!!!!!!!!!
Answer:
hi
Explanation:
what happens the second time dr. hewitt lifts the bowling ball near his teeth and gives it a push?
The second time Dr. Hewitt lifts the bowling ball near his teeth and gives it a push, the same forces are at play as the first time he did so. When he lifts the ball, he exerts an upward force equal to the weight of the ball to overcome gravity.
When he gives it a push, he applies a forward force to the ball. The friction between the ball and the ground opposes the motion of the ball, but eventually, the ball starts moving forward.
Assuming Dr. Hewitt applies the same amount of force, the ball will move at the same speed and cover the same distance as the first time. However, if he applies more force or pushes it in a different direction, the ball's speed and direction will change.
It is important to note that repeatedly lifting heavy objects near one's teeth can be dangerous, as it can strain the neck and back muscles and cause injury. It is best to use proper lifting techniques and seek assistance when handling heavy objects.
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4. Hijackers are taking over a plane, They tell the pilot to get to Spain as fast as possible. The plane goes from 900
km/hr (beginning speed) to 1140 km/hr (final speed) in just 6 seconds. What is the acceleration of the plane?
What energy transformation takes place when you push a pencil off your desk? A. Mechanical energy transforms into kinetic energy. B. Potential energy transforms into nuclear energy. C. Potential energy transforms into kinetic energy. D. Kinetic energy transforms into potential energy.
When you push a pencil off your desk, the energy transformation that takes place is that potential energy transforms into kinetic energy.
The correct answer to the given question is option C.
Potential energy is the energy stored within an object because of its position or configuration.
In this scenario, the pencil has potential energy because of its elevated position on the desk. When the pencil is pushed off the desk, it begins to move, which means that it has kinetic energy. Kinetic energy is the energy of motion.
As the pencil falls off the desk, its potential energy is transformed into kinetic energy, which is the energy that results from its motion. The faster the pencil falls, the greater its kinetic energy will be because kinetic energy is directly proportional to the square of an object's velocity.
Therefore, when you push a pencil off your desk, the potential energy that it has because of its elevated position is transformed into kinetic energy as it falls towards the ground.
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If our planet was twice as far away how would the Earth’s orbit change?
Answer:
One of the indirect proofs that orbits change is actually in the growth of our own teeth when we were children. our teeth are some of the most basic, and primitive
parts of our bodies. They grow on a 9 day cycle, which was an ancient full moon to full moon cycle when the Earth and the Moon were a lot smaller, and closer together, and the co-orbital period was only 9 days, not the 29.5 days that it is currently.
So Given any two " Planets " that co-orbit a common gravitational center, the larger planet will grow larger far faster than the smaller planet, and the larger planet will accelerate the smaller planet to a higher orbit with a longer period, and decelerate itself to a lower orbit with a longer period, and the absolute value of the center to center distance will increase, and the orbital period will increase. The two orbs and their common gravitational center will remain co-linear through out the gradual growing and changing process.
This is an important process for the enlargement of the solar system as time passes, and an important process for larger galaxies as they attract and merge with smaller galaxies.
All of the planets grow larger at an accelerating rate, and thus systems spiral outward concentrating mass into larger and fewer galaxies, solar systems, and planet - moon systems.
which statement is a scientific theory
A.most cells are so small that they can be observed only through a microscope
B.the interactions between cells can be predicted with mathematical equations
C.The various functions of different types of cells can be determined by experiments
D.cells are fundamental units of all living organisms
Most cells are so small that they can be observed only through a microscope is a scientific theory. Option A is correct.
What is a scientific theory?A well-considered explanation for observations of the natural world that has been developed through the scientific method and that combines numerous facts and hypotheses is known as a theory.
A scientific hypothesis states that most cells are so tiny that a microscope is the only way to see them.
Hence option A is correct.
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(03.04 MC)
If the distance between two charged particles is doubled, the force between them changes by a factor of...
1/2
1/4
2
4
Answer:
1/4
Explanation:
If the distance between two charges is doubled, the attraction of repulsion between the two becomes weaker, and decreases to 1/4 of the original value.
Which formula uses mass in the equation?
The mass can be calculated by dividing the net force acting on an object by the acceleration of the object. When talking about net force, we use the units kilogram meter per second squared. This is also known as a Newton. The units for acceleration is meters per seconds squared, and the units for mass are kilograms.
Calculate the amount of extension of a spring with a spring constant of 3 kN/m, if the amount of work done in extending it is 35 N. Give your answer in m.
The extension of the spring is 4.83 m, if work done is 35 Newton and spring constant is 3 k N/m.
The spring constant, k, is a measure of the stiffness of the spring. it's far one of a kind for unique springs and materials. the larger the spring regular, the stiffer the spring and the greater.
Spring constant of 3 k N/m,
The amount of work done in extending is 35 N
WORK DONE by spring force = 1/2 k X²
⇒0.5 * 3 * X²
35 N = 0.5 * 3 * X²
X² = 35/1.5
x = \(\sqrt{23.33}\)
X = 4.83 m
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The extension of the spring is can be found out by using the Work Done due to extension in Spring Constant K. The extension in the spring is 4.83m.
The spring constant, k, is a measure of the stiffness of the spring. It is for springs and materials which measures the ratio of force that affects the spring and the displacement caused by the force action.
Spring constant depends on the stiffness of the spring, wire thickness, number of turns in wound coil, length of spring and diameter of the coil.
Given:
Spring constant = 3000 N/m
Work Done in extension= 35 N
Let the extension in spring by x.
∴ Work Done by spring force = 1/2 kx²
Work done = 0.5 × 3 × x²
⇒ 35 N = 0.5 × 3 × x²
⇒ x² = 35/1.5
⇒ x = 4.83m
Hence, the extension of spring is 4.83m.
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2
Select the correct answer.
Which statement is true about acceleration?
OA.
It is the rate of change of speed per unit time.
OB.
It is the rate of change of displacement per unit time.
Ос.
It is the rate of change of velocity per unit time.
OD.
It is the rate of change of position per unit time.
Reset
Next
Answer:
the answer is C ----- it is the rate of change of velocity per unit time
Explanation:
acceleration
\( = \frac{velocity(v)}{time(t)} \)
When an alternating current circuit supplies power to a ? load, the circuit voltage and current are in-phase with each other. this is also known as unity power factor.
Georgie was pulling her brother (of mass 27 kg) in a 12.1 kg sled with a constant force of 40 N for one block (92 m). How much work did Georgie do?
Georgie did 3,648 Joules of work by pulling her brother and the sled for one block.
The work done by Georgie can be calculated using the formula: Work = Force × Distance. In this case, the force applied by Georgie is 40 N, and the distance covered is 92 m. Therefore, the work done is equal to 40 N × 92 m = 3,648 J.
Work is a measure of the energy transferred when a force acts on an object and causes it to move. In this scenario, Georgie applied a constant force of 40 N to pull her brother and the sled. The work done is directly proportional to the force applied and the distance covered. By multiplying the force and distance values, we find that Georgie performed 3,648 Joules of work.
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Georgie did 3,648 Joules of work by pulling her brother and the sled for one block.
The work done by Georgie can be calculated using the formula: Work = Force × Distance. In this case, the force applied by Georgie is 40 N, and the distance covered is 92 m. Therefore, the work done is equal to 40 N × 92 m = 3,648 J.
Work is a measure of the energy transferred when a force acts on an object and causes it to move. In this scenario, Georgie applied a constant force of 40 N to pull her brother and the sled. The work done is directly proportional to the force applied and the distance covered. By multiplying the force and distance values, we find that Georgie performed 3,648 Joules of work.
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Types of Spectra 5) Stars like our Sun have low-density, gaseous atmospheres surrounding their hot, dense cores. If you were looking at the spectra of light coming from the Sun (or any star), which of the three types of spectrum would be observed? Explain your reasoning.
The spectrum observed from the Sun (or any star) would exhibit an absorption spectrum. This is because the outer gaseous atmosphere of the star absorbs specific wavelengths of light, resulting in dark absorption lines in the spectrum.
In the cooler, lower-density outer atmosphere, where white light from the star travels, some atoms or molecules in the atmosphere absorb photons with particular energy. In the spectrum, these absorptions show up as black lines at specific wavelengths. The specific set of absorption lines that each element or molecule generates results in a distinctive pattern that can be used to identify the elements that are present in the star's atmosphere.
The absorption spectrum offers insightful data on the chemical make-up and physical characteristics of the star. Astronomers can ascertain the elements present, their abundances, and other characteristics like the temperature, pressure, and velocity of the star's atmosphere by examining the absorption lines.
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1. A 2.5 kg led projector is launched as a projectile off a tall building. At one point, as it
is flying through the air it has a velocity of 24 m/s and a height of 14 m.
a) Find the potential energy
b) Find the kinetic energy
c) Find the total mechanical energy
d) Find the potential energy at a height of 8.7 m
e) Find the kinetic energy at that same height. (Hint – the total energy is always the same
as in part c)
f) Find the velocity at that height
g) Find the velocity at a height of 11.6 m
h) At what height would the velocity be 26 m/s?
i) What is the velocity just before it smashes into the ground?
See
Answer:
Explanation:
I got everything but i. Don't know why but it's eluding me. So let's do everything but that.
a. PE = mgh so
PE = (2.5)(98)(14) and
PE = 340 J
b. \(KE=\frac{1}{2}mv^2\) so
\(KE=\frac{1}{2}(2.5)(14)^2\) and
KE = 250 J
c. TE = KE + PE so
TE = 340 + 250 and
TE = 590 J
d. PE at 8.7 m:
PE = (2.5)(9.8)(8.7) and
PE = 210 J
e. The KE at the same height:
TE = KE + PE and
590 = KE + 210 so
KE = 380 J
f. The velocity at that height:
\(380=\frac{1}{2}(2.5)v^2\) and
\(v=\sqrt{\frac{2(380)}{2.5} }\) so
v = 17 m/s
g. The velocity at a height of 11.6 m (these get a bit more involed as we move forward!). First we need to find the PE at that height and then use it in the TE equation to solve for KE, then use the value for KE in the KE equation to solve for velocity:
590 = KE + PE and
PE = (2.5)(9.8)(11.6) so
PE = 280 then
590 = KE + 280 so
KE = 310 then
\(310=\frac{1}{2}(2.5)v^2\) and
\(v=\sqrt{\frac{2(310)}{2.5} }\) so
v = 16 m/s
h. This one is a one-dimensional problem not using the TE. This one uses parabolic motion equations. We know that the initial velocity of this object was 0 since it started from the launcher. That allows us to find the time at which the object was at a velocity of 26 m/s. Let's do that first:
\(v=v_0+at\) and
26 = 0 + 9.8t and
26 = 9.8t so the time at 26 m/s is
t = 2.7 seconds. Now we use that in the equation for displacement:
Δx = \(v_0t+\frac{1}{2}at^2\) and filling in the time the object was at 26 m/s:
Δx = 0t + \(\frac{1}{2}(-9.8)2.7)^2\) so
Δx = 36 m
i. ??? In order to find the velocity at which the object hits the ground we would need to know the initial height so we could find the time it takes to hit the ground, and then from there, sub all that in to find final velocity. In my estimations, we have 2 unknowns and I can't seem to see my way around that connundrum.
25. A wave has a frequency of 46 Hz and a wavelength of 1.7 meters. What is the speed of this wave?
Answer:
78.2 m/time
Explanation:
Wavelength =Speed/Frequency
Speed = 46 x 1.7 =78.2 m/time.
Calculate the Schwarzschild radius (in kilometers) for each of the following.1.) A 1 ×108MSun black hole in the center of a quasar. Express your answer using two significant figures.2.) A 6 MSun black hole that formed in the supernova of a massive star. Express your answer using two significant figures.3.) A mini-black hole with the mass of the Moon. Express your answer using two significant figures.4.) Estimate the Schwarzschild radius (in kilometers) for a mini-black hole formed when a superadvanced civilization decides to punish you (unfairly) by squeezing you until you become so small that you disappear inside your own event horizon. (Assume that your weight is 50 kg.) Express your answer using one significant figure.
Answer:
(I). The Schwarzschild radius is \(2.94\times10^{8}\ km\)
(II). The Schwarzschild radius is 17.7 km.
(III). The Schwarzschild radius is \(1.1\times10^{-7}\ km\)
(IV). The Schwarzschild radius is \(7.4\times10^{-29}\ km\)
Explanation:
Given that,
Mass of black hole \(m= 1\times10^{8} M_{sun}\)
(I). We need to calculate the Schwarzschild radius
Using formula of radius
\(R_{g}=\dfrac{2MG}{c^2}\)
Where, G = gravitational constant
M = mass
c = speed of light
Put the value into the formula
\(R_{g}=\dfrac{2\times6.67\times10^{-11}\times1\times10^{8}\times1.989\times10^{30}}{(3\times10^{8})^2}\)
\(R_{g}=2.94\times10^{8}\ km\)
(II). Mass of block hole \(m= 6 M_{sun}\)
We need to calculate the Schwarzschild radius
Using formula of radius
\(R_{g}=\dfrac{2MG}{c^2}\)
Put the value into the formula
\(R_{g}=\dfrac{2\times6.67\times10^{-11}\times6\times1.989\times10^{30}}{(3\times10^{8})^2}\)
\(R_{g}=17.7\ km\)
(III). Mass of block hole m= mass of moon
We need to calculate the Schwarzschild radius
Using formula of radius
\(R_{g}=\dfrac{2MG}{c^2}\)
Put the value into the formula
\(R_{g}=\dfrac{2\times6.67\times10^{-11}\times7.35\times10^{22}}{(3\times10^{8})^2}\)
\(R_{g}=1.1\times10^{-7}\ km\)
(IV). Mass = 50 kg
We need to calculate the Schwarzschild radius
Using formula of radius
\(R_{g}=\dfrac{2MG}{c^2}\)
Put the value into the formula
\(R_{g}=\dfrac{2\times6.67\times10^{-11}\times50}{(3\times10^{8})^2}\)
\(R_{g}=7.4\times10^{-29}\ km\)
Hence, (I). The Schwarzschild radius is \(2.94\times10^{8}\ km\)
(II). The Schwarzschild radius is 17.7 km.
(III). The Schwarzschild radius is \(1.1\times10^{-7}\ km\)
(IV). The Schwarzschild radius is \(7.4\times10^{-29}\ km\)
The energy conservation allows to find the Schwarschild radius for several bodies of different masses are:
1) Black hole quasar is: r = 2.9 10⁸ km
2) Blsck hole supernove is: r = 17.7 km
3) Mini black hole is: r = 1.1 10⁻⁷ km
4) Human body is: r= 7 10⁻²⁹ km
The schwarschild radius is defined as the distance from a black hole center at radius which the escape velocity is equal to the light speed, in some cases it is also called the event horizon.
Let's use Newton's second law where force is the universal law of attraction and acceleration is centripetal.
F = ma
F = \(G \frac{Mm}{r^2}\)
Where F is the force, M the mass of the black hole, m the handle of the body, r the radius and v the speed of the body.
The energy of the gravitational field is
F = \(- \frac{dU}{dr }\)
U = \(-G \frac{Mm}{r}\)
Let's use conservation of energy
Em₀ = K + U = ½ m v² - \(G \frac{Mm}{r}\)
In infinity the energy
Em_f = 0
energy is conserved
Em₀ = Em_f
½ m v² - \(G \frac{Mm }{r}\) = 0
r = \(\frac{2GM}{v^2}\)
From the definition of the Schwarschild radius this speed is equal to the light speed
v = c
r = \(\frac{2GM}{c^2 }\)
They ask to calculate the radius for several cases of different mass, claculate the constant value
V = \(\frac{2 \ 6.67 \ 10^{-11} }{(3 \ 10^8) ^2 }\)
V = 1.482 10⁻²⁷
1) A black hole of mass M = 1 10⁸ \(M_{sum}\)
The tabulated mass of the sun is \(M_{sum}\) = 1.989 10³⁰ kg
Let's substitute
r = 1.482 10⁻²⁷ 1 10⁸ 1.989 10³⁰
r = 2.94 10⁸ km
With two significant figures
r = 2.9 10⁸ km
2) A black hole of mass M = 6 \(M_{sum}\)
r = 1.482 10⁻²⁷ 6 1.989 10-30
r = 17.7 km
3) a mini black hole with the mass of the moon
Tabulated mass of the moon M = 7.35 10²² kg
r = 1.482 10⁻²⁷ 7.35 10²²
r = 1.1 10⁻⁷ km
4) A person of M = 50 kg
r = 1.482 10⁻²⁷ 50
r= 7 10-29 km
In conclusion using the conservation of energy we can find the Schwarschild radius for several bodies of different masses are:
1) Black hole quasar is: r = 2.9 10⁸ km
2) Blsck hole supernove is: r = 17.7 km
3) Mini black hole is: r = 1.1 10⁻⁷ km
4) Human body is: r= 7 10⁻²⁹ km
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A certain amount of a monatomic gas is maintained at constant volume as it is cooled by 50 k. This feat is accomplished by removing 400 j of energy from the gas. How much work is done by the gas?.
The concept mentioned is Energy .The answer is 400J.
Energy is the quantitative property transferred to a body or a physical system, recognizable in the performance of work and the form of heat and light. When the implicit energy is positive, a constant energy expansion reduces implicit energy and increases kinetic energy, adding temperature.
To understand if the work is positive or negative we've to:
The work is positive when the gas performs( expansion)
The work is negative when done outdoors on the gas( contraction)
In this case, the work is done by the gas, so it's positive.
So, it'll be 400J.
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Which statement explains how planets move in orbit as supported by Newton’s first law of motion?
Planets can change the direction of their own orbital path.
Planets can change orbits due to their inertia.
Planets in motion will have a constant speed unless acted on by an outside force.
Planets with a greater mass will orbit more quickly than smaller planets.
Answer:
C
Explanation:
When the planet in motion should have the same speed so until it should be acted by an outer force. This statement explained the movement of the planets.
The information regarding the first law of motion is as follows:
In the case when the body is at rest or moves at the same speed on the straight line so it should be the same at rest or a movement until it is acted by an outside force. It is also called as law of inertia.Therefore, the third option is correct.
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According to newton's first law, an object traveling in a circle does not have a force acting on it.
A. True
B. False
Answer:
I say its true
Explanation:
Determine both the mass and the charge of a block of material consisting of 3 x 10^27 protons, 3 x 10^37 neutrons, and 3.1 x 10^27 electrons.
Answer:
The mass of the block of material is 3 x 10³⁷ g/mol
The charge of the material is 4.8 x 10⁸ C
Explanation:
Given;
number of protons of the material, P = 3 x 10²⁷
number of neutrons in the material, N = 3 x 10³⁷
number of electrons in the material, E = 3 x 10²⁷
The mass of the block of material is calculated as follows;
M = P + N
M = 3 x 10²⁷ + 3 x 10³⁷
M = 3 x 10³⁷ g/mol
The charge of the material is calculated as follows;
charge of 1 electron = 1.6 x 10⁻¹⁹ C
charge of 3 x 10²⁷ electrons = 3 x 10²⁷ electrons x 1.6 x 10⁻¹⁹ C
= 4.8 x 10⁸ C
what is electromagnetic spectrum
Answer:
range of wavelength and frequencies is the answer
Explanation:
the defintion is:
the range of wavelengths or frequencies over which electromagnetic radiation extends.
and also
It is the most complete range of all types of radiation that has both electric & magnetic fields and travels in waves.
Making electromagnetic spectrum a electromagnetic spectrum
Range of wavelength and frequencies being the answer
Which term represents the change of a substance from the solid phase to the liquid phase?
Answer:
it is called melting or phase transition :)
Explanation:
black holes are often discovered by observing the shifting of spectral lines in an ordinary star that they are orbiting. careful measurements of the shifting spectral lines can provide
Careful measurements of the shifting spectral lines in an ordinary star orbiting a black hole can provide valuable information about the presence and properties of the black hole.
By observing the shifting of spectral lines, scientists can infer the presence of a massive object exerting gravitational influence on the star. This gravitational effect, known as gravitational redshift or blueshift, causes the wavelengths of light emitted by the star to shift towards longer or shorter wavelengths, respectively. The careful measurements of these spectral line shifts can provide insights into various aspects of the black hole, such as its mass, spin, and orbital characteristics. The degree of spectral line shift can be used to estimate the gravitational force exerted by the black hole, which in turn helps determine its mass.
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A curved line going up indicates the object is
Explanation:
Both graphs show plotted points forming a curved line. Curved lines have changing slope; they may start with a very small slope and begin curving sharply (either upwards or downwards) towards a large slope. In either case, the curved line of changing slope is a sign of accelerated motion (i.e., changing velocity).
explain what you think is happening in this picture
Answer:
sorry, there is no picture, try re-uploading it with the pic
Explanation: