Answer:
Effort force\(=824.04 \sin\theta\)
where \(\theta\) is the angle of inclination of the ramp.
Explanation:
The given combined mass of a person and wheelchair is 185 lb.
In SI unit, 1 pound= 0.453592 kg
So, 185 lb=\(185\times0.453592\) kg=84kg (approximately)
Assuming the whole mass as a point mass and denote it by M, so
M=84kg
Let the angle of inclination of the ram with the is \(\theta\) with respect to the ground and assume that the friction offered by ram id negligible, so neglection the frictional force.
The applied effort force, F, will be minimum when applied in the direction parallel to the ramp surface as shown in the figure.
The gravitational force action on M is Mg in the downward direction.
For the mass M to be at an equilibrium condition on the ramp, the sum of the total force in any direction will be zero.
Equate the sum of all the forces in the direction parallel to the ramp to zero.
\(F-Mg\sin\theta=0\)
\(\Rightarrow F=Mg \sin\theta\)
\(\Rightarrow F=84\times 9.81\sin\theta\)
\(\Rightarrow F=824.04\sin\theta N\).
A satellite is orbiting the earth at 15000.km above the center of the earth, What speed is it going?
An 8.0 Kg mass is placed at = 3 where should a 10 Kg mass be placed along the − so that the center of mass will be located ay = 4.5?
Answer:
Therefore, the 10 kg mass should be placed at x = 5.7 m along the x-axis to achieve a center of mass located at y = 4.5 m.
Explanation:
To find the position along the x-axis where a 10 kg mass should be placed such that the center of mass is located at y = 4.5, we can use the formula for the center of mass:
x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)
Here, m1 and x1 represent the mass and position of the 8 kg mass, respectively. m2 is the mass of the 10 kg mass, and we need to find x2, its position.
Given:
m1 = 8 kg
x1 = 3 m
x_cm = unknown (to be found)
m2 = 10 kg
y_cm = 4.5 m
Since the center of mass is at y = 4.5, we only need to consider the y-coordinate when calculating the center of mass position along the x-axis.
To solve for x2, we can rearrange the formula as follows:
x2 = (x_cm * (m1 + m2) - m1 * x1) / m2
Substituting the given values:
x2 = (x_cm * (8 kg + 10 kg) - 8 kg * 3 m) / 10 kg
Simplifying:
x2 = (x_cm * 18 kg - 24 kg*m) / 10 kg
Now, we can set the y-coordinate of the center of mass equal to 4.5 m and solve for x_cm:
4.5 m = (8 kg * 3 m + 10 kg * x2) / (8 kg + 10 kg)
Simplifying:
4.5 m = (24 kg + 10 kg * x2) / 18 kg
Multiplying both sides by 18 kg:
81 kg*m = 24 kg + 10 kg * x2
Subtracting 24 kg from both sides:
10 kg * x2 = 81 kg*m - 24 kg
Dividing both sides by 10 kg:
x2 = (81 kg*m - 24 kg) / 10 kg
Simplifying:
x2 = 8.1 m - 2.4 m
x2 = 5.7 m
(brainlest?) ples:(
Answer:
the 10 kg mass should be placed at x = -2.4 m to achieve a center of mass at y = 4.5 m.
Explanation:
To find the position along the x-axis where the 10 kg mass should be placed so that the center of mass is located at y = 4.5, we can use the principle of the center of mass.
The center of mass of a system is given by the equation:
x_cm = (m1x1 + m2x2) / (m1 + m2),
where x_cm is the x-coordinate of the center of mass, m1 and m2 are the masses, and x1 and x2 are the positions along the x-axis.
Given:
m1 = 8 kg,
x1 = 3 m,
m2 = 10 kg,
y_cm = 4.5 m.
To solve for x2, we need to find the x-coordinate of the center of mass (x_cm) by using the y-coordinate:
y_cm = (m1y1 + m2y2) / (m1 + m2),
where y1 and y2 are the positions along the y-axis.
Rearranging the equation and substituting the given values:
4.5 = (83 + 10y2) / (8 + 10).
Simplifying the equation:
4.5 = (24 + 10*y2) / 18.
Multiplying both sides by 18:
81 = 24 + 10*y2.
Rearranging the equation:
10*y2 = 81 - 24,
10*y2 = 57.
Dividing both sides by 10:
y2 = 5.7.
Therefore, the y-coordinate of the 10 kg mass should be 5.7 m.
To find the x-coordinate of the 10 kg mass, we can use the equation for the center of mass:
x_cm = (m1x1 + m2x2) / (m1 + m2).
Substituting the given values:
x_cm = (83 + 10x2) / (8 + 10).
Since the center of mass is at x_cm = 0 (the origin), we can solve for x2:
0 = (83 + 10x2) / (8 + 10).
Rearranging the equation:
83 + 10x2 = 0.
24 + 10*x2 = 0.
10*x2 = -24.
Dividing both sides by 10:
x2 = -2.4.
What are some of the forces affecting rock climbers?
Answer:
Gravitational force
Explanation:
Gravitational force is obviously one of the biggest obstacles in climbing. You are essentially going against this very strong force to pull your body mass up the beautiful terrain. Gravity is defined as the force of attraction between all masses in the universe, gravity is what allows the sport of climbing.
Answer:
Gravity, low oxygen, and rock slides.
Explanation:
Some rock climbers train for years but are hardly prepared for some situations.
3. A car has a mass of 1,000 kilograms. If a net force of 2,000 N is exerted on the car, what is its acceleration?
Answer:
2 m/s^2
Explanation:
Acceleration = Force/mass
= 2,000/1,000
= 2
1.Copper is wrapped with rubber when used in electric wiring. What describes rubber as a material? (1 point)
Responses
superconductor
electromagnet
insulator
conductor
2. Which material provides resistance to the flow of electrons? (1 point)
Responses
silver
saltwater
copper
salt crystals
3. The set up for a science experiment uses a battery, light bulb and copper wire. Which material can be connected to copper wire and a battery to light up the bulb?(1 point)
Responses
nylon string
aluminum foil
plastic straw
rope
4. An electrician wears rubber gloves when working on electrical wiring. What is the purpose of the rubber gloves? (1 point)
Responses
to protect hands from being punctured or cut
to increase the temperature of the hands
to prevent electric shock by restricting the flow of electrons
to allow more electrons to pass through.
5. Why is metal a good conductor? (1 point)
Responses
Its valence electrons flow freely through the material.
It has a higher restriction for moving electrons.
Its rigid structure creates a strong bond among electrons.
It has a solid and compact material.
Rubber is not conducting and is called an insulator. Insulators provide resistance to the flow of electrons. Aluminum foil can be used to the copper wire to light up the bulb.
What are conductors ?Based on the conductivity, there are three types of materials namely, conductor, semiconductors and insulators. Conductors are able to allow the flow of free electron through them thus conduct electricity at room temperature.
Semiconductors only conduct at high temperature and insulators does not conduct at any temperature. Rubber is an insulator and thus used as protecting gloves for hands to prevent electric shock.
Salt crystals in the solid state are not conducting. But the salt solution is conducting due to the presence of ions.
The material which can be used connected to copper wire and a battery to light up a bulb is aluminum foil. Metals are good conductors because, its valence electrons flow freely through the material.
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Rubber, which is not conducting, is referred to be an insulator. Providing barrier to the movement of electrons is an insulator. Copper wire can be wrapped in aluminum foil to light the bulb.
How do conductors work?Three different categories of materials—conductors, semiconductors, and insulators—are categorized according to their conductivity. At normal temperature, conductors can flow free electrons through them and conduct electricity.
Insulators do not conduct at any temperature, while semiconductors only do so at high temperatures. Rubber acts as an insulator, making it ideal for use as hand protection against electric shock.
In the solid state, salt crystals are not conductors. But because ions are present, the salt solution conducts.
Therefore, Rubber, which is not conducting, is referred to be an insulator. Providing barrier to the movement of electrons is an insulator. Copper wire can be wrapped in aluminum foil to light the bulb.
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A pencil is dropped from rest from a height of 1.8 meters above the ground. How much time does it take the pencil to hit the ground?
Answer:
0.60s
Explanation:
Using the motion equation as follows:
S = ut + 1/2gt²
Where;
S = distance travelled (m)
u = initial velocity (m/s)
t = time (s)
g = acceleration due to gravity (m/s²)
Based on the information provided, S = 1.8m, u = 0m/s, t = ?
S = ut + 1/2gt²
1.8 = (0×t) + 1/2 (9.8t²)
1.8 = 0 + 4.9t²
1.8 = 4.9t²
t² = 1.8/4.9
t² = 0.3673
t = √0.3673
t = 0.6060
t = 0.60s
Which of the following would be examples of derived demand?
1. A school hiring more teachers because the school's enrollment increased.
II. More people working at the movie theatre on Friday night because attendance increased.
III. More construction workers are needed because more people can afford to buy a new house.
O I and II only
o I and III only
Il and Ill only
O I, II and III
Answer:
The last one
Explanation:
on the exam
Among the following the derived demands are options 1 and 3 only. Because in each case, the demand for one thing is originated by the demand for another.
What is derived demand?The phrase derived demand in economics refers to the demand for a factor of production or intermediate good that results from the demand for another intermediate or final good. In essence, consumer demand for the firm's product determines how much a firm will need.
Additionally, if activity in one area rises, any sector that contributed to the success of the first sector may also experience growth. Here, the school is hiring more teachers because enrollment is increased. Thus, enrolling more teachers satisfies the demand by greater enrollments.
Similarly by recruiting more construction workers the increased demand for new house by people can be solved. However, the second case for filling the attendance is a necessary and not a derived demand.
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What is the difference between wind energy and solar energy?
Answer: Wind energy is powered by wind, and solar energy is powered by the Sun.
A neutral cloth and a neutral rod are rubbed together. Electrons are transferred from the cloth to the rod. What is the final charge on the overall cloth-rod system?A. PositiveB. NeutralC. NegativeD. Not enough info
Given that a neutral cloth and a neutral rod are rubbed together and electrons are transferred from the cloth to the rod.
Let's find the final charge on the overall cloth-rod system.
Here, since a neutral cloth and a neural rod are rubbed together, there is a transfer of charges between both materials.
The metal rod is a conductor while the cloth is an insulator.
As both materials are rubbed together, there is a transfer of electrons. This is due to friction on the materials.
Now, we know that electrons are negatively charged.
As electrons transfer, the rod becomes positively charged while the cloth becomes negatively charged.
Since both materials have opposite charges, the final charge on the overall cloth-rod system will be a NEUTRAL charge.
When a system is neutral, it means that the system has an equal amount of positive and negative cha
• ANSWER:
B. Neutral
Explain the advantages and disadvantages of having a racecar with a small mass in reference to Newton’s 1st law of motion. Use the term inertia in your answer.
Answer:
Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. This tendency to resist changes in a state of motion is inertia.
Explanation:
A 200kg car is driving at 20m/s down the road when he sees a red light. He slows to a stop.
The car's initial momentum is ___kg m/s
The car's final momentum is ___kg m/s
The car's impulse is
___kg m/s
Answer:
Initial Momentum - 4000 kg*m/s
Final Momentum - 0 kg*m/s
Impulse: -4000 kg*m/s
Explanation:
The equation for momentum is P = mv
Initial Momentum
200kg * 20m/s = 4000 kg*m/s
Final Momentum
200kg * 0m/s = 0kg*m/s
Impulse = ΔP
Pfinal - Pintial = Impulse
0-4000 = -4000 kg*m/s
blank refers to the method of spreading fertilizer evenly over the entire field by hand it is done at the blank stage
Answer:
Broadcasting is the method, not sure about the stage it is done in
Explanation:
Answer:
Broadcasting is the first (blank) second (blank) is Cultivation.
Explanation:
I took the test & got this answer correct.
A small car with mass 0.610 kg
travels at constant speed on the inside of a track that is a vertical circle with radius 5.00 m
If the normal force exerted by the track on the car when it is at the top of the track (point B
) is 6.00 N
, what is the normal force on the car when it is at the bottom of the track (point A
)?
Express your answer with the appropriate units.
The normal force on the car when it is at the bottom of the track is 8.84 N.
At the top of the track (point B), the normal force (N) acting on the car is equal to the weight of the car (mg) plus the centrifugal force (mv²/r) acting outwards:
N = mg + mv²/r
where m is the mass of the car, g is the acceleration due to gravity, v is the speed of the car, and r is the radius of the track.
Since the car is traveling at constant speed, its acceleration is zero, so the centrifugal force is balanced by the force of gravity, and we have:
N = mg
Substituting the given values, we get:
6.00 N = (0.610 kg)(9.81 m/s²)
Solving for g, we get:
g = 9.68 m/s²
At the bottom of the track (point A), the normal force acting on the car is equal to the weight of the car minus the centrifugal force acting downwards:
N = mg - mv²/r
Substituting the known values, we get:
N = (0.610 kg)(9.81 m/s²) - (0.610 kg)(v²/5.00 m)
Since the car is traveling at constant speed, we can use the fact that its kinetic energy is equal to its gravitational potential energy to solve for v:
mg(2r) = (1/2)mv²
where 2r is the total distance traveled by the car (i.e., the circumference of the circle), so 2r = 2πr = 31.4 m. Solving for v, we get:
v = sqrt(2gr)
Substituting the known values, we get:
v = sqrt(2(9.68 m/s²)(5.00 m)) = 6.19 m/s
Substituting this value of v into the equation for N, we get:
N = (0.610 kg)(9.81 m/s²) - (0.610 kg)((6.19 m/s)²/5.00 m) = 8.84 N
Therefore, the normal force on the car when it is at the bottom of the track is 8.84 N.
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a current of a 6 flows through a light bulb for 12 s, how many coulombs of charge pass through the light bulb during this time
A current of a 6 flows through a light bulb for 12 s. The total charge that passes through the light bulb during the given time is 72 coulombs.
To calculate the total charge that passes through the light bulb, we need to use the formula Q = I * t, where Q represents the charge in coulombs, I represents the current in amperes, and t represents the time in seconds.
Step 1: Identify the known values:
Current (I) = 6 amperes
Time (t) = 12 seconds
Step 2: Calculate the charge using the formula:
Q = I * t
Step 3: Substitute the known values into the formula:
Q = 6 amperes * 12 seconds
Q = 72 coulombs
Therefore, the total charge that passes through the light bulb during the given time is 72 coulombs.
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find the average speed of a car that travels 45km in 2hours 15minutes
Answer:
20 km/h
Explanation:
45 km ÷ 2.25 hours (15 mins is 0.25 hours)
= 20
20 km/h
If you walk at an average speed of 5 km/h for 30 minutes. How far will you walk ?
The distance walked is 2500 m.
To find the distance, the given values are,
Average speed = 5 km /hr
Time = 30 minutes.
What is the distance?The distance covered by a body is equal to the sum of total path covered i.e., the total speed with respect to particular time. It is equal to the total path traveled by an object during its entire journey.This quantity is always positive. It can't be 0 or a negative number.It is defined as a scalar quantity. A scalar quantity represents only the magnitude and does not give any detail about the direction of the quantity. Distance can be measured in any length also in any direction (no specific direction)Mathematically, it can be calculated as follows :
Distance = speed × time
Substituting the given values are,
Distance = 5 km / hr × 30 minutes
= 2500 m.
The distance walked is 2500 m.
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Professor Stauffer conducts basic research on the psychological, biological, and behavioral
factors that contribute to heart disease. She is most likely a
High blood pressure, high LDL cholesterol, diabetes, smoking, exposure to secondhand smoke, obesity, a poor diet, and inactivity are the main risk factors for heart disease and stroke.
Explain about the contribute to heart disease?High blood pressure, high cholesterol, and smoking are the three main risk factors for heart disease that at least half of all Americans (47%) have. Age and family history are two uncontrollable risk factors for heart disease.
The most frequent cause of coronary artery disease is atherosclerosis, which is a buildup of fatty plaques in the arteries. Poor diet, lack of exercise, obesity, and smoking are risk factors. Choosing a healthy lifestyle can help reduce the risk of atherosclerosis.
The most prevalent type of heart disease is coronary heart disease (CHD). It happens when plaque deposits cause the arteries that carry blood to the heart to constrict or stiffen. Fat, cholesterol, and other components found in blood make up plaque. The term "atherosclerosis" also refers to this plaque accumulation.
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A bus of mass 2500 kg goes round a corner of radius 50 m at a speed of 5 m/s. What force is needed for the bus to go round the corner?
Answer:
force needed for the bus to go round the corner is 50,000 N.
Explanation:
To find the force needed for the bus to go round the corner, we can use the formula for centripetal force:
F = (mv^2)/r
where F is the centripetal force, m is the mass of the object, v is the velocity of the object, and r is the radius of the circular path.
Plugging in the values given in the problem, we get:
F = (2500 kg)(5 m/s)^2 / 50 m
= 50,000 N
So the force needed for the bus to go round the corner is 50,000 N.
3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?
The car is moving at approximately 12.5 meters per second.
The kinetic energy (KE) of an object can be calculated using the formula:
KE = 1/2 * m * \(v^2\)
where
KE = kinetic energy,
m =Mass of the object, and
v = velocity.
In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .
Substituting the values , we have:
125,000 J = 1/2 * 1600 kg *\(v^2\)
Now, we can solve for v by rearranging the equation:
\(v^2\) = (2 * 125,000 J) / 1600 kg
\(v^2\) = 156.25 \(m^2/s^2\)
Taking the square root, we find:
v = √156.25\(m^2/s^2\)
v ≈ 12.5 m/s
Therefore, the car is moving at approximately 12.5 meters per second.
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explain why the length of the pendulum is measured from the lower part of the wooden clamp
The length of the pendulum is measured from the lower part of the wooden clamp, because the center of gravity is at the center of the bob.
The simple pendulum's length, l is determined by measuring it from the point of suspension to the center of gravity (center of the bob), which is the place where all of this sphere's mass is concentrated.
The center of the mass will exactly reside in the center of the bob when we take the bob's dimensions into account.
As a result, the total length is now equal to the length of the string plus the bob's radius. The length is thus measured from the lower part of the wooden clamp.
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During a head on collision between a car and an SUV, which one, if any experiences, a larger impact force?
what is the velocity of the object 2.3 seconds after it is released from the top of the empire state building?
Explanation:
Object is under the effect of the acceleration of gravity
v = 1/2 a t^2 a = 9.81 m/s^2 t = 2.3
v = 25.9 m/s^2 = ~ 26 m/s ( two significant digits)
hello using the kinematic eqautions for the horizontal projectile of a ball being thrown I am given range of flight dx= 1.02time of flight t= 1.20 sheight of launch dy= 1m I need help finding the initial velocity of the realase
Answer:
intial velocity: 6.02 m /s
Explanation:
To find the initial velocity, we make use of the following kinematic equations
\(\begin{gathered} y=y_0+(v_0\sin \theta)t-\frac{1}{2}gt^2 \\ x=(v_0\cos \theta)t \end{gathered}\)Now we know that t = 1.20 s, g = 9.8 m /s, y0 = 1.0 m, and at the ground y =0; therefore, the above equations give
\(\begin{gathered} 0=1+(v_0\sin \theta)(1.20)-\frac{1}{2}(9.8)(1.20)^2 \\ 1.02=(v_0\cos \theta)(1.20) \end{gathered}\)solving these equations for v0 sin θ and v0 cos θ gives
\(\frac{\frac{1}{2}(9.8)(1.20)^2-1}{\mleft(1.20\mright)}=(v_0\sin \theta)\)\(\Rightarrow v_0\sin \theta=5.05\)and
\(\frac{1.02}{\mleft(1.20\mright)}=(v_0\cos \theta)\)\(v_0\cos \theta=0.85\)Now dividing the two equations gives
\(\frac{v_0\sin \theta}{v_0\cos \theta}=\frac{5.05}{0.85}\)\(\tan \theta=5.94\)taking the inverse tan gives
\(\theta=80.45^o\)Now that we know theta, it is easy to find v0.
\(v_0\sin (80.45)=5.94\)\(v_0=\frac{5.94}{\sin (80.45)}\)\(\boxed{v_0=6.02}\)which is our answer!
A hypothetical planet has a radius 1.8 times that of Earth but has the same mass. What is the acceleration due to gravity near its surface?
The acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².
The formula for acceleration due to gravity is:
g = GM/r² Where, g = acceleration due to gravity G = universal gravitational constant M = mass of the planet r = radius of the planet
In this case, since the mass of the hypothetical planet is the same as that of Earth, we can use the mass of Earth instead of M.
Therefore, g is proportional to 1/r².
So, using the ratio of radii given (1.8), we can write:
r = 1.8 x r Earth, where r Earth is the radius of Earth.
Substituting this value of r in the formula for acceleration due to gravity, we get:
g = GM/(1.8 x r Earth)² = GM/(3.24 x rEarth²) = (1/3.24)GM/rEarth²
We know that the acceleration due to gravity on Earth (g Earth) is 9.8 m/s².
Therefore, we can calculate the acceleration due to gravity on the hypothetical planet (gh) as follows:
gh = (1/3.24) x g Earth = 3.02 m/s²
Thus, the acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².
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plate tectonics allow scientists to explain many ________ and to ________ geologic events.
Answer: Plate tectonics allow scientists to explain many _observations_______ and to ___predict_____ geologic events.
Explanation:
observations, predict
A 10-kg package drops from chute into a 25-kg cart with a velocity of 3 m/s. The cart is initially at rest and can roll freely with no friction. Determine: a) the final velocity of the cart, b) the impulse exerted by the cart on the package, c) the fraction of the initial energy lost in the impact.
Answer:
(a) the final velocity of the cart is 0.857 m/s
(b) the impulse experienced by the package is 21.43 kg.m/s
(c) the fraction of the initial energy lost is 0.71
Explanation:
Given;
mass of the package, m₁ = 10 kg
mass of the cart, m₂ = 25 kg
initial velocity of the package, u₁ = 3 m/s
initial velocity of the cart, u₂ = 0
let the final velocity of the cart = v
(a) Apply the principle of conservation of linear momentum to determine common final velocity for ineleastic collision;
m₁u₁ + m₂u₂ = v(m₁ + m₂)
10 x 3 + 25 x 0 = v(10 + 25)
30 = 35v
v = 30 / 35
v = 0.857 m/s
(b) the impulse experienced by the package;
The impulse = change in momentum of the package
J = ΔP = m₁v - m₁u₁
J = m₁(v - u₁)
J = 10(0.857 - 3)
J = -21.43 kg.m/s
the magnitude of the impulse experienced by the package = 21.43 kg.m/s
(c)
the initial kinetic energy of the package is calculated as;
\(K.E_i = \frac{1}{2} mu_1^2\\\\K.E_i = \frac{1}{2} \times 10 \times (3)^2\\\\K.E_i = 45 \ J\\\\\)
the final kinetic energy of the package;
\(K.E_f = \frac{1}{2} (m_1 + m_2)v^2\\\\K.E_f = \frac{1}{2} \times (10 + 25) \times 0.857^2\\\\K.E_f = 12.85 \ J\)
the fraction of the initial energy lost;
\(= \frac{\Delta K.E}{K.E_i} = \frac{45 -12.85}{45} = 0.71\)
Object A is an insulator. Object B is a conductor. Object A is neutral. Object B has a positive charge. Object A is touched to the ground. When the ground is pulled away, what charge do the two objects have?
When the ground is pulled away, the charge that the two objects have is that Object A is now negatively charged and Object B is still positively charged.
How does this work?After touching object A to the ground, object A will have zero charges as it is an insulator and the ground is neutral, so no charges will flow.
Object B still has a positive charge as it is a conductor, and since object A is not connected to it anymore, there will be no transfer of charges between them.
Recall that an insulator is any property that does NOT allow electric charges to pass through them.
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?
Which activity is health enhancing?
folding a load of laundry
driving long distances
O biking to school
unloading the dishwasher
Answer:
biking to school
Explanation:
plato
If a ball is thrown horizontally with an initial velocity of 20.0 Meters per second from a 60.0 meter high tower what is the horizontal velocity of the ball before it reaches the ground
Answer:
Below
Explanation:
Horizontal velocity will not change ( since we are neglecting air friction)
it will still be 20 m/s horizontally
The horizontal velocity of the ball before it reaches the ground is 20.0 meters per second.
What is velocity?
The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
Given that: a ball is thrown horizontally with an initial velocity of 20.0 Meters per second from a 60.0 meter high tower.
Now when the ball is in free fall, acceleration due to gravity acts in downwards in vertical direction but there has no acceleration in horizontal direction.
So, as there has no mention of air resistance in the question; the horizontal velocity will remain same before it reaches the ground.
Hence, the horizontal velocity of the ball before it reaches the ground is 20.0 meters per second.
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What happens to a blackbody radiator as it increases in temperature?
Answer:
it gives off a range of electromagnetic radiation of shorter wavelengths.
Explanation:
I took the test
Answer:it gives off range of electromagnetic radiation for shorter
Wavelengths
Explanation: