To find the specific heat capacity, we can use the formula Q = mcΔT, where Q is the amount of heat energy required, m is the mass of the object, c is the specific heat capacity, and ΔT is the change in temperature.
Given:
- Mass of the object (m) = 50.0g
- Amount of heat energy required (Q) = 1,145 joules
- Change in temperature (ΔT) = 10.0°C
Using the formula Q = mcΔT, we can rearrange it to solve for c:
c = Q / (mΔT)
Plugging in the given values, we get:
c = 1,145 J / (50.0 g x 10.0 °C)
c = 2.29 J/g°C
Therefore, the specific heat capacity of the object is 2.29 J/g°C.
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A ball is thrown directly downward with an initial speed of 7.05 m/s, from a height of 29.9 m. after what time interval does it strike the ground? s
The ball that is thrown directly downward with an initial speed of 7.05 m/s, from a height of 29.9 m. takes 3.29 s to strike the ground
The formula for the downward vertical launch and the procedure we will use is:
t = {V₀ + \(\sqrt{}\)[(V₀)² + 2*g*y]}/ g
Where:
v₀ = initial velocityg = gravityy = heightt = timeInformation about the problem:
g = 9.8 m/s²v₀ = 7.05 m/sy = 29.9 mt= ?With the information gave, we can calculate the time from the ball is thrown, using the formula of downward vertical launch:
t = {V₀ + \(\sqrt{}\)[(V₀)² + 2*g*y]}/ g
t = {7.05 m/s + \(\sqrt{}\)[(7.05 m/s)² + 2*9.8 m/s²*29.9 m]}/ 9.8 m/s²
t = {7.05 m/s + \(\sqrt{}\)[49.70 m²/s² + 586.04m²/s² ]}/ 9.8 m/s²
t = {7.05 m/s + \(\sqrt{}\)[635.74 m²/s² ]}/ 9.8 m/s²
t = {7.05 m/s + 25.214 m/s}/ 9.8 m/s²
t = 32.26 m/s/ 9.8 m/s²
t = 3.29 s
What is vertical launch?In physics vertical launch is the motion described by an object that has been launched vertically in which the acceleration is the earth's gravitational force.
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a particle in uniform circular motion has a period of 4.0 seconds. what is the particle's frequency?
If you pay children in kindergarten to make things from modeling clay, and then stop, you may find that they are less willing to do it for nothing than they were before you ever started paying them. This is an example of?
Answer: overjustification
Explanation:
The overjustification effect is a situation that occurs when an incentive like prizes or money or prizes leads to the reduction in an individual's intrinsic motivation that is necessary in performing a task.
In this case, because the children are motivated by money, when the take doesn't involve money anymore, they may not be willing to do it.
Who was this scientist, what ideas did he form, and how did he figure out these new ideas of atoms?
pls dont plagiarize!!
Answer:
Atoms cannot be divided.
Explanation:
What are the two groups of planets based on composition?
Where did Ford first see parts made from vanadium steel? What properties of this steel impressed Ford? Did Ford need to overcome any problems before going ahead with his plan?
Explanation:
Historical sources believe that Henry Ford first saw parts made from vanadium steel in Europe which were been used on racing cars and luxurious vehicles.
Ford was impressed due to the fact that Vanadium steel unlike normal steel was cheaper and at the same time stronger and lighter if it was used on automobiles.
What force besides gravity controls the orbit of a planet or moon?
The gravitational force from the sun controls the orbit of the moon and the planet besides gravity.
Anything in the universe if has mass, then it is tends to have some gravitational interaction with other objects having some mass.
The moon and the planet interact with each other due to the gravity of the planet. Beside this gravity, one more force that is responsible is the gravitational force due to the sun.
The gravitational force of the sun makes the earth rotate around the sun, and it indeed result in the rotation of the moon around the planet.
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Explain why you exert a force on the pedals, but you obey the laws of conservation of energy
When you exert a force on the pedals while cycling, you convert chemical energy stored in your body into mechanical energy to propel the bike forward.
Despite exerting force, you obey the laws of conservation of energy because the total energy of the system remains constant. The chemical energy from your body is transferred to the pedals, which in turn transfers it to the bike's wheels through the chain. This mechanical energy is then used to overcome friction and air resistance, ultimately propelling the bike forward. While you are exerting a force, the energy is conserved by converting it from one form to another, rather than creating or destroying it. When you pedal a bike, you apply a force on the pedals to generate power. This force causes the pedals to rotate, which transfers the energy from your muscles to the bike's drivetrain. This energy is then converted from chemical energy (stored in your body) to mechanical energy (the movement of the bike). According to the law of conservation of energy, energy cannot be created or destroyed, only converted from one form to another. Therefore, the energy you exert on the pedals is not lost but transformed into other forms, such as kinetic energy to move the bike forward, potential energy due to elevation changes, or heat energy due to friction and air resistance. The total energy of the system (you and the bike) remains constant throughout this process.
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IMPORTANT! A 50.0 g bullet is fired horizontally into a 4.50 kg wooden block that is initially at rest on a horizontal table. The initial speed of the bullet is 95.0 m/s. Upon impact, the block with the bullet slides across the table for a distance d before coming to a stop. Given that the coefficient of friction between the block and the table is 0.250, how far (d) did the block with the embedded bullet slide?
Answer:
20.22 m
Explanation:
Bullet mass = .05 kg
Initial Kinetic Energy = 1/2 m v^2 = 1/2 (.05)(95^2 ) = 225.625 j
The work of friction must equal this KE
Normal force will be the wooden block PLUS the bullet times g
= 4.55 * 9.81
force of friction is normal force * coefficient of friction
= 4.55 * 9.81 * .250 N
work of friction will be the force of friction x distance
225.625 J = (4.55)(9.81)(.250) * d
d = 20.22 m
HELP ME ASAP PLZ!
What is the relationship between an electromagnetic wave and the vibrations of the electric and magnetic fields it moves through.
Calculate the power required to move a 2,000-kilogram automobile to the top of a 100-meter hill in 15. 0 seconds. Express the power both in
units of watts and horsepower.
The power required to move the automobile to the top of the hill is 130,666.67 watts or 175.41 horsepower.
The power required to move an object can be calculated using the formula: power = work / time.
First, let's calculate the work done in lifting the automobile to the top of the hill. The work done against gravity is given by the formula: work = force × distance.
The force required to lift the automobile is equal to its weight. The weight of an object is given by the formula: weight = mass × acceleration due to gravity.
Substituting the given values, we have: weight = 2,000 kg × 9.8 m/s^2 (acceleration due to gravity) = 19,600 N.
The distance the automobile is lifted is 100 meters.
Therefore, the work done against gravity is: work = 19,600 N × 100 m = 1,960,000 J (joules).
The time taken to reach the top of the hill is given as 15.0 seconds.
Now, we can calculate the power using the formula: power = work / time.
power = 1,960,000 J / 15.0 s = 130,666.67 W (watts).
To convert watts to horsepower, divide the power in watts by 746 (1 horsepower = 746 watts).
power in horsepower = 130,666.67 W / 746 = 175.41 hp (horsepower).
Rounding to two decimal places, the power required to move the automobile to the top of the hill is approximately 130,666.67 watts or 175.41 horsepower.
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The to problem of calculating the power required to move a 2,000-kilogram automobile to the top of a 100-meter hill in 15.0 seconds is given
Given, Mass of the automobile, m = 2000 knight of the hill, h = 100 time, t = 15.0 the gravitational potential energy of the automobile when at the bottom of the hill is equal to the work done in lifting it up the hill
.W = mgh= (2000 kg) (9.81 m/s²)
(100 m)= 1,962,000 J
Power is defined as the rate at which work is done, or the work per unit time. Therefore,
Power = Work / Time= 1,962,000 J / 15.0 s
= 130,800 WIn horsepower, Power = (130,800 W) / (746 W/hp)
= 175.3 hp
Therefore, the required power to move a 2,000-kilogram automobile to the top of a 100-meter hill in 15.0 seconds is 130,800 W or 175.3 hp.
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Question 7 of 10
What is kinetic friction?
A. Friction that acts when an object is not moving
B. Friction that opposes air resistance
C. Friction that exerts no force
D. Friction that acts on a sliding object
SUBMIT
Answer: Friction that acts on a sliding object
Explanation:
A force of 85 N is used to push a box along the floor a distance of 15 m. How much work was done?
Answer:
1275J
Explanation:
Given parameters:
Force on box = 85N
Distance moved = 15m
Unknown:
Work done = ?
Solution:
Work done is the amount of force applied on a body to move it through a specific distance.
Work done = Force x distance
Now insert the parameters and solve;
Work done = 85 x 15 = 1275J
When a sample of Radium-226 decays, the energy released is 7.81 ×10^-13 J.What is the mass defectA. 8.68×10^-30 kgB. 2.60×10^-21 kgC. 3.84 × 10^20 kgD. 1.15×10^29 kg
The mass defect and the energy released in radioactive decay are related by the following equation:
\(E=mc^2\)Where:
\(\begin{gathered} E=\text{ Energy} \\ m=\text{ mass} \\ c=\text{ speed of light} \end{gathered}\)We solve for the mass by dividing both sides by the square of the velocity of light:
\(\frac{E}{c^2}=m\)The speed of light is a constant and is equal to:
\(c=3\times10^8\frac{m}{s}\)Now we replace the given values:
\(\frac{7.81\times10^{-13}J}{(3\times10^8\frac{m}{s})^2}=m\)Now we solve the square in the denominator:
\(\frac{7.81\times10^{-13}J}{9\times10^{16}\frac{m}{s}}=m\)Now we solve the operations and we get:
\(8.68\times10^{-30}\operatorname{kg}=m\)Therefore, the mass defect is option A.
A bullet of mass 0.01kg is fired with velocity of [230,0]m/s in to a sack of sand of mass 9.99kg which is swinging from rope. At the moment the bullet hits, the sack has a velocity of [0,0.2]m/s. Workout the velocity of bullet of the sack.
Answer:
The velocity of the bullet and the sack after the bullet hits the sack is [0.2,0.2] m/s.
Explanation:
To calculate the velocity of the bullet and the sack after the bullet hits the sack, we can use the equation:
vf = (m1 * v1 + m2 * v2) / (m1 + m2)
Plugging in the values given in the question, we get:
vf = (0.01 kg * [230,0] m/s + 9.99 kg * [0,0.2] m/s) / (0.01 kg + 9.99 kg)
Solving for vf, we get:
vf = [0.2, 0.2] m/s
Therefore, the velocity of the bullet and the sack after the bullet hits the sack is [0.2,0.2] m/s.
The initial and final momentum of a body will be conserved during collision. From this concept, the final velocity of the bullet and sack is 2.5 m/s.
What is momentum?Momentum is the product of mass and velocity of a body. During a collision of two bodies, the sum of initial momentum of the two bodies will be equal to the sum of their final momentum.
Given that, mass of bullet = 0.01 Kg
velocity = 2300 m/s
mass of sand sack = 9.99 Kg
velocity = 0.2 m/s
Then sum of initial momentum = (0.01 kg × 2300 m/s) + (9.99 kg × 0.2 m/s) = 24.9 kg m/s.
The final momentum of the combined mass = (9.99 kg + 0.01 kg) v = 24.9 Kg m/s
Thus, final velocity v = 24.9 / ( (9.99 kg + 0.01 kg) = 2.5 m/s
Therefore, the velocity of the bullet and sack after the collision will be 2.5 m/s.
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A car travels at a speed of 62 km/h for 37 min. How far does the car travel in km?
The correct answer is car travels distance of 38.19 Km. in time of 37 min.
What is relation between speed, time, distance?
Speed = Distance/Time
It describes one object how much distance travelled is going to cover in referred time.
Given, Speed = 62 Km/hr. means 62 Km is going to cover in 1 hr. or 60 min
As Speed = Distance / time
As time is given in min form so in hr. it will be 37 min / 60 = 0.616 hr.
62 Km/ hr. = X Km / 0.616
X in Km= 62 x 0.616 = 38.19 Km.
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A plate has an area of 1m square. It slide down an incline plane , having an angle of inclined 60° to horizontal, which a velocity of 0.75m/s. The thickness of oil film between the plate and the plate is 2mm. Find the viscosity of the fluid if the weight of the plate is 90N
Answer:
\(\mu =0.169704 Ns/m^2\)
Explanation:
From the question we are told that
Area of plate\(a=1m^2\)
Angle of inclination \(\theta=60 \textdegree\)
Velocity \(v=0.75m/s\)
Thickness of oil \(t=2mm\)
Weight of plate \(w=90N\)
Generally the equation for shear force is mathematically given by
\(F=mgsin45 \textdegree\)
\(F=90sin45 \textdegree\)
\(F=63.639N\)
\(F=\mu* \frac{v}{t}\)
\(F=\mu* \frac{0.75}{2*10^-^3}\)
\(\mu* \frac{0.75}{2*10^-^3}=63.639N\)
\(\mu =\frac{63.639}{375}\)
Therefore viscosity is given by
\(\mu =0.169704 Ns/m^2\)
What happens to the force of gravity between two masses if one mass is decreased?
A. It stays the same.
B.it fluctuates.
C. It increases.
D. It decreases.
Answer:
D. It decreases
Explanation:
The watermelon is heaviest, followed by the soccer ball, golf ball and ping pong ball. How does the weight of an object relate to how fast it falls with a parachute?
Answer:
It doesn’t really relate
Explanation:
heavier load the parachute must be moving faster to match the downward force of the greater load
and approx terminal velocity when the parachute is open
velocity for Ping pong ball with parachute = 9m/s
velocity for Soccer ball with parachute = 15m/s
velocity for Golf ball with parachute =24m/s
velocity for Watermelon with parachute = 25m/s
so weight of an object doesn’t really realted how fast it falls with a parachute
what would the roche limit be for an earth-orbiting body with the same density as earth? (the earth's density is 5.5 g/cm3. give your answer in terms of rearth.)
Buying or selling the Earth will go against the rights of the inhabitants of the world (humans and other living beings).
What is the Roche limit of Earth?
Solar influence
Far from the Roche limit, the mass is practically spherical. Closer to the Roche limit, the body is deformed by tidal forces. Within the Roche limit, the mass's own gravity can no longer withstand the tidal forces, and the body disintegrates.If Earth had two moons, it would be catastrophic. An extra moon would lead to larger tides and wipe out major cities like New York and Singapore. The extra pull of the moons would also slow down the Earth's rotation, causing the day to get longer.The Moon will swing ever closer to Earth until it reaches a point 11,470 miles (18,470 kilometers) above our planet, a point termed the Roche limit. "Reaching the Roche limit means that the gravity holding it [the Moon] together is weaker than the tidal forces acting to pull it apart," Wilson said.The Roche limit for the Moon orbiting the Earth is 2.86 times radius of EarthThe nearest distance between the planet and its satellite at where the planets gravitational pull does not torn apart the planets satellite is known as Roche limit.The relation to determine Roche limit is:
\(Roche Limit=(2.423) (Rp3) {{\sqrt[3]{\frac{D_{P} }{D_{m} } } } }\)
Here is radius of planet and are density of planet and moon respectively.
According to the problem,
Density of Earth, = 5.5 g/cm³
Density of Moon, = 3.34 g/cm³
Consider be the radius of the Earth.
Substitute the suitable values in the equation (1).
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An electric motor lifts a roller coaster car that weighs 10,000 N to the top of the first hill that is 20 m above the ground. To add suspense, the ride up to the top takes 150 seconds.
Caculate the power of the motor
The power of the motor is 1333.33 watts or 1.33 kilowatts (kW).
The work done by the electric motor in lifting the roller coaster car to the top of the hill is given by the product of the force applied and the distance moved in the direction of the force:
Work = Force x Distance
The force applied by the motor is the weight of the roller coaster car, which is 10,000 N. The distance moved in the direction of the force is the height of the hill, which is 20 m.
So, the work done by the motor is:
Work = Force x Distance
= 10,000 N x 20 m
= 200,000 J
The time taken for the motor to do this work is 150 seconds. The power of the motor is the rate at which it does work, or the work done per unit time. So, the power of the motor is:
Power = Work / Time
= 200,000 J / 150 s
= 1333.33 W
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HIS system of color stands for hue, intensity and saturation, respectively. They represent: which color depending on light spectrum, the average of its R,G,B components, and the degree of mixture of a color from R, G,B colors. Light frequency, wave length, and brightness. degree of mixture of a color from R, G, B, the average of its (R, , G,B), and which color depending on light spectrum which color depending on light spectrum, degree of mixture of a color from R, G, B colors, and the average of its R, G, B components.
The HIS color system represents a color's hue, intensity (brightness), and saturation (purity) to describe its position in the light spectrum, average RGB components, and degree of mixture from RGB channels. It helps understand color perception and is used in fields like image processing and computer graphics.
The HIS system of color, which stands for hue, intensity, and saturation, is a color model that represents different aspects of a color's characteristics. The three components of the HIS system provide information about the color's position in the visible light spectrum, its brightness, and the degree of mixture of the red (R), green (G), and blue (B) color components.
Hue refers to the actual color perceived by our eyes and is determined by the dominant wavelength of light. It represents which specific color the light falls under in the visible spectrum, such as red, orange, yellow, green, blue, or violet.
Intensity, also known as brightness, is the average of the red, green, and blue components of a color. It indicates how much light is present in the color, ranging from darker shades to brighter ones. Higher intensity values result in more vibrant and saturated colors, while lower values indicate darker and less vibrant colors.
Saturation represents the degree of mixture of a color from the red, green, and blue color channels. It determines the purity or vividness of a color. A highly saturated color is more pure and vibrant, while a desaturated color appears more washed out or pale.
In summary, the HIS color system provides a comprehensive representation of a color's characteristics. Hue determines the color based on the light spectrum, intensity represents the average of the color's RGB components and its brightness, and saturation indicates the degree of mixture of the color from the RGB channels. This model helps in understanding and describing various aspects of color perception and is commonly used in fields like image processing, computer graphics, and color theory.
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Antonio reads in his lab directions that he needs to obtain 15ml of distilled water. which piece of lab equipment does antonio need in order to measure this?
Antonio will need a pipette to measure 15 ml of distilled water in a laboratory.
What is a pipette?A pipette is a laboratory equipment used in measuring liquids in little amounts. 15 ml is a small amount of liquid so a pipette is a better fit for such amount.
We can conclude that a pipette is a better instrument to measure 15 ml of distilled water.
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if you shout into the grand canyon, your voice travels at the speed of sound (340 m/s) to the bottom of the canyon and back, and you hear an echo. how deep is the grand canyon at a spot where you can hear your echo 5.2 seconds after you shout? [hint: think about the path the sound has to travel for you to hear your own echo.]
The Grand Canyon is 884 m deep from the spot where I heard the echo
The formula for uniformly rectilinear motion (URM) and procedure we will use to solve this exercise is:
v = x /t
Where:
x = distancet = timev = velocityInformation about the problem:
t(echo) = 5.2 sv= 340 m/sx = ?Notice that the echo is a sound that is produced when its wave hits an object (Grand Canyon) and returns to the place where it was emitted (person), that is to say that to calculate the time in which the echo arrived effectively to the bottom of the canyon we must divide it by 2.
t(canyon's bottom) = t(echo)/2
t(canyon's bottom) = 5.2 s/2
t(canyon's bottom) = 2.6 s
Applying the velocity formula, and isolating the distance, we get:
v = x /t(canyon's bottom)
x = v * t(canyon's bottom)
x = 340 m/s * 2.6 s
x = 884 m
What is velocity?It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).
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A 0.060 kg ball hits the ground with a speed of –32 m/s. the ball is in contact with the ground for 45 milliseconds and the ground exerts a 55 n force on the ball. what is the magnitude of the velocity after it hits the ground? 9.3 m/s 12 m/s 41 m/s 73 m/s
Answer:
Approximately \(9.3\; {\rm m\cdot s^{-1}}\).
Explanation:
Apply unit conversion:
\(t = 45\; {\rm ms} = 45 \times 10^{-3}\; {\rm s}\).
At a velocity of \(v\), the momentum \(p\) of an object of mass \(m\) would be \(p = m\, v\).
Initial momentum of this ball:
\(\begin{aligned}p_{0} &= m\, v_{0} \\ &= 0.060\; {\rm kg} \times (-32\; {\rm m\cdot s^{-1}}) \\ &= (-1.92\; {\rm kg \cdot m \cdot s^{-1}})\end{aligned}\).
When a constant force \(F\) is exerted on an object for a duration of length \(t\), the impulse \(J\) applied to that object would be \(J = F\, t\).
Impulse that the ground applied to this ball:
\(\begin{aligned}J &= F\, t \\ &= 55\; {\rm N} \times (45 \times 10^{-3}\; {\rm s}) \\ &= 2.475\; {\rm N \cdot s}\end{aligned}\).
Note that \(1\; {\rm N} = 1\; {\rm kg \cdot m \cdot s^{-2}}\). Thus, the impulse applied to this ball would be equivalent to:
\(\begin{aligned}J &= 2.475\; {\rm (kg \cdot m \cdot s^{-2}) \cdot s} \\ &= 2.475\; {\rm kg \cdot m \cdot s^{-1}}\end{aligned}\).
After this impulse was applied, the momentum of this ball would become:
\(\begin{aligned}p_{1} &= p_{0} + J \\ &= (-1.92\; {\rm kg \cdot m \cdot s^{-1}}) + 2.475\; {\rm kg \cdot m \cdot s^{-1}} \\ &= 0.555\; {\rm kg \cdot m \cdot s^{-1}}\end{aligned}\).
The new velocity of this ball would be:
\(\begin{aligned}v_{1} &= \frac{p_{1}}{m} \\ &= \frac{0.555\; {\rm kg \cdot m \cdot s^{-1}}}{0.060\; {\rm kg}} \\ &\approx 9.3\; {\rm m\cdot s^{-1}}\end{aligned}\).
Answer:
(A)
Explanation:
I took the test
Lunar phases occur when the moon appears to change shape as seen from earth. What causes different phases of the moon?.
Answer: The moon is said to be in full phase when the illuminated half of the moon is fully in position for us to see it. The "new moon" phase of the lunar cycle happens when the sun, moon, and earth are located in a straight line, with the moon between the earth and the sun. The moon is said to be in a "waxing" phase when it is moving from the new moon phase into the full moon phase. During this time, the amount of visible, illuminated moon will be gradually growing. The moon is said to be in a "waning" phase when it is moving from the full moon phase into the new moon phase. During this time, the visible portion of the moon will appear to be shrinking. A crescent moon occurs close to the new and full moon stages, whether the moon is waxing or waning. At this time, only a small sliver of the illuminated moon is visible to us.
Explanation:
A 136 kg defensive lineman is about to tackle a 100 kg quarterback. Right before
impact, the lineman is moving north at 6.0 m/s and the quarterback is moving
north at 1.0 m/s. Determine the speed and direction of the two players
immediately after the tackle.
Answer:
3.88 m/s North
Explanation:
We are given that
\(m_1=136kg\)
\(m_2=100 kg\)
\(v_1=6 m/s\)
\(v_2=1m/s\)
We have to find the speed and direction of the two players
immediately after the tackle.
Using linear conservation of momentum
\(m_1v_1+m_2v_2=(m_1+m_2)v\)
Substitute the values
\(136\times 6+100\times 1=(136+100)v\)
\(916=236v\)
\(v=\frac{916}{236}\)
\(v=3.88m/s\)
Direction of the two players immediately after the tackle is North.
why do we see different phases of the moon? a. the motion of the moon in its orbit around the earth causes us to see different amounts of the earth's shadow falling on the moon. b. the motion of the moon in its orbit around the earth causes us to see different amounts of the sunlit side of the moon. c. the distance of the moon f
Most crashes occur at intersections because __________.
*
2 points
drivers fail to search and identify a safe path of travel when approaching an intersection
drivers don't identify or understand the risks
drivers fail to develop good driving habits to effectively manage the risks
all of the above
Most crashes occur at intersections because Drivers fail to search and identify a safe path of the travel when approaching an intersection. Drivers don't identify or understand the risks. Drivers fail tp develop good driving habits to effectively manage the risks.
Most crashes occur at intersections because of the following reason:
1) Drivers fail to search and identify a safe path of the travel when approaching an intersection.
2) Drivers don't identify or understand the risks.
3) Drivers fail tp develop good driving habits to effectively manage the risks.
Thus, Most crashes occur at intersections because all of the above reason. Most crashes occur at intersections because Drivers fail to search and identify a safe path of the travel when approaching an intersection. Drivers don't identify or understand the risks. Drivers fail tp develop good driving habits to effectively manage the risks.
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350L 125kpa decreased to 2.00l
Answer:
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