Answer:
25
Step-by-step explanation: im pretty sure sorry if not but it does seem right..
Answer:
it would be a 25% decrease
a quiz includes 5 questions, and each question has 4 possible answers. in how many unique ways can the quiz be completed?
The number of unique ways to complete a quiz with 5 questions and 4 possible answers to each question is \(4^5\), or 1024.
This can be calculated using exponential notation, which states that a number raised to the power of another number is equal to the number multiplied by itself that many times. In this case, 4 to the power of 5 is equal to 4 x 4 x 4 x 4 x 4, or 1024.
In other words, the number of unique ways to answer a quiz with 5 questions and 4 possible answers to each question is equal to 4 multiplied by itself 5 times. This can also be written using the exponential notation as \(4^5\). There are 1024 unique ways to complete a quiz with 5 questions and 4 possible answers to each question.
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A line passes through the points (-6, 8) and ( 3, 7). What is the equation of the line in Slope-Intercept Form?
Step-by-step explanation:
y=−x+2
Explanation:
Alright, so this is a two-part question. First we need to find the slope, then we need to find the y-intercept. Finally we plug all this into the slope intercept equation y=mx+b
The slope is commonly referred to as m=riserun this can also be expressed as m=y2−y1x2−x1 by using the change in y and the change in x.
m=5−8−3−(−6)
m=−33
m=−1
Alright, now lets find the y-intercept by using that slope. If we plug that slope into the base formula we get y=−x+b. Since we already know one point, lets put (−3,5) into that equation and solve for b.
5=−(−3)+b
5−3=3+b−3
2=b
Now is if plug out b into out equation, we get a finally answer of y=−x+2
Even though we're done, lets check it by putting in the other point.
8=−(−6)+2
8−6=6+2−6
2=2
There are four students named A,B,C, and D. All four of them are loss averse over money, with the same value function for money: v(x dollars )={√x x ≥ 0
{-2√-x x < 0
All three of them are also loss averse over mugs, with the same value function for mugs:
v(y mugs)={3y y ≥ 0
{4y y < 0
Total utility is the sum of the gain/loss utility for mugs and the gain/loss utility for money. The reference point is the status quo, that is, a person's initial endowment. Student A owns a mug and is willing to sell it for a price of a dollars or more. Student B does not own a mug and is willing to pay up to b dollars for buying it. Student C does not own a mug and is indifferent between getting a mug and getting c dollars. Student D is indifferent between losing a mug and losing d dollars.
1. Solve for a,b,c, and d.
2. Instead, suppose A, B, C, and D are only loss averse over mugs, but not over money. That is, their value function for money is instead:
v(x dollars)={√x x ≥ 0
{-√-x x < 0
and their value function for mugs remains:
v(y mugs)={3y y ≥ 0
{4y y < 0
Solve for a,b,c, and d.
3. Instead, suppose A,B,C, and D are not loss averse:
v(x dollars)={√x x ≥ 0
{-√-x x < 0
and v(y mugs)=3y
Solve for a,b,c, and d.
4. Suppose A, B, C, and D are not loss averse (as in the previous question), but their value for a mug varies with ownership. Specifically, the value of the mug is 3 for someone who does not currently own the mug, and 4 for someone who currently owns a mug. Solve for a,b,c, and d.
As per the question, All four students A, B, C, and D are loss-averse over money and have the same value function as below:v(x dollars)={√x x ≥ 0 {-2√-x x < 0They are also loss averse over mugs and have the same value function.
v(y mugs)={3y y ≥ 0
{4y y < 0
Now, we have to find the values of a, b, c and d as below:
- Student A owns a mug and is willing to sell it for a price of a dollars or more. i.e v(a) = v(0) + v(a-A), where A is the initial endowment of A. According to the given function, v(0) = 0, v(a-A) = 3, and v(A) = 4.
So, a ≥ A+3/2
- Student B does not own a mug and is willing to pay up to b dollars for buying it. i.e v(B-b) = v(B) - v(0), where B is the initial endowment of B. According to the given function, v(0) = 0, v(B-b) = -4, and v(B) = -3.
So, b ≤ B+1/2
- Student C does not own a mug and is indifferent between getting a mug and getting c dollars. i.e v(c) = v(0) + v(c), where C is the initial endowment of C. According to the given function, v(0) = 0, v(c) = 3.
So, c = C/2
- Student D is indifferent between losing a mug and losing d dollars. i.e v(D-d) = v(D) - v(0), where D is the initial endowment of D. According to the given function, v(0) = 0, v(D-d) = -3.
So, d = D/2
2) In this case, value function for money changes to:v(x dollars)={√x x ≥ 0
{-√-x x < 0
However, the value function for mugs remains the same:v(y mugs)={3y y ≥ 0
{4y y < 0
Therefore, values for a, b, c, and d will remain the same as calculated in part (1).
3) In this case, students are not loss-averse. Value function for money:v(x dollars)={√x x ≥ 0
{-√-x x < 0
Value function for mugs:v(y mugs)={3y y ≥ 0
The reference point is the status quo, i.e initial endowment. So,
- Student A owns a mug and is willing to sell it for a price of a dollars or more. The value of mug for A is 3 initially and he would sell it for 3 or more.
So, a ≥ A+3/2
- Student B does not own a mug and is willing to pay up to b dollars for buying it. The value of mug for B is 3 initially and he would buy it for 3 or less.
So, b ≤ B+3/2
- Student C does not own a mug and is indifferent between getting a mug and getting c dollars. The value of the mug for C is 3 initially.
So, c = 3
- Student D is indifferent between losing a mug and losing d dollars. The value of the mug for D is 3 initially.
So, d = 3
4) In this case, value function for money:v(x dollars)={√x x ≥ 0
{-√-x x < 0
Value function for mugs: Mug will have a value of 4 for someone who owns it and 3 for someone who does not own it.
The reference point is the status quo, i.e initial endowment. So,
- Student A owns a mug and is willing to sell it for a price of a dollars or more. The value of mug for A is 4 initially and he would sell it for 4 or more.
So, a ≥ A+2
- Student B does not own a mug and is willing to pay up to b dollars for buying it. The value of mug for B is 3 initially and he would buy it for 3 or less.
So, b ≤ B+3/2
- Student C does not own a mug and is indifferent between getting a mug and getting c dollars. The value of the mug for C is 3 initially and he would like to buy it for 3.
So, c = 3
- Student D is indifferent between losing a mug and losing d dollars. The value of the mug for D is 3 initially.
So, d = 3.
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0.3 repeating as a fraction
Answer:
3/10 or three-tenths
Step-by-step explanation:
Hope this helps=D
Answer:
O.3 = 1/3
Step-by-step explanation:
divide 1÷3
you will get 0.3 to infinity
If you are purchasing a building for $8,000,000 and the bank lends you $6,400,000 the Loan to Value is $1,600,000 65% 80% 100%
To calculate the Loan to Value (LTV) ratio, we divide the loan amount by the purchase price of the property and express the result as a percentage. LTV = 80%
Given: Purchase price of the building: $8,000,000 Loan amount: $6,400,000 LTV = (Loan amount / Purchase price) * 100 LTV = ($6,400,000 / $8,000,000) * 100 LTV = 0.8 * 100 LTV = 80%
Therefore, the Loan to Value (LTV) ratio in this scenario is 80%. This means that the bank has provided a loan equivalent to 80% of the purchase price of the building.
The remaining 20% of the purchase price, which is $1,600,000 in this case, would be the down payment or equity contribution made by the borrower. Correct answer is 80%
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En un tablero de 1×100 las casillas están numeradas del 1 al 100. Se pintan las casillas con tres colores, de izquierda a derecha, de la siguiente manera: la primera casilla azul, a continuación 2 rojas, luego 3 verdes, luego 4 azules, 5 rojas, y así siguiendo, cada vez se ointa una casilla más. ¿Qué número tiene la última casilla pintada de azul? Explica cómo lo encontraste
The last blue colored square on a 1x100 board with alternating color pattern every increasing number is 97th box.
In an 1x100 board, the boxes are numbered from 1 to 100. The boxes are painted with three colors from left to right in the following way: the first box is blue, then 2 red boxes, then 3 green boxes, then 4 blue boxes, 5 red boxes, and so on, painting one more box each time. What number is the last blue painted box? Explain how you found it.
To solve the problem, we need to find the pattern in the way the boxes are painted. We can notice that the colors repeat after every three boxes, so we need to find the remainder when 100 is divided by 3.
100 ÷ 3 gives a quotient of 33 and a remainder of 1.
This means that after painting 99 boxes, the next box would be the first blue box again. Therefore, the last blue painted box is the 97th box, which is two boxes before the first blue box on the board.
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50 POINTS PLZ HELP!!!!
In two or more complete sentences, compare the number of x-intercepts in the graph of f(x) = x^2 to the number of x-intercepts in the graph of g(x) = x^2 -7. Be sure to include the transformations that occurred between the parent function f(x) and its image g(x).
Answer:
1 intercept and 2 intercepts
Step-by-step explanation:
there is only one x-intercept for the first graph, which is (0,0)
for the second equation there are two: (-sqrt7,0) and (sqrt7, 0)
the transormation that occured from f(x) to its image g(x) is g(x) = -7 + f(x)
Karla is selling tickets for a high school play. Child tickets cost $7 and adult tickets cost $13 she sells 180 tickets and collects $1830 Setup a system of equations using C for number of child tickets and A for number of adult tickets to find the number of each ticket sold
Answer: The number of child tickets is 85 and the number of adult tickets is 95.
Step-by-step explanation:
Let C = Number of child tickets
A = Number of adult tickets.
As per given, we have
C+A=180 (i)
7C+13A=1830 (ii)
Multiply 7 to both sides of equation (ii), we get
7C+7A=1260 (iii)
Eliminate (iii) from (ii) , we get
\(6A=570\\\\\Rightarrow\ A=95\)
Put value of y in (i), we get
C= 85
Hence, the number of child tickets is 85 and the number of adult tickets is 95.
What additional information is required in order to know that the triangles are
congruent by HL?
Answer:
Option D
Step-by-step explanation:
In ΔHBC and ΔACB,
Statements Reasons
1). CB ≅ CB (leg) 1). Reflexive property
2). BA ≅ CH (Hypotenuse) 2). Additional information for the
congruence of two right triangles by HL
property.
3). ΔHBC ≅ ΔACB 3). HL property of congruence
Option D will be the correct option.
Let (Xn)n20 be a Markov chain with state space S = transition probability matrix {1,2,3} and 0.5 0.4 0.1 0.3 0.4 0.3 P = 0.2 0.3 0.5/ Compute the stationary distribution 7r
The stationary distribution of the given Markov chain with a state space of {1, 2, 3} and transition probability matrix P = {{0.5, 0.4, 0.1}, {0.3, 0.4, 0.3}, {0.2, 0.3, 0.5}} can be calculated by finding the eigenvector corresponding to the eigenvalue 1.
To find the stationary distribution of a Markov chain, we need to solve the equation πP = π, where π is the stationary distribution and P is the transition probability matrix. Since the stationary distribution is a probability distribution, the sum of its elements should be equal to 1.
In this case, we have the transition probability matrix P as given. To find the stationary distribution, we need to find the eigenvector corresponding to the eigenvalue 1. This can be done by solving the equation (P - I)π = 0, where I is the identity matrix.
By subtracting the identity matrix from P and solving the system of linear equations, we can find the eigenvector. The resulting eigenvector will represent the stationary distribution.
Performing the calculations, we find that the stationary distribution π is approximately {0.2, 0.4, 0.4} or 20%, 40%, and 40% respectively for states 1, 2, and 3. This means that in the long run, the Markov chain is expected to spend approximately 20% of its time in state 1, 40% in state 2, and 40% in state 3.
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Which comparison is true? Use the number line to help.
Answer:
I NEED A PICTURE!!!
Step-by-step explanation:
so i can answer
Tyler leaves his house to meet a friend at 2:25 p.m. He comes back at 3:10 p.m.
How long was he gone?
Tyler was gone for 45 minutes
Answer: 45 minutes
Step-by-step explanation: First, do 60-25 to find how much time there is till 3. (60-25=35) Then, add 10 because he came back at 3:10, not 3:00.
hope this helps!
please give brainliest!
Angle MON is a straight angle and Ray O P bisects AngleMOQ.
Four lines extend from point O. The space between lines O M and O P is an orange arc. The space between lines P O and P Q has an orange arc. The space between lines O Q and O N is 58 degrees.
What is the measure of AngleMOP?
29°
58°
61°
122°
answer
°
61°
Step-by-step explanation:
The measure of ∠MOP=61°.
What is a straight angel?A straight angle is an angle which measures 180°.
So according to the question,
∠MON is a straight angle.
⇒m∠MON=180°
∠QON=58° (according to the figure)
OP bisects ∠MOQ,
then OP makes ∠MOQ into two equal angles i.e. ∠MOP and ∠POQ:
∠MOP=∠POQ=∠MOQ/2 -----equation-1
As OQ divides ∠MON into two angles ∠MOQ and ∠QON. So,
m∠MOQ+m∠QON=m∠MON
⇒m∠MOQ+58°=180°
⇒m∠MOQ=180°-58°
⇒m∠MOQ=122°
Replacing ∠MOQ by 122° in the equation-1
m∠MOP=m∠POQ=m∠MOQ/2=122°/2
⇒m∠MOP=m<POQ=61°
Therefore the measure of ∠MOP=61°.
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Thomas went for a long hike and burned 675 calories in 2 hours. Marvin decided to go for a bike ride and burned 1,035 calories in 3 hours. Who burned the most calories per hour? Let t represent Thomas's calories burned and m represent Marvin's calories burned. Equivalent Ratio 1: Equivalent Ratio 2: burned the most calories per hour.
Step-by-step explanation:
I am not sure I fully understand what your teacher wants from you, but I would say we only need to define the burning rate per hour for both people, and with that normed rate (number / hour) we can answer the main question directly.
Thomas burned 675 cal/ 2 hours.
by dividing to and bottom by 2 (it is important to do the same action on the top and the bottom to keep the value of the ratio unchanged) we get
337.5 cal / hour
and Marvin burned 1035 cal / 3 hours.
so, the same trick, this time dividing to and bottom by 3 to norm the whole ratio to a 1 hour baseline :
345 cal / hour
so, Marvin burned more calories per hour.
Find the selling price of each item. Show work for full credit.
Original Price of a truck: $47,500
Discount: 45%
Answer:26,125 is your answer
Step-by-step explanation:
Answer:
$26,125
Step-by-step explanation:
45% of 47,500 is 21,375
47,500 - 21,375 = 26,125
The continuous random variable X has a probability density function (pdf) given by f(x) Şi- & for 0 < x < 2 lo otherwise Part(a) Find the median of X, correct to 2 decimal places. 0.59 Part(b) Find P(X >>). Give your answer as a decimal, correct to 2 decimal places. 0.56 Part(c) Two independent observations of X are taken. Find the probability correct to 2 decimal places that one is less than and the other is greater than 2. The order in which we take observations matters. 0.25 Part(d) Find Var(X), correct to 2 decimal places. 0.22 Part(e) Find E(X), correct to 2 decimal places. 0.75 Part(f) Find the value of q such that P(X
The median of X is 1; P(X > 2) = 0; P(one observation < 2 and the other > 2) = P(X < 2) * P(X > 2) = 0 * 0 = 0; Var(X) is approximately 0.33; E(X) is 1 and the value of q such that P(X < q) = 0.95 is 1.9.
(a) To find the median of X, we need to find the value of x for which the cumulative distribution function (CDF) equals 0.5.
Since the PDF is given as f(x) = 1/2 for 0 < x < 2 and 0 otherwise, the CDF is the integral of the PDF from 0 to x.
For 0 < x < 2, the CDF is:
F(x) = ∫(0 to x) f(t) dt = ∫(0 to x) 1/2 dt = (1/2) * (t) | (0 to x) = (1/2) * x
Setting (1/2) * x = 0.5 and solving for x:
(1/2) * x = 0.5; x = 1
Therefore, the median of X is 1.
(b) To find P(X > x), we need to calculate the integral of the PDF from x to infinity.
For x > 2, the PDF is 0, so P(X > x) = 0.
Therefore, P(X > 2) = 0.
(c) To find the probability that one observation is less than 2 and the other is greater than 2, we need to consider the possibilities of the first observation being less than 2 and the second observation being greater than 2, and vice versa.
P(one observation < 2 and the other > 2) = P(X < 2 and X > 2)
Since X follows a continuous uniform distribution from 0 to 2, the probability of X being exactly 2 is 0.
Therefore, P(one observation < 2 and the other > 2) = P(X < 2) * P(X > 2) = 0 * 0 = 0.
(d) The variance of X can be calculated using the formula:
Var(X) = E(X²) - [E(X)]²
To find E(X²), we need to calculate the integral of x² * f(x) from 0 to 2:
E(X²) = ∫(0 to 2) x² * (1/2) dx = (1/2) * (x³/3) | (0 to 2) = (1/2) * (8/3) = 4/3
To find E(X), we need to calculate the integral of x * f(x) from 0 to 2:
E(X) = ∫(0 to 2) x * (1/2) dx = (1/2) * (x²/2) | (0 to 2) = (1/2) * 2 = 1
Now we can calculate the variance:
Var(X) = E(X²) - [E(X)]² = 4/3 - (1)² = 4/3 - 1 = 1/3 ≈ 0.33
Therefore, Var(X) is approximately 0.33.
(e) The expected value of X, E(X), is given by:
E(X) = ∫(0 to 2) x * f(x) dx = ∫(0 to 2) x * (1/2) dx = (1/2) * (x²/2) | (0 to 2) = (1/2) * 2 = 1
Therefore, E(X) is 1.
(f) The value of q such that P(X < q) = 0.95 can be found by solving the following equation:
∫(0 to q) f(x) dx = 0.95
Since the PDF is constant at 1/2 for 0 < x < 2, we have:
(1/2) * (x) | (0 to q) = 0.95
(1/2) * q = 0.95
q = 0.95 * 2 = 1.9
Therefore, the value of q such that P(X < q) = 0.95 is 1.9.
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Study the information provided below and answer the questions that follow. Chief executive officers (CEOs) have long been a focus of organisational research. This emphasis is understandable, given the widespread belief that a firm's top executive has a substantial impact on its performance. Three years ago, the board of directors (BOD) of TMG Ltd and the then incumbent CEO mutually agreed to part ways due to poor financial performance of the business. The new CEO appointed to replace him was mandated by the BOD to initiate an intervention strategy to turn around the business. As part of a review of the financial performance of the business, a researcher has recently been contracted by the BOD of TMG Ltd to determine whether the intervention strategy introduced three years ago by the current CEO has produced significantly improved outcomes for the business. The BOD wants the quarterly operating profit margin of the business for the past six year to constitute the unit of analysis. Table 4.1, below, shows the quarterly operating profit margin retrieved from the database of the company. Table 4.1: Quarterly operating profit margin (%) of TMG Ltd over the past six years.
The quarterly operating profit margin of TMG Ltd over the past six years is provided in Table 4.1, indicating the financial performance of the business during that period.
In order to assess the impact of the intervention strategy introduced by the current CEO three years ago, the board of directors (BOD) of TMG Ltd has contracted a researcher to analyze the data and determine if there have been significant improvements in the business outcomes. The quarterly operating profit margin serves as the unit of analysis for this evaluation.
Table 4.1 allows the researcher to examine the trend and fluctuations in the quarterly operating profit margin over the six-year period. By analyzing the data, the researcher can identify any noticeable changes in the financial performance of TMG Ltd, particularly after the implementation of the intervention strategy. The BOD is interested in understanding whether the strategy has resulted in improved profitability and overall financial health of the company.
The researcher will likely perform statistical analysis, such as calculating averages, trends, and identifying any significant variations, to draw conclusions about the effectiveness of the intervention strategy. By comparing the quarterly operating profit margin before and after the strategy's implementation, the researcher can assess whether the new CEO's efforts have had a positive impact on the company's financial performance.
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What is the value of x? Round your answer to the nearest Whole number
X
A 10
C 17
B 1
D 13
Answer:
B
Step-by-step explanation:
Using Pythagoras' identity in the right triangle
x² + 9² = 15²
x² + 81 = 225 ( subtract 81 from both sides )
x² = 144 ( take the square root of both sides )
x = \(\sqrt{144}\) = 12 → B
How do numbers help us predict the ebbs and flows in our lives? Think about things like circadian rhythms.
Numbers play a crucial role in helping us predict the ebbs and flows in our lives. They are used to measure and quantify patterns and cycles that occur in our daily lives, such as circadian rhythms.
Circadian rhythms are the physical, mental, and behavioral changes that follow a 24-hour cycle, responding primarily to light and darkness in an organism's environment. Numbers help us measure and track these rhythms, allowing us to predict when we will feel awake or sleepy, hungry or full, and so on.
For example, we know that the average human circadian rhythm is 24.2 hours, and that our bodies produce the hormone melatonin at night to help us sleep. By measuring and tracking these numbers, we can predict when we will feel tired and need to sleep, and when we will feel awake and alert.
Numbers also help us predict other patterns in our lives, such as our menstrual cycles, the best times to exercise, and when we are most likely to get sick. By tracking and measuring these numbers, we can better understand and predict the ebbs and flows in our lives and make more informed decisions about our health and well-being.
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consider the figure shown on the graph.Which equation represents the line of reflection that maps ABC onto EDF?
Let's begin by listing out the information given:
A (-1, 0); B (-3, 0); C (-1, 3)
E (2, -3); D (2, -5); F (5, -3)
A = E; B = D; C = F
A (-1, 0) = E (2, -3) = (2--1, -3-0) = (3, -3)
B (-3, 0) = D (2, -5) = (2--3, -5-0) = (5, -5)
C (-1, 3) = F (5, -3) = (5--1, -3-3) = (6, -6)
We observe that x = -y or y = -x
\(y=-x\)Decide which of the two points lies on the graph of the line
2x+y=10
A.(4,3)
B.(-4,18)
Answer:
A
Step-by-step explanation:
when you substitute 4 in x and 3 in y, your result are 11 no 10
A recent study of cardiovascular risk factors reported that 30% of adults met criteria for hypertension. If 15 adults are assessed what is the probability that:A. Exactly 5 meet thecriteria for hypertenstion ?B. None meet the criteria for hypertension?C. Less than or equal to 7 meet the criteria for hypertension?
A. The probability that exactly 5 adults meet the criteria for hypertension is approximately 0.0916 or 9.16%.
B. The probability that none of the adults meet the criteria for hypertension is approximately 0.0255 or 2.55%.
C. The probability that less than or equal to 7 adults meet the criteria for hypertension is approximately 0.9999 or 99.99%.
To calculate the probabilities,
Use the binomial probability formula.
The binomial probability formula is,
P(X = k) = C (n ,k) × \(p^k\) × \((1 - p)^{(n - k)\)
Where,
P(X = k) is the probability of exactly k successes
n is the number of trials
k is the number of successes
p is the probability of success in a single trial
(1 - p) is the probability of failure in a single trial
C(n, k) represents the binomial coefficient,
which can be calculated as n! / (k! × (n - k)!)
A. To calculate the probability that exactly 5 adults meet the criteria for hypertension,
n = 15 (number of adults assessed)
k = 5 (number of adults meeting the criteria)
p = 0.30 (probability of meeting the criteria)
A. Probability that exactly 5 adults meet the criteria for hypertension,
n = 15
k = 5
p = 0.30
P(X = 5) = C( 15, 5) × 0.30⁵ × (1 - 0.30)¹⁵⁻⁵
Using the binomial coefficient formula C (n ,k) = n! / (k! × (n - k)!), we have,
(¹⁵C₅) = 15! / (5! × (15 - 5)!) = 3003
P(X = 5) = 3003 × 0.30⁵ × 0.70¹⁰
Calculating the probability,
P(X = 5) = 0.0916 (approximately)
B. Probability that none of the adults meet the criteria for hypertension,
n = 15
k = 0
p = 0.30
P(X = 0) = (¹⁵C₀) × 0.30⁰× (1 - 0.30)¹⁵⁻⁰
(¹⁵C₀) = 1 (since choosing 0 from any set results in 1)
P(X = 0) = 1 × 0.30⁰ × 0.70¹⁵
Calculating the probability,
P(X = 0) = 0.0255 (approximately)
C. Probability that less than or equal to 7 adults meet the criteria for hypertension,
n = 15
k = 0, 1, 2, 3, 4, 5, 6, 7
p = 0.30
P(X ≤7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7)
Calculate each individual probability using the binomial probability formula and sum them up.
P(X ≤7) = (¹⁵C₀) × 0.30⁰ × 0.70¹⁵ + ¹⁵C₁× 0.30¹× 0.70¹⁴+ (¹⁵C₂) × 0.30²× 0.70¹³ + (¹⁵C₃) × 0.30³ × 0.70¹² + (¹⁵C₄) ×0.30⁴ × 0.70¹¹ + (¹⁵C₅) × 0.30⁵× 0.70¹⁰ + (¹⁵C₆) × 0.30⁶× 0.70⁹ + (¹⁵C₇) × 0.30⁷ ×0.70⁸
Calculating the probability,
P(X ≤ 7) ≈ 0.9999
Therefore, the probabilities for different conditions are,
A. For exactly 5 adults is 0.0916 or 9.16%.
B. For none of the adults is 0.0255 or 2.55%.
C. less than or equal to 7 adults is 0.9999 or 99.99%.
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what is the product of -8x^7 and -2xy^3
Answer:
16x^8y^3
Step-by-step explanation:
Simplify the expression.
Answer:
\(-8x^7(-2xy^3) = 16x^8y^3\)
Step-by-step explanation:
⭐Multiplication rules
negative * negative = positivenegative * positive = negativepositive * positive = positive⭐ Exponent multiplication rule
\(a^n * a^m = a^{n+m}\)⭐ Multiplying two terms with variables
multiply the coefficients (the numbers next to the variables) and the variablesWe need to utilize these 3 key points (⭐) when multiplying to terms with variables.
First, let's multiply the coefficients:
-8 * -2 = 16
negative * negative = positiveNext, let's multiply the variables:
\(x^7 * xy^3\)
These two variables have the same base (x), so we will add their exponents up.
* remember: if you see a variable without an exponent, it has an exponent of 1 *
\(x^7 * x = x^8\)
\(a^n * a^m = a^{n+m}\)The variable \(y^3\) will stay the same because there is no other y variable.
= \(x^8y^3\)
Now, "attach" the variables to the product of the coefficients:
= \(16x^8y^3\)
In degrees, what is the measure of
Answer:
m<PFR=62
m<RFT=28
m<MFE=28
m<EFT=152
HOPE THIS HELPS
-Todo <3
Step-by-step explanation:
90=x+6+3x-4
90=4x+2
-2 -2
88=4x
/4 /4
x=22
3(22)-4=66-4=62
22+6=28
180-28=152
Help me solve this please
Step-by-step explanation:
let's use the law of sine :
a/sin(A) = b/sin(B) = c/sin(C)
so,
5.4/sin(K/2) = 12.3/sin(M1)
8.2/sin(K/2) = x/sin(M2)
M1 + M2 = 180 (as complementary angles or linear pair)
M2 = 180 - M1
sin(K/2) = 5.4×sin(M1)/12.3
sin(K/2) = 8.2×sin(M2)/x
therefore
5.4×sin(M1)/12.3 = 8.2×sin(180 - M1)/x
since sin(a) = sin(180 - a)
5.4×sin(M1)/12.3 = 8.2×sin(M1)/x
and then
5.4/12.3 = 8.2/x
x×5.4 = 8.2×12.3
x = 8.2×12.3/5.4 = 18.67777777... ≈ 18.7
Step-by-step explanation:Step-by-step explanation:
let's use the law of sine :
a/sin(A) = b/sin(B) = c/sin(C)
so,
5.4/sin(K/2) = 12.3/sin(M1)
8.2/sin(K/2) = x/sin(M2)
M1 + M2 = 180 (as complementary angles or linear pair)
M2 = 180 - M1
can someone help me with this : 4g = 8
Answer:
4g = 8
You would just have to divide 4 on both sides. The 4's would cancel out and now your left with 8÷4 = 2
Your answer would be
g = 2
Does anyone know the answer ?
Answer:
Using Piragorean Theorem:
\(x=\sqrt{7^2+10^2}=\sqrt{100+49}=\sqrt{149}\)
Answer:
\(\sqrt{149\)
Step-by-step explanation:
7² + 10² = 12.21²
49 + 100 = 149
Lester and Ralph work at an athletic shoe store in the mall, but whenever they goof off too much, their boss punishes them by making them lace-up all the inventory. I f it takes Lester 30 seconds to lace up a high top and Ralph 35 seconds to do the same, how many seconds will it take them to lace-up 260 high tops?
Answer:
4200
Step-by-step explanation:
Time taken by Lester 30 seconds
Time taken by Ralph = 35 seconds
Their rate :
Lester = 1/time taken = 1/30
Ralph = 1/ time taken = 1/35
Combined rate:
1/30 + 1/35 = (35 + 30) / 1050 = 65 / 1050 = 0.0619047 per boot
Time taken = number of boots / combined rate per boot
Time taken = 260 / 0.0619047
Time taken = 4200 seconds
Give the value of M and C.
Answer:
y = 5x - 3, so M = 5 and C = -3.
the following table shows the results of a screening test hypothesized to detect persons at risk for side effects of a new cosmetic surgery
side effects pos side effects absent total
Screen Positive 12 6 18
screen negative 85 204 289
total 97 210 307
a. compute the sensitivity of the test
b. compute the specificity of the test
c. compute the false postive fraction
d. compute the false negatie fraction
Hence, the answers are:a. Sensitivity of the test is 12.37%.b. Specificity of the test is 97.18%.c. False-positive fraction of the test is 2.86%.d. False-negative fraction of the test is 87.63%.
Sensitivity of a screening testSensitivity of the screening test is the probability of obtaining a positive screening test result among people with the disease. It is calculated as follows:Sensitivity = True positive / (True positive + False negative)From the given table,True positive = 12False negative = 85Total number of people with the disease = True positive + False negative = 12 + 85 = 97Sensitivity = 12 / (12 + 85) = 0.1237 = 12.37%Therefore, the sensitivity of the test is 12.37%.Specificity of a screening testSpecificity of the screening test is the probability of obtaining a negative screening test result among people who do not have the disease. It is calculated as follows:Specificity = True negative / (True negative + False positive)From the given table,True negative = 204False positive = 6Total number of people without the disease = True negative + False positive = 204 + 6 = 210Specificity = 204 / (204 + 6) = 0.9718 = 97.18%Therefore, the specificity of the test is 97.18%.False-positive fractionFalse-positive fraction is the proportion of healthy people who get a positive result out of the total number of healthy people. It is calculated as follows:False-positive fraction = False positive / (False positive + True negative)From the given table,False positive = 6True negative = 204False-positive fraction = 6 / (6 + 204) = 0.0286 = 2.86%Therefore, the false-positive fraction of the test is 2.86%.False-negative fractionFalse-negative fraction is the proportion of sick people who get a negative result out of the total number of sick people. It is calculated as follows:False-negative fraction = False negative / (False negative + True positive)From the given table,False negative = 85True positive = 12False-negative fraction = 85 / (85 + 12) = 0.8763 = 87.63%Therefore, the false-negative fraction of the test is 87.63%.Hence, the answers are:a. Sensitivity of the test is 12.37%.b. Specificity of the test is 97.18%.c. False-positive fraction of the test is 2.86%.d. False-negative fraction of the test is 87.63%.
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