If 55% of a number is 110 and 40% of the same number is 80, find 95% of that number.

Given data:

The given figure is shown.

The expression for sin(θ) is,

Thus, the line of sight distance from the television to the base of a stadium​ is 1,653.426 m.

Answer: 4)90˚

Step-by-step explanation:

(90˚ is more towards the middle

A regular octagon is a shape with 8 congruent sides.

The minimum angle of rotation is 45 degrees

The number of sides of a regular octagon is:

\(\mathbf{n = 8}\)

The total angle at the center of the regular octagon is:

\(\mathbf{\theta = 360}\)

So, the minimum angle of rotation is calculated as follows:

\(\mathbf{\alpha = \frac{\theta}{n}}\)

This gives

\(\mathbf{\alpha = \frac{360}{8}}\)

\(\mathbf{\alpha = 45}\)

Hence, the minimum angle of rotation is 45 degrees

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Answer: f ( x ) = x + 4

x = 3 p

f ( 3 p ) = 3 p + 4

Answer. D )

The ordered pair is:

( x, y ) =  ( 3 p, 3 p + 4 )

PLEASEEEE!!! GIVE ME A BRAINLY!!!!

The job with the longest process time is scheduled first, followed by the next longest, and so on.

Using the LPT (Longest Processing Time) priority, the sequence for jobs a, b, c, and d with process times 4, 6, 5, and 2 respectively would be:

1. Job b (6 units)
2. Job c (5 units)
3. Job a (4 units)
4. Job d (2 units)

The LPT priority rule arranges the jobs in decreasing order of their process times. So, the job with the longest process time is scheduled first, followed by the next longest, and so on.

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The term for the value that occurs most often in a series of numbers is called the mode.

The mode is one of the three main measures of central tendency, along with the mean and the median. It is a useful descriptive statistic that can provide insights into the characteristics of a dataset.

To find the mode of a set of data, you first need to arrange the data in order, either in increasing or decreasing order. Then, you simply identify the most frequent data point, which is the mode. In some cases, there may be more than one mode if multiple data points occur with the same maximum frequency.

The mode is particularly useful when dealing with categorical or nominal data, where there are distinct categories or values that cannot be ordered in a meaningful way. For example, the mode can help identify the most popular color among a group of people or the most common type of car on a given street. It can also be used for continuous data, although it may be less useful in this case than the mean or median.

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To determine the number of tons of metal per year needed for Machine A to be favored over Machine B, we compare their costs. Machine A costs $323,000 with an annual operating cost of $2.40/ton, while Machine B costs $178,000 with an annual operating cost of $8.00/ton. The machines have useful lives of 10 years and 6 years, respectively, and the minimum attractive rate of return (MARR) is 18% per year.

By calculating the equivalent annual costs (EAC) for each machine using the given formula and comparing them, we can determine the point at which Machine A becomes more favorable. However, specific values for the discounting factors and the tons per year needed are missing, making it impossible to provide an exact answer.

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Answer:

a) Para \(i = 4\), hay 13 flores en la fila 4.

b) Para \(i = 7\), hay 22 flores en la fila 7.

c) La fila 11 tiene 34 flores.

Step-by-step explanation:

De acuerdo con el enunciado, cada fila tiene tres flores más que la fila inmediatamente anterior, significando que se puede determinar el número de flores de cada fila mediante una serie aritmética:

\(n = 4+3\cdot (i-1)\), \(i \ge 1\) (1)

Donde:

\(i\) - Índice de la fila de flores.

\(n\) - Número de flores del índice de la fila de flores.

a) Para \(i = 4\), hay 13 flores en la fila 4.

b) Para \(i = 7\), hay 22 flores en la fila 7.

c) Si \(n = 34\), entonces el índice de la fila es:

\(i=1+\frac{n-4}{3}\)

\(i = 11\)

La fila 11 tiene 34 flores.

There are 155 ways to select three vehicles so that at least one truck is chosen.

To solve the problem given above, we first need to calculate the total number of ways of choosing three vehicles without any restrictions. We can do this by using the combination formula.

The number of combinations of n objects taken r at a time is given by:

nCr = n! / r! (n - r)!

where n! is the factorial of n (i.e. the product of all positive integers up to n), r! is the factorial of r, and (n - r)! is the factorial of n - r.

Using this formula, we can calculate the total number of ways of choosing three vehicles as follows:

nCr = 11! / 3! 8! = 11 × 10 × 9 / 3 × 2 × 1 = 165

Now, we need to calculate the number of ways of choosing three vehicles so that no truck is chosen. Since there are 5 cars, we can choose 3 cars in 5C3 = 10 ways.

Therefore, the number of ways of choosing three vehicles so that at least one truck is chosen is given by the difference between the total number of ways of choosing three vehicles and the number of ways of choosing three vehicles so that no truck is chosen.

Thus, the number of ways of choosing three vehicles so that at least one truck is chosen is:

165 - 10 = 155

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Answer:

x = 7

y = 2

Step-by-step explanation:

In the above question, we are given 2 equations which are simultaneous. To solve this equation, we have to find the values of x and y

x + 3y = 13 ........ Equation 1

x - y = 5...........Equation 2

From Equation 2,

x = 5 + y

Substitute 5 + y for x in Equation 1

x + 3y = 13 ........ Equation 1

5 + y + 3y = 13

5 + 4y = 13

4y = 13 - 5

4y = 8

y = 8/4

y = 2

Since y = 2, substitute , 2 for y in Equation 2

x - y = 5...........Equation 2

x - 2 = 5

x = 5 + 2

x = 7

Therefore, x = 7 and y = 2

Answer:

The unit rate is 2700 ÷ 3 = 900 2700 \div 3 = 900 2700÷3=900 kilometers per hour.

Step-by-step explanation:

Answer:

The answer is 60:4

Answer:

One real root (multiplicity 2).

Step-by-step explanation:

-3=x^2+4x+1

x^2 + 4x + 4 = 0

Discriminant = 4^2 - 4*1*4 = 0

There is one real root (multiplicity 2).

The equation has 1 real solution.

The quadratic function is given as:

\(-3=x^2+4x+1\)

Add 3 to both sides of the equation

\(3-3=x^2+4x+1 + 3\)

This gives

\(0=x^2+4x+4\)

Rewrite the equation as:

\(x^2+4x+4 = 0\)

A quadratic equation is represented as:

\(ax^2+bx+c = 0\)

By comparison, we have:

\(a =1\)

\(b =4\)

\(c = 4\)

The discriminant (d) is calculated as:

\(d =b^2 - 4ac\)

So, we have:

\(d =4^2 - 4 \times 1 \times 4\)

\(d =16 - 16\)

Evaluate like terms

\(d = 0\)

Given that the discriminant value is 0, it means that the equation has 1 real solution.

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Answer:

-6

Step-by-step explanation:

Hello!

Since we are finding f(-1) we put -1 in for x

2(-1)^2 + 8(-1)

Follow PEMDAS

2 * 1 + 8(-1)

2 * 1 + -8

2 + -8 = -6

The answer is -6

Hope this helps!

The probability that exactly of them say job applicants should follow up within two weeks is 0.2291

Probability refers to potential. A random event's occurrence is the subject of this area of mathematics. The range of the value is 0 to 1. Mathematics has incorporated probability to forecast the likelihood of various events.

The binary probability distribution can be used to model the given issue.

Assume that X is a binomial random variable with the values n and p, where n is the total number of human resource managers that were randomly chosen and p is the likelihood that the chosen manager will advise job seekers to follow up within two weeks.

total human resource managers were chosen at random, n = 9

The likelihood that the chosen human resources manager will advise job seekers to follow up within two weeks = 57 (0.57)

As we are aware, the probability of "m" successes for a binomial distribution is calculated as -

\(P(X=m) = ^{n}C_{m} (p)^{m}(1-p)^{n-m} = \frac{n!}{m! (n-m)!}(p)^{m}(1-p)^{n-m}\)

Using the aforementioned data, we can now calculate the likelihood that exactly 6 of the 9 applications who were chosen will advise job seekers to follow up within two weeks as follows:

n = 9

p = 0.57

m = 6

\(P(X=m) = \frac{n!}{m! (n-m)!}(p)^{m}(1-p)^{n-m}\)

\(P(X=6) = \frac{9!}{6! (9-6)!}(0.57)^{6}(1-0.57)^{9-6}\)

\(= \frac{9!}{6! 3!} (0.57)^{6} (0.43)^{3}\)  = 0.2291 (rounded to 4 decimal places)

Therefore, the probability that exactly of them say job applicants should follow up within two weeks is 0.2291

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The root of the equation sinx = 2x-3 is 0.8401 (approx).

Given equation is sinx = 2x-3

We need to solve this equation using false position method.

False position method is also known as the regula falsi method.

It is an iterative method used to solve nonlinear equations.

The method is based on the intermediate value theorem.

False position method is a modified version of the bisection method.

The following steps are followed to solve the given equation using the false position method:

1. We will take the end points of the interval a and b in such a way that f(a) and f(b) have opposite signs.

Here, f(x) = sinx - 2x + 3.

2. Calculate the value of c using the following formula: c = [(a*f(b)) - (b*f(a))] / (f(b) - f(a))

3. Evaluate the function at point c and find the sign of f(c).

4. If f(c) is positive, then the root lies between a and c. So, we replace b with c. If f(c) is negative, then the root lies between c and b. So, we replace a with c.

5. Repeat the steps 2 to 4 until we obtain the required accuracy.

Let's solve the given equation using the false position method.

We will take a = 0 and b = 1 because f(0) = 3 and f(1) = -0.1585 have opposite signs.

So, the root lies between 0 and 1.

The calculation is shown in the attached image below.

Therefore, the root of the equation sinx = 2x-3 is 0.8401 (approx).

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The odd function y = x³, with a line of symmetry at x = 0, is drawn by the image given at the end of the answer.

The function for this problem is given as follows:

f(x) = x³.

The justification for the function being odd is given as follows:

f(-x) = (-x)³ = -x³ = -f(x).

(negative base to odd exponent, hence the result is negative).

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The area of the figure is similar to the area of a triangle with a base of 6 in and a height of 9 in.

Option C is the correct answer.

We have,

The figure has one square and one rectangle.

So,

Area of a rectangle.

= length x width

Now,

Top square.

= length x width

= 3 x 3

= 9 in²

Bottom rectangle.

= length x width

= 9 x 2

= 18 in²

Now,

The area of the figure.
= 9 + 18

= 27 in²

Now,

The area of a triangle with base 6 in and height 9 in

Area = 1/2 x 6 x 9 = 3 x 9 = 27 in²

Thus,

The area of the figure is similar to the area of a triangle with a base of 6 in and a height of 9 in.

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Answer:

I am not sure but i will say C.

Step-by-step explanation:

Answer: 4

Step-by-step explanation:

First you do the exponent because of "order of operation", which in this case is 2 to the 2nd power or 2 squared. Then you substract the answer you got by doing 2 squared, which is supposed to give you an answer of 4 which then gets substracted by 2, which leads to the answer being 2 and then you add 2 + 2 and the final answer is 4

The limit of ln(x)/x as x approaches 0 is 0. To find the limit of ln(x)/x as x approaches 0, we can apply L'Hospital's rule.

Let's differentiate the numerator and denominator separately:

d/dx(ln(x)) = 1/x,

d/dx(x) = 1.

Now, we can evaluate the limit of the derivative of the numerator divided by the derivative of the denominator:

lim x→0 (1/x) / 1 = lim x→0 1/x = ∞.

Since the limit is indeterminate, we can apply L'Hospital's rule again. Differentiating both the numerator and denominator gives:

d/dx(1/x) = -1/x²,

d/dx(1) = 0.

Evaluating the new limit, we get: lim x→0 (-1/x²) / 0 = lim x→0 (-1/x²) = -∞.

Again, the limit is indeterminate, so we apply L'Hospital's rule once more. Differentiating both the numerator and denominator gives:

d/dx(-1/x²) = 2/x³,

d/dx(0) = 0.

Taking the limit again, we have: lim x→0 (2/x³) / 0 = lim x→0 (2/x³) = ∞. We see that applying L'Hospital's rule leads to an indeterminate form. However, by using a more elementary method, we can find the limit:

As x approaches 0, ln(x) approaches negative infinity, and x approaches 0. Therefore, ln(x)/x approaches 0. The limit of ln(x)/x as x approaches 0 is 0, which we obtained by a more elementary method, without using L'Hospital's rule.

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Yes , SAS (Side-Angle-Side) is a second Congruence postulate to prove triangle congruence by showing that two sides and their included angles are congruent.

Side-Angle-Side is the rule used to prove whether a given set of triangles are congruent. The SAS rule states: Triangles are congruent if two sides and an included angle of a triangle are equal to two sides and an included angle of another triangle. An included angle is the angle formed by two given sides.. For example : let's us consider two triangles ∆SQR and ∆TSR ,

In above given figure, sides

RS = RS ( common side)

QS = ST ( S divides QT in two equal parts) and angle between QS and SR equal to angle between SR and ST i.e. ∠QSR = ∠RST = 90° (right angle ) and it is included angle . So, by SAS Congruence rule, both of triangles are congruent. Hence, Δ ABC ≅ Δ PQR.

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The number of packs that should be bought should be considered as the 5.

Since

28 batteries for smoke alarm. Store sells them in 6 packs

So here we simply divide it

\(= 28 \div 6\)

= 5

hence, The number of packs that should be bought should be considered as the 5.

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Answer:

( √15 + 8)/7

Step-by-step explanation:

TanA = -√15

.we are to find tan(A-π/4).

In trigonometry

Tan(A-B) = TanA - TanB/1+ tanAtanB

Hence:

tan(A-π/4) = TanA - Tanπ/4/1+ tanAtanπ/4

Substitute tan A value into the formula

tan(A-π/4) = -√15-tanπ/4 / 1+(-√15)(tanπ/4

tan(A-π/4) = -√15-1/1-√15

Rationalize

-√15-1/1-√15 × 1+√15/1+√15

= -√15-√225-1-√15/(1-√225)

= -2√15-15-1/1-15

= -2√15 -16/(-14)

= -2(√15+8)/-14

= √15 + 8/7

Hence the required value is ( √15 + 8)/7

Answer:

Probably D ( -√15-1/1-√15)

Step-by-step explanation:

it was in adidemiokin's answer before they rationalized it. Couldn't find the darn answer anywhere else.  I'm on my 3rd attempt on the EDGE precalc Unit test hopefully D is right.

Answer:

Step-by-step explanation:

See attachment

m = (y2-y1)/(x2-x1)

m = (1-0)/(-3-5)

m = 1/-8

Answer:

2:20 pm to 5:57 pm is 3 hours and 37 minutes.

Answer:

3 hours and 37 minutes.

Step-by-step explanation:

5:57

-2:20

= 3:37

It is constant because otherwise it wouldn't be proportional

The difference between an interval scale and a ratio scale is: an interval scale has equal intervals; a ratio scale has an absolute zero point; an interval scale does not. The correct option is: C.

An interval scale has an absolute zero point; a ratio scale does not. An interval scale is a type of scale where the distance between two points is equal. It is useful for representing numbers and performing arithmetic operations on them.

The interval scale measures the interval or the difference between the measurements of the attribute. A ratio scale, on the other hand, has an absolute zero point. The zero point is significant since it represents the absence of a particular characteristic.

A ratio scale has a similar measurement scale to an interval scale, but it has an absolute zero point. The ratio scale may perform mathematical calculations such as addition, subtraction, multiplication, and division with ease. The measurements can be multiplied or divided by a constant value, and the resulting ratios are meaningful.

The correct option is: C. an interval scale has an absolute zero point; a ratio scale does not.

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