If 36% of a number is 325, what is 15% of the number?

Equation

The answer would be R = -3 and R = 3

The probability that either event will occur is P ( C ) = 0.89

Given data ,

Let the probability that either event will occur  be P ( C )

P ( A ) = 20/36

P ( B ) = 12/36

where P ( A or B ) = P ( C )

P ( C ) = P ( A ) + P ( B )

P ( C ) = 32/36

P ( C ) = 0.88888

Hence , the probability is P ( C ) = 0.89

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Step-by-step explanation:

hi, this looks complicated, however, let's deal with it.

using sine rule,

we have,

a/sin A= c/sin C

4.83/sin 46= 5.5/sin C

cross multiply

4.83sin C=5.5sin 46

sin C= (5.5sin46)/4.83

sin C= 0.8191

C=sin inverse of 0.8191

C=54.99 approximately 55

since we have C, we can now find B to get b or rather AC

A+B+C=180. (sum of angles in a triangle)

46°+ B + 54.99°=180°

B+ 100.99°=180°

B°=180°-100.99°

B=79°

since we have B, we can find b or rather AC

using cosine rule,

b²=c²+a²-2 x c x a x cos B

b²= 5.5² + 4.83² - 2 x 5.5 x 4.83 x cos 79°

b²=30.25+23.33-53.13cos79

b²=53.58-10.14

b²=43.44

b=6.59 approximately 6.6

Answer:

\(b.\ cos 70 =\dfrac{4}x\) is the correct answer.

Step-by-step explanation:

First of all, let us label the diagram as shown in the attached figure.

OR = 20'

QS = 16'

\(\triangle OPQ\) is the right angled triangle that we get.

\(\angle P=90^\circ\)

\(\angle O =70^\circ\)

From the given figure symmetry, we can clearly see that:

Side OP = OR - QS

OP = 20 - 16 = 4'

Now, let us use trigonometric identity of cosine in \(\triangle OPQ\).

\(cos\theta = \dfrac{Base}{Hypotenuse}\)

\(cosO= \dfrac{OP}{OQ}\\\Rightarrow cos70^\circ= \dfrac{4}{OQ}\)

Let the distance of ramp, OQ = x'

So, the above ratio becomes:

\(cos70^\circ= \dfrac{4}{x}\)

So, the correct answer is:

\(b.\ cos 70 =\dfrac{4}x\)

Let's begin by listing out the information given to us:

To calculate the inverse for this function, we interchange the variables x & y:

The top angle is right (90 degrees, kinda looks like a bent elbow).

The 2nd is acute (smaller than 90, kind of 'cute' bc it's small).

The 3rd is obtuse (greater than 90, I have nothing corny to say, sorry).

4th is acute.

5th is straight because it's a straight line.

6th is also obtuse.

Have a good day :)

A mathematics topic that van be looked into is how linear algebra, graph theory and optimization can be used on the airline industry.

In this case, to solve the scheduling issues faced by airlines such as planning flights, assigning planes and crews to routes - mathematical techniques can be employed.

By leveraging Linear Algebra, operators can simulate the flow of aircrafts and passengers while Graph Theory can help model flight schedules and aircraft routes.

Simultaneously using Optimization techniques in the problem-solving process can work to streamline various operations resulting in reduced costs and improved efficiency which can increase profit margins.

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The given passage provides a proof that the Separation Axioms follow from the Replacement Schema.

The proof involves introducing a set F and showing that {a: e X : O(x)} is equal to F (X) for every X. Therefore, the conclusion is that the Separation Axioms can be derived from the Replacement Schema.In the given passage, the author presents a proof that demonstrates a relationship between the Separation Axioms and the Replacement Schema.

The proof involves the introduction of a set F and establishes that the set {a: e X : O(x)} is equivalent to F (X) for any given set X. This implies that the conditions of the Separation Axioms can be satisfied by applying the Replacement Schema. Essentially, the author is showing that the Replacement Schema can be used to derive or prove the Separation Axioms. By providing this proof, the passage establishes a connection between these two concepts in set theory.

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Answer: Here you go! Any questions?

Step-by-step explanation:

Sorry if this is not right...I tried forgive me

\($$16[(x_2 - x_1)^2 + (y_2 - y_1)^2]x^2 - 32(x_2 - x_1)x^3 + 16(x_2 - x_1)[(y_2 - y_1)^2 + (x_2 - x_1)^2 - 180^2]x + 16[(y_2 - y_1)^2 + (x_2 - x_1)^2]y^2 - 32(y_2 - y_1)y^3 + 16(y_2 - y_1)[(y_2 - y_1)^2 + (x_2 - x_1)^2 - 180^2]y + [(x_2 - x_1)^2 + (y_2 - y_1)^2 - 180^2]^2 = 0$$\)

this is the standard form of the hyperbola that the receiver sits on if the transmitters behave as foci of the hyperbola.

What is hyperbola ?

A hyperbola is a type of conic section that has two separate parts, called branches, which are mirror images of each other. It is defined as the set of all points in a plane, such that the difference between the distances from two fixed points, called foci, is a constant. Hyperbolas have many applications in science, engineering, and mathematics.

Given two LORAN transmitters located at the coordinates \($(x_1, y_1)$\) and \((x_2, y_2)$\), where unit distance on the coordinate plane is measured in miles.

Let the coordinates of the receiver be \((x,y)$.\)

The distance from the receiver to the first transmitter is given by \($\sqrt{(x - x_1)^2 + (y - y_1)^2}$\), and the distance from the receiver to the second transmitter is given by \(\sqrt{(x - x_2)^2 + (y - y_2)^2}$.\)

Since the difference in the distances from the receiver to these transmitters is 180 miles, we have:

\($$\sqrt{(x - x_1)^2 + (y - y_1)^2} - \sqrt{(x - x_2)^2 + (y - y_2)^2} = 180$$\)

Squaring both sides, we get:

\($$(x - x_1)^2 + (y - y_1)^2 - 2\sqrt{(x - x_1)^2 + (y - y_1)^2} \sqrt{(x - x_2)^2 + (y - y_2)^2} + (x - x_2)^2 + (y - y_2)^2 = 180^2$$\)

Rearranging, we get:

\($$(x - x_1)^2 + (y - y_1)^2 - (x - x_2)^2 - (y - y_2)^2 = 4\sqrt{(x - x_1)^2 + (y - y_1)^2} \sqrt{(x - x_2)^2 + (y - y_2)^2} - 180^2$$\)

Using the identity $a^2 - b^2 = (a + b)(a - b)$, we can simplify the left-hand side as:

\($$4x(x_2 - x_1) + 4y(y_2 - y_1) = 4\sqrt{(x - x_1)^2 + (y - y_1)^2} \sqrt{(x - x_2)^2 + (y - y_2)^2} - 180^2$$\)

Squaring both sides again and simplifying, we get:

\($$16[(x_2 - x_1)^2 + (y_2 - y_1)^2]x^2 - 32(x_2 - x_1)x^3 + 16(x_2 - x_1)[(y_2 - y_1)^2 + (x_2 - x_1)^2 - 180^2]x + 16[(y_2 - y_1)^2 + (x_2 - x_1)^2]y^2 - 32(y_2 - y_1)y^3 + 16(y_2 - y_1)[(y_2 - y_1)^2 + (x_2 - x_1)^2 - 180^2]y + [(x_2 - x_1)^2 + (y_2 - y_1)^2 - 180^2]^2 = 0$$\)

this is the standard form of the hyperbola that the receiver sits on if the transmitters behave as foci of the hyperbola.

Therefore, \($$16[(x_2 - x_1)^2 + (y_2 - y_1)^2]x^2 - 32(x_2 - x_1)x^3 + 16(x_2 - x_1)[(y_2 - y_1)^2 + (x_2 - x_1)^2 - 180^2]x + 16[(y_2 - y_1)^2 + (x_2 - x_1)^2]y^2 - 32(y_2 - y_1)y^3 + 16(y_2 - y_1)[(y_2 - y_1)^2 + (x_2 - x_1)^2 - 180^2]y + [(x_2 - x_1)^2 + (y_2 - y_1)^2 - 180^2]^2 = 0$$\)

this is the standard form of the hyperbola that the receiver sits on if the transmitters behave as foci of the hyperbola.

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Answer: A (5⁻²)² and D 5²*5⁻⁶.

Step-by-step explanation:

\(\displaystyle\\\frac{1}{5}*\frac{1}{5} *\frac{1}{5} *\frac{1}{5}=\\\\\frac{1*1*1*1}{5*5*5*5} = \\\\\frac{1^4}{5^4}=\\\\\frac{1}{5^4}=\\\\5^{-4}=\\\\5^{-2*2}=\\\\(5^{-2})^2.\)

\(5^{-4}=\\\\5^{2-6}=\\\\5^2*5^{-6}.\)

Answer:

Karen is waiting for a pot of soup to cool off before serving it. After 4 min the soup has cooled from 100°C to 78°C. What was the average change in temperature each minute?

✓ Answer:It went down 5.5°C a minute.Step-by-step explanation:You have to look for the difference of 100 and 78, which is …

Answer:

Mean = 18.8

Step-by-step explanation:

Mean = (Sum of all values)/(Number of values)

Mean = (12 + 15 + 18 + 23 + 26)/5

Mean = 94/5

Mean = 18.8

Answer:

18.8

Step-by-step explanation:

12+15+18+23+26=94 94/5 (5 is how many pair of numbers there are)=18.8

9514 1404 393

Answer:

  10,450 cm³

Step-by-step explanation:

The volume is the product of the area of the facing face and the depth of the figure. The area of the facing face is the sum of the areas of a rectangle and a triangle. The relevant area formulas are ...

  A = bh . . . . . area of rectangle with base b and height h

  A = 1/2bh . . . area of triangle with base b and height h

Here the rectangle and triangle have the same base, 19 cm. Then the sum of the areas is ...

  Atot = (19 cm)(18 cm) + 1/2(19 cm)(14 cm)

  Atot = (19 cm)(18 cm +1/2×14 cm) = (19 cm)(25 cm) = 475 cm².

Then the volume of the figure is ...

  V = Bh = (475 cm²)(22 cm) = 10,450 cm³

_____

Additional comment

Effectively, this is the volume of a cuboid whose height is that of the bottom rectangular prism (18 cm) plus half the height of the triangular prism on top (1/2×14 cm = 7 cm). (18+7=25) The volume is essentially 19 cm × 25 cm × 22 cm. This recognition can serve to simplify the work or to act as a check on the work done some other way.

The length FE in the circle is 6 units

The arc AE has a measure of 64 degrees

From the question, we have the following parameters that can be used in our computation:

The circle

Given that the lengths from the center to either chords are equal

This means that

FE = 6 units

For the other circle, we have

BC = 58 degrees

AB = ED

The arc AE is calculated as

AE = 180 - BC - ED

Where

AB = ED = BC = 58 degrees

So, we have

AE = 180 - 58 - 58

Evaluate

AE = 64

Hence, the arc AE is 64 degrees

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Therefore , the solution of the given problem of probability comes out to be a)1/78 ,b)65/624 ,c)1/4 ,d)0 and e)12/13.

The basic goal of any considerations technique is to assess the probability that a statement is accurate or that a specific incident will occur. Chance can be represented by any number range between 0 and 1, where 0 normally indicates a percentage but 1 typically indicates the level of certainty. An illustration of probability displays how probable it is that a specific event will take place.

Here,

a.

P(Bert gets a Jack and Ernie rolls a five) = P(Bert gets a Jack) * P(Ernie rolls a five)

= (4/52) * (1/12)

= 1/78

b.

P(Bert gets a heart and Ernie rolls a number less than six) = P(Bert gets a heart) * P(Ernie rolls a number less than six)

= (13/52) * (5/12)

= 65/624

c.

P(Bert gets a face card and Ernie rolls an even number) = P(Bert gets a face card) * P(Ernie rolls an even number)

= (12/52) * (6/12)

= 1/4

d.

P(Bert gets a red card and Ernie rolls a fifteen) = 0

e.

Ernie rolls a number that is not twelve, and Bert draws a card that is not a Jack:

A regular 52-card deck contains 48 cards that are not Jacks,

so the likelihood that Bert will draw one of those cards is 48/52, or 12/13.

On a 12-sided dice with 11 possible outcomes,

Ernie rolls a non-12th-number (1, 2, 3, etc.).

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Answer:

decreasing.

Step-by-step explanation:

the graph shows the line is going downwards in section 1.

The description that best fits the pilot's distance in section I is "decreasing."

Here, we have,

We know that,

A graph is a visual representation of data that shows the relationship between two or more variables. It is a way of presenting information in a clear and concise manner that makes it easy to interpret and understand.

Graphs can be used to show trends over time, compare different groups or categories, or illustrate the relationship between two or more variables.

Given , A graph titled Pilot's Distance from Home. The horizontal axis shows time (hours) and the vertical axis shows distance (miles)

This is because the graph shows a reduction in distance over time in section I, which means that the pilot is getting closer to the home airport.

Therefore , The description that best fits the pilot's distance in section I is "decreasing."

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Answer:

52

Step-by-step explanation:

Answer:

9/2

Step-by-step explanation:

Answer:

I think the answer is D  

Step-by-step explanation:

The 9 adult tickets and 93 children tickets were purchased.Let's assume the number of adult tickets purchased is "a" and the number of children tickets purchased is "c."

According to the given information, children tickets cost $9 and adult tickets cost $11. So, the total cost of children tickets is 9c, and the total cost of adult tickets is 11a.

The problem also states that the total cost of all the tickets is $936. Therefore, we can write the following equation:

9c + 11a = 936

Additionally, it is mentioned that the number of children tickets purchased was three more than ten times the number of adult tickets purchased:

c = 10a + 3

We can now solve this system of equations to find the values of "a" and "c." By substituting the value of "c" from the second equation into the first equation, we have:

9(10a + 3) + 11a = 936

90a + 27 + 11a = 936

101a = 936 - 27

101a = 909

a = 909 / 101

a = 9

Substituting this value back into the second equation, we find:

c = 10(9) + 3

c = 90 + 3

c = 93.

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Answer:

I don't know what to do with it but I don't

Step-by-step explanation:

hahahaha

Answer:

IQR = 32 - 26 = 6

Step-by-step explanation:

Answer:

the answer is 11

Step-by-step explanation:

I took the algebra nation test

Answer:

58/33 or 1.75

Step-by-step explanation:

djskskdkdkjdjddjdjdkf

Answer:

a

Step-by-step explanation:

Based on the information, we can infer that the theoretical probability of these colors would be 33.33%. However, the table reflects different data.

To calculate the theoretical probability of each color we must perform the following mathematical operation.

Bearing in mind that 300 is 100% of the people, we must divide 300 by 3 to know how many people should choose a specific color. In this case, every 100 people should choose a different color.

Additionally, these 100% would represent 33.33% of the total population.

100 * 100 / 300 = 33.33%

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The amount of work done is Option A) 12 N/m

Work done is simply defined as the product of the magnitude of displacement, (d) and the component of the force that in the direction of displacement.

It measures energy transfer that occurs when an object is moved to a distance by an external force which is applied in the direction of the displacement.

Work done on a body is equivalent  to the increase in the energy of the body, because it transfers energy to the body.

The formula for work done is;

W = fd

Where, 'f' is the applied force and d is the distance

Substitute the values

Work done = 6(2)

Work done = 12 N/m

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Answer:

x<-12 or x>16

Step-by-step explanation:

Answer:

|x - 2| + 3 > 17

|x - 2| > 14

x - 2 < -14 or x - 2 > 14

x < -12 or x > 16