If 298.2g of HCL is produced what is the percent yield

Answer:

D

Explanation:

got it right on the test

The "alum" used in cooking is potassium aluminum sulfate hydrate, KAl(SO4)2·x H2O and the value of x calculated is 12.

Alum is a type of chemical compound, usually hydrated double sulfate salt of aluminum having general formula X Al ₂·12 H ₂O, where X is  monovalent cation such as potassium or ammonium.

Given mass of KAl(SO₄)₂.XH₂O = 4.74 g

and mass of water = 2.16 g

So, mass of KAl(SO₄)₂ = 4.74 – 2.16 = 2.58 g

Molar mass of KAl(SO₄)₂ ;

= 39 + 27 + 2[32 + (4×26)]

Now, molar mass of KAl(SO₄)₂ = 258 g/mol

Molar mass of H₂O ;

= (2×1) + 16

Now, molar mass of H₂O = 18 g/mol

Hence, KAl(SO₄)₂ = 2.58 / 258 = 0.01

and H₂O = 2.16 / 18 = 0.12

KAl(SO₄)₂ = 0.01 / 0.01 = 1

H₂O = 0.12 / 0.01 = 12

The formula of the compound is obtained as KAl(SO₄)₂.12H₂O

Comparing KAl(SO₄)₂.12H₂O with KAl(SO₄)₂.XH₂O,  value of X is 12.

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Answer:

1) 1.51 * 10^-3

2) 1.55 * 10^-2

3) cannot be turned into scientific notation

4) If 15,347; 1.53 * 10^4  but If 15.347; 1.53 * 10^1

Explanation:

Scientific notation just means moving the decimal place of a number so that there is only one number in the one's place (the exponent on the ten is the number of times the decimal moved). It is used to write really big or really small numbers without having to write a bunch of zeros.

The mass of hydrogen needed to produce 51.0 grams of ammonia is  ≈ 9.07 grams.

To determine the mass of hydrogen required to produce 51.0 grams of ammonia (NH3) using the Haber process, we need to calculate the stoichiometric ratio between hydrogen and ammonia.

From the balanced chemical equation:

3 H₂(g) + N₂(g) → 2 NH₃(g)

We can see that for every 3 moles of hydrogen (H₂), we obtain 2 moles of ammonia (NH₃).

First, we need to convert the given mass of ammonia (51.0 grams) to moles. The molar mass of NH₃ is 17.03 g/mol.

Number of moles of NH₃ = Mass / Molar mass

                     = 51.0 g / 17.03 g/mol

                     ≈ 2.995 moles

Next, using the stoichiometric ratio, we can calculate the moles of hydrogen required.

Moles of H₂ = (Moles of NH₃ × Coefficient of H₂) / Coefficient of NH₃

           = (2.995 moles × 3) / 2

           ≈ 4.493 moles

Finally, we can convert the moles of hydrogen to mass using the molar mass of hydrogen (2.02 g/mol).

Mass of H₂ = Moles × Molar mass

          = 4.493 moles × 2.02 g/mol

          ≈ 9.07 grams

Therefore, approximately 9.07 grams of hydrogen is needed to produce 51.0 grams of ammonia in the Haber process.

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Answer: Although the rocks of the produced by similar processes but their chemical composition may vary dependent upon the type of mineral present in these rocks so the color of the rock also varies depending upon the mineral composition.

Explanation:

The rocks are made by basic steps like disintegration of parent rock material, erosion, crystallization, metamorphism, and sedimentation. These basic steps are common in same kind of rocks but their color may vary because of the mineral composition in them for example, Rhyolite is of light colored because of the presence of quartz mineral present in it.

Answer:

You would need 8 eight packs of water

Explanation:

32  x  2 (seeing as this is the amount of water each person consumes)

= 64 divided by 8 (the amount of water in each pack)

= 8 eight packs of water

Answer:

0.25 mol

Explanation:

Use the formula n=N/NA

n= number of mols

N =  number of particles

Nᵃ = Avogadros constant = 6.02 x \(\\10^{23\)

So, n= \(\frac{1.505 X 10^{23} }{6.02 X 10^{23}}\)

The 10 to the power of 23 cancels out and you are left with 1.505/6.02, which is approximately 1/4. This is the same as 0.25 mol.

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A 50.0 mL solution of 0.250 M HC₂H₃O₂ before and after adding 50 mL of 0.250 M NaOH has a pH of 2.87, the pH changes due to the formation of a buffer solution, which can be calculated using the Henderson-Hasselbalch equation.

This problem requires us to calculate the pH of a buffer solution after the addition of a strong base. A buffer solution is one that resists pH changes when modest amounts of acid or base are added. The buffer system in this case is the weak acid, acetic acid (HC₂H₃O₂) and its conjugate base, acetate ion (C₂H₃O₂-).

Before the addition of NaOH, we have a solution of 0.250 M HC₂H₃O₂, which we can assume to be completely dissociated in water:

HC₂H₃O₂ + H₂O ⇌ H₃O+ + C₂H₃O₂-

HC₂H₃O₂ has a Ka value of 1.8 x 10-5. We can use this Ka value to calculate the equilibrium concentration of H3O+ and C₂H₃O₂- in the solution.

First, we need to calculate the initial concentrations of HC₂H₃O₂ and C₂H₃O₂-.

moles of HC₂H₃O₂ = 0.250 M × 0.0500 L = 0.0125 mol

moles of C₂H₃O₂- = 0 mol (since there is no NaOH added yet)

Since HC₂H₃O₂ is a weak acid, it only partially dissociates in water. The equilibrium concentrations of H₃O+ and C₂H₃O₂- can be calculated using the Ka expression:

Ka = [H₃O+][C₂H₃O₂-]/[HC₂H₃O₂]

We can assume that the initial concentration of H3O+ is negligible compared to the amount that will be produced by the dissociation of HC₂H₃O₂, so we can simplify the expression to:

Ka = [H₃O+]²/[HC₂H₃O₂]

[H₃O+]² = Ka × [HC₂H₃O₂]

[H₃O+]² = 1.8 × 10⁻⁵ × 0.0125

[H₃O+] = 1.34 × 10⁻³ M

Now that we know the equilibrium concentration of H₃O+, we can use the pH formula to calculate the pH:

pH = -log[H₃O+]

pH = -log(1.34 × 10⁻³)

pH = 2.87

This is the pH of the buffer solution before the addition of NaOH.

Next, we add 50 mL of 0.250 M NaOH to the solution. NaOH is a strong base, so it completely dissociates in water to produce OH- ions:

NaOH → Na+ + OH-

The OH- ions will react with the acetate ions in the buffer solution to form water and acetate ions:

OH- + C₂H₃O₂- → H₂O + C₂H₃O₂-

This reaction will consume some of the acetate ions in the buffer solution, causing the equilibrium to shift to the left to produce more acetate ions.

To calculate the new concentrations of H₃O+ and C₂H₃O₂-, we need to use the Henderson-Hasselbalch equation:

pH = pKa + log([C₂H₃O₂-]/[HC₂H₃O₂])

where pKa = -log(Ka), [C₂H₃O₂-] is the equilibrium concentration of acetate ions, and [HC₂H₃O₂] is the equilibrium concentration of acetic acid.

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Mn(s) metal will spontaneously react with Zn²⁺(aq), but will not

spontaneously react with Mg²⁺ (aq)

The Eo value of an electrochemical cell determines its spontaneity. Positive Eo electrochemical cells are spontaneous, and vice versa.

The relevant Eo of the half-cell in this instance are as follows for Mn(s) metal

Zn2+/Zn = -0.763v for Eo

2.37v for Eo Mg2+/Mg.

Mn2+/Mn = -1.18v for Eo.

Consequently, the equation for an Eo cell (with Zn as one of the half-cells) is: Eo Zn2+/Zn - Eo Mn2+/Mn = -0.763 - (-1.18) = 0.417v.

On the other hand, the equation for an Eo cell (with Mg as one of the half-cells) is: Eo Mg2+/Zn - Eo Mn2+/Mn = -2.37 - (-1.18) = -1.19v.

As a result, Mn(s) metal will spontaneously react with Zn2+(aq), but not with Mg2+ (aq)

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The electrons move from left to right through the circle labeled "M" to reach the cathode, where reduction takes place.

If oxidation occurs on the left side of the fuel cell and reduction occurs on the right side, the movement of electrons can be described as follows: Electrons move from left to right through the circle labeled "M."

In a fuel cell, the process of oxidation takes place at the anode (labeled A) where the fuel is oxidized, releasing electrons. These electrons then flow through the external electrical circuit, represented by the wire connecting objects A and B. The electrons reach the cathode (also labeled A) on the right side of the cell, where reduction occurs.The circle labeled "M" represents the membrane or electrolyte in the fuel cell. This membrane allows the transport of ions but blocks the movement of electrons. As a result, electrons cannot flow directly through the electrolyte but must travel through the external circuit.

This movement of electrons through the external circuit is what generates an electric current that can be used to power electrical devices or systems.

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Compose balanced molecule, gross ionic, as well as net ionic formulae for the interaction between sodium hydroxide plus nitric acid in aqueous solutions. The net ionic equation's coefficient sum is three.

Ammonium nitrate, a crucial component of fertilizers, is created using nitric acid. Additionally, it is used to oxidize materials and to make explosives like trinitrotoluene (TNT) as well as nitroglycerin.

The liquid leads to severe burns when it comes in contact with your eyes, which could cause lifelong damage and vision loss. The liquefied or concentrated vapor causes immediate, severe, and profound burns on the skin, while acidic solution result in deep ulcers and leave a brilliant yellow stain.

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471 g, or roughly 16.6 ounces, of the snack mix, can be consumed daily by an adult.

The chemical element sodium has an atomic number of 11 and the symbol Na, which comes from its Latin name, natrium. It is an alkali metal, which is a soft, silvery-white group of elements in the periodic table. Due to its strong reactivity, sodium is not found in nature's elemental form but rather in compounds like sodium hydroxide, sodium bicarbonate, and sodium chloride (table salt) (lye).

We must first translate the quantity of salt in the snack mix into the quantity of sodium it contains in order to determine how much sodium is in the snack mix:

1.30 g of salt/100 g of mix x 39.33 g of sodium/100 g of salt = 0.51 g of sodium/100 g of mix

As a result, the snack mix has 0.51 g of salt per 100 g.

The following calculation can be used to determine how much of the snack mix an adult can eat without exceeding the FDA's daily salt recommendation:

2.40 g of sodium/day ÷ 0.51 g of sodium/100 g of mix = 4.71 x 100 g of mix.

Therefore, 471 g, or roughly 16.6 ounces, of the snack mix, can be consumed daily by an adult and yet keep under the FDA's daily sodium recommendation.

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The concentration of particles in a 0.651 M solution of AlCl₃ is 2.06 M.

This can be calculated by multiplying the molarity of the solution (0.651 M) by the van't Hoff factor (3.20). Therefore, 0.651 x 3.20 = 2.06.

What is molarity?

Molarity is a unit of concentration that is defined as the number of moles of a solute per liter of solution. It is usually represented by the symbol M. The calculation of molarity is done by dividing the number of moles of a solute by the total volume of the solution in liters. It is also often used in dilutions, where the concentration of a solution is reduced by adding more solvent. Molarity is a very important concept in chemistry and is used to predict and measure the amount of substances needed in a reaction.

Therefore, The concentration of particles in a 0.651 M solution of AlCl₃ is 2.06 M.

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The system from the description must be an open system. Option C

An open system is one that communicates with and is influenced by its surroundings. An open system interacts with its environment by exchanging matter, energy, and information, as opposed to a closed system, which is self-contained and runs autonomously.

The idea of open systems highlights how interconnected and reliant on its environment a system is. For the analysis of system behavior, adaptability, and responses to external forces, understanding these interconnections is essential.

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Answer:

Emulsion:

A colloidal solution in which both the dispersed phase and dispersion medium are liquids is called an Emulsion.

Gel:

Gels is that kind of colloid in which the dispersed phase is a liquid and the dispersion medium is a solid.

Foam:

Foam is a substance in which the particles are gas bubbles and the medium is a liquid.

2.5 moles of BaCl2 can produce 5 moles of NaCl.

Chemical equation is the symbolic representation of a chemical reaction in the form of symbols and chemical formulas.

The balanced chemical equation for the reaction between barium chloride (BaCl2) and sodium sulfate (Na2SO4) is:

BaCl2 + Na2SO4 → 2 NaCl + BaSO4

From this equation, we can see that for every 1 mole of BaCl2, 2 moles of NaCl are produced.

Therefore, to calculate how many moles of NaCl can be produced from 2.5 moles of BaCl2, we can use the following proportion:

1 mole BaCl2 : 2 moles NaCl = 2.5 moles BaCl2 : x moles NaCl

Where

Solving for x, we get:

x = 2.5 moles BaCl2 × (2 moles NaCl / 1 mole BaCl2)

x = 5 moles NaCl

Therefore, 2.5 moles of BaCl2 can produce 5 moles of NaCl.

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The total volume of the solution prepared by dissolving 48.0 grams of Ca(OH)₂ in enough water is 0.865 L

First, we shall obtain the mole of 48.0 grams of Ca(OH)₂. This is shown below:

Mole = mass / molar mass

Mole of Ca(OH)₂ = 48 / 74

Mole of Ca(OH)₂ = 0.649 mole

Finally, we shall obtain the total volume of the Ca(OH)₂ solution. Details below:

Volume = mole / molarity

Volume of solution = 0.649 / 0.750

Volume of solution = 0.865 L

Thus, we can conclude that the total volume of the solution is 0.865 L

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Explanation:

lo que tú as puesto es falso

Option B is the correct answer .

What is Charge ?

Charge is a basic property of matter that is associated with the presence or absence of electrons. Objects can have positive or negative charge, or they can be neutral, which means they have an equal number of positive and negative charges. In physics, charge is one of the fundamental concepts used to explain the behavior of matter and energy in the universe. The interaction between charges is described by Coulomb's law, which states that the force between two charges is proportional to the product of their charges and inversely proportional to the square of the distance between them.

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Answer:

Voltage is the measure of electric potential energy per unit charge, current is the flow of electric charge through a circuit, and resistance is the property of a material that opposes the flow of electric current.

Ohm's Law relates these three concepts by stating that current is directly proportional to voltage and inversely proportional to resistance.

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Answer : The correct chemical equation is:

\(2NaBr(aq)+Pb(NO_3)_2(aq)\rightarrow PbBr_2(s)+2NaNO_3(aq)\)

Explanation :

Balanced chemical equation : It is defined as the equation in which the atoms of individual elements present of reactant side must be equal to the product side.

According to the question, when sodium bromide reacts with lead nitrate then it reacts to give sodium nitrate and lead bromide as a products.

The balanced chemical equation will be:

\(2NaBr(aq)+Pb(NO_3)_2(aq)\rightarrow PbBr_2(s)+2NaNO_3(aq)\)

Electron configuration refers to the distribution of electrons in atoms and molecules.

In conclusion, electron configuration refers to the distribution of electrons in atoms and molecules.

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Answer:

In atomic physics and quantum chemistry, the electron configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals.

The cell produces an emf of 2.32 V. For this cell reaction at 25 degrees Celsius, use the Nernst equation. where n represents the number of electrons exchanged during the cellular process.

According to measurements, the electromotive force (EMF) is 1.100 V. The standard condition is specified as a concentration of 1 M in an ideal solution, and as a result, 1.100 V is the standard electromotive force, DEo, or standard cell potential for the Zn–Cu galvanic cell.

Due to the larger standard reduction potential of the silver half-cell, the reduction will occur. The half-cell of tin will oxidize. The formula E0cell=E0red+E0oxid can be used to get the overall cell potential.

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Answer:

cis-2-hexene

Explanation:

Hello.

In this case, since a Lindlar's catalyst is mainly composed by palladium, which is a transition metal with a very exceptional surface area which makes it a suitable catalyst for hydrogenation reactions by which hydrogen is added to the insaturation in order to make a double bond where the triple bonds was in an alkyne, based on the attached picture we can see that the major product of that reaction is cis-2-hexene.

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The  statements about an E1 mechanism is not true is that  " the loss of a proton by the carbocation is a slow step."

The E1 mechanism is also called as the unimolecular elimination reaction. in the E1 mechanism there are two parts involves that is ionization and deprotonation. In the ionization process the formation of the carbocation takes place as the intermediate. and in the deprotonation steps the protons is lost by the carbocation.

Thus, in the E1 mechanism the loss of the proton by the carbocation is not the slow step. this process happens in the presence of the base.

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Answer:

Explanation:

Robert Boyle

Answer:

La ley de los gases ideales relaciona cuatro propiedades macroscópicas de los gases ideales (presión, volumen, número de moles y temperatura). Si conocemos los valores de tres de estas propiedades, podemos utilizar la ley de los gases ideales para conocer la cuarta. En este video, usaremos la ley de los gases ideales para resolver el número de moles (y en última instancia de moléculas) en una muestra de un gas

Explanation:

42.4 ml is the volume in milliliters of the lead ball if a lead ball is added to a graduated cylinder containing 50.6 ml of water.

A tall narrow container with a volume scale is used especially for measuring liquids.

The graduated cylinder contains water

mL is a volume unit.

Water volume = 50.6 ml

The lead ball caused an increase in volume from 50.6 ml to 93.0 mL.

The new volume is the lead ball volume plus the original water volume :

Final volume = Vlead ball+ Water original volume

\(93.0 mL= V_(lead ball) +50.6 ml\)

\(V_(lead ball) = 93.0 mL - 50.6 ml\)

\(V_(lead ball) = 42.4 ml\)

Hence, 42.4 ml is the volume in milliliters of the lead ball.

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The first question has an answer of A: the bulb turns 60 J of electrical energy into heat and light every second. It is True that a gas's molecules are significantly more spaced away from one another than those of a solid or liquid.

A heated filament or a gas discharge generate light in a light bulb, an electric device. The light of the bulb is produced by a wire filament that is heated by an electric current. Thomas Edison created the first incandescent light bulb that was commercially viable in 1879, and by creating a useful source of artificial light, it completely changed the way we live today. With the introduction of compact fluorescent bulbs, LED lights, and other technologies, light bulbs have developed over time to become more energy-efficient. Light bulbs today are a necessary part of contemporary life, providing illumination for private residences, commercial buildings, and public areas.

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At constant temperature, if the volume of the gas decreased to the given value, the pressure increases to 2.16atm.

Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.

Boyle's law is expressed as;

P₁V₁ = P₂V₂

Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.

Given the data in the question question;

P₁V₁ = P₂V₂

P₂ = P₁V₁ / V₂

P₂ = ( 1.33atm × 0.682L) / 0.419L

P₂ = 0.90706Latm / 0.419L

P₂ = 2.16atm

Therefore, at constant temperature, if the volume of the gas decreased to the given value, the pressure increases to 2.16atm.

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