if 200 g of carbon reacts with excess sulfur dioxide to produce 225 g of carbon disulfide (cs2 ; molar mass 76.139 g/mol), what is the percent yield for the reaction?

Answer:

You have about 6158 Molecules of 02.

Explanation:

Chromium(III) chlorate (Cr(ClO3)3) is a solid (s) that dissolves in water to form aqueous chromium(III) ions (Cr^3+, aq) and 3 aqueous chlorate ions (ClO3^-, aq). The coefficients represent the lowest possible whole numbers to balance the equation.

When Cr(ClO3)3 is dissolved in water, it dissociates into its respective ions. The balanced chemical equation for the dissolution of Cr(ClO3)3 can be written as:

Cr(ClO3)3(s) → Cr3+(aq) + 3ClO3-(aq)

This equation shows that one molecule of solid Cr(ClO3)3 dissociates into one Cr3+ ion and three ClO3- ions in aqueous solution. The state-of-matter for Cr(ClO3)3 is solid (s), while the state-of-matter for Cr3+ ion and ClO3- ions is aqueous (aq). The coefficients in the equation are already in their lowest possible whole number form.

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AgNO₃ will act as the oxidising agent.

Cu + 2AgNO₃ →  2Ag + Cu(NO₃)₂

Half reactions for the given chemical reaction:

Reducing agent:

Cu → Cu²⁺ + 2e⁻

Copper is a reducing agent because it is losing 2 electrons, which causes an oxidation process.

Oxidising Agent:

Ag⁺ + e⁻ → Ag

The silver ion undergoes a reduction process and is regarded as an oxidizing agent since it is acquiring one electron per atom.

Hence, AgNO₃ is considered as an oxidizing agent and therefore the correct answer is Option B.

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Fluorescence spectroscopy provides more detailed information compared to absorption spectroscopy due to its ability to detect both the excitation and emission wavelengths of a sample.

In absorption spectroscopy, only the absorption of light by the sample is measured, while in fluorescence spectroscopy, the absorbed light is re-emitted at a longer wavelength, providing additional data. This emission spectrum can reveal structural and environmental information about the molecules in the sample, such as their chemical composition, electronic states, and interactions.

Thus, fluorescence spectroscopy offers a more comprehensive understanding of molecular properties, making it a powerful tool in various scientific fields, including biochemistry, materials science, and environmental analysis.

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Yes, all the liquid will evaporates,

given that :

vapor pressure of liquid carbon disulfide = 100mmHg = 0.1315 kpa

temperature = 268 K

volume of the container = 370 mL = 0.370 L

using ideal gas equation we get :

PV = n R T

n = P V / R T

n = ( 0.315 × 0.370 ) / ( 0.0823 × 278)

n = 0.0050 mol = 5.0 × 10⁻³ mol

number of moles of CS₂ = mass / molar mass

                                        = 0.0979 / 76.139

                                        = 0.00128 mol

                                        = 1.2 × 10⁻³ mol

it is clear that , the vapor pressure of liquid carbon disulfide, , is 100. mm hg at 268 k. a 0.0979 g sample of liquid is placed in a closed, evacuated 370. ml container at a temperature of 268 k. yes the temperature remains constant, all of the liquid evaporate.

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The oxidation number of Mn in potassium permanganate is +7.

The oxidation number, also known as the oxidation state, is a measure of the degree of oxidation of an atom in a chemical compound. In potassium permanganate, the potassium ion (K+) has an oxidation state of +1, and each oxygen atom (O) has an oxidation state of -2. To determine the oxidation number of Mn, we can use the fact that the sum of the oxidation states in a neutral molecule must be zero. Therefore, we have:

(+1) + x + 4(-2) = 0

Simplifying this equation, we get:

x - 7 = 0

Solving for x, we get:

x = +7

Therefore, the oxidation number of Mn in KMnO₄ is +7. Answer: b. +7.

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Answer:

No, because oxygen wants two electrons to become stable and lithium will only give up 1 electron.

Answer:

Q.1

To calculate moles of helium (n)=?

given

p=1.1 Atm

V=5.10 L

T =22°C

R =8.314 (universal gas constant)

Now use,

PV = nRT

1.1×5.10 =n×8.314×22

n= 5.61÷182.9

n= 0.030 moles

Use the same method to solve further questions!

Answer:

2

Explanation:

The phenomenon in which electrons that are closer to the nucleus slightly repel those that are farther out is known as Shielding.

Electrons in an atom are negatively charged particles, and they are attracted to the positively charged nucleus. However, the outer electrons of an atom are also repelled by the inner electrons that are closer to the nucleus. This repulsion is due to the negative charges of the electrons, and it partially cancels out the attraction of the nucleus for the outer electrons.

Shielding is the phenomenon in which electrons that are closer to the nucleus slightly repel those that are farther out. This makes it possible for electrons in higher energy levels to be farther from the nucleus, so they are less strongly attracted and easier to remove.

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Answer:

c)elements in the same group are in the same family

The elements in the same column are in the same family.

The periodic table is arranged in rows and the periods. The elements in the same row has the same number of shells. The elements in the same column are in the same family.

The correct statements are;

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Answer:

The restoring force that prevents the furniture from tipping over when pushing the furniture towards the right, F= W × D

Where;

W = The weight of the furniture

D = The horizontal distance from the center of gravity of the furniture, CG and the to the lower right corner of the furniture

Given that A > D, for the furniture to tip over when pushing above the CG, we have;

F1 × A ≤ W × D

∴ F1 << W or for a force much smaller than W, the weight of the furniture applied above the center of gravity, the furniture will tip over

However when the force F2 is applied, where C < D, we have for no tipping over;

F2 × C ≤ W × D, therefore, given that C < D, when a force much higher than the weight, W, is applied at F2, the furniture will remain upright

Therefore, it is better push at a point lower than or equal to the center of gravity, whereby the point B is lower than the center of gravity, it is better to push at point B, Ravleen is correct and it is better to push at point B because the center of gravity is lower

If the furniture is pushed at the wrong spot it may tip over

Please see attached drawing

Explanation:

The solutions will be ranked as follows from lowest to highest vapor pressure:

20 g. of glucose C6H12O6 in 100ml h2o

20 g. of sucrose C12H22O11 in 100ml h2o

10 g. of potassium acetate KC2H3O2 in 100ml h2o

The vapor pressure depends on the concentration and nature of the solute. A nonvolatile solute like sugar will decrease the vapor pressure of the solvent, while a volatile solute such as acetate salt , will increase it

Both glucose and sucrose are non-volatile solutes, so they will decrease the vapor pressure of the solvent and thus will have lower vapor pressure than the pure solvent. However, sucrose has a lower molecular weight than glucose which means that it will have a greater effect on the vapor pressure of the solution and thus have a slightly lower vapor pressure.

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Answer:

NO OF NEUTRON =MASS NO -ATOMIC NO

=39-19

=20

bcz atomic no is equal to no of electrons

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Answer:

ruthenium (Ru), rhodium (Rh), palladium (Pd), osmium (Os), iridium (Ir), platinum (Pt), gold (Au), silver (Ag).

Explanation:

The term "Noble Metals" traditionally refers to a group of metals that are resistant to corrosion and oxidation in moist or chemically aggressive environments. The elements commonly considered noble metals are Gold, Platinum, Palladium, Palladium, etc.

Gold is perhaps the most well-known noble metal. It is highly resistant to corrosion and oxidation. Platinum is another widely recognized noble metal. It is extremely resistant to corrosion and has a high melting point.

Palladium is a noble metal that exhibits excellent chemical stability and resistance to corrosion.

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Answer:

properties of compounds with covalent bonds include:

They are powerful chemical bonds that exist between atoms.

Covalent bonds rarely break on their own after they are formed.

A covalent bond forms when two non-metal atoms share a pair of electrons.

Covalent bonds are strong – much energy is needed to break them.

Compounds with giant covalent structures have high melting and boiling points. The large number of strong covalent bonds involved means that a large amount of energy is required to break them apart.

Compounds with covalent bonds may be solid, liquid or gas at room temperature depending on the number of atoms in the compound. Since most covalent compounds contain only a few atoms and the forces between molecules are weak, most covalent compounds have low melting and boiling points.

Covalent compounds do not conduct electrical currents. This is because they lack free ions. The movement of charge carriers is the reason why water is conductive. In contrast, covalent compounds do not contain ions and are not soluble in water. However, there are several examples of covalent compounds that do conduct electricity. These include graphite, a metal with a single free electron.

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Which statement about exothermic reactions is TRUE?

A.In an exothermic reaction, energy is absorbed, bonds are broken, and the temperature decreases.

When 170.2 grams of HNO3 are consumed, 1.35 moles of water can be created. The answer, rounded to the closest tenth, is 1.4 moles of water.

The mass in grams of one mole of a chemical is its molar mass. The quantity of atoms, molecules, and ions contained in a substance is measured in terms of moles. A mole of any substance contains 6.022 x 1023 molecules.

We must first calculate how many moles of HNO3 are present in 170.2 grams.

We may convert grams to moles using the molar mass of HNO3:

molar mass of HNO3 = (1 x 1) + (14 x 1) + (3 x 16) = 63 g/mol

moles of HNO3 = 170.2 g / 63 g/mol = 2.70 mol

To calculate the quantity of water produced, we can use the following ratio:

4 moles H2O / 8 moles HNO3 = x moles H2O / 2.70 moles HNO3

After finding x, we obtain:

x = (4 moles H2O / 8 moles HNO3) * 2.70 moles HNO3 = 1.35 moles H2O.

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Answer:

liquid ethanol can be separated from a mixture of ethanol and water by fractional distillation and separation of various components of crude oil. This method works because the liquids in the mixture have different boiling points.

Explanation:

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The correct order of decreasing density of the gases under STP conditions is Fluorine, Oxygen, Neon, and Helium.

Under STP conditions, the gases can be arranged in order of decreasing density as follows:

Fluorine > Oxygen > Neon > Helium

Fluorine has the highest density due to its relatively heavy atomic mass compared to the other gases. Oxygen follows next with a density higher than Neon and Helium. Neon has a density higher than Helium as it has a larger atomic size and atomic mass than Helium. Helium, being the lightest gas, has the lowest density among the given gases under STP conditions.
The higher the molar mass, the greater the density of the gas. Here are the molar masses of the given gases:

1. Helium (He) - 4 g/mol
2. Neon (Ne) - 20 g/mol
3. Fluorine (F2) - 38 g/mol
4. Oxygen (O2) - 32 g/mol

Using the molar masses, we can arrange the gases in decreasing order of density:

1. Fluorine (F2)
2. Oxygen (O2)
3. Neon (Ne)
4. Helium (He)
Under STP conditions, the gases in decreasing order of density are: Fluorine, Oxygen, Neon, and Helium.

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Water and carbon dioxide are ineffective extinguishing agents for a sodium fire because they react with sodium to produce hydrogen gas and carbon monoxide, which can ignite and worsen the fire.

When sodium metal is exposed to air or water, it reacts vigorously and can ignite, producing a bright yellow flame. Sodium is highly reactive and has a low ignition temperature, so even a small amount of heat or moisture can cause it to ignite.

Water is not appropriate because it reacts with sodium to produce hydrogen gas, which can ignite and make the fire worse. This reaction also releases a large amount of heat, which can further fuel the fire.

Carbon dioxide can also be ineffective for extinguishing a sodium fire. While carbon dioxide does displace oxygen, it can also react with the sodium metal to produce carbon monoxide and sodium oxide. These products can also ignite and potentially increase the intensity of the fire.

Therefore, in the case of a sodium fire, specialized extinguishing agents such as dry powder, sand or graphite are recommended. These agents can help to smother the fire and prevent the sodium from coming into contact with air or moisture, which can further fuel the fire. It is important to note that sodium fires should be handled with extreme caution and should only be extinguished by trained professionals using the appropriate equipment and techniques

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If more \(H_{2}\) and \(N_{2}\) are added to the reaction 3\(H_{2}\) + N2 → 2\(NH_{3}\) after it reaches equilibrium, two events will occur Shift in Equilibrium and Increased Yield of \(NH_{3}\)

1. Shift in Equilibrium: According to Le Chatelier's principle, when additional reactants are added, the equilibrium will shift in the forward direction to consume the added reactants and establish a new equilibrium. In this case, more \(NH_{3}\) will be produced to counteract the increase in \(H_{2}\) and \(N_{2}\).

2. Increased Yield of \(NH_{3}\): The shift in equilibrium towards the forward reaction will result in an increased yield of \(NH_{3}\). As more \(H_{2}\) and \(N_{2}\) are added, the reaction will favor the production of \(NH_{3}\) to maintain equilibrium. This will lead to an increase in the concentration of \(NH_{3}\) compared to the initial equilibrium state.

It is important to note that the equilibrium position will ultimately depend on factors such as the concentrations of \(H_{2}\), \(N_{2}\), and \(NH_{3}\), as well as the temperature and pressure of the system. By adding more reactants, the equilibrium will adjust to achieve a new balance, favoring the formation of more \(NH_{3}\).

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The molar concentration of CO2 in a 4.26 L sample of acid rain is 0.0081 mol/L.Acid rain is caused by air pollution.

The molar concentration of carbon dioxide in a 4.26L sample of acid rain is calculated as follows:First, we will calculate the number of moles of carbon dioxide in the sample. The formula to calculate the number of moles is:Number of moles = mass of the substance/molar mass of the substanceThe molar mass of CO2 is 44.01 g/mol. 355 ppm means 355 parts per million, which is equivalent to 355 mg/L.To calculate the mass of carbon dioxide in 4.26 L of acid rain:Mass of CO2 = Volume × ConcentrationMass of CO2 = 4.26 L × 355 mg/L = 1510.3 mg = 1.51 gTherefore, the number of moles of CO2 in the sample is:Number of moles of CO2 = Mass of CO2/Molar mass of CO2 = 1.51 g/44.01 g/mol = 0.0344 molTo calculate the molar concentration of CO2:Molar concentration of CO2 = Number of moles of CO2/Volume of solution in litersMolar concentration of CO2 = 0.0344 mol/4.26 L = 0.0081 mol/L, When sulfur dioxide and nitrogen oxide pollutants combine with atmospheric moisture, they form acidic compounds that can travel long distances and fall as acid rain. Acid rain can damage forests, kill fish in streams, and corrode buildings and monuments, among other things.

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(i) The initial reaction rate is \(2*10^{-4} mol litre^{-1} sec^{-1.\)

(ii) The half-life period of the reaction is 1386 seconds.

(iii) The time taken to complete 75% of the reaction is approximately 2772 seconds.

We can use the first-order rate equation:

Rate = k[N2O5]

Where:

Rate is the reaction rate,

k is the rate constant,

[N2O5] is the concentration of N2O5.

Given:

Rate constant (k) = \(5*10^{-4} sec^{-1}\)

Initial concentration of N2O5 =\(0.4 mol litre^{-1}\)

(i) To find the initial reaction rate:

Substitute the given values into the rate equation:

Rate = k[N2O5]

Rate = \((5*10^{-4} sec^{-1})(0.4 mol litre^{-1})\)

Rate = \(2*10^{-4} mol litre^{-1} sec^{-1}\)

The initial reaction rate is \(2*10^{-4} mol litre^{-1} sec^{-1}\).

(ii) To find the half-life period:

The half-life of a first-order reaction is given by the equation:

t(1/2) = (0.693 / k)

Substitute the given value of k into the equation:

t(1/2) = \((0.693 / 5*10^{-4} sec^{-1})\)

t(1/2) = 1386 sec

The half-life period of this reaction is 1386 seconds.

(iii) To find the time taken to complete 75% of the reaction:

The time required to complete a certain percentage of a reaction can be found using the equation:

t = (ln(1 / (1 - x)) / k)

Where x is the fraction of the reaction completed (in this case, 75%).

Substitute the given values into the equation:

t =\((ln(1 / (1 - 0.75)) / 5*10^{-4} sec^{-1})\)

t = 2772 sec

The time taken to complete 75% of the reaction is approximately 2772 seconds.

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Answer:

Energy can be changed from one form to another, but it cannot be created or destroyed. The total amount of energy and matter in the Universe remains constant, merely changing from one form to another

Explanation:

energy cannot be created Or destroyed.

Answer:

a drought !

- little to no water causes it

- it causes for organisms to die and organisms need water !