identify tje scale factor that was used to graph W' X' Y'​

Answer:

TWO CRACKERS

Step-by-step explanation:

I'm assuming they want to find x. Here we see that these two are similar triangles, so the sides are reflective. 5x/5 should be equal to 4/x, so 5x/5 = 4/x. If we use cross multiplying we get 5x^2 = 20. divide both sides by 5 and we get x^2 = 4 or x = 2.

Hope this helped

Answer:

(P/2)-6

because its is perimeter you need to add the sides so the answer is (P/2)-6

Answer: find zero on the number line then put a dot on -7/5 (-1 2/5) then do the same on positive 7/5 (1 2/5

Step-by-step explanation:

find zero on the number line then put a dot on -7/5 (-1 2/5) then do the same on positive 7/5 (1 2/5 . I think that is correct sorry if it isnt.

Step-by-step explanation:

Answer:

B: 19.3

Step-by-step explanation:

Mark brainliest

Answer:

19.3

Step-by-step explanation:

Answer:

88

Step-by-step explanation:

We are given the expression:

x+43x

and asked to evaluate when x=2. Therefore, we must substitute 2 in for x.

x + 43 x (plug 2 in for each x )

2+43(2)

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.

Multiply 43 and 2 first.

2+ (43*2)

2+ 86

Add 2 and 86.

88

The expression x+43x when evaluated for x=2 is 88.

Answer:

1

Step-by-step explanation:

=============================================================

Explanation:

The perimeter is the amount of fencing needed to enclose this trapezoid.

The known sides of the figure add to 11+6+11 = 17+11 = 28 feet

The entire peimeter is 44 feet, which means 44-28 = 16 feet are needed along the bottom side.

---------------

If you want to involve algebra, then let x be the missing side

side1+side2+side3+side4 = perimeter

x+11+6+11 = 44

x+28 = 44

x = 44-28

x = 16

1. The measure of ∠E = 135°. 2. Angles ∠E and ∠K are alternate exterior angles, and the measure of ∠K = 135°

An exterior Angle is defined as an angle produced on the outside of a polygon by extending the sides of the polygon.

The figure is given in the question, as shown.

Since we have a regular octagon that has :

∠I = 45° = ∠G = 45°

Here ∠G + ∠H = 90° (complementary angles)

45° + ∠H = 90°

∠H = 45°

So ∠H + ∠E = 180° (supplementary angles)

45° + ∠E = 180°

∠E = 135°

2. Here the relationship between angles ∠E and ∠K is that they are alternate exterior angles.

So the measure of ∠K = 135°

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The missing figure has been attached below.

Answer:

Step-by-step explanation:

since the base angles of a triangle are equal the given triangle an isosceles triangles.

therefore side x is also 9 because the two sides of an isosceles triangle is equal.

Now for side y

using pythagoras theorem

a^2 + b^2 = c^2

9^2 + 9^2 =y^2

81 + 81 = y^2

162 = y^2

\(\sqrt{162}\) = y

\(9\sqrt{2}\) =y

Based on the Law of Cosines; it was proven that:

Please note that the given equation on number 3 is wrong. The correct equation should be: a² + b² + 2bx = c². The explanation why the given equation is incorrect will be explained later.

Based on the unshaded triangle, we can find that:

cos Θ = x/a

Next, we will prove that: cos (180 - C) = x/a

Remember that:

cos (A + B) = cos A cos B - sin A sin B

Law of Cosines: c² = a² + b² - 2ab. cos C

cos C = - [c² - (a² + b²)] /2ab ... (i)

Then:

cos Θ = cos (180 - C)

cos (180 - C) = cos 180 . cos C - sin 180 . sin  C

We subtitute equation (i):

cos (180 - C) = (-1) (- [c² - ((a² + b²)] / 2ab) - 0 sin C

cos (180 - C) = [c² - (a² + b²)]/ 2ab ... (ii)

If we focus on the unshaded triangle, we can find an equation of a, where:

a² = h² + x² ... (iii)

And if we combine both triangle into a giant triangle, we can make another equation of c. where:

c² = (x + b)² + h² ... (iv)

We will subtitute equation (iv) into equation (ii):

cos (180 - C) =  [c² - (a² + b²)]/ 2ab

cos (180 - C) = [(x + b)² + h² - (a² + b²)] / 2ab

cos (180 - C) = [x² + b² + 2bx + h² - a² - b²] / 2ab

cos (180 - C) = [x² + 2bx + h² - a²] / 2ab ... (v)

We subtitute equation (iii) into equation (v):

cos (180 - C) = [x² + 2bx + h² - a²] / 2ab

cos (180 - C) = [a² + 2bx - a²] / 2ab

cos (180 - C) = 2bx / 2ab

cos (180 - C) = x/a --> PROVEN!

Next, we will try to show why the given equation of a² + b² - 2bx = c² is incorrect.

We know that:

a² + b² - 2ab cos C = c²

c² = (x + b)² + h²

We will try to find the value of cos C:

a² + b² - 2ab cos C = (x + b)² + h²

a² + b² - 2ab cos C = x² + b² + 2bx + h²

a² - 2ab cos C = a² + 2bx

- 2 ab cos C = 2bx

cos C = - x/a

We will subtitute the value of cos C under the Law of Cosines:

c² = a² + b² - 2ab cos C

c² = a² + b² - 2ab (- x/a)

c² = a² + b² + 2bx --> PROVEN!

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Answer:

k=-4

Step-by-step explanation:

brainliest plzzz its the crown

The X variables have an overall correlation of 0. VIF, or Variance Inflationary Factor, measures the

Regression analysis's level of multicollinearity is gauged by a variance inflation factor, or VIF. When several independent variables in some kind of a model with multiple regression correlate with one another, this is known as multicollinearity. The regression findings may be significantly impacted by this.

Greater correlation between the variable and other variables is indicated by a higher value. With values of Ten or more being considered very high, values greater than 4 or 5 are occasionally considered to be moderate to high.

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Answer:

C

Step-by-step explanation:

First we need to find the average in every section, such as the Hw, quiz and tests.

(76+82+85)/3=81 Hw

(74+80+80)/3=78 quiz

(60+68)/2=64 test

Hw is weighted at 10% so it is 81×1=81.

Quizzes are weighted at 20% so 78×2=156

Tests are weighted at 60% so 64×6=384.

Add them all up then divide them by 9,

(81+156+384)/9= 69%

Answer:

5,600

Step-by-step explanation:

rounding by the nearest hundred would mean rounding up or down in the hundreds based off of thr tens. If the tens are above 50, you round up. if they are below 50, you round down

Answer:

The hundred place here is the the 2nd 5 to the left.

Rounding is when it’s 5 or above you go up, 4 or below you stay.
So 5565
In this case we look at the tenth place number which is 6 and since it’s 5 or above the hundreths place “5” goes up 1. Everything else below under th place turns 0.
So

5,600

The tri-linear inequality with the required 80% confidence interval of 54.1 to 57.7 shows the genuine mean value by which the drug decreases the average patient's systolic blood pressure.

A confidence interval expresses the likelihood that a population parameter will fall between a range of values a predetermined percentage of the time. It is the estimate's mean plus or minus the estimate's range of values.

Given the confidence level is 80%, the significance level α=100-80=20% = 0.20. The sample mean \(\overline{x}\) is 55.9, the sample standard deviation s is 7.4, and the sample size n is 29.

We are using t-distribution to population standard deviation first. For that first find the degree of freedom and critical value of t.

Degree of freedom,

df = n - 1

df = 29 - 1

df = 28.

The critical value of t calculated from the t-distribution table is,

\(\begin{aligned}t_{\text{critical}}&=t_{\alpha/2,df}\\&=t_{0.10,28}\\&=\pm1.3125 \end{aligned}\)

Then, an 80% confidence interval is,

\(\begin{aligned}\mu&=\overline{x}\pm\frac{t\cdot s}{\sqrt{n}}\\&=55.9\pm\frac{1.3125\times7.4}{\sqrt{29}}\\&=55.9\pm1.80\end{aligned}\)

Then, the interval is written as

55.9 - 1.80 < μ < 55.9 + 1.80

54.1 < μ < 57.7

The required interval is 54.1 < μ < 57.7.

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Check the picture below.

Answer:

The probability, to the nearest 10th of a percent, that both marbles drawn will be red is 28.5%

Step-by-step explanation:

Number of red marbles = 4

Number of blue marbles = 8

Number of Green marbles = 2

Total number of marbles = 4+8+2 =14

We need to find the probability, to the nearest 10th of a percent, that both marbles drawn will be red?

The formula used will be: \(Probability=\frac{Number\:of\:favourable\:outcomes}{Number\:of\;possible\:outcomes}\\\)

In our case, Number of favourable outcomes = 4 (as red marbles are drawn)

Number of possible outcome = 14 (Total number of marbles)

The probability will be:

\(Probability=\frac{Number\:of\:favourable\:outcomes}{Number\:of\;possible\:outcomes}\\\\Probability=\frac{4}{14}\\ Probability=0.2857\\\)

Now, calculating nearest 10th of a percent

\(Probability = 0.2857*100\\Probability=28.5%\)

So, the probability, to the nearest 10th of a percent, that both marbles drawn will be red is 28.5%

The transformation of f(x) to g(x) is :

From the question, we have the following parameters that can be used in our computation:

The functions f(x) and g(x)

Where, we have

f(x) = x

g(x) = 1/9x - 2

The graph of the functions f(x) and g(x) are added as an attachment

And we have the transformations to be:

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Answer

Connie can cut the ribbon into 12 foot pieces.

Step-by-step explanation:

For these problems we should find the GCF, which is 12.

The algebraic expression is 0.3G+25F

An algebraic expression is a sentence with a minimum of two numbers or variables and at least one mathematical operation.  

First, we can use G to represent green house flowers and F to represent ferns.

Then thirty percent of the green house flower can be represented by 0.3G.

25 ferns can be written as 25F.

The algebraic expression for the given verbal description is 0.3G+25F.

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The categories and their  Percentages on the circle graph would be as follows:

Cape: 25%

Garrison: 40%

Split: 35%

To represent the distribution of house types in a town containing 25,000 houses on a circle graph, we need to determine the percentage of each category.

The given data provides the following frequencies for each house style:

Cape: 6,250 houses

Garrison: 10,000 houses

Split: 8,750 houses

To calculate the percentage for each category, we divide the frequency of each house style by the total number of houses in the town (25,000) and multiply by 100.

Percentage for Cape: (6,250 / 25,000) * 100 = 25%

Percentage for Garrison: (10,000 / 25,000) * 100 = 40%

Percentage for Split: (8,750 / 25,000) * 100 = 35%

Therefore, the categories and their respective percentages on the circle graph would be as follows:

Cape: 25%

Garrison: 40%

Split: 35%

These percentages represent the proportion of each house style in the town and can be visually represented on a circle graph to provide a clear visualization of the distribution of house types.

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Answer:

\( 180 - 16 - 126 = 38\\ 13x = 180 - 16 - 38\\ 3x = 126 \\ 3x = 126 \\ x = \frac{126}{3} = 42\)

Answer:

hi

Step-by-step explanation:

1. The area formulas for a triangle and a parallelogram require multiplying base by height.

true

2 .A triangle and parallelogram with the same base and height will have the same area.

false

3. A rectangle and parallelogram with the same base and height will have the same area.

true

4. The area formula of a trapezoid requires finding the product of the bases.

false

5. The base of a triangle is always the shortest side.

false

Answer:

12

Step-by-step explanation:

Step-by-step explanation:

B. not a rational number

Step-by-step explanation:

it seems you solved the tricky part yourself already.

just to be sure, let's do the first derivative here again.

the easiest way would be for me to simply multiply the functional expression out and then do a simple derivative action ...

f(t) = (t² + 6t + 7)(3t² + 3) = 3t⁴ + 3t² + 18t³ + 18t + 21t² + 21 =

= 3t⁴ + 18t³ + 24t² + 18t + 21

f'(t) = 12t³ + 54t² + 48t + 18

and now comes the simple part (what was your problem here, don't you know how functions work ? then you are in a completely wrong class doing derivatives; for that you need to understand what functions are, and how they work). we calculate the function result of f'(2).

we simply put the input number (2) at every place of the input variable (t).

so,

f'(2) = 12×2³ + 54×2² + 48×2 + 18 = 96 + 216 + 96 + 18 =

= 426

Answer: a1= 4

Step-by-step explanation:

In the quadratic equation y = a\(x^{2}\) + c ,the value of x = ± \(\sqrt \frac{y-c}{a}\)

A quadratic equation is any equation containing one term wherein the unknown is squared and no term wherein it's far raised to a higher power.

A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax2 + bx + c = 0, in which a and b are the coefficients, x is the variable, and c is the constant term.

To find the value of x

Assuming \(a\neq o\)

First, subtract c from both the sides to get:

\(y-c=ax^{2}\)

then, divide both sides by \(a\) and transpose to get:

\(x^{2} =\frac{y-c}{a}\)

So, \(x\) must be a square root of \(\frac{y-c}{a}\)  and we can deduce:

\(x=\) ± \(\sqrt \frac{y-c}{a}\)

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Answer:

1. 7.3

2. 33.3

3. 21.3

4. 31.9

5. 25.6

6. 11.0

7. 42°

8. 64°

9. 13°

10. 51°

Step-by-step explanation:

make sure if you're using a math calculator that it is in degree mode.

SIN, COS, OR TAN. SOH CAH TOA. Sin is Opposite/hypotenus.

Cos is Adjacent(next to it)/hypotenus.

Tan is Opposite/Adjacent.

~~

PROBLEM 1:

So we have 63°, 16 as hypotenus, and x as one of the legs.

1. Figure out whether it is Sin, Cos, or Tan. (It's adj and hyp. of the angle degree (63° listed so it's cos.)

2. Once you set it up, it is Cos 63°= x/16 then flip it around. which makes it 16 COS 63= X.

3. Input it into your calculator as 16cos(63, then it will give you.. 7.263847996

4. Don't forget to round to the nearest tenth, which gives you

x = 7.3

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

PROBLEM 2:

Given: 39°, 27 is opposite of the °, and adj is x. So this is Tan.

1. Set it up, Tan 39° = 27/x can't solve this way so fix it.

2. rewritten as X = 27/tan39

3. round ur answer.

x = 33.3

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

PROBLEM 3:

Given: 49°, adj is 14, hyp is x. So this is Cos.

1. Set up according to CAH, Cos 49=(14/x).

We can't solve it this way since the X is on the bottom. So we have to fix it!

2. Turns into X Cos 49 = 14, which then turns into X= 14/cos49.

3. Put it in your calculator as 14 DIVIDED BY cos 49. ( Put image example)

4. Round.

x= 21.3

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

PROBLEM 4:

Given: 15°, 33 hyp, adj x. Which is Cos.

1. Cos 15= x/33 and rewrite.

2. Input as 33 cos(15 into calculator = 31.875...

3. Round to tenth.

x = 31.9

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

PROBLEM 5:

Given: 52°, 20 adj of °, and x opp of °. Will use TAN.

1. Tan 52° = x/20

2. 20 Tan(52 into calculator

3. Round

x = 25.6

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

PROBLEM 6:

Given: 27°, opp of ° is 5, hyp is x. Will use Sin.

1. Write out as I have the last few times, Sin 27 = 5/x rewrite cause x can't be at the bottom.

2. Input into calculator as: 5/sin 27 which equals 11.01...

3. Round.

x = 11.0

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

PROBLEM 7:

Given: x°, 6 as hyp, 4 opp. now we have to solve this different since we don't know the degree. Now when we input into the calculator you will press 2nd, then sin/cos/tan so it will be negative this is depending on which one ur solving for.

We will be using SIN, x is still a °.

1. Sin X = 4/6 Rewrite.

2. X= Sin^-1 (4/6)

Make sure ur sin is negative in calculator when doing this.

3. It SHOULD give you 41.81, round.

x = 42°

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

PROBLEM 8:

Given: x°, 29 opp, 14 adj. TAN.

1. Tan x°= 29/14 or..

2. X = Tan^-1(29/14) solve..

3. gives u 64.23.... round.

x = 64°

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

PROBLEM 9:

Given: x°, hyp 54, opp 12. SIN

1. Sin x°=(12/54)

2. X= Sin^-1(12/54) solve. (dont put x= into calculator.)

3. Don't Forget to round, answer unrounded: 12.839..

x = 13°

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

PROBLEM 10:

Given: x°, adj 25, hyp 40. COS

1. Cos x°=25/40 rewrite.

2. X= Cos^-1(25/40) Solve.

3. Round.

X= 51°