Identify the measure of angle x please show work Bc I have too !!

The appropriate set operators (∩, ∪, -, ') when expressing these sets in terms of A and B.

Remember to use the appropriate set operators (∩, ∪, -, ') when expressing these sets in terms of A and B.

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The poll  indicates that 95% of the respondents support raising fees to increase funding for student organizations. However, further analysis reveals that a significant portion of the votes, 3200 out of 5000, were cast from a single off-campus computer owned by a member of the student organization that conducted the poll.

The poll initially suggests strong support for raising fees based on the reported 95% in favor. However, the credibility of the results is compromised by the fact that a substantial number of votes, 3200 out of 5000, were cast from a single off-campus computer associated with a member of the student organization responsible for the poll. This raises concerns about the objectivity and integrity of the voting process. The concentration of votes from a single source suggests a potential bias or manipulation, calling into question the representativeness of the poll's findings. Therefore, while the reported result shows a majority in favor of raising fees, it is essential to interpret it with caution due to the significant influence of a single source on the outcome.

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Answer:

3.24x10^-5,    5.48x10^-2,    1.2x10^1,      4.68x10^6,         8.34x10^6

Step-by-step explanation:

3.24 x 10^-5 = 0.0000324

5.48 x 10^-2 = 0.0548

1.2 x 10^1 = 12

4.68 x 10^6 = 4680000

8.34 x 10^6 = 8340000

a) The height of the frisbee each second it is in the air are 5, 29, 45, 53, 53, 45, 29, 5, -27 and -67.

b) The frisbee is in the air for a total of 8 seconds.

To find the height of the frisbee each second it is in the air, we need to substitute different values of t into the equation \(h = -16t^2 + 40t + 5\) and calculate the corresponding height.

a) Let's substitute t = 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9 into the equation:

When t = 0: \(h = -16(0)^2 + 40(0) + 5 = 5\)

When t = 1: \(h = -16(1)^2 + 40(1) + 5 = 29\)

When t = 2: \(h = -16(2)^2 + 40(2) + 5 = 45\)

When t = 3: \(h = -16(3)^2 + 40(3) + 5 = 53\)

When t = 4: \(h = -16(4)^2 + 40(4) + 5 = 53\)

When t = 5: h = \(-16(5)^2 + 40(5) + 5 = 45\)

When t = 6: h = \(-16(6)^2 + 40(6) + 5 = 29\)

When t = 7: h = \(-16(7)^2 + 40(7) + 5 = 5\)

When t = 8: h = \(-16(8)^2 + 40(8) + 5 = -27\)

When t = 9: h =\(-16(9)^2 + 40(9) + 5 = -67\)

b) The frisbee is in the air as long as its height is greater than 0. From the calculations above, we can see that the frisbee is in the air from t = 0 to t = 7, inclusive.

Note: The table you provided shows the height of the frisbee at each second it is in the air, but it seems to be cut off. However, based on the calculations above, the height values at each second should be as follows:

0 seconds: 5 feet

1 second: 29 feet

2 seconds: 45 feet

3 seconds: 53 feet

4 seconds: 53 feet

5 seconds: 45 feet

6 seconds: 29 feet

7 seconds: 5 feet

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The system of equations to the inverse of its coefficient matrix, A⁻¹, and the matrix of its solution, X is shown in the figure.

Given that the system of equations are shown in given figure.

The first system of equations are

\(\begin{aligned}4x+2y-z&=150\\x+y-z&=-100\\-3x-y+z&=600\\\end\)

By writing in matrix AX=b, we get

Coefficient matrix \(A=\left[\begin{array}{lll}4&2&-1\\1&1&-1\\-3&-1&1\end{array}\right]\) and \(B=\left[\begin{array}{l}150&-100&600\end{array}\right]\)

Firstly, we will find the A⁻¹ by finding the determinant and adjoint of A and divide the adjoint with determinant, we get

\(\begin{aligned}|A|&=\left|\begin{array}{lll}4&2&-1\\1&1&-1\\-3&-1&1\end{array}\right|\\ &=4(1-1)-2(1-3)-1(-1+3)\\&=4(0)-2(-2)-1(2)\\ &=2\neq 0\end\)

\(\begin{aligned}Adj A&=\left[\begin{array}{lll}0&2&2\\-1&1&-2\\-2&3&2\end{array}\right]^T\\&=\left[\begin{array}{lll}0&-1&-2\\2&1&3\\2&-2&2\end{array}\right]\end\)

\(\begin{aligned}A^{-1}&=\frac{Adj A}{|A|}\\ &=\left[\begin{array}{lll}0&-0.5&-0.5\\1&0.5&1.5\\1&-1&1\end{array}\right]\end\)

For a solution Consider [A B] and apply row operations, we get

\(\begin{aligned}\left[A\right.\text{ }\left.B\right]&=\left[\begin{array}{lll1}4&2&-1&150\\1&1&-1&-100\\-3&-1&1&600\end{array}\right]\\ R_{2}&\rightarrow 4R_{2}-R_{1},R_{3}\rightarrow 4R_{3}+3R_{1}\\ &\sim \left[\begin{array}{lll1}4&2&-1&150\\0&2&-3&-550\\0&2&1&2850\end{array}\right]\\ R_{3}&\rightarrow R_{3}-R_{2}\\ &\sim \left[\begin{array}{llll}4&2&-1&150\\0&2&-3&-550\\0&0&4&3400\end{array}\right]\end\)

Thus, \(x=\left[\begin{array}{l}x\\y\\z\end{array}\right]=\left[\begin{array}{l}-250\\1000\\850\end{array}\right]\)

The second system of equations are

\(\begin{aligned}x+y-z&=220\\5x-5y-z&=-640\\-x+y+z&=200\\\end\)

Similarly, we will find for second system of equations

\(\begin{aligned}|A|&=\left|\begin{array}{lll}1&1&-1\\5&-5&-1\\-1&1&1\end{array}\right|\\ &=1(-5+1)-1(5-1)-1(5-5)\\&=1(-4)-1(4)-1(0)\\ &=-8\neq 0\end\)

\(\begin{aligned}Adj A&=\left[\begin{array}{lll}-4&-4&0\\-2&0&-2\\-6&-4&-10\end{array}\right]^T\\&=\left[\begin{array}{lll}-4&-2&-6\\-4&0&-4\\0&-2&-10\end{array}\right]\end\)

\(\begin{aligned}A^{-1}&=\frac{Adj A}{|A|}\\ &=\left[\begin{array}{lll}0.5&0.25&0.75\\0.5&0&0.5\\0&0.25&1.25\end{array}\right]\end\)

\(\begin{aligned}\left[A\right.\text{ }\left.B\right]&=\left[\begin{array}{llll}1&1&-1&220\\5&-5&-1&-640\\-1&1&1&200\end{array}\right]\\ R_{2}&\rightarrow R_{2}-5R_{1},R_{3}\rightarrow R_{3}+R_{1}\\ &\sim \left[\begin{array}{llll}1&1&-1&220\\0&-10&4&-1740\\0&2&0&420\end{array}\right]\\ R_{3}&\rightarrow 5R_{3}+R_{2}\\ &\sim \left[\begin{array}{llll}1&1&-1&220\\0&-10&4&-1740\\0&0&4&360\end{array}\right]\end\)

Thus, \(x=\left[\begin{array}{l}x\\y\\z\end{array}\right]=\left[\begin{array}{l}100\\210\\90\end{array}\right]\)

The third system of equations are

\(\begin{aligned}2x+2y-z&=290\\x+y-3z&=500\\x-y+2z&=600\\\end\)

Similarly, we will find for third system of equations

\(\begin{aligned}|A|&=\left|\begin{array}{lll}2&2&-1\\1&1&-3\\1&-1&2\end{array}\right|\\ &=2(2-3)-2(2+3)-1(-1-1)\\&=2(-1)-2(5)-1(-2)\\ &=-10\neq 0\end\)

\(\begin{aligned}Adj A&=\left[\begin{array}{lll}-1&-5&-2\\-3&5&4\\-5&5&0\end{array}\right]^T\\&=\left[\begin{array}{lll}-1&-3&-5\\-5&5&5\\-2&4&0\end{array}\right]\end\)

\(\begin{aligned}A^{-1}&=\frac{Adj A}{|A|}\\ &=\left[\begin{array}{lll}0.1&0.3&0.5\\0.5&-0.5&-0.5\\0.2&-0.4&0\end{array}\right]\end\)

get

\(\begin{aligned}\left[A\right.\text{ }\left.B\right]&=\left[\begin{array}{llll}2&2&-1&290\\1&1&-3&500\\1&-1&2&600\end{array}\right]\\ R_{2}&\rightarrow 2R_{2}-R_{1},R_{3}\rightarrow 2R_{3}-R_{1}\\ &\sim \left[\begin{array}{llll}2&2&-1&290\\&0&-5&710\\0&-4&5&910\end{array}\right]\end\)

Thus, \(x=\left[\begin{array}{l}x\\y\\z\end{array}\right]=\left[\begin{array}{l}479\\-405\\-142\end{array}\right]\)

Hence, each system of equations to the inverse of its coefficient matrix, A⁻¹, and the matrix of its solution, X.

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The statement is false because the element 2 does not meet the criteria of being an integer greater than 13.

To determine if {2} is an element of the set of integers greater than 13, we need to analyze the statement.

The set of integers greater than 13 can be represented as {x | x ∈ ℤ, x > 13}. This set contains all integers that are greater than 13.

Now, let's check if the element 2 is in this set. Since 2 is not greater than 13, it does not satisfy the condition x > 13. Therefore, {2} is not an element of the set of integers greater than 13.

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Answer:

you change the percent into a decimal and multiply because of means multiply

Step-by-step explanation:

lets say you finding 85% of 4

.85 x 4

Answer: Radius Would be 5

Step-by-step explanation:

Use formula d=2r

Solving for radius

r = d/2 = 10/2 = 5

Answer:

\(\frac{-7}{10}\ or \ 0.7\)

Step-by-step explanation:

step 1.

\(\frac{1}{3} (\frac{-6}{4}-\frac{1}{2}(\frac{6}{5}))\)

step 2.

put it in a calculator

step 3

=\(\frac{-7}{10}\ or \ 0.7\)

Answer:

the answer is A that's the answer

Answer:

atq= let no.be x and y

x= 4y-3.......(1)

x-2y=7....(2)

subtracting both eqn

x-x+2y=4y-3-7

2y=4y-10

-2y= -10

y=5 ........second no.

first no...x=7+2y=7+10=17.......first no.

Step-by-step explanation:

Answer:

To convert from slope intercept form y = mx + b to standard form Ax + By + C = 0, let m = A/B, collect all terms on the left side of the equation and multiply by the denominator B to get rid of the fraction.

explanation:

pls make me brainliest

Answer:17

Step-by-step explanation:

Answer: B, 2 1/2

Step-by-step explanation:

When dividing fractions, we can use the Keep, Change, Flip Method.

1. Keep the first fraction

2. Change the sign from division to multiplication

3. Flip the last fraction so that the numerator becomes the denominator and vice versa

Our equation:

\(\frac{2}{3}\) ÷ \(\frac{4}{15}\)

Let's use the method we just learned and apply it to this equation.

1. Keep 2/3

2. Change the sign

3. Flip 4/15 to 15/4

Our new equation:

\(\frac{2}{3} * \frac{15}{4}\)

Now let's solve by just multiplying straight across.

15*2=30

3*4=12

\(\frac{30}{12}\)

Now, we can simplify. 12 fits two times in 30, so 2 is our whole number. After taking out 12 twice (24), we have 6 remaining (30-24=6). Our expression is 2 6/12. 6/12 can be simplified to 1/2 (divide both sides by 6).

Our final expression:

\(2\frac{1}{2}\)

hope this helps!

Divide 2/3 by 4/15 by multiplying 2/3 by the reciprocal of 4/15.

Multiply 2/3 by 15/4 (to do this, multiply the numerator by the numerator and the denominator by the denominator).

Do the multiplications on the fraction.

We reduce the fraction 30/12 to its lowest expression by extracting and canceling 6.

Therefore, the correct option is alternative "B".

Answer: linear

Step-by-step explanation: cus when u connect the points it forms a straight line

The another endpoint of a line is (13, -3).

What is Straight line?

A line with no curve is called a straight line.

Given that;

One endpoint of a line = (-3, 7)

Midpoint of a line = (5, 2).

Now, Let the other endpoint of a line = (x, y)

Then, Other endpoint is solve by the definition of midpoint of two points as;

(x + (-3) / 2 , y + 7 / 2 ) = (5, 2)

(x - 3 / 2 , y + 7 / 2) = (5, 2)

By compare we get;

x - 3/ 2 = 5

x - 3 = 2 * 5

x - 3 = 10

x = 10 + 3

x = 13

And,  

y + 7 / 2 = 2

y + 7 = 2 * 2

y + 7 = 4

y = 4 - 7

y = -3

Hence, The another endpoint of a line is (13, -3).

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Answer:

should be 3,672

Step-by-step explanation:

just multiply them and you get the partial number please give brainliest!!

Eighty-six thousand and one hundred sixty-three thousandths can be written as a decimal number as 86.163.

To write eighty-six thousand and one hundred sixty-three thousandths as a decimal number, we can express it as 86,163.000.

To write eighty-six thousand and one hundred sixty-three thousandths as a decimal number, we need to convert the whole number and the fraction into decimals separately.

Let's start with the whole number, which is 86,000.

To convert it into a decimal, we move the decimal point three places to the left since there are three zeros after the 86.

This gives us 86.000. Now, let's focus on the fraction, which is one hundred sixty-three thousandths.

This fraction can be written as 163/1000. To convert it into a decimal, we divide the numerator (163) by the denominator (1000). This gives us 0.163.

Finally, we add the decimal form of the whole number (86.000) and the decimal form of the fraction (0.163) together.

86.000 + 0.163 = 86.163

Therefore, eighty-six thousand and one hundred sixty-three thousandths can be written as a decimal number as 86.163.

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The equation sin\((tan^(-1)(x))\) = cos\((sin^(-1)(x/2))\) holds true when x is equal to ±√2.

The given equation is \(sin(tan^(-1)(x)) = cos(sin^(-1)(x/2)).\)

Let's simplify both sides of the equation separately:

On the left side:

\(sin(tan^(-1)(x))\)

We know that \(tan^(-1)(x)\) is the inverse tangent function, which returns an angle whose tangent is x. Let's denote this angle as θ.

\(tan^(-1)(x)\) = θ

Then, we have:

sin(θ)

By using the Pythagorean identity \(sin^2\)(θ) + \(cos^2\)(θ) = 1, we can determine the value of sin(θ) when tan(θ) = x:

tan(θ) = x

\(sin^2(θ) / cos^2(θ) = x^2 / 1\)

\(sin^2(θ) = x^2(1 + cos^2(θ))\)

\(sin(θ) = ±(x / sqrt(1 + x^2))\)

On the right side:

\(cos(sin^(-1)(x/2))\)

We know that \(sin^(-1)(x/2)\) is the inverse sine function, which returns an angle whose sine is x/2. Let's denote this angle as φ.

\(sin^(-1)(x/2) = φ\)

Then, we have:

cos(φ)

Using the Pythagorean identity \(sin^2\)(φ) + \(cos^2\)(φ) = 1, we can determine the value of cos(φ) when sin(φ) = x/2:

sin(φ) = x/2

\(cos^2\)(φ) = 1 -\((x^2 / 4)\)

cos(φ) = ±sqrt(1 -\((x^2 / 4))\)

Comparing the expressions for sin(θ) and cos(φ), we can see that:

±(x / sqrt\((1 + x^2))\) = ±sqrt(1 - \((x^2 / 4))\)

To simplify further, we can square both sides of the equation:

\((x^2 / (1 + x^2)) = 1 - (x^2 / 4)\)

Multiplying both sides by \((1 + x^2)\) and 4, we get:

\(4x^2 = (1 + x^2)(4 - x^2)\)

Expanding the right side, we have:

\(4x^2 = 4 - x^4 + 4x^2 - x^2\)

Simplifying, we obtain:

\(0 = -x^4 + 4\)

Rearranging the equation, we get:

\(x^4 = 4\)

Taking the fourth root of both sides, we find:

x = ±√2

Therefore, the equation sin\((tan^(-1)(x))\) = cos\((sin^(-1)(x/2))\)holds true when x is equal to ±√2.

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sin(tan^−1x)= cos(sin^−1(x​/2)). Simplify the equations.

Answer:

nine times the difference of a number cubed and three; 9(n^3-3)

The description is paired with its correct expression is

nine times the difference of a number cubed and three; 9(n³-3)

In mathematics, an expression is a phrase that has at least two numbers or variables and at least one math operation. Addition, subtraction, multiplication, or division are all examples of math operations. An expression's structure is as follows:

(Number/variable, Math Operator, Number/variable) is an expression.

We have,

7 less than the quotient of two and a number squared increased by six

7 -  (2/n²)  + 6

The Correct Expression is -7 + (2/n²)  + 6  

2. nine times the difference of a number cubed and three; 9(n³-3)

The Expression is Correct.

3. 8 more than the quotient of a number squared and four, decreased by seven; 8 + (4 /n²) - 7

The Correct Expression is 8 + (n²/4) - 7.

4. twice the difference of a number cubed and eight;  2 n³- 8

The correct expression is 2( n³- 8)

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The exchange rate from US dollars to Myanma Kyat is given as:

1 : (45.85 × 1.507) × (0.0928) (Option C).

The rate at which one currency is converted to another is what is referred to as Exchange Rate.

Recall that the following is given from the question:

Step One - Convert from USD to BDT

This gives us 1 : (45.85 × 1.507); Hence, the rate from BDT to MMK is 1 : 0.0928

Step Two: - Ascertain the current rate for USD to MMK

This gives us - 1 : (45.85 × 1.507) × (0.0928). To get a simplified version. One would have to open the brackets.

However, from the above, it is clear that the correct answer is Option C.

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Part A

Given info:

Because n > 30 is not true, and we don't know the population standard deviation (sigma), this means we must use a T distribution.

The degrees of freedom here are n-1 = 23-1 = 22.

At 90% confidence and the degrees of freedom mentioned, the t critical value is roughly t = 1.717

Use a T distribution table or calculator to determine this. If you don't have a calculator for the task, then you can search out "inverse T calculator" and there are tons of free options to pick from.

The margin of error E is

E = t*s/sqrt(n)

E = 1.717*1.12/sqrt(23)

E = 0.400982

This is approximate and accurate to 6 decimal places.

The confidence interval is going to be xbar plus or minus that E value

L = lower bound = xbar - E = 4.90 - 0.400982 = 4.499018 = 4.50

U = upper bound = xbar + E = 4.90 + 0.400982 = 5.300982 = 5.30

The confidence interval in the format of (L, U) is (4.50, 5.30)

You could also express it as the format L < mu < U and it would be 4.50 < mu < 5.30; however, I'll stick to the first method.

=====================================================

Part B

Since we know sigma = 2.6 is the population standard deviation, we can use a Z distribution now.

At 90% confidence, the z critical value is roughly 1.645; use a table or calculator to determine this.

\(n = \left(\frac{z*\sigma}{E}\right)^2\\\\n \approx \left(\frac{1.645*2.6}{0.03}\right)^2\\\\n \approx 20325.254444 \\\\\)

Round this up to the nearest integer to get 20326. For min sample size problems, always round up.

Answer:

1) Weed-Hand (the 3rd option)

2) y=63x (the 2nd chose option)

3) $1,512.00 ( the 1st option)

Step-by-step explanation:

i just did it on Edg. i hope this was helpful

Answer:

1) Weed-Hand (the 3rd option)

2) y=63x (the 2nd chose option)

3) $1,512.00 ( the 1st option)

Step-by-step explanation:

Answer:k=-7/6x+6

Step-by-step explanation: \(6kx+18-12kx=25+6k\) We use the distributive property first. Then combine like terms. -6xk+18-6k=25

factor it out (-6x-6)k=7 and divided (-6x-6) on both side.

Then our final answer is k=-7/6x+6

Answer: Figure (i)

Step-by-step explanation:

The two angles shown are corresponding angles which means they have the same angle measure above and below.

The angles 132 and 48 add together to equal 180 degrees which is a straight line at that point.

If the angles' sum equals 180 degrees, then they are parallel.

Answer:

figure 1

Step-by-step explanation:

the sum of  given angles= 132°+148°=180°

Explanation:

Let's say 5 people get a lunch platter. The cost would be 7*5 = 35 dollars.

Or if 3 people got the lunch platter, then it would be 7*3 = 21 dollars

In general, the cost is 7p dollars where p is a placeholder for a whole number. So that's how we end up with c = 7p

If it is one platter per person, the following will be true,

Answer:

c = 7p

Step-by-step explanation:

    This is because every time someone buys a platter, it adds $7 to the total cost

-> If two people buy a platter, it is 7 + 7, aka 7 *2

-> If three, it is 7 + 7 + 7 aka 7 * 3

    Using this pattern, we can see that the total cost will be 7 times the number of people there.

We can put this into an equation by doing:

c = 7p

The directional derivative of the function f(x, y) = 3ex sin y at the point (0, π/3) in the direction of the vector v = <0, -5, 12> is -15/26.

To find the directional derivative of a function f(x, y) at a point (a, b) in the direction of a unit vector v = <u, v>, we use the following formula:

Dv(f)(a, b) = ∇f(a, b) · v

where ∇f(a, b) is the gradient of f(x, y) at the point (a, b). The gradient is a vector that points in the direction of the steepest increase of the function and has a magnitude equal to the rate of change of the function in that direction.

In this problem, our function is f(x, y) = 3ex sin y, and the point is (0, π/3). The gradient of the function is:

∇f(x, y) = <∂f/∂x, ∂f/∂y> = <3ex sin y, 3ex cos y>

Evaluating the gradient at the point (0, π/3), we get:

∇f(0, π/3) = <3e0 sin (π/3), 3e0 cos (π/3)> = <0, 3/2>

Next, we need to find the unit vector in the direction of v = <0, -5, 12>. To do this, we first find the magnitude of v:

|v| = √(0² + (-5)² + 12²) = 13

Then, we divide v by its magnitude to get the unit vector:

u = v/|v| = <0, -5/13, 12/13>

Finally, we can use the formula for the directional derivative to find Dv(f)(0, π/3):

Dv(f)(0, π/3) = ∇f(0, π/3) · u = <0, 3/2> · <0, -5/13, 12/13> = -15/26

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Answer:

x-intercept: 8; the number of hours

y-intercept: 400; distance to be covered