identify the following substance​

Answer:

Soil helps anchor plants and provides them essential elements of water and nutrients. Plants prevent soil erosion and provide organic matter.

Explanation:

When an element has a cation of +2, it has lost two electrons. A solution is a choice (E).

In electrolysis, the cathode would be drawn to a positively charged ion called a cation. In order for a cation to develop, one or more electrons must be lost, usually by the action of atoms with a larger affinity for them.

Following the chemical symbol is a number indicating the number of electrons lost and consequently the charge of the ion. For example, silver (Ag) loses one electron to become Ag+ while zinc (Zn) loses two electrons to become Zn2+.

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THANK YOU SO MUCH!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer:

thank you so much!!

Explanation:

:D

Explanation:

J.J. Thomson's experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons. ... Rutherford's gold foil experiment showed that the atom is mostly empty space with a tiny, dense, positively-charged nucleus.

there u go :>

The experiment that proved atoms  positive, negative, and neutral particles is the J.J. Thomson's experiments with cathode ray tubes, which showed that all atoms contain  negatively charged s electrons, on the other hand  Rutherford's gold foil experiment showed the atom  is present in mostly empty space with a tiny, dense, positively-charged nucleus.

J J Thomson's experiment was used to determine the existence of corpuscles or electrons which says the cathode rays are charges of negative electricity which is carried by particles of matter.

He studied about electric discharge with high vacuum cathode ray tube and there were many other scientists who also have done the same experiment on the similar field.

Cathode ray is made up of of negatively-charged particles and these particles must exist as part of the atom and the mass of the particle is only ∼ 20001​ start fraction, 1, divided by, 2000, end fraction the mass of a hydrogen atom.

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Answer:

D) The electrons move around the nucleus in an electron cloud

Explanation:

i just did it on usa test prep !

Answer: 2.81%

Explanation:

If the abundance of Fe-56 is 91.75%, then the other two isotopes have a combined abundance of 100%-91.75%=8.25%.

If we let the abundance of Fe-54 be x, then the abundance of Fe-57 is 0.0825-x. Substituting this into the atomic mass formula, we get:

\(55.85=(55.93)(0.9175)+(53.94)(x)+(56.94)(0.0825-x)\\55.85=51.315775+53.94x+4.69755-56.94x\\55.85=56.0133-3x\\-0.1633=-3x\\x=\frac{-0.1633}{-3} \approx 0.0544\)

If x=0.1633/3, this means that 0.0825-x=0.0281, so Fe-57 is the rarest isotope, with an abundance of 2.81%

When you use a soap or detergent to wash, the surfactant molecules will interact with the dirt and oils to help wash them away. During this interaction, something called a micelle is formed.

A micelle is a cluster of surfactant molecules that are formed when soap or detergent molecules are mixed with water. When soap or detergent is added to water, the hydrophobic tails of the molecules (which do not mix with water) cluster together, while the hydrophilic heads (which are attracted to water) point outwards towards the water.

Micelles are formed by the hydrophobic tails of the surfactant molecules clustering together in the center, with the hydrophilic heads facing outward.

The soap or detergent's molecules' hydrophobic tails attract oils and dirt, while the hydrophilic heads attract water molecules. The hydrophobic tails of the detergent molecules encircle the dirt and oil particles, while the hydrophilic heads point outward toward the water, creating a micelle.

The micelles disperse the dirt and oil particles throughout the water so that they can be washed away.

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Answer:

A

Explanation:

i had to answer this question a few weeks ago

Answer:

Explanation

:Both b/c a chemical formula tells you how many and a sketch formula shows how they are bonded together.

Molecular formulas show how many atoms of each element one molecule of a compound contains. Note: Ionic compounds are generally crystalline solids with high melting points. Other compounds, however, have very different properties.

Atomic configuration refers to the arrangement of electrons in an atom, specifically the distribution of electrons in the various energy levels and orbitals. Every element has a unique atomic configuration that determines its chemical and physical properties.

Electron configuration is the arrangement of electrons in an atom or molecule in atomic or molecular orbitals. It describes the number of electrons in each energy level and the distribution of electrons in the sub-shells (s, p, d, f) within each energy level. The electron configuration of an atom can be represented by a set of quantum numbers or by a notation that uses the symbol of the element, followed by the number of electrons in each sub-shell.

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Answer:

0.7μM = 0.6 μM = 0.5 μM > 0.4 μM > 0.3 μM > 0.2 μM

Explanation:

An enzyme solution is saturated when all the active sites of the enzyme molecule are full.  When an enzyme solution is saturated, the reaction is occurring at the maximum rate.

From the given information, an enzyme concentration of 1.0 μM Y can convert a maximum of 0.5 μM AB to the products A and B per second means that a 1.0 M Y solution is saturated when an AB concentration of 0.5 M or greater is present.

The addition of more substrate to a solution that contains the enzyme required  for its catalysis will generally increase the rate of the reaction. However, if the enzyme is saturated with substrate, the addition of more substrate will have no effect on the rate of reaction.

Therefore the reaction rates at substrate concentrations of 0.7μM, 0.6 μM, and 0.5 μM are equal. But the reaction rate at substrate concentrations of  0.2 μM is lower than at 0.3 μM, 0.3 μM is lower than 0.4 μM and 0.4 μM is lower than 0.5 μM, 0.6 μM and 0.7 μM.

The solutions in decreasing order of reaction rate will be:

0.7μM = 0.6 μM = 0.5 μM > 0.4 μM > 0.3 μM > 0.2 μM

It is saturated when all the active sites of the enzyme molecule are full.  When an enzyme solution is saturated, the reaction is occurring at the maximum rate.

From the given information, an enzyme concentration of 1.0 μM Y can convert a maximum of 0.5 μM AB to the products A and B per second means that a 1.0 M Y solution is saturated when an AB concentration of 0.5 M or greater is present. If the enzyme is saturated with substrate, the addition of more substrate will have no effect on the rate of reaction.

Therefore, the reaction rates at substrate concentrations of 0.7μM, 0.6 μM, and 0.5 μM are equal. But the reaction rate at substrate concentrations of  0.2 μM is lower than at 0.3 μM, 0.3 μM is lower than 0.4 μM and 0.4 μM is lower than 0.5 μM, 0.6 μM and 0.7 μM.

Thus, the solutions in decreasing order of reaction rate will be:

0.7μM = 0.6 μM = 0.5 μM > 0.4 μM > 0.3 μM > 0.2 μM

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A substance's density, energy, and intermolecular bonds between particles would be affected if it had to melt from a solid into a liquid.

The solid and liquid phases are in equilibrium at the melting point.

The chemical bonding and melting point of the substance are not affected by melting because it is a physical change (process) in which the same substance is present before and after.

Since atoms in solids are arranged farther apart, their density in liquids is often lower.

Atoms and molecules move more quickly in liquids due to their increased energy.

In liquids, intermolecular bonds are weaker.

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d. Ba₃(PO₄)₂(s)+6HNO₃(aq)

Double-Replacement reactions. Happens if there is an ion exchange between two ion compounds in the reactant to form two new ion compounds in the product  

To predict whether this reaction can occur or not is one of them, the precipitation reaction. A precipitation reaction occurs if two ionic compounds which are dissolved reacted to produce one of the products of the ion compound does not dissolve. Formation of these precipitating compounds that cause reactions can occur  

Because A precipitate is formed, then compounds of CO₃²⁻ and PO₄³⁻ except for Compounds of Li +, Na +, K +, Rb +, Cs +, and NH₄ + are generally included in the insoluble compound

So the reaction :

3Ba(NO₃)₂(aq)+2H₃PO₄(aq)⇒Ba₃(PO₄)₂(s)+6HNO₃(aq)

A precipitate is formed ⇒ Ba₃(PO₄)₂

Stereochemistry of the carbon at the 17 position for 17-a-estradiol and 17-b-estradiol:

Stereochemical relationship between the two isomers:

17-a-estradiol and 17-b-estradiol are enantiomers. This means that they are mirror images of each other, and they cannot be superimposed.

A diagram of the two isomers, with the hydroxyl group at the 17 position highlighted is attached.

The 17-a-estradiol molecule is shown on the left, and the 17-b-estradiol molecule is shown on the right. The hydroxyl group at the 17 position is on the R side of the 17-a-estradiol molecule, and it is on the S side of the 17-b-estradiol molecule.

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Answer:

The EF of the compound is CH2O and the MF is C6H12O6.

Explanation:

To find the empirical formula (EF) of the compound, we need to determine the simplest whole number ratio of the atoms in the compound. We can assume we have 100 g of the compound, which means we have:

40 g of carbon

6.67 g of hydrogen

53.33 g of oxygen (since the rest of the compound is oxygen)

Next, we can convert the masses to moles:

Moles of carbon = 40 g / 12.01 g/mol = 3.33 mol

Moles of hydrogen = 6.67 g / 1.01 g/mol = 6.61 mol

Moles of oxygen = 53.33 g / 16.00 g/mol = 3.33 mol

We then divide each of the mole values by the smallest number of moles, which is 3.33, to get the simplest whole number ratio:

Carbon: 3.33 / 3.33 = 1

Hydrogen: 6.61 / 3.33 = 1.98 (rounded to 2)

Oxygen: 3.33 / 3.33 = 1

So the EF of the compound is CH2O.

To find the molecular formula (MF), we need to know the molecular mass of the EF. The empirical formula mass (EFM) of CH2O is:

EFM = (1 x 12.01 g/mol) + (2 x 1.01 g/mol) + (1 x 16.00 g/mol) = 30.03 g/mol

We can then calculate the molecular formula mass (MFM) by dividing the given molecular mass (180 g/mol) by the EFM:

MFM = 180 g/mol / 30.03 g/mol = 6

This means the MF is 6 times the EF, or C6H12O6. Therefore

In a weak acid and strong base titration, the pH at the equivalence point is affected by: the basicity of the salt anion. Hence, the final pH of the equivalence factor will be higher than 7.

At the equivalence point, the mixture of a weak acid and a strong base produces basic salt. This happens because the acid is too weak to donate the hydrogen ions to the solution, so it has an anion of a strong base. Meanwhile, the base is strong enough to accept hydrogen ions from water, so it has a cation of a weak acid. It affects the salt pH to be greater than 7 (basic salt).

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Based on the atomic structure of the given elements, the atoms in each pair having the larger atomic radii are as follows:

The atomic radius of an atom is the radius of the atom of an element.

It is measured as half the distance between the nucleus of two covalently bonded atoms of the element.

The atomic radius of an atom increases with an increase in electron shells or orbital but decreases with an increase in atomic number in atoms with the same number of electron shells.

Comparing the atomic radii of the given elements:

1. Li or Cs - Cs has the larger atomic radii because of greater atomic orbitals

2. K or Br - K has a greater atomic radius because it has a smaller atomic number with the same number of orbitals as Br.

3. Li or Fluorine - Li has a greater atomic radius because it has a smaller atomic number with the same number of orbitals as Fluorine.

4. C or Pb - Pb has the larger atomic radii because of greater atomic orbitals

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Answer:

"it can help us explain the universe" or "it can help us study how cells in the body function"

Explanation:

you choose which one you want but their still both technicly right

The balanced equation is:

(a) 2Mn^2+ + 2H2O2 + 4OH^- → 2MnO_2 + 4H2O.

(b)3SnO2^2- + 6OH^- + 2Bi(OH)3 → 3SnO3^2- + 2Bi + 9H2O. (c)14Cr2O7^2- + 7C2O4^2- + 22H2O → 4Cr^3+ + 14CO2 + 28H+ + 28e^-. (d)2ClO3^- + 16H^+ + 3Cl^- → 3Cl2 + 8H2O

(e)10BiO3^- + 60H^+ + 12Mn^2+ → 10Bi^3+ + 30H2O + 12MnO4^-

a. In the balanced redox equation Mn^2+ + H_2O_2 → MnO_2 + H_2O (in basic solution), the half-reactions are:

Reduction: Mn^2+ → MnO_2

Oxidation: H_2O_2 → H_2O

To balance the reduction half-reaction, we need to add four OH^- ions to the left side: Mn^2+ + 4OH^- → MnO_2 + 2H2O + 2e^-

To balance the oxidation half-reaction, we add four OH^- ions to the right side and water molecules to balance the oxygen atoms: H2O2 + 4OH^- → 2H2O + 2e^-

Now, multiply the reduction half-reaction by two and the oxidation half-reaction by one to equalize the electrons:

2(Mn^2+ + 4OH^- → MnO_2 + 2H2O + 2e^-)

H2O2 + 4OH^- → 2H2O + 2e^-

Finally, add the two half-reactions together and cancel out the common species: 2Mn^2+ + 2H2O2 + 4OH^- → 2MnO_2 + 4H2O

b. The balanced redox equation Bi(OH)3 + SnO2^2- → SnO3^2- + Bi (in basic solution) can be balanced by following these steps:

Reduction: SnO2^2- → SnO3^2-

Oxidation: Bi(OH)3 → Bi

To balance the reduction half-reaction, add two OH^- ions to the left side: SnO2^2- + 2OH^- → SnO3^2- + H2O + 2e^-

To balance the oxidation half-reaction, add six OH^- ions to the right side: Bi(OH)3 → Bi + 3H2O + 3e^-

Multiply the reduction half-reaction by three and the oxidation half-reaction by two to equalize the electrons:

3(SnO2^2- + 2OH^- → SnO3^2- + H2O + 2e^-)

2(Bi(OH)3 → Bi + 3H2O + 3e^-)

Combine the two half-reactions and cancel out the common species:

3SnO2^2- + 6OH^- + 2Bi(OH)3 → 3SnO3^2- + 2Bi + 9H2O

c. In the acidic solution, the balanced redox equation Cr2O7^2- + C2O4^2- → Cr^3+ + CO2 can be balanced as follows:

Reduction: Cr2O7^2- → Cr^3+

Oxidation: C2O4^2- → CO2

To balance the reduction half-reaction, add seven H2O molecules to the right side: Cr2O7^2- → 2Cr^3+ + 7H2O + 14e^-

To balance the oxidation half-reaction, add eight H^+ ions to the left side:

C2O4^2- + 2H2O → 2CO2 + 4H+ + 4e^-

Multiply the reduction half-reaction by two and the oxidation half-reaction by seven to equalize the electrons:

2(Cr2O7^2- → 2Cr^3+ + 7H2O + 14e^-)

7(C2O4^2- + 2H2O → 2CO2 + 4H+ + 4e^-)

Combine the two half-reactions and cancel out the common species:

14Cr2O7^2- + 7C2O4^2- + 22H2O → 4Cr^3+ + 14CO2 + 28H+ + 28e^-

d. In the acidic solution, the balanced redox equation ClO3^- + Cl^- → Cl2 + ClO2 can be balanced as follows:

Reduction: ClO3^- → ClO2

Oxidation: Cl^- → Cl2

To balance the reduction half-reaction, add two H^+ ions to the right side:

ClO3^- + 2H^+ → ClO2 + H2O + 2e^-

To balance the oxidation half-reaction, add two H2O molecules to the left side:

2Cl^- → Cl2 + 2e^-

Multiply the reduction half-reaction by two and the oxidation half-reaction by one to equalize the electrons:

2(ClO3^- + 2H^+ → ClO2 + H2O + 2e^-)

Cl^- → Cl2 + 2e^-

Combine the two half-reactions and cancel out the common species:

2ClO3^- + 16H^+ + 3Cl^- → 3Cl2 + 8H2O

e. In the acidic solution, the balanced redox equation Mn^2+ + BiO3^- → Bi^3+ + MnO4^- can be balanced as follows:

Reduction: BiO3^- → Bi^3+

Oxidation: Mn^2+ → MnO4^-

To balance the reduction half-reaction, add six H^+ ions to the left side:

BiO3^- + 6H^+ → Bi^3+ + 3H2O + 6e^-

To balance the oxidation half-reaction, add eight H^+ ions to the right side:

Mn^2+ → MnO4^- + 8H^+ + 5e^-

Multiply the reduction half-reaction by five and the oxidation half-reaction by two to equalize the electrons:

5(BiO3^- + 6H^+ → Bi^3+ + 3H2O + 6e^-)

2(Mn^2+ → MnO4^- + 8H^+ + 5e^-)

Combine the two half-reactions and cancel out the common species:

10BiO3^- + 60H^+ + 12Mn^2+ → 10Bi^3+ + 30H2O + 12MnO4^-

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Answer: This is called a chemical reaction.

Explanation: Gas may form, heat may be produced, and color may change. These types of changes indicate that a chemical reaction has occurred.

Plants use sunlight and cellular respiration to transform carbon dioxide into the hydrocarbon molecule glucose, which is then ingested by the plants.

During photosynthesis, oxygen and glucose are created from water and carbon dioxide; the plant uses the glucose and produces oxygen as a waste product.

In the process of cellular respiration, oxygen & glucose are transformed into carbon dioxide and water. Carbon dioxide, water, & ATP, which would be converted into energy, are the process' byproducts.

The main purpose of photosynthetic is to transform chemical energy into solar energy, which is then stored for future use. This mechanism primarily provides energy to the planet's life systems.

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True. Thermal energy, which is quantified as heat, is the movement of particles inside a material. Particles exchange energy in the form of heat as they travel more quickly or collide with one another.

Hence, thermal energy may be produced by the movement of particles.

The movement of particles within a material results in the production of thermal energy, often known as heat energy. Kinetic energy, which occurs when particles travel more quickly, or potential energy, which occurs when particles vibrate more quickly, might cause this movement. As particles contact, heat is transferred from one particle to the next, and this energy transfer lasts until the substance reaches thermal equilibrium. The temperature and quantity of heat energy within the material increase with particle mobility. Understanding this concept is crucial for comprehending a variety of phenomena, such as heat transport, thermodynamics, and the behaviour of matter in different states.

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We are aware that a reaction's time need is inversely correlated with its rate, or that as the rate of the reaction rises, the reaction's time requirement falls.

We can express the rate law for a reaction involving products of form A as follows:

Rate = k[A]^n

where k is the rate constant and n is the order of the reaction with respect to A.

Given that the initial concentration of reactant A in the first reaction is 0.100 M and the time required for the reaction is 50 s, we can write:

50 s = 1 / (k * (0.100 M)^n)

Similarly, for the second reaction with an initial concentration of 0.200 M and a time of 25 s, we can write:

25 s = 1 / (k * (0.200 M)^n)

Dividing the two equations, we get:

50 s / 25 s = (0.100 M / 0.200 M)^n

Simplifying, we get:

0.5 = 0.5^n

Taking the logarithm of both sides, we get:

log(0.5) = n * log(0.5)

Solving for n, we get:

n = 1

Therefore, the order of the reaction with respect to A is 1.

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The Old Way

If the peaks matched those of known impurities, they could use the intensities to calculate the purity of the ester.

IR-spectroscopy is perhaps the most frequently used technique in the organic chemistry labs at PSU. It is routinely used to identify products and to verify that an experiment has succeeded.

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Answer:

They are positively charged

Explanation:

Hope it will help you

Protons are the sub-atomic particles present within the nucleus of the atom. The protons determine the atomic number and carry a positive charge. Thus, options c and d are correct.

Protons have been discovered as the smallest unit or particle of the atom. They are present in the nucleus of the atom situated in the middle along with the neutrons. The protons alone are the characteristics to determine the atomic number and property of the element in the periodic table.

The protons have also been discovered to have a positive charge (+1) on them that binds the atom and electron by the attractive forces. They are heavier than the other particles and are the determinant of the chemical element.

Therefore, options c and d. protons are equivalent to atomic numbers and carry a positive charge is correct.

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From the image, the numbers represent the following:

238 - Mass number

92 - Atomic number

The number of elements from the image are
Nitrogen - 2

Hydrogen - 8

Hydrogen - 1

Phosphorous - 1

Oxygen - 4

In the first diagram, we are given the element, Uranium. For this element, the number, 238 stands for mass number while the number 92 stands for an atomic number.

The mass number is the sum of the protons and neutrons in the element. So, we can obtain the number of neutrons by subtracting the atomic number from the mass number.

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Answer:

The answer is "Option B"

Explanation:

Law:

In the law of the conservation of matter, states the volume of matter throughout the process remains constant. In any particular case, it is closed to the movement of matter.  It is mostly on conservation of energy means, that the total mass of the products should consider the sum of the mass, which is the reactant of the event of chemical processes.

Reaction:

\(2AgClO_3+ Na_2CO_3= Ag_2CO_3+Na_2ClO_3\)

In the above equation when we react to \(2AgClO_3\) from the \(Na_2CO_3\), it will give \(Ag_2CO_3 \ \ \text{and} \ \ Na_2ClO_3\). that's why option b is correct.

Answer:

Ag2CO3

Explanation:

The balanced chemical equation for this reaction is 6CO2+6H2O+Δ→C6H12O6+6O2 that the reaction is balanced with respect to mass and charge .

A chemical is any substance that has a defined composition. In other words, a chemical is always made up of the same "stuff." Some chemicals occur in nature, such as water. Other chemicals are manufactured, such as chlorine (used for bleaching fabrics or in swimming pools).

Air, water, iron, gasoline, clothing, stones, furniture, plastics, plants, food are all composed of chemicals, some natural, some synthetic. Chemicals can be single chemical molecules, like water, or mixtures of different chemicals. Air is a mixture nitrogen, oxygen, water, carbon dioxide + other chemicals.

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The empirical formula of a compound shows the simplest whole-number ratio of the atoms present in the compound. To determine the empirical formula, we need to find the ratio of the moles of carbon, hydrogen, and oxygen in the compound. From the balanced equation for the combustion of the organic compound, we know that one mole of the compound produces one mole of CO₂ and one mole of H₂O

Given:
Mass of CO₂ obtained = 1.312 g
Mass of H₂O obtained = 0.805 g

To find the moles of CO₂ and H₂O, we need to divide their masses by their respective molar masses. The molar mass of CO₂ is 44.01 g/mol, and the molar mass of H₂O is 18.02 g/mol.

Moles of CO₂ = 1.312 g / 44.01 g/mol
Moles of H₂O = 0.805 g / 18.02 g/mol

Simplifying these calculations, we find:
Moles of CO₂ = 0.0298 mol
Moles of H₂O = 0.0447 mol

Therefore, the empirical formula of the compound is C₂H₆O₅.

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