Cl(aq) can reduce Br(1) to Br-(aq) but cannot reduce 1(s) to I-(aq). Therefore, Cl(aq) is the substance that can reduce Br(1) to Br-(aq) but cannot reduce I(s) to I-(aq).
An oxidation-reduction reaction, also known as a redox reaction, is a type of chemical reaction in which one or more electrons are transferred from one molecule or atom to another. Oxidation is a process in which an atom or molecule loses one or more electrons, whereas reduction is a process in which an atom or molecule gains one or more electrons.In the given options, Cl(aq) is the substance that can reduce Br(1) to Br-(aq) but cannot reduce I(s) to I-(aq). Chlorine gas (Cl2) is commonly utilized to treat water supplies to eliminate bacteria and other contaminants.
It is a powerful oxidizing agent that can react with water to form hypochlorite ions (ClO-), chlorite ions (ClO2-), chlorate ions (ClO3-), and perchlorate ions (ClO4-) depending on the conditions. Chlorine gas can easily oxidize Br- to Br2, which is a powerful oxidant in its own right, in the presence of water. However, it is unable to oxidize I- to I2, which is why Cl(aq) can reduce Br(1) to Br-(aq) but cannot reduce I(s) to I-(aq).
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Question 11
A material whose particle composition allows heat and electricity to pass through it easily are described as having a high
OA) conductivity
O B) density
OC) hardness
OD) weight
Answer:
Coductivity
Explanation:
Because heat conducts to them!
21. What type of cells are found on the retina and provide signals to the brain about incoming light?
A photoreceivers
B optic cells
C photoreceptors
D retina cells
Answer:
Explanation:
have a good day
Which forces can be represented in a free body diagram
Hydrochloric acid (HCI) and acetic acid (HC, H2O2) are both acids.
HCl completely dissociates in water, while HC2H2O2 does not.
Which statement best describes these two acids?
O HCl is a strong acid, HC2H2O2 is a weak acid.
O HCl is a weak acid, HC2H3O2 is a weak acid.
O HCl is a strong acid, HC2H2O2 is a strong acid.
O HCl is a weak acid, HC2H2O2 is a strong acid.
Answer:
I think that A or C is the correct answer
Answer:
HCl is a strong acid, HC2H2O2 is a weak acid.
Explanation:
strong acid: completely dissociates in water
weak acid: partially dissociates in water
Pls help!
Is volume equal to mass over density?
density = mass/volume
volume= mass/density
Yes, you're correct.
Answer:
Volume isn't equal to mass.
Explanation: Mass is weight, volume is like how much something can hold.
The lewis representation above depicts a reaction between hydrogen (blue) and a main-group element from group (red). in this representation, each y atom needs 1 electron(s) to complete its octet, and gains these electrons by forming 1 bond(s) with atoms of h . there are 1 unshared electron pair(s) and 1 bonding electron pair(s) in the product molecule. the bonds in the product are .
The question is incomplete, the complete question is;
The Lewis representation above depicts a reaction between hydrogen (blue) and a main-group element from group______ (red).
In this representation, each Y atom needs ______ electron(s) to complete its octet, and gains these electrons by forming______ bond(s) with atoms of H .
There are ______ unshared electron pair(s) and _______bonding electron pair(s) in the product molecule.
The bonds in the product are _________ (Ionic or Covalent)
Answer:
1) 16
2) 2 electrons
3) 2 bonds
4) 2 unshared pairs of electrons
5) 2 bonding pairs of electrons
6) The bonds in the product are covalent
Explanation:
Group sixteen elements have six electrons on their outermost shell. These include two unshared pairs of electrons and two unpaired electrons. These two unpaired electrons can now be covalently bonded to two hydrogen atoms to give H2Y. The compound H2Y has two lone pairs and two bond pairs of electrons.
H2Y can be a general formula for all hydrides of group 16. They are all very similar in structure but gradually differ in physical and chemical properties according to the graduated variation observed down the group.
The molecule has been \(\rm H_2Y\), where the two bonds have been formed for the sharing of 2 electrons pair between the H and Y atom.
The Lewis representation above depicts a reaction between hydrogen (blue) and a main-group element from group ______ (red).
The main group element that has the ability to form \(\rm H_2Y\) type of structure has been Group 16.
In this representation, each Y atom needs ______ electron(s) to complete its octet, and gains these electrons by forming______ bond(s) with atoms of H .The atom required 2 electrons to complete its octet, and in order to gain two electrons, the atom form 2 bonds with the H, resulting in \(\rm H_2Y\).
There are ______ unshared electron pair(s) and _______ bonding electron pair(s) in the product molecule.The atom forms bond with the two H atoms, thus there has been the presence of two unshared electrons pair. The bonding electrons pair are also two in the molecule.
The bonds in the product are _________ (Ionic or Covalent)The bond has been formed with the sharing of the electron pair. Thus it has been a covalent bond.
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How is the number of shells in an atom related to the position of the element on the periodic table?
Answer:
The number of shells are called period ,so in the periodic table there are places under a column written periods in bib charts
The main purpose of cell division is
A.
to absorb nutrients.
B.
to remove cellular waste.
C.
to produce cellular energy.
D.
to produce more cells.
Explain the relationship between atomic mass and atomic number in your own words
Answer:
Explanation:The atomic number is just a part of the atomic mass the atomic number is like the number of protons in the nucleus of an atom while the atomic mass is the sum of the number of protons and the number of neutrons within the nucleus.
what wouldn't be a redox reaction?
Answer:
Explanation:
Combination of oxidation and reduction reactions.
Where there is oxidation, there is reduction too.
Which of the following elements will most likely not form an ion at all?
Br
Na
O
Ar
Mg
Answer:
О
because it has the fewest number of electrons
a student dissolves of resveratrol in of a solvent with a density of . the student notices that the volume of the solvent does not change when the resveratrol dissolves in it. calculate the molarity and
The molarity when a student dissolves of resveratrol in of a solvent with a density of . the student notices that the volume of the solvent does not change when the resveratrol dissolves in it is 0.185 M and 0.3645 g
As we know the formula of Resveratrol
C14H12O3
We know the molar mass is 228 g/mol
Mole of resveratol is 19/228=0.083 g
So, the molarity of the Solution is 0.083/0.45=0.185 L
Now as we know molality mole of the solute mass of solvent
volume of solvent = 450 ml
Molality is the mass of solute upon the mass of solvent
M=0.81X450=0.3645 kg
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First period in the periodic table has ____ elements and they are called____
We need ti find how many elements there are in the first period and what are these.
To know what is the first period we must use that
Seeing the periodic table, the first row has two elements.
We can see that these elements are H ( hydrogen ) and He ( helium ).
ANSWER:
Firs period in the periodic table has two elements and they are called hydrogen and helium.
what is the bond order for al2
Answer:
The bond order is 1.091
Explanation:
there really is no explanation.
- Which equation represents the radioactive decay
of 226Ra?
(1) Ra→ 86
226Ra89
(2)
(3) 88
226
(4) Ra→Ra+n
88
88
226 Ra
.
222Rn+He
226 Act
226 Fr+
87
0
ve
0
the
The correct equation representing the radioactive decay of 226Ra is (2) 226Ra → 222Rn + 4He.
This equation correctly represents the radioactive decay process of 226Ra (Radium-226) into 222Rn (Radon-222) and 4He (Helium-4).
In radioactive decay, unstable isotopes undergo a spontaneous process to transform into more stable forms by emitting particles or radiation. In the case of 226Ra, it decays by a process called alpha decay. Alpha decay involves the emission of an alpha particle, which consists of two protons and two neutrons (equivalent to a helium nucleus).
The equation (2) shows that 226Ra undergoes alpha decay, resulting in the formation of 222Rn and the release of an alpha particle (4He). The atomic number and mass number must be conserved in the decay process. Therefore, 226 (atomic number 88) on the left side of the equation decays to 222 (atomic number 86) on the right side, while the mass number also decreases by 4 units.
It's important to note that equation (1) represents an incorrect notation, as it suggests that 226Ra undergoes a transformation to 226Ra89, which is not possible as it implies an increase in atomic number. Equation (3) does not accurately represent the decay of 226Ra. Equation (4) is incorrect as it represents the formation of an isotope that doesn't exist.
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waste water treatment often has at least one oxidation-reduction step. in the collection of waste water, chlorine can be added to control corrosion by hydrogen sulfide to give sulfur and chloride ions. what is the balanced equation for the reaction that occurs in this step?
The balanced reaction equation for this redox reaction looks like this:
H₂S(aq) + Cl₂(g) → S(s) + 2HCl(aq)
First, we write what we know about the reaction:
Hydrogen sulfide (H₂S) that is dissolved in the wastewater (so the physical state is (aq)) is reacting with gaseous chlorine (so Cl₂(g)) to form sulfur (which is solid at room temperature, and does not dissolve in water, so S(g)) and chloride ions (Cl⁻). To counter their negative charge, we add the hydrogen from H₂S to chlorides, which results in HCl, which is soluble in water, so the physical state is (aq):
H₂S(aq) + Cl₂(g) → S(s) + HCl(aq)
When we look at this equation we can see that it is not balanced, because we have 2 H atoms and 2 Cl atoms on the left, and only 1 of both on the right. The easiest way to rectify this is to add "2" in front of HCl, resulting in a balanced reaction equation:
H₂S(aq) + Cl₂(g) → S(s) + 2HCl(aq)
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5.00 g of glucose, C6H12O6, is dissolved in 72.8 g of water. What will be the freezingpoint and the boiling point?
Answer
The freezing point o the solution = 273.714153 K
The boiling point of the solution= 373.1955328 K
Explanation
Given:
Mass of glucose = 5.00 g
Volume of water = 72.8 g
What to find:
The freezing point and the boiling point of the solution.
Step-by-step solution:
Note: (Freezing point of water = 273K, Kf for water =1.87K kg/mol, atomic weight C = 12, H = 1, O = 16).
The freezing point of the solution:
The molecular weight of glucose C6H12O6 = 6(12) + 12(1) + 6(16) = 180 g/mol
The number of moles of glucose = (Mass of glucose/Molecular weight) = 5.00 g/180.0 g/mol = 0.0278 moles
Mass of water = 72.8 g = 0.0728 kg
So molality of glucose = (Moles o glcsose/Volume of solution) = 0.0278 mol/0.0728 kg = 0.3819 mol/kg
The depression in the freezing point, ∆T = Kf x molality = 1.87 K kg/mol x 0.3819 mol/kg = 0.714153 K
Since the freezing point of water = 273 K
Therefore, the freezing point of the solution= 273 K + 0.714153 K = 273.714153K
The boiling point of the solution:
∆T = i x m x Kb
∆T = change in temperature i.e boiling point elevation
i = van't Hoff factor = 1 for glucose since it does not ionize or dissociate. It is a single particle.
m = molality = moles solut/kg solvent = 0.0278 mol/0.0728 kg = 0.3819 mol/kg
Kb = boiling poin constant = 0.512 K kg/mol
∆T = 1 x 0.3819 mol/kg x 0.512 K kg/mol
∆T = 0.1955328 K
Since the freezing point of water = 373 K
Therefore, the boiling point of the solution = 373 K + 0.1955328 K = 373.1955328 K
Predict the immediate effect of the following changes on the observed cell voltage, E.
H2(g) + PbCl2(s) <–> Pb(s) + 2HCl (aq)
Delta H standard rxn > 0
Match
a) Dissolve NaOH into solution
b) Increase the temperature
c) Increase the amount of PbCl2
d) Dilute the solution by adding H2O
i) Increased E
ii) Decreased E
iii) No change in E
Dissolve NaOH into the Solution will - Increased E
Increase the temperature - Increased E
Increase the amount of \(PbCl_{2}\) - No change in E
Dilute the solution by adding \(H_{2}O\) - Increased E
E= Voltage or the electromotive force generated in the cell
Dissolving NaOH will increase the conductivity and number of ions in the cell and Increases E . Adding water also increases the presence of hydrogen and hydroxide ions in the solution and Increases E.
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Which of the following does not represent a characteristic of pure substance?
A It has a uniform texture throughout (homogeneous).
B It has a fixed boiling point or melting point.
C It is made up of different types of particles.
D It can be an element or a compound.
The option that does not represent a characteristic of a pure substance is:
C) It is made up of different types of particles.
A pure substance is a material that consists of only one type of particle, either atoms of an element or molecules of a compound. It does not contain different types of particles. This is what distinguishes a pure substance from a mixture, which is composed of two or more different substances mixed together.
Option A states that a pure substance has a uniform texture throughout, which means it is homogeneous. This is true because pure substances have a consistent composition and properties throughout.
Option B states that a pure substance has a fixed boiling point or melting point. This is also true because pure substances have well-defined temperature ranges at which they transition between solid, liquid, and gas phases.
Option D states that a pure substance can be an element or a compound. This is true as well because pure substances can exist as either single elements or compounds consisting of two or more elements chemically bonded together.
In summary, the correct option is C, as a pure substance does not consist of different types of particles.
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Give examples of environmental concerns I will be taking into account by a mining company when it created a reclamation plan for a mine site
Answer:
The major potential environmental impacts associated with mining and associated mineral processing operations are related to erosion-prone landscapes, soil and water quality, and air quality.
Explanation:
Plants were native to the mining site and making sure the soil is healthy are the examples of environmental concerns taking into account by a mining company when it created a reclamation plan for a mine site.
What are environmental concerns?Land use may change as a result of mine exploration, construction, operation, and maintenance.
It may also have detrimental effects on the environment, such as deforestation, erosion, contamination of nearby streams and wetlands, alteration of soil profiles, increased noise levels, and dust.
Mining is a naturally invasive operation that can alter the landscape over a much wider region than the actual mining site.
Therefore, years after a mine closes, the impacts of this harm can still be felt, adding to greenhouse gas emissions, causing flora and fauna to die, and eroding the land and environment.
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What do you do to test a hypothesis
Guess
Create a spreadsheet with data
Publish a scientific paper
Design an experiment
which experimental approach can be used to analyze the metal content of soapy precipitate produced by reaction 1? dissolve the solid in a known volume of:
The experimental approach used to analyze the metal content in the precipitate of soap produced by reaction 1 was 0.1 M HCl(aq), then titrated with standard 0.1 M NaOH(aq) using an indicator.
Soap precipitate is a salt of a weak base. The addition of HCl produces free fatty acids, which can then be neutralized with NaOH. The difference between the number of moles of HCl and NaOH required to reach the endpoint gives the number of moles of RCO₂, which can then be used to calculate the mass and percent of the metal in the solid.
Complete questions:
Which experimental approach can be used to analyze the metal content of the soapy precipitate produced by Reaction 1?
M₂+(aq) + 2NaC₁₇H₃₂CO₂(aq) → 2Na+(aq) + M(C₁₇H₃₂CO₂)₂(s)
Dissolve the solid in a known volume of:
A. 0.1 M NaHCO3(aq), then titrate with standardized 0.1 M HCl(aq) using an indicator.B. 0.1 M NaOH(aq), then titrate with standardized 0.1 M HCl(aq) using an indicator.C. 0.1 M NaCl(aq), then titrate with standardized 0.1 M NaOH(aq) using an indicator.D. 0.1 M HCl(aq), then titrate with standardized 0.1 M NaOH(aq) using an indicator.The true choice is D
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Arrange the elements in each of the following groups
in increasing order of the most positive electron affinity: (a) Li, Na, K; (b) F, Cl, Br, I; (c) O, Si, P, Ca, Ba
The elements arranged in increasing order of the most positive electron affinity for each group are:
(a) Li, Na, K
(b) I, Br, Cl, F
(c) Ba, Ca, Si, P, O
(a) Li, Na, K: In this group, the electron affinity increases as we move from left to right in the periodic table. Therefore, the elements arranged in increasing order of the most positive electron affinity are Li, Na, and K.
(b) F, Cl, Br, I: In this group, the electron affinity generally increases as we move from left to right and from bottom to top in the periodic table. Therefore, the elements arranged in increasing order of the most positive electron affinity are I, Br, Cl, and F.
(c) O, Si, P, Ca, Ba: In this group, the electron affinity generally increases as we move from left to right and from top to bottom in the periodic table. Therefore, the elements arranged in increasing order of the most positive electron affinity are Ba, Ca, Si, P, and O.
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When a forest burns and all that's left is some ash,
where did most of the mass of the trees go? List the 2 molecules produced. What is the equation for combustion, starting with sugar and oxygen.
Answer:
C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + H₂O
Explanation:
When a forest burns and all that's left is some ash, most of the mass of the trees go to the atmosphere, in the form of carbon dioxide.
In a total combustion process of organic matter, the two molecules produced are carbon dioxide and water. (CO₂ and H₂O)
The equation for the combustion of glucose is:
C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + H₂O
Answer: i think C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + H₂O
Explanation:
Aluminum oxide reacts with lithium metal. What is the coefficient for lithium when the equation is balanced?
Answer:
The Coefficient is 1
Explanation:
I need help with this Asap. Best answer gets brainiest, also how is your day.
ASAP!!!!!! PLSS
This question has two parts. First, answer Part A. Then, answer Part B.
Part A
Fill in the blank question.
When as 30.98-g sample of phosphorus reacts with oxygen, a 71.00-g sample of phosphorus oxide is formed. What is the percent composition of the compound?
How many grams of phosphorus are in a 100.0g sample of the phosphorus oxide?
What percent of the phosphorus oxide is phosphorus?
What percent of the phosphorus oxide is oxygen?
Part B
Fill in the blank question.
What is the empirical formula for this phosphorus oxide compound?
Step 2:
How many moles of phosphorus?
How many moles of oxygen?
Step 3: Divide by the smallest # moles, make whole numbers.
What is the subscript for the phosphorus?
What is the subscript for oxygen?
The chemical has a percent composition of 56.35% oxygen and 43.65% phosphorus.
What is the empirical formula for a substance that contains 11.1% hydrogen and 88.9% oxygen?A substance has an oxygen content of 88.79% and a hydrogen content of 11.19%. Calculate this compound's empirical formula. Nonetheless, it's customary to employ the atom ratio with the smallest whole number. H 2 O is the compound's empirical formula as a result.
Determine the compound's overall mass:P mass of 30.98 g and O mass of 40.00 g add up to 70.98 g.
Phosphorus: \((30.98 g / 70.98 g) x 100% = 43.65%\)
\((40 g/70.98 g) x 100% = 56.35% for oxygen.\)
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Which of the following statements regarding cytoskeletal filaments is FALSE? Microtubules will rapidly disassemble in response to a drop in the ATP concentration. G-actin monomers and alpha-tubulin/beta-tubulin dimers assemble into filaments in their ATP-bound and GTP-bound forms, respectively. Microtubules are stabilized by microtubule-binding proteins, such as Tau. Actin-binding proteins allow F-actin to assemble in cells in many different ways. Hydrolysis of ATP and GTP changes the conformation of the subunits once they are incorporated into actin filaments and microtubules, respectively. Which is NOT a general function of the cellular cytoskeleton? Regulation of intracellular transport Regulation of cell motility and cellular contraction Structural support for the cell Separation of the chromosomes during mitosis Assembly of DNA into chromatin
The first statement regarding the cytoskeletal filaments is False. This is due to the fact that the microtubules disassemble in response to the GTP drop. Regulation of intracellular transport is not a function of the cellular cytoskeleton. Option A is correct.
The Cytoskeleton is a large network made up of protein fibers and other molecules. It gives the body's cells their shape and structure. The Cytoskeleton also helps to form organelles inside the cell and other substances in the cell's fluid.
In addition to the microtubules, the cell’s cytoskeleton is composed of microfilaments, intermediate filaments, and microtubules. The network of microtubules is responsible for the growth and movement of cells.
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Balance the equations by putting the necessary coefficients in the blanks. Normally we do not write 1s when balancing, but for this particular question you need to include them for full credit.
__Na3N___ Na +__ N2
___H3PO4 + __ KOH __K3PO4 + __ H2O
__ N2 +__ H2 __ NH3
__H2O2 __ O2 + __ H2O
__ Zn + __ HCl __ ZnCl2 + __H2
__ C2H6 + __ O2 __ CO2 + __H2O
__ CuCl2 + __H2S __ CuS + __HCl
Tally up all the atoms in the reactants and products. In order to maximize the amount of molecules or atoms in the substances, add coefficients as necessary on top of the symbol or formulas.
How should a coefficient equation be formatted?The variable is frequently followed by an integer that has been multiplied by the variable. It is assumed that the variables with no matching number have a coefficient of 1. In the equations 3x, for instance, this same value of a x coefficient is 3, but the value of a x2 coefficient in the statement x2 + 3 is 1.
In Class 7, how do we balance a chemical equation?Choose the components that appear in the equation the least amount of times. On the both sides of a reaction, maintain a balance of each element's atoms. Hydrogen and oxygen should always be balanced last. Last, balance the hydrogen atoms, then balance the oxygen atoms.
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A 13.9 - g piece of metal ( specific heat capacity is 0.449 /g^ C)who whose temperature is 54.2 degrees * C was added to a sample of water at 13.4 degrees * C in a constant - pressure calorimeter of negligible heat capacity . If the final temperature of the water is 15.6 °C, calculate the mass of the water in the calorimeter .
Answer:
26.2g = Mass of water in the calorimeter
Explanation:
The heat absorbed for the water is equal to the heat released for the metal. Based on the equation:
Q = m*C*ΔT
Where Q is heat, m is the mass of the sample, C is specific heat of the material and ΔT is change in temperature
Replacing we can write:
\(m_{metal}*C_{metal}*dT_{metal}=m_{water}*C_{water}*dT_{water}\)
13.9g * 0.449J/g°C * (54.2°C-15.6°C) = m(H₂O) * 4.184J/g°C * (15.6°C-13.4°C)
240.9J = m(H₂O) * 9.2J/g
26.2g = Mass of water in the calorimeter