Answer:
D
Step-by-step explanation:
We can substitute y = 2x + 1 in the second equation
2x + 1 = -7x + 8
Add 7x to both sides
9x + 1 = 8
Subtact 1 from both sides
9x = 7
x = 7/9
Substituing x in the first equation
y = 14/9 + 1
x rounds to 0.8
y rounds to 2.5
Hello people ~
Factorise: x^2 + 7x + 12
Step-by-step explanation:
x^2 + (4+3)X + 12
x^2 + 4x + 3X + 12
X (X + 4) + 3 ( X + 4)
( X + 3) (X +4)
Solving steps:
\(\sf \rightarrow x^2\:+\:7x\:+\:12\)
breakdown the following
\(\sf \rightarrow x^2\:+\:3x + 4x\:+\:12\)
break the expressions into groups
\(\sf \rightarrow \left(x^2+3x\right)+\left(4x+12\right)\)
factor the following
\(\rightarrow \sf x\left(x+3\right)+4\left(x+3\right)\)
factor the common term: (x+3)
\(\rightarrow \sf \left(x+3\right)\left(x+4\right)\)
Mrs. Figueroa made a spaghetti dinner for the cheerleaders after practice. She purchased four and three fourths pounds of beef for $3.99 per pound. How much money did she spend on the beef for the spaghetti?
$7.25
$8.87
$9.98
$18.95
The cost of four and three-fourths pounds of beef is $18.95.
Given,
Amount of beef purchased = 4 and 3/4th pounds.
Cost of beef per pound = $3.99
We need to find how much four and three-fourths pounds of beef cost.
Find the cost of 1 pound of beef.
1 pound = $3.99
We can write four and three-fourths as:
= 4 3/4
= 19/4
Find the cost of 19/4 pounds of beef.
1 pound = $3.99
Multiplying by 19/4 on both sides.
19/4 x 1 pound = 19/4 x $3.99
19/4 pounds =$18.95
Thus the cost of four and three-fourths pounds of beef is $18.95.
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PLEASE HELPPPPPPPPPPPPPP
The correct answer is: -2x > 6!
-2x > 6
-2x / -2 > 6 / -2
x > -3
pls, help asap!! The image is attached. 30 points!!!
Answer:
see below, answers underlined
Step-by-step explanation:
1. Change both fractions to decimals
1/5=0.20
1/7=0.14
The question is basically asking us to find a fraction between these 2 fractions. We can pick any number between 0.20 and 0.14.
Let's pick 0.15.
Change 0.15 back to a fraction:
0.15=3/20
Hope this helps!
*There are multiple answers for this. These include 4/25, 6/35, etc.*
Can someone please help me on this question! Thank you very much!!
Answer:
(9√3 - 3π) cm² or ≈ 6.16 cm²
Step-by-step explanation:
Refer to attached pictures
We have equilateral triangle with side of 6 cm and inscribed circle, we need to find the shaded area inside the triangle not covered by the circle.
The shaded are is the difference of areas of the triangle and circle
Area of equilateral triangle is calculated as per formula:
A= √3 /4 × a², where a is side of triangleA= √3 /4 × 6² = 9√3 cm²Area of circle is calculated as per formula:
A= πr², where r is the radius of circleLet's find the value of r:
Δ ADB is the right triangle with angles 30° and 60°
It has sides of 3 cm, 6 cm and AD= m cm
As per attached, m is the long leg and equal to a√3, so
m = 3√3also,
AD= AO+OD= AO +rWe can find AO in the same way as above using Δ AOF
AO= 2r as it is the hypotenuse and the hypotenuse is twice a short leg in the right triangle with angles 30° and 60°
So,
AD= 2r+r= 3r ⇒ r= AD/3 = 3√3/3= √3 cmNow we can get the area of circle:
A= πr²= π×√3²= 3π cm²Shaded are is:
(9√3 - 3π) cm² or ≈ 6.16 cm²
Q1: Use simple exponential smoothing with a = 0.75 to forecast the water pumps sales for February through May. Assume that the forecast for January was for 25 units. [4 marks) Month January February March April Air-condition sales 28 72 98 126
Therefore, using simple exponential smoothing with a = 0.75, the forecast for water pump sales for February through May are:- February: 26.5 units, March: 37.63 units, April: 72.66 units.
To use simple exponential smoothing with a = 0.75, we first need to calculate the forecast for January:
F1 = 25 (given)
Next, we calculate the forecast for February using the formula:
F2 = a * Y1 + (1 - a) * F1
F2 = 0.75 * 28 + 0.25 * 25
F2 = 26.5 (rounded to one decimal place)
We repeat this process for each month, using the previous month's forecast and the actual sales data for the current month. The results are as follows:
Month Actual Sales Forecast
-------------------------------------
January 28 25
February 72 26.5
March 98 37.63
April 126 72.66
- May: 101.17 units
Hi, I'd be happy to help you with your question. To use simple exponential smoothing with a smoothing constant α = 0.75 to forecast the water pump sales for February through May, given that the forecast for January was 25 units, follow these steps:
Step 1: Start with the given forecast for January, which is 25 units.
Step 2: Calculate the forecast for February using the formula:
Forecast_February = α * (Actual_January) + (1 - α) * Forecast_January
Step 3: Calculate the forecast for March using the formula:
Forecast_March = α * (Actual_February) + (1 - α) * Forecast_February
Step 4: Calculate the forecast for April using the formula:
Forecast_April = α * (Actual_March) + (1 - α) * Forecast_March
Step 5: Calculate the forecast for May using the formula:
Forecast_May = α * (Actual_April) + (1 - α) * Forecast_April
Please note that you have provided sales data for air-conditioning sales, but the question is about water pump sales. If you meant to ask about air-conditioning sales, you can use the given sales data to calculate the forecasts for February through May. If you need help with water pump sales, please provide the correct sales data for January through April, and I will gladly help you with the calculations.
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Every friday, lois orders pizza for everyone at work before she gets tied up designing advertising campaigns for the following week. she is also on the event organizing committee and planning the outfits for the upcoming christmas party at work. she ensures that she is very polite and approachable to all her colleagues.
Lois is a very dedicated and hardworking individual. Every Friday, she takes the initiative to order pizza for her colleagues at work, showing that she is considerate of their needs and wants.
On top of that, she is responsible for designing advertising campaigns for the following week, which requires a lot of creativity and attention to detail. Lois is also actively involved in the event organizing committee and is currently planning the outfits for the upcoming Christmas party, which is a crucial task.
Despite her busy schedule, Lois always ensures that she remains polite and approachable to her colleagues, demonstrating her excellent interpersonal skills. Overall, Lois is an essential member of the team who goes above and beyond to ensure that everything runs smoothly.
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Express 30 as power with base 6
Answer:
30 ÷ 6 =5 so
5 is to the power 6
if event a and event b cannot occur at the same time, then events a and b are said to be : (a) mutually exclusive
(b) statistically independent
(c) collectively exhaustive
(d) none of the above
The correct option is option a) mutually exclusive.
Mutually exclusive events are events that cannot occur simultaneously. They are also referred to as disjoint or incompatible events. In probability theory and statistics, mutually exclusive events have a probability of zero occurring together.
For example, in a coin flip, getting "heads" and getting "tails" are mutually exclusive events because a coin cannot land on both "heads" and "tails" at the same time.
Another example would be the events "rolling a six on a dice" and "rolling an even number on a dice", these events are mutually exclusive because a dice can't land on a six and an even number at the same time.
In general, mutually exclusive events have no intersection, meaning that they don't share any outcomes.
Therefore, The correct option is option a) mutually exclusive.
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Q3) Jim is scuba diving. Jim started out 25 feet below the surface. He
descended 13 feet, and rose 7 feet. Then he rested. Find his position
relative to sea level?
Plz help me
Answer:
-31 feet
Step-by-step explanation:
so, -25 is the start point.
he goes anither -13 feet, so hes at -38.
he rises 7 feet, so hes at -31 feet.
Two circles intersect at A and B. A common external tangent is tangent to the circles at T and U, as shown. Let M be the intersection of line AB and TU. If AB = 9 and BM = 3, find TU.
Two circles intersect at points A and B and have a common external tangent that is tangent to the circles at points T and U, M be the intersection of line AB and TU. If AB = 9 and BM = 3, then TU will be equal to 9.6.
In order to find the length of TU, We can use the Pythagorean theorem to find the length of TU. We know that AB = 9, and BM = 3, so the length of AM must be 6. We can then use the Pythagorean theorem to solve for TU:
TU = √(62 + 92) = √93 = 9.6.
Therefore, the length of TU is 9.6.
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In the picture I need the answers to the questions.
Answer:
a) \(\mathbf{ f(g(x))=x+2\sqrt{x} +1}\)
b) \(\mathbf{f(g(9))=16}\)
Step-by-step explanation:
We are given:
\(f(x)=(x-2)^2\\g(x)=\sqrt{x} +3\)
We need to find \(a) f(g(x))\\b) f(g(9))\)
a) First finding: \(f(g(x))\)
It can be found by putting the value of g(x) into f(x)
We are given:
\(f(x)=(x-2)^2\\Put\:x=g(x)\:i.e. \: x= \sqrt{x} +3\\f(g(x))=(\sqrt{x} +3-2)^2\\Now\: solving:\\f(g(x))=(\sqrt{x} +1)^2\\Using\:formula\:\mathbf{(a+b)^2=a^2+2ab+b^2}\\f(g(x))=(\sqrt{x})^2+2(\sqrt{x} )(1)+(1)^2\\ f(g(x))=x+2\sqrt{x} +1\)
SO, we get: \(\mathbf{ f(g(x))=x+2\sqrt{x} +1}\)
b) Now finding: \(f(g(9))\)
It can be found by putting x=9 in f(g(x))
We have:
\(f(g(x))=x+2\sqrt{x} +1\\Put\:x=9\\f(g(9))=9+2\sqrt{9}+1\\We\:know\: \sqrt{9}=3\\ f(g(9))=9+2(3)+1\\f(g(9))=9+6+1\\f(g(9))=16\)
So, we get: \(\mathbf{f(g(9))=16}\)
suppose that the length of a confidence interval is 0.06 when the sample size is 400. determine how the sample size must change to decrease the length of the confidence interval to 0.03.
The way that the sample size would have to change to decrease the length of the confidence interval is to increase from 400 to 1600.
Why should the sample size change ?The confidence interval's length is directly proportional to the sample size. The specific relationship between these two factors follows an inverse proportion that correlates to the square root of the sample size.
One could represent this correlation through a proportionality statement: the larger the sample size, the smaller the confidence interval's length becomes.
Given that L1 = 0. 06 and n1 = 400, we want to find n2 such that L 2 = 0. 03:
L1 / L2 = √(n 2 / n 1)
The values would then be:
L1 / L2 = √ ( n2 / n1 )
0.06 / 0.03 = √ ( n2 / 400)
2 = √ (n2 / 400)
2² = ( √ (n2 / 400))²
4 = n2 / 400
n2 = 4 x 400
n2 = 1600
In conclusion, the sample size needs to increase to 1, 600.
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The total weight of a shipping crate is modeled by the function c = 24b + 30, * where c is the total weight of the crate with b boxes packed inside the crate. If each crate holds a maximum of 6 boxes, then what are the domain and range of the function for this situation?
The domain of the function is 0 ≤ b ≤ 6, and the range of the function is 30 ≤ c ≤ 174.
Understanding Domain of a FunctionThe function that models the total weight of a crate with b boxes inside is given as:
c = 24b + 30
We know that each crate can hold a maximum of 6 boxes. Therefore, the number of boxes inside the crate can only take values from 0 to 6.
Domain:
The number of boxes b can take values from 0 to 6. Therefore, the domain of the function is:
0 ≤ b ≤ 6
Range:
To find the range of the function, we need to consider the maximum and minimum values that c can take when
0 ≤ b ≤ 6.
When b = 0, the crate is empty, and the total weight of the crate is:
c = 24(0) + 30 = 30.
When b = 6, the crate is full with 6 boxes, and the total weight of the crate is:
c = 24(6) + 30 = 174.
Therefore, the range of the function is:
30 ≤ c ≤ 174
We can then say the domain of the function is 0 ≤ b ≤ 6, and the range of the function is 30 ≤ c ≤ 174.
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What is the general form of the equation of the given circle with center A?
A.
x2 + y2 + 6x − 24y − 25 = 0
B.
x2 + y2 − 6x + 24y + 128 = 0
C.
x2 + y2 + 6x – 24y + 128 = 0
D.
x2 + y2 + 6x − 24y + 148 = 0
The general form of the equation of the given circle with center A is option A: \(x^2 + y^2 + 6x - 24y - 25 = 0.\)
To determine the general form of the equation of the given circle with center A, we need to complete the square for both the x and y terms.
The general form of a circle equation with center coordinates (h, k) is given by:
\((x - h)^2 + (y - k)^2 = r^2\)
In this case, the center of the circle is A, which is represented by (h, k) = (-3, 12) as given in the options.
Let's examine each option and determine which one matches the general form:
A. \(x^2 + y^2 + 6x - 24y - 25 = 0\)
Completing the square for x:\((x^2 + 6x) + (y^2 - 24y) = 25\)
\((x^2 + 6x + 9) + (y^2 - 24y) = 25 + 9\)
\((x + 3)^2 + (y - 12)^2 = 34\)
B. \(x^2 + y^2 - 6x + 24y + 128 = 0\)
Completing the square for x: \((x^2 - 6x) + (y^2 + 24y) = -128\)
\((x^2 - 6x + 9) + (y^2 + 24y) = -128 + 9\)
\((x - 3)^2 + (y + 12)^2 = -119\) (Not a valid equation for a circle since the radius squared is negative)
C. \(x^2 + y^2 + 6x - 24y + 128 = 0\)
Completing the square for x: \((x^2 + 6x) + (y^2 - 24y) = -128\)
\((x^2 + 6x + 9) + (y^2 - 24y) = -128 + 9\)
\((x + 3)^2 + (y - 12)^2 = -119\) (Not a valid equation for a circle since the radius squared is negative)
D. \(x^2 + y^2 + 6x - 24y + 148 = 0\)
Completing the square for x: (\(x^2 + 6x) + (y^2 - 24y) = -148\)
\((x^2 + 6x + 9) + (y^2 - 24y) = -148 + 9\)
(\(x + 3)^2 + (y - 12)^2 = -139\) (Not a valid equation for a circle since the radius squared is negative)
From the options given, none of the equations represent a valid circle. Therefore, none of the options (A, B, C, D) correctly represent the general form of the equation of the given circle with center A.
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On Tuesday, Mario does Taco Tuesday where tacos are 5 for $7.00. If the regular price is $2.00 what is the per taco savings on taco Tuesday ? a.$1 b.$80 cents c$1.20 d.60 cents
Answer:
d. 60 cents
Step-by-step explanation:
7 divided by 5 is 1.4
2 - 1.4 = .60
A stone pyramid in Egypt has a square base that measures 154 m on each side. The height is 91 m. What is
the volume of the pyramid?
Answer:
14014
Step-by-step explanation:
base of stone pyramid=154
height=91
b×h
154×91=4014
A certain city is experiencing a terrible city-wide fire. The city decides that it needs to put its firefighters out into the streets all across the city to ensure that the fire can be put out. The city is conveniently arranged into a 100 × 100 grid of streets. Each street intersection can be identified by two integers (a, b) where 1 ≤ a ≤ 100 and 1 ≤ b ≤ 100. The city only has 1000 firefighters, so it decides to send each firefighter to a uniformly random grid location, independent of each other (i.e., multiple firefighters can end up at the same intersection). The city wants to make sure that every 30 × 30 subgrid (corresponding to grid points (a, b) with A ≤ a ≤ A + 29 and B ≤ b ≤ B + 29 for valid A, B) gets more than 10 firefighters (subgrids can overlap). a) Use the Chernoff bound (in particular, the version presented in class) to compute the probability that a single subgrid gets at most 10 firefighters. b) Use the union bound together with the result from above to calculate an upper bound on the probability that the city fails to meet its goal.
a) The probability that a single subgrid gets at most 10 firefighters, calculated using the Chernoff bound, is given by exp(-10/3).
b) Using the union bound, the upper bound on the probability that the city fails to meet its goal is 5041 times exp(-10/3).
a) Using the Chernoff bound, we can compute the probability that a single subgrid gets at most 10 firefighters. Let X be the number of firefighters assigned to a subgrid. We want to find P(X ≤ 10). Since the firefighters are assigned uniformly and independently, each firefighter has a 1/100 probability of being assigned to any given intersection. Therefore, for a single subgrid, the number of firefighters assigned, X, follows a binomial distribution with parameters n = 1000 (total number of firefighters) and p = 1/100 (probability of a firefighter being assigned to the subgrid).
Applying the Chernoff bound, we have:
P(X ≤ 10) = P(X ≤ (1 - ε)np) ≤ exp(-ε²np/3),
where ε is a positive constant. In this case, we want to find an upper bound, so we set ε = 1.
Plugging in the values, we get:
P(X ≤ 10) ≤ exp(-(1²)(1000)(1/100)/3) = exp(-10/3).
b) Now, using the union bound, we can calculate an upper bound on the probability that the city fails to meet its goal of having more than 10 firefighters in every 30 × 30 subgrid. Since there are (100-30+1) × (100-30+1) = 71 × 71 = 5041 subgrids, the probability that any single subgrid fails to meet the goal is at most exp(-10/3).
Applying the union bound, the overall probability that the city fails to meet its goal is at most the number of subgrids multiplied by the probability that a single subgrid fails:
P(failure) ≤ 5041 × exp(-10/3).
Thus, we have obtained an upper bound on the probability that the city fails to meet its goal using the Chernoff bound and the union bound.
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Two-thirds of the members of Highland Church attended the International Dinner during their annual missions conference. When seven of the members were not able to attend, the total number of attendees was Seventy-one. How many members does Highland Church have?
The total number of members Highland Church have, 113
What is the ratio?A ratio in mathematics is a comparison of two or more numbers that shows how big one is in comparison to the other. The dividend or number being divided is referred to as the antecedent, while the divisor or number that is dividing is referred to as the consequent.
Given that,
Two-thirds of the members of Highland Church attended the International Dinner
The members were not able to attend = 7
The total number of attendees = 71
Suppose the total members of Highland Church = x
So, 2/3x = 71
⇒ x = 106.5 ≈ 106
The total number in church = attendees + non attendees
= 106 + 7
= 113
So, 113 members lives in Highland Church
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solve this simultaneous equations using the elimination method 2x +1y=10 1x+1y=4
deon runs each lap in 5 minutes. he will run at least 8 laps today. what are the possible numbers of minutes he will run today?
The number of minutes Deon will run is equal to or more than 40 minutes if he will run at least 8 laps today.
The possible number of minutes he will run can be determined using inequality.
Inequality is a relation used in mathematics that represents a non-equal comparison between two numbers or any other mathematical expression.
As he runs each lap in 5 minutes and will run at least 8 laps, therefore,
n/5 ≥ 8
Here n represents the number of minutes he will run.
Solving for n;
n ≥ 8 × 5
n ≥ 40
Therefore, the number of minutes he will run is equal to or more than 40 minutes if he will run at least 8 laps today.
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when determining the size of a fact table, estimating the number of possible values for each dimension associated with the fact table is equivalent to:
When determining the size of a fact table, estimating the number of possible values for each dimension associated with the fact table is equivalent to: determining the number of possible values for each foreign key in the fact table.
The measures, metrics, or facts of a business process are contained in a fact table in data warehousing. In a star or snowflake schema, it sits in the middle, surrounded by dimension tables.
When several fact tables are employed, they are organized according to a fact constellation schema. The two types of columns that make up a fact table are typically those that hold facts and those that serve as a foreign key to dimension tables.
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HELPPPPP PLEASE NOW
Is the graph below a function? If it is a function what is the domain and range of the graph below
Answer:
yes it is a function
domain: all real numbers
range: all real numbers
how to write as one fraction 7/2a+4/a*a
The fraction 7/2a+4/a*a can be written as (7 + 8a) / 2a
What is a fraction?
In general, any number of equal pieces is represented by a fraction, which is a portion of the entire. A fraction, such as one-half, eight-fifths, or three-quarters, indicates how many pieces of a particular size there are in spoken common English. In other words, a fraction indicates the components of a whole or group of items.
Solution Explained:
First, we simplify the equation
= \(\frac{7}{2a} + \frac{4}{a} X a\)
= \(\frac{7}{2a} + 4\)
= \(\frac{7 + 8a}{2a}\)
Therefore, the equation can be written as (7 + 8a) / 2a
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there are 68% of students drive to school in one university. here is a sample of 20 students. (1) what is the probability that only 12 students drive to school? (2) what is the probability that more than 15 students drive to school? (3) what is the probability that no more than 10 students drive to school? (4) what is the mean and standard deviation? (5) what is the percentage falling with 1 standard deviation? does it satisfy the empirical rule?
1. The probability that exactly 12 students drive to school is 0.169.
2.The probability that more than 15 students drive to school is 0.027.
3. The probability that no more than 10 students drive to school is 0.004.
4. The mean and standard deviation of the sample are 13.6 and 2.4, respectively.
5. The percentage falling within 1 standard deviation of the mean is approximately 68%, which satisfies the empirical rule for normal distributions.
This problem involves the binomial distribution, since each student either drives to school (success) or does not (failure), and the probability of success is given as 0.68 for each student.
(1) The probability that exactly 12 students drive to school is given by the binomial probability mass function:
P(X = 12) \(= (20 choose 12) * (0.68)^12 * (1 - 0.68)^(20 - 12) = 0.169\)
(2) The probability that more than 15 students drive to school is given by the complement of the probability that at most 15 students drive to school:
P(X > 15) = 1 - P(X <= 15) = 1 - sum[(20 choose i) * \((0.68)^i * (1 - 0.68)^{20 - i)}\) for i = 0 to 15.
This is approximately 0.027.
(3) The probability that no more than 10 students drive to school is given by the cumulative distribution function:
P(X <= 10) = sum[(20 choose i) * \((0.68)^i * (1 - 0.68)^{20 - i}\) for i = 0 to 10. This is approximately 0.004.
(4) The mean of the binomial distribution is given by the formula np, where n is the sample size and p is the probability of success.
Thus, the mean is 200.68 = 13.6.
The standard deviation of the binomial distribution is given by the formula sqrt(np(1-p)), which is approximately 2.4.
(5) The percentage falling within one standard deviation of the mean is approximately 68% by the empirical rule, which is the same as the percentage of students who drive to school in the university.
However, the empirical rule applies to normal distributions, and the binomial distribution is not exactly normal.
Nonetheless, for large sample sizes, the binomial distribution can be approximated by a normal distribution using the central limit theorem, which would make the empirical rule applicable.
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help me answer this please it’s due today
$5 for 1 shirt
y = cost
x = number be shirts
10y = 2x
5y = x
Find Sn for the following geometric sequences described.
From the question, the sum of each of the geometric sequence are;
1) 31 3/4
2) 340
3) 11/16
4) -6, 12, -24
What is geometric sequence?
We have that;
Sn = a(1 -\(r^n\))/1 - r
Sn = 16(1 \(- (1/2)^7\))1 - 1/2
Sn = 16(1 - 1/128)/1/2
Sn = 16(127/128) * 2
Sn = 31 3/4
2) Un = a\(r^n\) -1
256 = \(4(4)^n-1\)
64 =\(4^n-1\)
\(4^3 = 4^n-1\)
n = 4
Sn= \(4(4^4 - 1)\)/4 - 1
Sn = 340
3) Since we have a5 then n = 5
Sn = 1(1 - (\(-1/2)^5\))/1 -(-1/2)
Sn = 33/32 * 2/3
= 11/16
4) 30= a(1 -\((-2)^4\))/1 - (-2)
30 = a(-15)/3
30 = -5a
a = 30/-5
a = -6
Then the first three terms are;
-6, 12, -24
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Which word is associated with multiplication when computing probabilities? Choose the correct answer below Disjoint O And O Not
When we calculate probabilities involving one event AND another event occurring, we multiply their probabilities.
According to me , independent is the word which is associated with multiplication when computing probabilities . Because when the events are independent then we multiply the probabilities .
According to the multiplication rule of probability, the probability of occurrence of both the events A and B is equal to the product of the probability of B occurring and the conditional probability that event A occurring given that event B occurs.
The probability of the union of two events is equal to the sum of individual probabilities. The union of two set contains all the elements of previous sets. The union is denoted by ∪. The equation for the students earnings will be expressed as P(A∪B). The occurrence of event A changes the probability of B then the events are dependent. If the probability of two events happening together is zero then the events are mutually exclusive.
Therefore,
When we calculate probabilities involving one event AND another event occurring, we multiply their probabilities.
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Which of the following statements should the salesperson use if he wished to ignore the objection?
a. "I think I might be able to explain that better to you after showing you this diagram."
b. "I think you have a point there; do you have any idea how we can improve that situation?"
c. "That's true. It does have a shorter shelf life, but that hasn't really been a problem. It is so popular it never gets to stay on the shelf that long anyway."
d. "Where did you hear that? Your source must have erroneous information."
e. "As I was saying, . . . "
E, "As I was saying, . . .". The salesperson should use this statement if they wished to ignore the objection.
Option E is the best choice to ignore the objection because it allows the salesperson to redirect the conversation back to their main point without directly addressing the objection. The statement implies that the objection is not important enough to interrupt the flow of the conversation.
Ignoring objections is not always the best approach in sales, but if the salesperson chooses to do so, they should use a statement like option E to redirect the conversation back to their main point.
When a salesperson wants to ignore an objection, they should choose a response that does not address the concern raised and instead redirects the conversation back to the topic they were discussing. Option e does this effectively by not acknowledging the objection and continuing with the original discussion.
To ignore an objection, a salesperson should use a statement like option e, which allows them to refocus the conversation without addressing the concern raised.
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What type of correlation is shown by the graph?
Answer: Positive correlation
Step-by-step explanation:
As you go up and along the graph the values go up.
Both have to be increasing basically.