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The particles of a substance vibrate in place but stay in fixed positions. When thermal energy is added to the substance, the particles stay close together but start to slide past one another. What change in state has occurred?

O A. Solid to gas
OB. Solid to liquid
O C. Liquid to gas
OD. Liquid to solid​

Ideally in no air resistance, the ball will return to the thrower's hand with a speed of 10 m/s. Thus, the correct option is B.

Speed is the distance covered by an object with respect to time taken. It can also be defined as the change in the position of an object with respect to time. It is a scalar quantity as it has only magnitude and no direction.

The ball which is thrown straight upward in the sky with a speed of 10 m/s will return back to the thrower's hands with a speed of 10m/s in the ideal case of no air resistance because during this situation, no acceleration takes place. At the highest point, the velocity of the ball is zero however the ball is still under the influence of gravity, here the acceleration due to gravity is acting downwards on the ball.

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Answer:

If you are using a machine that has a mechanical advantage of 2.5,you will have increased your EFFORT DISTANCE by 2.5 times. This allows you to REDUCE the EFFORT FORCE needed by 2.5 times.

the force generated by a pressure of 1250 mbar on an area of 3 mm^2 is 375 Newtons.The force generated by a pressure can be calculated using the formula:

Force = Pressure x Area

Given that the pressure is 1250 mbar and the area is 3 mm^2, we need to convert the units to ensure consistency.

To convert mbar to pascal (Pa), we use the conversion factor: 1 mbar = 100 Pa. Therefore, the pressure in pascals is 1250 mbar x 100 Pa/mbar = 125,000 Pa.

To convert mm^2 to m^2, we use the conversion factor: 1 mm^2 = 10^-6 m^2. Therefore, the area in square meters is 3 mm^2 x (10^-6 m^2/mm^2) = 3 x 10^-6 m^2.

Now, we can calculate the force:

Force = 125,000 Pa x 3 x 10^-6 m^2

Simplifying the calculation, we get:

Force = 375 N

Therefore, the force generated by a pressure of 1250 mbar on an area of 3 mm^2 is 375 Newtons.

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Therefore, the force generated by a 1250 mbar pressure on an area of 3 mm² is 3.75 x 10^(-4) N.

To calculate the force generated by a pressure of 1250 mbar on an area of 3 mm², we can use the formula:

Force = Pressure x Area

First, let's convert the pressure from millibars (mbar) to pascals (Pa) since the SI unit for pressure is the pascal.

1 mbar is equal to 100 pascals, so 1250 mbar is equal to 1250 x 100 = 125000 pascals (Pa).

Now, let's convert the area from square millimeters (mm²) to square meters (m²) since the SI unit for area is the square meter.

1 mm² is equal to 1 x 10^(-6) square meters (m²), so 3 mm² is equal to 3 x 10^(-6) m².

Substituting the values into the formula:

Force = 125000 Pa x 3 x 10^(-6) m²

Simplifying the expression:

Force = 375 x 10^(-6) N

This can be written as 3.75 x 10^(-4) N in scientific notation.

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Hi there!

When finding work (J) given force (N), we use the equation:

W = FdcosФ <-- Only take into account the force in the direction of motion

Plug in the given values:

W = 27(32)cos(20) = 811.89 J

Explanation:

Here,

Given that,

pulls a wagon a distance of 32 meters the handle is above an angle of 20 degrees above horizontal if you pull on it with a force of 27 N

To find,

As we know that,

\({\boxed{\sf{W=f.d.cos\theta }}}\)

According to the question,

\(W=27(32)cos{20}\\\\w=811.89J\)

Case: The effect of balloon color on inflation time.

Independent variable: Balloon color (categorical) with four levels (e.g., red, blue, green, yellow).

Dependent variable: Time taken for inflation to a diameter of 7 inches (continuous, measured in seconds).

Study design: Within-subject design (the same group of participants inflating balloons of different colors).

Confounding variable: Possible confounding variables could be the size or material of the balloons, as these factors might affect the inflation time. To control for this, it would be important to ensure that all balloons used in the experiment are of the same size and material.

Violation of Validity: A violation of validity could occur if the measurement of inflation time is not accurate or consistent (e.g., if the stopwatch used is unreliable or if the experimenter's recording of times is inconsistent). Ensuring proper measurement procedures and equipment would help mitigate this violation.

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So, key answer is inter-molecular forces of solids is stronger than liquids.

Explanation:

THE EFFECT OF GRAVITATIONAL FORCE IS MORE IN LIQUID THAN IN SOLIDS. BECAUSE THE INTERMOLECULAR FORCE IN LIQUID ARE WEAKER COMPAIRED TO THAT OF SOLIDS.......

HOPE IT HELP.......❣❣❣

Answer:

D

Explanation:

Answer:When a wind-up toy is set in motion, elastic potential energy that was stored in a compressed spring is converted into the kinetic energy of the toy's moving parts.

Explanation:

Answer:

2000

Explanation:

ddoes rest : add the components

Answer:

P2 = 128,205 pascal.

Explanation:

Given the following data;

Original Pressure, P1 = 100,000 pascals

Original Temperature, T1 = 273K

New Temperature, T2 = 350K

To find new pressure P2, we would use Gay Lussac' law.

Gay Lussac's law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Gay Lussac's law is given by;

\( PT = K\)

Where;

\( \frac{P1}{T1} = \frac{P2}{T2}\)

Making P2 as the subject formula, we have;

\( P_{2}= \frac{P1}{T1} * T_{2}\)

Substituting into the equation, we have;

\( P_{2}= \frac{100000}{273} * 350\)

\( P_{2}= 366.3004* 350\)

P2 = 128205.13 ≈ 128205 pascal.

Therefore, the pressure inside the hot water bottle is 128,205 pascal.

The magnitude of the work done by the car's brakes to slow the car down is 235,537.5 Joules.

The work done:

W = ΔKE

The change observed in kinetic energy (ΔKE) can be find as:

ΔKE = (1/2) × m × (vf² - vi²)

Where m = mass of the car,

vf = final velocity, and

vi = initial velocity.

Let's replace the given values into the equation:

m = 1,500 kg

vf = 28.6 m/s

vi = 45.9 m/s

ΔKE = (1/2) × 1,500 kg  × ((28.6 m/s)² -  (45.9 m/s)²)

Now, determine the magnitude of the work done:

W = ΔKE

ΔKE = (1/2) ×  1,500 kg ×  ((28.6 m/s)² -  (45.9 m/s)²)

= (1/2) ×  1,500 kg ×  (-314.05 m²/s²)

= -235,537.5 J

The amount of work done by the car's brakes to slow it down is 235,537.5 Joules since the change in kinetic energy is negative (indicates a drop in kinetic energy).

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Because r is given, we can use the second expression in the equation ac=v2r;ac=rω2 a c = v 2 r ; a c = r ω 2 to calculate the centripetal acceleration. Solution.

The coefficient of static friction between the book and the tabletop is 0.13.

The coefficient of static friction between the book and the tabletop can be calculated using the formula:

μs = Fs / N

Where μs is the coefficient of static friction, Fs is the force of static friction, and N is the normal force.

In this case, the force of static friction is the force required to start the book sliding, which is 2.16 N. The normal force is the weight of the book, which is 1.70 kg × 9.8 m/s2 = 16.66 N.

Plugging in the values into the formula, we get:

μs = 2.16 N / 16.66 N
μs = 0.13

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Answer:

I’d say the air outside the hemisphere is more free than from the inside of the hemisphere.

Explanation:

hope this help!

If a 1200 N box were lifted off the ground for a distance of 5 m, the amount of work done would be 6000 J.

Work (W) is defined as the product of the force (F) applied on an object and the distance (d) over which the force is applied. Mathematically, W = Fd.

In this case, the force applied is the weight of the box, which is 1200 N. The distance through which the box is lifted is 5 m. Therefore, the work done in lifting the box can be calculated as W = Fd = 1200 N x 5 m = 6000 J.

This means that lifting the box requires an input of 6000 Joules of energy.

It is important to note that as work is a scalar quantity and the direction of the force and displacement are parallel, therefore, work done is simply the product of force and displacement.

Additionally, the work done on the box is equal to the potential energy gained by the box, which is at a height above the ground.

Therefore, if the box is allowed to fall back to the ground, it will release the same amount of potential energy as it gained, which will be converted into kinetic energy.

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Answer:

a = -6/t (on the opposite direction of the bicycle motion)

Explanation:

For all problems of physics we need to set the positive axis direction. and the origin. In our case the origin location does not make difference since we are only interested in velocities and acceleration. So I'm gonna set the positive axis in the same direction that the bicycle is moving. Therefore, our initial (10 m/s)  and final (4 m/s) velocities are also positive.

However we have some problems. We do not know how this bicycle was decelerated (constant or not). Besides we do not have the information like time or displacement of this deceleration.

So, supposing an uniform deceleration and using the velocity time function for uniform "a", we get:

v = vo + at (set the initial time to 0s)

4 = 10 + at

a = -6/t

So you only can determine the acceleration if you have either the time or the displacement (using Torricelli equation). But we know that our bicycle acceleration points against the direction of the bicycle motion due to the negative sign.

Answer:

sound is a vibration that propagates as an acoustic wave, through a transmission medium such as a gas, liquid or solid. In human physiology and psychology, sound is the reception of such waves and their perception by the brain

Answer:

Sound waves travel at 343 m/s through the air and faster through liquids and solids. The waves transfer energy from the source of the sound, e.g. a drum, to its surroundings. Your ear detects sound waves when vibrating air particles cause your ear drum to vibrate. The bigger the vibrations the louder the sound.

Explanation:

I looked it up and I looove ur pfp! HP fan 4life!

Answer:

Weather is the state of atmosphere,temperature atmospheric pressure, wind.It differs from climate which is all weather conditions for a location averaged over about 30 years

To calculate the power of the crane, we need to use the formula:

Power = Force × Velocity

First, let's find the force acting on the crane using Newton's second law of motion:

Force = Mass × Acceleration

Given:

Mass of the crane (m) = 800 kg

Acceleration (a) = 1 m/s²

Force = 800 kg × 1 m/s² = 800 N

Next, we need to calculate the power at a velocity of 1.5 m/s. Power is the rate at which work is done, and work is equal to the change in kinetic energy. So, we'll use the formula:

Power = Work / Time

Since the crane starts from rest (initial velocity = 0) and reaches a final velocity of 1.5 m/s, we can calculate the work done on the crane:

Work = Change in kinetic energy

= (1/2) × Mass × (Final Velocity² - Initial Velocity²)

Given:

Initial Velocity (v1) = 0 m/s

Final Velocity (v2) = 1.5 m/s

Work = (1/2) × 800 kg × (1.5 m/s)² = 900 J

Now, let's calculate the power:

Power = Work / Time

Since we don't have the time, let's assume it took 1 second to reach the final velocity.

Power = 900 J / 1 s = 900 W

Therefore, the power of the crane when it reaches a speed of 1.5 m/s is 900 watts (W).

1. Pressure = Force/Area

When a ballon is pressed against many pins then the area is increased as compared to when it is pressed against a single pin. The force by which the balloon is pressed remains the same. Less the area, more the pressure. So, the balloon pops when it is pressed against one pin.

2. The candle goes off when covered with a glass because for burning the candle need oxygen. When glass on placed on the candle then the oxygen supply is stopped. So, when available oxygen is finished, the candle goes off. Water rises in the glass, because when the candle is burning, it expands the air inside the glass due to its heat. But when candle wents off, the air is cooled again and it contracts. So, a vacuum is created. That's why the water rises in the glass to fill the vacuum and to balance the air pressure inside and outside the glass.

3. Objects tend to maintain their state of motion or rest unless subjected to an external force. This property is called Inertia. More the mass more the inertia. When sudden brakes are applied, then our body still tends to remain in motion. That's why our body go forward.

Answer:

"solve: given that F -12 N and time 4 seconds and let we have to find out the P.

F = 12 N

t = 4 s

p = ?

F = m×( v - u ) / t

12 = m×v / 4

m×v = 12× 4

p = 48 kg m/s

Linear momentum will be 48 kg m/s.

Explanation:

To find the tangential and normal components of acceleration, we need to differentiate the given position vector twice with respect to time (t) to obtain the acceleration vector.

Then, we can decompose the acceleration vector into its tangential and normal components.

Given position vector: \(r(t) = t^2i + (t^2 - 1)j + 2t^2k\)

First, let's differentiate the position vector with respect to time to find the velocity vector:

\(v(t) = dr(t)/dt = 2ti + (2t)j + 4tk\)

Now, let's differentiate the velocity vector with respect to time to find the acceleration vector:

\(a(t) = dv(t)/dt = d^2r(t)/dt^2 = d^2r(t)/dt^2 = 2i + 2j + 4k\)

The acceleration vector is a(t) = 2i + 2j + 4k.

Now, let's decompose the acceleration vector into its tangential and normal components.

The tangential component of acceleration (a_T) is the component of acceleration parallel to the velocity vector. It can be calculated by taking the dot product of the acceleration vector (a) and the unit vector in the direction of the velocity vector (v/|v|):

\(a_T\) = (a · v/|v|) * (v/|v|)

To find the unit vector in the direction of v, we divide the velocity vector (v) by its magnitude:

v = 2ti + 2tj + 4tk

\(|v| = sqrt((2t)^2 + (2t)^2 + (4t)^2) = sqrt(4t^2 + 4t^2 + 16t^2) = sqrt(24t^2) = 2sqrt(6)t\)

v/|v| = (2ti + 2tj + 4tk) / (2sqrt(6)t) = (i + j + 2k) / sqrt(6)

Now, let's calculate the dot product of a and v/|v|:

a · v/|v| = (2i + 2j + 4k) · (i + j + 2k) / sqrt(6)

          = 2 + 2 + 8 / sqrt(6)

          = 12 / sqrt(6)

          = 2sqrt(6)

Finally, we can calculate the tangential component of acceleration (a_T):

\(a_T\)= (a · v/|v|) * (v/|v|)

   = (2sqrt(6)) * ((i + j + 2k) / sqrt(6))

   = 2(i + j + 2k)

Therefore, the tangential component of acceleration \((a_T)\) is 2(i + j + 2k).

The normal component of acceleration (a_N) is the component of acceleration perpendicular to the velocity vector. It can be calculated by subtracting the tangential component of acceleration from the total acceleration vector:

\(a_N = a - a_T\)

   = (2i + 2j + 4k) - 2(i + j + 2k)

   = 2i + 2j + 4k - 2i - 2j - 4k

   = 0i + 0j + 0k

   = 0

Therefore, the normal component of acceleration \((a_N)\) is 0.

In summary, at any time t > 0, the tangential component of acceleration \((a_T)\) is 2(i + j + 2k), and the normal component of acceleration \((a_N)\) is 0.

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According to Newton's law, action and reaction are equal and opposite.

According to the Newton's third law of motion, action and reaction are equal and opposite. As such, when the arrow hits the vertical wood board, the board exerts some force on the arrow.

We can not determine the magnitude of this force numerically because the question is incomplete.

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Answer:

newtons law action and reaction are equal and opposite

Explanation:

Answer:

The speed of light is approximately 299,792 kilometers per second. If the distance from Earth to the Moon is 386,400 kilometers, then it would take light about 1.28 seconds to travel from Earth to the Moon.

As a result, light would need to travel from Earth to the moon for around 1.29 seconds.

On average, our planet and its sizable natural satellite are separated by roughly 238,855 miles (384,400 kilometres). As a result, the total amount of moonlight we observe is 1.255 seconds old, and it takes around 2.51 seconds for light to travel from the Earth to the moon.

we can use the following formula:

time = distance / speed

First, we need to convert the distance from kilometers to meters:

386,400 km = 386,400,000 meters

Now, we can calculate the time it will take light to travel from Earth to the Moon:

time = 386,400,000 meters / 299,792,458 meters per second

time

≈ 1.29 seconds

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Answer:

i) El período de la rueda es de 0,25 segundos.

ii) La frecuencia de la rueda es 4 Hertz

iii) La velocidad angular es aproximadamente 25.133

iv) La velocidad lineal es de aproximadamente 3,77 m / s

Explanation:

El radio de la rueda, r = 15 cm = 0,15 m

El número de vueltas que hace la rueda = 64 vueltas

El tiempo que tarda el volante en dar 64 vueltas = 16 segundos

i) El período = El tiempo que tarda la rueda en dar 1 vuelta

∴ El período de la rueda, T = 16 segundos/(64 vueltas) = 0,25 segundos

El período de la rueda, T = 0,25 segundos

ii) La frecuencia = El número de vueltas por segundo

∴ La frecuencia de la rueda, f = 64 vueltas /(16 segundos) = 4 Hertz

1 vuelta = 2 · π radianes

La frecuencia de la rueda, f = 4 Hertz

iii) Velocidad angular = La medida del ángulo girado por segundo

∴ La velocidad angular, ω = 64 × 2 × π/16 segundos ≈ 8 · π rad/segundos ≈ 25.133 rad/seg

La velocidad angular, ω ≈ 25.133

iv) La velocidad lineal, v = r × ω

∴ v = 0,15 m × 8 · π rad / segundos ≈ 3,77 m/s

La velocidad lineal, v ≈ 3.77 m/s

Answer:  Gravity is the force that keeps planets in orbit around the Sun. Gravity alone holds us to Earth's surface.

Planets have measurable properties, such as size, mass, density, and composition. A planet's size and mass determines its gravitational pull.

A planet's mass and size determines how strong its gravitational pull is.

Models can help us experiment with the motions of objects in space, which are determined by the gravitational pull between them.

Explanation:

A star of the apparent magnitude of +1 would appear farther away than a star of the apparent magnitude of +2. Hence, option B is correct.

In astronomy, a star is a brilliant plasma spheroid that is held together through gravity. The Sun is the planet's closest star. The human eye can see a great number of other stars at night, but due to our planet's size, they seem alike stationary points of light.

Numerous of the shining stars were given names, whereas the most notable stars have been grouped into constellations and asterisms. The known stars have been recognized and given standard designations in star inventories that astronomers have put together.

The birth of a star is caused by the gravitational attraction of a gaseous nebula made largely of hydrogen, helium, and traces of transition metals. Its overall mass is the primary factor influencing how it will develop and end up.

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Answer: 112.992

Explanation: If you divide 287 by 2.54, you will get 112.992125984. I just got rid of the five numbers after 992.

1 inch = 2.54 cm

?= 287 cm let, ? be (a)

cross multiply

2.54a= 1×287

a= 287/2.54

a= 112.992126

therefore 287 cm = 112.992126 inches.

To calculate the mass of the gold rectangular bar, we need to use the formula:
Mass = Density × Volume
First, let's find the volume of the bar. The volume of a rectangular bar can be calculated using the formula:
Volume = Length × Width × Height
Given that the dimensions of the bar are:
Length = 4.50 cm
Width = 11.0 cm
Height = 26.0 cm
We can substitute these values into the formula to find the volume:
Volume = 4.50 cm × 11.0 cm × 26.0 cm
Multiplying these values, we find that the volume of the bar is:
Volume = 1287.0 cm³
Next, we need to know the density of gold. The density of gold is 19.3 grams per cubic centimeter (g/cm³).
Now, we can substitute the volume and the density into the mass formula:
Mass = 19.3 g/cm³ × 1287.0 cm³
Multiplying these values, we find that the mass of the gold rectangular bar is:
Mass = 24823.1 g
Converting the mass to kilograms by dividing by 1000, we find:
Mass = 24.8231 kg
Therefore, the mass of the solid gold rectangular bar with dimensions 4.50 cm × 11.0 cm × 26.0 cm is approximately 24.8231 kilograms.

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