What are the magnitude and the direction of the electric field that will allow an electron to fall with an acceleration of 4.3 m/s2?
Answer:
Explanation:
The acceleration of an electron in an electric field is given by the equation:
a = qE/m
where a is the acceleration, q is the charge of the electron, E is the electric field, and m is the mass of the electron.
Given that the acceleration of the electron is 4.3 m/s^2, and the mass of the electron is 9.11 × 10^-31 kg, and the charge of the electron is -1.6 × 10^-19 C, we can solve for the electric field E:
E = ma/q
E = (4.3 m/s^2) × (9.11 × 10^-31 kg) / (-1.6 × 10^-19 C)
E = -2.44 × 10^4 N/C
The negative sign indicates that the direction of the electric field is opposite to the direction of the electron's motion. Therefore, the magnitude of the electric field required to accelerate an electron with an acceleration of 4.3 m/s^2 is 2.44 × 10^4 N/C and the direction is opposite to the direction of motion of the electron.
HELP ASAP PLZ
What is the most likely reason for using the following model? A diagram that shows the different layers inside the sun Image © 2010 NASA The object is too small. The object represents a set of data. The object cannot be directly observed. The object represents a prediction about the future.
Answer:
Option C, The object cannot be directly observed.
Explanation:The temperature of sun is extremely high due to which it is almost impossible to land on its surface and explore the depth of it. Thus a prototype of it is required to predict its probable internal structure and associated feature which effect our planet "earth".
This prototype/model is based on the deduction arrived after analyzing the satellite information available in the form of high resolution images.
Hence, option C is correct
Answer:
The answer is c the object cannot be directly observed.
Explanation:
I took the test and got it right.
A girl rode a scooter 43 m north, then 38 m south, and then 16 m north. The girl then rode south again before stopping. Her total distance traveled was 122 m. How far south did she ride on the last part of her trip, and what was her total displacement
Answer:
First, let's write some definitions.
Displacement is the distance between the final position and the initial position.
Here we can define north as the positive direction and south as the negative one.
First, we assume that the initial position is 0m
We know that she first goes 43m north
Then she goes 38m south
Then she goes 16m north
And then she goes south again for X meters, such that the total distance traveled is 122m
The total distance traveled is the sum of all distances traveled, regardless of the direction
then we have:
43m + 38m + 16m + X = 122m
Solving this for X we get:
97m + X = 122m
X = 122m - 97m = 25m
So she finally goes 25m south.
Now let's analyze how her position changes:
First, she starts at 0m
Then she goes north for 43m, then her new position is:
0m + 43m = 43m
Now she goes 38m south, then her new position is:
43m - 38m = 5m
Then she goes north again, for 16m
Then the new position is:
5m + 16m = 21m
Now she goes south for 25m, then the final position is:
21m - 25m = -4m
The displacement is equal to the difference between the final position and the initial one, so the displacement is:
-4m - 0m = -4m
The displacement is -4m.
Which of the following would you expect to be a strong electrolyte in solution?
The following would expect to be a strong electrolyte in solution (b) KCI is correct option.
When dissolved in water, a strong electrolyte produces a large concentration of ions in solution by totally dissociating into ions. The following compounds are typically strong electrolytes in solution according to this definition:
Al(OH)₃ (aluminum hydroxide) is a weak electrolyte. It does not dissociate significantly into ions in solution, resulting in a low electrical conductivity.KCl (potassium chloride) is a strong electrolyte. It completely dissociates into potassium ions (K⁺) and chloride ions (Cl⁻) in solution, resulting in a high concentration of ions and a high electrical conductivity.PbI₂ (lead(II) iodide) is a weak electrolyte. It does not dissociate significantly into ions in solution, resulting in a low electrical conductivity.These substances readily dissociate into ions in water and exhibit high electrical conductivity, making them strong electrolytes in solution.
Therefore, the correct option is (b).
The complete question is,
Which of the following would be a strong electrolyte in solution?
a) Al(OH)₃ b) KCI c) Pbl₂
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statics and strength of materials
The magnitude of the force P provided that the stress in the part AB is two times that of BC part is 0.8 kN.
What is the force P?The magnitude of the force P provided that the stress in the part AB is two times that of BC part is calculated as follows;
Take moment about the joint to determine the magnitude of the force along part BC.
120 kN x 750 mm = F x 1000 mm
F = ( 120 kN x 750 mm ) / ( 1000 mm )
F = 90 kN
Stress is given as force divided by area. The following equation can be used to determine the magnitude of force P.
Stress in AB = 2 times stress in BC
P/A₁ = 2F/A₂
where;
A₁ is the area of segment ABA₂ is the area of segment BCA₁ = πd²/4 = π(50 x 10⁻³)²/4
A₁ = 1.96 x 10⁻⁵ m²
A₂ = πd²/4 = π(75 x 10⁻³)²/4
A₂ = 4.42 x 10⁻³ m²
P/A₁ = 2F/A₂
P = (2F x A₁) / (A₂)
P = (2 x 90 kN x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )
P = (2 x 90,000 N x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )
P = 798.2 N
P = 0.798 kN
P ≈ 0.8 kN
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Perform the operation of 147.02 / 0.338, and report the result with the proper number of significant figures
in standard powers-of-10 notation.
Answer:
434.97041
Explanation:
an object with mass M is attached to an ideal horizontal spring with spring constant k, who's other end is attached to a wall. The object is pushed to position x= -A on a horizontal surface with negligible friction and released at t=0; describe each of the following during one full cycle of its motion.
a. The total distance traveled by the object
b. the displacement of the object
c. the times at which the velocity and speed of the object were greatest
d. the average velocity of the object
e. the average speed of the object
f. the maximum force on the object
(a). The spring will revert back by travelling A distance and overshoot by another A distance. Then the mass reach back to its initial compressed position by travelling another 2A distance. The total distance travelled is 4A in one complete cycle.
(b). As the mass reach back to its initial position so that the initial and final point of the mass is same then the displacement is 0 during one complete cycle
(c). The motion of the spring is in SHM. At its maximum amplitude position [At x = -A and A] velocity and speed is 0 but acceleration maximum a = -ω^2A (ω = Angular frequency = \(\sqrt{\frac{k}{m} }\)). When the mass reaches at mean position (x=0) the velocity and speed is maximum.
(d). Average velocity = displacement/time
= 0/T
= 0m/s
(e). Average speed = Distance total/time period
= 4A/T (\(T = 2\pi \sqrt{\frac{m}{k} }\))
= \(\frac{4A}{2\pi \sqrt{\frac{m}{k} } }\)
\(= \frac{2A}{\pi } \sqrt{\frac{k}{m} } m/s\)
(f). Maximum force ; \(F_{max} = -kx_{max}\)
but \(x_{max} = A\)
\(F_{max} = -kA\)
Hence, the magnitude of maximum force is kA.
Motion is the phenomenon in which an object changes its position with respect to b.
The motion of an object perceived when its position changes continuously with respect to some stationary object. Terms such as distance, displacement, speed, velocity and acceleration are all related to the concept of motion.
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Given the list of items, select all that are considered to be matter:
music
heat
air
dreams
water
gasoline
love
bacteria
thoughts
From the given list of items, examples of matter include, heat, air, water, gasoline, and bacteria.
What is matter?Matter is a substance made up of various types of particles that occupies physical space and has inertia.
A matter must have mass and occupy space.
Examples of matter include the following;
heatairwatergasolinebacteriaThus, from the given list of items, examples of matter include, heat, air, water, gasoline, and bacteria.
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It is possible to extend the circuit infinitely in both directions as shown in the figure. Knowing r=1 a) Calculate RAB when both locks are open or when K1 is closed K2 are closed b) Calculate RAB when K1 is closed K2 is open c) Calculate RAB when both locks are closed
Answer:
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In the circuit shown in Figure, initially K
1
is closed and K
2
is open. What are the charges on each capacitor. Then K
1
was opened and K
2
was closed (order is important), What will be the charge on each capacitor now? [C=1μF]
1796057
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Medium
Solution
verified
Verified by Toppr
When K
2
is open and K
1
is closed the capacitors C
1
and C
2
will charge and potential develops across them i.e., V
1
and V
2
respectively which will be equal to the potential of battery 9V
∴V
1
+V
2
=9……..I
∵V=
C
q
=orVα
C
1
Or
V
2
V
1
=
C
1
C
2
V
2
V
1
=
6C
3C
3V
2
=6V
1
V
2
=2V
1
…II
From Eqns. I and II
V
1
+2V
1
=9
3V
1
=9
V
1
=3
Volt
V
2
=2×3Volt=6Volt
∴q
1
=C
1
V
1
=6C×3=18C[(from II C=1μF)
=18×1μF=18μc
q
2
=C
2
V
2
=3C×6
=3×1μF×6=18μC
So, charges on each capacitor i.e., q
1
=q
2
=18μc
When k
1
is open and k
2
is closed then charge q
2
will be distributed among
C
2
and C
3
. Let it be q
2
and q
3
∴q
2
=q
2
+q
3
As C
2
and C
3
are now in parallel combination so their potentials
remain same (V)
∴q
2
=C
2
V+C
3
V
18μC=3×1μFxV+3×1μF×V
18=6V
V=3Volt
So potential on C
2
and C
3
capacitors are 3 Volt each
q
2
′
=C
2
V−3×1μF×3Volt=9μC
q
3
=C
3
V=3×1μF×3Volt=9μC
The pressure of a constant volume gas thermometer is 2100N/M squared at 38c. What will be the temperature of the gas when the pressure is increased by 1/3?
Answer:
Explanation:
In
Knowing that warp three is 27 times the speed of light, how long does it take you to get to the nebula (in years).
The time taken to move from Earth to Orion Nebula (in years) is 49.8 years
What is speed?Speed is the distance travelled per unit. Mathematically, it can be expressed as:
Speed = distance / time
With the above formula, we can obtain the time. Details below
How to determine the timeThe time taken to travel from Earth to Orion Nebula can be obtained as illustrated below:
Speed of light = 3×10⁸ m/s = 1 light-year/year Speed of warp three = 27 × speed of light = 27 × 1 = 27 light-year/yearDistance to Orion Nebula from Earth = 1344 light yearsTime =?
Speed = Distance / time
Cross multiply
Speed × time = distance
Divide both sides by speed
Time = Distance / speed
Time = 1344 / 27
Time = 49.8 years
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the following statements describe ways in which the analogy might apply to the real universe. which statements are correct?
The following statements describe ways in which the analogy might apply to the real universe:
The average distance increases with time, both between raisins in the cake and between galaxies in the universe.An observer at any raisin sees more distant raisins moving away faster, just as an observer in any galaxy sees more distant galaxies moving away faster.An analogy is a comparison between two objects, events, or ideas that share certain characteristics. In the context of the real universe, an analogy can be used to compare the universe to something familiar, such as a balloon.
Just as a balloon expands when air is added to it, the universe is expanding, with the average distance between galaxies increasing over time. Similarly, just as a balloon needs energy to expand, the universe contains vast amounts of matter and energy, with much of it still undiscovered.
Finally, just as a balloon follows the same basic rules of geometry, the geometry of the universe follows ordinary Euclidean geometry, with the same basic rules of geometry applying to both the small and large scale.
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Complete question:
The following statements describe ways in which the analogy might apply to the real universe. Which statements are correct?
Check all that apply.
- The average distance increases with time both between raisins in the cake and between galaxies in the universe.
-An observer at any raisin sees more distant raisins moving away faster, just as an observer in any galaxy sees more distant galaxies moving away faster.
-The raisins stay roughly the same size as the cake expands, just as galaxies stay roughly the same size as the universe expands.
Hi
Please help on question asap if the answer is correct I'll rate you five stars a thanks and maybe even brainliest!
When two light bulbs are connected in series, the resistance in the circuit is increase compared to that with one lightbulb. The increased resistance opposes the flow of current so far fewer electrons pass per second , transferring less energy. The lightbulbs are therefore not as bright as In a circuit with same voltage but only one bulb.
However, when Two lightbulbs are connected in parallel, each loop behaves like a separate circuit . The resistance in each branch is the same as if there were just one light bulb in the whole circuit.there is the same current in each branch of the circuit ,so the bulbs Will light up with the same brightness as a single bulb circuit. The energy stored in the battery will decrease twice as quickly and battery will run out faster than I series circuit.
6) explain the advantages and disadvantages of arranging components in series or parallel.
1. A boulder fell from a small cliff and accelerated towards a car below at 9.8 m/s^2. The
boulder smashed into a car with a force of 99,000 Newtons. What is the mass of the
boulder?
Answer:
Mass = 10102.04 kilograms.
Explanation:
Given the following data;
Acceleration = 9.8m/s²
Force = 99000N
To find the mass;
Mass = force/acceleration
Mass = 99000/9.8
Mass = 10102.04 kilograms.
Therefore, the mass of the boulder is 10102.04 kilograms.
Approximately 20.0gm of milk at 6.0oC is added into a cup containing 270.0 gm of weak tea. The specific heat of weak tea is 3.91 x 103J kg-1 oC-1 and the final temperature of the milk - tea mixture is 85.0oC. Given the initial temperature of the weak tea is 90.0oC, what is the specific heat of milk?
Answer:
4161 J/kg·°C
Explanation:
We can use the principle of conservation of energy to solve this problem, which states that the total heat energy in a closed system is constant. The heat lost by the tea is equal to the heat gained by the milk.
Let's first calculate the heat lost by the tea:
Q(tea) = mcΔT
Q(tea) = (0.27 kg)(3910 J/kg·°C)(90.0°C - 85.0°C)
Q(tea) = 6555 J
where m is the mass of tea, c is the specific heat of tea, and ΔT is the change in temperature.
Next, let's calculate the heat gained by the milk:
Q(milk) = mcΔT
Q(milk) = (0.02 kg)(c)(85.0°C - 6.0°C)
Now we can equate the two expressions:
Q(tea) = Q(milk)
6555 J = (0.02 kg)(c)(79.0°C)
Solving for c, we get:
c = 4161 J/kg·°C
Therefore, the specific heat of milk is approximately 4161 J/kg·°C.
Using conservation of momentum, explain how two vehicles can collide and the final location is the same as their spot of collision.
Answer:
Hope this is helpful!
Explanation:
In every form of collision the momentum is conserved and it is the same before and after the collision, but in perfectly elastic collision, there is no loss of kinetic energy in the collision. In an inelastic collision is one in which part of the kinetic energy is changed to some other form of energy in the collision. Any macroscopic collision between objects will convert some of the kinetic energy into internal energy and other forms of energy.
What is sound waves
Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.
Characteristics of sound wavesFrequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).
Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.
Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.
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FLAMING OR ALBERT .........
Answer:
Albert
Explanation:
How have astronomers used models to explain galactic evolution through mergers and collisions? Use this model to explain how astronomers might test their understanding of the physical processes of the universe.
Answer:
Astronomers use computer models to simulate the process of galactic evolution through mergers and collisions. These models are based on our current understanding of the physical laws that govern the behavior of matter and energy in the universe. By running simulations of galactic mergers and collisions, astronomers can test their understanding of how these physical processes work in practice and how they contribute to the formation and evolution of galaxies.
One way that astronomers might test their understanding of the physical processes of the universe is by comparing the predictions of their models to observations of real galaxies. For example, if a model predicts that a particular type of galaxy should have a certain shape, size, or distribution of stars, astronomers can compare these predictions to observations of actual galaxies to see if they match up. If there is a discrepancy between the model's predictions and the observations, this can indicate that there are some physical processes that are not well understood or included in the model.
Another way that astronomers might test their understanding is by looking for patterns or trends in the properties of galaxies that are consistent with the predictions of their models. For example, if a model predicts that galaxies that have undergone a recent merger should have a particular distribution of gas and dust, astronomers can look for evidence of this pattern in observations of real galaxies. If they find that the predicted pattern is consistently observed in a large sample of galaxies, this can provide support for the model's predictions and the physical processes that it includes.
Overall, computer models of galactic evolution through mergers and collisions provide a powerful tool for astronomers to test their understanding of the physical processes of the universe. By comparing the predictions of their models to observations of real galaxies and looking for consistent patterns and trends, astronomers can refine their understanding of how galaxies form and evolve over time.
A 2.56×104-kg rocket blasts off vertically from the earth's surface with a constant acceleration. During the motion considered in the problem, assume that g remains constant. Inside the rocket, a 13.6-N instrument hangs from a wire that can support a maximum tension of 27.5 N .
a)Find the minimum time for this rocket to reach the sound barrier (330m/s)
without breaking the inside wire.
b)Find the maximum vertical thrust of the rocket engines under these conditions.
c)How far is the rocket above the earth's surface when it breaks the sound barrier?
a. The minimum time for the rocket to reach the sound barrier is 33.67 seconds.
b. The maximum vertical thrust of the rocket engines under these conditions is 250,893.6 N.
c. The rocket is 5548.1 meters above the Earth's surface when it breaks the sound barrier.
To solve this problem, we'll use Newton's second law of motion (F = ma) and consider the forces acting on the rocket and the instrument inside.
Calculating the minimum time for the rocket to reach the sound barrier without breaking the inside wire.
a) Minimum time to reach the sound barrier:
Given:
Mass of the rocket (m) = 2.56 × \(10^4\) kg
Acceleration due to gravity (g) = 9.8 m/\(s^2\)
Maximum tension the wire can support (T_max) = 27.5 N
Weight of the instrument (W) = mass of the instrument × acceleration due to gravity = 13.6 N
The forces acting on the instrument inside the rocket are its weight (W) and the tension in the wire (T). At maximum tension, the net force on the instrument is zero.
T - W = 0
T = W
Therefore, the maximum tension in the wire is equal to the weight of the instrument, which is 13.6 N.
Now, let's determine the acceleration of the rocket. The total force acting on the rocket is the sum of the rocket's weight (mg) and the tension in the wire (T).
F_total = mg + T
F_total = (2.56 × \(10^4\) kg)(9.8 m/\(s^2\)) + 13.6 N
F_total = 250,880 N + 13.6 N
F_total = 250,893.6 N
Since we're assuming the rocket's acceleration is constant.
we can use Newton's second law:
F_total = ma
250,893.6 N = (2.56 × \(10^4\) kg)a
Solving for acceleration:
a = 250,893.6 N / (2.56 × \(10^4\) kg)
a ≈ 9.8 m/\(s^2\)
The acceleration of the rocket is approximately 9.8 m/\(s^2\), which is the same as the acceleration due to gravity.
To find the minimum time to reach the sound barrier, we can use the following equation of motion:
v = u + at
where,
v = final velocity (sound barrier velocity = 330 m/s)
u = initial velocity (which is zero since the rocket starts from rest)
a = acceleration
t = time
330 m/s = 0 + (9.8 m/\(s^2\))t
Solving for t:
t = 330 m/s / 9.8 m/\(s^2\)
t ≈ 33.67 s
Therefore, the minimum time for the rocket to reach the sound barrier without breaking the inside wire is approximately 33.67 seconds.
b) Maximum vertical thrust of the rocket engines:
The maximum vertical thrust of the rocket engines is equal to the total force acting on the rocket, which we calculated earlier:
Maximum vertical thrust = F_total
Maximum vertical thrust ≈ 250,893.6 N
Therefore, the maximum vertical thrust of the rocket engines under these conditions is approximately 250,893.6 N.
c) Distance above the Earth's surface when breaking the sound barrier:
To determine the distance above the Earth's surface when breaking the sound barrier, we can use the following equation of motion:
s = ut + (1/2)at^2
where,
s = distance
u = initial velocity (which is zero)
a = acceleration
t = time it takes to reach the sound barrier (33.67 s).
s = 0 + (1/2)( 9.8 m/\(s^2\))\((33.67 s)^2\)
s = (\(4.9 m/s^2\))(1132.8289 \(s^2\))
s ≈ 5548.1 m
Therefore, the rocket is approximately 5548.1 meters (or 5.55 kilometers) above the Earth's surface when it breaks the sound barrier.
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Common Misconceptions about the Consumer Price Index [CPI]: Questions and
Answers
When the cost of food rises, does the CPI assume that consumers switch to less
desired foods, such as substituting hamburger for steak?
No. In January 1999, the BLS [Bureau of Labor Statistics] began using a geometric
mean formula in the CPI that reflects the fact that consumers shift their purchases
toward products that have fallen in relative price.... The CPI's objective is to calculate
the change in the amount consumers need to spend to maintain a constant level of
satisfaction.... The BLS is not assuming that consumers substitute hamburgers for
steak... Furthermore, the CPI doesn't implicitly assume that consumers always
substitute toward the less desirable good. Within the beef steaks item category, for
example, the assumption is that consumers on average would move up from flank
steak to filet mignon if the price of flank steak rose by a greater amount (or fell by less)
than filet mignon prices.
"Consumer Price Index," U.S. Bureau of Labor Statistics
Based on the text, how does the Consumer Price Index vary over the course of a
business cycle? E.2.1
O It changes according to the number of goods produced by a business.
O It changes according to availability of items, depending upon which items are priced the highest.
O It changes according to the desires of the consumers and access to lower-priced goods.
() It changes according to availability of ponds in the market hased on consumer needs
Consumer Price Index vary over the course of a business cycle It changes according to the desires of the consumers and access to lower-priced goods.
Based on the provided text, the Consumer Price Index (CPI) changes according to the desires of the consumers and access to lower-priced goods. The text mentions that consumers shift their purchases toward products that have fallen in relative price. The objective of the CPI is to calculate the change in the amount consumers need to spend to maintain a constant level of satisfaction.
The passage specifically states that the CPI does not assume that consumers substitute less desirable goods for more expensive ones. Instead, it acknowledges that consumers may move up within a category if the price of a lower-priced item rises more than that of a higher-priced item.
For example, within the beef steaks category, consumers are assumed to move up from flank steak to filet mignon if the price of flank steak rises by a greater amount or falls by less than filet mignon prices.
Therefore, the CPI takes into account consumer preferences and the availability of lower-priced goods. It reflects changes in prices and consumer behavior over the course of a business cycle, considering how consumers adjust their purchasing decisions based on price fluctuations and their desire for maintaining a constant level of satisfaction.
In summary, the CPI varies over the course of a business cycle based on consumer desires and access to lower-priced goods, rather than the availability of goods produced by businesses or the availability of specific items priced the highest.
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Why does the rocket keep moving upwards even after thrust has finished?
Answer:
It is so because of momentum. i.e a body keeps trying to stay at its current position.
What is the resistance force when you walk up an inclined plane?
Please help quick!
The resistance force which is the type of force that oppose the motion when we walk on an inclined plane is mgcos (-).
What is Resistance force?
A Resistance force is defined as a force that acts to oppose the motion or motion of an object that is an opposing force. Resistance force opposes the moving body to move in the opposite direction. Resistive force is described as the force, or the vector sum of several forces where the direction is opposite to the motion of a body is also called friction during sliding and/or rolling.
Some examples of resistive force are friction, where an object is held back from sliding on a surface, while another form of resistive force is fluid resistance in which the object is trying to plow through a fluid material.
Thus, the resistance force which is the type of force that oppose the motion when we walk on an inclined plane is mgcos (-).
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You would like to know whether silicon will float in mercury and you know that can determine this based on their densities. Unfortunately, you have the density of mercury in units of kilogram-meter^3 and the density of silicon in other units: 2.33 gram-centimeter^3. You decide to convert the density of silicon into units of kilogram-meter^3 to perform the comparison.
By which combination of conversion factors will you multiply 2.33 gram-centimeter^3 to perform the unit conversion?
Answer:
Explanation:
To convert gram / centimeter³ to kg / m³
gram / centimeter³
= 10⁻³ kg / centimeter³
= 10⁻³ / (10⁻²)³ kg / m³
= 10⁻³ / 10⁻⁶ kg / m³
= 10⁻³⁺⁶ kg / m³
= 10³ kg / m³
So we shall have to multiply be 10³ with amount in gm / cm³ to convert it into kg/m³
2.33 gram / cm³
= 2.33 x 10³ kg / m³ .
A car travels from point A to B in 3 hours and returns back to point A in 5 hours. Points A and B are 150 miles apart along a straight highway. Calculate: a) Total distance and total displacement (in mile and meter) b) Average speed and Average velocity (in mile/hr and m/s
The total distance covered by the car is 300 miles.
The total displacement covered by the car is zero.
The average speed of the car is 17.88 m/s.
The average velocity of the car is also zero.
Distance between the points A and B, d = 150 miles
Time taken by the car to travel from A to B, t₁ = 3 hours
Time taken by the car to travel from B to A, t₂ = 5 hours
a) Given that the car travelled from A to B and then back to A.
Therefore, the total distance covered by the car is,
Distance = 2 x d
Distance = 2 x 150
Distance = 300 miles
Since the car is travelling from A to B and then returning back to the initial point A, the total displacement covered by the car is zero.
b) The speed with which the car travelled from A to B is,
v₁ = d/t₁
v₁ = 150/3
v₁ = 50 miles/hr
v₁ = 22.35 m/s
The speed with which the car travelled from B to A is,
v₂ = d/t₂
v₂ = 150/5
v₂ = 30 miles/hr
v₂ = 13.41 m/s
Therefore, the average speed of the car is,
v = (v₁ + v₂)/2
v = (22.35 + 13.41)/2
v = 17.88 m/s
As, the total displacement of the car is zero, the average velocity of the car is also zero.
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In a race, Usain Bolt accelerates at
1.99 m/s2 for the first 60.0 m, then
decelerates at -0.266 m/s2 for the final
40.0 m. What was his final velocity? (Unit = m/s)
calculate the electric potential energy in a capacitor that stores 9.40 x 10 to the negative 10 C of charge at 50.0 V
The electric potential energy stored in the capacitor is 4.70 x 10^-8 Joules.
The electric potential energy stored in a capacitor is given by the formula:
U = (1/2) * C * V^2
where U is the potential energy in Joules, C is the capacitance in Farads, and V is the voltage across the capacitor in Volts.
In this case, we are given that the capacitor stores 9.40 x 10^-10 C of charge at 50.0 V. However, we are not given the capacitance value. Therefore, we cannot calculate the potential energy directly using the above formula.
To find the capacitance value, we can use the formula:
C = Q / V
where Q is the charge stored in the capacitor and V is the voltage across the capacitor.
Substituting the given values, we get:
C = 9.40 x 10^-10 / 50.0
= 1.88 x 10^-11 F
Now we can use the formula for electric potential energy to find the energy stored in the capacitor:
U = (1/2) * 1.88 x 10^-11 * (50.0)^2
= 4.70 x 10^-8 J
Therefore, the electric potential energy stored in the capacitor is 4.70 x 10^-8 Joules.
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The input and output forces for four machines are shown in the table. Machine Forces Machine Input Force (N) Output Force (N) 1 5 50 2 10 50 3 25 50 4 50 50 Which machine would have the greatest mechanical advantage? Responses 1 1 2 2 3 3 4
Machine 1 has the greatest mechanical advantage among the given machines. To determine the machine with the greatest mechanical advantage, we need to calculate the mechanical advantage for each machine.
Machine 1: Mechanical Advantage = Output Force / Input Force = 50 N / 5 N = 10
Machine 2: Mechanical Advantage = Output Force / Input Force = 50 N / 10 N = 5
Machine 3: Mechanical Advantage = Output Force / Input Force = 50 N / 25 N = 2
Machine 4: Mechanical Advantage = Output Force / Input Force = 50 N / 50 N = 1
Comparing the mechanical advantages, we can see that Machine 1 has the highest mechanical advantage of 10. This means that Machine 1 can multiply the input force by 10 to produce the output force. It provides the greatest amplification of force among the four machines.
Machine 2 has a mechanical advantage of 5, Machine 3 has a mechanical advantage of 2, and Machine 4 has a mechanical advantage of 1. Therefore, Machine 1 has the greatest mechanical advantage among the given machines.
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Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey. The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. Which of the following expressions correctly relates torquey to torquex?
Explanation: ΔL = τ(average) * Δt
Change in angular momentum = average torque * change in time
solve for average torque for each objects
τ(average) = ΔL / Δt
Object y average torque
τy = ΔLy / Δt = 20 / 5 = 4
τy = 4
Object x average torque
τx = ΔLx / Δt = 10 / 5 = 2
τx = 2
Relates τy and τx
2τx = τy
Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey.
The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. The precise relation between torquey and torquex is torquey = 2 * torquex.
To relate torquey to torquex, we are able to use the concept of angular momentum and torque. Angular momentum is described because the manufactured from the moment of inertia and angular velocity:
L = I * ω
Differentiating this equation with an appreciation of time, we get:
dL/dt = d(I * ω)/dt
Using the product rule of differentiation, we've got:
dL/dt = I * dω/dt + ω * dI/dt
Now, we realize that torque (τ) is described because of the charge of the exchange of angular momentum:
τ = dL/dt
Substituting the expression for dL/dt in terms of angular velocity and second of inertia:
τ = I * dω/dt + ω * dI/dt
Let's denote the common price of torque for item X as torquex. Since object X has a moment of inertia I0, we can write:
torquex = I0 * dω/dt + ω * dI0/dt
Now, let's consider item Y. It has a moment of inertia 2I0. Using the identical expression, we will write:
torquey = (2I0) * dω/dt + ω * d(2I0)/dt
torquey = 2I0 * dω/dt + ω * (2 * dI0/dt)
torquey = 2I0 * dω/dt + 2ω * dI0/dt
Comparing the expressions for torquex and torquey, we will see that:
torquey = 2 * torquex
Therefore, the precise relation between torquey and torquex is;
torquey = 2 * torquex.
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The correct question is;
"Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey. The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. Which of the following expressions correctly relates torquey to torquex?"
What is the key variable for calculating potential energy?