i will mark as brainliest
Jason has applied to be a camp counselor for the summer. The job pays $9 per hour. The equation to represent Jason’s job is y = 9x, where x is the number of hours he works and y is the total amount he earns.

Mia has applied to be a lifeguard for the summer. The lifeguard job is three days a week with hours and pay as shown in the table below.


Tuesday
Thursday
Saturday
Hours worked
6
8
5
Amount paid
$52.50
$70.00
$43.75

Which statement best describes the hourly rates?
The two jobs pay the same hourly rate.
The comparison cannot be made with the information given.
Jason’s camp counselor job pays a higher hourly rate than Mia’s lifeguard job.
Jason’s camp counselor job pays a lower hourly rate than Mia’s lifeguard job.

The conversion of a fraction number with denominator 5 and numerator 2 , 2/5 in decimals is equals to the 0.4 value.

A decimal number can be defined as a number whose whole number part and fractional part are separated by a decimal point. Writing 2/5 as a decimal number by converting the denominator to powers of 10. We multiply the numerator and denominator by a number so that the denominator is a power of 10.

2/5 = (2 × 2) / (5 × 2) = 4/10

Now move the decimal point to the left as many places as there are zeros in the denominator, which is a power of 10.

The decimal moved one place to the left because the denominator was 10. Therefore, 4/10 = 0.4. Hence, required value is 0.4.

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Therefore, the triple integral ∭D y dv over the region D = {(x, y, z): x² + y² + z² ≤ 1, x ≥ 0, y ≥ 0, z ≤ 0} is equal to -yπ/4.

To evaluate the triple integral ∭D y dv in the given region D = {(x, y, z): x² + y² + z² ≤ 1, x ≥ 0, y ≥ 0, z ≤ 0}, we need to determine the limits of integration for each variable.

In cylindrical coordinates, the region D can be described as follows:

The radius of the cylinder is 1, as given by x² + y² ≤ 1.

The height of the cylinder is limited by z ≤ 0.

The region is restricted to the first octant, so x ≥ 0 and y ≥ 0.

Therefore, the limits of integration for each variable are:

For z: -∞ to 0

For ρ (radius): 0 to 1

For θ (angle): 0 to π/2

The integral can be written as:

∭D y dv = ∫₀^(π/2) ∫₀¹ ∫₋∞⁰ y ρ dz dρ dθ

Integrating with respect to z:

∫₋∞⁰ y ρ dz = ∫₋∞⁰ y ρ (-1) dρ = ∫₀¹ -yρ dρ = -y/2

Substituting this result back into the integral:

∫₀^(π/2) ∫₀¹ ∫₋∞⁰ y ρ dz dρ dθ = ∫₀^(π/2) ∫₀¹ -y/2 dρ dθ

Integrating with respect to ρ:

∫₀¹ -y/2 dρ = -(y/2) [ρ]₀¹ = -(y/2) (1 - 0) = -y/2

Substituting this result back into the integral:

∫₀^(π/2) ∫₀¹ -y/2 dρ dθ = ∫₀^(π/2) (-y/2) dθ

Integrating with respect to θ:

∫₀^(π/2) (-y/2) dθ = (-y/2) [θ]₀^(π/2) = (-y/2) (π/2 - 0) = -yπ/4

Therefore, the triple integral ∭D y dv over the region D = {(x, y, z): x² + y² + z² ≤ 1, x ≥ 0, y ≥ 0, z ≤ 0} is equal to -yπ/4.

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Check the picture below.

\((\sqrt{3})^2=(x+2)(x)\implies 3=x^2+2x \\\\\\ 0=x^2+2x-3\implies 0=(x-1)(x+3)\implies x= \begin{cases} ~~ ~1 ~~ \checkmark\\\\ -3 ~~ \bigotimes \end{cases}\)

notice, the negative value doesn't apply in this case.

Answer:

I mean we don’t have to use the net becuase there is a shape right there already so the answer is 280 m for SA

Step-by-step explanation:

So find 5*6 first aAnd you’d get 30

30*2 becuase there are 2 sides, 60

10*6 is 60

60*2 is 120

5*10 is 50

50*2 is 100

now add them all up

you’d get 280 inches :)

Answer:

That they have the same length

Step-by-step explanation:

What does it mean for two segments to be congruent?

Congruent segments are segments that have the same length. ≅ Points that lie on the same line are called collinear. A theorem is a mathematical statement that can be proved. The midpoint of a segment is a point that divides the segment into two congruent segments.

Answer:

tada

Step-by-step explanation:

y decreases

exponential decay, there for the function is exponential

y > 0

y=8

x=1,y=5

The given line y = -2x + 3 will cross the y-axis at (0, 3).

A coordinate plane is a two-dimensional plane that consists x-axis and a y-axis. These are perpendicular to each other and will be intersected at the point called the origin.  

The coordinates of the point that lies on the y-axis are (0, y), Similarly, the coordinates of the point that lies on the x-axis are (0, x).    

Here we have

The equation of the line is y = -2x + 3  

To find the required point take x = 0

=> y = -2(0) + 3

=> y = 0 + 3

=> y = 3

Therefore,

The given line y = -2x + 3 will cross the y-axis at (0, 3).

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Answer:

1) 4

2) 1

3) -7

4) 13

Step-by-step explanation:

Instructions:

a) Subtract or add the slope from each side

( it doesn't matter which one you pick )

b) Subtract or add the # next to the slope from each side

( it doesn't matter which one you pick )

c) Divide Each number by the slope

d You have you answer

____________________________________________

1) 9x - 35 = - 7x + 29

+7x + 7x

_____________________

16x - 35 = 29

+ 35 +35

_____________________

16x = 64

_____________________

16 16

x = 4

2). - 2x - 2 = 9x - 13

+2x +2x

_____________________

- 2 = 11x - 13

+ 13 + 13

_____________________

11 = 11x

_____________________

11 11

1 = x

3). 3x + 29 = - 5x - 27

+5x + 5x

_____________________

8x + 29 = - 27

-29 -29

_____________________

8x = -56

_____________________

8 8

x = -7

4). x - 11 = 3x - 37

- x - x

______________________

-11 = 2x - 37

+37 +37

______________________

26 = 2x

_______________________

2 2

13 = x

Hope this helps! (:

Answer:

I cant see the photo

Step-by-step explanation:

The label covers 11,936 over 7 square centimeters of the wheel.

The cylindrical-shaped wheel of cheese has a radius of 22 centimeters and a height of 16 centimeters. The label covers the entire wheel except the circular top and bottom. Therefore, the area covered by the label is the lateral surface area of the cylinder.

The lateral surface area of a cylinder can be calculated using the formula 2πrh, where r is the radius of the base, h is the height, and π is approximately equal to 22/7.

Substituting the given values, we get:

Lateral surface area = 2 × (22/7) × 22 × 16

Lateral surface area = (44/7) × 22 × 16

Lateral surface area = 1,936 square centimeters (approx.)

Therefore, the label covers approximately 1,936/7 square centimeters of the wheel. The closest option is (C) 1,936 over 7 square centimeters.

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Answer:

The center of this circle is (5, -4) and the radius is 1.

Step-by-step explanation:

First regroup these terms according to x and y :

x^2 - 10x + y^2 + 8y = -40

Next, complete the square for x^2 - 10x:  x^2 - 10x + 5^2 - 5^2.

and the same for y^2 + 8y:  y^2 + 8y + 16 - 16

Substituting these results into x^2 - 10x + y^2 + 8y = -40, we get:

x^2 - 10x + 5^2 - 5^2 y^2 + 8y + 16 - 16 = -40.

Next, rewrite x^2 - 10x + 25 and y^2 + 8y + 16 as squares of binomials:

Then x^2 - 10x + 5^2 - 5^2 y^2 + 8y + 16 - 16 = -40 becomes:

(x - 5)^2 + (y + 4)^2 - 25 - 16 = -40, or:

(x - 5)^2 + (y + 4)^2 = 1

This equation has the form (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center and r is the radius.  Matching like terms, we get h = 5, k = -4 and r = 1.

The center of this circle is (5, -4) and the radius is 1.

Answer:

Center (5,-4) Radius = 1

Step-by-step explanation:

Put it in the form of the standard circle equation after dividing everything by 2. (-10x/2=-5x) (8y/2=4y) Since the radius wasn't given, it's just going to be a 1.

(x-5)^2+y(-(-4))^2 = 1^2

Hence, center (5, -4) and radius 1.

The Latin square that is balanced for residual effects is Latin Square 1.

To determine whether a Latin square is balanced for residual effects, we need to check if the order effects and carryover effects are equal across all rows and columns.

In Latin Square 1:

Order effects: Each treatment appears once in each row and column. Therefore, there are no order effects.

Carryover effects: Each treatment follows every other treatment once in each row and column. Therefore, there are no carryover effects.

Since there are no order or carryover effects in Latin Square 1, it is balanced for residual effects.

In Latin Square 2:

Order effects: Treatment A appears twice in row 1, while treatment D appears twice in row 2. Therefore, there are order effects.

Carryover effects: Treatment C follows treatment A twice in row 3, but only once in row 2. Therefore, there are carryover effects.

Since there are order and carryover effects in Latin Square 2, it is not balanced for residual effects.

Therefore, the Latin square that is balanced for residual effects is Latin Square 1.

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Answer:

I think it is complement. Not so sure so sorry If i get it wrong I haven't done this in 2 or 3 years

Step-by-step explanation:

Answer is : Cos L = 55/73.

This scenario is described by the following inequality:

\(2.5 + 5B \leq 21\)

-------------------------

\(T = 2.5 + 5B\)

-------------------------

\(T \leq 21\)

Replacing the equation for T, the inequality is:

\(2.5 + 5B \leq 21\)

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Answer:

1) is a

2) is 9

Step-by-step explanation:

the subgroups of Z/6Z are: - The trivial subgroup {0} - The entire group {0, 1, 2, 3, 4, 5} - The subgroups generated by 2 and 4, which are {0, 2, 4} and {0, 4}, respectively. - The subgroup generated by 3, which is {0, 3}.

To write down the subgroups of Z/6Z, we can start by listing out all the possible elements in Z/6Z, which are {0, 1, 2, 3, 4, 5}. Then, we can group these elements together based on their common factors.

The trivial subgroup is always present in any group, which is the subgroup containing only the identity element (in this case, 0).

Next, we can consider the subgroups generated by each element in the group. For example, the subgroup generated by 1 would be {0, 1, 2, 3, 4, 5} since we can add 1 to any element in the group and still get a valid element in the group. Similarly, the subgroup generated by 2 would be {0, 2, 4} since adding 2 repeatedly will only cycle through those three elements. We can continue this process for each element in the group.

So, the subgroups of Z/6Z are:
- The trivial subgroup {0}
- The entire group {0, 1, 2, 3, 4, 5}
- The subgroups generated by 2 and 4, which are {0, 2, 4} and {0, 4}, respectively.
- The subgroup generated by 3, which is {0, 3}.

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The estimated value of the explanatory variable is not statistically significant at the 5%-level if a. the t-statistic is greater than 2.5.

The t-test is a hypothesis testing technique used to decide whether the estimated coefficient of a linear regression model is statistically significant or not. The t-value is used to measure the size of the difference between the estimated coefficient and the hypothesized value. When the t-value exceeds a critical value, such as 2.5, the estimated value of the explanatory variable is not significant at the 5%-level. It implies that the null hypothesis, which assumes that the explanatory variable's coefficient is zero, cannot be rejected.

The p-value is a measure of the probability of obtaining a more extreme value of the test statistic than the observed value if the null hypothesis is true. A small p-value implies that the null hypothesis should be rejected. When the p-value is less than 0.05, it means that the estimated value of the explanatory variable is significant at the 5%-level.

The confidence interval is a range of values that is expected to include the true value of the population parameter with a specified level of confidence. A 95% confidence interval means that the true value of the population parameter lies within the range 95% of the time. The 95% confidence interval does not contain zero implies that the estimated value of the explanatory variable is statistically significant at the 5%-level since it suggests that the population parameter is different from zero at the 5%-level. Conversely, if the 95% confidence interval contains zero, the estimated value of the explanatory variable is not statistically significant at the 5%-level since it means that the population parameter is not different from zero at the 5%-level. Therefore, it is essential to examine the t-statistic, p-value, and confidence interval while conducting hypothesis testing to make an informed decision.

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Answer:

there will only be one 3

Step-by-step explanation:

see cause the first 3 of both numbers are 2 but only the last one of both numbers are 3 .

Check the picture below.

well, we know the angle's cosine and sine or namely adjacent and opposite sides, let's get the hypotenuse.

\(\textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2 \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{1}\\ b=\stackrel{opposite}{-8}\\ \end{cases} c=\sqrt{1^2+(-8)^2}\implies c=\sqrt{65} \\\\[-0.35em] ~\dotfill\\\\ csc(\theta )=\cfrac{\stackrel{hypotenuse}{\sqrt{65}}}{\underset{opposite}{-8}}\implies csc(\theta )=-\cfrac{\sqrt{65}}{8}\)

Answer:

$139.84

Step-by-step explanation:

if you do 18.75 × 3 it equals 56.25

add up 56.25 + 23.60 + 59.99 and it equals 139.84

Hope this helps!

Answer:

A) 200 students

B) 24

C) 46%

D) 46% are driven by car

Step-by-step explanation:

The probability that at least 4 of the next 5 flights at the airline will be overbooked will be 0.446.

Its simple notion is that something will most likely occur. The favorable event's proportion to the overall number of occurrences.

Based on the histogram. Then the probability that at least 4 of the next 5 flights at the airline will be overbooked will be

The probability of 4 flights will be overbooked = P(4) = 0.332

The probability of 5 flights will be overbooked = P(5) = 0.114

Then the probability that at least 4 of the next 5 flights at the airline will be overbooked will be

P(X ≥ 4) = P(4) + P(5)

P(X ≥ 4) = 0.332 + 0.114

P(X ≥ 4) = 0.446

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The confidence interval is (5.0, 5.4)

To determine the confidence interval, we have that

First, determine the mean, we get;

The sample mean is expressed as;

Mean = (5.3 + 5.0 + 5.1 + 5.3) / 4 = 5.2

Then, determine the standard deviation, we have;

standard deviation = sqrt[((5.3-5.2² + (5.0-5.2)² + (5.1-5.2)² + (5.3-5.2)^²)/3]

Square the value and divide by the divisor, we have;

standard deviation = 0.1

The 95% confidence interval for the mean weight of all bags of tomatoes is then determined as;

CI = mean  ± z×(s/√n)

Substitute the values, we get;

CI = 5.2 ± 1.96×(0.1/√4)

Divide the values, we have;

= (5.0, 5.4)

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Answer:

Step-by-step explanation:

Sorry I can't explain how it is done. It is very difficult to explain on paper.

If demand or annual usage increases by 10 percent, the Economic Order Quantity (EOQ) will increase. The EOQ model is used in inventory management to determine the optimal order quantity that minimizes total inventory costs.

The Economic Order Quantity (EOQ) is a model used in inventory management to determine the optimal order quantity that minimizes total inventory costs. It takes into account factors such as demand, holding costs, and ordering costs. When demand or annual usage increases by 10 percent, it means that more units are being consumed or sold within a given time period.

With an increase in demand, the EOQ will also increase. This is because the EOQ formula takes into consideration the trade-off between holding costs and ordering costs. Holding costs are the costs associated with holding inventory, such as warehousing and insurance, while ordering costs are the costs incurred when placing an order, such as administrative and transportation costs.

When demand increases, more units need to be ordered to meet the higher demand. This results in an increase in ordering costs, as more frequent orders will need to be placed. Consequently, the EOQ will increase to find the new optimal order quantity that balances the increased ordering costs with the holding costs.

In summary, if demand or annual usage increases by 10 percent, the EOQ will increase due to the need to order more frequently to meet the higher demand, resulting in increased ordering costs. This adjustment ensures that the inventory management system remains efficient and cost-effective.

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Answer:

Let's take the angle LEFT to p to be "x".

80+30+x = 180

110+x = 180

x = 70

Finding p:

90+70+p = 180     (REASON: linear pair)

160+p = 180

p = 20

THEREFORE, THE VALUE OF 'p' IS 20°

Answer:29.2

Step-by-step explanation:

Answer:29.2m

Step-by-step explanation:

The Number of sodas sold: 174,

The number of hot dogs sold: 58.

Each term in a linear equation has an exponent of 1, and when this algebraic equation is graphed, it always produces a straight line. It is called a "linear equation" for this reason.

Both linear equations with one variable and those with two variables exist.

Given a vendor sold a combined total of 232 sodas and hot dogs.

let S for the number of sodas sold and H for the number of hot dogs sold,

S + H = 232

The number of sodas sold was three times the number of hot dogs sold

S = 3H

substitute the values,

S + H = 232

3H + H = 232

4H = 232

H = 232/4

H = 58

and the number of sodas sold

S = 3H

S = 3*58

S = 174

Hence the number of sodas sold = 174,

and the number of hot dogs sold = 58.

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Answer:

(1) To prove that for any integer n, there exist two integers a and b of opposite parity such that an + b is an odd integer, we can consider two cases: if n is even, then we can choose a = 1 and b = 1, which are both odd, and their sum will be even. Then, we can add another odd number, such as 1, to the sum to make it odd. Therefore, we have an + b = n + 2, which is odd. If n is odd, then we can choose a = 1 and b = −1, which are of opposite parity, and their sum will also be odd. Then, we can add (n + 1) to the sum to make it equal to an + b = n + 1. Therefore, we have proven the statement for both even and odd n.

(2) To prove the contrapositive of the statement "If p is a prime greater than or equal to 5, then either 3 | (p+2) or 3 | (p-2)", we assume that p is a prime greater than or equal to 5 and that 3 does not divide (p+2) or (p-2). Since p is odd, it can be written as p = 3k + 1 or p = 3k + 2 for some integer k. If p = 3k + 1, then p+2 = 3k + 3 = 3(k+1), which is divisible by 3. This contradicts our assumption that 3 does not divide (p+2). Similarly, if p = 3k + 2, then p-2 = 3k, which is divisible by 3, again contradicting our assumption. Therefore, we have proven the contrapositive, which implies the original statement.

(3) To prove by contradiction that log3045 is irrational, we assume that log3045 is a rational number and can be expressed as a ratio of two integers, say log3045 = p/q, where p and q are coprime integers. Then, we can exponentiate both sides of this equation to get 45 = 3^(p/q). Taking the qth power of both sides, we get 45^q = 3^p. Since 3 and 45 are coprime, this implies that both q and p must be multiples of each other

Step-by-step explanation:

Answer:

All pairs of corresponding sides are congruent

Step-by-step explanation:

∠A≅∠D

∠B≅∠E

∠C≅∠F

Equation that has the specified asymptotes for the translation of y=2/x. x=4 and y=-8  is :

y = 2 / x- 4   -  8

The graph is shifted by that many units in the positive direction if you deduct a constant from your original function's x.

The original function's graph is shifted downward by that many units if a constant is subtracted from the y value.

Your first formula was y=2/x. The vertical asymptote is discovered when the denominator's root is solved for. It is x=0 in this instance, or the y-axis.

And when x changes to ∞, y=2/∞=0. This indicates that the y-axis, or your horizontal asymptote, is at y=0.

After seeing the first graph

Now, you can see the transformation of y=2/x below. As is evident, it has shifted 2 units to the right and 8 units down with vertical asymptote at x=4 and horizontal asymptote at y=−8.

you can see the second graph here...

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