I really need to pass chem, someone please help me! <3

Answer

mass of Carbon = 0.437 g

Explanation

Given:

mass of cinnamaldehyde = 0.5347 g

mass of CO2 = 1.6024 g

mass of H2O = 0.2916 g

moles of CO2 = 0.036410 mol

Required: The mass of C, in cinnamaldehyde

Solution:

mass of C in cinnamaldehyde sample = mass of C in CO2

Now that we know the moles of CO2, we can calculate the mass of C

0.036410 mol CO2 x 12.01 g/mol C = 0.437 g of C

Explanation:

Manganese exhibit the largest number of oxidation states. It shows the oxidation states 2+,+3,+4,+5,+6 and +7. The reason is the maximum no. of unpaired e

−

s present in the outermost shell. i.e. 3d

9

4S

2

.

Answer: The lewis dot structure is attached below.

Explanation:

A Lewis dot structure is defined as the representation of atoms having electrons around the atom where electrons are represented as dots.

A ketene is an organic compound having general formula R′R″C=C=O, where R and R' are two different/same monovalent chemical groups.

The given chemical compound having formula \(C_2H_2O\) is represented as \(H_2-C=C=O\).

Total number of unshared electrons = 4 (left on oxygen atom only)

The lewis dot structure of \(C_2H_2O\) is given in the image below.

The balanced molecular equation for the reaction between sodium hydroxide (NaOH) and aluminum chloride (\(AlCl_3\)) in aqueous solution can be written as follows: 2NaOH(aq) + 3\(AlCl_3\)(aq) → 3NaCl(aq) + \(Al(OH)_3\)(s)

In this reaction, sodium hydroxide (NaOH) reacts with aluminum chloride (\(AlCl_3\)) to form sodium chloride (NaCl) and aluminum hydroxide (\(Al(OH)_3\)). The coefficients in the balanced equation indicate the stoichiometric ratio between the reactants and products.

The physical states of the substances are indicated by the symbols (aq) for aqueous solutions and (s) for the solid precipitate.

The reaction is a double-displacement reaction, also known as a precipitation reaction. Double-displacement reactions involve the exchange of ions between two compounds, resulting in the formation of a precipitate.

In this case, sodium hydroxide and aluminum chloride react to form sodium chloride and aluminum hydroxide, with aluminum hydroxide being the white solid precipitate.

It's worth noting that the actual reaction might involve hydrated forms of the compounds, such as NaOH·x\(H_2O\) and \(AlCl_3\)·y\(H_2O\). However, for simplicity, these hydrated forms are not included in the balanced equation.

Overall, the balanced equation represents the chemical reaction between sodium hydroxide and aluminum chloride, showing the reactants, products, and their stoichiometric ratios.

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Answer:

4.50 L

Explanation:

First we calculate how many moles are there in 3.84 L of a 8.50 mol/L solution:

Now, keeping in mind that

we can calculate the volume of a 7.25 mol/L solution that would contain 32.64 moles:

So we could take 4.50 L of the 7.25 mol/L solution and evaporate the solvent until only 3.84 L remain.

The name of the compound from the structure that we can see in the question is;

4,4-dibromohex-2one

The International Union of Pure and Applied Chemistry (IUPAC) established a systematic set of guidelines for naming organic compounds.

Find the compound's longest continuous chain of carbon atoms. The compound's name is derived from this chain, which also acts as the compound's parent chain.

Assign a number to each carbon atom in the parent chain to give each carbon atom in the compound a special identification. The end that is closest to the functional group or substitutes is where the numbering begins.

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Answer:

conservation of mass

The formula of the ionic compound consisting of the positive ion to the left of the box and the negative ion above the box are as follows:

MgCl₂, MgS, MgF₂, Mg₃N₂, MgO, Mg₃P₂

CsCl, Cs₂S, CsF, Cs₃N, Cs₂O, Cs₃P

CrCl₃, Cr₂S₃, CrF₃, CrN, Cr₂O₃, CrP

NaCl, Na₂S, NaF, Na₃N, Na₂O, Na₃P

ZnCl₂, ZnS, ZnF₂, Zn₃N₂, ZnO, Zn₃P₂

AlCl₃, Al₂S₃, AlF₃, AlN, Al₂O₃, AlP

Ionic compounds are pure substances made up of chemically bound ions. Examples include his binary compounds such as table salt and polyatomic compounds such as sodium sulfate. All ionic compounds form crystal lattices. Ionic compounds are pure substances formed mainly by positive and negative ionic attraction. Compounds are formed mainly by ions, although a small amount of electron sharing always occurs.

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Answer: For number 8. I think only one if not i'm so sorry also you would need 143. 0914

Explanation:

Answer:

Hello! :p

I hope this helps! Thank you so much! :)

Answer:

its A

Explanation:

The only one that makes sense

The percent yield of a chemical response is the proportion of the real yield to the hypothetical yield, communicated as a rate.

In this case, the hypothetical yield is 150 grams of sodium hydroxide, as calculated by the researcher. The genuine yield is 135 grams of sodium hydroxide, as gotten from the experiment.

The percent yield can be calculated utilizing the equation:

Percent yield = (real yield / hypothetical yield) x 100%

Substituting the values given within the issue, we get:

Percent  yield= (135 / 150) x 100%

Percent yield = 0.9 x 100%

Percent yield = 90%

Hence, the percent yield of the experiment is 90%. This implies that 90% of the hypothetical abdicate was gotten within the test.

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- In reactions 1 and 2, the highlighted atom (oxygen) is reduced.

- In reaction 3, the highlighted atom (sulfur) is neither oxidized nor reduced.

- In reaction 4, the highlighted atom (oxygen) is reduced.

In the given chemical reactions, we need to identify whether the highlighted atom is being oxidized or reduced. Let's analyze each reaction individually:

Reaction 1: 4 HF (g) + SiO₂ (s) → SiF₄ (g) + 2 H₂O (g)

In this reaction, the highlighted atom is oxygen (O). Oxygen in SiO₂ undergoes a change in oxidation state from -2 to 0 in SiF₄. Therefore, the highlighted atom (oxygen) is reduced.

Reaction 2: 2 Cl (aq) + 2 H₂O (l) → 2 OH (aq) + H₂ (g) + Cl₂ (g)

In this reaction, the highlighted atom is oxygen (O). Oxygen in H₂O undergoes a change in oxidation state from -2 to -1 in OH. Therefore, the highlighted atom (oxygen) is reduced.

Reaction 3: H₂S (aq) + 2 NaOH (aq) → Na₂S (aq) + 2 H₂O (l)

In this reaction, the highlighted atom is sulfur (S). Sulfur in H₂S undergoes a change in oxidation state from -2 to -2 in Na₂S. Therefore, the highlighted atom (sulfur) is neither oxidized nor reduced.

Reaction 4: 2 H₂ (g) + O₂ (g) → 2 H₂O (g)

In this reaction, the highlighted atom is oxygen (O). Oxygen in O₂ undergoes a change in oxidation state from 0 to -2 in H₂O. Therefore, the highlighted atom (oxygen) is reduced.

To summarize:

- In reactions 1 and 2, the highlighted atom (oxygen) is reduced.

- In reaction 3, the highlighted atom (sulfur) is neither oxidized nor reduced.

- In reaction 4, the highlighted atom (oxygen) is reduced.

It's important to note that oxidation and reduction involve changes in the oxidation state of atoms, indicating the gain or loss of electrons. The analysis above is based on the change in oxidation state of the highlighted atom in each reaction.

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Answer:

I assume air pollution.

Explanation:

If you incinerate something, usually fire or some kind of heating element is used. A byproduct of fire and/or burning is smoke, which can pollute the air.

Answer:

A. Air pollution

Explanation:

In the incineration Factories they produce items And Air pollution

The waves that  has the greatest wavelength is Wavelength shown with 1 wavelength stretched over a long distance.

A wave could be a disturbance or variety that voyages through a medium or space, carrying vitality without transporting matter. Waves can take different shapes and happen totally different sorts of waves, counting mechanical waves and electromagnetic waves.

Mechanical waves require a medium to propagate, meaning they require a substance like water, discuss, or a strong fabric to transmit the wave. Illustrations of mechanical waves incorporate water waves, sound waves, and seismic waves. In these waves, particles of the medium sway or vibrate in a design, exchanging energy from one molecule to another.

Electromagnetic waves, on the other hand, don't require a medium and can travel through vacuum, such as in space. Electromagnetic waves comprise of electric and attractive areas swaying opposite to each other and to the heading of wave engendering. Illustrations of electromagnetic waves incorporate obvious light, radio waves, microwaves, infrared waves, bright waves, X-rays, and gamma beams.

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Answer:

b. The splitting of the d-orbitals is smaller in the [Ni(Cl)6]4- complex than in the [Ni(en)3]2+ complex.

Explanation:

The spectrochemical series is an arrangement of ligands in increasing order of their magnitude of crystal field splitting.

Ligands that occurs towards the right in the series are called strong field ligands and they tend to cause a greater magnitude of crystal field splitting. Ligands that occur towards the left hand side in the series are called weak field ligands and they tend to cause a lesser magnitude of crystal field splitting.

Since Cl^- is a weak field ligand, it causes a lesser magnitude of d orbital splitting compared to ethylenediammine (en) which causes a greater magnitude of d orbital splitting.

Hence; the splitting of the d-orbitals is smaller in the [Ni(Cl)6]4- complex than in the [Ni(en)3]2+ complex.

Answer:

Have only single bonds.

Explanation:

Hello,

In this case, we need to remember that saturation is a state at which a carbon chain contains no insaturations, that is neither double nor triple bonds such case are alkenes and alkynes, but saturations only which are characterized by the presence of single bonds between adjacent carbon atoms. Such is the case of ethane (CH₃-CH₃), propane (CH₃-CH₂-CH₃), butane (CH₃-CH₂-CH₂-CH₃) and so on.

Best regards.

3.21 grams of Aluminum Sulfate are got when 4 g of Aluminum Nitrate reacts chemcially with 3 g of Sodium Sulfate.

The equation given is not balanced. Thus,  when balanced the equation becomes:

2 Al(NO₃)₃ + 3 Na₂SO₄ → Al₂(SO₄)₃ + 6 NaNO₃

The molar mass of Al(NO₃)₃ is:

Al(NO₃)₃ = 1(Al) + 3(N) + 9(O) = 213 g/mol

The molar mass of Na₂SO₄ is:

Na₂SO₄ = 2(Na) + 1(S) + 4(O) = 142 g/mol

From the balanced equation, we can see that 2 moles of Al(NO₃)₃ react with 3 moles of Na2SO4 to produce 1 mole of Al₂(SO₄)₃. Therefore, we can calculate the number of moles of Al(NO₃)₃ and Na₂SO₄ that react:

Number of moles of Al(NO₃)₃ = 4 g / 213 g/mol = 0.0188 mol

Number of moles of Na₂SO₄ = 3 g / 142 g/mol = 0.0211 mol

From the balanced equation, we can see that 2 moles of Al(NO₃)₃ produce 1 mole of Al₂(SO₄)₃. Therefore, the number of moles of Al₂(SO₄)₃ produced is:

Number of moles of Al₂(SO₄)₃ = 0.0188 mol / 2 * 1 = 0.0094 mol

The molar mass of Aluminum Sulfate (Al₂(SO₄)₃) is:

Al₂(SO₄)₃ = 2(Al) + 3(S) + 12(O) = 342 g/mol

Therefore, the mass of Aluminum Sulfate produced is:

Mass of Al₂(SO₄)₃ = Number of moles of Al₂(SO₄)₃ * Molar mass of Al₂(SO₄)₃

= 0.0094 mol * 342 g/mol

= 3.21 g

Hence, 3.21 grams of Aluminum Sulfate are liberated when 4 g of Aluminum Nitrate change state with 3 g of Sodium Sulfate.

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The difference between all three Magnesium, Mg isotopes is in; the number of neutrons.

Isotopy is a property of elements in which case the element has two or more types of atoms that have the same atomic number and hence, same position in the periodic table, but differ in nucleon numbers due to different numbers of neutrons in their nuclei.

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Answer:

Filter it

Explanation:

Answer:

lungs

Explanation:

Answer:

The answer is Diffusion.

Answer:

Hypertonic

Explanation:

Answer:

Exothermic Reaction

Product  = Calcium hydroxide + hydrogen

Explanation:

Answer:

C3H5NO2

Explanation:

C = 41.37%;

H = 5.75% ;

N= 16.09 %;

O= (100 - 41.37 - 5.75 - 16.09)% = 36.79 %.

In 100 g of substance we have

C = 41.37 g;

H = 5.75 g ;

N= 16.09 g;

O = 36.79 g.

Molar mass (C) = 12 g/mol;

Molar mass(H) =1 g/mol;

Molar mass(N)= 14 g/mol;

Molar mass(O) = 16 g/mol.

C = 41.37 g* 1 mol/12g = 3.4475 mol;

H = 5.75 g *1 mol/1g = 5.75 mol;

N= 16.09 g*1mol/14g = 1.1493 mol;

O = 36.79 g* 1mol/16g = 2.2994 mol.

The Empirical formula shows ratio of moles of elements in the substance , so

C : H : N : O = 3.4475 mol : 5.75 mol : 1.1493 mol : 2.2994 mol =

= (3.4475 mol /1.1493 mol) : (5.75 mol/1.1493 mol) : (1.1493 mol /1.1493 mol) :   :( 2.2994 mol/1.1493 mol) = 3 : 5 : 1 : 2

C : H : N : O = 3 : 5 : 1 : 2

C3H5NO2

The column 1 has the value of Isotope, column 2 has the value of mass in atomic mass units, and column 3 has the value of abundance and the average atomic mass of strontium is 87.47 amu.

To calculate the average atomic mass of strontium using the given information, we need to multiply the mass of each isotope by its abundance and then sum up these values. Here's the calculation:

Isotope | Mass (amu) | Abundance

^84Sr | 83.913428 | 0.56%

^86Sr | 85.909273 | 9.86%

^87Sr | 86.908902 | 7.00%

^88Sr | 87.905625 | 82.58%

To find the average atomic mass, we multiply each isotope's mass by its abundance (in decimal form) and sum up the values:

Average atomic mass = (\(Mass of ^{84Sr}\) × \(Abundance of^{84Sr}\)) + (\(Mass of ^{86Sr}\)× \(Abundance of^{86Sr}\)) + (\(Mass of ^{87Sr}\) × \(Abundance of^{87Sr}\)) + (\(Mass of ^{88Sr}\) × \(Abundance of^{88Sr}\))

Average atomic mass = (83.913428 amu × 0.0056) + (85.909273 amu × 0.0986) + (86.908902 amu × 0.0700) + (87.905625 amu × 0.8258)

Calculating this expression yields:

Average atomic mass = 0.469901638 + 8.468098826 + 6.08462314 + 72.44409075

= 87.466714354 amu

Rounding the result to two decimal places, the average atomic mass of strontium is approximately 87.47 amu.

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Answer:

need what?? I would love to help though!

Answer:

Explanation:

IN order for us to help you, we would like to know the question.

Answer:

and is capillaries

Explanation:

hope it helps

Answer:

Explanation:

The amount of heat that must be added to heat 50 grams of water from 42.0° C to 100.0° C can be calculated using the specific heat capacity formula: Q = m*C*ΔT, where Q is the heat required, m is the mass of the water, C is the specific heat capacity of water, and ΔT is the temperature change.

Using the values given, we have:

Q = 50 g * 1 cal/g °C * (100.0°C - 42.0°C)

Q = 50 g * 1 cal/g °C * 58.0°C

Q = 2,900 calories

Therefore, the amount of heat that must be added to heat 50 grams of water from 42.0° C to 100.0° C is 2,900 calories. The answer is option (C).

Answer: 8 (feet)

Explanation:

24 inches = 2 feet

48 inches = 4 feet

12 inches = 1 foot

To find volume you do Base * Width * Height

2*4*1 = 8

Hope this helps!

The correct answer is  8 (feet).

How to calculate ?

Therefore, 2*4*1 = 8

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The goals of scientific research are to further knowledge and address pressing issues. This assisted us in comprehending the state of the art.

Chemical elements with an atomic number greater than 103 are referred to as superheavy elements, transactinide elements, transactinides, or super-heavy elements. The periodic table's superheavy elements are the ones that follow the actinides; lawrencium is the final actinide.

Superheavy elements are transuranium elements by definition, meaning they have atomic numbers higher than uranium (92). Lawrencium could also be added to conclude the 6d series, in accordance with the definition of 3 groups that the authors use. The goals of scientific research are to further knowledge and address pressing issues. This assisted us in comprehending the state of the art.

Therefore, the goals of scientific research are to further knowledge and address pressing issues. This assisted us in comprehending the state of the art.

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Answer:

throughout the metallic structure allowing the atoms to slide past each other. This sliding is why metals are ductile and malleable. Ionic compound must break bonds to slide past one another, which causes the ionic material to split and crack.

Explanation:

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