I only need help with b as it isnt right /((

Answer:

405.6

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The stream velocity has no influence on the amount of dissolved load it contains. The amount of dissolved material depends on erosion and deposition carried out in the watercourse. These are affected by factors such as the slope of the land, the resistance of the material to erosion, the size of the sediments transported, etc.

Stream velocity plays an important role in the transport of sediments and dissolved loads in a watercourse. It affects the erosion and deposition processes that occur in the watercourse, which in turn affect the amount of sediment and dissolved load that is carried by the stream. For example, faster stream velocities can cause more erosion of the stream bed, leading to more material being carried in the water.

Sediment is any particulate matter that is transported by a fluid, and it can come in many different forms. The three main types of sediment are:

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The change in Gibbs free energy (ΔG) for the reaction at a temperature of 25°C is 3.27 kJ.

The equation for the change in Gibbs free energy (ΔG) is given by ΔG = ΔH - TΔS. The values of ΔH° and ΔS° can be used to calculate ΔG at a temperature of 25°C, which is 298 K. The reaction is:H2(g) + I2(g) → 2HI(g)The values given are:ΔH° = 52.96 kJΔS° = 166.4 J/KTo convert ΔH° from kJ to J, multiply by 1000:ΔH° = 52.96 kJ × 1000 J/kJ = 52960 J  Substituting the values into the equation, we get:ΔG = ΔH - TΔSΔG = (52960 J) - (298 K)(166.4 J/K)ΔG = 52960 J - 49687.2 JΔG = 3267.8 J or 3.27 kJ (to two significant figures).

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At a temperature of 25°C, the change in Gibbs free energy (\(\Delta G\)) for the reaction \(H_2(g) + I_2(g) \rightarrow 2HI(g)\) is 3355.04 J.To calculate the change in Gibbs free energy (\(\Delta G\)) for the reaction \(H_2(g) + I_2(g) \rightarrow 2HI(g)\) at a temperature of 25°C, we can use the equation:

\(\Delta G = \Delta H - T \cdot \Delta S\)

where \(\Delta H\) is the change in enthalpy, \(\Delta S\) is the change in entropy, and \(T\) is the temperature in Kelvin.

Given that \(\Delta H^\circ = 52.96 \, \text{kJ}\) and \(\Delta S^\circ = 166.4 \, \text{J/K}\), we need to convert the units to match.

\(\Delta H^\circ\) should be in J, so we multiply it by 1000:

\(\Delta H = 52.96 \, \text{kJ} \times 1000 = 52960 \, \text{J}\)

The temperature \(T\) is given as 25°C, which needs to be converted to Kelvin:

\(T = 25 + 273.15 = 298.15 \, \text{K}\)

Now, we can calculate \(\Delta G\) using the equation mentioned above:

\(\Delta G = \Delta H - T \cdot \Delta S\)

\(\Delta G = 52960 \, \text{J} - 298.15 \, \text{K} \times 166.4 \, \text{J/K}\)

Calculating the expression above:

\(\Delta G = 52960 \, \text{J} - 49604.96 \, \text{J}\)

\(\Delta G = 3355.04 \, \text{J}\)

Therefore, at a temperature of 25°C, the change in Gibbs free energy (\(\Delta G\)) for the reaction \(H_2(g) + I_2(g) \rightarrow 2HI(g)\) is 3355.04 J.

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Answer:

Clockwise : going the way the clock hand goes (going right)

Counterclockwise : opposite of clock hand (going left)

The opposite of being short $4.28 would be having $4.28 or more. That is a surplus or extra of $4.28.

Surplus refers to an amount or quantity that is left over or in excess of what is needed or used. It can refer to various things, such as:

In finance, a surplus refers to an excess of revenue over expenses, or an excess of assets over liabilities. It means having more of something than is necessary or expected.

Therefore, the opposite of being short $4.28 would be having $4.28 or more. This is often referred to as having a surplus or extra of $4.28.

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The required difference of the polynomial functions is -9s^2 + 4s - 2

Given the following difference of polynomial expressed as:

(–6s2 + 12s – 8) – (3s2 + 8s – 6)

We are to find the difference

(–6s2 + 12s – 8) – (3s2 + 8s – 6)

Expand

–6s^2 + 12s – 8 - 3s^2 - 8s + 6

Collect the like terms

–6s^2- 3s^2 + 12s - 8s - 8 + 6

-9s^2 + 4s - 2

Hence the required difference of the polynomial functions is -9s^2 + 4s - 2

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complete question

Find each difference.

(–6s2 + 12s – 8) – (3s2 + 8s – 6) =

–9s2 + 4s – 14

–9s2 + 4s – 2

–9s2 + 20s – 14

–9s2 + 20s – 2

The quadratic regression equation that best models this set of data is given as follows:

D. H(x) = -7x² + 4x + 28.

To find the quadratic regression equation, we need to insert the points (x,y) into a quadratic regression calculator.

We use a quadratic regression for this problem, instead of linear regression, as there is a vast difference in the first differences of the function.

The points for this problem are given as follows:

(0,28), (1, 25), (2, 8), (3, -28), (4, -60), (5, -126), (6, -200), (7, -287), (8, -388).

Inserting these points into a calculator, the equation is given as follows:

H(x) = -7x² + 4x + 28.

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When x³-2x^2-15x is factored completely, one of the factors is x-5.

To factor the expression, we can use the method of grouping. We can rewrite the expression as follows:

x³-2x^2-15x = (x³-2x^2) - 15x

We can then factor the first two terms using the difference of squares:

x³-2x^2-15x = (x-2)(x^2+2x) - 15x

We can then factor the last term using the difference of squares:

x³-2x^2-15x = (x-2)(x^2+2x) - (5)(3x)

Then, we can combine the two factors to get the final answer:

x³-2x^2-15x = (x-5)(x^2+2x-3x)

The final factorization is:

x³-2x^2-15x = (x-5)(x^2-x)

So, the correct answer is (A) x-5.

Answer:

2

Step-by-step explanation:

2^-5/2^-6

= 2 ^ -5 - (-6)

= 2 ^ -5 + 6

= 2 ^ 1

= 2

In order to test if the supervisor's county is different from the United States average, she will perform a two tailed test.

Here we are given the following data-

number of observations in the sample n = 795

observed value x = 150

and proportion p = 0.155

We need to test whether proportion is different from 15.5 % or not.

Thus, we will do a two tailed test with hypothesis as follows -

Null hypothesis H₀ ⇒ p = 0.155

Alternate hypothesis Hₐ ⇒ p ≠ 0.155

Hence, in order to test if the supervisor's county is different from the United States average, she will perform a two tailed test.

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The estimated rate of change of the amount of gasoline at t = 3 hours is 1/4 thousand gallons per hour, or 250 gallons per hour. the maximum amount of gasoline in the storage tank will occur at t = 10 hours.  the tangent line lies below the graph of G(t) near t = 5, indicating a lower value.

(a) To estimate the rate of change of the amount of gasoline in the storage tank at t = 3 hours, we can use the average rate of change between the points (t₁, G(t₁)) and (t₂, G(t₂)). In this case, we'll use the points (1, 18.5) and (5, 19.5) from the table.

The average rate of change is given by (G(t₂) - G(t₁))/(t₂ - t₁). Plugging in the values, we have (19.5 - 18.5)/(5 - 1), which simplifies to 1/4.

Therefore, the estimated rate of change of the amount of gasoline at t = 3 hours is 1/4 thousand gallons per hour, or 250 gallons per hour.

(b) To find the time t when the amount of gasoline in the storage tank is changing most rapidly, we can look for the maximum or minimum of the function G(t). Since G(t) represents the amount of gasoline in the storage tank, we're interested in finding the maximum.

From the given table, we observe that the values of G(t) are increasing as t increases. Therefore, the maximum amount of gasoline in the storage tank will occur at t = 10 hours.

(c) The locally linear approximation for G at t = 5 can be found using the tangent line to the graph of G at t = 5. Since G'(5) = 0.5, we have the slope of the tangent line.

Using the point-slope form of a line, we can write the equation of the tangent line as follows:

G(t) = G(5) + G'(5) * (t - 5)

Plugging in the values, we have:

G(t) = 19.5 + 0.5 * (t - 5)

To approximate the amount of gasoline at t = 7, we substitute t = 7 into the equation:

G(7) ≈ 19.5 + 0.5 * (7 - 5)

G(7) ≈ 19.5 + 1

G(7) ≈ 20.5 thousand gallons

This approximation is an underestimate for the actual amount of gasoline in the storage tank at t = 7 because the tangent line lies below the graph of G(t) near t = 5, indicating a lower value.

(d) To find the time t when the rate at which gasoline flows out of the storage tank is an absolute maximum, we need to analyze the function R(t) = 100t/(t² + 4) over the interval 0 ≤ t ≤ 10.

First, we find the critical points by setting the derivative of R(t) equal to zero:

R'(t) = 0

100(t² + 4) - 100t(2t) = 0

100t² + 400 - 200t² = 0

-100t² + 400 = 0

100t² = 400

t² = 4

t = ±2

Since the interval is restricted to 0 ≤ t ≤ 10, we disregard the negative solution and consider t = 2.

Next, we evaluate the second derivative of R(t):

R''(t) = (200t - 400)/(t² + 4)²

For t = 2, R''(2) = (400 - 400)/(2² + 4)² = 0.

Since the second derivative is zero and the function is continuous within the interval, the absolute maximum or minimum of R(t) occurs at the endpoints or critical points. Therefore, the absolute maximum occurs at t = 2 hours.

By justifying our answer through the second derivative test, we can conclude that the rate at which gasoline flows out of the storage tank is an absolute maximum at t = 2 hours.

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The required we can reject the null hypothesis and accept the alternative hypothesis.

Based on the given p-value of 0.045 and a significance level of 0.05 (or 5%), we can draw the following conclusion:

Since the p-value (0.045) is less than the significance level (0.05), we have evidence to reject the null hypothesis. In other words, there is sufficient statistical evidence to conclude that there are significant differences among the groups being compared in the ANOVA F test.

Therefore, we can reject the null hypothesis and accept the alternative hypothesis, indicating that there are statistically significant differences between at least two of the groups being compared.

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Answer:

38 & 39

Step-by-step explanation:

Answer:

98 units.

Step-by-step explanation:

Circumference = 2 * pi * radius

615.44 = 2 * 3.14 * r

r = 615.44 / (2 * 3.14)

 =2 * 3.14

 = 98 units.

Answer:

V = 108

Step-by-step explanation:

B = 9 x 4 = 36 Height of Triangular prism is 3 so 36 x 3 = 108

The mean value of the radius (r) at which you would find the electron, given the H atom wave function is 100(r), is 0.

The wave function of an electron in the hydrogen atom, denoted by Ψ, describes the probability distribution of finding the electron at different positions around the nucleus. In this case, the given wave function is 100(r), where r represents the radius.

To calculate the mean value of the radius, we need to evaluate the integral of r multiplied by the absolute square of the wave function, integrated over all possible values of r. However, the wave function 100(r) does not provide a valid description of the hydrogen atom's electron distribution. The wave function should be normalized, meaning that the integral of the absolute square of the wave function over all space should equal 1. In this case, the given wave function lacks normalization.

Since the wave function is not properly normalized, we cannot accurately calculate the mean value of the radius. Without normalization, the probability distribution described by the wave function does not provide meaningful information about the electron's position.

In summary, based on the given wave function, the mean value of the radius cannot be determined without proper normalization of the wave function. A properly normalized wave function is necessary to obtain accurate information about the electron's position.

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To determine the probability that an ADA will earn between $50 and $60 per hour, we can use the standard normal distribution and the z-score.

Given:

Mean (μ) = $52

Standard deviation (σ) = $5.50

To find the probability, we need to calculate the z-scores for the lower and upper limits, and then use the z-table or a calculator to find the corresponding probabilities.

Step 1: Calculate the z-scores

For the lower limit of $50:

z_lower = (X_lower - μ) / σ = (50 - 52) / 5.50

For the upper limit of $60:

z_upper = (X_upper - μ) / σ = (60 - 52) / 5.50

Step 2: Look up the probabilities from the z-table or use a calculator

Using the z-table or a calculator, we can find the probabilities corresponding to the z-scores.

Let's denote the probability for the lower limit as P1 and the probability for the upper limit as P2.

Step 3: Calculate the final probability

The probability that an ADA will earn between $50 and $60 per hour is the difference between P2 and P1.

P(X_lower < X < X_upper) = P2 - P1

Note: Make sure to use the cumulative probabilities (area under the curve) from the z-table or calculator.

I will perform the calculations using the given mean and standard deviation to find the probabilities. Please hold on.

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Therefore, the correct answer is (b) H(0) and H(a), where H(0) represents the null hypothesis and H(a) represents the alternative hypothesis.

Based on the given information, D represents the null hypothesis (H₀) and E represents the alternative hypothesis (Hₐ).

The null hypothesis (H₀) is a statement that there is no significant difference between the observed data and the expected results. In this case, the null hypothesis is that the population mean (μ) is greater than or equal to 1000.

The alternative hypothesis (Hₐ) is a statement that there is a significant difference between the observed data and the expected results. In this case, the alternative hypothesis is that the population mean (μ) is less than 1000.

Correct answer is (b) H(0) and H(a), where H(0) represents the null hypothesis and H(a) represents the alternative hypothesis.

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Answer:

anser A

Step-by-step explanation:

Let's fill x and y and we'll see which one is right

a) 0 = -3(-7+7)(-7+4)

<=> 0 = 3 * 0 * -3

<=> 0 = 0 => true

b) 0 = -0.5(-7-7)(-7+4)

<=> 0 = -0.5 * -14 * -3

<=> 0 =  -21 => false

c) 0 = (-7-7)(-7-4)

<=> 0 = -154 => false

d) 0 = 2(-7+7)(-7-4)

<=> 0 = 0 => true

so both a and d are right for (-7,0). Now let's for (-4,0)

a) 0 = -3(-4+7)(-4+4)

<=> 0 = 0 => true

d) 0 = 2(-4+7)(-4-4)

<=> 0 = -48 => false

Answer:

6, 7, 8, 9

Step-by-step explanation:

you plug in the number in the X column into the variable, which you divide by 4 and add 7 to your number.

Answer:

$638.16

Step-by-step explanation:

594.99x7.25%=43.17

594.99+43.17=638.18

The cost of one computer is £600 and the cost of one printer is £800.

Computing equipment is bought from a supplier. The cost of 5 Computers and 4 Printers is £6,600, and the cost of 4 Computers and 5 Printers is £6,000. Form two simultaneous equations and solve them to find the costs of a Computer and a Printer.

Let the cost of a computer be x and the cost of a printer be y.

Then, the two simultaneous equations are:5x + 4y = 6600 ---------------------- (1)

4x + 5y = 6000 ---------------------- (2)

Solving equations (1) and (2) simultaneously:x = 600y = 800

Therefore, the cost of a computer is £600 and the cost of a printer is £800..

:Therefore, the cost of one computer is £600 and the cost of one printer is £800.

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Answer:

50

Step-by-step explanation:

What I did first is I converted 72% into a decimal (I work better with decimals), giving me 0.72. Then I solved the equation 36/0.72=x.

x = 50

Answer:

Step-by-step explanation:

Let the number of questions be x.

We have:

Build an equation and solve for x:

The quadratic function given can be written in vertex form by completing the square: f(x) = -22 + 82 = -2 + (9 + 7)x - 7x2 = -2 + 9x + 7x2.

The vertex of this function can be found using the formula x = -b/2a, where a = 7, b = 9.

Thus, the vertex is (4, -2).

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The formula for the volume of a cone is:

V = (1/3)πr²h

where r is the radius of the base, h is the height of the cone, and π is pi.

In this case, the slant height is given as 17 cm, which we can use with the radius to find the height of the cone using the Pythagorean theorem:

h² = s² - r²

h² = 17² - 8²

h² = 225

h = 15

Now that we have the height, we can plug in the values for r and h into the formula for the volume:

V = (1/3)π(8²)(15)

V = (1/3)π(64)(15)

V = (1/3)(960π)

V = 320π

Therefore, the volume of the cone is 320π cubic cm. Answer: 320π.

The average of the 150 measurements is 24.33, and Quantity B with a value of 25 is greater.

To compare the averages of the 150 measurements, let's calculate the total sum of all the measurements.

For the first set of 100 measurements with an average of 23, the total sum is 100 * 23 = 2300. For the second set of 50 measurements with an average of 27, the total sum is 50 * 27 = 1350.

To find the average of all 150 measurements, we need to find the total sum of all 150 measurements. Adding the two total sums calculated above, we have 2300 + 1350 = 3650.

To find the average, we divide the total sum by the total number of measurements: 3650 / 150 = 24.33.

Comparing the average of the 150 measurements to the individual averages A and B:

Quantity A: 24.33

Quantity B: 25

Since 25 is greater than 24.33, the answer is that Quantity B is greater.

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Answer:

x = 1/2

Step-by-step explanation:

\( \frac{4}{7} x = \frac{2}{7} \\ \\ x = \frac{ \cancel2}{ \cancel7} \times \frac{ \cancel7}{ \cancel4 \: \: 2} \\ \\ x = \frac{1}{2} \)

Answer:

C

Step-by-step explanation:

3|x-2|=18-6

3|x-2|=12

|x-2|=4

Ther are two options.

First;

x-2=-4

x=-2

Second;

x-2=4

x=6

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