i need to find the slope! can u help me?

The Coefficient of xⁿ In the Expansion 1 / (1 + x + x²) is 1

A coefficient in mathematics is a multiplicative factor in a polynomial term, a series term, or an expression.

It is typically a number, but it can also be any expression. They may also be referred to as parameters

The coefficient is usually the number in front of the variable represent by an letter.

For the given problem the given letter is x and the coefficient is 1, a coefficient of 1 is most times not written and hence we know the coefficient is 1

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Answer:

-85.9 feet below sea level.

Step-by-step explanation:

Yes, These data suggest a statistically significant difference between the proportions of drug-resistant cases in the two cities.

In first city, the drug-resistant proportion is significant while In other city, It is not significant.

What is Ratio and proportion ?

A ratio is an ordered pair of numbers a and b, expressed as a / b, where b is not equal to 0. A percentage is an equation in which two ratios are made equal to one another.

Let the first city to be City A and the other city as City B.

In city A, 14 cases are of drug-resistant out of total 221 cases.

In city B, 6 cases are of drug-resistant out of total 322 cases.

We'll find the proportion of drug-resistant cases of both cities,

City A = 14 / 221 = 0.06 > 0.02

City B = 6 / 322 = 0.018 < 0.02

If use a 0.02 level of significance then,

City A has significant drug-resistant cases while City B does not have significant cases.

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Answer:

see explanation

Step-by-step explanation:

(1)

x² + 4 = 0 ( subtract 4 from both sides )

x² = - 4 ( take the square root of both sides )

x = ± \(\sqrt{-4}\) = ± 2i ← complex solutions

(2)

x² - 81 = 0 ( add 81 to both sides )

x² = 81 ( take the square root of both sides )

x = ± \(\sqrt{81}\) = ± 9 ← real solutions

Answer:

1. -2

2. 9

Step-by-step explanation:

1. 0 = x2 + 4

  -4 = x2

  \(\sqrt{-4}\) = x

x = -2

2. 0 = x2 - 81

   81 = x2

    \(\sqrt{81}\) = x

 x = 9

    MARK IT BRAINLIEST!!!

option:-

\( \large \tt{ \red{A) \: Add \: 15}}\)

Solution:-

\( \: \)

\( \: \)

\( \: \)

hope it helps! :)

The equation to predict how many hours, x, the second part of the trip will take is :x = (total distance - distance traveled in the first part) / average speed x = (125 - 75) / 50  x = 1

To predict how many hours, x, the second part of the trip will take, we can use the equation:

x = (total distance - distance traveled in the first part) / average speed

In this case, the total distance of the trip is 125 miles, and the distance traveled in the first part is the product of the average speed and the time taken for the first part, which is 50 miles/hour * 1.5 hours = 75 miles.

Substituting these values into the equation, we have:

x = (125 - 75) / 50

Simplifying the equation, we get:

x = 50 / 50

x = 1

Therefore, the equation to predict how many hours, x, the second part of the trip will take is:

x = (total distance - distance traveled in the first part) / average speed

x = (125 - 75) / 50

x = 1

This means that the second part of the trip will take 1 hour to complete after the bus stops to refuel.

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Answer: 14/6

Step-by-step explanation:

A line passes through point A(14,21). A second point on the line has an x-value that is 125% of the x-value of point A and a y-value that is 75% of the y-value of point A. Use point A to write an equation of the line in point-slope form.

The length of the fence that will be installed is equal to 75 ft to the nearest tenth of foot using sine rule of the angles.

The sine rule is a relationship between the size of an angle in a triangle and the opposing side.

Let the angle opposite side with 22ft be represented with B, side with 33ft be A and side with c be C. We shall evaluate for the angles B and C, and the side c as follows:

22/sinB° = 33/sin104°

sinB = (22 × sin104°)/33 {cross multiplication}

B = sin⁻¹(0.6469)

B = 40° approximately to the nearest whole degree.

C + 40° + 104° = 180° {sum of interior angles of a triangle}

C = 36°

33/sin104° = c/sin36°

c = (33 × sin36°)/33 {cross multiplication}

c = 19.9907

c = 20 approximately to the nearest tenth.

length of the fence = 22ft + 33ft + 20ft = 75ft.

Therefore, the length of the fence that will be installed is equal to 75 ft to the nearest tenth of foot using sine rule of the angles.

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Answer:

bgyuhjvy;uhclgcxfghvmdxultgjvffgxfbc hgv

Step-by-step explanation:

vgfdhvczczxcgfzdsdvcxfdghcbcd

The Remainder is 3 and the Quotient is 2141.

Therefore,

The given Divisor = 4 and Dividend = 8567

4 ÷ 8567

= 2141.75

The Quotient is 2141 and the Remainder is 3

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Answer:

C. Add 9.6, then divide by 3.2.

Step-by-step explanation:

\(3.2x−9.6=38.4\)

\(3.2x=38.4+9.6\)

\(3.2x=48\)

\(x = 15\)

Answer : x = 30 degrees

< JKL and < MKQ are complementary

Let < MKQ = x

Angle JKL is twice the measure of angle MKQ

JKL = 2 x MKQ

Sum of a complementary angles = 90 degrees

< JKL + < MKQ = 90

< JKL = 2MKQ

Substitute the value of < jkl

2(<2MKQ + Since, Therefore,

2x + x = 90

3x = 90

Divide both sides by 3

3x / 3 = 90/3

x = 30 degrees

Cases (b), (c), (d), (e), (f), (g), (h), and (k) violate some of the Gauss-Markov assumptions in the given model. These assumptions include the absence of heteroscedasticity, no inclusion of omitted variables that are correlated with the explanatory variables,

no presence of endogeneity, no perfect multicollinearity, and normally distributed errors. Cases (a), (i), and (j) do not violate the Gauss-Markov assumptions.

(b) Violates the assumption of homoscedasticity, as the variance of the error term differs between union and non-union members.

(c) Violates the assumption of no inclusion of omitted variables, as innate ability affects both wage and education.

(d) Violates the assumption of linearity, as taking the logarithm of wage changes the functional form of the model.

(e) Violates the assumption of normally distributed errors, as the error term does not follow a normal distribution.

(f) Violates the assumption of no inclusion of omitted variables, as every person in the sample being a union member introduces a systematic difference.

(g) Violates the assumption of no inclusion of omitted variables, as adding the square of exper as an additional explanatory variable affects the model.

(h) Violates the assumption of no inclusion of omitted variables, as adding the square of D as an additional explanatory variable affects the model.

(k) Violates the assumption of no perfect multicollinearity, as education and experience are strongly correlated.

On the other hand, cases (a), (i), and (j) do not violate any of the Gauss-Markov assumptions.

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The estimated monthly average daily radiation on a horizontal surface in June in Amman is approximately 7.35 kWh/m(^2)/day.

To estimate the monthly average daily radiation on a horizontal surface H in June in Amman, we can use the following equation:

\([H = S \times H_s \times \frac{\sin(\phi)\sin(\delta)+\cos(\phi)\cos(\delta)\cos(H_a)}{\pi}]\)

where:

S is the solar constant, which is approximately equal to 1367 W/m(^2);

\(H(_s)\) is the average number of sunshine hours per day in Amman in June, which is given as 10 hours;

(\(\phi\)) is the latitude of the location, which for Amman is approximately 31.9 degrees North;

(\(\delta\)) is the solar declination angle, which is a function of the day of the year and can be calculated using various methods such as the one given in the answer to Q1;

\(H(_a)\) is the hour angle, which is the difference between the local solar time and solar noon, and can also be calculated using various methods such as the one given in the answer to Q1.

Substituting the given values, we get:

\([H = 1367 \times 10 \times \frac{\sin(31.9)\sin(\delta)+\cos(31.9)\cos(\delta)\cos(H_a)}{\pi}]\)

Since we are only interested in the monthly average daily radiation, we can assume an average value for the solar declination angle and the hour angle over the month of June. For simplicity, we can assume that the solar declination angle (\(\delta\)) is constant at the value it has on June 21, which is approximately 23.5 degrees North. We can also assume that the hour angle \(H(_a)\) varies linearly from -15 degrees at sunrise to +15 degrees at sunset, with an average value of 0 degrees over the day.

Substituting these values, we get:

\([H = 1367 \times 10 \times \frac{\sin(31.9)\sin(23.5)+\cos(31.9)\cos(23.5)\cos(0)}{\pi}]\)

Simplifying the equation, we get:

\([H \approx 7.35 \text{ kWh/m}^2\text{/day}]\)

Therefore, the estimated monthly average daily radiation on a horizontal surface in June in Amman is approximately 7.35 kWh/m(^2)/day.

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In this problem we have that

JK=KL

JM=LM

and

KM is a common side

therefore

triangle KJM and triangle KLM are congruent by SSS

The diameter of the sphere tank is 27.2 ft.  

Every point on the surface of the sphere is equally spaced from its center, making it a three-dimensional round solid object.

The capacity of a sphere is defined as its volume or the area that the sphere occupies. Cubic units are used to measure a sphere's volume.

The formula for the Volume of a sphere is given by

Here we have

A spherical water tank holds 10,500 ft³ of water.  

Here capacity of the sphere = Volume of the sphere  

As we know the volume of the sphere = 4/3 πr³  

=> 4/3 πr³ = 10500

=> πr³ = 10500(3/4)

=> (22/7)r³ = 7875

=> 22r³ = 7875(7)    

=>  r³ = 55125/22  

=>  r³ = 2505

=> r = 13.6  (Approx)  

As we know diameter = 2 × Radius

=> Diameter of sphere = 2(13.6) = 27.2 ft

Therefore,

The diameter of the sphere tank is 27.2 ft.  

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This problem involves the concept of parametric differentiation. We are given parametric equations:

1. \(\(x(t) = e^{-3t}\)\)

2. \(\(y(t) = e^{3t}\)\)

We are asked to find \(\(\frac{d^2 y}{d x^2}\), the second derivative of \(y\) with respect to \(x\). Here are the steps to solve this problem:

Step 1: Calculate \(\(\frac{dy}{dt}\) and \(\frac{dx}{dt}\)\)

\(\(\frac{dy}{dt} = \frac{d}{dt} e^{3t} = 3e^{3t}\)\)

\(\(\frac{dx}{dt} = \frac{d}{dt} e^{-3t} = -3e^{-3t}\)\)

Step 2: Calculate \(\(\frac{dy}{dx}\)\)

By the chain rule, we can express \(\frac{dy}{dx}\)\) as \(\frac{dy}{dt} / \frac{dx}{dt}\)\).

Hence,

\(\(\frac{dy}{dx} = \frac{3e^{3t}}{-3e^{-3t}} = -e^{6t}\)\)

Step 3: Calculate  \(\(\frac{d^2 y}{dx^2}\)\)

Now, we find the second derivative. Here we have to apply the chain rule again, but now it's a bit trickier because \(\(\frac{dy}{dx}\)\) itself is a function of t, not x So we need to take \(\(\frac{d}{dt}\)\) of \(\(\frac{dy}{dx}\)\) and then divide by \(\(\frac{dx}{dt}\)\)

\(\(\frac{d^2 y}{dx^2} = \frac{d}{dt} (\frac{dy}{dx}) / \frac{dx}{dt}\)\)

Taking the derivative of \(\(\frac{dy}{dx} = -e^{6t}\)\) with respect to t, we get:

\(\(\frac{d}{dt} (\frac{dy}{dx}) = -6e^{6t}\)\)

So,

\(\(\frac{d^2 y}{dx^2} = \frac{-6e^{6t}}{-3e^{-3t}} = 2e^{9t}\)\)

So, the answer is (D)  \(2e^{9t}\)\)

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The second derivative d²y/dx² in terms of t is \(2e^{(9t)\).

Calculus's essential idea of derivatives is how quickly a function changes in relation to its independent variable. They offer details about how a function is altering for a certain input or point.

We must use the chain rule to determine the second derivative of y with respect to x (d²y/dx²) in terms of t.

According to the chain rule, the derivative of y with respect to x is given by dy/dx = (dy/dt) / (dx/dt) if we have a parametric curve defined by x = f(t) and y = g(t).

In this case, we have \(x(t) = e^{(-3t)\) and \(y(t) = e^{(3t)\).

First, we'll find the first derivatives dx/dt and dy/dt:

dx/dt = d/dt \((e^{(-3t)}) = -3e^{(-3t)\)

dy/dt = d/dt \((e^{(3t)}) = 3e^{(3t)\)

Next, we can find dy/dx:

dy/dx = (dy/dt) / (dx/dt)

\(= (3e^{(3t)}) / (-3e^{(-3t)})\\= -e^{(6t)\)

Finally, we differentiate dy/dx with respect to x to find d²y/dx²:

d²y/dx² = \(d/dx (-e^{(6t)})\)

\(= d/dt (-e^{(6t))} \times (dt/dx)\\= -6e^{(6t)} \times (1 / (-3e^{(-3t)}))\\= 2e^{(9t)\)

Therefore, the second derivative d²y/dx² in terms of t is \(2e^{(9t)\).

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The person can run 5.33 miles (distance) in 16 minutes (time) if they run 20 per hour (speed).

Distance is the length of one point to the next.

Time refers to the hours or minutes consumed in making a displacement.

Speed shows the rate of the change in displacement resulting from the interaction of distance with time.

Speed measures the ratio of distance to time.

Thus, the person can run 5.33 miles (distance) in 16 minutes (time) if they run 20 per hour (speed).

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The probability that the sample mean will be greater than 57.95 is 0.0495.

Probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event. The value is expressed from zero to one. This is the basic probability theory, which is also used in the probability distribution.

To solve this question, we need to know the concepts of the normal probability distribution and of the central limit theorem.

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \(\mu\) and standard deviation \(\sigma\), the z-score of a measure X is given by:

\(Z=\dfrac{X-\mu}{\sigma}\)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The Central Limit Theorem establishes that, for a random variable X, with mean \(\mu\) and standard deviation \(\sigma\), a large sample size can be approximated to a normal distribution with mean \(\mu\) and standard deviation \(\frac{\sigma}{\sqrt{\text{n}} }\).

In this problem, we have that:

The probability that the sample mean will be greater than 57.95

This is 1 subtracted by the p-value of Z when X = 57.95. So

\(Z=\dfrac{X-\mu}{\sigma}\)

By the Central Limit Theorem

\(Z=\dfrac{X-\mu}{\text{s}}\)

\(Z=\dfrac{57.95-53}{3}\)

\(Z=1.65\)

\(Z=1.65\) has a p-value of 0.9505.

Therefore, the probability that the sample mean will be greater than 57.95 is 1-0.9505 = 0.0495

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Answer:

\(<-5, 20>\)

Step-by-step explanation:

What we're given:

The vector \(3v-4w\) is then \(3(-3i)-4(-i+5j)=-9i+4i-20j=-5i+20j\implies \boxed{<-5, 20>}\)

Answer:

A ≈ 14.8 units²

Step-by-step explanation:

the area (A) of the triangle is calculated as

A = \(\frac{1}{2}\) yz sin Y ( that is 2 sides and the angle between them )

where x is the side opposite ∠ X and z the side opposite ∠ Z

here y = XZ = 4.3 and z = XY = 7 , then

A = \(\frac{1}{2}\) × 4.3 × 7 × sin79°

   = 15.05 × sin79°

   ≈ 14.8 units² ( to 1 decimal place )

Answer:

25

Step-by-step explanation:

180-155

The volume of the solid obtained by rotating the region bounded by y = x^2 and y = 6 about the line x = -3 is approximately 481.39 cubic units.


To find the volume of the solid, we can use the method of cylindrical shells. The region bounded by y = x^2 and y = 6 in the first quadrant is a parabolic shape above the x-axis.
To set up the integral for the volume, we consider an infinitesimally small vertical strip of thickness Δx at a distance x from the line x = -3. The height of the strip is given by the difference between the two curves: h = 6 – x^2. The circumference of the cylindrical shell is given by the formula 2πr, where r is the distance between x and the line x = -3, which is r = x + 3.

The volume of the infinitesimal shell is then given by dV = 2π(x + 3)(6 – x^2)Δx. Integrating this expression from x = 0 to x = 3, we obtain the volume V = ∫[0,3] 2π(x + 3)(6 – x^2)dx. Evaluating this integral, we find V ≈ 481.39 cubic units.
In summary, the volume of the solid obtained by rotating the region bounded by y = x^2 and y = 6 about the line x = -3 is approximately 481.39 cubic units.

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Answer:

y^6 z^12

Step-by-step explanation:

When the bases are the same that means that the powers on the inside can be multiplied by whatever is outside.

Hope this helps :)

Answer:

560

Step-by-step explanation:

Answer:

560

Step-by-step explanation:

substitute "s" and "t" into the equation:

4(4)(6)^2-(4)^2

when you solve this according to the order of operations, you will get 560

As per the average, the distance of planes at 2:45pm is 678 miles.

First, let's talk about the concept of "average." When we say a plane is traveling at an average speed of 428 mph, that means it may be going faster or slower at different points in its journey, but the overall average speed over time is 428 mph.

To find out how far apart the planes are at 2:45pm, we need to know how far each plane has traveled by that time. Since the first plane left at 1:00pm and it is now 2:45pm, it has been flying for 1 hour and 45 minutes. To find out how far it has traveled, we can use the formula:

distance = speed x time.

So, distance = 428 mph x 1.75 hours = 749 miles.

The second plane left 15 minutes later, so it has been flying for 1 hour and 30 minutes by 2:45pm.

To find out how far it has traveled, we can use the same formula:

distance = speed x time.

So, distance = 452 mph x 1.5 hours = 678 miles.

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Answer:

The Ratio is 8:16.

Step-by-step explanation:

The correct statements about omitted variable bias are:

1. If the omitted variable and included variable are correlated, there is a bias.

2. If the omitted variable is relevant, there is a bias.

Omitted variable bias refers to the bias introduced in an econometric model when a relevant variable is left out of the analysis. The bias occurs when the omitted variable is correlated with both the dependent variable and the included variables in the model.

If the omitted variable and included variable are correlated, there is a bias because the included variable may capture some of the effects of the omitted variable. In this case, the estimated coefficient of the included variable will be biased, as it will include the influence of the omitted variable.

Similarly, if the omitted variable is relevant, there is a bias because it has a direct impact on the dependent variable. By excluding the relevant variable, the model fails to account for its influence, leading to biased estimates of the coefficients of the included variables.

Random assignment of included variables does not eliminate omitted variable bias. While random assignment may help control for confounding factors and reduce bias in certain experimental designs, it does not address the issue of omitting a relevant variable from the analysis. Omitted variable bias can still exist even with random assignment of included variables.

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